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  • Make Trac use a Drupal user database for authentication

    - by denisw
    I am trying to set up a Trac instance as a complement to a Drupal site and would like to give users the possibility to use their Drupal account in Trac, too, ideally in a single sign-on fashion (if the user is already logged into Drupal, he is automatically logged into Trac). The question now is how to accomplish this. I have found a plugin named DrupalIntegration which seems to implement that functionality; however, it is poorly documented - in fact, not documented at all. I managed to install it, but don't know how to configure it. Here is what I came up with from looking at the source code and the documentation of the AccountManager plugin (on which DrupalIntegration depends): [components] trac.web.auth.loginmodule = disabled acct_mgr.api = enabled acct_mgr.web_ui.LoginModule = enabled acct_mgr.web_ui.RegistrationModule = disabled TracDrupalIntegration.DrupalIntegration = enabled [account-manager] drupal_database = mysql://<usernam>:<password>@localhost/<db> password_store = DrupalIntegration (<username>, <password> and <db> are naturally substituted with the correct data). While the Trac log says: 2010-12-18 10:54:09,570 Trac[loader] DEBUG: Loading TracDrupalIntegration from /usr/lib/python2.5/site-packages/TracDrupalIntegration-0.1-py2.5.egg this doesn't seem to work: trying to log in with a Drupal username / password results in an "Invalid username or password" error. Has someone used the DrupalIntegration and can point out to me what I did wrong? Or is there any other approach you know (or even have used in the past) to integrate Drupal and Trac that way?

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  • PHP and MySQL validating problem

    - by IPADvsSLATE
    I'm trying to check if a color is already entered into the database if it is the color should not be entered and stored into the database and the following error code <p>This color has already been entered!</p> should be displayed. But for some reason I cant get this to work, can someone please help me? The color names are entered into $_POST['color'] which is an array entered by the user. Here is the html code that collects the colors. <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> Here is the PHP & MySQL code. for($i=0; $i < count($_POST['color']); $i++) { $color = "'" . $_POST['color'][$i] . "'"; } $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT * FROM colors WHERE color = '$color' AND user = '$user_id' "); if(mysqli_num_rows($dbc) == TRUE) { echo '<p>This color has already been entered!</p>'; } else if(mysqli_num_rows($dbc) == 0) { // enter the color into the database }

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  • How to check what goes wrong in $view->render with Zend Framework?

    - by koko
    Hi, I'm working on a CMS with Widgets. On my localhost the followong code works perfect, but I have no idea what I'm doing wrong ... The neede files exist, I think and I get no error message. As far as I can see, the error occurs in the one before last line of code and I get no error message. $view = new Zend_View(); $view->setScriptPath(APPLICATION_PATH . '/../public/websites/' . My_Cookie::get('alpha_key') . '/views'); $view->headScript()->appendFile($vervang['conf']['jqueryJS']); $view->headLink()->appendStylesheet($vervang['conf']['jqueryCSS']); $view->class = $pluginExtraFinal; $view->vervang = $vervang['data']; $view->moduleName = $moduleName; $parsed = $view->render($vervang['conf']['viewFile']); $inhoud = str_replace($plugin, $parsed, $inhoud); Is there a way to troubleshoot this code? How can I get an error message? What can be wrong? Any suggestions please?

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  • tracd server problems

    - by deddihp
    Hello, I got the following error while accessing tracd server, what's going on ? Thanks. [oke@localhost Trac-0.11.7]$ sudo tracd -p 8000 /home/deddihp/trac/ Server starting in PID 5082. Serving on 0.0.0.0:8000 view at http://127.0.0.1:8000/ ---------------------------------------- Exception happened during processing of request from ('127.0.0.1', 47804) Traceback (most recent call last): File "/usr/lib/python2.6/SocketServer.py", line 558, in process_request_thread self.finish_request(request, client_address) File "/usr/lib/python2.6/SocketServer.py", line 320, in finish_request self.RequestHandlerClass(request, client_address, self) File "/usr/lib/python2.6/SocketServer.py", line 615, in __init__ self.handle() File "/usr/lib/python2.6/BaseHTTPServer.py", line 329, in handle self.handle_one_request() File "/usr/lib/python2.6/site-packages/Trac-0.11.7-py2.6.egg/trac/web/wsgi.py", line 194, in handle_one_request gateway.run(self.server.application) File "/usr/lib/python2.6/site-packages/Trac-0.11.7-py2.6.egg/trac/web/wsgi.py", line 94, in run response = application(self.environ, self._start_response) File "/usr/lib/python2.6/site-packages/Trac-0.11.7-py2.6.egg/trac/web/standalone.py", line 100, in __call__ return self.application(environ, start_response) File "/usr/lib/python2.6/site-packages/Trac-0.11.7-py2.6.egg/trac/web/main.py", line 346, in dispatch_request locale.setlocale(locale.LC_ALL, environ['trac.locale']) File "/usr/lib/python2.6/locale.py", line 513, in setlocale return _setlocale(category, locale) Error: unsupported locale setting ----------------------------------------

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  • Ajax not working in visual studio 2005

    - by sachin
    I am trying to do an ajax website, but my ajax is not working. I checked my GAC and system.web,extensions dll is available. Why it is not working .? I am also not getting any errors. I tried many ways. I wrote the below code to test ajax. <%@ Page Language="C#" AutoEventWireup="true" CodeFile="Default.aspx.cs" Inherits="_Default" %> <%@ Register Assembly="System.Web.Extensions" Namespace="System.Web.UI" TagPrefix="asp" %> <%@ Register Assembly="AjaxControlToolkit" Namespace="AjaxControlToolkit" TagPrefix="cc1" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" > <head runat="server"> <title>Untitled Page</title> </head> <body> <form id="form1" runat="server"> <div> <cc1:ToolkitScriptManager ID="ToolkitScriptManager1" runat="server"> </cc1:ToolkitScriptManager> <asp:TextBox ID="TextBox1" runat="server"></asp:TextBox> <cc1:CalendarExtender ID="CalendarExtender1" runat="server" TargetControlID="TextBox1"> </cc1:CalendarExtender> </div> </form> </body> </html> JAvascript error that i got 1.Type is not defined http://localhost:1467/testnew/Default.aspx?_TSM_HiddenField_=ToolkitScriptManager1_HiddenField&_TSM_CombinedScripts_=%3b%3bAjaxControlToolkit%2c+Version%3d1.0.20229.20821%2c+Culture%3dneutral%2c+PublicKeyToken%3d28f01b0e84b6d53e%3aen-US%3ac5c982cc-4942-4683-9b48-c2c58277700f%3ae2e86ef9%3aa9a7729d%3a9ea3f0e2%3a9e8e87e9%3a1df13a87%3a4c9865be%3aba594826%3a507fcf1b%3ac7a4182e

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  • UTF-8 MySQL and Charset, pls help me understand this once and for all!

    - by FFish
    Can someone explain me when I set everything to UTF-8 I keep getting those damn ??? MySQL Server version: 5.1.44 MySQL charset: UTF-8 Unicode (utf8) I create a new database name: utf8test collation: utf8_general_ci MySQL connection collation: utf8_general_ci My SQL looks like this: SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO"; CREATE TABLE IF NOT EXISTS `test_table` ( `test_id` int(11) NOT NULL, `test_text` text NOT NULL, PRIMARY KEY (`test_id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; INSERT INTO `test_table` (`test_id`, `test_text`) VALUES (1, 'hééélo'), (2, 'wööörld'); My PHP / HTML: <?php $db_conn = mysql_connect("localhost", "root", "") or die("Can't connect to db"); mysql_select_db("utf8test", $db_conn) or die("Can't select db"); // $result = mysql_query("set names 'utf8'"); // this works... why?? $query = "SELECT * FROM test_table"; $result = mysql_query($query); $output = ""; while($row = mysql_fetch_assoc($result)) { $output .= "id: " . $row['test_id'] . " - text: " . $row['test_text'] . "<br />"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html lang="it" xmlns="http://www.w3.org/1999/xhtml" xml:lang="it"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>UTF-8 test</title> </head> <body> <?php echo $output; ?> </body> </html>

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  • creating new instance fails PHP

    - by as3isolib
    I am relatively new to PHP and having some decent success however I am running into this issue: If I try to create a new instance of the class GenericEntryVO, I get a 500 error with little to no helpful error information. However, if I use a generic object as the result, I get no errors. I'd like to be able to cast this object as a GenericEntryVO as I am using AMFPHP to communicate serialize data with a Flex client. I've read a few different ways to create constructors in PHP but the typical 'public function Foo()' for a class Foo was recommended for PHP 5.4.4 //in my EntryService.php class public function getEntryByID($id) { $link = mysqli_connect("localhost", "root", "root", "BabyTrackingAppDB"); if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); exit(); } $query = "SELECT * FROM Entries WHERE id = '$id' LIMIT 1"; if ($result = mysqli_query($link, $query)) { // $entry = new GenericEntryVO(); this is where the problem lies! while ($row = mysqli_fetch_row($result)) { $entry->id = $row[0]; $entry->entryType = $row[1]; $entry->title = $row[2]; $entry->description = $row[3]; $entry->value = $row[4]; $entry->created = $row[5]; $entry->updated = $row[6]; } } mysqli_free_result($result); mysqli_close($link); return $entry; } //my GenericEntryVO.php class <?php class GenericEntryVO { public function __construct() { } public $id; public $title; public $entryType; public $description; public $value; public $created; public $updated; // public $properties; } ?>

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  • python on apache - getting 404

    - by Kirby
    I edited this question after i found a solution... i need to understand why the solution worked instead of my method? This is likely to be a silly question. I tried searching other questions that are related... but to no avail. i am running Apache/2.2.11 (Ubuntu) DAV/2 SVN/1.5.4 PHP/5.2.6-3ubuntu4.5 with Suhosin-Patch mod_python/3.3.1 Python/2.6.2 i have a script called test.py #! /usr/bin/python print "Content-Type: text/html" # HTML is following print # blank line, end of headers print "hello world" running it as an executable works... /var/www$ ./test.py Content-Type: text/html hello world when i run http://localhost/test.py i get a 404 error. What am i missing? i used this resource to enable python parsing on apache. http://ubuntuforums.org/showthread.php?t=91101 From that same thread... the following code worked.. why? #!/usr/bin/python import sys import time def index(req): # Following line causes error to be sent to browser # rather than to log file (great for debug!) sys.stderr = sys.stdout #print "Content-type: text/html\n" #print """ blah1 = """<html> <head><title>A page from Python</title></head> <body> <h4>This page is generated by a Python script!</h4> The current date and time is """ now = time.gmtime() displaytime = time.strftime("%A %d %B %Y, %X",now) #print displaytime, blah1 += displaytime #print """ blah1 += """ <hr> Well House Consultants demonstration </body> </html> """ return blah1

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  • AngularJS - $routeParams Empty on $locationChangeSuccess

    - by Marc M.
    I configure my app in the following run block. Basically I want to preform an action that requires me to know the $routeParams every $locationChangeSuccess. However $routeParams is empty at this point! Are there any work rounds? What's going on? app.run(['$routeParams', function ($routeParams) { $rootScope.$on("$locationChangeSuccess", function () { console.log($routeParams); }); }]); UPDATE function configureApp(app, user) { app.config(['$routeProvider', function ($routeProvider) { $routeProvider. when('/rentroll', { templateUrl: 'rent-roll/rent-roll.html', controller: 'pwRentRollCtrl' }). when('/bill', { templateUrl: 'bill/bill/bill.html', controller: 'pwBillCtrl' }). when('/fileroom', { templateUrl: 'file-room/file-room/file-room.html', controller: 'pwFileRoomCtrl' }). when('/estate-creator', { templateUrl: 'estate/creator.html' }). when('/estate-manager', { templateUrl: 'estate/manager.html', controller: 'pwEstateManagerCtrl' }). when('/welcomepage', { templateURL: 'welcome-page/welcome-page.html', controller: 'welcomePageCtrl' }). otherwise({ redirectTo: '/welcomepage' }); }]); app.run(['$rootScope', '$routeParams', 'pwCurrentEstate','pwToolbar', function ($rootScope, $routeParams, pwCurrentEstate, pwToolbar) { $rootScope.user = user; $rootScope.$on("$locationChangeSuccess", function () { pwToolbar.reset(); console.log($routeParams); }); }]); } Accessing URL: http://localhost:8080/landlord/#/rentroll?landlord-account-id=ahlwcm9wZXJ0eS1tYW5hZ2VtZW50LXN1aXRlchwLEg9MYW5kbG9yZEFjY291bnQYgICAgICAgAoM&billing-month=2014-06

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  • URL-Encoded post parameters don't Bind to model

    - by Steven Klein
    I have the following Model namespace ClientAPI.Models { public class Internal { public class ReportRequest { public DateTime StartTime; public DateTime EndTime; public string FileName; public string UserName; public string Password; } } } with the following method: [HttpPost] public HttpResponseMessage GetQuickbooksOFXService(Internal.ReportRequest Request){ return GetQuickbooksOFXService(Request.UserName, Request.Password, Request.StartTime, Request.EndTime, Request.FileName); } My webform looks like this: <form method="POST" action="http://localhost:56772/Internal/GetQuickbooksOFXService" target="_blank"> <input type="text" name="StartTime" value="2013-04-03T00:00:00"> <input type="text" name="EndTime" value="2013-05-04T00:00:00"> <input type="text" name="FileName" value="Export_2013-04-03_to_2013-05-03.qbo"> <input type="text" name="UserName" value="UserName"> <input type="text" name="Password" value="*****"> <input type="submit" value="Submit"></form> My question is: I get into the GetQuickbooksOFXService function but my model has all nulls in it instead something useful. Am I doing something wrong?

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  • I am unable to upload file to my local host folder in php.

    - by Nauman khan
    Hi, I have the follwing code <form enctype="multipart/form-data" action="upload.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> my page is in http://localhost/nausal/upload.php now I am having the follwing error though i have created a folder in site with name upload. Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 15 Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 17 Sorry, there was a problem uploading your file. Please help me I am very new to php. :(

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  • javascript ajax help

    - by ngreenwood6
    I have the following code. var d3_ad = 1; function displayD3Ad(){ var query_string = '?d3_ad='+d3_ad; query_string += '&location='+escape(location); //document.write('<iframe src="index.php'+query_string+'"></iframe>'); var data = httpRequest('http://localhost/test/index.php','GET',query_string); document.write(data); } function httpRequest(strURL,type,query) { var request = false; if (window.XMLHttpRequest) {// Mozilla/Safari request = new XMLHttpRequest(); } else if (window.ActiveXObject) { //Internet Explorer request= new ActiveXObject("Microsoft.XMLHTTP"); } request.open(type, strURL + query, true); request.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded'); request.onreadystatechange = function() { if (request.readyState == 4) { return request.responseText; } } request.send(null); } displayD3Ad(); now when it writes out the data it is saying undefined. It seems like it isnt returning the data. I looked in firebug and it completes and shows the response that shoudl be there. Any help is appreciated. I just need to set the data variable so that I can use it later on.

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  • MySQL Database is Indexed at Apache Solr, How to access it via URL

    - by Wasim
    data-config.xml <dataConfig> <dataSource encoding="UTF-8" type="JdbcDataSource" driver="com.mysql.jdbc.Driver" url="jdbc:mysql://localhost:3306/somevisits" user="root" password=""/> <document name="somevisits"> <entity name="login" query="select * from login"> <field column="sv_id" name="sv_id" /> <field column="sv_username" name="sv_username" /> </entity> </document> </dataConfig> schema.xml <?xml version="1.0" encoding="UTF-8" ?> <schema name="example" version="1.5"> <fields> <field name="sv_id" type="string" indexed="true" stored="true" required="true" multiValued="false" /> <field name="username" type="string" indexed="true" stored="true" required="true"/> <field name="_version_" type="long" indexed="true" stored="true" multiValued="false"/> <field name="text" type="string" indexed="true" stored="false" multiValued="true"/> </fields> <uniqueKey>sv_id</uniqueKey> <types> <fieldType name="string" class="solr.StrField" sortMissingLast="true" /> <fieldType name="long" class="solr.TrieLongField" precisionStep="0" positionIncrementGap="0"/> </types> </schema> Solr successfully imported mysql database using full http://[localSolr]:8983/solr/#/collection1/dataimport?command=full-import My question is, how to access that mysql imported database now?

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  • javascript :Object doesn't support this property or method

    - by Kaushik
    In my jsp page, I have in the tag, the following code: <script type="text/javascript" src="<%=request.getContextPath()%>/static/js/common/common.js"></script> <script type="text/javascript"> // Function for Suppressing the JS Error function silentErrorHandler() {return true;} window.onerror=silentErrorHandler; </script> If there is some javascript executing on the jsp page after this, then I guess silentErrorHandler() will have no effect. i.e. the error will still show on page. IS this correct? Because the error is showing and am not sure why. The second part of the question is this: The error is Webpage error details User Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.1; Trident/4.0; SLCC2; .NET CLR 2.0.50727; .NET CLR 3.5.30729; .NET CLR 3.0.30729; Media Center PC 6.0; InfoPath.2; AskTbFXTV5/5.9.1.14019) Timestamp: Fri, 7 Jan 2011 21:26:23 UTC Message: Object doesn't support this property or method Line: 613 Char: 1 Code: 0 URI: http://localhost:9080/Claris/static/js/common/common.js And finally, line 613 states document.captureEvents(Event.MOUSEUP); There is error on IE8. Runs fine on Mozilla and IE7. Any suggestions will be very helpful

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  • Passing list of values to django view via jQuery ajax call

    - by finspin
    I'm trying to pass a list of numeric values (ids) from one web page to another with jQuery ajax call. I can't figure out how to pass and read all the values in the list. I can successfully post and read 1 value but not multiple values. Here is what I have so far: jQuery: var postUrl = "http://localhost:8000/ingredients/"; $('li').click(function(){ values = [1, 2]; $.ajax({ url: postUrl, type: 'POST', data: {'terid': values}, traditional: true, dataType: 'html', success: function(result){ $('#ingredients').append(result); } }); }); /ingredients/ view: def ingredients(request): if request.is_ajax(): ourid = request.POST.get('terid', False) ingredients = Ingredience.objects.filter(food__id__in=ourid) t = get_template('ingredients.html') html = t.render(Context({'ingredients': ingredients,})) return HttpResponse(html) else: html = '<p>This is not ajax</p>' return HttpResponse(html) With Firebug I can see that POST contains both ids but probably in the wrong format (terid=1&terid=2). So my ingredients view picks up only terid=2. What am I doing wrong? EDIT: To clarify, I need the ourid variable pass values [1, 2] to the filter in the ingredients view.

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  • I can't insert data into my database

    - by Ken
    I don't know why, but my data doesn't go into my database 'users' with the table 'data'. <html> <body> <?php date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db(`users`, $con) or die(mysql_error()); mysql_query(INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password')) or die(mysql_error()); mysql_close($con) echo("Thank you for registering!"); ?> </body> </html> All i get is a blank page.

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  • Advise guidance on how to form this jQuery script for show/hide fade element

    - by Rick
    Hey guys.. I basically have several links on the left side of the screen and on the right is a preview window. Below the preview window is another box for the affiliate link code. So what I am trying to do is create an affiliate page where you choose the banner size on the left by clicking on the link and on the right you see it dynamically change to the banner size and the code changes accordingly as well. So far I have the following code and it works but it seems very very cumbersome and bloated. Can you see if I can trim this down? jQuery(".banner-style li").click(function() { jQuery(".banner-style li").removeClass("selected"); jQuery(this).addClass("selected"); var $banner = jQuery(this).attr("class"); $banner = $banner.replace(" selected",""); jQuery(".preview img").fadeOut('fast',function() { jQuery(".preview img").attr("src", "http://localhost/site/banners/"+$banner+".jpg") .fadeIn('slow'); }); jQuery(".code p").removeClass('hide').hide(); jQuery(".code p."+$banner).show(); }); Also to note the funny thing is in FF, when you click for the first to on any link, the original image on the right fades out and in real quick and then it loads the "clicked" image. This does not happen in other browsers...

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  • Memcache error: Failed reading line from stream (0) Array

    - by daviddripps
    I get some variation of the following error when our server gets put under any significant load. I've Googled for hours about it and tried everything (including upgrading to the latest versions and clean installs). I've read all the posts about it here on SA, but can't figure it out. A lot of people are having the same problem, but no one seems to have a definitive answer. Any help would be greatly appreciated. Thanks in advance. Fatal error: Uncaught exception 'Zend_Session_Exception' with message 'Zend_Session::start() - /var/www/trunk/library/Zend/Cache/Backend/Memcached.php(Line:180): Error #8 Memcache::get() [memcache.get]: Server localhost (tcp 11211) failed with: Failed reading line from stream (0) Array We have a copy of our production environment for testing and everything works great until we start load-testing. I think the biggest object stored is about 170KB, but it will probably be about 500KB when all is said and done (well below the 1MB limit). Just FYI: Memcache gets hit about 10-20 times per page load. Here's the memcached settings: PORT="11211" USER="memcached" MAXCONN="1024" CACHESIZE="64" OPTIONS="" I'm running Memcache 1.4.5 with version 2.2.6 of the PHP-memcache module. PHP is version 5.2.6. memcache details from php -i: memcache memcache support = enabled Active persistent connections = 0 Version = 2.2.6 Revision = $Revision: 303962 $ Directive = Local Value = Master Value memcache.allow_failover = 1 = 1 memcache.chunk_size = 8192 = 8192 memcache.default_port = 11211 = 11211 memcache.default_timeout_ms = 1000 = 1000 memcache.hash_function = crc32 = crc32 memcache.hash_strategy = standard = standard memcache.max_failover_attempts = 20 = 20 Thanks everyone

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  • Rails 3, Devise and custom controller action

    - by Johnny Klassy
    routes.rb match 'agencies/stub' => 'agencies#stub', :via => :get resources :agencies Here's the rake routes dump agencies_stub GET /agencies/stub(.:format) {:controller=>"agencies", :action=>"stub"} agencies GET /agencies(.:format) {:action=>"index", :controller=>"agencies"} POST /agencies(.:format) {:action=>"create", :controller=>"agencies"} new_agency GET /agencies/new(.:format) {:action=>"new", :controller=>"agencies"} edit_agency GET /agencies/:id/edit(.:format) {:action=>"edit", :controller=>"agencies"} agency GET /agencies/:id(.:format) {:action=>"show", :controller=>"agencies"} PUT /agencies/:id(.:format) {:action=>"update", :controller=>"agencies"} DELETE /agencies/:id(.:format) {:action=>"destroy", :controller=>"agencies"} Devise is setup to have all agenciesroutes only accessible as admin. The call I'm testing with is http://xyz:12345@localhost:3000/agencies/stub but it doesn't authenticate properly, ie, it doesn't recognize it as admin and throws me back to the Devise login page. The creds are a valid admin account. I'm baffled and have no idea why this is happening. Any insights will be much appreciated.

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  • Selecting Date Range on a PHP form and displaying results from MySQL database

    - by Sarah HSL
    This may be something simple but I cant understand why this wouldn't work.. I have a php form where you can select a date range from drop downs. I've given the field names day, month year, and day1, month1, year1. When clicking submit it takes you to a second php form. Here is the code for second form: <?php $username="***"; $password="***"; $database="****"; mysql_connect('localhost',$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $day = $_GET['day']; $month = $_GET['month']; $year = $_GET['year']; $day1 = $_GET['day1']; $month1 = $_GET['month1']; $year1 = $_GET['year1']; $date1 = "$year-$month-$day"; $date2 = "$year1-$month1-$day1"; $query = "SELECT * FROM main_stock WHERE curr_timestamp BETWEEN '$date1' AND '$date2'"; $result=mysql_query($query); $num=mysql_num_rows($result); ?> <table border="1" cellspacing="2" cellpadding="2"> <tr> <td><b><font face="Arial, Helvetica, sans-serif">Product Description</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Category</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Master Category</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Barcode</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Status</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">TimeStamp</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">New Own</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Serial No.</font></b></td> </tr> <?php $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"product_desc"); $f2=mysql_result($result,$i,"category"); $f3=mysql_result($result,$i,"mastercategory"); $f4=mysql_result($result,$i,"barcode"); $f5=mysql_result($result,$i,"status"); $f6=mysql_result($result,$i,"curr_timestamp"); $f7=mysql_result($result,$i,"newown"); $f8=mysql_result($result,$i,"serial"); ?> <tr> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f1; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f2; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f3; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f4; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f5; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f6; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f7; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f8; ?></font></td> </tr> <?php $i++; } $num_rows = mysql_num_rows($result); echo "$num_rows Rows\n"; mysql_close(); ?> Is there any reason this wouldn't work? I'm not sure where I am going wrong. It displays results when there is another option as well as the date such as 'status' but when this is taken out and I just want to display all the results between the date range it doesn't work.. This works: <?php $username="+++"; $password="+++"; $database="+++"; mysql_connect('localhost',$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $day = $_GET['day']; $month = $_GET['month']; $year = $_GET['year']; $day1 = $_GET['day1']; $month1 = $_GET['month1']; $year1 = $_GET['year1']; $status = $_GET['status']; $date1 = "$year-$month-$day"; $date2 = "$year1-$month1-$day1"; $query = "SELECT * FROM main_stock WHERE status = '$status' AND curr_timestamp BETWEEN '$date1' AND '$date2'"; $result=mysql_query($query); $num=mysql_num_rows($result); ?> <table border="1" cellspacing="2" cellpadding="2"> <tr> <td><b><font face="Arial, Helvetica, sans-serif">Product Description</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Category</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Master Category</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Barcode</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Status</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">TimeStamp</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">New Own</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Serial No.</font></b></td> </tr> <?php $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"product_desc"); $f2=mysql_result($result,$i,"category"); $f3=mysql_result($result,$i,"mastercategory"); $f4=mysql_result($result,$i,"barcode"); $f5=mysql_result($result,$i,"status"); $f6=mysql_result($result,$i,"curr_timestamp"); $f7=mysql_result($result,$i,"newown"); $f8=mysql_result($result,$i,"serial"); ?> <tr> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f1; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f2; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f3; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f4; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f5; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f6; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f7; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f8; ?></font></td> </tr> <?php $i++; } $num_rows = mysql_num_rows($result); echo "$num_rows Rows\n"; mysql_close(); ?> But when the 'status' field is taken out (and obviously the serial drop down in the first form) it stops working...

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  • php + MySQL editing table data.

    - by Jacksta
    This question is relating to 2 php scripts. The first script is called pick_modcontact.php where I choose a contact (from a contact book like phone book), then posts to the script show_modcontact.php When I click the submit button on the form on pick.modcontact.php. As a result of submitting the form I am then taken to show_modcontact.php. As the variables are not present the user is directed back to pick_modcontact.php I can not work out how to correct the code so that it will show the results of the script show_modcontact.php This script shows all contacts in a database which is an "address book" this part works fine. please see below. Name:pick_modcontact.php if ($_SESSION['valid'] != "yes") { header( "Location: contact_menu.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "admin", "user") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT id, f_name, l_name FROM $table_name ORDER BY f_name"; $result = @mysql_query($sql, $connection) or die(mysql_error()); $num = @mysql_num_rows($result); if ($num < 1) { $display_block = "<p><em>Sorry No Results!</em></p>"; } else { while ($row = mysql_fetch_array($result)) { $id = $row['id']; $f_name = $row['f_name']; $l_name = $row['l_name']; $option_block .= "<option value\"$id\">$f_name, $l_name</option>"; } $display_block = "<form method=\"POST\" action=\"show_modcontact.php\"> <p><strong>Contact:</strong> <select name=\"id\">$option_block</select> <input type=\"submit\" name=\"submit\" value=\"Select This Contact\"></p> </form>"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <h1>My Contact Management System</h1> <h2><em>Modify a Contact</em></h2> <p>Select a contact from the list below, to modify the contact's record.</p> <? echo "$display_block"; ?> <br> <p><a href="contact_menu.php">Return to Main Menu</a></p> </body> </html> This script is for modifying the contact: named show_modcontact.php <?php if (!$_POST['id']) { header( "Location: pick_modcontact.php"); exit; } else { session_start(); } if ($_SESSION['valid'] != "yes") { header( "Location: pick_modcontact.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "admin", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT f_name, l_name, address1, address2, address3, postcode, prim_tel, sec_tel, email, birthday FROM $table_name WHERE id = '" . $_POST['id'] . "'"; $result = @mysql_query($sql, $connection) or die(mysql_error()); while ($row = mysql_fetch_array($result)) { $f_name = $row['f_name']; $l_name = $row['l_name']; $address1 = $row['address1']; $address2 = $row['address2']; $address3 = $row['address3']; $country = $row['country']; $prim_tel = $row['prim_tel']; $sec_tel = $row['sec_tel']; $email = $row['email']; $birthday = $row['birthday']; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <form action="do_modcontact.php" method="post"> <input type="text" name="id" value="<? echo $_POST['id']; ?>" /> <table cellpadding="5" cellspacing="3"> <tr> <th>Name & Address Information</th> <th> Other Contact / Personal Information</th> </tr> <tr> <td align="top"> <p><strong>First Name:</strong><br /> <input type="text" name="f_name" value="<? echo "$f_name"; ?>" size="35" maxlength="75" /></p> <p><strong>Last Name:</strong><br /> <input type="text" name="l_name" value="<? echo "$l_name"; ?>" size="35" maxlength="75" /></p> <p><strong>Address1:</strong><br /> <input type="text" name="f_name" value="<? echo "$address1"; ?>" size="35" maxlength="75" /></p> <p><strong>Address2:</strong><br /> <input type="text" name="f_name" value="<? echo "$address2"; ?>" size="35" maxlength="75" /></p> <p><strong>Address3:</strong><br /> <input type="text" name="f_name" value="<? echo "$address3"; ?>" size="35" maxlength="75" /> </p> <p><strong>Postcode:</strong><br /> <input type="text" name="f_name" value="<? echo "$postcode"; ?>" size="35" maxlength="75" /></p> <p><strong>Country:</strong><br /> <input type="text" name="f_name" value="<? echo "$country"; ?>" size="35" maxlength="75" /> </p> <p><strong>First Name:</strong><br /> <input type="text" name="f_name" value="<? echo "$f_name"; ?>" size="35" maxlength="75" /></p> </td> <td align="top"> <p><strong>Prim Tel:</strong><br /> <input type="text" name="f_name" value="<? echo "$prim_tel"; ?>" size="35" maxlength="75" /></p> <p><strong>Sec Tel:</strong><br /> <input type="text" name="f_name" value="<? echo "$sec_tel"; ?>" size="35" maxlength="75" /></p> <p><strong>Email:</strong><br /> <input type="text" name="f_name" value="<? echo "$email;" ?>" size="35" maxlength="75" /> </p> <p><strong>Birthday:</strong><br /> <input type="text" name="f_name" value="<? echo "$birthday"; ?>" size="35" maxlength="75" /> </p> </td> </tr> <tr> <td align="center"> <p><input type="submit" name="submit" value="Update Contact" /></p> <br /> <p><a href="contact_menu.php">Retuen To Menu</a></p> </td> </tr> </table> </form> </body> </html> note for site admin, I am re posting this question with the hope of someone else reading over it. older questions seem to go dead after a while.

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  • how to make connection pool in spring application using BasicDataSource.

    - by vipin
    hi friend, I have created the application in which I need to configure the connection pool.In which I am configuring the connection pooling in the spring_Config file. using the Basicdatasource. but there is some problem to create the connection pool. Please tell me how to create the connection pooling in spring application using BasicDatasource. I tried this one code in spring config ;- bean id="datasource" class="org.apache.commons.dbcp.BasicDataSource" com.mysql.jdbc.Driver jdbc:mysql://192.168.1.12:3306/revup?noAccessToProcedureBodies=true jdbc:mysql://localhost:3306/revup?noAccessToProcedureBodies=true-- revuser root-- kjacob gme997FK-- <property name="poolPreparedStatements"> <value>true</value> </property> <property name="initialSize"> <value>2</value> </property> <property name="maxActive"> <value>15</value> </property> Is there any modification of code please tell me. thanks in advance.

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  • php oop and mysql

    - by gloris
    I need to get data, to check and send to db. Programming with PHP OOP. Could you tell me if my class structure is good and how dislpay all data?. Thanks <?php class Database{ private $DBhost = 'localhost'; private $DBuser = 'root'; private $DBpass = 'root'; private $DBname = 'blog'; public function connect(){ //Connect to mysql db } public function select($rows){ //select data from db } public function insert($rows){ //Insert data to db } public function delete($rows){ //Delete data from db } } class CheckData{ public $number1; public $number2; public function __construct(){ $this->number1 = $_POST['number1']; $this->number2 = $_POST['number2']; } function ISempty(){ if(!empty($this->$number1)){ echo "Not Empty"; $data = new Database(); $data->insert($this->$number1); } else{ echo "Empty1"; } if(!empty($this->$number2)){ echo "Not Empty"; $data = new Database(); $data->insert($this->$number2); } else{ echo "Empty2"; } } } class DisplayData{ //How print all data? function DisplayNumber(){ $data = new Database(); $data->select(); } } $check = new CheckData(); $check->ISempty(); $display = new DisplayData() $display->DisplayNumber(); ?>

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  • select2: "text is undefined" when getting json using ajax

    - by user3046715
    I'm having an issue when getting json results back to select2. My json does not return a result that has a "text" field so need to format the result so that select2 accepts "Name". This code works if the text field in the json is set to "text" but in this case, I cannot change the formatting of the json result (code outside my control). $("#e1").select2({ formatNoMatches: function(term) {return term +" does not match any items." }, ajax: { // instead of writing the function to execute the request we use Select2's convenient helper url: "localhost:1111/Items.json", dataType: 'jsonp', cache: true, quietMillis: 200, data: function (term, page) { return { q: term, // search term p: page, s: 15 }; }, results: function (data, page) { // parse the results into the format expected by Select2. var numPages = Math.ceil(data.total / 15); return {results: data.Data, numPages: numPages}; } } }); I have looked into the documentation and found some statements you can put into the results such as text: 'Name', but I am still getting "text is undefined". Thanks for any help.

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  • User input in Perl with IO::Socket

    - by David
    I am trying to make a perl program which allows a user to input the host and the port number of a foreign host to connect to using IO::Socket. It allows me to run the program and input a host and a port but it never connects and says "Could not connect to [host] at c:\users\USER\Documents\code\perl\sql.pl line 18, line 2." What am i doing wrong with this code shown below? And also, how can i have input validation on my host, which can either be a host name or an ip address? Thanks a bunch! Code Below use IO::Socket print "Host to connect to: "; chomp ($host = <STDIN>); print "Port to connect with: "; chomp ($port = <STDIN>); while(($port > 65535) || ($port <= 0)){ print "Port to connect with [Port > 0 < 65535] : "; chomp ($port = <STDIN>); } print "\nConnecting to host $host on port $port\n"; $socket = new IO::Socket::INET ( LocalHost => '$host', LocalPort => '$port', Proto => 'tcp', Listen => 5, Reuse => 1 ); die "Could not connect to $host";

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