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  • SSIS Basics: Using the Merge Join Transformation

    SSIS is able to take sorted data from more than one OLE DB data source and merge them into one table which can then be sent to an OLE DB destination. This 'Merge Join' transformation works in a similar way to a SQL join by specifying a 'join key' relationship. this transformation can save a great deal of processing on the destination. Annette Allen, as usual, gives clear guidance on how to do it.

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  • SSIS Basics: Using the Merge Join Transformation

    SSIS is able to take sorted data from more than one OLE DB data source and merge them into one table which can then be sent to an OLE DB destination. This 'Merge Join' transformation works in a similar way to a SQL join by specifying a 'join key' relationship. this transformation can save a great deal of processing on the destination. Annette Allen, as usual, gives clear guidance on how to do it.

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  • flXHR - getting started (a simple question)

    - by Yaron
    Hello, I am trying to use the flXHR javascript library for making cross-domain calls. I got stuck at the begining. As they say in the docs, I copied the /deploy directory's content to a /scripts directory. All the dependencies are supposed to be included in the flXHR download. This is my html, which returns several errors: the errors: y.base_path is undefined y.checkplayer is undefined y.ua is undefined E.attachEvent is not a function thanks

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  • Cross-Channel Survey Report

    - by David Dorf
    The folks at Retail Touchpoints surveyed 84 retailers on the topic of cross-channel and have published the results in Completing the Cross-Channel Challenge.  Below is an overview video that summarizes the findings and cites retailer examples. One thing is clear: customers demand Commerce Anywhere, the ability to shop when, where, and the way they want.  So retailers are doing what it takes to revamp their business to meet their customers' demands.

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  • Cross-Cultural Design (great video from HFI) - #usableapps #UX #L10n

    - by ultan o'broin
    Great video from HFI Animate, featuring user-centered design for emerging markets called Cross Cultural Design: Getting It Right the First Time. Cross Cultural Design: Getting It Right the First Time Apala Lahiri Chavan talks about the issues involved in designing solutions for Africa, India, China and more markets! Design for the local customer's ecosystem - and their feelings! Timely reminder of the important of global and local research in UX!

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  • Heaps of Trouble?

    - by Paul White NZ
    If you’re not already a regular reader of Brad Schulz’s blog, you’re missing out on some great material.  In his latest entry, he is tasked with optimizing a query run against tables that have no indexes at all.  The problem is, predictably, that performance is not very good.  The catch is that we are not allowed to create any indexes (or even new statistics) as part of our optimization efforts. In this post, I’m going to look at the problem from a slightly different angle, and present an alternative solution to the one Brad found.  Inevitably, there’s going to be some overlap between our entries, and while you don’t necessarily need to read Brad’s post before this one, I do strongly recommend that you read it at some stage; he covers some important points that I won’t cover again here. The Example We’ll use data from the AdventureWorks database, copied to temporary unindexed tables.  A script to create these structures is shown below: CREATE TABLE #Custs ( CustomerID INTEGER NOT NULL, TerritoryID INTEGER NULL, CustomerType NCHAR(1) COLLATE SQL_Latin1_General_CP1_CI_AI NOT NULL, ); GO CREATE TABLE #Prods ( ProductMainID INTEGER NOT NULL, ProductSubID INTEGER NOT NULL, ProductSubSubID INTEGER NOT NULL, Name NVARCHAR(50) COLLATE SQL_Latin1_General_CP1_CI_AI NOT NULL, ); GO CREATE TABLE #OrdHeader ( SalesOrderID INTEGER NOT NULL, OrderDate DATETIME NOT NULL, SalesOrderNumber NVARCHAR(25) COLLATE SQL_Latin1_General_CP1_CI_AI NOT NULL, CustomerID INTEGER NOT NULL, ); GO CREATE TABLE #OrdDetail ( SalesOrderID INTEGER NOT NULL, OrderQty SMALLINT NOT NULL, LineTotal NUMERIC(38,6) NOT NULL, ProductMainID INTEGER NOT NULL, ProductSubID INTEGER NOT NULL, ProductSubSubID INTEGER NOT NULL, ); GO INSERT #Custs ( CustomerID, TerritoryID, CustomerType ) SELECT C.CustomerID, C.TerritoryID, C.CustomerType FROM AdventureWorks.Sales.Customer C WITH (TABLOCK); GO INSERT #Prods ( ProductMainID, ProductSubID, ProductSubSubID, Name ) SELECT P.ProductID, P.ProductID, P.ProductID, P.Name FROM AdventureWorks.Production.Product P WITH (TABLOCK); GO INSERT #OrdHeader ( SalesOrderID, OrderDate, SalesOrderNumber, CustomerID ) SELECT H.SalesOrderID, H.OrderDate, H.SalesOrderNumber, H.CustomerID FROM AdventureWorks.Sales.SalesOrderHeader H WITH (TABLOCK); GO INSERT #OrdDetail ( SalesOrderID, OrderQty, LineTotal, ProductMainID, ProductSubID, ProductSubSubID ) SELECT D.SalesOrderID, D.OrderQty, D.LineTotal, D.ProductID, D.ProductID, D.ProductID FROM AdventureWorks.Sales.SalesOrderDetail D WITH (TABLOCK); The query itself is a simple join of the four tables: SELECT P.ProductMainID AS PID, P.Name, D.OrderQty, H.SalesOrderNumber, H.OrderDate, C.TerritoryID FROM #Prods P JOIN #OrdDetail D ON P.ProductMainID = D.ProductMainID AND P.ProductSubID = D.ProductSubID AND P.ProductSubSubID = D.ProductSubSubID JOIN #OrdHeader H ON D.SalesOrderID = H.SalesOrderID JOIN #Custs C ON H.CustomerID = C.CustomerID ORDER BY P.ProductMainID ASC OPTION (RECOMPILE, MAXDOP 1); Remember that these tables have no indexes at all, and only the single-column sampled statistics SQL Server automatically creates (assuming default settings).  The estimated query plan produced for the test query looks like this (click to enlarge): The Problem The problem here is one of cardinality estimation – the number of rows SQL Server expects to find at each step of the plan.  The lack of indexes and useful statistical information means that SQL Server does not have the information it needs to make a good estimate.  Every join in the plan shown above estimates that it will produce just a single row as output.  Brad covers the factors that lead to the low estimates in his post. In reality, the join between the #Prods and #OrdDetail tables will produce 121,317 rows.  It should not surprise you that this has rather dire consequences for the remainder of the query plan.  In particular, it makes a nonsense of the optimizer’s decision to use Nested Loops to join to the two remaining tables.  Instead of scanning the #OrdHeader and #Custs tables once (as it expected), it has to perform 121,317 full scans of each.  The query takes somewhere in the region of twenty minutes to run to completion on my development machine. A Solution At this point, you may be thinking the same thing I was: if we really are stuck with no indexes, the best we can do is to use hash joins everywhere. We can force the exclusive use of hash joins in several ways, the two most common being join and query hints.  A join hint means writing the query using the INNER HASH JOIN syntax; using a query hint involves adding OPTION (HASH JOIN) at the bottom of the query.  The difference is that using join hints also forces the order of the join, whereas the query hint gives the optimizer freedom to reorder the joins at its discretion. Adding the OPTION (HASH JOIN) hint results in this estimated plan: That produces the correct output in around seven seconds, which is quite an improvement!  As a purely practical matter, and given the rigid rules of the environment we find ourselves in, we might leave things there.  (We can improve the hashing solution a bit – I’ll come back to that later on). Faster Nested Loops It might surprise you to hear that we can beat the performance of the hash join solution shown above using nested loops joins exclusively, and without breaking the rules we have been set. The key to this part is to realize that a condition like (A = B) can be expressed as (A <= B) AND (A >= B).  Armed with this tremendous new insight, we can rewrite the join predicates like so: SELECT P.ProductMainID AS PID, P.Name, D.OrderQty, H.SalesOrderNumber, H.OrderDate, C.TerritoryID FROM #OrdDetail D JOIN #OrdHeader H ON D.SalesOrderID >= H.SalesOrderID AND D.SalesOrderID <= H.SalesOrderID JOIN #Custs C ON H.CustomerID >= C.CustomerID AND H.CustomerID <= C.CustomerID JOIN #Prods P ON P.ProductMainID >= D.ProductMainID AND P.ProductMainID <= D.ProductMainID AND P.ProductSubID = D.ProductSubID AND P.ProductSubSubID = D.ProductSubSubID ORDER BY D.ProductMainID OPTION (RECOMPILE, LOOP JOIN, MAXDOP 1, FORCE ORDER); I’ve also added LOOP JOIN and FORCE ORDER query hints to ensure that only nested loops joins are used, and that the tables are joined in the order they appear.  The new estimated execution plan is: This new query runs in under 2 seconds. Why Is It Faster? The main reason for the improvement is the appearance of the eager Index Spools, which are also known as index-on-the-fly spools.  If you read my Inside The Optimiser series you might be interested to know that the rule responsible is called JoinToIndexOnTheFly. An eager index spool consumes all rows from the table it sits above, and builds a index suitable for the join to seek on.  Taking the index spool above the #Custs table as an example, it reads all the CustomerID and TerritoryID values with a single scan of the table, and builds an index keyed on CustomerID.  The term ‘eager’ means that the spool consumes all of its input rows when it starts up.  The index is built in a work table in tempdb, has no associated statistics, and only exists until the query finishes executing. The result is that each unindexed table is only scanned once, and just for the columns necessary to build the temporary index.  From that point on, every execution of the inner side of the join is answered by a seek on the temporary index – not the base table. A second optimization is that the sort on ProductMainID (required by the ORDER BY clause) is performed early, on just the rows coming from the #OrdDetail table.  The optimizer has a good estimate for the number of rows it needs to sort at that stage – it is just the cardinality of the table itself.  The accuracy of the estimate there is important because it helps determine the memory grant given to the sort operation.  Nested loops join preserves the order of rows on its outer input, so sorting early is safe.  (Hash joins do not preserve order in this way, of course). The extra lazy spool on the #Prods branch is a further optimization that avoids executing the seek on the temporary index if the value being joined (the ‘outer reference’) hasn’t changed from the last row received on the outer input.  It takes advantage of the fact that rows are still sorted on ProductMainID, so if duplicates exist, they will arrive at the join operator one after the other. The optimizer is quite conservative about introducing index spools into a plan, because creating and dropping a temporary index is a relatively expensive operation.  It’s presence in a plan is often an indication that a useful index is missing. I want to stress that I rewrote the query in this way primarily as an educational exercise – I can’t imagine having to do something so horrible to a production system. Improving the Hash Join I promised I would return to the solution that uses hash joins.  You might be puzzled that SQL Server can create three new indexes (and perform all those nested loops iterations) faster than it can perform three hash joins.  The answer, again, is down to the poor information available to the optimizer.  Let’s look at the hash join plan again: Two of the hash joins have single-row estimates on their build inputs.  SQL Server fixes the amount of memory available for the hash table based on this cardinality estimate, so at run time the hash join very quickly runs out of memory. This results in the join spilling hash buckets to disk, and any rows from the probe input that hash to the spilled buckets also get written to disk.  The join process then continues, and may again run out of memory.  This is a recursive process, which may eventually result in SQL Server resorting to a bailout join algorithm, which is guaranteed to complete eventually, but may be very slow.  The data sizes in the example tables are not large enough to force a hash bailout, but it does result in multiple levels of hash recursion.  You can see this for yourself by tracing the Hash Warning event using the Profiler tool. The final sort in the plan also suffers from a similar problem: it receives very little memory and has to perform multiple sort passes, saving intermediate runs to disk (the Sort Warnings Profiler event can be used to confirm this).  Notice also that because hash joins don’t preserve sort order, the sort cannot be pushed down the plan toward the #OrdDetail table, as in the nested loops plan. Ok, so now we understand the problems, what can we do to fix it?  We can address the hash spilling by forcing a different order for the joins: SELECT P.ProductMainID AS PID, P.Name, D.OrderQty, H.SalesOrderNumber, H.OrderDate, C.TerritoryID FROM #Prods P JOIN #Custs C JOIN #OrdHeader H ON H.CustomerID = C.CustomerID JOIN #OrdDetail D ON D.SalesOrderID = H.SalesOrderID ON P.ProductMainID = D.ProductMainID AND P.ProductSubID = D.ProductSubID AND P.ProductSubSubID = D.ProductSubSubID ORDER BY D.ProductMainID OPTION (MAXDOP 1, HASH JOIN, FORCE ORDER); With this plan, each of the inputs to the hash joins has a good estimate, and no hash recursion occurs.  The final sort still suffers from the one-row estimate problem, and we get a single-pass sort warning as it writes rows to disk.  Even so, the query runs to completion in three or four seconds.  That’s around half the time of the previous hashing solution, but still not as fast as the nested loops trickery. Final Thoughts SQL Server’s optimizer makes cost-based decisions, so it is vital to provide it with accurate information.  We can’t really blame the performance problems highlighted here on anything other than the decision to use completely unindexed tables, and not to allow the creation of additional statistics. I should probably stress that the nested loops solution shown above is not one I would normally contemplate in the real world.  It’s there primarily for its educational and entertainment value.  I might perhaps use it to demonstrate to the sceptical that SQL Server itself is crying out for an index. Be sure to read Brad’s original post for more details.  My grateful thanks to him for granting permission to reuse some of his material. Paul White Email: [email protected] Twitter: @PaulWhiteNZ

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  • execute javascript function in a another iframe when parent is from different domain.

    - by Frushko
    The page A.com has 2 iframes B.com/page1 and B.com/page2. This is the code of A.com: <html><body> <iframe src="b.com/page1" name="iframe1" id="iframe1"> <iframe src="b.com/page2"> </body></html> I want to execute js function on B.com/page1 from B.com/page2. Both examples below works well when the parent is from the same domain but not in cross domain scenario: parent.window.frames['iframe1'].SomeFunction(args); or parent.document.getElementById('iframe1').contentWindow.SomeFunction(args); Is there any way to do it?

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  • Ubuntu and Windows 8 shared partition gets corrupted

    - by Bruno-P
    I have a dual boot (Ubuntu 12.04 and Windows 8) system. Both systems have access to an NTFS "DATA" partition which contains all my images, documents, music and some application data like Chrome and Thunderbird Profiles which used by both OS. Everything was working fine in my Dual boot Ubuntu/Windows 7, but after updating to Windows 8 I am having a lot of troubles. First, sometimes, I add some files from Ubuntu into my DATA partition but they don't show up in Windows. Sometimes, I can't even use the DATA partition from Windows. When I try to save a file it gives an error "The directory or file is corrupted or unreadable". I need to run checkdisk to fix it but after some time, same error appears. Before upgrading to Windows 8 I also installed a new hard drive and copied the old data using clonezilla (full disk clone). Here is the log of my last chkdisk: Chkdsk was executed in read/write mode. Checking file system on D: Volume dismounted. All opened handles to this volume are now invalid. Volume label is DATA. CHKDSK is verifying files (stage 1 of 3)... Deleted corrupt attribute list entry with type code 128 in file 67963. Unable to find child frs 0x12a3f with sequence number 0x15. The attribute of type 0x80 and instance tag 0x2 in file 0x1097b has allocated length of 0x560000 instead of 0x427000. Deleted corrupt attribute list entry with type code 128 in file 67963. Unable to locate attribute with instance tag 0x2 and segment reference 0x1e00000001097b. The expected attribute type is 0x80. Deleting corrupt attribute record (128, "") from file record segment 67963. Attribute record of type 0x80 and instance tag 0x3 is cross linked starting at 0x2431b2 for possibly 0x20 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x3 in file 0x1791e is already in use. Deleting corrupt attribute record (128, "") from file record segment 96542. Attribute record of type 0x80 and instance tag 0x4 is cross linked starting at 0x6bc7 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x4 in file 0x17e83 is already in use. Deleting corrupt attribute record (128, "") from file record segment 97923. Attribute record of type 0x80 and instance tag 0x4 is cross linked starting at 0x1f7cec for possibly 0x5 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x4 in file 0x17eaf is already in use. Deleting corrupt attribute record (128, "") from file record segment 97967. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x441bd7f for possibly 0x9 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x32085 is already in use. Deleting corrupt attribute record (128, "") from file record segment 204933. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4457850 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x320be is already in use. Deleting corrupt attribute record (128, "") from file record segment 204990. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4859249 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x3726b is already in use. Deleting corrupt attribute record (128, "") from file record segment 225899. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x485d309 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x3726c is already in use. Deleting corrupt attribute record (128, "") from file record segment 225900. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x48a47de for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37286 is already in use. Deleting corrupt attribute record (128, "") from file record segment 225926. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x48ac80b for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37287 is already in use. Deleting corrupt attribute record (128, "") from file record segment 225927. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x48ae7ef for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37288 is already in use. Deleting corrupt attribute record (128, "") from file record segment 225928. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x48af7f8 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x3728a is already in use. Deleting corrupt attribute record (128, "") from file record segment 225930. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x48c39b6 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37292 is already in use. Deleting corrupt attribute record (128, "") from file record segment 225938. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x495d37a for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x372d7 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226007. Attribute record of type 0xa0 and instance tag 0x5 is cross linked starting at 0x4d0bd38 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0xa0 and instance tag 0x5 in file 0x372dc is already in use. Deleting corrupt attribute record (160, $I30) from file record segment 226012. Attribute record of type 0xa0 and instance tag 0x5 is cross linked starting at 0x4c2d9bc for possibly 0x1 clusters. Some clusters occupied by attribute of type 0xa0 and instance tag 0x5 in file 0x372ed is already in use. Deleting corrupt attribute record (160, $I30) from file record segment 226029. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4a4c1c3 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37354 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226132. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4a8e639 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37376 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226166. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4a8f6eb for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37379 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226169. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4ae1aa8 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37391 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226193. Attribute record of type 0xa0 and instance tag 0x5 is cross linked starting at 0x4b00d45 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0xa0 and instance tag 0x5 in file 0x37396 is already in use. Deleting corrupt attribute record (160, $I30) from file record segment 226198. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4b02d50 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x3739c is already in use. Deleting corrupt attribute record (128, "") from file record segment 226204. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4b3407a for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x373a8 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226216. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4bd8a1b for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x373db is already in use. Deleting corrupt attribute record (128, "") from file record segment 226267. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4bd9a28 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x373dd is already in use. Deleting corrupt attribute record (128, "") from file record segment 226269. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4c2fb24 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x373f3 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226291. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4cb67e9 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37424 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226340. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4cba829 for possibly 0x2 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37425 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226341. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4cbe868 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37427 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226343. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4cbf878 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37428 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226344. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4cc58d8 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x3742a is already in use. Deleting corrupt attribute record (128, "") from file record segment 226346. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4ccc943 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x3742b is already in use. Deleting corrupt attribute record (128, "") from file record segment 226347. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4cd199b for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x3742d is already in use. Deleting corrupt attribute record (128, "") from file record segment 226349. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4cd29a8 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x3742f is already in use. Deleting corrupt attribute record (128, "") from file record segment 226351. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4cd39b8 for possibly 0x2 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37430 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226352. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4cd49c8 for possibly 0x2 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37432 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226354. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4cd9a16 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37435 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226357. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4cdca46 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37436 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226358. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4ce0a78 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37437 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226359. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4ce6ad9 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x3743a is already in use. Deleting corrupt attribute record (128, "") from file record segment 226362. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4cebb28 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x3743b is already in use. Deleting corrupt attribute record (128, "") from file record segment 226363. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4ceeb67 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x3743d is already in use. Deleting corrupt attribute record (128, "") from file record segment 226365. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4cf4bc6 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x3743e is already in use. Deleting corrupt attribute record (128, "") from file record segment 226366. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4cfbc3a for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37440 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226368. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4cfcc48 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37442 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226370. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4d02ca9 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37443 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226371. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4d06ce8 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37444 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226372. Attribute record of type 0xa0 and instance tag 0x5 is cross linked starting at 0x4d9a608 for possibly 0x2 clusters. Some clusters occupied by attribute of type 0xa0 and instance tag 0x5 in file 0x37449 is already in use. Deleting corrupt attribute record (160, $I30) from file record segment 226377. Attribute record of type 0xa0 and instance tag 0x5 is cross linked starting at 0x4d844ab for possibly 0x1 clusters. Some clusters occupied by attribute of type 0xa0 and instance tag 0x5 in file 0x3744b is already in use. Deleting corrupt attribute record (160, $I30) from file record segment 226379. Attribute record of type 0xa0 and instance tag 0x5 is cross linked starting at 0x4d6c32b for possibly 0x1 clusters. Some clusters occupied by attribute of type 0xa0 and instance tag 0x5 in file 0x3744c is already in use. Deleting corrupt attribute record (160, $I30) from file record segment 226380. Attribute record of type 0xa0 and instance tag 0x5 is cross linked starting at 0x4d2af25 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0xa0 and instance tag 0x5 in file 0x3744e is already in use. Deleting corrupt attribute record (160, $I30) from file record segment 226382. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4d0fd78 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x80 and instance tag 0x2 in file 0x37451 is already in use. Deleting corrupt attribute record (128, "") from file record segment 226385. Attribute record of type 0x80 and instance tag 0x2 is cross linked starting at 0x4d16ef8 for possibly 0x1 clusters. Some clusters occupied by attribute of type 0x8 Can anyone help? Thank you

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  • Example: Cross Cutting Concerns of an Application

    A little while ago I was given an opportunity to design and implement a new system that sent data via an HTTP Post method and then processed the results that were returned so that they could be inserted in to a database. My system had eight core concerns that it needed to fulfill. Eight Core Concerns Database Access Data Entities Worker Result Processing Process Flow Manager Email/Notification Error Handling Logging Of these eight, five were actually cross cutting concerns. 5 Cross Cutting Concerns Database Access Data Entities Email/Notification Error Handling Logging These five cross cutting concerns were determined after I created an aspect oriented model to help identity the system components that could be factored out into separate components.  These separated components would then be included in the system so that they could be used by various other components.  These five components allow all of the other components to access the database, store data, send notifications, handle errors, and log all system events.  Thus, these components are used to share unique aspects to the system via their implementation. The use of Aspect oriented architecture greatly helped me define what components I needed to create and what each of those components could do.  It also showed how all of the other aspects depended on each other so that each component did not have to re-implement code that was already created in the existing system.

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  • In SQL, a Join is actually an Intersection? And it is also a linkage or a "Sideway Union"?

    - by Jian Lin
    I always thought of a Join in SQL as some kind of linkage between two tables. For example, select e.name, d.name from employees e, departments d where employees.deptID = departments.deptID In this case, it is linking two tables, to show each employee with a department name instead of a department ID. And kind of like a "linkage" or "Union" sideway". But, after learning about inner join vs outer join, it shows that a Join (Inner join) is actually an intersection. For example, when one table has the ID 1, 2, 7, 8, while another table has the ID 7 and 8 only, the way we get the intersection is: select * from t1, t2 where t1.ID = t2.ID to get the two records of "7 and 8". So it is actually an intersection. So we have the "Intersection" of 2 tables. Compare this with the "Union" operation on 2 tables. Can a Join be thought of as an "Intersection"? But what about the "linking" or "sideway union" aspect of it?

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  • Flash doesn't connect to socket even though policy allows it

    - by Bart van Heukelom
    In my Flash app, I'm connecting to my server like this: Security.loadPolicyFile("xmlsocket://example.com:12860"); socket = new Socket("example.com", 12869); socket.writeByte(...); ... socket.flush(); At port 12860 I'm running a socket policy server, which (according to this document) correctly serves up my policy like this: 00000000 3c 70 6f 6c 69 63 79 2d 66 69 6c 65 2d 72 65 71 <policy- file-req 00000010 75 65 73 74 2f 3e 00 uest/>. 00000000 3c 63 72 6f 73 73 2d 64 6f 6d 61 69 6e 2d 70 6f <cross-d omain-po 00000010 6c 69 63 79 3e 3c 73 69 74 65 2d 63 6f 6e 74 72 licy><si te-contr 00000020 6f 6c 20 70 65 72 6d 69 74 74 65 64 2d 63 72 6f ol permi tted-cro 00000030 73 73 2d 64 6f 6d 61 69 6e 2d 70 6f 6c 69 63 69 ss-domai n-polici 00000040 65 73 3d 22 6d 61 73 74 65 72 2d 6f 6e 6c 79 22 es="mast er-only" 00000050 20 2f 3e 3c 61 6c 6c 6f 77 2d 61 63 63 65 73 73 /><allo w-access 00000060 2d 66 72 6f 6d 20 64 6f 6d 61 69 6e 3d 22 2a 22 -from do main="*" 00000070 20 74 6f 2d 70 6f 72 74 73 3d 22 31 32 38 36 39 to-port s="12869 00000080 22 20 2f 3e 3c 2f 63 72 6f 73 73 2d 64 6f 6d 61 " /></cr oss-doma 00000090 69 6e 2d 70 6f 6c 69 63 79 3e 00 in-polic y>. I get no security warnings, which I used to get before the policy server was in place. Still, the connection to port 12869 doesn't work. It's made (I can see with Wireshark and on the server), but no data is sent by Flash. It might be worth knowing that the SWF itself is served from example.com as well.

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  • What's the different between these 2 mysql queries? one using left join

    - by Lyon
    Hi, I see people using LEFT JOIN in their mysql queries to fetch data from two tables. But I normally do it without left join. Is there any differences besides the syntax, e.g. performance? Here's my normal query style: SELECT * FROM table1 as tbl1, table2 as tbl2 WHERE tbl1.id=tbl2.table_id as compared to SELECT * FROM table1 as tbl1 LEFT JOIN table2 as tbl2 on tbl1.id=tbl2.id Personally I prefer the first style...hmm..

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  • Why would I do an inner join on a non-distinct field?

    - by froadie
    I just came across a query that does an inner join on a non-distinct field. I've never seen this before and I'm a little confused about this usage. Something like: SELECT distinct all, my, stuff FROM myTable INNER JOIN myOtherTable ON myTable.nonDistinctField = myOtherTable.nonDistinctField (WHERE some filters here...) I'm not quite sure what my question is or how to phrase it, or why exactly this confuses me, but I was wondering if anyone could explain why someone would need to do an inner join on a non-distinct field and then select only distinct values...? Is there ever a legitimate use of an inner join on a non-distinct field? What would be the purpose? And if there's is a legitimate reason for such a query, can you give examples of where it would be used?

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  • In SQL / MySQL, can a Left Outer Join be used to find out the duplicates when there is no Primary ID

    - by Jian Lin
    I would like to try using Outer Join to find out duplicates in a table: If a table has Primary Index ID, then the following outer join can find out the duplicate names: mysql> select * from gifts; +--------+------------+-----------------+---------------------+ | giftID | name | filename | effectiveTime | +--------+------------+-----------------+---------------------+ | 2 | teddy bear | bear.jpg | 2010-04-24 04:36:03 | | 3 | coffee | coffee123.jpg | 2010-04-24 05:10:43 | | 6 | beer | beer_glass.png | 2010-04-24 05:18:12 | | 10 | heart | heart_shape.jpg | 2010-04-24 05:11:29 | | 11 | ice tea | icetea.jpg | 2010-04-24 05:19:53 | | 12 | cash | cash.png | 2010-04-24 05:27:44 | | 13 | chocolate | choco.jpg | 2010-04-25 04:04:31 | | 14 | coffee | latte.jpg | 2010-04-27 05:49:52 | | 15 | coffee | espresso.jpg | 2010-04-27 06:03:03 | +--------+------------+-----------------+---------------------+ 9 rows in set (0.00 sec) mysql> select * from gifts g1 LEFT JOIN (select * from gifts group by name) g2 on g1.giftID = g2.giftID where g2.giftID IS NULL; +--------+--------+--------------+---------------------+--------+------+----------+---------------+ | giftID | name | filename | effectiveTime | giftID | name | filename | effectiveTime | +--------+--------+--------------+---------------------+--------+------+----------+---------------+ | 14 | coffee | latte.jpg | 2010-04-27 05:49:52 | NULL | NULL | NULL | NULL | | 15 | coffee | espresso.jpg | 2010-04-27 06:03:03 | NULL | NULL | NULL | NULL | +--------+--------+--------------+---------------------+--------+------+----------+---------------+ 2 rows in set (0.00 sec) But what if the table doesn't have a Primary Index ID, then can an outer join still be used to find out duplicates?

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  • why this left join query failed to load all the data in left table ?

    - by lzyy
    users table +-----+-----------+ | id | username | +-----+-----------+ | 1 | tom | | 2 | jelly | | 3 | foo | | 4 | bar | +-----+-----------+ groups table +----+---------+-----------------------------+ | id | user_id | title | +----+---------+-----------------------------+ | 2 | 1 | title 1 | | 4 | 1 | title 2 | +----+---------+-----------------------------+ the query SELECT users.username,users.id,count(groups.title) as group_count FROM users LEFT JOIN groups ON users.id = groups.user_id result +----------+----+-------------+ | username | id | group_count | +----------+----+-------------+ | tom | 1 | 2 | +----------+----+-------------+ where is the rest users' info? the result is the same as inner join , shouldn't left join return all left table's data? PS:I'm using mysql

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  • Is it a Good Practice to Add two Conditions when using a JOIN keyword?

    - by Raúl Roa
    I'd like to know if having to conditionals when using a JOIN keyword is a good practice. I'm trying to filter this resultset by date but I'm unable to get all the branches listed even if there's no expense or income for a date using a WHERE clause. Is there a better way of doing this, if so how? SELECT Branches.Name ,SUM(Expenses.Amount) AS Expenses ,SUM(Incomes.Amount) AS Incomes FROM Branches LEFT JOIN Expenses ON Branches.Id = Expenses.BranchId AND Expenses.Date = '3/11/2010' LEFT JOIN Incomes ON Branches.Id = Incomes.BranchId AND Incomes.Date = '3/11/2010' GROUP BY Branches.Name

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  • In SQL / MySQL, what is the difference between "On" and "Where" in a join statement?

    - by Jian Lin
    The following statements give the same result (one is using "on", and the other using "where"): mysql> select * from gifts INNER JOIN sentGifts on gifts.giftID = sentGifts.giftID; mysql> select * from gifts INNER JOIN sentGifts where gifts.giftID = sentGifts.giftID; I can only see in a case of a Left Outer Join finding the "unmatched" cases: (to find out the gifts that were never sent by anybody) mysql> select name from gifts LEFT OUTER JOIN sentgifts on gifts.giftID = sentgifts.giftID where sentgifts.giftID IS NULL; In this case, it is first using "on", and then "where". Does the "on" first do the matching, and then "where" does the "secondary" filtering? Or is there a more general rule of using "on" versus "where"? Thanks.

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  • Does it make sense to replace sub-queries by join?

    - by Roman
    For example I have a query like that. select col1 from t1 where col2>0 and col1 in (select col1 from t2 where col2>0) As far as I understand, I can replace it by the following query: select t1.col1 from t1 join (select col1 from t2 where col2>0) as t2 on t1.col1=t2.col1 where t1.col2>0 ADDED In some answers I see join in other inner join. Are both right? Or they are even identical?

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  • Limitations of the SharePoint join using CAML

    - by ybbest
    Limitation One In SharePoint 2010, you can join the primary list to a foreign list and include more than one field from the foreign list. However, the limitation is that the included fields from foreign list have to be the following type: Calculated (treated as plain text) ContentTypeId Counter Currency DateTime Guid Integer Note (one-line only) Number Text The above limitation also explains why you cannot include some types of the fields from the remote list when creating a lookup. Limitation Two When using CAML query to join SharePoint lists, there can be joins to multiple lists, multiple joins to the same list, and chains of joins. However, the limitations are only inner and left outer joins are permitted and the field in the primary list must be a Lookup type field that looks up to the field in the foreign list. Limitation Three The support for writing the JOIN query in CAML is very limited.I have to hand-code the CAML query to join the lists,not fun at all.Although some blogs post mentioned about using LINQ to SharePoint and get the CAML code from there , but I never get it to work.You can check this blog post  for this.Let me know if it works for you. References: http://msdn.microsoft.com/en-us/library/ee535502.aspx http://msdn.microsoft.com/en-us/library/microsoft.sharepoint.spquery.joins.aspx

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  • Topics for development team cross training sessions

    - by BBlake
    Our team of developers are going to start holding monthly meetings for the purposes of cross training and knowledge improvement. We're looking for ideas for topics to discuss. We've already made a list of some obvious ones, such as discussions/training on specific applications, proper usage of TFS for source control, bug tracking and code reviews, coding standards, and corporate architecture. The problem we're having is that we are a cross-platform development team so we don't want to look at topics that only apply to certain members of the team (Sql, .NET, reporting, third party apps, etc). We'll use sub-team meetings for those. So what other topics that would apply across a broad development team would be good for these training sessions?

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  • Hosting cross-domain Silverlight applications (XAP)

    In the Silverlight world, there are two types of cross-domain things that may leave some banging their head against a wall for a while. The first involves making network-based calls (WebClient, HttpWebRequest, etc) to services hosted on a domain other than the one that is the site of origin for the XAP. This is solved by ensuring the service provider enables a clientaccesspolicy.xml file for their service. More information here: Cross Domain Policy Files with Silverlight. NOTE: site of origin is...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Google I/O 2012 - Fast UIs for the Cross-Device Web

    Google I/O 2012 - Fast UIs for the Cross-Device Web Boris Smus One of the great features of the modern web is that sites work on any device with a browser. This session will focus on creating UIs for the cross-device web. We will cover building web sites that support multiple device form factors (responsive and non-responsive approaches), discuss single page sites and some of the layout features in modern mobile browsers, and do a deep dive into multi-touch input on the web. Finally, we'll show some of the awesome new mobile debugging tools in Chrome and Chrome for Android. For all I/O 2012 sessions, go to developers.google.com From: GoogleDevelopers Views: 105 3 ratings Time: 49:31 More in Science & Technology

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  • SQL Outer Join on a bunch of Inner Joined results

    - by Matthew Frederick
    I received some great help on joining a table to itself and am trying to take it to the next level. The SQL below is from the help but with my addition of the select line beginning with COUNT, the inner join to the Recipient table, and the Group By. SELECT Event.EventID AS EventID, Event.EventDate AS EventDateUTC, Participant2.ParticipantID AS AwayID, Participant1.ParticipantID AS HostID, COUNT(Recipient.ChallengeID) AS AllChallenges FROM Event INNER JOIN Matchup Matchup1 ON (Event.EventID = Matchup1.EventID) INNER JOIN Matchup Matchup2 ON (Event.EventID = Matchup2.EventID) INNER JOIN Participant Participant1 ON (Matchup1.Host = 1 AND Matchup1.ParticipantID = Participant1.ParticipantID) INNER JOIN Participant Participant2 ON (Matchup2.Host != 1 AND Matchup2.ParticipantID = Participant2.ParticipantID) INNER JOIN Recipient ON (Event.EventID = Recipient.EventID) WHERE Event.CategoryID = 1 AND Event.Resolved = 0 AND Event.Type = 1 GROUP BY Recipient.ChallengeID ORDER BY EventDateUTC ASC My goal is to get a count of how many rows in the Recipient table match the EventID in Event. This code works fine except that I also want to get results where there are 0 matching rows in Recipient. I want 15 rows (= the number of events) but I get 2 rows, one with a count of 1 and one with a count of 2 (which is appropriate for an inner join as there are 3 rows in the sample Recipient table, one for one EventID and two for another EventID). I thought that either a LEFT join or an OUTER join was what I was looking for, but I know that I'm not quite getting how the tables are actually joined. A LEFT join there gives me one more row with 0, which happens to be EventID 1 (first thing in the table), but that's all. Errors advise me that I can't just change that INNER join to an OUTER. I tried some parenthesizing and some subselects and such but can't seem to make it work.

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