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  • Computer Science graduate. Master or full-time job? [closed]

    - by Alex
    Possible Duplicate: Is a Master's worth it? I have just gotten my Bachelor's Degree in Computer Science and I have to make choice. Whether to continue with my full-time job I just got or put the job slightly in the background and concentrate on getting a Master's degree. I am currently working as an embedded C developer in a small company. The cool thing is that, because the team is quite small, my engineering ideas really play a part in the final product. Not to mention that I get to work on very different areas of embedded programming: device drivers and development of a Real Time OS. I am very enthusiastic about my job and what I do. On the other hand, in my country there isn't really a master's degree that focuses on embedded development so my gain from getting this degree will mainly in the field of general computer science knowledge. That being said, is it worth giving up all my spare time which I now use to study different areas of embedded devices and work mainly to get a degree rather than pure knowledge and experience in the field I want to work in?

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  • Do you know of a C macro to compute Unix time and date?

    - by Alexis Wilke
    I'm wondering if someone knows/has a C macro to compute a static Unix time from a hard coded date and time as in: time_t t = UNIX_TIMESTAMP(2012, 5, 10, 9, 26, 13); I'm looking into that because I want to have a numeric static timestamp. This will be done hundred of times throughout the software, each time with a different date, and I want to make sure it is fast because it will run hundreds of times every second. Converting dates that many times would definitively slow down things (i.e. calling mktime() is slower than having a static number compiled in place, right?) [made an update to try to render this paragraph clearer, Nov 23, 2012] Update I want to clarify the question with more information about the process being used. As my server receives requests, for each request, it starts a new process. That process is constantly updated with new plugins and quite often such updates require a database update. Those must be run only once. To know whether an update is necessary, I want to use a Unix date (which is better than using a counter because a counter is much more likely to break once in a while.) The plugins will thus receive an update signal and have their on_update() function called. There I want to do something like this: void some_plugin::on_update(time_t last_update) { if(last_update < UNIX_TIMESTAMP(2010, 3, 22, 20, 9, 26)) { ...run update... } if(last_update < UNIX_TIMESTAMP(2012, 5, 10, 9, 26, 13)) { ...run update... } // as many test as required... } As you can see, if I have to compute the unix timestamp each time, this could represent thousands of calls per process and if you receive 100 hits a second x 1000 calls, you wasted 100,000 calls when you could have had the compiler compute those numbers once at compile time. Putting the value in a static variable is of no interest because this code will run once per process run. Note that the last_update variable changes depending on the website being hit (it comes from the database.) Code Okay, I got the code now: // helper (Days in February) #define _SNAP_UNIX_TIMESTAMP_FDAY(year) \ (((year) % 400) == 0 ? 29LL : \ (((year) % 100) == 0 ? 28LL : \ (((year) % 4) == 0 ? 29LL : \ 28LL))) // helper (Days in the year) #define _SNAP_UNIX_TIMESTAMP_YDAY(year, month, day) \ ( \ /* January */ static_cast<qint64>(day) \ /* February */ + ((month) >= 2 ? 31LL : 0LL) \ /* March */ + ((month) >= 3 ? _SNAP_UNIX_TIMESTAMP_FDAY(year) : 0LL) \ /* April */ + ((month) >= 4 ? 31LL : 0LL) \ /* May */ + ((month) >= 5 ? 30LL : 0LL) \ /* June */ + ((month) >= 6 ? 31LL : 0LL) \ /* July */ + ((month) >= 7 ? 30LL : 0LL) \ /* August */ + ((month) >= 8 ? 31LL : 0LL) \ /* September */+ ((month) >= 9 ? 31LL : 0LL) \ /* October */ + ((month) >= 10 ? 30LL : 0LL) \ /* November */ + ((month) >= 11 ? 31LL : 0LL) \ /* December */ + ((month) >= 12 ? 30LL : 0LL) \ ) #define SNAP_UNIX_TIMESTAMP(year, month, day, hour, minute, second) \ ( /* time */ static_cast<qint64>(second) \ + static_cast<qint64>(minute) * 60LL \ + static_cast<qint64>(hour) * 3600LL \ + /* year day (month + day) */ (_SNAP_UNIX_TIMESTAMP_YDAY(year, month, day) - 1) * 86400LL \ + /* year */ (static_cast<qint64>(year) - 1970LL) * 31536000LL \ + ((static_cast<qint64>(year) - 1969LL) / 4LL) * 86400LL \ - ((static_cast<qint64>(year) - 1901LL) / 100LL) * 86400LL \ + ((static_cast<qint64>(year) - 1601LL) / 400LL) * 86400LL ) WARNING: Do not use these macros to dynamically compute a date. It is SLOWER than mktime(). This being said, if you have a hard coded date, then the compiler will compute the time_t value at compile time. Slower to compile, but faster to execute over and over again.

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  • Inserting Records in Ascending Order function- C homework assignment

    - by Aaron McRuer
    Good day, Stack Overflow. I have a homework assignment that I'm working on this weekend that I'm having a bit of a problem with. We have a struct "Record" (which contains information about cars for a dealership) that gets placed in a particular spot in a linked list according to 1) its make and 2) according to its model year. This is done when initially building the list, when a "int insertRecordInAscendingOrder" function is called in Main. In "insertRecordInAscendingOrder", a third function, "createRecord" is called, where the linked list is created. The function then goes to the function "compareCars" to determine what elements get put where. Depending on the value returned by this function, insertRecordInAscendingOrder then places the record where it belongs. The list is then printed out. There's more to the assignment, but I'll cross that bridge when I come to it. Ideally, and for the assignment to be considered correct, the linked list must be ordered as: Chevrolet 2012 25 Chevrolet 2013 10 Ford 2010 5 Ford 2011 3 Ford 2012 15 Honda 2011 9 Honda 2012 3 Honda 2013 12 Toyota 2009 2 Toyota 2011 7 Toyota 2013 20 from the a text file that has the data ordered the following way: Ford 2012 15 Ford 2011 3 Ford 2010 5 Toyota 2011 7 Toyota 2012 20 Toyota 2009 2 Honda 2011 9 Honda 2012 3 Honda 2013 12 Chevrolet 2013 10 Chevrolet 2012 25 Notice that the alphabetical order of the "make" field takes precedence, then, the model year is arranged from oldest to newest. However, the program produces this as the final list: Chevrolet 2012 25 Chevrolet 2013 10 Honda 2011 9 Honda 2012 3 Honda 2013 12 Toyota 2009 2 Toyota 2011 7 Toyota 2012 20 Ford 2010 5 Ford 2011 3 Ford 2012 15 I sat down with a grad student and tried to work out all of this yesterday, but we just couldn't figure out why it was kicking the Ford nodes down to the end of the list. Here's the code. As you'll notice, I included a printList call at each instance of the insertion of a node. This way, you can see just what is happening when the nodes are being put in "order". It is in ANSI C99. All function calls must be made as they are specified, so unfortunately, there's no real way of getting around this problem by creating a more efficient algorithm. #include <stdio.h> #include <stdlib.h> #include <string.h> #define MAX_LINE 50 #define MAX_MAKE 20 typedef struct record { char *make; int year; int stock; struct record *next; } Record; int compareCars(Record *car1, Record *car2); void printList(Record *head); Record* createRecord(char *make, int year, int stock); int insertRecordInAscendingOrder(Record **head, char *make, int year, int stock); int main(int argc, char **argv) { FILE *inFile = NULL; char line[MAX_LINE + 1]; char *make, *yearStr, *stockStr; int year, stock, len; Record* headRecord = NULL; /*Input and file diagnostics*/ if (argc!=2) { printf ("Filename not provided.\n"); return 1; } if((inFile=fopen(argv[1], "r"))==NULL) { printf("Can't open the file\n"); return 2; } /*obtain values for linked list*/ while (fgets(line, MAX_LINE, inFile)) { make = strtok(line, " "); yearStr = strtok(NULL, " "); stockStr = strtok(NULL, " "); year = atoi(yearStr); stock = atoi(stockStr); insertRecordInAscendingOrder(&headRecord,make, year, stock); } printf("The original list in ascending order: \n"); printList(headRecord); } /*use strcmp to compare two makes*/ int compareCars(Record *car1, Record *car2) { int compStrResult; compStrResult = strcmp(car1->make, car2->make); int compYearResult = 0; if(car1->year > car2->year) { compYearResult = 1; } else if(car1->year == car2->year) { compYearResult = 0; } else { compYearResult = -1; } if(compStrResult == 0 ) { if(compYearResult == 1) { return 1; } else if(compYearResult == -1) { return -1; } else { return compStrResult; } } else if(compStrResult == 1) { return 1; } else { return -1; } } int insertRecordInAscendingOrder(Record **head, char *make, int year, int stock) { Record *previous = *head; Record *newRecord = createRecord(make, year, stock); Record *current = *head; int compResult; if(*head == NULL) { *head = newRecord; printf("Head is null, list was empty\n"); printList(*head); return 1; } else if ( compareCars(newRecord, *head)==-1) { *head = newRecord; (*head)->next = current; printf("New record was less than the head, replacing\n"); printList(*head); return 1; } else { printf("standard case, searching and inserting\n"); previous = *head; while ( current != NULL &&(compareCars(newRecord, current)==1)) { printList(*head); previous = current; current = current->next; } printList(*head); previous->next = newRecord; previous->next->next = current; } return 1; } /*creates records from info passed in from main via insertRecordInAscendingOrder.*/ Record* createRecord(char *make, int year, int stock) { printf("CreateRecord\n"); Record *theRecord; int len; if(!make) { return NULL; } theRecord = malloc(sizeof(Record)); if(!theRecord) { printf("Unable to allocate memory for the structure.\n"); return NULL; } theRecord->year = year; theRecord->stock = stock; len = strlen(make); theRecord->make = malloc(len + 1); strncpy(theRecord->make, make, len); theRecord->make[len] = '\0'; theRecord->next=NULL; return theRecord; } /*prints list. lists print.*/ void printList(Record *head) { int i; int j = 50; Record *aRecord; aRecord = head; for(i = 0; i < j; i++) { printf("-"); } printf("\n"); printf("%20s%20s%10s\n", "Make", "Year", "Stock"); for(i = 0; i < j; i++) { printf("-"); } printf("\n"); while(aRecord != NULL) { printf("%20s%20d%10d\n", aRecord->make, aRecord->year, aRecord->stock); aRecord = aRecord->next; } printf("\n"); } The text file you'll need for a command line argument can be saved under any name you like; here are the contents you'll need: Ford 2012 15 Ford 2011 3 Ford 2010 5 Toyota 2011 7 Toyota 2012 20 Toyota 2009 2 Honda 2011 9 Honda 2012 3 Honda 2013 12 Chevrolet 2013 10 Chevrolet 2012 25 Thanks in advance for your help. I shall continue to plow away at it myself.

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  • At what year in history was computers first used to store porn? [closed]

    - by Emil H
    Of course this sounds like a joke question, but it's meant seriously. I remember being told by an old system administrator back in the early nineties about people asking about good FTPs for porn, and that they would as a joke always tell them to connect to 127.0.0.1. They would come back saying that there was a lot of porn at that address, but that oddly enough it seemed like they already had it all. Point being, it seems like it's been around for quite a while. Anyway. Considering that a considerable portion of the internet is devoted to porn these days, it would be interesting to know if someone has any kind of idea as to when and where the phenomena first arose? There must be some mention of this in old hacker folk lore? (Changed to CW to emphasize that this isn't about rep, but about genuine curiousity. :)

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  • Have optical drive connectors changed in the last year?

    - by Zippityboomba
    In early 2010 my motherboard freaked out, and I was able to drop in a new board and connect my two DVD drives that were initially bought in 2005. Tonight my new components arrived to build my next system, and I figured I'd just reuse the old DVD drives. Surprise, the long flat connector cable has no mate on the new motherboard. Reckon I'll just pick up a new DVD drive for $25, but what gives? Thanks!

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  • Like to Upgrade My PC (7 year old) - for animation and hardcore gaming ! - help me [closed]

    - by sri
    I like to buy a new computer for my studies and as well as gaming. My old pc has 1.5 GB RAM with 512MB Graphics card. And it is very old to run Adobe CS5 version and other high end animation software. My budget will be INR 20k-25k. I have 500GB hard disk, keyboard and mouse new. So apart from this, I like to buy : Intel or AMD is good ? My idea is : Corei5 or Corei7 = which is best and economy ? Which mother board. 4 GB RAM with upto 8 GB RAM slot for future upgrade. 1 GB or 2 GB Graphic card - which one ? If I am wrong - please suggest me

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  • Skype Mac API - Use AppleScript or 5 year old API?

    - by Andrew
    I have a x86_64 app that I would like to have optionally read Skype status messages. However, the 5 year old skype mac framework is 32-bit, and if there is a way to have that compile within a 64-bit app, I haven't found it. My question is, basically, how should I go about doing this? I really only need to get and set the USERSTATUS AWAY/ONLINE string. Using AppleScript, a "Should Skype allow this" dialog pops up... every time. This is highly inefficient and downright irritating. Advice? I'm considering writing a 32-bit CLI wrapper, but that seems like overkill.

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  • What production software have you written in F# in the past year or so that you would previously hav

    - by Peter McGrattan
    Over the last few years F# has evolved into one of Microsoft's fully supported languages employing many ideas incubated in OCaml, ML and Haskell. Over the last several years C# has extended it's general purpose features by introducing more and more functional language features: LINQ (list comprehension), Lamdas, Closures, Anonymous Delegates and more... Given C#'s adoption of these functional features and F#'s taxonomy as an impure functional language (it allows YOU to access framework libraries or change shared state when a function is called if you want to) there is a strong similarity between the two languages although each has it's own polar opposite primary emphasis. I'm interested in any successful models employing these two languages in your production polyglot programs and also the areas within production software (web apps, client apps, server apps) you have written in F# in the past year or so that you would previously have written in C#.

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  • where to store information like gender and year of birth?

    - by fayer
    i have users and i need them to specify a gender (male, female) and year of birth (1930, 1931...1999, 2000). i wonder where i should store these values: in the database? in php file? if i store them in the database i have to manually create all entries first. but a good thing is that the user table will have constraints so the gender field will always be male or female, it cannot be something else. if i store them in the php file (eg. as html) then i can easily add/remove values. but a con is that i dont have the constraints in database, so another value could be stored as gender by mistake, even though i could add validation in php backend so even if someone hacked the html it is not stored unless it's either male or female. what is best practice to do this? thanks

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  • Min-Ordered Bionomial Heap Insertion java

    - by Charodd Richardson
    Im writing a java code to make a min-ordered Binomial Heap and I have to Insert and Remove-min. I'm having a very big problem inserting into the Heap. I have been stuck on this for a couple of days now and it is due tomorrow. Whenever I go to insert, It only prints out the item I insert instead of the whole tree (which is in preorder). Such as if I insert 1 it prints (1) and then I go to insert 2 it prints out (2) instead of (1(2)) It keeps printing out only the number I insert last instead of the whole preordered tree. I would be very grateful if someone could help me with this problem. Thank you so much in advance, Here is my code. public class BHeap { int key; int degree;//The degree(Number of children) BHeap parent, leftmostChild, rightmostChild, rightSibling,root,previous,next; public BHeap(){ key =0; degree=0; parent =null; leftmostChild=null; rightmostChild=null; rightSibling=null; root=null; previous=null; next=null; } public BHeap merge(BHeap x, BHeap y){ BHeap newHeap = new BHeap(); y.rightSibling=x.root; BHeap currentHeap = y; BHeap nextHeap = y.rightSibling; while(currentHeap.rightSibling !=null){ if(currentHeap.degree==nextHeap.degree){ if(currentHeap.key<nextHeap.key){ if(currentHeap.degree ==0){ currentHeap.leftmostChild=nextHeap; currentHeap.rightmostChild=nextHeap; currentHeap.rightSibling=nextHeap.rightSibling; nextHeap.rightSibling=null; nextHeap.parent=currentHeap; currentHeap.degree++; } else{ newHeap = currentHeap; newHeap.rightmostChild.rightSibling=nextHeap; newHeap.rightmostChild=nextHeap; nextHeap.parent=newHeap; newHeap.degree++; nextHeap.rightSibling=null; nextHeap=newHeap.rightSibling; } } else{ if(currentHeap.degree==0){ nextHeap.rightmostChild=currentHeap; nextHeap.rightmostChild.root = nextHeap.rightmostChild;//add nextHeap.leftmostChild=currentHeap; nextHeap.leftmostChild.root = nextHeap.leftmostChild;//add currentHeap.parent=nextHeap; currentHeap.rightSibling=null; currentHeap.root=currentHeap;//add nextHeap.degree++; } else{ newHeap=nextHeap; newHeap.rightmostChild.rightSibling=currentHeap; newHeap.rightmostChild=currentHeap; currentHeap.parent= newHeap; newHeap.degree++; currentHeap=newHeap.rightSibling; currentHeap.rightSibling=null; } } } else{ currentHeap=currentHeap.rightSibling; nextHeap=nextHeap.rightSibling; } } return y; } public void Insert(int x){ /*BHeap newHeap = new BHeap(); newHeap.key=x; if(this.root==null){ this.root=newHeap; return; } else{ this.root=merge(newHeap,this.root); }*/ BHeap newHeap= new BHeap(); newHeap.key=x; if(this.root==null){ this.root=newHeap; } else{ this.root = merge(this,newHeap); }} public void RemoveMin(){ BHeap newHeap = new BHeap(); BHeap child = new BHeap(); newHeap=this; BHeap pos = newHeap.next; while(pos !=null){ if(pos.key<newHeap.key){ newHeap=pos; } pos=pos.rightSibling; } pos=this; BHeap B1 = new BHeap(); if(newHeap.previous!=null){ newHeap.previous.rightSibling=newHeap.rightSibling; B1 =pos.leftmostChild; B1.rightSibling=pos; pos.leftmostChild=pos.rightmostChild.leftmostChild; } else{ newHeap=newHeap.rightSibling; newHeap.previous.rightSibling=newHeap.rightSibling; B1 =pos.leftmostChild; B1.rightSibling=pos; pos.leftmostChild=pos.rightmostChild.leftmostChild; } merge(newHeap,B1); } public void Display(){ System.out.print("("); System.out.print(this.root.key); if(this.leftmostChild != null){ this.leftmostChild.Display(); } System.out.print(")"); if(this.rightSibling!=null){ this.rightSibling.Display(); } } }

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  • The script not working as expected files dump path

    - by user3319390
    I have a script needs to be dump matching cname from my file contains and then matching scode to dump file to $cname/$year/$month/$day/ into files like access and error logs #!/bin/sh #base_dir="/home/vizion/Desktop" path="/home/vizion/Desktop/adn_DF9D_20140515_0005.log" name=$(basename "$path" ".log") for x in *.log; do year=${x:9:4}; month=${x:13:2}; day=${x:15:2}; done while read -r line do cname=$(echo ${line} | awk '{split($7,c,"/"); print c[3]}') scode=$(echo ${line} | awk -F"[ ]" '{print $9}') [[ ! -d "$cname/$year/$month/$day" ]] && mkdir -p "$cname/$year/$month/$day/" [[ ( ${scode} -ge 200 ) && ( ${scode} -le 399 ) ]] && { # [[ ! -d "$cname/$year/$month/$day" ]] && mkdir -p "$cname/$year/$month/$day/" echo ${line} >> /home/vizion/Desktop/$cname/$year/$month/$day/${cname}_${name}_access.log } [[ ( ${scode} -ge 400 ) && ( ${scode} -le 599 ) ]] && { [[ ! -d "$cname/$year/$month/$day" ]] && mkdir -p "$cname/$year/$month/$day" echo ${line} >> ${cname}_${name}_error.log } done < $path i am able to filter logs but not not dumping the exact location It's going other locations suggest to me correction in script

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  • Die glücklichen Gewinner der Oracle Partner Awards Germany 2012

    - by A&C Redaktion
    Es war ein Höhepunkt des Oracle Partner Days: Die Award Ceremony, auf der deutsche Oracle Partner für ihr besonderes Engagement und herausragende Erfolge bei der Spezialisierung ausgezeichnet wurden. Jeder Preisträger erhielt neben dem Award eine Urkunde sowie einen Wertscheck in Höhe von 2.000 Euro für eine Demand Generation Kampagne. Wir gratulieren allen Gewinnern ganz herzlich und stellen sie Ihnen im Folgenden kurz vor:Database Partner of the Year Germany: inforsacom Informationssysteme GmbHDass der EMEA Database Partner of the Year inforsacom auch im bundesweiten Vergleich überzeugen würde, war keine große Überraschung, ist aber ein Riesenerfolg! Übrigens war inforsacom auch schon 2011 unter den Preisträgern des OPN Day Satellite (wir berichteten). Der Platinum Partner inforsacom Informationssysteme GmbH entwickelt und liefert seit 1997 integrierte IT-Lösungen im Data-Center. Als „trusted advisor“ ist es ein Schwerpunkt von Inforsacom, in der Beratung den größtmöglichen Kundennutzen aufzuzeigen. inforsacom setzt einen deutlichen Fokus auf Oracle Datenbanktechnologien sowie das Hardware und Engineered Systems Portfolio -  inklusive der damit verbundenen Spezialisierung und Ausbildung der Mitarbeiter. Middleware Partner of the Year Germany: People at Work Systems AGZum Middleware Partner of the Year wurde die People at Work Systems AG gekürt, ein Software- und Beratungsunternehmen aus München, das  Kunden individuelle Dienstleistungen und Lösungen für Customer Relationship Management (CRM) und  Business Process Management (BPM) auf der Basis von Oracle anbietet. Seit Jahren zeigt der Oracle Partner ein hohes Commitment zu Oracle, unter anderem durch sein umfassendes Engagement im Rahmen der Solution Partner Community SOA. Die große technologische und vertriebliche Kompetenz in Sachen BPM, SOA & Integration hat die People at Work GmbH in verschiedenen komplexen Fusion Middleware-Projekten erfolgreich unter Beweis gestellt. Applications Partner of the Year Germany: ifb AGDie ifb-group deckt als einer der wenigen Partner das komplette Hyperion, Oracle EPM und BI Portfolio ab. Dabei ist das Markenzeichen der ifb die enge Verbindung von Fachexpertise und Umsetzungsstärke, denn weltweit setzen über 800 Unternehmen seit vielen Jahren erfolgreich auf Lösungen der ifb. Der Award „Applications Partner of the Year“ würdigt die Spezialisierung der ifb auf EPM. Industry Partner of the Year Germany: PORTRIX LOGISTIC SOFTWARE GmbHÜber den Preis als bester Industry Partner freute sich die PORTRIX LOGISTIC SOFTWARE GmbH aus Hamburg, eine Tochter der portrix.net GmbH. Mit einer eigenen Software-Lösung bietet der ISV Speditionen eine Lösung an, die die Abrechnung und Transparenz von Vertragskonditionen über die ganze Transportkette hinweg vereinfacht. Die Unternehmensgruppe portrix.net ist mit mehr als vier Spezialisierungen mit sehr gutem Oracle Know-how ausgestattet und somit in der Lage, zu unterschiedlichsten Anforderungen von Endkunden und Oracle Partnern exzellent zu beraten. Oracle Accelerate Partner of the Year Germany: ICP Solution GmbHICP Solution unterstützt als "One-Stop-Shop" auf dem europäischen Markt Kunden in allen Fragen rund um PLM und Agile von Oracle. Das Leistungsspektrum reicht dabei von der Prozessoptimierung und PLM Einführung, über ERP Integration bis hin zum Wartungsvertrag und speziellen Schulungen.Server & Storage Systems Partner of the Year Germany: CCF AGDie CCF AG ist schon seit 19 Jahren ein überzeugter Sun/Oracle Partner, der ca. 90% seines Umsatzes mit Sun/Oracle Produkten macht. Als flexibles regionales Unternehmen mit angeschlossener Consulting Firma, die auf Solaris und Unix spezialisiert ist, ist die CCF einer der wenigen Oracle Partner mit eigenen Solaris Administratoren. Der Award würdigt auch die herausragenden Umsatzergebnisse von CCF im Hardware Segment.Oracle on Oracle Partner of the Year Germany: anykey GmbHAuch ankey ist bereits ein langjähriger Partner von Sun/Oracle und verfügt über hohes Consulting-Know-how. 2012 ist anykey richtig durchgestartet: Viele Zertifizierungen sowie Datenbankspezialisierung wurden erworben und der Platinum Partner hat sich damit den Bereich „Oracle on Oracle“ erschlossen. Durch die erfolgreiche Platzierung bei Kunden konnte anykey im letzten Fiskaljahr sogar den Umsatz verdoppeln.

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  • Die glücklichen Gewinner der Oracle Partner Awards Germany 2012

    - by A&C Redaktion
    Es war ein Höhepunkt des Oracle Partner Days: Die Award Ceremony, auf der deutsche Oracle Partner für ihr besonderes Engagement und herausragende Erfolge bei der Spezialisierung ausgezeichnet wurden. Jeder Preisträger erhielt neben dem Award eine Urkunde sowie einen Wertscheck in Höhe von 2.000 Euro für eine Demand Generation Kampagne. Wir gratulieren allen Gewinnern ganz herzlich und stellen sie Ihnen im Folgenden kurz vor:Database Partner of the Year Germany: inforsacom Informationssysteme GmbHDass der EMEA Database Partner of the Year inforsacom auch im bundesweiten Vergleich überzeugen würde, war keine große Überraschung, ist aber ein Riesenerfolg! Übrigens war inforsacom auch schon 2011 unter den Preisträgern des OPN Day Satellite (wir berichteten). Der Platinum Partner inforsacom Informationssysteme GmbH entwickelt und liefert seit 1997 integrierte IT-Lösungen im Data-Center. Als „trusted advisor“ ist es ein Schwerpunkt von Inforsacom, in der Beratung den größtmöglichen Kundennutzen aufzuzeigen. inforsacom setzt einen deutlichen Fokus auf Oracle Datenbanktechnologien sowie das Hardware und Engineered Systems Portfolio -  inklusive der damit verbundenen Spezialisierung und Ausbildung der Mitarbeiter. Middleware Partner of the Year Germany: People at Work Systems AGZum Middleware Partner of the Year wurde die People at Work Systems AG gekürt, ein Software- und Beratungsunternehmen aus München, das  Kunden individuelle Dienstleistungen und Lösungen für Customer Relationship Management (CRM) und  Business Process Management (BPM) auf der Basis von Oracle anbietet. Seit Jahren zeigt der Oracle Partner ein hohes Commitment zu Oracle, unter anderem durch sein umfassendes Engagement im Rahmen der Solution Partner Community SOA. Die große technologische und vertriebliche Kompetenz in Sachen BPM, SOA & Integration hat die People at Work GmbH in verschiedenen komplexen Fusion Middleware-Projekten erfolgreich unter Beweis gestellt. Applications Partner of the Year Germany: ifb AGDie ifb-group deckt als einer der wenigen Partner das komplette Hyperion, Oracle EPM und BI Portfolio ab. Dabei ist das Markenzeichen der ifb die enge Verbindung von Fachexpertise und Umsetzungsstärke, denn weltweit setzen über 800 Unternehmen seit vielen Jahren erfolgreich auf Lösungen der ifb. Der Award „Applications Partner of the Year“ würdigt die Spezialisierung der ifb auf EPM. Industry Partner of the Year Germany: PORTRIX LOGISTIC SOFTWARE GmbHÜber den Preis als bester Industry Partner freute sich die PORTRIX LOGISTIC SOFTWARE GmbH aus Hamburg, eine Tochter der portrix.net GmbH. Mit einer eigenen Software-Lösung bietet der ISV Speditionen eine Lösung an, die die Abrechnung und Transparenz von Vertragskonditionen über die ganze Transportkette hinweg vereinfacht. Die Unternehmensgruppe portrix.net ist mit mehr als vier Spezialisierungen mit sehr gutem Oracle Know-how ausgestattet und somit in der Lage, zu unterschiedlichsten Anforderungen von Endkunden und Oracle Partnern exzellent zu beraten. Oracle Accelerate Partner of the Year Germany: ICP Solution GmbHICP Solution unterstützt als "One-Stop-Shop" auf dem europäischen Markt Kunden in allen Fragen rund um PLM und Agile von Oracle. Das Leistungsspektrum reicht dabei von der Prozessoptimierung und PLM Einführung, über ERP Integration bis hin zum Wartungsvertrag und speziellen Schulungen.Server & Storage Systems Partner of the Year Germany: CCF AGDie CCF AG ist schon seit 19 Jahren ein überzeugter Sun/Oracle Partner, der ca. 90% seines Umsatzes mit Sun/Oracle Produkten macht. Als flexibles regionales Unternehmen mit angeschlossener Consulting Firma, die auf Solaris und Unix spezialisiert ist, ist die CCF einer der wenigen Oracle Partner mit eigenen Solaris Administratoren. Der Award würdigt auch die herausragenden Umsatzergebnisse von CCF im Hardware Segment.Oracle on Oracle Partner of the Year Germany: anykey GmbHAuch ankey ist bereits ein langjähriger Partner von Sun/Oracle und verfügt über hohes Consulting-Know-how. 2012 ist anykey richtig durchgestartet: Viele Zertifizierungen sowie Datenbankspezialisierung wurden erworben und der Platinum Partner hat sich damit den Bereich „Oracle on Oracle“ erschlossen. Durch die erfolgreiche Platzierung bei Kunden konnte anykey im letzten Fiskaljahr sogar den Umsatz verdoppeln.

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  • PASS Summit 2013 Review

    - by Ajarn Mark Caldwell
    As a long-standing member of PASS who lives in the greater Seattle area and has attended about nine of these Summits, let me start out by saying how GREAT it was to go to Charlotte, North Carolina this year.  Many of the new folks that I met at the Summit this year, upon hearing that I was from Seattle, commented that I must have been disappointed to have to travel to the Summit this year after 5 years in a row in Seattle.  Well, nothing could be further from the truth.  I cheered loudly when I first heard that the 2013 Summit would be outside Seattle.  I have many fond memories of trips to Orlando, Florida and Grapevine, Texas for past Summits (missed out on Denver, unfortunately).  And there is a funny dynamic that takes place when the conference is local.  If you do as I have done the last several years and saved my company money by not getting a hotel, but rather just commuting from home, then both family and coworkers tend to act like you’re just on a normal schedule.  For example, I have a young family, and my wife and kids really wanted to still see me come home “after work”, but there are a whole lot of after-hours activities, social events, and great food to be enjoyed at the Summit each year.  Even more so if you really capitalize on the opportunities to meet face-to-face with people you either met at previous summits or have spoken to or heard of, from Twitter, blogs, and forums.  Then there is also the lovely commuting in Seattle traffic from neighboring cities rather than the convenience of just walking across the street from your hotel.  So I’m just saying, there are really nice aspects of having the conference 2500 miles away. Beyond that, the training was fantastic as usual.  The SQL Server community has many outstanding presenters and experts with deep knowledge of the tools who are extremely willing to share all of that with anyone who wants to listen.  The opening video with PASS President Bill Graziano in a NASCAR race turned dream sequence was very well done, and the keynotes, as usual, were great.  This year I was particularly impressed with how well attended were the Professional Development sessions.  Not too many years ago, those were very sparsely attended, but this year, the two that I attended were standing-room only, and these were not tiny rooms.  I would say this is a testament to both the maturity of the attendees realizing how important these topics are to career success, as well as to the ever-increasing skills of the presenters and the program committee for selecting speakers and topics that resonated with people.  If, as is usually the case, you were not able to get to every session that you wanted to because there were just too darn many good ones, I encourage you to get the recordings. Overall, it was a great time as these events always are.  It was wonderful to see old friends and make new ones, and the people of Charlotte did an awesome job hosting the event and letting their hospitality shine (extra kudos to SQLSentry for all they did with the shuttle, maps, and other event sponsorships).  We’re back in Seattle next year (it is a release year, after all) but I would say that with the success of this year’s event, I strongly encourage the Board and PASS HQ to firmly reestablish the location rotation schedule.  I’ll even go so far as to suggest standardizing on an alternating Seattle – Charlotte schedule, or something like that. If you missed the Summit this year, start saving now, and register early, so you can join us!

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  • Query to find the data for every month of last year from the given date using mysql?

    - by Salil
    Hi All, I want data for the the last 1 year from the given date For ex:- I have date "2013-06-01" and i want data as follows also data i want is from three table using Group By or something else Month             Amount         Total_Data June 2013     100                5 May 2013       80                  4 -                     100                5 -                     100                5 July 2012       10                  2 I try following query but didn't workout SELECT DATE_FORMAT(rf.period, '%M %Y') as Month , sum(p.amount * ((100-q.amount)/100)) as Amount ,count(distinct q.label_id) as Total Data FROM table1 rf , table2 p , table3 q ,table4 a where rf.period BETWEEN '2013-06-01' AND '2013-06-01' and q.royalty_period BETWEEN '2013-06-01' AND '2013-06-01' and a.id = q.album_id and p.file_id = rf.id and p.upc = a.upc and p.local_revenue is not null GROUP BY Month Thanks in Advance, Salil Gaikwad

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  • SQL : where vs. on in join

    - by Erwin
    Perhaps a dumb question, but consider these 2 tables : T1 Store Year 01 2009 02 2009 03 2009 01 2010 02 2010 03 2010 T2 Store 02 Why is this INNER JOIN giving me the results I want (filtering the [year] in the ON clause) : select t1.* from t1 inner join t2 on t1.store = t2.store and t1.[year] = '2009' Store Year 02 2009 And why the LEFT OUTER JOIN include records of year 2010 ? select t1.* from t1 left outer join t2 on t1.store = t2.store and t1.year = '2009' where t2.store is null 01 2009 03 2009 01 2010 02 2010 03 2010 And I have to write the [year] filter in the 'WHERE' clause : select t1.* from t1 left outer join t2 on t1.store = t2.store where t2.store is null and t1.year = '2009' 01 2009 03 2009 Like I said, perhaps a dumb question, but it's bugging me !

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  • jQuery DatePicker - How to highlight certain days every month?

    - by Sergio
    Hi I have a jquery datepicker which is renders the current date by default as a full calendar. Before this is rendered I get a list of days from the server via ajax of days that need to be highlighted for the current month. The code for this is as follows: $.get("Note/GetActionDates/?orgID=" + orgID + "&month=" + month +"&year=" + year, null, function(result) { RenderCalendar(result); }, "json"); function RenderCalendar(dates) { $("#actionCal").datepicker({ dateFormat: 'dd/mm/yy', beforeShowDay: function(thedate) { var theday = thedate.getDate(); if ($.inArray(theday, dates) == -1) { return [true, "", ""]; } else { return [true, "specialDate", "Actions Today"]; } } }); } This is all good, but I would like the highlighted dates to update when the user clicks to a different month. I can modify the jquery datepicker initialise code with the following code: onChangeMonthYear: function(year, month, inst) { //get new array of dates for that month $.get("Note/GetActionDates/?orgID=" + orgID + "&month=" + month + "&year=" + year, null, function(result) { RenderCalendar(result); }, "json"); } But this doesn't seem to work. Could anyone show me what I'm doing wrong? Thanks! :) UPDATE - Working Code Thanks for the help! I have tweaked the code from petersendidit as follows and it now works. Gonna add a little more code to remove duplicate dates from the dates array but aside from that its all good. $("#actionCal").datepicker({ dateFormat: 'dd/mm/yyyy', beforeShowDay: function(thedate) { var theday = thedate.getDate() + "/" + (thedate.getMonth() + 1) + "/" + thedate.getFullYear(); if ($.inArray(theday, actionCalDates) == -1) { return [true, "", ""]; } else { return [true, "specialDate", "Actions Today"]; } }, onChangeMonthYear: function(year, month, inst) { dateCount = 0; getDates(orgID, month, year); } }); function getDates(orgID, month, year) { dateCount += 1; if (dateCount < 4) { $.ajax({ url: "Note/GetActionDates/", data: { 'orgID': orgID, 'month': month, 'year': year }, type: "GET", dataType: "json", success: function(result) { actionCalDates = actionCalDates.concat(result); getDates(orgID, month + 1, year); getDates(orgID, month - 1, year); } }); } }

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  • Date problem in MYSQL Query

    - by davykiash
    Am looking for a query to sum values in a particular time duration say an year or a particular month in an year using MYSQL syntax.Note that my transaction_date column stores daily amount transacted. Am example of a query that returns total sales in an year query would look something like this SELECT SUM(transaction_amount) WHERE transaction_date = (YEAR) Am example of a query that returns total sales in an particular month and year would look something like this SELECT SUM(transaction_amount) WHERE transaction_date = (YEAR)(MONTH) How achievable is this?

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  • Most efficient way to check if a date falls between two dates?

    - by Dave Jarvis
    Given: Start Month & Start Day End Month & End Day Any Year What SQL statement results in TRUE if a date lands between the Start and End days? 1st example: Start Date = 11-22 End Date = 01-17 Year = 2009 Specific Date = 2010-01-14 TRUE 2nd example: Start Date = 11-22 End Date = 11-16 Year = 2009 Specific Date = 2010-11-20 FALSE 3rd example: Start Date = 02-25 End Date = 03-19 Year = 2004 Specific Date = 2004-02-29 TRUE I was thinking of using the MySQL functions datediff and sign plus a CASE condition to determine whether the year wraps, but it seems rather expensive. Am looking for a simple, efficient calculation. Update The problem is the end date cannot simply use the year. The year must be increased if the end month/day combination happens before the start date. The start date is easy: Start Date = date( concat_ws( '-', year, Start Month, Start Day ) The end date is not so simple. Thank you!

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  • To what degree should I use Marshal.ReleaseComObject with Excel Interop objects?

    - by DanM
    I've seen several examples where Marshal.ReleaseComObject() is used with Excel Interop objects (i.e., objects from namespace Microsoft.Office.Interop.Excel), but I've seen it used to various degrees. I'm wondering if I can get away with something like this: var application = new ApplicationClass(); try { // do work with application, workbooks, worksheets, cells, etc. } finally { Marashal.ReleaseComObject(application) } Or if I need to release every single object created, as in this method: public void CreateExcelWorkbookWithSingleSheet() { var application = new ApplicationClass(); var workbook = application.Workbooks.Add(_missing); var worksheets = workbook.Worksheets; for (var worksheetIndex = 1; worksheetIndex < worksheets.Count; worksheetIndex++) { var worksheet = (WorksheetClass)worksheets[worksheetIndex]; worksheet.Delete(); Marshal.ReleaseComObject(worksheet); } workbook.SaveAs( WorkbookPath, _missing, _missing, _missing, _missing, _missing, XlSaveAsAccessMode.xlExclusive, _missing, _missing, _missing, _missing, _missing); workbook.Close(true, _missing, _missing); application.Quit(); Marshal.ReleaseComObject(worksheets); Marshal.ReleaseComObject(workbook); Marshal.ReleaseComObject(application); } What prompted me to ask this question is that, being the LINQ devotee I am, I really want to do something like this: var worksheetNames = worksheets.Cast<Worksheet>().Select(ws => ws.Name); ...but I'm concerned I'll end up with memory leaks or ghost processes if I don't release each worksheet (ws) object. Any insight on this would be appreciated.

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  • Range partition skip check

    - by user289429
    We have large amount of data partitioned on year value using range partition in oracle. We have used range partition but each partition contains data only for one year. When we write a query targeting a specific year, oracle fetches the information from that partition but still checks if the year is what we have specified. Since this year column is not part of the index it fetches the year from table and compares it. We have seen that any time the query goes to fetch table data it is getting too slow. Can we somehow avoid oracle comparing the year values since we for sure know that the partition contains information for only one year.

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  • linq multiple order DESCENDING

    - by ile
    .OrderBy(y => y.Year).ThenBy(m => m.Month); How to set descending order? EDIT: I tried this: var result = (from dn in db.DealNotes where dn.DealID == dealID group dn by new { month = dn.Date.Month, year = dn.Date.Year } into date orderby date.Key.year descending orderby date.Key.month descending select new DealNoteDateListView { DisplayDate = date.Key.month + "-" + date.Key.year, Month = date.Key.month, Year = date.Key.year, Count = date.Count() }) //.OrderBy(y => y.Year).ThenBy(m => m.Month) ; And it seems working. Is it wrong to use orderby twice like I used it here?

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  • OpenGL: How to draw Bezier curve of degree higher then 8?

    - by maciekp
    I am trying to draw high order Bezier Curve using OpenGL evaluators: glMap1f(GL_MAP1_VERTEX_3, 0.0, 1.0, 3, 30, &points[0][0]); glMapGrid1f(30, 0, 1); glEvalMesh1(GL_LINE, 0, 30); or glBegin(GL_LINE_STRIP); for (int i = 0; i <= 30; i++) glEvalCoord1f((GLfloat) i/30.0); glEnd(); When number of points exceeds 8, curve disappears. How to draw higher order Bezier curve using evaluators?

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  • Stupid newbie c++ two-dimensional array problem.

    - by paulson scott
    I've no idea if this is too newbie or generic for stackoverlflow. Apologies if that's the case, I don't intend to waste time. I've just started working through C++ Primer Plus and I've hit a little stump. This is probably super laughable but: for (int year = 0; year < YEARS; year++) { cout << "Year " << year + 1 << ":"; for (int month = 0; month < MONTHS; month++) { absoluteTotal = (yearlyTotal[year][year] += sales[year][month]); } cout << yearlyTotal[year][year] << endl; } cout << "The total number of books sold over a period of " << YEARS << " years is: " << absoluteTotal << endl; I wish to display the total of all 3 years. The rest of the code works fine: input is fine, individual yearly output is fine but I just can't get 3 years added together for one final total. I did have the total working at one point but I didn't have the individual totals working. I messed with it and reversed the situation. I've been messing with it for God knows how long. Any idea guys? Sorry if this isn't the place!

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