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  • drupal views block arguments

    - by slimcady
    I currently have a view (Drupal 6 using Views2) that properly aggregates a custom content type (videos) and filters them for a page display. When I create a block display, it previews the results in live preview just great, but when i go to the page expecting to see the block it doesn't appear. I'm fairly certain the argument I'm attempting to pass it fails because when I select "Display all results" for "Action to take if argument does not validate:" the block shows up on the page just fine. Any advice definitely appreciated.

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  • How can I get awk input from a file and add my own text to the data?

    - by xs2dhillon
    Assume that I have a text file separated by colons. I understand how to display the entire text file or any specific column using awk. However, what I want to do is to get the awk output and then display it by adding my own text using a shell script? For example, assume that my text file is: England:London:GMT USA:Washington:EST France:Paris:GMT What I want to do is to display this input into the below format: COUNTRY: England CAPITOL: London TIMEZONE: GMT COUNTRY: USA CAPITOL: Washington TIMEZONE: EST COUNTRY: France CAPITOL: Paris TIMEZONE: GMT

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  • Updating NVIDIA drivers from 295.40: What will happen to TwinView?

    - by Spice
    Right now, I have the NVIDIA proprietary drivers enabled without the Ubuntu-X repo, so the driver version is 295.40 (which is on the official Ubuntu repo) instead of the current 304.64 for my card, but I want to update to the current (using the Ubuntu-X repo). From what I heard, after 302.xx, NVIDIA started supporting RandR and removed TwinView. My question is, I have TwinView enabled for two monitors. If I update to the new version, what will happen to my TwinView settings? Will there be any extra work to do to migrate to the new driver?

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  • how to send on previous page where a part of html was loaded

    - by I Like PHP
    hello all, i m using Jquery ajax post method to edit a form on same page, but if there is some mistake then how do i send user back on that page where data were loaded. now i describe u what i do? i have a page manageMovies.php there are list of movie name, now when i click on a name of any movie, then i load editMovie.php on same page now when i do some mistakes( i.e when validations fails) then i want to go back on same page manageMovies.php loaded with editunit.php regarding that movie on the page. here is my page structure manageMovies.php <div id="display"></div> <div id="movieList"> <table > <tr><td id="mov_10">Apharan</td></tr> <tr><td id="mov_11">Gangaajal</td></tr> <tr><td id="mov_12">Rajniti</td></tr> </table> </div> <script type="text/javascript"> jQuery('td').click(function () { jQuery('#movieList').hide(); // hide the div 'movielist' jQuery.post('editMovie.php', { idForEdit: jQuery(this).attr('id') }, function (data) { jQuery("#display").html(data); //display the editMovie.php page on 'display' div }); }); </script> now when i do some mistakes on editunit.php and go further for post, then i need to go back on same page (manageMovies.php) where editMovie.php is shown on display div and movielist div should be hidden

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  • How do I create a command like \title in LaTeX?

    - by Kjir
    I am writing a document class for LaTeX and I want it to be generic. In this document class I redefine the \maketitle command to display a custom title page, and here I want to display some information, like the title, author, etc., but also some other informations. Here is how I display the title: {\LARGE{\bf \@title}}\\ I'd like to create a new command that works similarly to \title or \author, how can I do that?

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  • What's wrong (or right) with this JS Object Pattern?

    - by unsane1
    Here's an example of the pattern I'm using in my javascript objects these days (this example relies on jQuery). http://pastie.org/private/ryn0m1gnjsxdos9onsyxg It works for me reasonably well, but I'm guessing there's something wrong, or at least sub-optimal about it, I'm just curious to get people's opinions. Here's a smaller, inline example of it: sample = function(attach) { // set internal reference to self var self = this; // public variable(s) self.iAmPublic = true; // private variable(s) var debug = false; var host = attach; var pane = { element: false, display: false } // public function(s) self.show = function() { if (!pane.display) { position(); $(pane.element).show('fast'); pane.display = true; } } self.hide = function() { if (pane.display) { $(pane.element).hide('fast'); pane.display = false; } } // private function(s) function init () { // do whatever stuff is needed on instantiation of this object // like perhaps positioning a hidden div pane.element = document.createElement('div'); return self; } function position() { var h = { 'h': $(host).outerHeight(), 'w': $(host).outerWidth(), 'pos': $(host).offset() }; var p = { 'w': $(pane.element).outerWidth() }; $(pane.element).css({ top: h.pos.top + (h.h-1), left: h.pos.left + ((h.w - p.w) / 2) }); } function log () { if (debug) { console.log(arguments); } } // on-instantiation let's set ourselves up return init(); } I'm really curious to get people's thoughts on this.

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  • Displaying Data from a Join in Codeigniter

    - by Brad
    I am using a simple join to pull data from two databases. This is the join in the model function com_control(){ $this->db->select('*'); $this->db->from('comments'); $this->db->join('posts', 'comments.entry_id = posts.id'); $query = $this->db->get(); return $query->result; } My desired method of display is going to be in a table so I am starting out to use like this foreach($comm_control as $row){ $this->table->add_row( $row->entry_id, $row->comments.id, $row->comment, $row->title ); }//end of foreach My problem is the display of data from comments.id. What is the proper format to add the comment.id into the table rows? I need the ID from both tables for display, edit and delete further on in the table. The only display I get at this time for "comment.id" is the word id. The Any help would be appreciated.

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  • JQuery search page textbox

    - by Geetha
    Hi all, I am creating a search page using asp.net[c#] with jquery. Needs: If we are typing a word in the text box, for each letter it has to display the related word in the database. ex: step 1. w [display: world Whole] step 2: wor[display: World] How to achieve this using jquery Geetha.

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  • How to compare the year with the current year in iphone?

    - by Warrior
    I am new to iphone development.I am parsing a XML URL and display the title ,date and summary in a table view.I noticed some of the date were very old like "Wed, 31 Dec 1969 19:00:00 -0500" ,So i don't want to display the dates which are 1 year older than the current year.How to do that? I used the sample code from this site for parsing and display the details.Please help me out.Thanks.

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  • Ubuntu 12.04 Nvidia GTX 460 video card installation

    - by aczietlow
    Currently testing Ubuntu 12.04 x64 for our development team. After upgrading from 11.10 I've been having video card issues. I'm using Nvidia GeForce GTX 460. When ever I try to launch Nvidia X server I get the following error message. You do not appear to be using the NVIDIA X driver. Please edit your X configuration file (just run nvidia-xconfig as root), and restart the X server. I've tried running sudo nvidia-xconfig multiple times and rebooting with no success. I've also tried getting the nvidia-current driver from the x-swat repo sudo apt-add-repository ppa:ubuntu-x-swat/x-updates sudo apt-get update sudo apt-get install nvidia-current Followed again by a reboot did nothing for me but knock my resolution down to 800x600 Finally I've tried sudo apt-get purge xserver-xorg sudo apt-get update sudo apt-get install xserver-xorg xserver-xorg-video-all sudo reboot Does anyone have any thoughts or directions they could point me in? To the best of my understanding my video card is suppose to be supported.

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  • How does one find a '.' in a string object in Object-C

    - by NaZer
    I am working on getting a simple calculator working as part of my adventure to learning Object-C and iOS development. In Object-C using NSString, how does one look for a period in a string? Based on the comments this is what I got so far. NSString * tmp = [display text]; NSLog(@"%@", tmp); // Shows the number on the display correctly int x = [tmp rangeOfString:@"."].location; NSLog(@"%i", x); // Shows some random signed number if (x < 0) { [display setText:[[display text] stringByAppendingFormat:@"."]]; } It is still not working :(

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  • Client Side pagination with jQuery

    - by TheNone
    I have tried to write a script for pagination contents of an element with jQuery: <script type="text/javascript"> $(document).ready(function(){ var per_page = 2; var num_item = $('#en1').children().size(); var num_page = Math.ceil(num_item/per_page); $('#current_page').val(0); $('#per_page').val(per_page); var navigation_html = ''; var current = 0; while(num_page > current){ navigation_html += '<a class="page_link" href="javascript:paginate(' + current +')" longdesc="' + current +'">'+ (current + 1) +'</a>'; current++; } $('#page_navigation').html(navigation_html); $('#page_navigation .page_link:first').addClass('active_page'); $('#en1').children().css('display', 'none'); $('#en1').children().slice(0, per_page).css('display', 'block'); }); function paginate(page_num){ var per_page = parseInt($('#per_page').val()); start = page_num * per_page; finish= start + per_page; $('#en1').children().css('display', 'none').slice(start, finish).css('display', 'block'); $('.page_link[longdesc=' + page_num +']').addClass('active_page').siblings('.active_page').removeClass('active_page'); $('#current_page').val(page_num); } </script> http://jsfiddle.net/kqfyL/9/ This script paginate the contents of element by id "en1". I want to paginate 4-5 element (en2, en3, ...). When I insert code inside o document ready in a function, pagination doesnt work: function init(myId){ var ID = document.getElementById("myId"); var per_page = 6; var num_item = $(ID).children().size(); var num_page = Math.ceil(num_item/per_page); $('#current_page').val(0); $('#per_page').val(per_page); var navigation_html = ''; var current = 0; while(num_page > current){ navigation_html += '<a class="page_link" href="javascript:paginate(' + current +')" longdesc="' + current +'">'+ (current + 1) +'</a>'; current++; } $('#page_navigation').html(navigation_html); $('#page_navigation .page_link:first').addClass('active_page'); $('#ID').children().css('display', 'none'); $('#ID').children().slice(0, per_page).css('display', 'block'); } init(en1); What is wrong in init function? Thanks in advance

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  • Doesn't get the output in Java Database Connectivity

    - by Dooree
    I'm working on Java Database Connectivity through Eclipse IDE. I built a database through Ubuntu Terminal, and I need to connect and work with it. However, when I tried to run the following code, I don't get any error, but the following output is showed, anybody knows why I don't get the output from the code ? //STEP 1. Import required packages import java.sql.*; public class FirstExample { // JDBC driver name and database URL static final String JDBC_DRIVER = "com.mysql.jdbc.Driver"; static final String DB_URL = "jdbc:mysql://localhost/EMP"; // Database credentials static final String USER = "username"; static final String PASS = "password"; public static void main(String[] args) { Connection conn = null; Statement stmt = null; try{ //STEP 2: Register JDBC driver Class.forName("com.mysql.jdbc.Driver"); //STEP 3: Open a connection System.out.println("Connecting to database..."); conn = DriverManager.getConnection(DB_URL,USER,PASS); //STEP 4: Execute a query System.out.println("Creating statement..."); stmt = conn.createStatement(); String sql; sql = "SELECT id, first, last, age FROM Employees"; ResultSet rs = stmt.executeQuery(sql); //STEP 5: Extract data from result set while(rs.next()){ //Retrieve by column name int id = rs.getInt("id"); int age = rs.getInt("age"); String first = rs.getString("first"); String last = rs.getString("last"); //Display values System.out.print("ID: " + id); System.out.print(", Age: " + age); System.out.print(", First: " + first); System.out.println(", Last: " + last); } //STEP 6: Clean-up environment rs.close(); stmt.close(); conn.close(); }catch(SQLException se){ //Handle errors for JDBC se.printStackTrace(); }catch(Exception e){ //Handle errors for Class.forName e.printStackTrace(); }finally{ //finally block used to close resources try{ if(stmt!=null) stmt.close(); }catch(SQLException se2){ }// nothing we can do try{ if(conn!=null) conn.close(); }catch(SQLException se){ se.printStackTrace(); }//end finally try }//end try System.out.println("Goodbye!"); }//end main }//end FirstExample <ConnectionProperties> <PropertyCategory name="Connection/Authentication"> <Property name="user" required="No" default="" sortOrder="-2147483647" since="all"> The user to connect as </Property> <Property name="password" required="No" default="" sortOrder="-2147483646" since="all"> The password to use when connecting </Property> <Property name="socketFactory" required="No" default="com.mysql.jdbc.StandardSocketFactory" sortOrder="4" since="3.0.3"> The name of the class that the driver should use for creating socket connections to the server. This class must implement the interface 'com.mysql.jdbc.SocketFactory' and have public no-args constructor. </Property> <Property name="connectTimeout" required="No" default="0" sortOrder="9" since="3.0.1"> Timeout for socket connect (in milliseconds), with 0 being no timeout. Only works on JDK-1.4 or newer. Defaults to '0'. </Property> ...

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  • How can I make a table move in JavaScript?

    - by Michal Skrzypek
    My problem is that I was creating a simple website the other day and I needed the content to move according to the button pressed. I managed to do so in CSS3, but the solution did not work for IE whatsoever. Therefore I would like to ask if there is a simple solution for that in js? I don't know js at all but I heard what I need is much easier in js than in css. Details: http://i42.tinypic.com/6yl4ia.png I need the table in the picture to move according to the buttons (which are labels to be exact). The visible area is a div. Here's the relevant code (without animation as I was not satisfied with it): body { background-color: #fff; color: #fff; padding:0px; } #bodywrapperfixed { width: 1248px; margin: 0px auto; position: relative; overflow: hidden; height: 730px; } #bodywrapper { display:block; background-color: #fff; width: 1248px; color: #59595B; padding-top:50px; font-family: 'Roboto', sans-serif; position: absolute; top:0px; left:0px; z-index:1; font-size: 60px; height:730px; } #bodywrapper img { width:400px; padding:15px 0px 20px 0px; } #texten { font-family: 'Roboto', sans-serif; font-size: 35px; padding:5px; } #textpl { font-family: 'Roboto', sans-serif; font-size: 25px; padding:5px; } table#linki { width: 110px; border: none; margin-top:15px; } label { display: block; height: 54px; width: 54px; color:#fff; font-family: 'Roboto', sans-serif; font-weight: 300; font-size: 35px; background-color: #117D10; text-align: center; padding:23px; } label:hover { background-color: #004F00; cursor: pointer; } input#pl { position: absolute; top: -9999px; left: -9999px; } input#en { position: absolute; top: -9999px; left: -9999px; } and the relevant HTML: <div id="bodywrapperfixed"> <div id="bodywrapperfloat"> <table id="ramka"> <tr> <td>random text</td> <td><div id="bodywrapper"> <center> <div id="texten"><div style="font-weight:300; display:inline-block;">Introducing the all-in-one entertainment system.</div><div style="font-weight:500; display:inline-block;">&nbsp;For everyone.</div></div> <div id="textpl"><div style="font-weight:300; display:inline-block;">Przedstawiamy zintegrowany system rozrywki.</div><div style="font-weight:500; display:inline-block;">&nbsp;&nbsp;Dla wszystkich.</div></div> <img src="imgs/xboxone.png"> <div id="texten"><div style="font-weight:300; display:inline-block;">Choose your version of the story:</div></div> <div id="textpl"><div style="font-weight:300; display:inline-block;">Wybierz swoja wersja opowiesci:</div></div> <table id="linki"> <tr> <td><label for="en">en</label><input id="en" type="checkbox"></td> <td><label for="pl">pl</label><input id="pl" type="checkbox"></td> </tr></table> </center> </div></td> <td>random text</td> </tr> </table> </div> </div> Here's what it looks like: http://ingame.lh.pl/thinkone/ Please help me.

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  • WinForm And Looping

    - by Soo
    I have a WinForm set up and a process that loops until a button is pressed on the form. When I try to run my code, the form does not even display. I suspect this is because the code gets stuck in the loop and doesn't get far enough to display the WinForm. How can I get the form to display and the loop to run after that point?

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  • Are Interfaces "Object"?

    - by PrashantGupta
    package inheritance; class A{ public String display(){ return "This is A!"; } } interface Workable{ public String work(); } class B extends A implements Workable{ public String work(){ return "B is working!"; } } public class TestInterfaceObject{ public static void main(String... args){ B obj=new B(); Workable w=obj; //System.out.println(w.work()); //invoking work method on Workable type reference System.out.println(w.display()); //invoking display method on Workable type reference //System.out.println(w.hashCode()); // invoking Object's hashCode method on Workable type reference } } As we know that methods which can be invoked depend upon the type of the reference variable on which we are going to invoke. Here, in the code, work() method was invoked on "w" reference (which is Workable type) so method invoking will compile successfully. Then, display() method is invoked on "w" which yields a compilation error which says display method was not found, quite obvious as Workable doesn't know about it. Then we try to invoke the Object class's method i.e. hashCode() which yields a successful compilation and execution. How is it possible? Any logical explanation?

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  • Nashorn ?? JDBC ? Oracle DB ?????

    - by Homma
    ???? ????????????Nashorn ?? JavaScript ??????? JDBC ? API ??????Oracle DB ?????????????????????? ?????????????????????JDBC ? API ??????????????? ????????? URL ? https://blogs.oracle.com/nashorn_ja/entry/nashorn_jdbc_1 ??? ???? ???? DB ????Oracle Linux 6.5 ?? Oracle 11.2.0.3.0 ?????????????? JDBC ????????????? DB ????????????????? ???? ?Oracle Database JDBC ???????????????????????Nashorn ?? JavaScript ?????????????????????? JDBC ? Oracle DB ??????? Nashorn ?? JavaScript ??????? JDBC ? Oracle DB ?????? JavaScript ?????? DB ???????????????? JavaScript ?????? oracle ????????? JavaScript ?????? DB ?????????????????????????????????DB ???????????? JavaScript ???????????????????????? oracle ?????????? JDBC ??????????????????????? ???? DB ?????? ?????? DB ???????????? SQL> create user test identified by "test"; SQL> grant connect, resource to test; Java 8 ??????? ???? JDK 8 ?????????????????????????????? 8u5 ???? Java 8 ??????? ???????? JDK ? yum ??????????????? # yum install ./jdk-8u5-linux-x64.rpm JDK ????????????????????? # java -version java version "1.8.0_05" Java(TM) SE Runtime Environment (build 1.8.0_05-b13) Java HotSpot(TM) 64-Bit Server VM (build 25.5-b02, mixed mode) Nashorn ????? oracle ??????????PATH ??????? $ vi ~/.bash_profile PATH=${PATH}:/usr/java/latest/bin export PATH $ . ~/.bash_profile jjs ?????????????????? $ jjs -fv nashorn full version 1.8.0_05-b13 ????????????? JDBC ?????????????? JDBC ?????????JDBC ?????? ??????????????????? ???????? JDBC ????????????????????????? ?????????????? JavaScript ??????????jjs ???????????????????? Nashorn ? JavaScript ?????????????????? JDBC ??????? jjs ????? -cp ?????? JDBC ????? JAR ??????????? $ vi version.js var OracleDataSource = Java.type("oracle.jdbc.pool.OracleDataSource"); var ods = new OracleDataSource(); ods.setURL("jdbc:oracle:thin:test/test@localhost:1521:orcl"); var conn = ods.getConnection(); var meta = conn.getMetaData(); print("JDBC driver version is " + meta.getDriverVersion()); $ jjs -cp ${ORACLE_HOME}/jdbc/lib/ojdbc6.jar version.js JDBC driver version is 11.2.0.3.0 ??????JavaScript ???????? JDBC ?????????? (11.2.0.3.0) ????????? Java.type() ??????? JavaClass ??????? new ????? Java ??????????????????????????? Java ???????????????????? ????????????????????????????????????????????????????? ?????????????????????????????????????? Java ??????????????? JavaScript ???????????????????????????????? ?????? ???????????????? jjs ???????????Nashorn ??????????????jjs ??????????????????????????? $ jjs -cp ${ORACLE_HOME}/jdbc/lib/ojdbc6.jar jjs> var OracleDataSource = Java.type("oracle.jdbc.pool.OracleDataSource"); jjs> var ods = new OracleDataSource(); jjs> ods.setURL("jdbc:oracle:thin:test/test@localhost:1521:orcl"); null jjs> var conn = ods.getConnection(); jjs> var meta = conn.getMetaData(); jjs> print("JDBC driver version is " + meta.getDriverVersion()); JDBC driver version is 11.2.0.3.0 ???????? JDBC ?????????? (11.2.0.3.0) ????????? ?????????????????????????????????????????????????????????JDBC ?????????????????????? ??? Nashorn ???????? JDBC ? API ????????????? API ???????????????? ???????? JavaScript ?????????????????????????????????? ???????????? JDBC ? DB ???????????????? JDBC ??????????????????????????? ???? Oracle Database JDBC?????? 11g????2(11.2) ??????? jjs ?????????? Nashorn User's Guide Java Scripting Programmer's Guide Oracle Nashorn: A Next-Generation JavaScript Engine for the JVM

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  • Windows?????(C#?Visual Basic?Active Server Pages?Visual C++)??Oracle Database?????

    - by Yusuke.Yamamoto
    C#?Visual Basic?Active Server Pages?Visual C++???????? Windows ???????????????Oracle Database ????·???????????????? ???? Windows ?????????????Oracle Database ??????????·????·???????????? .NET Oracle Data Provider for .NET Oracle Provider for OLE DB ???? OLE DB.NET Oracle ODBC Driver ???? ODBC.NET Visual Basic/ASP/Access Oracle Objects for OLE(OO4O) Oracle ODBC Driver Oracle Provider for OLE DB OO4O?OLE DB?ODBC?ODP.NET ??Oracle Data Access Component(ODAC) ???????????? OTN Oracle Data Access Components ??????? ???? ????????Oracle DB????????????? Oracle on Windows / .NET ?? ?????????? .NET|???????????

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  • Windows XP Video Configuration Issues

    - by Matt
    Recently I had my motherboard burn out on me. Needing the machine for work, I purchased a different motherboard and installed that. Generally a reinstall of windows is good at that point but I am not in a position to do that so I just decided I would live with it for now. When I can log-in, everything works fine, what doesn't is getting to the log-in prompt to begin with. Basically when I first installed the new mobo, every time I rebooted the machine, I would not get the windows login prompt. One of the monitors would receive a signal but the screen would be black. Moving the mouse would not show the cursor and hitting the up arrow key and typing my password and hitting enter (which will normally log you in without mouse) wouldn't change anything. I would then change the monitor configuration around (2 lcd's and a crt) and reboot and at least one of the monitors would work and display the login prompt. I could then go into display properties and turn on the other monitors. However if I rebooted again, I would get the black screen on one monitor again. I would then have to change the configuration again to one not used before and I could re-do the manual setup at that point. I think windows saves the configurations so I had to keep giving it new ones. Needless to say I've been trying to not turn off my machine. Early this week I actually got the prompt to come up without playing musical monitors. Thinking everything was getting better, I found no harm in rebooting to install the latest windows updates. Boy was I wrong. Now no matter what I do I can't get a windows log-in prompt to display. I've tried almost every conceivable combination. The new mobo has onboard video so I set that in the bios (yea bios screen always displays fine, its not until windows boots that there is a problem) to be the primary video. Still no luck. I have two other graphics cards in the machine which I'm using. Tried all kinds of configurations between those and on-board but still get this black screen of death. I read somewhere that deleting the video drivers would reset the configurations. I logged into safe mode (which works on one monitor), and uninstalled the display drivers. Still no luck and when I booted back into safe mode, it wanted to install new hardware and the display adapters weren't there as expected. Anyone have any ideas? A fresh install would be a pain and I might be getting my old board back from RMA soon so not sure I want to go through with that just yet. Only thing I can think of is to continue to try other combinations like physically removing the graphics cards. They are both EVGA 8600 cards and the windows boot screen does display fwiw.

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  • Hyper-V Server 2012 - "No Active Network Adapter Found"

    - by Vazgen
    I just installed Hyper-V Server 2012 and first thing I get when logging in to the host is "No Active Network Adapter Found". I know I have to use the following command: pnputil –i –a <inf file> I found the Realtek Network Driver for my MB for Windows 7 here: http://za.asus.com/Motherboards/AMD_AM3Plus/M5A97_PRO/#download But there is not one for Windows 8 so I tried using the Win 7 one with PnPUtil, and I got: Failed to install the driver on any of the devices on the system: No more data is available. Does this really mean I can't use Hyper-V Server 2012 with my motherboard? This is hard to believe because I installed Windows Server 2012 directly (prior to installing Hyper-V Server 2012) on this same computer and I had internet access on that server without even configuring any drivers. Ok so I went to PowerShell from cmd and typed Get-NetIPConfiguration And it said the name of my driver (Realtek) and "Disconnected". I switched the Ethernet wire from my primary computer with my server and everything was fixed. Interestingly, my primary computer connects to the internet just fine with the wire that was previously in the server, just with much slower speed. Does anyone know what could be the difference between these 2 Ethernet wires?

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  • Are VMWare ESXi 5 patches cumulative?

    - by ewwhite
    It seems basic, but there's confusion about the patching strategy needed to manually update standalone VMWare ESXi hosts. The VMWare vSphere blog attempts to explain this, but it's still not clear. From the blog: Say Patch01 includes updates for the following VIBs: "esxi-base", "driver10" and "driver 44". And then later Patch02 comes out with updates to "esxi-base", "driver20" and "driver 44". P2 is cumulative in that the "esxi-base" and "driver44" VIBs will include the updates in Patch01. However, it's important to note that Patch02 not include the "driver 10" VIB as that module was not updated. Many of my ESXi installations are standalone and do not make use of Update Manager. It is possible to update an individual host using the patches make available through the VMWare patch download portal. The process is quite simple, and that part makes sense. The bigger issue is determining what to actually download and install. In my case, I have a good number of HP-specific ESXi builds that incorporate sensors and management for HP ProLiant hardware. Let's say that those servers start at ESXi build #474610 from 9/2011. Looking at the patch portal screenshot below, there is a patch for ESXi update01, build #623860. There are also patches for builds #653509 and #702118. Coming from the old version of ESXi, what is the proper approach to bring the system fully up-to-date? Which patches are cumulative and which need to be applied sequentially? Perhaps the download size is the confusing factor, but is installing the newest build the right approach, or do I need to step back and patch incrementally?

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