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  • Strange use of the index in Mysql

    - by user309067
    explain SELECT feed_objects.* FROM feed_objects WHERE (feed_objects.feed_id IN (165,160,159,158,157,153,152,151,150,149,148,147,129,128,127,126,125,124,122,121,120,119,118,117,116,115,114,113,111,110)) ; +----+-------------+--------------+------+---------------+------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+--------------+------+---------------+------+---------+------+------+-------------+ | 1 | SIMPLE | feed_objects | ALL | by_feed_id | NULL | NULL | NULL | 188 | Using where | +----+-------------+--------------+------+---------------+------+---------+------+------+-------------+ Not used index 'by_feed_id' But when I point less than the values in the "WHERE" - everything is working right explain SELECT feed_objects.* FROM feed_objects WHERE (feed_objects.feed_id IN (165,160,159,158,157,153,152,151,150,149,148,147,129,128,127,125,124)) ; +----+-------------+--------------+-------+---------------+------------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+--------------+-------+---------------+------------+---------+------+------+-------------+ | 1 | SIMPLE | feed_objects | range | by_feed_id | by_feed_id | 9 | NULL | 18 | Using where | +----+-------------+--------------+-------+---------------+------------+---------+------+------+-------------+ Used index 'by_feed_id' What is the problem?

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  • JSON Array Created in PHP/MySQL incorrectly decoded using JQuery

    - by Zak
    I am attempting to make an AJAX call to a very small PHP script that should return me an array that could be echo'd and decoded using JQuery. Here is what I have: My PHP page called to by AJAX: $web_q=mysql_query("select * from sec_u_g where uid='$id' "); $rs = array(); while($rs[] = mysql_fetch_assoc($web_q)) { } print_r(json_encode($rs)); This outputs: [{"id":"3","uid":"39","gid":"16"},{"id":"4","uid":"39","gid":"4"},{"id":"5","uid":"39","gid":"5"},{"id":"6","uid":"39","gid":"6"},{"id":"7","uid":"39","gid":"7"},{"id":"8","uid":"39","gid":"8"},{"id":"9","uid":"39","gid":"9"},false] I don't understand the "false" at the end for one .. But then I send to to JQuery and use: $.each(json.result, function(i, object) { $.each(object, function(property, value) { alert(property + "=" + value); }); }); This just fails. I try to alert "result" by itself which is set by: $.post("get_ug.php",{id:txt},function(result){ }); My output alerts are as follows: 1) The key is '0' and the value is '[' 2) The key is '1' and the value is 'f' 3) The key is '2' and the value is 'a' 4) The key is '3' and the value is 'l' 5) The key is '4' and the value is 's' 6) The key is '5' and the value is 'e' 7) The key is '6' and the value is ']' 8) The key is '7' and the value is ' ' (<-- Yes the line break is there in the alert) I am exhausted from trying different ideas and scripts. Other than setting a delimiter myself and concatenating my own array and decoding it with a custom script, does anyone have any ideas?? Thank you!!

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  • Help Optimizing MySQL Table (~ 500,000 records) and PHP Code.

    - by Pyrite
    I have a MySQL table that collects player data from various game servers (Urban Terror). The bot that collects the data runs 24/7, and currently the table is up to about 475,000+ records. Because of this, querying this table from PHP has become quite slow. I wonder what I can do on the database side of things to make it as optomized as possible, then I can focus on the application to query the database. The table is as follows: CREATE TABLE IF NOT EXISTS `people` ( `id` bigint(20) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(40) NOT NULL, `ip` int(4) unsigned NOT NULL, `guid` varchar(32) NOT NULL, `server` int(4) unsigned NOT NULL, `date` int(11) NOT NULL, PRIMARY KEY (`id`), UNIQUE KEY `Person` (`name`,`ip`,`guid`), KEY `server` (`server`), KEY `date` (`date`), KEY `PlayerName` (`name`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 COMMENT='People that Play on Servers' AUTO_INCREMENT=475843 ; I'm storying the IPv4 (ip and server) as 4 byte integers, and using the MySQL functions NTOA(), etc to encode and decode, I heard that this way is faster, rather than varchar(15). The guid is a md5sum, 32 char hex. Date is stored as unix timestamp. I have a unique key on name, ip and guid, as to avoid duplicates of the same player. Do I have my keys setup right? Is the way I'm storing data efficient? Here is the code to query this table. You search for a name, ip, or guid, and it grabs the results of the query and cross references other records that match the name, ip, or guid from the results of the first query, and does it for each field. This is kind of hard to explain. But basically, if I search for one player by name, I'll see every other name he has used, every IP he has used and every GUID he has used. <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> Search: <input type="text" name="query" id="query" /><input type="submit" name="btnSubmit" value="Submit" /> </form> <?php if (!empty($_POST['query'])) { ?> <table cellspacing="1" id="1up_people" class="tablesorter" width="300"> <thead> <tr> <th>ID</th> <th>Player Name</th> <th>Player IP</th> <th>Player GUID</th> <th>Server</th> <th>Date</th> </tr> </thead> <tbody> <?php function super_unique($array) { $result = array_map("unserialize", array_unique(array_map("serialize", $array))); foreach ($result as $key => $value) { if ( is_array($value) ) { $result[$key] = super_unique($value); } } return $result; } if (!empty($_POST['query'])) { $query = trim($_POST['query']); $count = 0; $people = array(); $link = mysql_connect('localhost', 'mysqluser', 'yea right!'); if (!$link) { die('Could not connect: ' . mysql_error()); } mysql_select_db("1up"); $sql = "SELECT id, name, INET_NTOA(ip) AS ip, guid, INET_NTOA(server) AS server, date FROM 1up_people WHERE (name LIKE \"%$query%\" OR INET_NTOA(ip) LIKE \"%$query%\" OR guid LIKE \"%$query%\")"; $result = mysql_query($sql, $link); if (!$result) { die(mysql_error()); } // Now take the initial results and parse each column into its own array while ($row = mysql_fetch_array($result, MYSQL_NUM)) { $name = htmlspecialchars($row[1]); $people[] = array( 'id' => $row[0], 'name' => $name, 'ip' => $row[2], 'guid' => $row[3], 'server' => $row[4], 'date' => $row[5] ); } // now for each name, ip, guid in results, find additonal records $people2 = array(); foreach ($people AS $person) { $ip = $person['ip']; $sql = "SELECT id, name, INET_NTOA(ip) AS ip, guid, INET_NTOA(server) AS server, date FROM 1up_people WHERE (ip = \"$ip\")"; $result = mysql_query($sql, $link); while ($row = mysql_fetch_array($result, MYSQL_NUM)) { $name = htmlspecialchars($row[1]); $people2[] = array( 'id' => $row[0], 'name' => $name, 'ip' => $row[2], 'guid' => $row[3], 'server' => $row[4], 'date' => $row[5] ); } } $people3 = array(); foreach ($people AS $person) { $guid = $person['guid']; $sql = "SELECT id, name, INET_NTOA(ip) AS ip, guid, INET_NTOA(server) AS server, date FROM 1up_people WHERE (guid = \"$guid\")"; $result = mysql_query($sql, $link); while ($row = mysql_fetch_array($result, MYSQL_NUM)) { $name = htmlspecialchars($row[1]); $people3[] = array( 'id' => $row[0], 'name' => $name, 'ip' => $row[2], 'guid' => $row[3], 'server' => $row[4], 'date' => $row[5] ); } } $people4 = array(); foreach ($people AS $person) { $name = $person['name']; $sql = "SELECT id, name, INET_NTOA(ip) AS ip, guid, INET_NTOA(server) AS server, date FROM 1up_people WHERE (name = \"$name\")"; $result = mysql_query($sql, $link); while ($row = mysql_fetch_array($result, MYSQL_NUM)) { $name = htmlspecialchars($row[1]); $people4[] = array( 'id' => $row[0], 'name' => $name, 'ip' => $row[2], 'guid' => $row[3], 'server' => $row[4], 'date' => $row[5] ); } } // Combine people and people2 into just people $people = array_merge($people, $people2); $people = array_merge($people, $people3); $people = array_merge($people, $people4); $people = super_unique($people); foreach ($people AS $person) { $date = ($person['date']) ? date("M d, Y", $person['date']) : 'Before 8/1/10'; echo "<tr>\n"; echo "<td>".$person['id']."</td>"; echo "<td>".$person['name']."</td>"; echo "<td>".$person['ip']."</td>"; echo "<td>".$person['guid']."</td>"; echo "<td>".$person['server']."</td>"; echo "<td>".$date."</td>"; echo "</tr>\n"; $count++; } // Find Total Records //$result = mysql_query("SELECT id FROM 1up_people", $link); //$total = mysql_num_rows($result); mysql_close($link); } ?> </tbody> </table> <p> <?php echo $count." Records Found for \"".$_POST['query']."\" out of $total"; ?> </p> <?php } $time_stop = microtime(true); print("Done (ran for ".round($time_stop-$time_start)." seconds)."); ?> Any help at all is appreciated! Thank you.

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  • mysql stored funtion usage

    - by shikhar
    I just wrote a stored function to calculate the working days between two dates. This works select CountWeekDays('2010-03-07','2010-04-07') This doesn't work select CountWeekDays(o.order_date,o.created_date) from orders o; Any idea how to make this one work ?? function definition delimiter $$; CREATE FUNCTION CountWeekDays (sdate VARCHAR(50), edate VARCHAR(50)) RETURNS INT BEGIN DECLARE wdays, tdiff, counter, thisday smallint; DECLARE newdate DATE; SET newdate := sdate; SET wdays = 0; if DATEDIFF(edate, sdate) = 0 THEN RETURN 1; END IF; if DATEDIFF(edate, sdate) < 0 THEN RETURN 0; END IF; label1: LOOP SET thisday = DAYOFWEEK(newdate); IF thisday BETWEEN 2 AND 6 THEN SET wdays := wdays + 1; END IF; SET newdate = DATE_ADD(newdate, INTERVAL 1 DAY); IF DATEDIFF(edate, newdate) < 0 THEN LEAVE label1; END IF; END LOOP label1; RETURN wdays; END

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  • MySQL: 4 Table "has-many-through" Join?

    - by Nebs
    Let's say I have the following 4 tables (for examples' sake): Owners, Trucks, Boxes, Apples. An owner can have many trucks, a truck can have many boxes and a box can have many apples. Owners have an id. Trucks have an id and owner_id. Boxes have an id and truck_id. Apples have an id and box_id. Let's say I want to get all the apples "owned" by an owner with id = 34. So I want to get all the boxes that are in boxes that are in trucks that owner 34 owns. There is a "hierarchy" if you will of 4 tables that each only has reference to its direct "parent". How can I quickly filter boxes while satisfying conditions across the other 3 tables? I hope that made sense somewhat. Thanks.

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  • Different meaning in the mysql code?

    - by Emre Saracoglu
    $result=mysql_query("select * from dosyabegeni where veri_id='" . get_custom_field('dwcode') . "'"); Not Working It says the number and the screen, but the application does not work veri_id='" . get_custom_field('dwcode') . "'"); veri_id='" . echo get_custom_field('dwcode') . "'"); Working veri_id='HelloTest'"); veri_id='1234567890'"); veri_id='" . $_GET['test'] . "'"); Main Codes <?php include('/home/emre2010/public_html/EntegreOz/DosyaBegeni/config.php'); $result=mysql_query("select * from dosyabegeni where veri_id='" .get_custom_field('dwcode') . "'"); while($row = mysql_fetch_array($result)) { $sira_id=$row['sira_id']; $veri_id=$row['veri_id']; $begeni=$row['begeni']; ?> <div class="reviewbox"> <div class="summarywrap"> <div class="summarywrapinner"> <div class="summary"> <div class="reviewsection"><div class="rating points"> <a href="#" class="begeni" id="<?php echo $sira_id; ?>"> <span style="color:#fff;" align="center"> <?php echo $begeni; ?> </span> </a> <p class="ratingtext">completed!</p></div> </div><div class="clear"></div> <div class="clear"></div> </div> <div class="ratingsummary"></div> <div class="clear"></div> </div> <div class="clear"></div> </div> What's the problem?

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  • Adding with PHP to a MySQL database

    - by shinjuo
    I am pretty new to PHP and I am trying to make an inventory database. I have been trying to make it so that a user can enter a card ID and then amount the want to add to the inventory and have it update the inventory. For example someone could type in test and 2342 and it would update test. Here is what I have been trying with no success: add.html <body> <form action="add.php" method="post"> Card ID: <input type="text" name="CardID" /> Amount to Add: <input type="text" name="Add" /> <input type="submit" /> </form> </body> </html> add.php <?php $link = mysql_connect('tulsadir.ipowermysql.com', 'cbouwkamp', '!starman1'); if (!$link){ die('Could not connect: ' . mysql_error()); } mysql_select_db("tdm_inventory", $link); $add = $_POST[Add] mysql_query("UPDATE cardLists SET AmountLeft = '$add' WHERE cardID = 'Test'"); echo "test successful"; mysql_close($link); ?>

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  • MySQL: difference of two result sets

    - by Zombies
    How can I get the set difference of two result sets? Say I have a result set (just one column in each): result1: 'a' 'b' 'c' result2: 'b' 'c' I want to minus what is in result1 by result2: result1 - result2 such that it equals: difference of result1 - result2: 'a'

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  • Filtering out unique rows in MySQL

    - by jpatokal
    So I've got a large amount of SQL data that looks basically like this: user | src | dst 1 | 1 | 1 1 | 1 | 1 1 | 1 | 2 1 | 1 | 2 2 | 1 | 1 2 | 1 | 3 I want to filter out pairs of (src,dst) that are unique to one user (even if that user has duplicates), leaving behind only those pairs belonging to more than one user: user | src | dst 1 | 1 | 1 1 | 1 | 1 2 | 1 | 1 In other words, pair (1,2) is unique to user 1 and pair (1,3) to user 2, so they're dropped, leaving behind only all instances of pair (1,1). Any ideas? The answers to the question below can find the non-unique pairs, but my SQL-fu doesn't suffice to handle the complication of requiring that they belong to multiple users as well. [SQL question] How to select non "unique" rows

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  • MYSQL - SImple database design

    - by sequelDesigner
    Hello guys, I would like to develop a system, where user will get the data dynamically(what I mean dynamic is, without reloading pages, using AJAX.. but well, it does not matter much). My situation is like this. I have this table, I called it "player", in this player table, I will store the player information like, player name, level, experience etc. Each player can have different clothes, start from tops(shirts), bottoms, shoes, and hairstyle, and each player can have more than 1 tops, bottoms, shoes etc. What I am hesitated or not very sure about is, how do you normally store the data? My current design is like this: Player Table =========================================================================================== id | name | (others player's info) | wearing | tops | bottoms =========================================================================================== 1 | player1 | | top=1;bottom=2;shoes=5;hair=8 | 1,2,3| 7,2,3 Tops Table ===================== id | name | etc... ===================== 1 | t-shirt | ... I am not sure if this design is good. If you are the database designer, how would you design the database? Or how you will store them? Please advise. Thanks

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  • mysql add auto increment and a additional key

    - by Lee
    Hey all I am trying to alter a table with adding a new column setting it as auto increment and with a key. The table already has one key and this one will be an addition. The error I get is the following. error : Multiple primary key defined My code is: alter table user add column id int (11) NOT NULL AUTO_INCREMENT PRIMARY KEY FIRST; I have also tries wrapping the key name ie alter table user add column id int (11) NOT NULL AUTO_INCREMENT PRIMARY (id) KEY FIRST; But still no luck. How can it be done ?

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  • Find and replace braced tags within a MySQL table

    - by Cy
    I have about 40000 records in that table that contains plain text and within the plain text, contains that kind of tags which its only characteristic is that they are braced between [ ] [caption id="attachment_2948" align="alignnone" width="480" caption="the caption goes here"] How could I remove those? (replace by nothing) I could also run a PHP program if necessary to do the cleanup.

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  • SQL query: Last but one rank for user

    - by Derk
    My table structure looks like this: create table rankings ( id IDENTITY NOT NULL, user_id INT NOT NULL, game_poule_id INT NOT NULL, rank INT NOT NULL, insertDate DATETIME NOT NULL, FOREIGN KEY (user_id) REFERENCES users(id) ON DELETE CASCADE, FOREIGN KEY (game_poule_id) REFERENCES game_poules(id) ON DELETE CASCADE ); All old rankings of users per game are saved in this table. Now I want to have the last but one rank in the table for all users in a gamepoule. Has someone an idea how to achive this? Thanks

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  • select command in mysql doesnot return any row

    - by jeyshree
    i created a database using the command CREATE TABLE login_table2(user_name VARCHAR(32), first_name VARCHAR(32), last_name VARCHAR(32), password VARCHAR(64)); then i inserted a data using command INSERT INTO login_table2(user_name ,first_name , last_name , password ) VALUES('ramya', 'ramya', 'muthu', 'India'); the data got inserted into the table. then i inserted another set of data using command INSERT INTO login_table2(user_name ,first_name , last_name , password ) VALUES('jeyshree', 'jey', 'shree', 'India'); the data got inserted into the table too. then i gave the command SELECT first_name FROM login_table2; the command displayed all the first_ name in the table. however when i gave the command SELECT password FROM login_table2 WHERE user_name = 'ramya'; it does not fetch anything though the entry exist in the table.mention where i am going wrong.awaiting your reply.

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  • Fighing system in Php & MYSQL

    - by Gully
    I am working on a game like Mafia Wars and i am trying to get the fighting system working but i keep getting lose trying to work out who is going to win the fight and it still needs to know if the stats are close then there is a random chace of them winning. $strength = $my_strength; $otherplayerinfo = mysql_query("SELECT * FROM accounts WHERE id='$player_id'"); $playerinfo = mysql_fetch_array($otherplayerinfo); $players_strength = $playerinfo['stre']; $players_speed = $playerinfo['speed']; $players_def = $playerinfo['def']; if($players_strength > $strength){ $strength_point_player = 1; $strength_point_your = 0; }else{ $strength_point_your = 1; $strength_point_player = 0; } I was trying a point system but i still could not do it.

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  • MySQL Casting in C#

    - by user798080
    Okay, so I'm attempting to print out the contents of a table in a comma-separated file. using (OdbcCommand com = new OdbcCommand("SELECT * FROM pie_data WHERE Pie_ID = ?", con)) { com.Parameters.AddWithValue("", Request.Form["pie_id"]); com.ExecuteNonQuery(); using (OdbcDataReader reader = com.ExecuteReader()) { string finalstring = ""; while (reader.Read()) { finalstring = reader.GetString(9) + ","; for (int i = 0; i <= 8; i = i + 1) { finalstring = finalstring + reader.GetString(i) + ","; } } } Response.Write(finalstring); noredirect = 1; } My table layout is: CREATE TABLE `rent_data` ( `Pies` INT(10) UNSIGNED NOT NULL, `Name` VARCHAR(85) NOT NULL, `Email` VARCHAR(85) NOT NULL, `Pie_Rent` DATE NOT NULL, `Rent_To` DATE NOT NULL, `Returned_Date` DATE NULL DEFAULT NULL, `Place` VARCHAR(100) NOT NULL, `Purpose` MEDIUMTEXT NOT NULL, `Comments` MEDIUMTEXT NULL, `Pie_ID` SMALLINT(5) UNSIGNED ZEROFILL NOT NULL, INDEX `Pie_ID` (`Equipment_ID`) ) The error I'm getting is this: Exception Details: System.InvalidCastException: Unable to cast object of type 'System.Int64' to type 'System.String'. On the line: finalstring = finalstring + reader.GetString(i) + ",";

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  • mysql select update

    - by Tillebeck
    Hi I have read quite a few selcet+update questions in here but cannot understand how to do it. So will have to ask from the beginning. I would like to update a table based on data in another table. Setup is like this: - TABLE a ( int ; string ) ID WORD 1 banana 2 orange 3 apple - TABLE b ( "comma separated" string ; string ) WORDS TEXTAREA 0 banana -> 0,1 0 orange apple apple -> BEST:0,2,3 ELSE 0,2,3,3 0 banana orange apple -> 0,1,2,3 Now I would like to for each word in TABLE a append ",a.ID" to b.WORDS like: SELECT id, word FROM a (for each) -> UPDATE b SET words = CONCAT(words, ',', a.id) WHERE b.textarea like %a.word% Or even better: replace the word found in b.textarea with ",a.id" so it is the b.textarea that ends up beeing a comma separeted string of id's... But I do not know if that is possible.

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  • Storing apostrophes, exclamation marks, etc. in mysql database

    - by rein
    I changed from latin1 to utf8. Although all sorts of text was displaying fine I noticed non-english characters were stored in the database as weird symbols. I spent a day trying to fix that and finally now non-english characters display as non-english characters in the database and display the same on the browser. However I noticed that I see apostrophes stored as &#39; and exclamation marks stored as &#33;. Is this normal, or should they be appearing as ' and ! in the database instead? If so, what would I need to do in order to fix that?

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