Search Results

Search found 21809 results on 873 pages for 'display interfaces'.

Page 225/873 | < Previous Page | 221 222 223 224 225 226 227 228 229 230 231 232  | Next Page >

  • How to implement iPhone TitleBar in Android

    - by edwar12345
    You know in iPhone, The four components of a typical iPhone application are a title bar, a navigation list, a destination page, and a button bar. for The Title Bar The title bar includes the following elements: Back button: Screen title: Command button: My question comes, although i can use UI framework tool, such as: Phonegap, iui, jtquery to develop web app, but i can't display the TitleBar effect in Android, i can't use below code in Android: meta content="yes" name="apple-mobile-web-app-capable" Actually, the above can work in Apple Safari Browser, but I can't use Safari to display our Android Project, which is i don't want to see. Does anyone know how to fulfill this effect in Android, please help me, your help will be great appreciated. to "It's unclear if you developing a native android application or a webapp. – alexanderblom yesterday" sorry that i forget to mention, i want to develop a iphone-webapp-style application in Android. Since it's too difficult, i want to use iWebkit, but it seems only work in apple iPhone OS or Safari which contain the specific engine to display the beautiful layout, like below:( -_-! i am new so i can't post images here) http://images.appshopper.com/screenshots/305/690205_2.jpg

    Read the article

  • Can't SSH into Linux server

    - by Charissa
    I have access to a Ubuntu Server (10.4) that I can't SSH into. From a terminal the connection times out and from putty the connection is refused. I have checked that sshd is running and listening on all interfaces, iptables has all chains empty and default is ACCEPT, additional firewall is accepting on port 22 inbound, and all outbound. I can't telnet into port 22 either. What could the problem be and how can I troubleshoot it?

    Read the article

  • Show models.ManyToManyField as inline, with the same form as models.ForeignKey inline

    - by Kristian
    I have a model similar to the following (simplified): models.py class Sample(models.Model): name=models.CharField(max_length=200) class Action(models.Model): samples=models.ManyToManyField(Sample) title=models.CharField(max_length=200) description=models.TextField() Now, if Action.samples would have been a ForeignKey instead of a ManyToManyField, when I display Action as a TabularInline in Sample in the Django Admin, I would get a number of rows, each containing a nice form to edit or add another Action. However; when I display the above as an inline using the following: class ActionInline(admin.TabularInline): model=Action.samples.through I get a select box listing all available actions, and not a nifty form to create a new Action. My question is really: How do I display the ManyToMany relation as an inline with a form to input information as described? In principle it should be possible since, from the Sample's point of view, the situation is identical in both cases; Each Sample has a list of Actions regardless if the relation is a ForeignKey or a ManyToManyRelation. Also; Through the Sample admin page, I never want to choose from existing Actions, only create new or edit old ones.

    Read the article

  • Wordpress displays posts of category ID

    - by Miker
    Can't seem to find the right answer for what I thought would be trivial. I have some categories arranged like this... Parent Category 1 - Child Category 1 - Child Category 2 - Child Category 3 ...and I have some posts that are in Child Category 2. I want my page to display all posts from the category I am currently in. This is what I am doing right now: <?php query_posts('cat=2&showposts=10'); if (have_posts()) : while (have_posts()) : the_post(); ?> <div class="timeline"> <h3><?php the_title(); ?></h3> <?php the_content();?> <?php endwhile; else: ?> <?php _e('No Posts Sorry.'); ?> <?php endif; ?> </div> As you can see I am having to manually specify the category (cat=2), but instead I want it to automatically detect the category I am already in and display the posts (that way if I'm in a different category it will display those posts). Any suggestions? Thanks in advance. (SO Community = Awesome Sauce).

    Read the article

  • Excel Range Format: Number is automatically formatted when Range::Value2 is set

    - by A9S6
    I have an Excel addin written in C# that imports a text file into Excel worksheet. Some of the fields in the file are text and some oare numbers. Problem Steps: Change the System's Regional Settings to Dutch (Belgium) Open Excel and import the file into Excel. Records contain values such as 78,1118 which gets converted to 781.118. Note that in Dutch(Belgium), COMMA is the decimal character and DOT is the thousand character. I do not require the number to be formatted automatically but just want to display whatver I get from the file (78,1118). If I set the cell's NumberFormat to "@" i.e. Text, then it displays an error (SmartTag) saying "Number stored as Text". I know I can change the settings by going to the "Options" box but I dont want to change any user options in Excel for this. I have tried setting the cell's Value2 with an "'" (apostrophe) but the same error is displayed. If I set the cell's format to something else after the value is set then the actual value changes and I loose the decimal. Is there a way in Excel to just display the value and NOT display the "Number Stored as Text" error in cell?

    Read the article

  • search data from FileReader in Java

    - by maya
    hi I'm new in java how to read and search data from file (txt) and then display the data in TextArea or Jtable. for example I have file txt contains data and I need to display this data in textarea after I clicked a button, I have used FileReader , and t1 t2 tp are attributes in the file import java.io.FileReader; import java.io.IOException; String t1,t2,tp; Ffile f1= new Ffile(); FileReader fin = new FileReader("test2.txt"); Scanner src = new Scanner(fin); while (src.hasNext()) { t1 = src.next(); textarea.setText(t1); t2 = src.next(); textarea.setText(t2); tp = src.next(); textarea.setText(tp); f1.insert(t1,t2,tp); } fin.close(); also I have used the inputstream DataInputStream dis = null; String dbRecord = null; try { File f = new File("text2.text"); FileInputStream fis = new FileInputStream(f); BufferedInputStream bis = new BufferedInputStream(fis); dis = new DataInputStream while ( (dbRecord = dis.readLine()) != null) { StringTokenizer st = new StringTokenizer(dbRecord, ":"); String t1 = st.nextToken(); String t2 = st.nextToken(); String tp = st.nextToken(); textarea.setText(textarea.getText()+t1); textarea.setText(textarea.getText()+t2); textarea.setText(textarea.getText()+tp); } } catch (IOException e) { // catch io errors from FileInputStream or readLine() System.out.println("Uh oh, got an IOException error: " + e.getMessage()); } finally { } but both of them don't work ,so please any one help me I want to know how to read data and also search it from file and i need to display the data in textarea . thanks in advance

    Read the article

  • UISearchDisplayController not working when created in code??

    - by Nick Bedford
    I'm working on a tab bar application and one of the tabs has a UISearchDisplayController hooked up to a UISearchBar. It's all connected up in the NIB and is working. When I tap the search bar, the Scope and Cancel buttons fly in etc, and the search delegate updates the results table correctly. However, I'm trying to implement the same code in the viewDidLoad message instead of the NIB, however when I delete the search display controller from the NIB and uncomment my code to create the same controller in the function, it doesn't work. It's as if there's some fundamental connection not being made so that all my search delegate functionality isn't being called. Here's my working NIB version of the Search Display Controller. It's hooked up to the search bar, the UINavigationController subclass (MASearchController) and the root view of that is hooked up as the searchContentsController. Now this is what you would expect to do in code to create the same, right? What I'm doing is leaving the UISearchBar in the NIB to eliminate one piece of the puzzle at a time in code. // [MASearchController viewDidLoad] UISearchDisplayController *searchController = [[[UISearchDisplayController alloc] initWithSearchBar:searchBar contentsController:[[self viewControllers] objectAtIndex:0]] autorelease]; [searchController setDelegate:self]; [searchController setSearchResultsDelegate:self]; [searchController setSearchResultsDataSource:self]; I've checked all objects at run time and they all check out. Essentially I've deleted the search display controller from the NIB and then put in the code to create it in the viewDidLoad message. Why would this not work? The search keyboard comes up but none of my search and button animation functionality work???

    Read the article

  • jQuery fadeIn/fadeOut loop problem

    - by liebgott
    Hi. I'm trying to do a sequentiall animation with a loop....but i can't accomplish it in a smooth way (some "lag" problems). jQuery var i = 0; var b = 0; var fades = function(){$(".caja").stop(0).each(function(){ $(this).delay(i * 500).fadeIn('slow', function(){ $(this).delay(5000).fadeOut('slow', function(){ $(".cajar").delay(1000).each(function(){ $(this).delay(b * 500).fadeIn('slow', function(){ $(this).delay(5000).fadeOut('slow', fades()); }); b++; }); }); }); i++; })} fades(); CSS .caja{ width: 150px; height: 150px; background-color: black; float: left; margin: 0 10px 0 0; display: none; } .cajar{ width: 150px; height: 150px; background-color: red; float: left; margin: 0 10px 0 0; display: none; } .cajav{ width: 150px; height: 150px; background-color: green; float: left; margin: 0 10px 0 0; display: none; } HTML <div class="caja"></div> <div class="caja"></div> <div class="caja"></div> <div class="cleaner"></div> <div class="cajar"></div> <div class="cajar"></div> <div class="cajar"></div> Thanks!

    Read the article

  • Overriding Only Some Default Parameters in ActionScript

    - by TheDarkIn1978
    i have a function which has all optional arguments. is it possible to override a an argument of a function without supplying the first? in the code below, i'd like to keep most of the default arguments for the drawSprite function, and only override the last argument, which is the sprite's color. but how can i call the object? DrawSprite(0x00FF00) clearly will not work. //Main Class package { import DrawSprite; import flash.display.Sprite; public class Start extends Sprite { public function Start():void { var myRect:DrawSprite = new DrawSprite(0x00FF00) addChild(myRect); } } } //Draw Sprite Class package { import flash.display.Sprite; import flash.display.Graphics; public class DrawSprite extends Sprite { private static const DEFAULT_WIDTH:Number = 100; private static const DEFAULT_HEIGHT:Number = 200; private static const DEFAULT_COLOR:Number = 0x000000; public function DrawSprite(spriteWidth:Number = DEFAULT_WIDTH, spriteHeight:Number = DEFAULT_HEIGHT, spriteColor:Number = DEFAULT_COLOR):void { graphics.beginFill(spriteColor, 1.0); graphics.drawRect(0, 0, spriteWidth, spriteHeight); graphics.endFill(); } } }

    Read the article

  • Linux (Ubuntu 12.04) two gateways one nic

    - by David
    I have Ubuntu 12.04 Server edition Two gateways, both on 192.168.0. network, let's make them 192.168.0.1 and 192.168.0.2 I've read you should be able to add second gateway into /etc/network/interfaces, that it will build out all the routing automatically, but I get "duplicate option" error. So if I have one default gateway, let's say 0.1, and a connection comes through from the 0.2 gateway, my understanding is that it still tries to respond through 0.1 gateway. Can we change this behavior?

    Read the article

  • Can't connect to samba

    - by Rick
    Windows 7, connecting to Samba shares I have a follow up question from the link above. I am running Samba 3.0.23d on FreeBSD is release 7.1 I changed the policies as described above but still cannot connect to the samba server with the windows 7 or a server 2008. I feel it is a problem with recognizing the new machines on the network. the windows machines can see the samba server, but cannot connect to it or view any of the files. After changing the security policies the samba server asked for network id and password but would not allow the machine to connect, said they were unknown username or bad password. Here is my current config file. there is no sign of encryption anywhere, should I just add the line? not sure what that would do elsewhere. Workgroup = WWOFFSET server string = WWO File Server (%v) security = server username map = /usr/local/etc/smb.users hosts allow = 10. 127. # If you want to automatically load your printer list rather # than setting them up individually then you'll need this ; load printers = yes # you may wish to override the location of the printcap file ; printcap name = /etc/printcap # on SystemV system setting printcap name to lpstat should allow # you to automatically obtain a printer list from the SystemV spool # system ; printcap name = lpstat # It should not be necessary to specify the print system type unless # it is non-standard. Currently supported print systems include: # bsd, cups, sysv, plp, lprng, aix, hpux, qnx ; printing = cups # Uncomment this if you want a guest account, you must add this to /etc/passwd # otherwise the user "nobody" is used ; guest account = pcguest # this tells Samba to use a separate log file for each machine # that connects log file = /var/log/samba/log.%m # Put a capping on the size of the log files (in Kb). max log size = 50 # Use password server option only with security = server # The argument list may include: # password server = My_PDC_Name [My_BDC_Name] [My_Next_BDC_Name] # or to auto-locate the domain controller/s # password server = * ; password server = <NT-Server-Name> password server = SERVER0 # Use the realm option only with security = ads # Specifies the Active Directory realm the host is part of ; realm = MY_REALM # Backend to store user information in. New installations should # use either tdbsam or ldapsam. smbpasswd is available for backwards # compatibility. tdbsam requires no further configuration. ; passdb backend = tdbsam ; passdb backend = smbpasswd # Using the following line enables you to customise your configuration # on a per machine basis. The %m gets replaced with the netbios name # of the machine that is connecting. # Note: Consider carefully the location in the configuration file of # this line. The included file is read at that point. ; include = /usr/local/etc/smb.conf.%m # Most people will find that this option gives better performance. # See the chapter 'Samba performance issues' in the Samba HOWTO Collection # and the manual pages for details. # You may want to add the following on a Linux system: # SO_RCVBUF=8192 SO_SNDBUF=8192 socket options = TCP_NODELAY # Configure Samba to use multiple interfaces # If you have multiple network interfaces then you must list them # here. See the man page for details. ; interfaces = 192.168.12.2/24 192.168.13.2/24 # Browser Control Options: # set local master to no if you don't want Samba to become a master # browser on your network. Otherwise the normal election rules apply ; local master = no # OS Level determines the precedence of this server in master browser # elections. The default value should be reasonable ; os level = 33 # Domain Master specifies Samba to be the Domain Master Browser. This # allows Samba to collate browse lists between subnets. Don't use this # if you already have a Windows NT domain controller doing this job ; domain master = yes # Preferred Master causes Samba to force a local browser election on startup # and gives it a slightly higher chance of winning the election ; preferred master = yes # Enable this if you want Samba to be a domain logon server for # Windows95 workstations. ; domain logons = yes # if you enable domain logons then you may want a per-machine or # per user logon script # run a specific logon batch file per workstation (machine) ; logon script = %m.bat # run a specific logon batch file per username ; logon script = %U.bat # Where to store roving profiles (only for Win95 and WinNT) # %L substitutes for this servers netbios name, %U is username # You must uncomment the [Profiles] share below ; logon path = \\%L\Profiles\%U # Windows Internet Name Serving Support Section: # WINS Support - Tells the NMBD component of Samba to enable it's WINS Server ; wins support = yes # WINS Server - Tells the NMBD components of Samba to be a WINS Client # Note: Samba can be either a WINS Server, or a WINS Client, but NOT both ; wins server = w.x.y.z # WINS Proxy - Tells Samba to answer name resolution queries on # behalf of a non WINS capable client, for this to work there must be # at least one WINS Server on the network. The default is NO. ; wins proxy = yes # DNS Proxy - tells Samba whether or not to try to resolve NetBIOS names # via DNS nslookups. The default is NO. dns proxy = no # charset settings ; display charset = ASCII ; unix charset = ASCII ; dos charset = ASCII # These scripts are used on a domain controller or stand-alone # machine to add or delete corresponding unix accounts ; add user script = /usr/sbin/useradd %u ; add group script = /usr/sbin/groupadd %g ; add machine script = /usr/sbin/adduser -n -g machines -c Machine -d /dev/null -s /bin/false %u ; delete user script = /usr/sbin/userdel %u ; delete user from group script = /usr/sbin/deluser %u %g ; delete group script = /usr/sbin/groupdel %g unix extensions = no

    Read the article

  • VB.NET invalid cast exception

    - by user127147
    Hi there, I have a simple application to store address details and edit them. I have been away from VB for a few years now and need to refreash my knowledge while working to a tight deadline. I have a general Sub responsible for displaying a form where user can add contact details (by pressing button add) and edit them (by pressing button edit). This sub is stored in a class Contact. The way it is supposed to work is that there is a list with all the contacts and when new contact is added a new entry is displayed. If user wants to edit given entry he or she selects it and presses edit button Public Sub Display() Dim C As New Contact C.Cont = InputBox("Enter a title for this contact.") C.Fname = frmAddCont.txtFName.Text C.Surname = frmAddCont.txtSName.Text C.Address = frmAddCont.txtAddress.Text frmStart.lstContact.Items.Add(C.Cont.ToString) End Sub I call it from the form responsible for adding new contacts by Dim C As New Contact C.Display() and it works just fine. However when I try to do something similar using the edit button I get errors - "Unable to cast object of type 'System.String' to type 'AddressBook.Contact'." Dim C As Contact If lstContact.SelectedItem IsNot Nothing Then C = lstContact.SelectedItem() C.Display() End If I think it may be something simple however I wasn't able to fix it and given short time I have I decided to ask for help here. Thank you

    Read the article

  • NullPointerException when installing the Android SDK on Mac OS X

    - by Feanor
    I'm installing the Android SDK on Mac OS X. Following the instructions on the Android Development site, I've downloaded the SDK and modified my .bash_profile to include the path. The next step is to use the Android SDK and AVD Manager to actually download the platforms. However, when I use the Manager to install the platforms, I get the following error in the Terminal. I've looked around for similar problems in the Eclipse and Android forums and haven't found anything yet. Is something else damaged in the environment and needs to be repaired? Any recommendations on where I should look? java.lang.NullPointerException at org.eclipse.swt.graphics.Device.getFontList(Unknown Source) at org.eclipse.jface.resource.FontRegistry.filterData(FontRegistry.java:456) at org.eclipse.jface.resource.FontRegistry.createFont(FontRegistry.java:490) at org.eclipse.jface.resource.FontRegistry.defaultFontRecord(FontRegistry.java:551) at org.eclipse.jface.resource.FontRegistry.defaultFontData(FontRegistry.java:563) at org.eclipse.jface.resource.FontRegistry.getFontData(FontRegistry.java:579) at org.eclipse.jface.dialogs.Dialog.dialogFontIsDefault(Dialog.java:1077) at org.eclipse.jface.dialogs.Dialog.applyDialogFont(Dialog.java:998) at org.eclipse.jface.dialogs.Dialog.createContents(Dialog.java:756) at org.eclipse.jface.window.Window.create(Window.java:431) at org.eclipse.jface.dialogs.Dialog.create(Dialog.java:1089) at com.android.sdkuilib.internal.repository.UpdateChooserDialog.create(UpdateChooserDialog.java:280) at org.eclipse.jface.window.Window.open(Window.java:790) at com.android.sdkuilib.internal.repository.UpdaterData.updateOrInstallAll(UpdaterData.java:502) at com.android.sdkuilib.internal.repository.RemotePackagesPage.onInstallSelectedArchives(RemotePackagesPage.java:323) at com.android.sdkuilib.internal.repository.RemotePackagesPage.access$600(RemotePackagesPage.java:54) at com.android.sdkuilib.internal.repository.RemotePackagesPage$7.widgetSelected(RemotePackagesPage.java:168) at org.eclipse.swt.widgets.TypedListener.handleEvent(Unknown Source) at org.eclipse.swt.widgets.EventTable.sendEvent(Unknown Source) at org.eclipse.swt.widgets.Display.sendEvent(Unknown Source) at org.eclipse.swt.widgets.Widget.sendEvent(Unknown Source) at org.eclipse.swt.widgets.Widget.sendEvent(Unknown Source) at org.eclipse.swt.widgets.Widget.sendEvent(Unknown Source) at org.eclipse.swt.widgets.Widget.notifyListeners(Unknown Source) at org.eclipse.swt.widgets.Display.runDeferredEvents(Unknown Source) at org.eclipse.swt.widgets.Display.readAndDispatch(Unknown Source) at com.android.sdkuilib.internal.repository.UpdaterWindowImpl.open(UpdaterWindowImpl.java:104) at com.android.sdkuilib.repository.UpdaterWindow.open(UpdaterWindow.java:110) at com.android.sdkmanager.Main.showMainWindow(Main.java:281) at com.android.sdkmanager.Main.doAction(Main.java:247) at com.android.sdkmanager.Main.run(Main.java:92) at com.android.sdkmanager.Main.main(Main.java:81) logout

    Read the article

  • 3 columns layout, want middle column to stretch wider when column 1 and 3 are empty

    - by Blankman
    I have a 3 column layout using table-less design. <div id="main"> <div id="left"></div> <div id="content"></div> <div id="right"></div> </div> The CSS: #left {width: 200px;float:left;display:inline;} #content {width: 600px;float:left;display:inline;padding: 0 10px;} #right {width: 160px;float:left;display:inline;} I am using a web application, and I can't change the layout. By can't change, I mean the div's with left/content/right cannot be removed. On some pages, both the left and right columns are completely empty. And I want the #content div to expand more than the 600px. is this possible, without altering the HTML? What are my options? Thanks allot!

    Read the article

  • How do I redirect the kernel console output on Ubuntu 10.04

    - by lorin
    When I reboot my Ubuntu 10.04 nodes, I'd like to be able to see the kernel boot messages when connecting to the IPMI interfaces using Serial Over LAN mode (ttyS0). What do I need to do to be able to redirect these messages to ttyS0? Ideally, I'd like them to also still appear in the usual place (tty0, I think) for when I plug a monitor directly into the box.

    Read the article

  • create graph using adjacency list

    - by sum1needhelp
    #include<iostream> using namespace std; class TCSGraph{ public: void addVertex(int vertex); void display(); TCSGraph(){ head = NULL; } ~TCSGraph(); private: struct ListNode { string name; struct ListNode *next; }; ListNode *head; } void TCSGraph::addVertex(int vertex){ ListNode *newNode; ListNode *nodePtr; string vName; for(int i = 0; i < vertex ; i++ ){ cout << "what is the name of the vertex"<< endl; cin >> vName; newNode = new ListNode; newNode->name = vName; if (!head) head = newNode; else nodePtr = head; while(nodePtr->next) nodePtr = nodePtr->next; nodePtr->next = newNode; } } void TCSGraph::display(){ ListNode *nodePtr; nodePtr = head; while(nodePtr){ cout << nodePtr->name<< endl; nodePtr = nodePtr->next; } } int main(){ int vertex; cout << " how many vertex u wan to add" << endl; cin >> vertex; TCSGraph g; g.addVertex(vertex); g.display(); return 0; }

    Read the article

  • problem on ajax call

    - by praveen
    hi i am using mootools ajax request in my project. its works properly but when i make request for it aborted first time and second time request mad. consequently abortion of request increase by one at each click. my code is following function addStepConfiguration(id,mystrip,comment,error,submitid) { // alert(id+'\n'+mystrip+'\n'+comment+'\n'+error+'\n'+submitid.value); $(id).addEvent('submit', function(e) { e.stop(); this.set('send', { onRequest:function(html){ $(submitid).setStyle('display','none'); loading_Img(); }, onComplete: function(responseText) { $('loading_img').innerHTML = ''; SplittedResText = responseText.split("|"); s //alert(SplittedResText); if(SplittedResText[1]=='undefined') { $(error).innerHTML=SplittedResText[0]; $(submitid).setStyle('display','block'); } else { $(comment).innerHTML=SplittedResText[0]; $(mystrip).set('class',SplittedResText[1]); //$(image).setProperty('src',SplittedResText[2]); removeMsg.delay(20,'',error); removeMsg.delay(3000,'',comment); $(submitid).setStyle('display','block'); } } }); this.send(); }); }

    Read the article

  • Unix Password Management Keyring

    - by Phil
    I am looking for a password manager for a command-line Unix environment. So far all I can find are keyring applications for Windows, Linux, and Mac. But no command-line Unix interfaces. My main goal is to be able to access a password keyring through an SSH connection to a machine that has no graphical user interface. If there are no good unix password keyrings out there, what would be a better way to store personal passwords in a central location?

    Read the article

  • Enable/disable RequiredValidator on client-side / CustomValidator not firing

    - by Simeon
    I've got a drop-down where the user selects a Country. It is a required "field". Next to it, there is a textfield named State. If the user selects US, then the field State is required. If the user selects e.g. Sweden, the State is not required, since Sweden has no states. Example code: <asp:DropDownList runat="server" ID="Country"></asp:DropDownList> <asp:RequiredFieldValidator ControlToValidate="Country" runat="server" Display="Static" ErrorMessage="Required field" /> <asp:TextBox runat="server" ID="State"></asp:TextBox> <asp:CustomValidator ClientValidationFunction="DoesntGetFiredIfStateIsEmpty" runat="server" Display="Static" ErrorMessage="Required field" /> <!-- SO, RATHER THIS TOGETHER WITH CONDITIONAL FIRING --> <asp:RequiredFieldValidator ControlToValidate="State" runat="server" Display="Static" ErrorMessage="Required field" /> My question to you is: How can I make this CustomValidator fire validation when it is empty? Or put simplier: How can I make a RequiredValidator fire conditionally? Or simplest: How can I enable/disable a RequiredValidator on client-side?

    Read the article

  • How can I terminate a system command with alarm in Perl?

    - by rockyurock
    I am running the below code snippet on Windows. The server starts listening continuously after reading from client. I want to terminate this command after a time period. If I use alarm() function call within main.pl, then it terminates the whole Perl program (here main.pl), so I called this system command by placing it in a separate Perl file and calling this Perl file (alarm.pl) in the original Perl File using the system command. But in this way I was unable to take the output of this system() call neither in the original Perl File nor in called one Perl File. Could anybody please let me know the way to terminate a system() call or take the output in that way I used above? main.pl my @output = system("alarm.pl"); print"one iperf completed\n"; open FILE, ">display.txt" or die $!; print FILE @output_1; close FILE; alarm.pl alarm 30; my @output_1 = readpipe("adb shell cd /data/app; ./iperf -u -s -p 5001"); open FILE, ">display.txt" or die $!; print FILE @output_1; close FILE; In both ways display.txt is always empty.

    Read the article

  • How to use JQUERY to filter table rows dynamically using multiple form inputs

    - by tresstylez
    I'm displaying a table with multiple rows and columns. I'm using a JQUERY plugin called uiTableFilter which uses a text field input and filters (shows/hides) the table rows based on the input you provide. All you do is specify a column you want to filter on, and it will display only rows that have the text field input in that column. Simple and works fine. I want to add a SECOND text input field that will help me narrow the results down even further. So, for instance if I had a PETS table and one column was petType and one was petColor -- I could type in CAT into the first text field, to show ALL cats, and then in the 2nd text field, I could type black, and the resulting table would display only rows where BLACK CATS were found. Basically, a subset. Here is the JQUERY I'm using: $("#typeFilter").live('keyup', function() { if ($(this).val().length > 2 || $(this).val().length == 0) { var newTable = $('#pets'); $.uiTableFilter( theTable, this.value, "petType" ); } }) // end typefilter $("#colorFilter").live('keyup', function() { if ($(this).val().length > 2 || $(this).val().length == 0) { var newTable = $('#pets'); $.uiTableFilter( newTable, this.value, "petColor" ); } }) // end colorfilter Problem is, I can use one filter, and it will display the correct subset of table rows, but when I provide input for the other filter, it doesn't seem to recognize the visible table rows that are remaining from the previous column, but instead it appears that it does an entirely new filtering of the original table. If 10 rows are returned after applying one filter, the 2nd filter should only apply to THOSE 10 rows. I've tried LIVE and BIND, but not working. Can anyone shed some light on where I'm going wrong? Thanks!

    Read the article

  • ASP.NET-MVC Page: image logo is not displaying while sending the email

    - by Rita
    Hi I have a page that sends an email on ASP.NET MVC Page. All the Text is displaying but the image is not displaying. Any workaround. Appreciate your responses. Here is my code: MailMessage mailMsg = new MailMessage(); mailMsg.IsBodyHtml = true; mailMsg.From = new MailAddress(ConfigurationManager.AppSettings["Email.Sender"]); mailMsg.To.Add(new MailAddress(email)); mailMsg.Subject = "Test mail to display the Logo in the email"; mailMsg.Body = " Test mail to display the Logo in the email; mailMsg.Body += Environment.NewLine + Environment.NewLine + "<html><body><img src=cid:companylogo/><br></body></html>"; //Insert Logo string logoPath = Server.MapPath(Links.Content.images.Amgen_MedInfo_Logo_jpg); // logo is placed in images folder LinkedResource logo = new LinkedResource(logoPath); logo.ContentId = "companylogo"; // done HTML formatting in the next line to display logo AlternateView aView = AlternateView.CreateAlternateViewFromString(mailMsg.Body, new System.Net.Mime.ContentType("text/html")); aView.LinkedResources.Add(logo); mailMsg.AlternateViews.Add(aView); mailMsg.IsBodyHtml = true; SmtpClient smtpClient = new SmtpClient(ConfigurationManager.AppSettings["SMTP"]); smtpClient.Send(mailMsg);

    Read the article

  • Wireless disabled after connecting ethernet cable

    - by user1716672
    Im using Linux Mint 13. Wireless has always worked fine but stopped yesterday after I connected to the internet via an ethernet cable. I ran: sudo rfkill list gives me: 0: phy0: Wireless LAN Soft blocked: yes Hard blocked: no sudo rfkill unblock 0 sudo rfkill list gives me 0: phy0: Wireless LAN Soft blocked: no Hard blocked: no sudo service networking start results in: networking stop/waiting The contents of /etc/network/interfaces is auto lo iface lo inet loopback Any ideas what I can do?

    Read the article

  • HTML onmouseover doesn't work to show up text

    - by REALFREE
    I'm trying to show some information on a picture when onmouseover/onmouseout event occurs. What I want to achieve is something like this website does on top selling. My code is like this: <div class="container" onmouseover="$('#info').css('display','block');" onmouseout="$('#info').css('display','none');"> <img src=..."> <div id="info" style="display:none"> ... some text ... </div> </div> So div info block is initially hidden, but when mouse is on a picture I want the information to appear on corresponding picture (with tint background on the image to see text well). But somewhat it doesn't work. I appreciate any suggestion how to approach this problem. Edit: more precisely, the reason why I choose to use inline because I need to show/hide text corresponding to the image(contain unique div id)that user put their mouse on/out. That means I have many div container and each container has unique div id.

    Read the article

  • Content-disposition:inline header won't show images inline?

    - by hamstar
    I'm trying to show an image inline on a page. It is being served by a codeigniter controller. class Asset extends MY_Controller { function index( $folder, $file ) { $asset = "assets/$folder/$file"; if ( !file_exists( $asset ) ) { show_404(); return; } switch ( $folder ) { case 'css': header('Content-type: text/css'); break; case 'js': header('Content-type: text/javascript'); break; case 'images': $ext = substr( $file, strrpos($file, '.') ); switch ( $ext ) { case 'jpg': $ext = 'jpeg'; break; case 'svg': $ext = 'svg+xml'; break; } header('Content-Disposition: inline'); header('Content-type: image/'.$ext); } readfile( $asset ); } } When I load a image in Chrome of FF its pops up the download window. I know when the browser can't display the content inline it will force a download anyway, but these are PNG and GIF images which display in the browser fine otherwise. In IE it doesn't force a download but it displays the image in ASCII. If I comment out the entire image case it FF and Chrome both display the ASCII but not the image. I thought setting the content type would allow FF and Chrome to show the actual image, and also allow the location to be used as an src. The javascript and css shows fine of course. Anyone got any ideas how I can make the images show properly? Thanks :)

    Read the article

< Previous Page | 221 222 223 224 225 226 227 228 229 230 231 232  | Next Page >