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  • Python appengine Query does not work when using a variable.

    - by Lloyd
    Hi, I am trying to use a fetcher method to retrieve items from my datastore. If I use the following def getItem(item_id): q = Item.all() q.filter("itemid = ", item_id) It fails because nothing is returned. If I hard code in an item like def getItem(item_id): q = Item.all() q.filter("itemid = ", 9000) it fetches just fine, and sings merrily along. I have tried every which way to get this to work. I have used result = db.GqlQuery("SELECT * FROM Item WHERE item_id = :1 LIMIT 1", title).fetch(1) to the same effect. If I hard code in a number, works fine. I have tried setting the select statement as a local string, assembling it that way, casting the int as a string, and nothing. When I output the SELECT statement to the screen, looks fine. I can cut ans paste the output into the string, and whammo, it works. Any help would be appreciated.

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  • How should I declare default values for instance variables in Python?

    - by int3
    Should I give my class members default values like this: class Foo: num = 1 or like this? class Foo: def __init__(self): self.num = 1 In this question I discovered that in both cases, bar = Foo() bar.num += 1 is a well-defined operation. I understand that the first method will give me a class variable while the second one will not. However, if I do not require a class variable, but only need to set a default value for my instance variables, are both methods equally good? Or one of them more 'pythonic' than the other? One thing I've noticed is that in the Django tutorial, they use the second method to declare Models. Personally I think the second method is more elegant, but I'd like to know what the 'standard' way is.

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  • Python instances and attributes: is this a bug or i got it totally wrong?

    - by Mirko Rossini
    Suppose you have something like this: class intlist: def __init__(self,l = []): self.l = l def add(self,a): self.l.append(a) def appender(a): obj = intlist() obj.add(a) print obj.l if __name__ == "__main__": for i in range(5): appender(i) A function creates an instance of intlist and calls on this fresh instance the method append on the instance attribute l. How comes the output of this code is: [0] [0, 1] [0, 1, 2] [0, 1, 2, 3] [0, 1, 2, 3, 4] ? If i switch obj = intlist() with obj = intlist(l=[]) I get the desired output [0] [1] [2] [3] [4] Why this happens? Thanks

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  • Python:How to override inner class methods if the inner class is defined as a property of the top cl

    - by Maddy
    I have a code snippet like this class A(object): class b: def print_hello(self): print "Hello world" b = property(b) And I want to override the inner class 'b'(please dont worry about the lowercase name) behaviour. Say, I want to add a new method or I want to change an existing method, like: class C(A): class b(A.b): def print_hello(self): print "Inner Class: Hello world" b = property(b) Now if I create C's object as c = C(), and call c.b I get TypeError: 'property' object is not callable error. How would I get pass this and call print_hello of the extended inner class? Disclaimer: I dont want to change the code for A class.

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  • So, I guess I can't use "&&" in the Python if conditional. Any help?

    - by Sergio Tapia
    Here's my code: # F. front_back # Consider dividing a string into two halves. # If the length is even, the front and back halves are the same length. # If the length is odd, we'll say that the extra char goes in the front half. # e.g. 'abcde', the front half is 'abc', the back half 'de'. # Given 2 strings, a and b, return a string of the form # a-front + b-front + a-back + b-back def front_back(a, b): # +++your code here+++ if len(a) % 2 == 0 && len(b) % 2 == 0: return a[:(len(a)/2)] + b[:(len(b)/2)] + a[(len(a)/2):] + b[(len(b)/2):] else: #todo! Not yet done. :P return I'm getting an error in the IF conditional. What am I doing wrong?

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  • Where is a good place/way to store Windows config files for Python scripts?

    - by thornomad
    I have a script/program I am working on that requires a configuration file (I am using ConfigParser). On linux, I will default to store these variables in ~/.myscript using the os.getenv('HOME') function. With Windows, I know I can use os.getenv('USERPROFILE') to find the User's "home" directory, however, is it a good idea to save a hidden file that way (ie, with the name .myscript)? I don't use Windows, obviously, but wanted to be smart about it for those who do. Is there a standard place/way to store these config variables on Windows?

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  • Create function in python to find the highest of all function arguments, and return the "tag" of the value.

    - by gatechgrad
    Consider the following: p1=1; p2=5; p3=7; highest=max(p1,p2,p3). The max function would return 7. I am looking to create a similar function, which would return "p3". I have created a small function (by simple comparisons) for the above example, shown below. however I am having trouble when the number of arguments go up. def highest(p1,p2,p3) if (p1p2) and (p1p3): return "p1" if (p2p1) and (p2p3): return "p2" if (p3p1) and (p3p1): return "p3". Is there a simpler way to do this

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  • how to scrawl file hosting website with scrapy in python?

    - by Veryel Hua
    Can anyone help me to figure out how to scrawl file hosting website like filefactory.com? I don't want to download all the file hosted but just to index all available files with scrapy. I have read the tutorial and docs with respect to spider class for scrapy. If I only give the website main page as the begining url I wouldn't not scrawl the whole site, because the scrawling depends on links but the begining page seems not point to any file pages. That's the problem I am thinking and any help would be appreciated!

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  • How can I specify a relative path in a Python logging config file?

    - by ClaudioA
    I've the following file to config logging: [loggers] keys=root [handlers] keys = root [formatters] keys = generic # Loggers [logger_root] level = DEBUG handlers = root # Handlers [handler_root] class = handlers.RotatingFileHandler args = ("test.log", "maxBytes=1*1024*1024", "backupCount=10") level = NOTSET formatter = generic # Formatters [formatter_generic] format = %(asctime)s,%(msecs)03d %(levelname)-5.5s [%(name)s] %(message)s datefmt = %Y-%m-%d %H:%M:%S In Development this works great, but when I deploy the application test.log is trying to be written in a path in which I don't have the necessary permission. So my question is, How can I do to specify a relative path in this configuration file.

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  • Why can I not access this class member in python?

    - by Peter Smit
    I have the following code class Transcription(object): WORD = 0 PHONE = 1 STATE = 2 def __init__(self): self.transcriptions = [] def align_transcription(self,model,target=Transcription.PHONE): pass The important part here is that I would like to have a class member as default value for a variable. This however gives the following error: NameError: name 'Transcription' is not defined Why is this not possible and what is the right (pythonic) way to do something like this.

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  • do the Python libraries have a natural dependence on the global namespace?

    - by msw
    I first ran into this when trying to determine the relative performance of two generators: t = timeit.repeat('g.get()', setup='g = my_generator()') So I dug into the timeit module and found that the setup and statement are evaluated with their own private, initially empty namespaces so naturally the binding of g never becomes accessible to the g.get() statement. The obvious solution is to wrap them into a class, thus adding to the global namespace. I bumped into this again when attempting, in another project, to use the multiprocessing module to divide a task among workers. I even bundled everything nicely into a class but unfortunately the call pool.apply_async(runmc, arg) fails with a PicklingError because buried inside the work object that runmc instantiates is (effectively) an assignment: self.predicate = lambda x, y: x > y so the whole object can't be (understandably) pickled and whereas: def foo(x, y): return x > y pickle.dumps(foo) is fine, the sequence bar = lambda x, y: x > y yields True from callable(bar) and from type(bar), but it Can't pickle <function <lambda> at 0xb759b764>: it's not found as __main__.<lambda>. I've given only code fragments because I can easily fix these cases by merely pulling them out into module or object level defs. The bug here appears to be in my understanding of the semantics of namespace use in general. If the nature of the language requires that I create more def statements I'll happily do so; I fear that I'm missing an essential concept though. Why is there such a strong reliance on the global namespace? Or, what am I failing to understand? Namespaces are one honking great idea -- let's do more of those!

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