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  • How to ensure DB security for a Windows Forms application?

    - by Vilx-
    The basic setup is classic - you're creating a Windows Forms application that connects to a DB and does all kinds of enterprise-y stuff. Naturally, such an application will have many users with different access rights in the DB, and each with their own login name and password. So how do you implement this? One way is to create a DB login for every application user, but that's a pretty serious thing to do, which even requires admin rights on the DB server, etc. If the DB server hosts several applications, the admins are quite likely not to be happy with this. In the web world typically one creates his own "Users" table which contains all the necessary info, and uses one fixed DB login for all interaction. That is all nice for a web app, but a windows forms can't hide this master login information, negating security altogether. (It can try to hide, but all such attempts are easily broken with a bit of effort). So... is there some middle way? Perhaps logging in with a fixed login, and then elevating priviledges from a special stored procedure which checks the username and password?

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  • Test if current page is inside a shadowbox? (so i can close the shadowbox and reopen that page in t

    - by Max Williams
    Hi all I have a couple of pages in my site which open in a shadowbox window rather than the main window. My problem is that if the user session expires, then the user clicks on one of the links that open in a shadowbox, they are redirected to the login page INSIDE THE SHADOWBOX, which i don't want. I've been trying to think of the best way to handle this - one way i thought of, which seems a bit clumsy tbh, was on the login page to test if we're in a shadowbox, and if we are then close it and redirect the parent window to the login page. a) does this seem like a sensible plan? I added the following to my login page, which works: $(document).ready(function(){ if(window.parent.location != window.location){ window.parent.location.href = window.location; } } but i have to wait for the shadowbox to finish loading the page and then redirect. So it's working but like i say a bit clumsy. Is there a nicer way? grateful for any advice - max

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  • How to use Grails Spring Security Plugin to require logging in before access an action?

    - by Hoàng Long
    Hi all, I know that I can use annotation or Request mapping to restrict access to an ACTION by some specific ROLES. But now I have a different circumstance. My scenario is: every user of my site can create posts, and they can make their own post public, private, or only share to some other users. I implement sharing post by a database table PERMISSION, which specify if a user have the right to view a post or not. The problem arises here is that when a customer access a post through a direct link, how can I determine he/she have the privilege to view it? There's 3 circumstances: The post is public, so it can be viewed by anyone (include not-login user) The post is private, so only the login-owner can view it The post is sharing, it means only the login-user that is shared and the owner can view it. I want to process like this: If the requested post is public: ok. If the requested post is private/sharing: I want to redirect the customer to the login page; after logging in, the user will be re-direct to the page he wants to see. The problem here is that I can redirect the user to login controller/ auth action, but after that I don't know how to redirect it back. The link to every post is different by post_id, so I can't use SpringSecurityUtils.securityConfig.successHandler.defaultTargetUrl Could anyone know a way to do this?

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  • How to set the returnURL manually when using Ajax.ActionLink

    - by Roge
    I have this link @Ajax.ActionLink("create poll question", "CreatePoll", new { id = Model.DebateID }, new AjaxOptions { UpdateTargetId = "poll-entry-box", InsertionMode = InsertionMode.Replace, HttpMethod = "GET" }) which is pointing at a action with the [Authorize] Attribute. The login works, but the returnURL is empty so it just redirects to the index page. Is there some way to manually set the returnURL ? NOTE I am using the method described here http://haacked.com/archive/2011/10/04/prevent-forms-authentication-login-page-redirect-when-you-donrsquot-want.aspx because the login page was loading inside my partial.

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  • PHP Frontpage/Page controller

    - by atno
    I using the following as Frontpage/Page Controller(s) and it's working ok so far, except two problems I'm facing which as you can see are the $pages array and the switch, which are actually much much longer as the one I've pasted here. Everytime there is a need for a new page controller I have to add it to $pages array and to switch which makes that list very long. How would you overcome this problem and do you see any other improvement on this code? loadLogic() in page controllers it is used to get functions under pages/controllername/logic/function.php. Frontpage Controller - index.php: include 'common/common.php'; if(!isset($_GET['p']) OR $_GET['p'] == ''){ $_GET['p'] = 'home'; header('Location: index.php?p=home'); } $pages = array('home','register','login','logout','page1','page2','page3'); $_GET['p'] = trim($_GET['p']); if(isset($_GET['p'])){ if(in_array($_GET['p'], $pages)){ switch ($_GET['p']) { case 'home': include 'home.php'; break; case 'register': include 'register.php'; break; case 'login': include 'login.php'; break; case 'logout': include 'logout.php'; break; case 'page1': include 'page1.php'; break; case 'page2': include 'page2.php'; break; case 'page3': include 'page3.php'; break; } }else{ echo '404!'; } } Page Controller - {home,register,login,logout,page1,page2,page3}.php: include 'tpl/common/header.php'; contentStart(); if(isset($_SESSION['logged'])){ loadLogic('dashboard'); }else{ loadLogic('nologin'); } //Display login form in logic page instead links // if(!isset($_SESSION['logged'])){ contentEnd(); loadLogic('nologinForm'); }else{ contentEnd(); include'tpl/common/rcol.php'; } include 'tpl/common/footer.php'; function loadLogic(): function loadLogic($logic) { $path = dirname(__DIR__) . '/pages'; $controller = preg_split('/&/',$_SERVER['QUERY_STRING']); $controller = trim($controller[0],"p="); $logicPath = 'logic'; $logic = $logic . '.php'; $err = 0; $logicFullPath = $path.'/'.$controller.'/'.$logicPath.'/'.$logic; if($err == '0'){ include "$logicFullPath"; } } Folder Structure: projectName | ---> common | ---> pages | | | --->home | | | --->register | | | --->login | | | --->logout | | | --->page1 | | | --->page2 | | | --->page3 | ---> tpl | | | ---> common | --> home.php | --> register.php | --> login.php | --> logout.php | --> page1.php | --> page2.php | --> page3.php

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  • Qt/PyQt dialog with togglable fullscreen mode - problem on Windows

    - by Guard
    I have a dialog created in PyQt. It's purpose and functionality don't matter. The init is: class MyDialog(QWidget, ui_module.Ui_Dialog): def __init__(self, parent=None): super(MyDialog, self).__init__(parent) self.setupUi(self) self.installEventFilter(self) self.setWindowFlags(Qt.Dialog | Qt.WindowTitleHint) self.showMaximized() Then I have event filtering method: def eventFilter(self, obj, event): if event.type() == QEvent.KeyPress: key = event.key() if key == Qt.Key_F11: if self.isFullScreen(): self.setWindowFlags(self._flags) if self._state == 'm': self.showMaximized() else: self.showNormal() self.setGeometry(self._geometry) else: self._state = 'm' if self.isMaximized() else 'n' self._flags = self.windowFlags() self._geometry = self.geometry() self.setWindowFlags(Qt.Tool | Qt.FramelessWindowHint) self.showFullScreen() return True elif key == Qt.Key_Escape: self.close() return QWidget.eventFilter(self, obj, event) As can be seen, Esc is used for dialog hiding, and F11 is used for toggling full-screen. In addition, if the user changed the dialog mode from the initial maximized to normal and possibly moved the dialog, it's state and position are restored after exiting the full-screen. Finally, the dialog is created on the MainWindow action triggered: d = MyDialog(self) d.show() It works fine on Linux (Ubuntu Lucid), but quite strange on Windows 7: if I go to the full-screen from the maximized mode, I can't exit full-screen (on F11 dialog disappears and appears in full-screen mode again). If I change the dialog's mode to Normal (by double-clicking its title), then go to full-screen and then return back, the dialog is shown in the normal mode, in the correct position, but without the title line. Most probably the reason for both cases is the same - the setWindowFlags doesn't work. But why? Is it also possible that it is the bug in the recent PyQt version? On Ubuntu I have 4.6.x from apt, and on Windows - the latest installer from the riverbank site.

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  • Smart Client App: How to give Different Settings for Different Users

    - by Daniel
    Hi! I have a smart client application being deployed with a CickOnce webpage. here's the current scenario. User runs the application, and the application shows a login form. User enters ID/Password in the login form, and the application sends that information to the server. The server authenticates the user and sends configuration and data to the application. Different users have different configuration and data for their application. I was concerned that anyone can download the application from the webpage if they know the URL. So I'm trying to change the authentication scheme, so that users can login at the webpage to download the application. I want to send the authentication info from the webpage(Program running at the server) to the smart client app, so that application can download the configuration information from the server, without prompting users to make a login again. How can the webpage send the ID/Passoword to the application securely?

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  • Trigger JavaScript action after Datatable is loaded

    - by perissf
    In a JSF 2.1 + PrimeFaces 3.2 web application, I need to trigger a JavaScript function after a p:dataTable is loaded. I know that there is no such event in this component, so I have to find a workaround. In order to better understand the scenario, on page load the dataTable is not rendered. It is rendered after a successful login: <p:commandButton value="Login" update=":aComponentHoldingMyDataTable" action="#{loginBean.login}" oncomplete="handleLoginRequest(xhr, status, args)"/> As you can see from the above code, I have a JavaScript hook after the successful login, if it can be of any help. Immediately after the oncomplete action has finished, the update attribute renders the dataTable: <p:dataTable var="person" value="#{myBean.lazyModel}" rendered="#{p:userPrincipal() != null}" /> After the datatable is loaded, I need to run a JavaScript function on each row item, in order to subscribe to a cometD topic. In theory I could use the oncomplete attribute of the login Button for triggering a property from myBean in order to retrieve once again the values to be displayed in the dataTable, but it doesn't seem very elegant. The JavaScript function should do something with the rowKey of each row of the dataTable: function javaScriptFunctionToBeTriggered(rowKey) { // do something }

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  • Form Not Submitting

    - by John
    Hello, When I try to click on the "submit" button for the form below, nothing happens. Any ideas why not? Thanks in advance, John submit.php: <?php require_once "header.php"; $u = $_SESSION['username']; if (!isLoggedIn()) { // user is not logged in. if (isset($_POST['cmdlogin'])) { // retrieve the username and password sent from login form & check the login. if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox2(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { . show_userbox2(); } echo '<div class="submittitle">Submit an item.</div>'; echo '<form action="http://www...com/.../submit2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <div class="submissiontitle"><label for="title">Story Title:</label></div> <div class="submissionfield"><input name="title" type="title" id="title" maxlength="1000"></div> <div class="urltitle"><label for="url">Link:</label></div> <div class="urlfield"><input name="url" type="url" id="url" maxlength="500"></div> <div class="submissionbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; ?> submit2.php: <?php //if($_SERVER['REQUEST_METHOD'] == "POST"){header('Location: http://www...com/.../submit2.php');} require_once "header.php"; if (isLoggedIn() == true) { $remove_array = array('http://www.', 'http://', 'https://', 'https://www.', 'www.'); $cleanurl = str_replace($remove_array, "", $_POST['url']); $cleanurl = strtolower($cleanurl); $cleanurl = preg_replace('/\/$/','',$cleanurl); $title = $_POST['title']; //$url = $_POST['url']; $uid = $_POST['uid']; $title = mysql_real_escape_string($title); $cleanurl = mysql_real_escape_string($cleanurl); $site1 = 'http://' . $cleanurl; $displayurl = parse_url($site1, PHP_URL_HOST); function isURL($url1 = NULL) { if($url1==NULL) return false; $protocol = '(http://|https://)'; $allowed = '[-a-z0-9]{1,63}'; $regex = "^". $protocol . // must include the protocol '(' . $allowed . '\.)'. // 1 or several sub domains with a max of 63 chars '[a-z]' . '{2,6}'; // followed by a TLD if(eregi($regex, $url1)==true) return true; else return false; } if(isURL($site1)==true) mysql_query("INSERT INTO submission VALUES (NULL, '$uid', '$title', '$cleanurl', '$displayurl', NULL)"); else echo "<p class=\"topicu\">Not a valid URL.</p>\n"; } else { // user is not loggedin show_loginform(); } if (!isLoggedIn()) { // user is not logged in. if (isset($_POST['cmdlogin'])) { // retrieve the username and password sent from login form & check the login. if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { // User is not logged in and has not pressed the login button // so we show him the loginform show_loginform(); } } else { // The user is already loggedin, so we show the userbox. show_userbox(); } require_once "footer.php"; ?>

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  • Why i get everytime the error-message that i've already sent the headers

    - by mikep
    Hey, i've another question about web-programming. I programmed a login script, but everytime when i try to login it says that i've send the header informations already. Here are the 2 files: <?php if($_GET['logout'] == 1) { setcookie('authorized', 1, time()-3600); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Login - photoAdminSite</title> </head> <style type="text/css"> body { text-align: center; font-family: helvetica; } #loginForm { padding: 1em; background: #e3e3e3; width: 260px; margin: 3em auto 0; text-align: left; } </style> <body> <div id="loginForm"> <form method="post" action="confirm_login_credentials.php"> <h2>LOGIN</h2> <p>Username: <input type="text" name="username" /></p> <p>Password: <input type="password" name="password" /></p> <p><input type="submit" value="Login" name="submit" /></p> </form> </div> </body> </html> <?php $username = $_POST['username']; $password = $_POST['password']; require 'database.php'; $q = "SELECT id FROM users_photoadminsite WHERE user_name = '$username' AND password = '$password'"; $result = $mysqli->query($q) or die(mysqli_error()); if (mysqli_num_rows($result) == 1) { setcookie('authorized', 1, 0); header("Location: index.php"); } else { header("Location: login.php"); } ?> i would be really happy about some helpful answers.

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  • get rid of red X in IE for non-existing images

    - by hubertg
    I have a 3rd website (Confluence) which references images which are secured by a login. If the current user is logged in the image is shown if not the image url would redirect to a login form. Example When you enter this url in the browser a redirect to the login page is done. The problem now: IE shows a the dreaded red X icon for the image even though there should be just nothing (like in Firefox). Anyone knows how to get around this?

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  • Using C# to HttpPost data to a web page

    - by druffmuff
    I want to log in into a website using C# code. Here's the html code of the example form: <form action="http://www.site.com/login.php" method="post" name="login" id="login"> <table border="0" cellpadding="2" cellspacing="0"> <tbody> <tr><td><b>User:</b></td><td colspan=\"2\"><b>Password:</b></td></tr> <tr> <td><input class="inputbg" name="user" type="text"></td> <td><input class="inputbg" name="password" type="password"></td> <td><input type="submit" name="user_control" value="Submit" class="buttonbg"></td> </tr> </tbody></table> </form> This is what I have tried so far with unsuccessful results: HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://www.site.com/login.php"); request.Method = "POST"; using (StreamWriter writer = new StreamWriter(request.GetRequestStream(), Encoding.ASCII)) { writer.Write("user=user&password=pass&user_control=Eingabe"); } HttpWebResponse response = (HttpWebResponse)request.GetResponse(); using (StreamReader reader = new StreamReader(response.GetResponseStream())) { stream = new StreamWriter("login.html"); stream.Write(reader.ReadToEnd()); stream.Close(); } Any Ideas, why this is failing?

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  • Update Facebook Page's status using pyfacebook

    - by thornomad
    I am attempting to add functionality to my Django app: when a new post is approved, I want to update the corresponding Facebook Page's status with a message and a link to the post automatically. Basic status update. I have downloaded and installed pyfacebook - and I have read through the tutorial from Facebook. I have also seen this suggestion here on SO: import facebook fb = facebook.Facebook('YOUR_API_KEY', 'YOUR_SECRET_KEY') fb.auth.createToken() fb.login() # THIS IS AS FAR AS I CAN GET fb.auth.getSession() fb.set_status('Checking out StackOverFlow.com') When I get to the login() call, however, pyfacebook tries to open lynx so I can login to Facebook 'via the web' -- this is, obviously, not going to work for me because the system is supposed to be automated ... I've been looking, but can't find out how I can keep this all working with the script and not having to login via a web browser. Any ideas?

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • ASP.NET MVC - ValidationSummary set from a different controller

    - by Rap
    I have a HomeController with an Index action that shows the Index.aspx view. It has a username/password login section. When the user clicks the submit button, it POSTs to a Login action in the AccountController. <% Html.BeginForm("Login", "Account", FormMethod.Post); %> In that action, it tests for Username/Password validity and if invalid, sends the user back to the Login page with a message that the credentials were bad. [HttpPost] public ActionResult Login(LoginViewModel Model, string ReturnUrl) { User user = MembershipService.ValidateUser(Model.UserName, Model.Password); if (user != null) { //Detail removed here FormsService.SignIn(user.ToString(), Model.RememberMe); return Redirect(ReturnUrl); } else { ModelState.AddModelError("", "The user name or password provided is incorrect."); } // If we got this far, something failed, redisplay form return RedirectToAction("Index", "Home"); // <-- Here is the problem. ModelState is lost. } But here's the problem: the ValidationSummary is always blank because we're losing the Model when we RedirectToAction. How do I send the user to the action on a different controller without a Redirect?

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  • Zend redirect problem

    - by John
    I'm trying to redirect to http://localhost/site/public/admin/login from http://localhost/site/public but for some reason, it keeps redirecting to http://localhost/admin/login The code I am using is: $this->_response->setRedirect('/admin/login')->sendResponse(); This is really frustrating me, and any help would be grealy appreciated

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  • How to get the root path in JavaScript?

    - by Axel
    I am using mod_rewrite to remap the URLs in my website in the following format: http://www.mydomain.com/health/54856 http://www.mydomain.com/economy/strategy/911025/ http://www.mydomain.com/tags/obama/new The problem is that I am making AJAX calls to a file: http://www.mydomain.com/login.php And I don't want to write the FULL url or even use the ../ trick because there isn't a fixed level of folders. So, what i want is something to access the login.php from the root, whatever the domain name is: $.ajax({ type: "POST", url: "http://www.mydomain.com/login.php" });

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  • PHP question about global variables and form requests

    - by user220201
    Hi, This is probably a stupid question but will ask anyway sine I have no idea. I have written basic php code which serve forms. Say I have a login page and I serve it using the login.php page and it will be called in the login.html page like this - <form action="login.php" method="post"> By this it is also implied that every POST needs its own php file, doesn't it? This kind of feels weird. Is there a way to have a single file, say code.php, and just have each of the forms as functions instead? EDIT: Specifically, say I have 5 forms that are used one after the other in my application. Say after login the user does A, B, C and D tasks each of which are sent to the server as a POST request. So instead of having A.php, B.php, C.php and D.php I would like to have a single code.php and have A(), B(), C() and D() as functions. Is there a way to do this? Also on the same note, how do I deal with say a global array (e.g. an array of currently logged in users) across multiple forms? I want to do this without writing to a DB. I know its probably better to write to a DB and query but is it even possible to do it with a global array? The reason I was thinking about having all the form functions in one file is to use a global array. Thanks, - Pav

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  • PHP Array Key & value Question

    - by Nano HE
    Hi I writed a test code as below. <?php $url = 'http://localhost/events/result/cn_index.php?login'; print_r(parse_url($url)); echo parse_url($url, PHP_URL_PATH); ?> Output Array ( [scheme] => http [host] => localhost [path] => /events/result/cn_index.php [query] => login ) /events/result/cn_index.php Now I inserted the line below echo array[query]; // I want to echo 'login', but failed. How to the the value of 'login'?

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  • PrimeFaces commandButton doesn't navigate or update

    - by Sven
    I'am using Primefaces to make my app a little bit more beautiful. I noticed that p:commandButton and h:commandButton don't work the same way. The p:commandButton calls the method and nothing else hapens. The h:commandButton calls the method and returns a navigation. I have got trouble with redirecting after pressing the login button when using p:commandButton. How to deal with that? I do have an update parameter: <p:commandButton value="Login" action="#{login.login}" type="submit" update="msgs" />

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  • How to check flash and javascript installed/enable/disable on browser using JQuery

    - by MKS
    Hi Guys, I am using JQuery. I have got one link as given below: <li><a href="http://staging/english/Skywards/skywards.aspx" id="skywardsTopLoginLink">Login</a></li> Now I want to check on page load whether Flash/javascript is installed or disabled and according to output the Login link will work, I mean if flash/javascript is disabled or not installed then it will go to the above Href else it will open jQuery model dialog box for login functionality

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  • Dynamic GUI Framework Designing

    - by user575715
    There is a Scenario to be developed for a 3-tier Application .We need to design a Framework or a utility sort of thing . In tradional aspect of GUI Designing , either we tend to create a static gui page and code the elements on it along with other properties of the elements such as (disabled/enabled,image source,name ,id ,which function to be called under onclick event.) or we tend to drag and drop the elements from the control pallete provided by variety of gui frameworks. Certain things i need to design a POC so that we can develop this concept. 1) There must a utility ,such that during creation of screen layout , that screen should be saved in the database(RDBMS) with a screen number. 2) All the Events related to that control should be saved in some other table which will be dynamically mapped during the calling of screen number by the user. 3) When the user call that screen ,a generic function should be invoked which'll call the screen file from the database and apply all the properties ,events,etc at runtime and the final output will be displayed to the user. This POC will help the us to customised the screens according to our usage.also all the code will seperated which can easily be used for some other development process. Thanks Amit Kalra

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