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  • Javascript and rendering pauses and stays paused on scroll in the android browser

    - by user357303
    Hi. I've found some wierd behaviour related to scrolling and rendering and javascript. How to make it happen: On any webpage that is long enough to scroll on. Start to scroll pretty fast (fling the page). then release the touch. No while the page is still scrolling because of the momentum. Tap the screen to stop the scroll. This make the browser enter a wierd mode. On the nexus one it behaves like this: The updating of what's shown on the screen stops, you can still click on links and the go to where they are supposed to but what's shown on the screen stays the same. If you then scroll the screen a bit the update of the screen kicks in again and what you you where suppsed to see all the time is shown. On all phones with HTC Sense I've tried (Hero, Desire, Legend) this happens: The updating of the screen is stopped just like on the nexus one, but also the execution of any javascript is stopped. If you click on a link that takes you to another page however things return to normal again. The way I tested this was I created a page like this: http://pastebin.ca/1881620 The changeColor function simply changed the background color of 'container' to a few different colors. So before the error what happens is that when you click any link the color changes. after the error this happens: Nexus one: when you click on the links nothing happens (except the "orange link selected rounded corner box thing" is shown as if the link is clicked). Then when you scroll abit. You can see the color has changed (and equal amount of times to the number of times I clicked the link). On Sense: The links take me to google.com Has anyone else noticed this problem? Is there anyway to work around it? Thanks.

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  • Form Not Submitting

    - by John
    Hello, When I try to click on the "submit" button for the form below, nothing happens. Any ideas why not? Thanks in advance, John submit.php: <?php require_once "header.php"; $u = $_SESSION['username']; if (!isLoggedIn()) { // user is not logged in. if (isset($_POST['cmdlogin'])) { // retrieve the username and password sent from login form & check the login. if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox2(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { . show_userbox2(); } echo '<div class="submittitle">Submit an item.</div>'; echo '<form action="http://www...com/.../submit2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <div class="submissiontitle"><label for="title">Story Title:</label></div> <div class="submissionfield"><input name="title" type="title" id="title" maxlength="1000"></div> <div class="urltitle"><label for="url">Link:</label></div> <div class="urlfield"><input name="url" type="url" id="url" maxlength="500"></div> <div class="submissionbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; ?> submit2.php: <?php //if($_SERVER['REQUEST_METHOD'] == "POST"){header('Location: http://www...com/.../submit2.php');} require_once "header.php"; if (isLoggedIn() == true) { $remove_array = array('http://www.', 'http://', 'https://', 'https://www.', 'www.'); $cleanurl = str_replace($remove_array, "", $_POST['url']); $cleanurl = strtolower($cleanurl); $cleanurl = preg_replace('/\/$/','',$cleanurl); $title = $_POST['title']; //$url = $_POST['url']; $uid = $_POST['uid']; $title = mysql_real_escape_string($title); $cleanurl = mysql_real_escape_string($cleanurl); $site1 = 'http://' . $cleanurl; $displayurl = parse_url($site1, PHP_URL_HOST); function isURL($url1 = NULL) { if($url1==NULL) return false; $protocol = '(http://|https://)'; $allowed = '[-a-z0-9]{1,63}'; $regex = "^". $protocol . // must include the protocol '(' . $allowed . '\.)'. // 1 or several sub domains with a max of 63 chars '[a-z]' . '{2,6}'; // followed by a TLD if(eregi($regex, $url1)==true) return true; else return false; } if(isURL($site1)==true) mysql_query("INSERT INTO submission VALUES (NULL, '$uid', '$title', '$cleanurl', '$displayurl', NULL)"); else echo "<p class=\"topicu\">Not a valid URL.</p>\n"; } else { // user is not loggedin show_loginform(); } if (!isLoggedIn()) { // user is not logged in. if (isset($_POST['cmdlogin'])) { // retrieve the username and password sent from login form & check the login. if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { // User is not logged in and has not pressed the login button // so we show him the loginform show_loginform(); } } else { // The user is already loggedin, so we show the userbox. show_userbox(); } require_once "footer.php"; ?>

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  • Transitioning from Domain Authentication to SQL Server Authentication

    - by Albert Perrien
    Greetings all, I've run into a problem that has me stumped. I've put together a database in SQL Server Express, and I'm having a strange permissions problem. The database is on my development machine with a domain user: DOMAIN\albertp. My development database server is set for "SQL Server and Windows Authentication" mode. I can edit and query my database without any problems when I log in using Windows Authentication. However, when I log in to any user that uses SQL Server authentication (Including sa) I get this message when I run queries against my database. SELECT * FROM [Testing].[dbo].[AuditingReport] I get: Msg 18456, Level 14, State 1, Line 1 Login failed for user 'auditor'. I'm logged into the server from SQL Server Management Studio as 'auditor' and I don't see anything in the error log about the login failure. I've already run: Use Testing; Grant All to auditor; Go And I still get the same error. What permissions do I have to set for the database to be usable by others outside of my personal domain login? Or am I looking at the wrong problem? My ultimate goal is to have the database be accessible from a set of PHP pages, using a either a common login (hence 'auditor') or a login specific to a set of individual users.

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  • Qt/PyQt dialog with togglable fullscreen mode - problem on Windows

    - by Guard
    I have a dialog created in PyQt. It's purpose and functionality don't matter. The init is: class MyDialog(QWidget, ui_module.Ui_Dialog): def __init__(self, parent=None): super(MyDialog, self).__init__(parent) self.setupUi(self) self.installEventFilter(self) self.setWindowFlags(Qt.Dialog | Qt.WindowTitleHint) self.showMaximized() Then I have event filtering method: def eventFilter(self, obj, event): if event.type() == QEvent.KeyPress: key = event.key() if key == Qt.Key_F11: if self.isFullScreen(): self.setWindowFlags(self._flags) if self._state == 'm': self.showMaximized() else: self.showNormal() self.setGeometry(self._geometry) else: self._state = 'm' if self.isMaximized() else 'n' self._flags = self.windowFlags() self._geometry = self.geometry() self.setWindowFlags(Qt.Tool | Qt.FramelessWindowHint) self.showFullScreen() return True elif key == Qt.Key_Escape: self.close() return QWidget.eventFilter(self, obj, event) As can be seen, Esc is used for dialog hiding, and F11 is used for toggling full-screen. In addition, if the user changed the dialog mode from the initial maximized to normal and possibly moved the dialog, it's state and position are restored after exiting the full-screen. Finally, the dialog is created on the MainWindow action triggered: d = MyDialog(self) d.show() It works fine on Linux (Ubuntu Lucid), but quite strange on Windows 7: if I go to the full-screen from the maximized mode, I can't exit full-screen (on F11 dialog disappears and appears in full-screen mode again). If I change the dialog's mode to Normal (by double-clicking its title), then go to full-screen and then return back, the dialog is shown in the normal mode, in the correct position, but without the title line. Most probably the reason for both cases is the same - the setWindowFlags doesn't work. But why? Is it also possible that it is the bug in the recent PyQt version? On Ubuntu I have 4.6.x from apt, and on Windows - the latest installer from the riverbank site.

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  • get rid of red X in IE for non-existing images

    - by hubertg
    I have a 3rd website (Confluence) which references images which are secured by a login. If the current user is logged in the image is shown if not the image url would redirect to a login form. Example When you enter this url in the browser a redirect to the login page is done. The problem now: IE shows a the dreaded red X icon for the image even though there should be just nothing (like in Firefox). Anyone knows how to get around this?

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  • How to set the returnURL manually when using Ajax.ActionLink

    - by Roge
    I have this link @Ajax.ActionLink("create poll question", "CreatePoll", new { id = Model.DebateID }, new AjaxOptions { UpdateTargetId = "poll-entry-box", InsertionMode = InsertionMode.Replace, HttpMethod = "GET" }) which is pointing at a action with the [Authorize] Attribute. The login works, but the returnURL is empty so it just redirects to the index page. Is there some way to manually set the returnURL ? NOTE I am using the method described here http://haacked.com/archive/2011/10/04/prevent-forms-authentication-login-page-redirect-when-you-donrsquot-want.aspx because the login page was loading inside my partial.

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  • PHP Frontpage/Page controller

    - by atno
    I using the following as Frontpage/Page Controller(s) and it's working ok so far, except two problems I'm facing which as you can see are the $pages array and the switch, which are actually much much longer as the one I've pasted here. Everytime there is a need for a new page controller I have to add it to $pages array and to switch which makes that list very long. How would you overcome this problem and do you see any other improvement on this code? loadLogic() in page controllers it is used to get functions under pages/controllername/logic/function.php. Frontpage Controller - index.php: include 'common/common.php'; if(!isset($_GET['p']) OR $_GET['p'] == ''){ $_GET['p'] = 'home'; header('Location: index.php?p=home'); } $pages = array('home','register','login','logout','page1','page2','page3'); $_GET['p'] = trim($_GET['p']); if(isset($_GET['p'])){ if(in_array($_GET['p'], $pages)){ switch ($_GET['p']) { case 'home': include 'home.php'; break; case 'register': include 'register.php'; break; case 'login': include 'login.php'; break; case 'logout': include 'logout.php'; break; case 'page1': include 'page1.php'; break; case 'page2': include 'page2.php'; break; case 'page3': include 'page3.php'; break; } }else{ echo '404!'; } } Page Controller - {home,register,login,logout,page1,page2,page3}.php: include 'tpl/common/header.php'; contentStart(); if(isset($_SESSION['logged'])){ loadLogic('dashboard'); }else{ loadLogic('nologin'); } //Display login form in logic page instead links // if(!isset($_SESSION['logged'])){ contentEnd(); loadLogic('nologinForm'); }else{ contentEnd(); include'tpl/common/rcol.php'; } include 'tpl/common/footer.php'; function loadLogic(): function loadLogic($logic) { $path = dirname(__DIR__) . '/pages'; $controller = preg_split('/&/',$_SERVER['QUERY_STRING']); $controller = trim($controller[0],"p="); $logicPath = 'logic'; $logic = $logic . '.php'; $err = 0; $logicFullPath = $path.'/'.$controller.'/'.$logicPath.'/'.$logic; if($err == '0'){ include "$logicFullPath"; } } Folder Structure: projectName | ---> common | ---> pages | | | --->home | | | --->register | | | --->login | | | --->logout | | | --->page1 | | | --->page2 | | | --->page3 | ---> tpl | | | ---> common | --> home.php | --> register.php | --> login.php | --> logout.php | --> page1.php | --> page2.php | --> page3.php

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  • How to use Grails Spring Security Plugin to require logging in before access an action?

    - by Hoàng Long
    Hi all, I know that I can use annotation or Request mapping to restrict access to an ACTION by some specific ROLES. But now I have a different circumstance. My scenario is: every user of my site can create posts, and they can make their own post public, private, or only share to some other users. I implement sharing post by a database table PERMISSION, which specify if a user have the right to view a post or not. The problem arises here is that when a customer access a post through a direct link, how can I determine he/she have the privilege to view it? There's 3 circumstances: The post is public, so it can be viewed by anyone (include not-login user) The post is private, so only the login-owner can view it The post is sharing, it means only the login-user that is shared and the owner can view it. I want to process like this: If the requested post is public: ok. If the requested post is private/sharing: I want to redirect the customer to the login page; after logging in, the user will be re-direct to the page he wants to see. The problem here is that I can redirect the user to login controller/ auth action, but after that I don't know how to redirect it back. The link to every post is different by post_id, so I can't use SpringSecurityUtils.securityConfig.successHandler.defaultTargetUrl Could anyone know a way to do this?

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  • Zend redirect problem

    - by John
    I'm trying to redirect to http://localhost/site/public/admin/login from http://localhost/site/public but for some reason, it keeps redirecting to http://localhost/admin/login The code I am using is: $this->_response->setRedirect('/admin/login')->sendResponse(); This is really frustrating me, and any help would be grealy appreciated

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  • Using C# to HttpPost data to a web page

    - by druffmuff
    I want to log in into a website using C# code. Here's the html code of the example form: <form action="http://www.site.com/login.php" method="post" name="login" id="login"> <table border="0" cellpadding="2" cellspacing="0"> <tbody> <tr><td><b>User:</b></td><td colspan=\"2\"><b>Password:</b></td></tr> <tr> <td><input class="inputbg" name="user" type="text"></td> <td><input class="inputbg" name="password" type="password"></td> <td><input type="submit" name="user_control" value="Submit" class="buttonbg"></td> </tr> </tbody></table> </form> This is what I have tried so far with unsuccessful results: HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://www.site.com/login.php"); request.Method = "POST"; using (StreamWriter writer = new StreamWriter(request.GetRequestStream(), Encoding.ASCII)) { writer.Write("user=user&password=pass&user_control=Eingabe"); } HttpWebResponse response = (HttpWebResponse)request.GetResponse(); using (StreamReader reader = new StreamReader(response.GetResponseStream())) { stream = new StreamWriter("login.html"); stream.Write(reader.ReadToEnd()); stream.Close(); } Any Ideas, why this is failing?

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  • ASP.NET MVC - ValidationSummary set from a different controller

    - by Rap
    I have a HomeController with an Index action that shows the Index.aspx view. It has a username/password login section. When the user clicks the submit button, it POSTs to a Login action in the AccountController. <% Html.BeginForm("Login", "Account", FormMethod.Post); %> In that action, it tests for Username/Password validity and if invalid, sends the user back to the Login page with a message that the credentials were bad. [HttpPost] public ActionResult Login(LoginViewModel Model, string ReturnUrl) { User user = MembershipService.ValidateUser(Model.UserName, Model.Password); if (user != null) { //Detail removed here FormsService.SignIn(user.ToString(), Model.RememberMe); return Redirect(ReturnUrl); } else { ModelState.AddModelError("", "The user name or password provided is incorrect."); } // If we got this far, something failed, redisplay form return RedirectToAction("Index", "Home"); // <-- Here is the problem. ModelState is lost. } But here's the problem: the ValidationSummary is always blank because we're losing the Model when we RedirectToAction. How do I send the user to the action on a different controller without a Redirect?

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  • How do I load content with ujs, jquery and rails?

    - by Joseph Silvashy
    I'm trying to figure out the best way to insert content into a light box using rails UJS. I have a link that looks like this: <%= link_to "login", login_path, :remote => true %> Which produces html as such: <a data-remote="true" href="/login">login</a> So this all works great, and I've created the view file: user_sessions/new.js.erb which also loads just fine, but my question what is the preferred method of inserting appending the html into the page? Like I already have the login form on the non-js page, so can't I just load that partial into the page? Any ideas would be very welcomed.

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  • Why i get everytime the error-message that i've already sent the headers

    - by mikep
    Hey, i've another question about web-programming. I programmed a login script, but everytime when i try to login it says that i've send the header informations already. Here are the 2 files: <?php if($_GET['logout'] == 1) { setcookie('authorized', 1, time()-3600); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Login - photoAdminSite</title> </head> <style type="text/css"> body { text-align: center; font-family: helvetica; } #loginForm { padding: 1em; background: #e3e3e3; width: 260px; margin: 3em auto 0; text-align: left; } </style> <body> <div id="loginForm"> <form method="post" action="confirm_login_credentials.php"> <h2>LOGIN</h2> <p>Username: <input type="text" name="username" /></p> <p>Password: <input type="password" name="password" /></p> <p><input type="submit" value="Login" name="submit" /></p> </form> </div> </body> </html> <?php $username = $_POST['username']; $password = $_POST['password']; require 'database.php'; $q = "SELECT id FROM users_photoadminsite WHERE user_name = '$username' AND password = '$password'"; $result = $mysqli->query($q) or die(mysqli_error()); if (mysqli_num_rows($result) == 1) { setcookie('authorized', 1, 0); header("Location: index.php"); } else { header("Location: login.php"); } ?> i would be really happy about some helpful answers.

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  • Trigger JavaScript action after Datatable is loaded

    - by perissf
    In a JSF 2.1 + PrimeFaces 3.2 web application, I need to trigger a JavaScript function after a p:dataTable is loaded. I know that there is no such event in this component, so I have to find a workaround. In order to better understand the scenario, on page load the dataTable is not rendered. It is rendered after a successful login: <p:commandButton value="Login" update=":aComponentHoldingMyDataTable" action="#{loginBean.login}" oncomplete="handleLoginRequest(xhr, status, args)"/> As you can see from the above code, I have a JavaScript hook after the successful login, if it can be of any help. Immediately after the oncomplete action has finished, the update attribute renders the dataTable: <p:dataTable var="person" value="#{myBean.lazyModel}" rendered="#{p:userPrincipal() != null}" /> After the datatable is loaded, I need to run a JavaScript function on each row item, in order to subscribe to a cometD topic. In theory I could use the oncomplete attribute of the login Button for triggering a property from myBean in order to retrieve once again the values to be displayed in the dataTable, but it doesn't seem very elegant. The JavaScript function should do something with the rowKey of each row of the dataTable: function javaScriptFunctionToBeTriggered(rowKey) { // do something }

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  • PHP Array Key & value Question

    - by Nano HE
    Hi I writed a test code as below. <?php $url = 'http://localhost/events/result/cn_index.php?login'; print_r(parse_url($url)); echo parse_url($url, PHP_URL_PATH); ?> Output Array ( [scheme] => http [host] => localhost [path] => /events/result/cn_index.php [query] => login ) /events/result/cn_index.php Now I inserted the line below echo array[query]; // I want to echo 'login', but failed. How to the the value of 'login'?

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  • PHP question about global variables and form requests

    - by user220201
    Hi, This is probably a stupid question but will ask anyway sine I have no idea. I have written basic php code which serve forms. Say I have a login page and I serve it using the login.php page and it will be called in the login.html page like this - <form action="login.php" method="post"> By this it is also implied that every POST needs its own php file, doesn't it? This kind of feels weird. Is there a way to have a single file, say code.php, and just have each of the forms as functions instead? EDIT: Specifically, say I have 5 forms that are used one after the other in my application. Say after login the user does A, B, C and D tasks each of which are sent to the server as a POST request. So instead of having A.php, B.php, C.php and D.php I would like to have a single code.php and have A(), B(), C() and D() as functions. Is there a way to do this? Also on the same note, how do I deal with say a global array (e.g. an array of currently logged in users) across multiple forms? I want to do this without writing to a DB. I know its probably better to write to a DB and query but is it even possible to do it with a global array? The reason I was thinking about having all the form functions in one file is to use a global array. Thanks, - Pav

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • NSFetchedResultsController on secondary UITableView - how to query data?

    - by Jason
    I am creating a core-data based Navigation iPhone app with multiple screens. Let's say it is a flash-card application. The data model is very simple, with only two entities: Language, and CardSet. There is a one-to-many relationship between the Language entity and the CardSet entities, so each Language may contain multiple CardSets. In other words, Language has a one-to-many relationship Language.cardSets which points to the list of CardSets, and CardSet has a relationship CardSet.language which points to the Language. There are two screens: (1) An initial TableView screen, which displays the list of languages; and (2) a secondary TableView screen, which displays the list of CardSets in the Language. In the initial screen, which lists the languages, I am using NSFetchedResultsController to keep the list of languages up-to-date. The screen passes the Language selected to the secondary screen. On the secondary screen, I am trying to figure out whether I should again use an NSFetchedResultsController to maintain the list of CardSets, or if I should work through Language.cardSets to simply pull the list out of the object model. The latter makes the most sense programatically because I already have the Language - but then it would not automatically be updated on changes. I have looked at the NSFetchedResultsController documentation, and it seems like I can easily create predicates based on attributes - but not relationships. I.e., I can create the following NSFetchedResultsController: NSPredicate *predicate = [NSPredicate predicateWithFormat:@"name LIKE[c] 'Chuck Norris'"]; How can I access my data through the direct relationship - Language.cardSets - and also have the table auto-update using NSFetchedResultsController? Is this possible?

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  • How to get the root path in JavaScript?

    - by Axel
    I am using mod_rewrite to remap the URLs in my website in the following format: http://www.mydomain.com/health/54856 http://www.mydomain.com/economy/strategy/911025/ http://www.mydomain.com/tags/obama/new The problem is that I am making AJAX calls to a file: http://www.mydomain.com/login.php And I don't want to write the FULL url or even use the ../ trick because there isn't a fixed level of folders. So, what i want is something to access the login.php from the root, whatever the domain name is: $.ajax({ type: "POST", url: "http://www.mydomain.com/login.php" });

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  • Dynamic GUI Framework Designing

    - by user575715
    There is a Scenario to be developed for a 3-tier Application .We need to design a Framework or a utility sort of thing . In tradional aspect of GUI Designing , either we tend to create a static gui page and code the elements on it along with other properties of the elements such as (disabled/enabled,image source,name ,id ,which function to be called under onclick event.) or we tend to drag and drop the elements from the control pallete provided by variety of gui frameworks. Certain things i need to design a POC so that we can develop this concept. 1) There must a utility ,such that during creation of screen layout , that screen should be saved in the database(RDBMS) with a screen number. 2) All the Events related to that control should be saved in some other table which will be dynamically mapped during the calling of screen number by the user. 3) When the user call that screen ,a generic function should be invoked which'll call the screen file from the database and apply all the properties ,events,etc at runtime and the final output will be displayed to the user. This POC will help the us to customised the screens according to our usage.also all the code will seperated which can easily be used for some other development process. Thanks Amit Kalra

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  • Update Facebook Page's status using pyfacebook

    - by thornomad
    I am attempting to add functionality to my Django app: when a new post is approved, I want to update the corresponding Facebook Page's status with a message and a link to the post automatically. Basic status update. I have downloaded and installed pyfacebook - and I have read through the tutorial from Facebook. I have also seen this suggestion here on SO: import facebook fb = facebook.Facebook('YOUR_API_KEY', 'YOUR_SECRET_KEY') fb.auth.createToken() fb.login() # THIS IS AS FAR AS I CAN GET fb.auth.getSession() fb.set_status('Checking out StackOverFlow.com') When I get to the login() call, however, pyfacebook tries to open lynx so I can login to Facebook 'via the web' -- this is, obviously, not going to work for me because the system is supposed to be automated ... I've been looking, but can't find out how I can keep this all working with the script and not having to login via a web browser. Any ideas?

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  • jquery validation plugin doesn't seem to work ....

    - by Pandiya Chendur
    asp.net mvc's Html.BeginForm() seems to work with jquery validation plugin but the validation plugin doesn't seem to work with a form which i ve added to a page.... This works, <% using (Html.BeginForm("Login", "Registration", FormMethod.Post, new { id = "Loginform" })) {%> <fieldset> <legend>Login</legend> <p> <label for="EmailId">EmailId:</label> <%= Html.TextBox("EmailId", null, new { @class = "text_box_height_14_width_150" })%> </p> <div class="status"></div> <p> <label for="Password">Password:</label> <%= Html.Password("Password",null, new { @class = "text_box_height_14_width_150" }) %> </p> <div class="status"></div> <p> <input type="submit" value="Login" id="login" /> </p> </fieldset> <% } %> But this doesn't work, <form id="Loginform" method="post" action="Registration/Login"> <table cellpadding="0" cellspacing="0" width="100%" style="border:none;"> <tr> <td width="12%">Email Id&nbsp;:&nbsp;</td><td width="15%"> <input id="EmailId" type="text" class="text_box_height_14_width_150 name="EmailId" /></td><td width="20%" class="status"></td> <td width="12%">Password&nbsp;:&nbsp;<td width="15%"><input id="Password" type="password" class="text_box_height_14_width_150 name="Password" /></td> <td width="20%" class="status"></td> <td width="5%"><input type="submit" value="Login" id="BtnLogin" /></td> </tr> </table> </form> and my jquery function has this, $(document).ready(function() { var validator = $("#Loginform").validate({ rules: { EmailId: "required", Password: { required: true, minlength: 6 } }, messages: { EmailId: "Enter your EMail ID", Password: { required: "Please Provide a password", rangelength: jQuery.format("Enter at least {0} characters") } }, // the errorPlacement has to take the table layout into account errorPlacement: function(error, element) { error.appendTo(element.parent().next()); }, // set this class to error-labels to indicate valid fields success: function(label) { // set &nbsp; as text for IE label.html("&nbsp;").addClass("checked"); } }); }); Any suggestion... Am i missing something?

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