Search Results

Search found 12055 results on 483 pages for 'password complexity'.

Page 228/483 | < Previous Page | 224 225 226 227 228 229 230 231 232 233 234 235  | Next Page >

  • ASP Classic, SQL 2008, XML Output, and DSN vs DSN-Less Produces Chinese Letters

    - by RoLYroLLs
    I've been having a problem for the past month and can't seem to figure out what is wrong. Here's the setup and a little background. Background: I have a web-host who was running my website on Windows Server 2003 and SQL Server 2000. One of my webpages returned a result set from a stored procedure from the SQL server as xml. Below is the code: Stored Procedure: select top 10 1 as tag , null as parent , column1 as [item!1!column1!element] , column2 as [item!1!column2!element] from table1 for XML EXPLICIT ASP Page: index.asp Call OpenConn Set cmd = Server.CreateObject("ADODB.Command") With cmd .ActiveConnection = dbc .CommandText = "name of proc" .CommandType = adCmdStoredProc .Parameters.Append .CreateParameter("@RetVal", adInteger, adParamReturnValue, 4) .Parameters.Append .CreateParameter("@Level", adInteger, adParamInput, 4, Level) End With Set rsItems = Server.CreateObject("ADODB.Recordset") With rsItems .CursorLocation = adUseClient .CursorType = adOpenStatic .LockType = adLockBatchOptimistic Set .Source = cmd .Open Set .ActiveConnection = Nothing End With If NOT rsItems.BOF AND NOT rsItems.EOF Then OutputXMLQueryResults rsItems,"items" End If Set rsItems = Nothing Set cmd = Nothing Call CloseConn Sub OpenConn() strConn = "Provider=SQLOLEDB;Data Source=[hidden];User Id=[hidden];Password=[hidden];Initial Catalog=[hidden];" Set dbc = Server.CreateObject("ADODB.Connection") dbc.open strConn End Sub Sub CloseConn() If IsObject(dbc) Then If dbc.State = adStateOpen Then dbc.Close End If Set dbc = Nothing End If End Sub Sub OutputXMLQueryResults(RS,RootElementName) Response.Clear Response.ContentType = "text/xml" Response.Codepage = 65001 Response.Charset = "utf-8" Response.Write "" Response.Write "" While Not RS.EOF Response.Write RS(0).Value RS.MoveNext WEnd Response.Write "" Response.End End Sub Present: All was working great, until my host upgraded to Windows Server 2008 and SQL Server 2008. All of the sudden I was getting results like this: From Browser: From View Source: However, I found that if I use a DSN connection strConn = "DSN=[my DSN Name];User Id=[hidden];Password=[hidden];Initial Catalog=[hidden];" it works perfectly fine! My current host is not going to support DSN any longer, but that's out of scope for this issue. Someone told me to use an ADO.Stream object instead of a Recordset object, but I'm unsure how to implement that. Question: Has anyone run into this and found a way to fix it? What about that ADO.Stream object, can someone help me with a sample that would fit my code?

    Read the article

  • undefined method `user_sessions_path' for #<ActionView::Base:0xdb3158>

    - by mrbernz
    I'm getting this error that's driving me up the wall. I don't see what's going on... I've followed instructions to the T and it's still complaining - help please!! I've got extracts of the error message, controller file, login page and routes file. Error message NoMethodError in User_sessions#new Showing app/views/user_sessions/new.html.erb where line #4 raised: undefined method `user_sessions_path' for # Extracted source (around line #4): 1: 2: User Login 3: 4: <% form_for @user_session do |f| % 5: <%= f.error_messages % 6: 7: controller/user_sessions_controller.rb class UserSessionsController < ApplicationController before_filter :require_no_user, :only = [:new, :create] before_filter :require_user, :only = :destroy def new @user_session = UserSession.new end def create @user_session = UserSession.new(params[:user_session]) if @user_session.save flash[:notice] = "Login successful!" redirect_to root_url #redirect_back_or_default account_url else render :action = :new end end def destroy current_user_session.destroy flash[:notice] = "Logout successful!" redirect_to root_url #redirect_back_or_default account_url end end user_sessions/new.html.erb User Login <% form_for @user_session do |f| % <%= f.error_messages % <%= f.label :Email % <%= f.text_field :email % <%= f.label :Password % <%= f.password_field :password % <%= f.submit "Submit" % <% end % routes.rb file ActionController::Routing::Routes.draw do |map| map.login "login", :controller = "user_sessions", :action = "new" Am I look in in the wrong place??

    Read the article

  • Devise not allowing active resource to access the services

    - by Saurabh Pandit
    In my application there are two folders one for a rails application and another for a ruby application. In the ruby folder I have created a ruby file in which I have written code to access some model which is present in the rails application using active resource. Sample code is shown below : active_resource_example.rb require 'rubygems' require 'active_resource' class Website < ActiveResource::Base self.site = "http://localhost:3000/admin/" self.user = "user" self.password = "password" end websites = Website.find(:all) puts websites.inspect In my rails application I have used ActiveAdmin gem which uses devise for authentication. On rails Server I get the following result : Started GET "/admin/websites.json" for 192.168.1.37 at 2011-11-12 14:41:06 +0530 Processing by Admin::WebsitesController#index as JSON Completed in 43ms And on my terminal where I executed active_resource_example.rb, I got following error : user@user:~/Desktop$ ruby active_resource_example.rb /home/user/.rvm/gems/ruby-1.9.2-p180/gems/activeresource-3.1.1/lib/active_resource/connection.rb:132:in `handle_response': Failed. Response code = 401. Response message = Unauthorized . (ActiveResource::UnauthorizedAccess) from /home/user/.rvm/gems/ruby-1.9.2-p180/gems/activeresource-3.1.1/lib/active_resource/connection.rb:115:in `request' from /home/user/.rvm/gems/ruby-1.9.2-p180/gems/activeresource-3.1.1/lib/active_resource/connection.rb:80:in `block in get' from /home/user/.rvm/gems/ruby-1.9.2-p180/gems/activeresource-3.1.1/lib/active_resource/connection.rb:218:in `with_auth' from /home/user/.rvm/gems/ruby-1.9.2-p180/gems/activeresource-3.1.1/lib/active_resource/connection.rb:80:in `get' from /home/user/.rvm/gems/ruby-1.9.2-p180/gems/activeresource-3.1.1/lib/active_resource/base.rb:894:in `find_every' from /home/user/.rvm/gems/ruby-1.9.2-p180/gems/activeresource-3.1.1/lib/active_resource/base.rb:806:in `find' from active_resource_example.rb:12:in `<main>' user@user:~/Desktop$ I tried this with another application in which Devise authentication is not used with the same configuration I used in active_resource_example.rb, there I got the result. Desperately need some solution to this issue.

    Read the article

  • Uploading to TwitVid using x_verify_credentials_authorization

    - by deepa
    Hi, I am developing an iPhone application that uploads videos to TwitVid using the library TwitVid-iPhone-OAuth3. I have selected this library since Twitter is shifting to OAuth mechanism of authentication. 1) Does this new library allows to upload without user-name and password parameters? 2) I am using the following steps for uploading videos (assumed that new library allows to upload without user-name and password parameters). But, I am getting the error 'Incorrect Signature'. I am not able to identify the mistake that I am doing here. Could you please help me out to solve this problem. Authenticate the app using OAuth (MGTwitterEngine etc) which redirects the user to the web-page asking for log-in and app authentication. If the user authenticates the app, access token will obtained as final step. Upload the video to TwitVid using the following code snippet: OAuth *authorizer = [[OAuth alloc] initWithConsumerKey: @"my_consumer_key" andConsumerSecret: @"my_consumer_secret"]; authorizer.oauth_token = //The key-part of the access token obtained in step 2 authorizer.oauth_token_secret = //The secret-part of the access token obtained in step 2 authorizer.oauth_token_authorized = YES; //Since authenticated in steps 1 and 2 NSString *authHeader = [authorizer oAuthHeaderForMethod: @"POST" andUrl: @"https://api.twitter.com/1/account/verify_credentials.xml" andParams: nil]; twitVid = [[TwitVid alloc] init]; [mTwitVid setDelegate: self]; [mTwitVid authenticateWithXVerifyCredentialsAuthorization: authHeader xAuthServiceProvider: nil]; Thanks and Regards, Deepa

    Read the article

  • EJB3Unit testing no-tx-datasource

    - by justastefan
    Hello, I am doing tests on an ejb3-project using ejb3unit http://ejb3unit.sourceforge.net/Session-Bean.html for testing. All my Services long for @PersistenceContext (UnitName=bla). I set up the ejb3unit.properties like this: ejb3unit_jndi.1.isSessionBean=true ejb3unit_jndi.1.jndiName=ejb/MyServiceBean ejb3unit_jndi.1.className=com.company.project.MyServiceBean everything works with the in-memory-database. So now i want additionally test another servicebean with @PersistenceContext (UnitName=noTxDatasource) that goes for a defined in my datasources.xml: <datasources> <local-tx-datasource> ... </local-tx-datasource> <no-tx-datasource> <jndi-name>noTxDatasource</jndi-name> <connection-url>...</connection-url> <driver-class>oracle.jdbc.OracleDriver</driver-class> <user-name>bla</user-name> <password>bla</password> </no-tx-datasource> </datasources> How do I tell ejb3unit to make this work: Object object = InitialContext.doLookup("java:/noTxDatasource"); if (object instanceof DataSource) { return ((DataSource) object).getConnection(); } else { return null; } Currently it fails saying: javax.NamingException: Cannot find the name (noTxDataSource) in the JNDI tree Current bindings: (ejb/MyServiceBean=com.company.project.MyServiceBean) How can I add this no-tx-datasource to the jndi bindings?

    Read the article

  • screens goes up when soft keyboard came in front in And

    - by Sanat Pandey
    I have a question that, I want to take our Activity screen up when a softskeyboard came, in my app on Android Phone. I have used android:windowSoftInputMode="adjustResize|adjustPan" property in Android Manifest but nothing changed, problem remains same. Please suggest me for the right solution. Thanks in advance. XML: <?xml version="1.0" encoding="utf-8"?> <FrameLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="#ffffff"> <FrameLayout android:id="@+id/frame" android:layout_gravity="top|bottom|center_horizontal" android:layout_width="wrap_content" android:layout_marginTop="10dip" android:layout_height="wrap_content"> <ImageView android:layout_gravity="center_horizontal" android:id="@+id/imageView1" android:src="@drawable/logo" android:layout_width="wrap_content" android:layout_marginTop="10dip" android:layout_height="78dp"></ImageView> </FrameLayout> <FrameLayout android:id="@+id/frameLayout1" android:layout_width="wrap_content" android:background="@drawable/login_box_bg" android:layout_gravity="center_horizontal" android:layout_marginTop="180dip" android:layout_height="wrap_content"> <EditText android:inputType="textEmailAddress" android:id="@+id/ed_Login_Email" android:background="@drawable/login_input_bg" android:layout_gravity="center_horizontal" android:layout_marginTop="10dip" android:layout_width="290dip" android:layout_height="40dip" android:hint="Email:" android:paddingLeft="10dp"> </EditText> <EditText android:background="@drawable/login_input_bg" android:layout_width="290dip" android:layout_gravity="center_horizontal" android:id="@+id/ed_Login_Pwd" android:inputType="textPassword" android:layout_marginTop="70dip" android:layout_height="40dip" android:hint="Password:" android:paddingLeft="10dip"> </EditText> <Button android:background="@drawable/login_btn_bg" android:id="@+id/btn_Login_Login" android:textColor="#ffffff" android:text="LOG IN" android:layout_gravity="bottom|center_horizontal" android:layout_height="wrap_content" android:layout_width="wrap_content" android:layout_marginBottom="25dip"></Button> <TextView android:layout_width="wrap_content" android:layout_height="wrap_content" android:id="@+id/tv_Login_ForgotPwd" android:text="Forgot your password?" android:textColor="#000000" android:layout_gravity="bottom|center_horizontal" android:layout_marginBottom="10dip" android:clickable="true"></TextView> </FrameLayout> </FrameLayout>

    Read the article

  • PHP mysqli Insert not working, but not giving any errors.

    - by asdasdas
    As the title says Im trying to do a simple insert, but nothing actually is inserted into the table. I try to print out errors, but nothing is reported. My users table has many more fields than these 4, but they should all default. $query = 'INSERT INTO users (username, password, level, name) VALUES (?, ?, ?, ?)'; if($stmt = $db -> prepare($query)) { $stmt -> bind_param('ssis', $username, $password, $newlevel, $realname); $stmt -> execute(); $stmt -> close(); echo 'Any Errors: '.$db->error.PHP_EOL; } There are no errors given, but when I go to look at the table in phpmyadmin there is not a new row added. I know for sure that the types are correct (strings and integers). Is there something really wrong here or does it have something to do with the fact that I'm ignoring other columns. I have about 8 columns in the user table.

    Read the article

  • Duplicate entries on mysql on insert using doctrine

    - by Nikos Galis
    Hi all! I am facing a very weird problem with mysql and doctrine [with help of codeIgniter]. I am trying to make a simple migration script taking all records from one table and after a little process, saving them to another. However, on my laptop [running windows and wamp] I get double numbers of the original table records to have been copied to the destination table. In my colleagues' laptops, everything works fine! We are all using mysql 5.0.86 [plus windows plus wamp]. Here is the code : function buggy_function(){ $this->db(); //get db connection $q = Doctrine_Query::create()->from('Oldtable r'); $oldrecords = $q->fetchArray(); $count = 0; foreach ($oldrecords as $oldrecord){ $newrecord = new NewTableClass(); $newrecord->password = md5($oldrecord['password']); $newrecord->save(); echo $newrecord->id. ' Id -> saved.' } } Simple as that! I have 39 records on the Old table and I am getting 78 records in the new table, which are exactly the same records, except from the unique primary key. It seems as if the script runs twice. But the output of the script is the following : 1 Id -> saved. 2 Id -> saved. ... ... 39 Id -> saved. Do you have any idea why this is happening? Any known bug for mysql? Thank you in advanced!'

    Read the article

  • Get Mechanize to handle cookies from an arbitrary POST (to log into https://www.t-mobile.com/ progra

    - by Horace Loeb
    I want to log into https://www.t-mobile.com/ programmatically. My first idea was to use Mechanize to submit the login form: However, it turns out that this isn't even a real form. Instead, when you click "Log in" some javascript grabs the values of the fields, creates a new form dynamically, and submits it. "Log in" button HTML: <button onclick="handleLogin(); return false;" class="btnBlue" id="myTMobile-login"><span>Log in</span></button> The handleLogin() function: function handleLogin() { if (ValidateMsisdnPassword()) { // client-side form validation logic var a = document.createElement("FORM"); a.name = "form1"; a.method = "POST"; a.action = mytmoUrl; // defined elsewhere as https://my.t-mobile.com/Login/LoginController.aspx var c = document.createElement("INPUT"); c.type = "HIDDEN"; c.value = document.getElementById("myTMobile-phone").value; // the value of the phone number input field c.name = "txtMSISDN"; a.appendChild(c); var b = document.createElement("INPUT"); b.type = "HIDDEN"; b.value = document.getElementById("myTMobile-password").value; // the value of the password input field b.name = "txtPassword"; a.appendChild(b); document.body.appendChild(a); a.submit(); return true } else { return false } } I could simulate this form submission by POSTing the form data to https://my.t-mobile.com/Login/LoginController.aspx with Net::HTTP#post_form, but I don't know how to get the resultant cookie into Mechanize so I can continue to scrape the UI available when I'm logged in. Any ideas?

    Read the article

  • How to protect/monitor your site from crawling by malicious user

    - by deathy
    Situation: Site with content protected by username/password (not all controlled since they can be trial/test users) a normal search engine can't get at it because of username/password restrictions a malicious user can still login and pass the session cookie to a "wget -r" or something else. The question would be what is the best solution to monitor such activity and respond to it (considering the site policy is no-crawling/scraping allowed) I can think of some options: Set up some traffic monitoring solution to limit the number of requests for a given user/IP. Related to the first point: Automatically block some user-agents (Evil :)) Set up a hidden link that when accessed logs out the user and disables his account. (Presumably this would not be accessed by a normal user since he wouldn't see it to click it, but a bot will crawl all links.) For point 1. do you know of a good already-implemented solution? Any experiences with it? One problem would be that some false positives might show up for very active but human users. For point 3: do you think this is really evil? Or do you see any possible problems with it? Also accepting other suggestions.

    Read the article

  • Why does Email::MIME split up my attachment?

    - by sid_com
    Why does the attachment(ca. 110KiB) split up in 10 parts(ca. 11KiB) when I send it with this script using Email::MIME? #!/usr/bin/env perl use warnings; use strict; use Email::Sender::Transport::SMTP::TLS; my $mailer = Email::Sender::Transport::SMTP::TLS->new( host => 'smtp.my.host', port => 587, username => 'username', password => 'password', ); use Email::MIME::Creator; use IO::All; my @parts = ( Email::MIME->create( attributes => { content_type => 'text/plain', disposition => 'inline', encoding => 'quoted-printable', charset => 'UTF-8', }, body => "Hello there!\n\nHow are you?", ), Email::MIME->create( attributes => { filename => "test.jpg", content_type => "image/jpeg", disposition => 'attachment', encoding => "base64", name => "test.jpg", }, body => io( "test.jpg" )->all, ), ); my $email = Email::MIME->create( header => [ From => 'my@address', To => 'your@address', Subject => 'subject', ], parts => [ @parts ], ); eval { $mailer->send( $email, { from => 'my@address', to => [ 'your@address' ], } ); }; die "Error sending email: $@" if $@;

    Read the article

  • Symfony fk issue on insertion

    - by Daniel Hertz
    Hi, I posted a similar problem but it could not be resolved. I create a relational database of users and groups but for some reason I cannot insert test data with fixtures properly. Here is a sample of the schema: User: actAs: { Timestampable: ~ } columns: name: { type: string(255), notnull: true } email: { type: string(255), notnull: true, unique: true } nickname: { type: string(255), unique: true } password: { type: string(300), notnull: true } image: { type: string(255) } Group: actAs: { Timestampable: ~ } columns: name: { type: string(500), notnull: true } image: { type: string(255) } type: { type: string(255), notnull: true } created_by_id: { type: integer } relations: User: { onDelete: SET NULL, class: User, local: created_by_id, foreign: id, foreignAlias: groups_created } FanOf: actAs: { Timestampable: ~ } columns: user_id: { type: integer, primary: true } group_id: { type: integer, primary: true } relations: User: { onDelete: CASCADE, local: user_id, foreign: id, foreignAlias: fanhood } Group: { onDelete: CASCADE, local: group_id, foreign: id, foreignAlias: fanhood } And this is the data i try to input: User: user1: name: Danny email: [email protected] nickname: danny password: f05050400c5e586fa6629ef497be Group: group1: name: Mets type: sports FanOf: fans1: user_id: user1 group_id: group1 I keep getting this error: SQLSTATE[23000]: Integrity constraint violation: 1452 Cannot add or update a child row: a foreign key constraint fails (`krowdd`.`fan_of`, CONSTRAINT `fan_of_user_id_user_id` FOREIGN KEY (`user_id`) REFERENCES `user` (`id`) ON DELETE CASCADE) The users and groups are clearly being created before the "fanhood" is so why am I getting this error?? Thanks!

    Read the article

  • Erlang, SSH and authorized_keys

    - by Roberto Aloi
    Playing with the ssh and public_key application in Erlang, I've discovered a nice feature. I was trying to connect to my running Erlang SSH daemon by using a rsa key, but the authentication was failing and I was prompted for a password. After some debugging and tracing (and a couple of coffees), I've realized that, for some weird reason, a non valid key for my user was there. The authorized_keys file contained two keys. The wrong one was at some point in the file, while the correct one was appended at the end of the file. Now, the Erlang SSH application, when diffing the provided key with the ones contained in the authorized_keys, it was finding the first entry (completely ignoring the second on - the correct one). Then, it was switching to different authentication mechanism (at first it was trying dsa instead of rsa and then it was prompting for a password). The question is: Is this behavior intended or should the SSH server check for multiple entries for the same user in the *authorized_keys* file? Is this a generic SSH behaviour or it's just specific to the Erlang implementation?

    Read the article

  • Please help me with database connection types in Windows.

    - by Hamish Grubijan
    Sorry for a badly-phrased question. I have a requirement coming from a non-technical person that I need to make sense of. I am basically told: "Here use 'Driver={SQL Server};Server=SERVERNAME\INSTANCENAME;Database=DATABASENAME;Uid=UNAME;Pwd=PASSWORD;'; and here use Server=SERVERNAME\INSTANCENAME;Database=DATABASENAME;Uid=UNAME;Pwd=PASSWORD;';. I am getting no additional help here. While this seems to miraculously fix a bug, I want to understand what is it that I am changing, so I can leave a proper comment for the next developer, plus I can structure the code and name variables differently, depending on the meaning of the change. The work revolves around ASP.net, reporting, SQL Server 2008. Please give me some examples about when you would use one connection string over another. Feel free to edit the question if you can see a way to improve it. When can you lose a 'Driver={SQL Server};? Thank you. EDIT: SQL Server 2008 is the target database, but other can be used ... or maybe will be used in the future.

    Read the article

  • Blocking on DBCP connection pool (open and close connnection). Is database connection pooling in OpenEJB pluggable?

    - by topchef
    We use OpenEJB on Tomcat (used to run on JBoss, Weblogic, etc.). While running load tests we experience significant performance problems with handling JMS messages (queues). Problem was localized to blocking on database connection pool getting or releasing connection to the pool. Blocking prevented concurrent MDB instances (threads) from running hence performance suffered 10-fold and worse. The same code used to run on application servers (with their respective connection pool implementations) with no blocking at all. Example of thread blocked: Name: JMS Resource Adapter-worker-23 State: BLOCKED on org.apache.commons.pool.impl.GenericObjectPool@1ea6b4a owned by: JMS Resource Adapter-worker-19 Total blocked: 18,426 Total waited: 0 Stack trace: org.apache.commons.pool.impl.GenericObjectPool.returnObject(GenericObjectPool.java:916) org.apache.commons.dbcp.PoolableConnection.close(PoolableConnection.java:91) - locked org.apache.commons.dbcp.PoolableConnection@1bcba8 org.apache.commons.dbcp.managed.ManagedConnection.close(ManagedConnection.java:147) com.xxxxx.persistence.DbHelper.closeConnection(DbHelper.java:290) .... Couple of questions. I am almost certain that some transactional attributes and properties contribute to this blocking, but MDBs are defined as non-transactional (we use both annotations and ejb-jar.xml). Some EJBs do use container-managed transactions though (and we can observe blocking there as well). Are there any DBCP configurations that may fix blocking? Is DBCP connection pool implementation replaceable in OpenEJB? How easy (difficult) to replace it with another library? Just in case this is how we define data source in OpenEJB (openejb.xml): <Resource id="MyDataSource" type="DataSource"> JdbcDriver oracle.jdbc.driver.OracleDriver JdbcUrl ${oracle.jdbc} UserName ${oracle.user} Password ${oracle.password} JtaManaged true InitialSize 5 MaxActive 30 ValidationQuery SELECT 1 FROM DUAL TestOnBorrow true </Resource>

    Read the article

  • authentication error while importing from netbeans to subversion

    - by SpikETidE
    Hi Everyone.... I just began looking into source control.... And installed subversion from collabnet... I also use netbeans(6.8) to work with PHP... I have done the following steps I have installed subversion is c:\program files\collabnet\ and the root for the repositories in e:\svn_repository I then created a repository as e:\svn_repository\lemon I then edited the passwd file and added the user and password I then tried importing an existing project into the repository with the address - svn://localhost/lemon with the new user and password. After all this, i get the error "authentication failed"... I am pretty sure the authentication is correct... I tried importing the project with the address file:///E:/sv_repository/lemon with no authentication and it connected... But i got other guys who got to connect to this server through lan and svn:// protocol is the only option.... What am i doing wrong here..? Also.. where can i find a proper tutorial to connect netbeans and collabnet subversion.....? Thanks for your suggestions and time...

    Read the article

  • Spring security with GAE

    - by xybrek
    I'm trying to implement Spring security for my GAE application however I'm getting this error: No bean named 'springSecurityFilterChain' is defined I added this configuration on my application web.xml: <filter> <filter-name>springSecurityFilterChain</filter-name> <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class> </filter> <filter-mapping> <filter-name>springSecurityFilterChain</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> And in the servlet-context: <!-- Configure security --> <security:http auto-config="true"> <security:intercept-url pattern="/**" access="ROLE_USER" /> </security:http> <security:authentication-manager alias="authenticationManager"> <security:authentication-provider> <security:user-service> <security:user name="jimi" password="jimi" authorities="ROLE_USER, ROLE_ADMIN" /> <security:user name="bob" password="bob" authorities="ROLE_USER" /> </security:user-service> </security:authentication-provider> </security:authentication-manager> What could be causing the error?

    Read the article

  • Problem with ASP.NET Authentication

    - by Niels Bosma
    I'm having problem with our login procedure. Some customers complain that they can't login. I can see in our logs that their login is successful and that they are redirected from the login page to the member area. But there somehow the login isn't detected and they are bounced back to the login page. I've asked customers to check if cookies are supported (http://www.html-kit.com/tools/cookietester/) but problem remains even if this test returns true. This is how I've implemented the login procedure (simplyfied): protected void Login(string email, string password) { FormsAuthentication.SignOut(); Guid clientId = /* Validate login by checking email and password, if fails display error otherwise get client id */ FormsAuthentication.SetAuthCookie(clientId.ToString(), true); HttpContext.Current.Response.Redirect("~/Members.aspx"); } On the member page I check for authentication by in Page_Load function: public static void IsAuthenticated() { if (!HttpContext.Current.User.Identity.IsAuthenticated) { HttpContext.Current.Response.Redirect("~/Login.aspx", true); } } Maybe I'm using FormsAuthentication completely wrong? I've asked this before but still haven't been able to figure this out, I'd appreciate any help.

    Read the article

  • Perl - MySQL connection problem in windows

    - by dexter
    I have two folders php and perl they contain index.php and index.pl respectivly in index.pl my perl code looks like: #!/usr/bin/perl use Mysql; print "Content-type: text/html\n\n"; print "<h2>PERL-mySQL Connect</h2>"; print "page info"; $host = "localhost"; $database = "cdcol"; $user = "root"; $password = ""; $db = Mysql->connect($host, $database, $user, $password); $db->selectdb($database); when i run above code (ie type: http://localhost:88/perl/ in browser) following error comes Error message: Can't locate Mysql.pm in @INC (@INC contains: C:/xampp/perl/site/lib/ C:/xampp/perl/lib C:/xampp/perl/site/lib C:/xampp/apache) at C:/xampp/htdocs/perl/index.pl line 2. BEGIN failed--compilation aborted at C:/xampp/htdocs/perl/index.pl line 2. while this works: in browser http://localhost:88/php/ where index.php has: <?php $con = mysql_connect("localhost","root",""); if($con) { if(mysql_select_db("cdcol", $con)) { $sql="SELECT Id From products"; if(mysql_query($sql)) { $result = mysql_query($sql); if ($result)............

    Read the article

  • can load data(google app enngine) from http://localhost:8100/remote_api ..

    - by zjm1126
    i can download data from gae (http://zjm1126.appspot.com/remote_api), this is code: appcfg.py download_data --application=zjm1126 --url=http://zjm1126.appspot.com/remote_api --filename=a.csv and it successful : D:\zjm_demo\app>appcfg.py download_data --application=zjm1126 --url=http://zjm1 126.appspot.com/remote_api --filename=a.csv Downloading data records. [INFO ] Logging to bulkloader-log-20100618.162421 [INFO ] Throttling transfers: [INFO ] Bandwidth: 250000 bytes/second [INFO ] HTTP connections: 8/second [INFO ] Entities inserted/fetched/modified: 20/second [INFO ] Batch Size: 10 [INFO ] Opening database: bulkloader-progress-20100618.162421.sql3 [INFO ] Opening database: bulkloader-results-20100618.162421.sql3 [INFO ] Connecting to zjm1126.appspot.com/remote_api Please enter login credentials for zjm1126.appspot.com Email: [email protected] Password for [email protected]: [INFO ] Downloading kinds: [u'LogText', u'Greeting', u'Forum', u'Thread'] .... [INFO ] Have 0 entities, 0 previously transferred [INFO ] 0 entities (8804 bytes) transferred in 11.3 seconds so i want to know can load data from 127.0.0.1 , this is my code : appcfg.py download_data --application=zjm1126 --url=http://localhost:8100/remote_api --filename=a.csv and the error is : D:\zjm_demo\app>appcfg.py download_data --application=zjm1126 --url=http://loca lhost:8100/remote_api --filename=a.csv Downloading data records. [INFO ] Logging to bulkloader-log-20100618.162325 [INFO ] Throttling transfers: [INFO ] Bandwidth: 250000 bytes/second [INFO ] HTTP connections: 8/second [INFO ] Entities inserted/fetched/modified: 20/second [INFO ] Batch Size: 10 [INFO ] Opening database: bulkloader-progress-20100618.162325.sql3 [INFO ] Opening database: bulkloader-results-20100618.162325.sql3 Please enter login credentials for localhost Email: [email protected] Password for [email protected]: [INFO ] Connecting to localhost:8100/remote_api [ERROR ] Exception during authentication Traceback (most recent call last): File "d:\Program Files\Google\google_appengine\google\appengine\tools\bulkload er.py", line 3169, in Run self.request_manager.Authenticate() File "d:\Program Files\Google\google_appengine\google\appengine\tools\bulkload er.py", line 1178, in Authenticate remote_api_stub.MaybeInvokeAuthentication() File "d:\Program Files\Google\google_appengine\google\appengine\ext\remote_api \remote_api_stub.py", line 542, in MaybeInvokeAuthentication datastore_stub._server.Send(datastore_stub._path, payload=None) File "d:\Program Files\Google\google_appengine\google\appengine\tools\appengin e_rpc.py", line 346, in Send f = self.opener.open(req) File "D:\Python25\lib\urllib2.py", line 387, in open response = meth(req, response) File "D:\Python25\lib\urllib2.py", line 498, in http_response 'http', request, response, code, msg, hdrs) File "D:\Python25\lib\urllib2.py", line 425, in error return self._call_chain(*args) File "D:\Python25\lib\urllib2.py", line 360, in _call_chain result = func(*args) File "D:\Python25\lib\urllib2.py", line 506, in http_error_default raise HTTPError(req.get_full_url(), code, msg, hdrs, fp) HTTPError: HTTP Error 404: Not Found [INFO ] Authentication Failed so what should i do , thanks

    Read the article

  • Perl WordPress::XMLRPC categories not being set.

    - by Jay
    The following code works fine to upload a new post to a WordPress blog but for the life of me I can't seem to get the categories to be set. The categories exist. I've tried all lower case, tried case-matching, tried the slug version. Nothing works. No matter how I try passing the categories, the post gets assigned only to the default category. I've scoured the web to find other pieces of sample code and none mention the actual code semantics of how to assign post to certain categories using the WordPress::XMLRPC module. use WordPress::XMLRPC; my $o = WordPress::XMLRPC-new; $o-username('username'); $o-password('password'); $o-proxy('http://blogdomain.com/xmlrpc.php'); $o-server() || die "$!"; my $hashref = { 'title' = 'Test New Post 999 555456782', 'categories' = ['Categorie1', 'Categorie2'], 'description' = '<pHere is the content</p', 'mt_keywords' = 'tag1, tag2, tag3', 'mt_allow_comments' = 1, }; my $ID = $o-newPost($hashref, 1);

    Read the article

  • Forms/AD Authentication with Sharepoint

    - by David Lively
    All, I'm configuring Sharepoint to use forms authentication with LDAP/Active Directory. I'm new to Sharepoint, so if this is obvious, please point me in the right direction. Whenever I attempt to log in with a bad account or password, I get the very friendly (and correct) error message, The server could not sign you in. Make sure your user name and password are correct, and then try again. ... which implies that Sharepoint is able to communicate with AD. If I log in with a valid account, I get a page that says: (I added the grey bar to cover up the login name) Any suggestions? The account I'm logging in with is an administrator and has been granted full control in central administration. Also, interesting note: If I click the "sign in as a different user" link, and attempt to sign in using with the same credentials I just used, the site just redirects back to the login page, with no error or status message. If I then manually enter the site url, it again shows the "Error: Access Denied" page. Argh.

    Read the article

  • Rails 2.3.2 trying to render ERB instead of HAML

    - by c00lryguy
    Rails is suddenly trying to render ERB instead of Haml and I can't figure out why. I've created new rails projects, reinstalled Haml, and reinstalled Rails. Here's exactly the steps I take when making my application (Rails 2.3.2): rails> rails test rails> cd test rails\test> haml --rails . rails\test> ruby script\generate model user email:string password:string rails\test> ruby script\generate controller users index rails\test> rake db:migrate Here's what the UsersController looks like: class UsersController < ApplicationController def index @users = User.all end end My routes: ActionController::Routing::Routes.draw do |map| map.resources :users end I now create views\users\index.html.haml: %table %th(style="text-align: left;") %h1 Users - for user in @users %tr %td= user.email %td= user.password Annnd run the server... I navigate to localhost:3000\users and I get this error message: Template is missing Missing template users/index.erb in view path app/views For some reason Rails is trying to find and render .erb files instead of .haml files. vendor\plugins\haml\init.rb exists, untouched. I've reinstalled Haml (Pretty Penny) multiple times and still get the same results. I've also tried adding config.gem 'haml' to my environment.rb but this also doesn't work. I can't figure out why suddenly rails will not render haml for me.

    Read the article

  • NSThread terminating too early

    - by JustinXXVII
    I have an app that uploads to Google Spreadsheets via the GData ObjC client for Mac/iPhone. It works fine as is. I'm trying to get the upload portion on its own thread and I'm attempting to call the upload method on a new thread. Look: -(void)establishNewThreadToUpload { [NSThread detachNewThreadSelector:@selector(uploadToGoogle) toTarget:self withObject:nil]; } -(void)uploadToGoogle { NSAutoReleasePool *pool = [[NSAutoReleasePool alloc] init]; //works fine [helper setNewServiceWithName:username password:password]; //works fine [helper fetchUserSpreadsheetFeed]; //inside the helper class, fetchUserSpreadsheet feed calls ANOTHER method, which //calls ANOTHER METHOD and so on, until the object is either uploaded or fails //However, once the class gets to the end of fetchUserSpreadsheetFeed //control is passed back to this method, and [pool release]; //is called. The thread terminates and nothing ever happens. } If I forget about using a separate thread, everything works like it's supposed to. I'm new to thread programming, so if there's something I'm missing, please clue me in! Thanks!

    Read the article

  • SharePoint Visual web part and Oracle connection problem

    - by Rishi
    Hi, I'm trying to build a "visual web part" for SharePoint 2010 which should connect to Oracle table and display records on SharePoint page.For development, Oracle 11g client (with ODP.net) ,SharePoint server 2010, Visual Studio 2010 and Oracle 10g express all running on my machine. First,I've written sample code in ASP.NET web app to connect my local Oracle table and display data in grid view and it works fine. My code is , OracleConnection con; try { // Connect string constr = "Data Source=(DESCRIPTION=(ADDRESS_LIST=(ADDRESS=(PROTOCOL=TCP)(HOST=localhost)(PORT=1521)))(CONNECT_DATA=(SERVER=DEDICATED)(SERVICE_NAME=XE)));User Id=SYSTEM; Password=password"; con = new OracleConnection(constr); //Open database connection con.Open(); // Execute a SQL SELECT OracleCommand cmd = new OracleCommand("select * from T_ACTIONPOINTS WHERE AP_STATUS='Active' ", con); OracleDataReader dr = cmd.ExecuteReader(); GridView.DataSource = dr; GridView.DataBind(); GridView.AllowPaging = true; } catch (Exception e) { lblError.Text = e.Message; } Now, I'm trying to create new "SharePoint" visual web part project and using same code and deploying it on my local SP server. But when it runs , I get following error here is my solution explorer, It looks something wrong in compatibility.Can someone point me in right direction ?

    Read the article

< Previous Page | 224 225 226 227 228 229 230 231 232 233 234 235  | Next Page >