Project Euler 8: (Iron)Python
- by Ben Griswold
In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 8.
As always, any feedback is welcome.
# Euler 8
# http://projecteuler.net/index.php?section=problems&id=8
# Find the greatest product of five consecutive digits
# in the following 1000-digit number
import time
start = time.time()
number = '\
73167176531330624919225119674426574742355349194934\
96983520312774506326239578318016984801869478851843\
85861560789112949495459501737958331952853208805511\
12540698747158523863050715693290963295227443043557\
66896648950445244523161731856403098711121722383113\
62229893423380308135336276614282806444486645238749\
30358907296290491560440772390713810515859307960866\
70172427121883998797908792274921901699720888093776\
65727333001053367881220235421809751254540594752243\
52584907711670556013604839586446706324415722155397\
53697817977846174064955149290862569321978468622482\
83972241375657056057490261407972968652414535100474\
82166370484403199890008895243450658541227588666881\
16427171479924442928230863465674813919123162824586\
17866458359124566529476545682848912883142607690042\
24219022671055626321111109370544217506941658960408\
07198403850962455444362981230987879927244284909188\
84580156166097919133875499200524063689912560717606\
05886116467109405077541002256983155200055935729725\
71636269561882670428252483600823257530420752963450'
max = 0
for i in xrange(0, len(number) - 5):
nums = [int(x) for x in number[i:i+5]]
val = reduce(lambda agg, x: agg*x, nums)
if val > max: max = val
print max
print "Elapsed Time:", (time.time() - start) * 1000, "millisecs"
a=raw_input('Press return to continue')
