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  • calling WinForms contextmenustrip programmatically

    - by jello
    I programmatically create a Picture Box in c# windows program. I assign it with a value for the Tag property. I would like to print out that tag number programmatically, just for test purposes. so I try this: private void Form1_Load(object sender, EventArgs e) { pic.ContextMenuStrip = contextMenuStrip1; pic.ContextMenuStrip.Click += new EventHandler(this.MyPicHandler); } void MyPicHandler(object sender, EventArgs e) { PictureBox pic = sender as PictureBox; MessageBox.Show(pic.Tag.ToString()); } But when I right-click on the picture, and click on the menu item, it gives me an exception. "A NullReferenceException was unhandled" "Object reference not set to an instance of an object.". anyone's got an idea what's going on?

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  • Prime Numbers Code Help

    - by andrew
    Hello Everybody, I am suppose to "write a Java program that reads a positive integer n from standard input, then prints out the first n prime number." It's divided into 3 parts. 1st: This function will return true or false according to whether m is prime or composite. The array argument P will contain a sufficient number of primes to do the testing. Specifically, at the time isPrime() is called, array P must contain (at least) all primes p in the range 2 p m . For instance, to test m = 53 for primality, one must do successive trial divisions by 2, 3, 5, and 7. We go no further since 11 53 . Thus a precondition for the function call isPrime(53, P) is that P[0] = 2 , P[1] = 3 , P[2] = 5, and P[3] = 7 . The return value in this case would be true since all these divisions fail. Similarly to test m =143 , one must do trial divisions by 2, 3, 5, 7, and 11 (since 13 143 ). The precondition for the function call isPrime(143, P) is therefore P[0] = 2 , P[1] = 3 , P[2] = 5, P[3] = 7 , and P[4] =11. The return value in this case would be false since 11 divides 143. Function isPrime() should contain a loop that steps through array P, doing trial divisions. This loop should terminate when 2 either a trial division succeeds, in which case false is returned, or until the next prime in P is greater than m , in which case true is returned. Then there is the "main function" • Check that the user supplied exactly one command line argument which can be interpreted as a positive integer n. If the command line argument is not a single positive integer, your program will print a usage message as specified in the examples below, then exit. • Allocate array Primes[] of length n and initialize Primes[0] = 2 . • Enter a loop which will discover subsequent primes and store them as Primes[1] , Primes[2], Primes[3] , ……, Primes[n -1] . This loop should contain an inner loop which walks through successive integers and tests them for primality by calling function isPrime() with appropriate arguments. • Print the contents of array Primes[] to stdout, 10 to a line separated by single spaces. In other words Primes[0] through Primes[9] will go on line 1, Primes[10] though Primes[19] will go on line 2, and so on. Note that if n is not a multiple of 10, then the last line of output will contain fewer than 10 primes. The last function is called "usage" which I am not sure how to execute this! Your program will include a function called Usage() having signature static void Usage() that prints this message to stderr, then exits. Thus your program will contain three functions in all: main(), isPrime(), and Usage(). Each should be preceded by a comment block giving it’s name, a short description of it’s operation, and any necessary preconditions (such as those for isPrime().) And hear is my code, but I am having a bit of a problem and could you guys help me fix it? If I enter the number "5" it gives me the prime numbers which are "6,7,8,9" which doesn't make much sense. import java.util.; import java.io.; import java.lang.*; public class PrimeNumber { static boolean isPrime(int m, int[] P){ int squarert = Math.round( (float)Math.sqrt(m) ); int i = 2; boolean ans=false; while ((i<=squarert) & (ans==false)) { int c= P[i]; if (m%c==0) ans= true; else ans= false; i++; } /* if(ans ==true) ans=false; else ans=true; return ans; } ///****main public static void main(String[] args ) { Scanner in= new Scanner(System.in); int input= in.nextInt(); int i, j; int squarert; boolean ans = false; int userNum; int remander = 0; System.out.println("input: " + input); int[] prime = new int[input]; prime[0]= 2; for(i=1; i ans = isPrime(j,prime); j++;} prime[i] = j; } //prnt prime System.out.println("The first " + input + " prime number(s) are: "); for(int r=0; r }//end of main } Thanks for the help

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  • Error when trying to create a faceted plot in ggplot2

    - by John Horton
    I am trying to make a faceted plot in ggplot2 of the coefficients on the regressors from two linear models with the same predictors. The data frame I constructed is this: r.together> reg coef se y 1 (Intercept) 5.068608671 0.6990873 Labels 2 goodTRUE 0.310575129 0.5228815 Labels 3 indiaTRUE -1.196868662 0.5192330 Labels 4 moneyTRUE -0.586451273 0.6011257 Labels 5 maleTRUE -0.157618168 0.5332040 Labels 6 (Intercept) 4.225580743 0.6010509 Bonus 7 goodTRUE 1.272760149 0.4524954 Bonus 8 indiaTRUE -0.829588862 0.4492838 Bonus 9 moneyTRUE -0.003571476 0.5175601 Bonus 10 maleTRUE 0.977011737 0.4602726 Bonus The "y" column is a label for the model, reg are the regressors and coef and se are what you would think. I want to plot: g <- qplot(reg, coef, facets=.~y, data = r.together) + coord_flip() But when I try to display the plot, I get: > print(g) Error in names(df) <- output : 'names' attribute [2] must be the same length as the vector [1] What's strange is that qplot(reg, coef, colour=y, data = r.together) + coord_flip() plots as you would expect.

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  • Why does Perl's readdir() cache directory entries?

    - by Frank Straetz
    For some reason Perl keeps caching the directory entries I'm trying to read using readdir: opendir(SNIPPETS, $dir_snippets); # or die... while ( my $snippet = readdir(SNIPPETS) ) { print ">>>".$snippet."\n"; } closedir(SNIPPETS); Since my directory contains two files, test.pl and test.man, I'm expecting the following output: . .. test.pl test.man Unfortunately Perl returns a lot of files that have since vanished, for example because I tried to rename them. After I move test.pl to test.yeah Perl will return the following list: . .. test.pl test.yeah test.man What's the reason for this strange behaviour? The documentation for opendir, readdir and closedir doesn't mention some sort of caching mechanism. "ls -l" clearly lists only two files.

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  • async handler deleted by the wrong thread in django

    - by user3480706
    I'm run this algorithm in my django application.when i run several time from my GUI django local server will stopped and i got this error Exception RuntimeError: RuntimeError('main thread is not in main loop',) in ignored Tcl_AsyncDelete: async handler deleted by the wrong thread Aborted (core dumped) code print "Learning the sin function" network =MLP.MLP(2,10,1) samples = np.zeros(2000, dtype=[('x', float, 1), ('y', float, 1)]) samples['x'] = np.linspace(-5,5,2000) samples['y'] = np.sin(samples['x']) #samples['y'] = np.linspace(-4,4,2500) for i in range(100000): n = np.random.randint(samples.size) network.propagate_forward(samples['x'][n]) network.propagate_backward(samples['y'][n]) plt.figure(figsize=(10,5)) # Draw real function x = samples['x'] y = samples['y'] #x=np.linspace(-6.0,7.0,50) plt.plot(x,y,color='b',lw=1) samples1 = np.zeros(2000, dtype=[('x1', float, 1), ('y1', float, 1)]) samples1['x1'] = np.linspace(-4,4,2000) samples1['y1'] = np.sin(samples1['x1']) # Draw network approximated function for i in range(samples1.size): samples1['y1'][i] = network.propagate_forward(samples1['x1'][i]) plt.plot(samples1['x1'],samples1['y1'],color='r',lw=3) plt.axis([-2,2,-2,2]) plt.show() plt.close() return HttpResponseRedirect('/charts/charts') how can i fix this error ?need a quick help

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  • Redirect output to file

    - by Algorist
    Hi, I have a shell script which is currently running and was running from past 8 hours. It will complete only by tomorrow evening. At the end of the program, it will print 2 million words to standard output. I am running the program on the screen. I forgot to redirect the output to a file. I know I won't be able to copy the data from the window. Is there a way to output the command to a file. I don't want to restart the program. Any thoughts?? Thank you. Bala

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  • Report group headings not repeating on every page.

    - by ProfK
    I have an RDLC report with three tables and associated data sets. In my second table, I cannot get the two 'header' rows to repeat on each printed page. When viewed interactively, each table is on its own page and this isn't a problem. When I switch to print layout, e.g. my second table now spans two pages, and the second page gets no header rows. Am I missing a setting or something? ADDED: I do have the 'Repeat Header columns on each page' checked.

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  • Uninstall Mono from Mac OS X v10.5 Leopard

    - by Mac
    I installed Mono on my iMac last night and I immidiately had a change of heart! I don't think Mono is ready for prime time. The Mono website says to run the following script to uninstall: #!/bin/sh -x #This script removes Mono from an OS X System. It must be run as root rm -r /Library/Frameworks/Mono.framework rm -r /Library/Receipts/MonoFramework-SVN.pkg cd /usr/bin for i in `ls -al | grep Mono | awk '{print $9}'`; do rm ${i} done Has anyone had to uninstall Mono? Was it as straight forward as running the above script or do I have to do more? How messy was it? Any pointers are appreciated. Thanks

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  • web development with ruby without rails?

    - by kmorris511
    For reasons beyond my control, I'm being tasked with Ruby web development that does NOT use Rails or really any other heavyweight framework such as Merb. I'm wondering if anybody else has encountered this and can recommend best practices or resources that describe best practices for such a problem. I'd like to avoid the dreaded out.print('<td class="foo">'+some_data+'</td>') style of web development. A coworker has suggested Rack as a light framework but the documentation is sketchy and it seems unproven in the market.

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  • How to insert a word into a string in Perl

    - by Nano HE
    #!C:\Perl\bin\perl.exe use strict; use warnings; use Data::Dumper; my $fh = \*DATA; while(my $line = <$fh>) { $line =~ s/ ^/male /x ; print $line ; } __DATA__ 1 0104 Mike Lee 2:01:48 output male 1 0104 Mike Lee 2:01:48 Then I tried to insert male after the racenumber(0104), I replaced the code with style. $line =~ s/ ^\d+\s+\d+\s+ /male /x ; # but failed Acturally I want the output. thank you. 1 0104 male Mike Lee 2:01:48

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  • Python urllib.urlopen IOError

    - by Michael
    So I have the following lines of code in a function sock = urllib.urlopen(url) html = sock.read() sock.close() and they work fine when I call the function by hand. However, when I call the function in a loop (using the same urls as earlier) I get the following error: > Traceback (most recent call last): File "./headlines.py", line 256, in <module> main(argv[1:]) File "./headlines.py", line 37, in main write_articles(headline, output_folder + "articles_" + term +"/") File "./headlines.py", line 232, in write_articles print get_blogs(headline, 5) File "/Users/michaelnussbaum08/Documents/College/Sophmore_Year/Quarter_2/Innovation/Headlines/_code/get_content.py", line 41, in get_blogs sock = urllib.urlopen(url) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib.py", line 87, in urlopen return opener.open(url) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib.py", line 203, in open return getattr(self, name)(url) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib.py", line 314, in open_http if not host: raise IOError, ('http error', 'no host given') IOError: [Errno http error] no host given Any ideas?

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  • Spring MVC - Cannot map request parameters as a Map parameter in method?

    - by Ken Chen
    What I want to do is passing a map to the method in Controller using @RequestParam, but it seems not working. While this is working in Struts 2. Below is what I am trying: In JSP using JQuery: var order = {}; order['seq'] = "ASC"; var criteria = {}; criteria['label'] = "Directory"; $.post(context + 'menu/list', {"orders" : order, "criterias" : criteria} The parameters I am trying to post is an 'map' object order and criteria for listing menu. In Java: @RequestMapping("/{collection}/list") public @ResponseBody Map<String, ? extends Object> list(@PathVariable String collection, @RequestParam("criterias") Map<String, String> criteria, @RequestParam("orders") Map<String, String> order) { However, when I print out the map criteria & order in Java, it takes all value as below: Criteria: {criterias[label]=Directory, orders[seq]=ASC} Order: {criterias[label]=Directory, orders[seq]=ASC} Can @RequestParam in Spring be used to init a Map parameter?

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  • Splitting strings using a delimiter in python.

    - by Jahkr
    OK so I have a string that has this: Dan|warrior|54 I'm trying to make so I can use python and split it using | as the delimiter. Here's what I have so far: #!/usr/bin/env python dan = 'dan|warrior|54' print dan.split('|') and that results into this: ['dan', 'warrior', '54'] I know it's incomplete but what do I have to do to finish it? Yes, I tried googling this problem... but it's not happening. :( I want so that I can choose specifically which one from the delimiter so if I was dan.split('|')[1] .. it would pick warrior. See my point?

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  • Properly using subprocess.PIPE in python?

    - by Gordon Fontenot
    I'm trying to use subprocess.Popen to construct a sequence to grab the duration of a video file. I've been searching for 3 days, and can't find any reason online as to why this code isn't working, but it keeps giving me a blank result: import sys import os import subprocess def main(): the_file = "/Volumes/Footage/Acura/MDX/2001/Crash Test/01 Acura MDX Front Crash.mov" ffmpeg = subprocess.Popen(['/opt/local/bin/ffmpeg', '-i', the_file], stdout = subprocess.PIPE, ) grep = subprocess.Popen(['grep', 'Duration'], stdin = subprocess.PIPE, stdout = subprocess.PIPE, ) cut = subprocess.Popen(['cut', '-d', ' ', '-f', '4'], stdin = subprocess.PIPE, stdout = subprocess.PIPE, ) sed = subprocess.Popen(['sed', 's/,//'], stdin = subprocess.PIPE, stdout = subprocess.PIPE, ) duration = sed.communicate() print duration if __name__ == '__main__': main()

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  • Get signal names from numbers in Python

    - by Brian M. Hunt
    Is there a way to map a signal number (e.g. signal.SIGINT) to its respective name (i.e. "SIGINT")? I'd like to be able to print the name of a signal in the log when I receive it, however I cannot find a map from signal numbers to names in Python, i.e. import signal def signal_handler(signum, frame): logging.debug("Received signal (%s)" % sig_names[signum]) signal.signal(signal.SIGINT, signal_handler) For some dictionary sig_names, so when the process receives SIGINT it prints: Received signal (SIGINT) Thank you.

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  • PycURL RESUME_FROM

    - by excid3
    I can't seem to get the RESUME_FROM option to work. Here's some example code that I have been testing with: import os import pycurl import sys def progress(total, existing, upload_t, upload_d): try: frac = float(existing)/float(total) except: frac = 0 sys.stdout.write("\r%s %3i%%" % ("file", frac*100) ) url = "http://launchpad.net/keryx/stable/0.92/+download/keryx_0.92.4.tar.gz" filename = url.split("/")[-1].strip() def test(debug_type, debug_msg): print "debug(%d): %s" % (debug_type, debug_msg) c = pycurl.Curl() c.setopt(pycurl.URL, url) c.setopt(pycurl.FOLLOWLOCATION, 1) c.setopt(pycurl.MAXREDIRS, 5) # Setup writing if os.path.exists(filename): f = open(filename, "ab") c.setopt(pycurl.RESUME_FROM, os.path.getsize(filename)) else: f = open(filename, "wb") c.setopt(pycurl.WRITEDATA, f) #c.setopt(pycurl.VERBOSE, 1) c.setopt(pycurl.DEBUGFUNCTION, test) c.setopt(pycurl.NOPROGRESS, 0) c.setopt(pycurl.PROGRESSFUNCTION, progress) c.perform()

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  • Why can't I download a whole image file with urllib2.urlopen()

    - by John Gann
    When I run the following code, it only seems to be downloading the first little bit of the file and then exiting. Occassionally, I will get a 10054 error, but usually it just exits without getting the whole file. My internet connection is crappy wireless, and I often get broken downloads on larger files in firefox, but my browser has no problem getting a 200k image file. I'm new to python, and programming in general, so I'm wondering what nuance I'm missing. import urllib2 xkcdpic=urllib2.urlopen("http://imgs.xkcd.com/comics/literally.png") xkcdpicfile=open("C:\\Documents and Settings\\John Gann\\Desktop\\xkcd.png","w") while 1: chunk=xkcdpic.read(4028) if chunk: print chunk xkcdpicfile.write(chunk) else: break

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  • Relating NP-Complete problems to real world problems

    - by terru
    I have a decent grasp of NP Complete problems; that's not the issue. What I don't have is a good sense of where they turn up in "real" programming. Some (like knapsack and traveling salesman) are obvious, but others don't seem obviously connected to "real" problems. I've had the experience several times of struggling with a difficult problem only to realize it is a well known NP Complete problem that has been researched extensively. If I had recognized the connection more quickly I could have saved quite a bit of time researching existing solutions to my specific problem. Are there any resources (online or print) that specifically connect NP Complete to real world instances?

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  • how to parse jquery ajax xhtml response?

    - by steve
    Sorry if this has been posted many times. But I've tried many variations and it still doesn't work. The HTML comes back from the jquery AJAX call fine and I am trying to remove the header and footers from the response using: // none of these work for me $("#content", data); $("#content", $(data)); $(data).find("#content").html() I've breakpoint the response to verify the #content exists by inspected $(data) and using alert to print out the data's text. I've also try using "body" or "a" as selectors, but it always come back as undefined. I've read in this post that you can't pull in the full XHTML document: http://stackoverflow.com/questions/1050333/jquery-ajax-parse-response-text. But I can't find the answer's quote anymore, maybe it's outdated? Has anyone ran into this problem? Many thanks, Steve

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  • What is a Perl regex for finding the first non-consecutively-repeating character in a string.

    - by DVK
    Your task, should you choose to accept it, is to write a Perl regular expression that for a given string, will return the first occurence of a character that is not consecutively duplicated. In other words, both preceded AND succeeded by characters different from itself (or start/end of string respectively). Example: IN: aabbcdecc OUT: c Please note that "not consecutively duplicated" does not mean "anywhere in the string". NOTE: it must be a pure regex expression. E.g. the solution that obviously comes to mind (clone the string, delete all the duplicates, and print the first remaining character) does not count, although it solves the problem. The question is inspired by my somewhat off-topic answer to this: http://stackoverflow.com/questions/2548606/perl-function-to-find-first-non-repeating-character-in-a-string

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  • better way to pass by reference in Perl?

    - by JoelFan
    I am doing pass-by-reference like this: sub repl { local *line = \$_[0]; our $line; $line = "new value"; } sub doRepl { my $foo = "old value"; my ($replFunc) = @_; $replFunc->($foo); print $foo; # prints "new value"; } doRepl(\&repl); Is there a cleaner way of doing it? Prototypes don't work because I'm using a function reference (trust be that there's a good reason for using a function reference). I also don't want to use $_[0] everywhere in repl because it's ugly.

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  • How to use jQuery .each() - I get a value, but it's the wrong one

    - by Ankur
    I am returning a JSON object (as a String) through a servlet. The JSON object looks like this: {"3":"Martin Luther","30":"Boris Becker","32":"Joseph Goebels","19":"Leonardo Da Vinci","31":"Adolf Hitler"} My jQuery looks like this (the submission of data is correct because I get a proper looking result from the servlet): $.ajax( { type : "GET", url : "MyServlet", data : queryString + "count=" + variables, success : function(resultObj) { $.each(resultObj, function(key, value) { $("#resultCount").html(key+", "+value); }); } }); However when I try to print the results, that is the variables key and value, I get a number for the key but not a number from the JSONObject and an empty string instead of the value. Essentially the question is about how to "extract" the information from a JSON object.

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  • sprintf an LPCWSTR variable

    - by Julio
    Hello everyone. I'm trying to debug print an LPCWSTR string, but I get a problem during the sprintf push in the buffer, because it retrieve only the first character from the string. Here is the code: HANDLE WINAPI hookedCreateFileW(LPCWSTR lpFileName, DWORD dwDesiredAccess, DWORD dwShareMode, LPSECURITY_ATTRIBUTES lpSecurityAttributes, DWORD dwCreationDisposition, DWORD dwFlagsAndAttributes, HANDLE hTemplateFile) { char buffer[1024]; sprintf_s(buffer, 1024, "CreateFileW: %s", lpFileName); OutputDebugString(buffer); return trueCreateFileW(lpFileName, dwDesiredAccess, dwShareMode, lpSecurityAttributes, dwFlagsAndAttributes, dwCreationDisposition, hTemplateFile); } For example I get "CreateFileW: C" or "CreateFileW: \". How do I properly push it in the buffer? Thank you.

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  • reference to specific hash key

    - by dave
    How do I create a reference to the value in a specific hash key. I tried the following but $$foo is empty. Any help is much appreciated. $hash->{1} = "one"; $hash->{2} = "two"; $hash->{3} = "three"; $foo = \${$hash->{1}}; $hash->{1} = "ONE"; #I want "MONEY: ONE"; print "MONEY: $$foo\n";

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  • group expression in jasper reports

    - by ed1t
    I've a report which has a has 5 columns on each page and I have a group defined which shows columns related to A | B | C | D | E - main column X | Y | Z - group - A is the key I have my query ORDER BY A, but when it is displayed it doesn't print the results in next page if A is changed. Following is how I have a group defined. <group name="A" isResetPageNumber="true" > <groupExpression><![CDATA[$F{A}]]></groupExpression> <groupHeader> <band/> </groupHeader> <groupFooter> <band/> </groupFooter> </group> does A need to be part of the group?

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