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  • WordPress > Activating plugin makes site go blank in one theme, not in another. Generated source ide

    - by Scott B
    Strangest thing. When I activate this specific plugin, the public side of the site goes blank (nothing but a white screen with blank view source). However, when I test the site with the wordpress default theme, the plugin does not conflict and the site works fine. The interesting thing is that I've compared the generated source (using FF's webmaster tools) with and without plugin activated and in each case they are identical. This led me to believe that perhaps the plugin was altering htaccess, however, that file is the same whether or not the plugin is active or not. How can I find out what is causing the problem with this plugin? The plugin is called "Crawl Rate Tracker".

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  • How can I overlay images over one another in Java?

    - by Sam
    So I have been posting all over and have yet to get a solid answer: I have created an image resizing class, with a crop method. The cropping works great. The issue that I am having is the background color that I specify in the drawImage function of Graphics is not working correctly. It defaults to black as the background regardless of what I supply (in this case Color.WHITE). Also, the overlaying image or top most image (comes from a file) is being inverted (I think it is) or otherwise discolored. Just so you can conceptualize this a little bit better, I am taking a jpeg and overlaying it on top of a new BufferedImage, the new buffered image's background is not being set. Here is the code below that I am working with: public void Crop(int Height, int Width, int SourceX, int SourceY) throws Exception { //output height and width int OutputWidth = this.OutputImage.getWidth(); int OutputHeight = this.OutputImage.getHeight(); //create output streams ByteArrayOutputStream MyByteArrayOutputStream = new ByteArrayOutputStream(); MemoryCacheImageOutputStream MyMemoryCacheImageOutputStream = new MemoryCacheImageOutputStream(MyByteArrayOutputStream); //Create a new BufferedImage BufferedImage NewImage = new BufferedImage(Width, Height, BufferedImage.TYPE_INT_RGB); Graphics MyGraphics = NewImage.createGraphics(); MyGraphics.drawImage(this.OutputImage, -SourceX, -SourceY, OutputWidth, OutputHeight, Color.WHITE, null); // Get Writer and set compression Iterator MyIterator = ImageIO.getImageWritersByFormatName("png"); if (MyIterator.hasNext()) { //get image writer ImageWriter MyImageWriter = (ImageWriter)MyIterator.next(); //get params ImageWriteParam MyImageWriteParam = MyImageWriter.getDefaultWriteParam(); //set outputstream MyImageWriter.setOutput(MyMemoryCacheImageOutputStream); //create new ioimage IIOImage MyIIOImage = new IIOImage(NewImage, null, null); //write new image MyImageWriter.write(null, MyIIOImage, MyImageWriteParam); } //convert output stream back to inputstream ByteArrayInputStream MyByteArrayInputStream = new ByteArrayInputStream(MyByteArrayOutputStream.toByteArray()); MemoryCacheImageInputStream MyMemoryCacheImageInputStream = new MemoryCacheImageInputStream(MyByteArrayInputStream); //resassign as a buffered image this.OutputImage = ImageIO.read(MyMemoryCacheImageInputStream); }

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  • Rails: Easy way to add more than one flash[:notice] at a time.

    - by Josh Pinter
    I thought every time you do a flash[:notice]="Message" it would add it to the array which would then get displayed during the view but the following just keeps the last flash: flash[:notice] = "Message 1" flash[:notice] = "Message 2" Now I realize it's just a simple hash with a key (I think :)) but is there a better way to do multiple flashes than the following: flash[:notice] = "Message 1<br />" flash[:notice] = "Message 2" Thanks. Josh

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  • How do I select an item out of a JavaScript array when I only know a value for one of the item's pro

    - by minus4
    I have the following JavaScript object: { "DPI": "66.8213457076566", "width": "563.341067", "editable": "True", "pricecat": "6", "numpages": "2", "height": "400", "page": [{ "filename": "999_9_1.jpg", "line": [{ "test": "test 1", lineid: 22 }, { "test": "test 2", lineid: 22 }, { "test": "test 3", lineid: 22 }, { "test": "test 4", lineid: 22 }, { "test": "blank", lineid: 22 }] }, { "filename": "999_9_2.jpg", "line": [] }] } I can do most things with lines like measurements.page[0].line[0].lineid; But what I am really stuck with is when I want to edit a specific line but I only have the lineid value available (for example 22) and not the line number in the array: measurements.page[0].line[WHAT DO I PUT HERE].test = "new changed value";

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  • Interview question: Check if one string is a rotation of other string.

    - by Webdev
    A friend of mine was asked the following question today at interview for the position of software developer. Given two string s1 and s2 how will you check if s1 is a rotated version of s2 ? Example: if s1 = "stackoverflow"; then the following are some of its rotated versions: "tackoverflows" "ackoverflowst" "overflowstack" where as "stackoverflwo" is not a rotated version. The answer he gave was: Take s2 and find the logest prefix that is a substring of s1, that will give you the point of rotation. Once you find that point, break s2 at that point to get s2a and s2b, then just check if concatenate(s2a,s2b) == s1 It looks like a good solution to me and my friend. But the interviewr though otherwise. He asked for a simpler solution. Please help me by telling how would you do this in Java/C/C++ ? Thanks in advance.

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  • operator "new" returning a non-local heap pointer for only one class ?

    - by KaluSingh Gabbar
    Language : C++ Platform : Windows Server 2003 I have an exe calling a DLL, in which when I allocate (new) the memory for class A (which is in DLL) it returns me a non-local heap pointer. I try to new other classes which are in DLL and "new" returns a valid heap pointer for them, its only Class A which is not being allocated properly. I am on windows and validating the heap by this function call : _CrtIsValidHeapPointer ( (const void *) pPtr ) I am seriously confused why this only happens with new-ing Class A and no other class ? (All Native Code)

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  • One click login to my google apps solution how can I do it?

    - by Ali
    Hi guys I'm developing a google apps solution and I'm building on the tutorial application give by google at http://code.google.com/googleapps/marketplace/tutorial_php.html - the thing is that the example given sets up the application such that the user has to enter in manually the email address or username and then it takes the user through an authentication process whereby it asks the user if they wish to allow the application to be given access to the services mentioned in the manifest.xml file. Isn't there a better way to do this I mean like I want that when the user upon logging into his google apps account just has to click in the application link installed and straight on should be able to enter the application. Can't the process of authentication and all be transparent in the backdrop. I need help on this asap. Thanks a bunch!

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  • HLSL How can one pass data between shaders / read existing colour value?

    - by RJFalconer
    Hello all, I have 2 HLSL ps2.0 shaders. Simplified, they are: Shader 1 Reads texture Outputs colour value based on this texture Shader 2 Needs to read in existing colour (or have it passed in/read from a register) Outputs the final colour which is a function of the previous colour (They need to be different shaders as I've reached the maximum vertex-shader outputs for 1 shader) My problem is I cannot work out how Shader 2 can access the existing fragment/pixel colour. Is the only way for shaders to interact really just the alpha blending options? These aren't sufficient if I want to use the colour as input to my function.

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  • How Does One Make Scala Control Abstraction in Repeat Until?

    - by peter_pilgrim
    Hi I am Peter Pilgrim. I watched Martin Odersky create a control abstraction in Scala. However I can not yet seem to repeat it inside IntelliJ IDEA 9. Is it the IDE? package demo class Control { def repeatLoop ( body: = Unit ) = new Until( body ) class Until( body: = Unit ) { def until( cond: = Boolean ) { body; val value: Boolean = cond; println("value="+value) if ( value ) repeatLoop(body).until(cond) // if (cond) until(cond) } } def doTest2(): Unit = { var y: Int = 1 println("testing ... repeatUntil() control structure") repeatLoop { println("found y="+y) y = y + 1 } { until ( y < 10 ) } } } The error message reads: Information:Compilation completed with 1 error and 0 warnings Information:1 error Information:0 warnings C:\Users\Peter\IdeaProjects\HelloWord\src\demo\Control.scala Error:Error:line (57)error: Control.this.repeatLoop({ scala.this.Predef.println("found y=".+(y)); y = y.+(1) }) of type Control.this.Until does not take parameters repeatLoop { In the curried function the body can be thought to return an expression (the value of y+1) however the declaration body parameter of repeatUntil clearly says this can be ignored or not? What does the error mean?

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  • Is there a way to set two C#.Net projects to trust one another?

    - by Eric
    I have two C#.NET projects in a single solution ModelProject and PluginProject. PlugInProject is a plug-in for another application, and consequently references its API. PlugInProject is used to extract data from the application it plugs into. ModelProject contains the data model of classes that are extracted by PlugInProject. The extracted data can be used independent of the application or the plug-in, which is why I am keeping PlugInProject separate from ModelProject. I want ModelProject to remain independent of PlugInProject, and the Applications API. Or in other words I want someone to be able to access the extracted data without needing access to PlugInProject, the application, or the application's API. The problem I'm running into though is PlugInProject needs to be able to create and modify classes in ModelProject. However, I'd prefer to not make these actions public to anyone using ModelProject. The extracted data should effectively be read-only, unless later modified by PlugInProject. How can I keep these projects separate but give PlugInProject exclusive access to ModelProject? Is this possible?

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  • C++ Class Inheritance architecture - preventing casting

    - by Some One
    I have a structure of base class and a couple of inherited classed. Base class should be pure virtual class, it should prevent instantiation. Inherited classes can be instantiated. Code example below: class BaseClass { public: BaseClass(void); virtual ~BaseClass(void) = 0; }; class InheritedClass : public BaseClass { public: InheritedClass1(void); ~InheritedClass1(void); }; class DifferentInheritedClass : public BaseClass { public: DifferentInheritedClass(void); ~DifferentInheritedClass(void); }; I want to prevent the following operations to happen: InheritedClass *inherited1 = new InheritedClass(); DifferentInheritedClass *inherited2 = new DifferentInheritedClass (); BaseClass *base_1 = inherited1; BaseClass *base_2 = inherited2; *base_1 = *base_2;

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  • Should client-server code be written in one "project" or two?

    - by Ricket
    I've been beginning a client-server application. At first I naturally created two projects in Eclipse, two source control repositories, etc. But I'm quickly seeing that there is a bit of shared code between the two that would probably benefit to sharing instead of copying. In addition, I've been learning and trying test-driven development, and it seems to me that it would be easier to test based on real client components rather than having to set up a huge amount of code just to mock something, when the code is probably mostly in the client. My biggest concern in merging the client and server is of security; how do I ensure that the server pieces of the code do not reach an user's computer? So especially if you are writing client-server applications yourself (and especially in Java, though this can turn into a language-agnostic question if you'd like to share your experience with this in other languages), what sort of separation do you keep between your client and server code? Are they just in different packages/namespaces or completely different binaries using shared libraries, or something else entirely? How do you test the code together and yet ship separately?

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  • need help building a stored procedure that takes rows from one table into another.

    - by MyHeadHurts
    alright i built this stored procedure to take the columns from a stagging table and copy them into my other table, but if these four columns are duplicates it wont insert the rows, works fine. however, what i want to do is if only the tour, taskname and deptdate are the same, then i will update the rest of the information. and if all four columns are the same dont instert. INSERT INTO dashboardtasks1 SELECT [tour], [taskname], [deptdate], [tasktype], [desc], [duedate], [compdate], [comments], [agent], [compby], [graceperiod] FROM staggingtasks WHERE NOT EXISTS(SELECT * FROM dashboardtasks1 WHERE (staggingtasks.tour=dashboardtasks1.tour and staggingtasks.taskname=dashboardtasks1.taskname and staggingtasks.deptdate=dashboardtasks1.deptdate and staggingtasks.duedate=dashboardtasks1.duedate ) ) i saw something like this INSERT INTO table (a,b,c) VALUES (1,2,3) ON DUPLICATE KEY UPDATE c=c+1; UPDATE table SET c=c+1 WHERE a=1; but how could i do it if my stated 3 columns are the samed then update? or is there a way to do this with an if statement and use 2 different queries, but how would my if statement work would it check if the row exists in the table i am uploading to and then run the insert statement? or what if i did something like IF EXISTS (SELECT * FROM dashboardtasks WHERE staggingtasks.tour=dashboardtasks.tour and staggingtasks.taskname=dashboardtasks.taskname and staggingtasks.deptdate=dashboardtasks.deptdate ) begin UPDATE [dashboardtasks] SET [tour] = staggingtasks.tour, [taskname] = staggingtasks.taskname, [deptdate] = staggingtasks.deptdate, [tasktype] = staggingtasks.tasktype, [desc] = staggingtasks.desc, [duedate] = staggingtasks.duedate, [compdate] = staggingtasks.compdate, [comments] = staggingtasks.comments, [agent] = staggingtasks.agent, [compby] = staggingtasks.compby, [graceperiod] = staggingtasks.graceperiod end else EXISTS (SELECT * FROM dashboardtasks WHERE staggingtasks.tour=dashboardtasks.tour and staggingtasks.taskname=dashboardtasks.taskname and staggingtasks.deptdate=dashboardtasks.deptdate and staggingtasks.duedate=dashboardtasks.duedate ) begin INSERT INTO dashboardtasks1 SELECT [tour], [taskname], [deptdate], [tasktype], [desc], [duedate], [compdate], [comments], [agent], [compby], [graceperiod] FROM staggingtasks WHERE NOT EXISTS(SELECT * FROM dashboardtasks1 WHERE (staggingtasks.tour=dashboardtasks1.tour and staggingtasks.taskname=dashboardtasks1.taskname and staggingtasks.deptdate=dashboardtasks1.deptdate and staggingtasks.duedate=dashboardtasks1.duedate ) ) end end

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  • Wordpress: How to override all default theme CSS so your custom one is loaded the last?

    - by mickael
    I have a problem where I've been able to include a custom css in the section of my wordpress theme with the following code: function load_my_style_wp_enqueue_scripts() { wp_register_style('my_styles_css', includes_url("/css/my_styles.css")); wp_enqueue_style('my_styles_css'); } add_action('wp_enqueue_scripts','load_my_style_wp_enqueue_scripts'); But the order in the source code is as follows: <link rel='stylesheet' id='my_styles_css-css' href='http://...folderA.../my_styles.css?ver=3.1' type='text/css' media='all' /> <link rel="stylesheet" id="default-css" href="http://...folderB.../default.css" type="text/css" media="screen,projection" /> <link rel="stylesheet" id="user-css" href="http://...folderC.../user.css" type="text/css" media="screen,projection" /> I want my_styles_css to be the last file to load, overriding default and user files. I've tried to achieve this by modifying wp_enqueue_style in different ways, but without any success. I've tried: wp_enqueue_style('my_styles_css', array('default','user')); or wp_enqueue_style('my_styles_css', false, array('default','user'), '1.0', 'all'); I've seen some related questions without answer or with these last 2 methods that are still failing for me. The function above is part of a plugin that I've got enabled in my wordpress installation.

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  • This pagination script is doodoo - I need a better one!

    - by ClarkSKent
    Hello, I was looking at the pagination script (posted below) and found it to be gros,s and not very good at all especially when trying to customize it. This is what the main page looks like: <?php include('config.php'); $per_page = 9; //Calculating no of pages $sql = "select * from messages"; $result = mysql_query($sql); $count = mysql_num_rows($result); $pages = ceil($count/$per_page) ?> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/ libs/jquery/1.3.0/jquery.min.js"></script> <script type="text/javascript" src="jquery_pagination.js"></script> <div id="loading" ></div> <div id="content" ></div> <ul id="pagination"> <?php //Pagination Numbers for($i=1; $i<=$pages; $i++) { echo '<li id="'.$i.'">'.$i.'</li>'; } ?> </ul> The top part of the code gets the results from the mysql db and than uses this information to display the numbers in the body of this page. I am trying to put something like this on a separate page like count_page.php and then just include it. I guess my question is, if there is a better way of doing the above with better structure. A better way to go through the db and count the results and display the appropriate numbers. The above seems messy. Thanks for any help or suggestions on this.

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  • How can one use the "Add view" dialog in Visual Studio efficiently when working with ASP.NET MVC?

    - by Marek
    Does anyone else think that the add view dialog in VS is useless or is it just me? Why is there no search/filtering in there? I can not even paste the type name (without namespace) there to speed up the view creation. Plus, there are a lot of irrelevant classes there, including classes from all referenced libraries. Am I missing something or Microsoft never did any usability testing with that?? Is it possible to filter out types/assemblies in the dialog and/or better navigation compared to manually scrolling the combobox with all the types listed? Is it possible to include only types from a particular directory/assembly/namespace? (the ViewModels namespace for example) EDIT: As it seems from the answers that there is no usable workaround for this, I have filed a suggestion at Connect: https://connect.microsoft.com/VisualStudio/feedback/ViewFeedback.aspx?FeedbackID=507784 Please vote for the suggestion if you find this is an important issue.

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