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  • sorting content of a text file in python

    - by rabidmachine9
    I have this small script that sorts the content of a text file # The built-in function `open` opens a file and returns a file object. # Read mode opens a file for reading only. try: f = open("tracks.txt", "r") try: # Read the entire contents of a file at once. # string = f.read() # OR read one line at a time. #line = f.readline() # OR read all the lines into a list. lines = f.readlines() lines.sort() f = open('tracks.txt', 'w') f.writelines(lines) # Write a sequence of strings to a file finally: f.close() except IOError: pass the only problem is that the text is displayed at the bottom of the text file everytime it's sortened... I assume it also sorts the blank lines...anybody knows why? thanks in advance

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  • undefined reference

    - by rantravee
    Hi, I'm unfamiliar to working in c++ under linux so I have some issues, one of them is that after I write a class and try to instantiate an object of that class I get to following error : "undefined reference to Constructor_of_that_class" . This happens for every class that I write , and it happens no matter where I try to do the instantiating, even if the code compiles without any problems . What is going wrong here and what I have to do to get over this error ? Because the project that I'm working wasn't created by me I suspect that it has to do something with some settings but I don't know which.

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  • Get Jira to run on shared Windows server on port 80

    - by codeulike
    I know this can be done on Linux with JIRA, using mod_proxy, but I'm not sure if its possible on Windows: Say we have a Windows server running IIS 7.0 and serving up pages on port 80, via an address like: http://twiddle.something.com We then install JIRA on the server, it uses its bundles Apache web server to serve stuff up on port 8080, like this: http://twiddle.something.com:8080 Is there a way to configure IIS and Apache so that JIRA runs off a port 80 folder, as in: http://twiddle.something.com still hits IIS http://twiddle.something.com/Jira hits JIRA on Apache? Thanks edit: I guess we might also want to throw SSL into the mix for JIRA too....

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  • Add 'expand' button to JTree node that has no children?

    - by thedude19
    I'd like to add the 'expand' button to my JTree's nodes to indicate that they are expandable. The catch is that they have no children until the user clicks on them (due to processing that happens in the background). Is there any way I can set a node as a parent or having children without it actually having children? Thanks

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  • Problem while adding a new value to a hashtable when it is enumerated

    - by karthik
    `hi I am doing a simple synchronous socket programming,in which i employed twothreads one for accepting the client and put the socket object into a collection,other thread will loop through the collection and send message to each client through the socket object. the problem is 1.i connect to clients to the server and start send messages 2.now i want to connect a new client,while doing this i cant update the collection and add a new client to my hashtable.it raises an exception "collection modified .Enumeration operation may not execute" how to add a NEW value without having problems in a hashtable. private void Listen() { try { //lblStatus.Text = "Server Started Listening"; while (true) { Socket ReceiveSock = ServerSock.Accept(); //keys.Clear(); ConnectedClients = new ListViewItem(); ConnectedClients.Text = ReceiveSock.RemoteEndPoint.ToString(); ConnectedClients.SubItems.Add("Connected"); ConnectedList.Items.Add(ConnectedClients); ClientTable.Add(ReceiveSock.RemoteEndPoint.ToString(), ReceiveSock); //foreach (System.Collections.DictionaryEntry de in ClientTable) //{ // keys.Add(de.Key.ToString()); //} //ClientTab.Add( //keys.Add( } //lblStatus.Text = "Client Connected Successfully."; } catch (Exception ex) { MessageBox.Show(ex.Message); } } private void btn_receive_Click(object sender, EventArgs e) { Thread receiveThread = new Thread(new ThreadStart(Receive)); receiveThread.IsBackground = true; receiveThread.Start(); } private void Receive() { while (true) { //lblMsg.Text = ""; byte[] Byt = new byte[2048]; //ReceiveSock.Receive(Byt); lblMsg.Text = Encoding.ASCII.GetString(Byt); } } private void btn_Send_Click(object sender, EventArgs e) { Thread SendThread = new Thread(new ThreadStart(SendMsg)); SendThread.IsBackground = true; SendThread.Start(); } private void btnlist_Click(object sender, EventArgs e) { //Thread ListThread = new Thread(new ThreadStart(Configure)); //ListThread.IsBackground = true; //ListThread.Start(); } private void SendMsg() { while (true) { try { foreach (object SockObj in ClientTable.Keys) { byte[] Tosend = new byte[2048]; Socket s = (Socket)ClientTable[SockObj]; Tosend = Encoding.ASCII.GetBytes("FirstValue&" + GenerateRandom.Next(6, 10).ToString()); s.Send(Tosend); //ReceiveSock.Send(Tosend); Thread.Sleep(300); } } catch (Exception ex) { MessageBox.Show(ex.Message); } } }

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  • System.Uri("") in default browser?

    - by Hallgaws
    I am using special program where it loads some url imagine it like window with automatically load www.google.com - program starts and it load the site - BUT when you click on some links in the program window it opens in default browser - how it can be opened in default browser - I am using this code: <Global.Microsoft.VisualBasic.CompilerServices.DesignerGenerated()> _ Partial Class Form1 Inherits System.Windows.Forms.Form <System.Diagnostics.DebuggerNonUserCode()> _ Protected Overrides Sub Dispose(ByVal disposing As Boolean) Try If disposing AndAlso components IsNot Nothing Then components.Dispose() End If Finally MyBase.Dispose(disposing) End Try End Sub Private components As System.ComponentModel.IContainer <System.Diagnostics.DebuggerStepThrough()> _ Private Sub InitializeComponent() Me.components = New System.ComponentModel.Container Dim resources As System.ComponentModel.ComponentResourceManager = New System.ComponentModel.ComponentResourceManager(GetType(Form1)) Me.WB = New System.Windows.Forms.WebBrowser ..... ..... Me.WB.Url = New System.Uri("http://www.google.com/", System.UriKind.Absolute) Using Visual Basic 2008

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  • Problem with tcp server when converting to service

    - by djerry
    Hello lads, I'm working on monitoring some object (cdr-packets). I'm setting up a tcp-server and am listening on port 50043 for the packages. The program as a console application is working just fine, my server is working like it should and i'm receiving the packets. When i try to use it as a service, i cannot seem to get a client connected to my server. Is there something i need to change to deploy this as a service? Code below is from my application: this is my service class where i start protected override void OnStart(string[] args) { server = new TcpServer(); server.StartServer(); } this is the constructor of TcpServer public TcpServer() { try { _server = new TcpListener(IPAddress.Any, 50043); } catch (Exception) { _server = null; } } this is the method i call after initialising the class public void StartServer() { if (_server != null) { // Create a ArrayList for storing SocketListeners before starting the server. _socketListenersList = new ArrayList(); // Start the Server and start the thread to listen client requests. _server.Start(); _serverThread = new Thread(new ThreadStart(ServerThreadStart)); _serverThread.Start(); // Create a low priority thread that checks and deletes client // SocktConnection objcts that are marked for deletion. _purgingThread = new Thread(new ThreadStart(PurgingThreadStart)); _purgingThread.Priority = ThreadPriority.Lowest; _purgingThread.Start(); } } this is the thread that keep checking if any client tries to connect private void ServerThreadStart() { // Client Socket variable; Socket clientSocket = null; TcpSocketListener socketListener = null; while (!_stopServer) { try { // Wait for any client requests and if there is any request from any //client accept it (Wait indefinitely). clientSocket = _server.AcceptSocket(); // Create a SocketListener object for the client. socketListener = new TcpSocketListener(clientSocket); // Add the socket listener to an array list in a thread safe fashon. lock (_socketListenersList) { _socketListenersList.Add(socketListener); } // Start a communicating with the client in a different thread. socketListener.StartSocketListener(); } catch (SocketException se) { _stopServer = true; } } } when for the first time a packet waits to be read, and i get to "clientSocket = _server.AcceptSocket();", it throws an exception (service, not very good debugable) Does anyone recognize this problem or can help me? Thanks in advance

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  • Google Custom Search Engine not giving the expected search result.

    - by iecut
    Hi, I have been trying to create a new google custom search engine, but when I try some query,the search engine it is not giving me the expected search result.On some queries it is working fine, but on other queries, it says"no result". I tried adding the URL of the website that I wanted to search for, but there are certain pages and keywords that are not coming up in the search result when I try to search for the keyword of that page. I tired adding both the main page URL and the URL of the sub page that I want to search for, but nothing is working. There are some sub pages to the main URL that are coming in the search result.

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  • Handling touches during animation on iPhone

    - by SalvoMaltese
    I have a view with multiple controls inside (a picker, a switch, a slider...). I use an animation to move this view; it appears from bottom and goes up until it disappear by the top. I can't get the inside controls respond to touches while the view is moving. How can I catch those touches?

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  • Silverlight Pixel Shader resource "not found"; what should the URI be?

    - by Grank
    So I've written and compiled an HLSL pixel shader with Shazzam, placed the resulting .ps file in my project, and am trying to instantiate it. No matter what URI I put, Blend tells me that the resource can't be found whenever I try to view any xaml designer, and Visual Studio just shows me a blank page, both in design view and if I try to run the application. This is a Silverlight 4 SketchFlow project, in Blend 4 RC and Visual Studio 2010. I've tried both Resource and EmbeddedResource as the Build Action for the .ps file, neither make any difference (I'm pretty sure it's supposed to be set to Resource). I've tried the following URI formats: "ShaderFileName.ps" "/ShaderFileName.ps" "AssemblyName;component/ShaderFileName.ps" "/AssemblyName;component/ShaderFileName.ps" I also tried moving the shader file from the Screens assembly to the root assembly (that's how SketchFlow projects are created) and that didn't help either. Anyone have any thoughts?

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  • Service Contracts with Message causes duplicate proxy classes

    - by jaklucky
    Hi, I have a service contract with Message as shown below. [OperationContract] Message MyMethodWithMessage(Message myMsgParam); Everything works fine. I could host my services. But when I try to create proxies through "Add Service References", I am getting the duplicate proxy classes. If I take out the above OperationContract and re run my services and try to create proxies, then "Add Service References" does not provide duplicate proxies. I am really confused about this!!! Any help is greatly appreciated... Thank you, Suresh

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  • How can i do the same thing with Gallery in Android

    - by Maxood
    I am navigating images with the clicks of next and previous buttons.Here is my code: package com.myapps.imagegallery; import android.app.Activity; import android.os.Bundle; import android.view.View; import android.widget.Button; import android.widget.ImageView; import android.widget.TextView; import android.widget.Toast; public class ImageGallery extends Activity { /** Called when the activity is first created. */ int imgs[] = {R.drawable.bluehills,R.drawable.lilies,R.drawable.sunset,R.drawable.winter}; String desc[] = {"Blue Hills", "Lillies", "Sunset", "Winter" }; int counter=0; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); final ImageView imgView = (ImageView)findViewById(R.id.ImageView01); imgView.setImageResource(imgs[counter]); final TextView tvDesc = (TextView)findViewById(R.id.tvDesc); Button btnNext = (Button)findViewById(R.id.btnNext); btnNext.setOnClickListener(new View.OnClickListener(){ @Override public void onClick(View arg0) { try{ // TODO Auto-generated method stub if (counter < desc.length -1) counter++; imgView.setImageResource(imgs[counter]); tvDesc.setText(desc[counter]); }catch(Exception e) { Toast.makeText(ImageGallery.this, e.toString(), Toast.LENGTH_SHORT).show(); } } }); Button btnPrev = (Button)findViewById(R.id.btnPre); btnPrev.setOnClickListener(new View.OnClickListener(){ @Override public void onClick(View arg0) { // TODO Auto-generated method stub try{ // TODO Auto-generated method stub if (counter > 0) counter--; imgView.setImageResource(imgs[counter]); tvDesc.setText(desc[counter]); }catch(Exception e) { Toast.makeText(ImageGallery.this, e.toString(), Toast.LENGTH_SHORT).show(); } }}); } } <?xml version="1.0" encoding="utf-8"?> <AbsoluteLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" > <ImageView android:id="@+id/ImageView01" android:layout_x="70dip" android:layout_width="200px" android:layout_height="200px" android:layout_y="90dip" > </ImageView> <TextView android:id="@+id/tvDesc" android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="@string/hello" android:layout_x="90px" android:layout_y="300px" /> <Button android:layout_x="47dip" android:layout_height="wrap_content" android:text="Previous" android:layout_width="100px" android:id="@+id/btnPre" android:layout_y="341dip"> </Button> <Button android:layout_x="190dip" android:layout_height="wrap_content" android:text="Next" android:layout_width="100px" android:id="@+id/btnNext" android:layout_y="341dip"> </Button> </AbsoluteLayout>

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  • How to validate hostname in perl?

    - by embedded
    Hi, I need to come up with a regular expression to validate hostname against RFC-1123 and RFC-952. Right now I'm using this: ^(?=.{1,255}$)[0-9A-Za-z](?:(?:[0-9A-Za-z]|\b-){0,61}[0-9A-Za-z])?(?:\.[0-9A-Za-z](?:(?:[0-9A-Za-z]|\b-){0,61}[0-9A-Za-z])?)*\.?$/ but this does not do the trick since it does not catch a. as invalid hostname. How do I enhance the reg expression to comply with those RFCs? Thanks

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  • sql statement "into outfile" not working with jdbc

    - by Celeste Berus
    I am attempting to add an "export to CSV" feature to a webapp that displays data from a MySQL database. I have a written a "queryExecuter" class to execute queries from my servlet. I have used this to successfully execute insert queries so I know the connection works etc however queries with the "into outfile" statement are simply not executing. Here is my code, the java class... import java.sql.Connection; import java.sql.DriverManager; import java.sql.Statement; import java.sql.ResultSet; public class queryExecuter { public void exportToCSV(String query) { DBase db = new DBase(); Connection conn = db.connect( mydatabaseurl ,"myusername","mypassword"); db.exportData(conn,query); } } class DBase { public DBase() { } public Connection connect(String db_connect_str, String db_userid, String db_password) { Connection conn; try { Class.forName("com.mysql.jdbc.Driver").newInstance(); conn = DriverManager.getConnection(db_connect_str, db_userid, db_password); } catch(Exception e) { e.printStackTrace(); conn = null; } return conn; } public void exportData(Connection conn,String query) { Statement stmt; try { stmt = conn.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE, ResultSet.CONCUR_UPDATABLE); stmt.execute(query); } catch(Exception e) { e.printStackTrace(); stmt = null; } } }; The servlet... import java.io.IOException; import java.io.PrintWriter; import java.sql.SQLException; import java.util.logging.Level; import java.util.logging.Logger; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import javax.servlet.*; import javax.servlet.http.*; import java.io.*; public class MyExportServlet extends HttpServlet { public void doPost(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException { String query = "select into outfile 'theoutfile.txt' * from mytable;"; request.setAttribute("query", query); queryExecuter mydata = new queryExecuter(); mydata.exportToCSV(query); RequestDispatcher view = request.getRequestDispatcher("ConfirmationPage.jsp"); view.forward(request, response); } } Any help would be greatly appreciated. Thank you

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  • Java: initialization problem, cannot print "assigned" values from arrayList

    - by HH
    $ javac ArrayListTest.java $ java ArrayListTest $ cat ArrayListTest.java import java.io.*; import java.util.*; public class ArrayListTest{ public static void main(String[] args) { try { String hello ="oeoaseu oeu hsoae sthoaust hoaeut hoasntu"; ArrayList<String> appendMe = null; for(String s : hello.split(" ")) appendMe.add(s+" "); for(String s : appendMe) System.out.println(s); //WHY DOES IT NOT PRINT? }catch(Exception e){ } } }

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  • How can i return dataset perfectly from sql?

    - by Phsika
    i try to write a winform application: i dislike below codes: DataTable dt = new DataTable(); dt.Load(dr); ds = new DataSet(); ds.Tables.Add(dt); Above part of codes looks unsufficient.How can i best loading dataset? public class LoadDataset { public DataSet GetAllData(string sp) { return LoadSQL(sp); } private DataSet LoadSQL(string sp) { SqlConnection con = new SqlConnection(ConfigurationSettings.AppSettings["ConnectionString"].ToString()); SqlCommand cmd = new SqlCommand(sp, con); DataSet ds; try { con.Open(); cmd.CommandType = CommandType.StoredProcedure; SqlDataReader dr = cmd.ExecuteReader(); DataTable dt = new DataTable(); dt.Load(dr); ds = new DataSet(); ds.Tables.Add(dt); return ds; } finally { con.Dispose(); cmd.Dispose(); } } }

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  • GF 3.0.1 + Virtual Server: www.myhost.com:8080/projectname-war => www.myhost.com. How?

    - by Harry Pham
    EDIT I need to change www.myhost.com:8080/myproject-war to www.myhost.com. Here is what I've been trying: I configurate the Virtual Server: server. I have still have default Network Listeners to be http-listener-1 and http-listner-2. I change the Default Web Module to ScholarActive#ScholarActive-war.war (The only option in the drop down list, since I only deploy 1 application). For the docroot, I try this ${com.sun.aas.instanceRoot}/applications/ScholarActive/ScholarActive-war_war or this ${com.sun.aas.instanceRoot}/applications/ScholarActive/ Both does not work. What does docroot need to point to, for this to work? what I try to do is: when I type localhost:8080/ScholarActive-war, then my application load, I want to make so that if I type locahost:8080, it will load the app as well, then what left is changed the port to 80. But no luck. Any Idea?

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  • PHP Strange error "0:". Possible Object syntax problem?

    - by Michael Stone
    I'm trying to transfer a site from one hosting company to another. I was using 000webhost until the client had hosting and a domain. Now that the client has their domain and hosting, using FatCow.com, I can not for the life of me, debug my PHP code. I'm not getting any errors. I have a successful DB connection. If you procedurally display data, it works, but when I try to use my original objects, something is breaking and just returns "0:". I have all errors on. On old server where the site worked: PHP Version 5.2.11 MySQL Version: 5.0.81 On new server where I get the "0:": PHP Version 5.2.12 MySQL Version 5.0.32 I've setup a test page to test just the output of the variables with the DB connection. Below is my code: <?php error_reporting(E_ALL); ini_set('display_errors', '1'); try { $link = mysql_connect('connectionstring', 'username', 'password'); if (!$link) { die('Could not connect: ' . mysql_error()); } else{ $db = mysql_select_db('a8210422_lit'); } if($db){ include_once('admin/classes/clsPOW.php'); include_once('admin/classes/clsProviders.php'); $pow = new POW(); $prov = new Providers(); $new = $pow->getNew(); $newAr = $new->val(); $get = $prov->getAll($newAr['providerId']); $getAr = $get->val(); $img = $getAr['image']; $name = $getAr['provider']; $desc = $getAr['description']; $zip = $getAr['zip']; $web = $getAr['link']; if($zip==0){ $zip = "Unavailable"; } print $img; print $name; print $desc; print $zip; print $web; } else{ print 'fail!'; } } //catch exception catch(Exception $e) { echo 'Message: ' .$e->getMessage(); } ?>

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  • Reading POST data from html form sent to serversocket.

    - by user32167
    i try to write simplest possible server app in Java, displaying html form with textarea input, which after submitting gives me possibility to parse xml typed in that textarea. For now i build simple serversocket based server like that: import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.PrintWriter; import java.net.ServerSocket; import java.net.Socket; public class WebServer { protected void start() { ServerSocket s; String gets = ""; System.out.println("Start on port 80"); try { // create the main server socket s = new ServerSocket(80); } catch (Exception e) { System.out.println("Error: " + e); return; } System.out.println("Waiting for connection"); for (;;) { try { // wait for a connection Socket remote = s.accept(); // remote is now the connected socket System.out.println("Connection, sending data."); BufferedReader in = new BufferedReader(new InputStreamReader( remote.getInputStream())); PrintWriter out = new PrintWriter(remote.getOutputStream()); String str = "."; while (!str.equals("")) { str = in.readLine(); if (str.contains("GET")){ gets = str; break; } } out.println("HTTP/1.0 200 OK"); out.println("Content-Type: text/html"); out.println(""); // Send the HTML page String method = "get"; out.print("<html><form method="+method+">"); out.print("<textarea name=we></textarea></br>"); out.print("<input type=text name=a><input type=submit></form></html>"); out.println(gets); out.flush(); remote.close(); } catch (Exception e) { System.out.println("Error: " + e); } } } public static void main(String args[]) { WebServer ws = new WebServer(); ws.start(); } } After form (textarea with xml and one additional text input) is submitted in 'gets' String-type variable I have Urlencoded values of my variables (also displayed on the screen, it looks like that: gets = GET /?we=%3Cnetwork+ip_addr%3D%2210.0.0.0%2F8%22+save_ip%3D%22true%22%3E%0D%0A%3Csubnet+interf_used%3D%22200%22+name%3D%22lan1%22+%2F%3E%0D%0A%3Csubnet+interf_used%3D%22254%22+name%3D%22lan2%22+%2F%3E%0D%0A%3C%2Fnetwork%3E&a=fooBar HTTP/1.1 What can i do to change GET to POST method (if i simply change it in form and than put " if (str.contains("POST")){" it gives me string like gets = POST / HTTP/1.1 with no variables. And after that, how i can use xml from my textarea field (called 'we')?

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  • print integer and array from file android

    - by vik
    i want to open a file and then calculate the integer and array value from file and print on the screen. i tried this but not working @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); TextView av = new TextView(this); setContentView(av); try { String i = "abc.xyz"; InputStream in = assets.open(i); try { DataInputStream din = new DataInputStream(in); int value = din.readInt(); // print value on screen int[] arry = new int[1]; // print arry on screen how to do it int arry[1] = din.readInt(); } } finally { in.close(); } } catch (IOException e) { throw new PuzzleIOException(e); } av.setText(size); }

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  • youtube - video upload failure - unable to convert file - encoding the video wrong?

    - by Anthony
    I am using .NET to create a video uploading application. Although it's communicating with YouTube and uploading the file, the processing of that file fails. YouTube gives me the error message, "Upload failed (unable to convert video file)." This supposedly means that "your video is in a format that our converters don't recognize..." I have made attempts with two different videos, both of which upload and process fine when I do it manually. So I suspect that my code is a.) not encoding the video properly and/or b.) not sending my API request properly. Below is how I am constructing my API PUT request and encoding the video: Any suggestions on what the error could be would be appreciated. Thanks P.S. I'm not using the client library because my application will use the resumable upload feature. Thus, I am manually constructing my API requests. Documentation: http://code.google.com/intl/ja/apis/youtube/2.0/developers_guide_protocol_resumable_uploads.html#Uploading_the_Video_File Code: // new PUT request for sending video WebRequest putRequest = WebRequest.Create(uploadURL); // set properties putRequest.Method = "PUT"; putRequest.ContentType = getMIME(file); //the MIME type of the uploaded video file //encode video byte[] videoInBytes = encodeVideo(file); public static byte[] encodeVideo(string video) { try { byte[] fileInBytes = File.ReadAllBytes(video); Console.WriteLine("\nSize of byte array containing " + video + ": " + fileInBytes.Length); return fileInBytes; } catch (Exception e) { Console.WriteLine("\nException: " + e.Message + "\nReturning an empty byte array"); byte [] empty = new byte[0]; return empty; } }//encodeVideo //encode custom headers in a byte array byte[] PUTbytes = encode(putRequest.Headers.ToString()); public static byte[] encode(string headers) { ASCIIEncoding encoding = new ASCIIEncoding(); byte[] bytes = encoding.GetBytes(headers); return bytes; }//encode //entire request contains headers + binary video data putRequest.ContentLength = PUTbytes.Length + videoInBytes.Length; //send request - correct? sendRequest(putRequest, PUTbytes); sendRequest(putRequest, videoInBytes); public static void sendRequest(WebRequest request, byte[] encoding) { Stream stream = request.GetRequestStream(); // The GetRequestStream method returns a stream to use to send data for the HttpWebRequest. try { stream.Write(encoding, 0, encoding.Length); } catch (Exception e) { Console.WriteLine("\nException writing stream: " + e.Message); } }//sendRequest

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  • How to change fileupload name

    - by Domnic
    im using following code to upload protected void UploadButton_Click(object sender, EventArgs e) { if(FileUploadControl.HasFile) { try { string filename = Path.GetFileName(FileUploadControl.FileName); FileUploadControl.SaveAs(Server.MapPath("~/") + filename); StatusLabel.Text = "Upload status: File uploaded!"; } catch(Exception ex) { StatusLabel.Text = "Upload status: The file could not be uploaded. The following error occured: " + ex.Message; } } } i want to cahnge upload file name...i have to assign file name for every uploaded file how?

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