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  • Add data to Django form class using modelformset_factory

    - by dean
    I have a problem where I need to display a lot of forms for detail data for a hierarchical data set. I want to display some relational fields as labels for the forms and I'm struggling with a way to do this in a more robust way. Here is the code... class Category(models.Model): name = models.CharField(max_length=160) class Item(models.Model): category = models.ForeignKey('Category') name = models.CharField(max_length=160) weight = models.IntegerField(default=0) class Meta: ordering = ('category','weight','name') class BudgetValue(models.Model): value = models.IntegerField() plan = models.ForeignKey('Plan') item = models.ForeignKey('Item') I use the modelformset_factory to create a formset of budgetvalue forms for a particular plan. What I'd like is item name and category name for each BudgetValue. When I iterate through the forms each one will be labeled properly. class BudgetValueForm(forms.ModelForm): item = forms.ModelChoiceField(queryset=Item.objects.all(),widget=forms.HiddenInput()) plan = forms.ModelChoiceField(queryset=Plan.objects.all(),widget=forms.HiddenInput()) category = "" < assign dynamically on form creation > item = "" < assign dynamically on form creation > class Meta: model = BudgetValue fields = ('item','plan','value') What I started out with is just creating a dictionary of budgetvalue.item.category.name, budgetvalue.item.name, and the form for each budget value. This gets passed to the template and I render it as I intended. I'm assuming that the ordering of the forms in the formset and the querset used to genererate the formset keep the budgetvalues in the same order and the dictionary is created correctly. That is the budgetvalue.item.name is associated with the correct form. This scares me and I'm thinking there has to be a better way. Any help would be greatly appreciated.

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  • Pydev and Django: Shell not finding certain modules?

    - by Rosarch
    I am developing a Django project with PyDev in Eclipse. For a while, PyDev's Django Shell worked great. Now, it doesn't: >>> import sys; print('%s %s' % (sys.executable or sys.platform, sys.version)) C:\Python26\python.exe 2.6.4 (r264:75708, Oct 26 2009, 08:23:19) [MSC v.1500 32 bit (Intel)] >>> >>> from django.core import management;import mysite.settings as settings;management.setup_environ(settings) Traceback (most recent call last): File "<console>", line 1, in <module> ImportError: No module named mysite.settings >>> The dev server runs just fine. What could I be doing wrong? The models module is also conspicuously absent: >>> import mysite.myapp.models Traceback (most recent call last): File "<console>", line 1, in <module> ImportError: No module named mysite.myapp.models On the normal command line, outside of PyDev, the shell works fine. Why could this be happening?

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  • Django Database design -- Is this a good stragety for overriding defaults

    - by rh0dium
    Hi SO's I have a question on good database design practices and I would like to leverage you guys for pointers. The project started out simple. Hey we have a bunch of questions we want answered for every project (no problem) Which turned into... Hey we have so many questions can we group them into sections (yup we can do that) Which lead into.. Can we weight these questions and I don't really want some of these questions for my project (Yes but we are getting difficult) And then I'm thinking they will want to have each section have it's own weight.. Requirements So there's the requirements - For n number of project Allow a admin member the ability select the questions for a project Allow the admin member to re-weigh or use the default weights for the questions Allow the admin member to re-weight the sections Allow team members to answer the questions. So here is what I came up with. Please feel free to comment and provide better examples models.py from django.db import models from django.contrib.sites.models import Site from django.conf import settings class Section(models.Model): """ This describes the various sections for a checklist: """ name = models.CharField(max_length=64) description = models.TextField() class Question(models.Model): """ This simply provides a simple way to list out the questions. """ question = models.CharField(max_length=255) answer_type = models.CharField(max_length=16) description = models.TextField() section = models.ForeignKey(Section) class ProjectQuestion(models.Model): """ These are the questions relevant to the project """ question = models.ForeignKey(Question) answer = models.CharField(max_length=255) required = models.BooleanField(default=True) weight = models.FloatField(default = XXX) class Project(models.Model): """ Here is where we want to gather our questions """ questions = models.ManyToManyField(ProjectQuestion) Immediate questions: - When I start a project - any ideas on how to "pre-populate" the questions (and ultimately the weights) for the project? - Is there a generally accepted method for doing this process that I am missing? Basically the idea that you refer to the questions overide your own default weight, and store the answer? - It appears that a good chuck of the work will be done in the views and that a lot of checking will need to occur there? Is that OK? Again - feel free to give me better strategies!! Thanks

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  • django-social-auth for Facebook is redirecting home and not logging in

    - by Scott Rogowski
    I have had django-social-auth working for Google for quite some time now but am having problems with Facebook. I am at the point where clicking on the /login/facebook/ link will take me to the Facebook authorization page. I then click "go to app" and it redirects me to my home page but does not log in or create a user but does put some strange "#=" onto the back of my URL. Reading up on that, here https://developers.facebook.com/blog/post/552/, and here https://github.com/omab/django-social-auth/issues/199, it seems that would be happening if the redirect uri was not defined. However, on my facebook app settings, I have the following (replacing my site with example.com): + App Namespace: "example" + Site URL: "http://example.com/complete/facebook/" + Site Domain: "example.com" + Sandbox Mode: "On" + Post-Authorize Redirect URL: "http://apps.facebook.com/example/" + Deauthorize URL: "http://www.example.com/" + Post-Authorize URL: "http://example.com/complete/facebook/" The request that django-social-auth is sending to facebook is (replacing my info again): "https://www.facebook.com/dialog/oauth?scope=email&state=*&redirect_uri=http%3A%2F%2Fexample.com%2Fcomplete%2Ffacebook%2F%3Fredirect_state%3D***&client_id=*" The /complete/facebook/ is what is in the documentation and google works as /complete/google/ What am I missing here?

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  • Using django and django-voting app, how can I order a queryset according to the votes of each item?

    - by snz3
    (I'm new to python and django so please bear with me for a second. I apologise if this has been answered elsewhere and couldn't find it) Let's say I have a Link model and through the django-voting application users can vote on link instances. How can I order those link instances according to their score, eg. display those with the higher score first. I assume I could use the get_top manager of django-voting, but that would only give me the top scoring link instances and wouldn't take into consideration other parameters I would like to add (for example, those links that belong to a specific user or paging or whatever). My guess would be to write a custom manager for my Link model where by I can filter a queryset according to each item's score. If I understand correctly that will require me to loop through each item, check its score, and then place it a list (or dictionary) which will then be sorted according to the score of each item. That wouldn't return a queryset but a dictionary with each item. Am I missing something here?

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  • Django IntegrityError: foreign key violation upon delete

    - by Lukasz Korzybski
    I have Order and Shipment model. Shipment has a foreign key to Order. class Order(...): ... class Shipment() order = m.ForeignKey('Order') ... Now in one of my views I want do delete order object along with all related objects. So I invoke order.delete(). I have Django 1.0.4, PostgreSQL 8.4 and I use transaction middleware, so whole request is enclosed in single transaction. The problem is that upon order.delete() I get: ... File "/usr/local/lib/python2.6/dist-packages/django/db/backends/__init__.py", line 28, in _commit return self.connection.commit() IntegrityError: update or delete on table "main_order" violates foreign key constraint "main_shipment_order_id_fkey" on table "main_shipment" DETAIL: Key (id)=(45) is still referenced from table "main_shipment". I checked in connection.queries that proper queries are executed in proper order. First shipment is deleted, after that django executes delete on order row: {'time': '0.000', 'sql': 'DELETE FROM "main_shipment" WHERE "id" IN (17)'}, {'time': '0.000', 'sql': 'DELETE FROM "main_order" WHERE "id" IN (45)'} Foreign key have ON DELETE NO ACTION (default) and is initially deferred. I don't know why I get foreign key constraint violation. I also tried to register pre_delete signal and manually delete shipment objects before delete on order is called, but it resulted in the same error. I can change ON DELETE behaviour for this key in Postgres but it would be just a hack, I wonder if anyone has a better idea what's going on here. There is also a small detail, my Order model inherits from Cart model, so it actually doesn't have id field but cart_ptr_id and after DELETE on order is executed there is also DELETE on cart, but it seems unrelated? to the shipment-order problem so I simplified it in the example.

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  • django: results in in_bulk style without IDs

    - by valya
    in django 1.1.1, Place.objects.in_bulk() does not work and Place.objects.in_bulk(range(1, 100)) works and returns a dictionary of Ints to Places with indexes - primary keys. How to avoid using range in this situation (and avoid using a special query for ids, I just want to get all objects in this dictionary format) >>> Place.objects.in_bulk() Traceback (most recent call last): File "<console>", line 1, in <module> File "/usr/lib/python2.5/site-packages/Django-1.1.1-py2.5.egg/django/db/models/manager.py", line 144, in in_bulk return self.get_query_set().in_bulk(*args, **kwargs) TypeError: in_bulk() takes exactly 2 arguments (1 given) >>> Place.objects.in_bulk(range(1, 100)) {1L: <Place: "??? ????">, 3L: <Place: "???????????? ?????">, 4L: <Place: "????????? "??????"">, 5L: <Place: "????????? "??????"">, 8L: <Place: "????????? "??????????????"">, 9L: <Place: "??????? ????????">, 10L: <Place: "????????? ???????">, 11L: <Place: "??????????????? ???">, 14L: <Place: "????? ????? ??????">}

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  • Django extending user model and displaying form

    - by MichalKlich
    Hello, I am writing website and i`d like to implement profile managment. Basic thing would be to edit some of user details by themself, like first and last name etc. Now, i had to extend User model to add my own stuff, and email address. I am having troubles with displaying form. Example will describe better what i would like achieve. This is mine extended user model. class UserExtended(models.Model): user = models.ForeignKey(User, unique=True) kod_pocztowy = models.CharField(max_length=6,blank=True) email = models.EmailField() This is how my form looks like. class UserCreationFormExtended(UserCreationForm): def __init__(self, *args, **kwargs): super(UserCreationFormExtended, self).__init__(*args, **kwargs) self.fields['email'].required = True self.fields['first_name'].required = False self.fields['last_name'].required = False class Meta: model = User fields = ('username', 'first_name', 'last_name', 'email') It works fine when registering, as i need allow users to put username and email but when it goes to editing profile it displays too many fields. I would not like them to be able to edit username and email. How could i disable fields in form? Thanks for help.

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  • Connecting a django application to a drupal database?

    - by Hans
    I have a 3 - 4000 nodes in a drupal 6 installation on mysql and want to access these data through my django application. I have used manage.py inspectdb to get a skeleton of a model structure. I guess that there are good/historical reasons for drupal's database schemes, but find that there are some hard to understand structure and that there are some challenges in applying django models on the database. Some experiences this far are: node and node revision are intertwined and I solved this by using a OneToOneField (don't need the versions). This meens that the node's body gets accessible through node.vid.body, but it works. Foreign keys need to define the proper db_column to sort out the primary keys. Terms need to use an intermediary table with ManyToManyField.through. Drupal stores both the original and the thumbnailed/resized versions of any image as files in the files table. Does anyone have experiences in accessing drupal data in django? Are there better solution to for example the node <- node revision relationship? Drupal stores time/dates as unix-style timestamps in integerfields. Any recommendations? How about time zones?

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  • Sumproduct using Django's aggregation

    - by Matthew Rankin
    Question Is it possible using Django's aggregation capabilities to calculate a sumproduct? Background I am modeling an invoice, which can contain multiple items. The many-to-many relationship between the Invoice and Item models is handled through the InvoiceItem intermediary table. The total amount of the invoice—amount_invoiced—is calculated by summing the product of unit_price and quantity for each item on a given invoice. Below is the code that I'm currently using to accomplish this, but I was wondering if there is a better way to handle this using Django's aggregation capabilities. Current Code class Item(models.Model): item_num = models.SlugField(unique=True) description = models.CharField(blank=True, max_length=100) class InvoiceItem(models.Model): item = models.ForeignKey(Item) invoice = models.ForeignKey('Invoice') unit_price = models.DecimalField(max_digits=10, decimal_places=2) quantity = models.DecimalField(max_digits=10, decimal_places=4) class Invoice(models.Model): invoice_num = models.SlugField(max_length=25) invoice_items = models.ManyToManyField(Item,through='InvoiceItem') def _get_amount_invoiced(self): invoice_items = self.invoiceitem_set.all() amount_invoiced = 0 for invoice_item in invoice_items: amount_invoiced += (invoice_item.unit_price * invoice_item.quantity) return amount_invoiced amount_invoiced = property(_get_amount_invoiced)

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  • django ManyToMany through help

    - by dotty
    Hay I've got a question about relationships. I want to Users to have Friendships. So a User can be a friend with another User. I'm assuming i'll need to use the ManyToManyField, through a Friendship table. But i cannot get it to work. Any ideas? Here are my models. class User(models.Model): username = models.CharField(max_length=999) password = models.CharField(max_length=999) created_on = models.DateField(auto_now = False, auto_now_add = True) updated_on = models.DateField(auto_now = True, auto_now_add = False) friends = models.ManyToManyField('User', through='Friendship') class Friendship(models.Model): user = models.ForeignKey('User') friend = models.ForeignKey('User') Thanks

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  • Django Per-site caching using memcached

    - by Paul
    Hi, So I'm using per-site caching on a project and I've observed the following, which is kind of confusing. When I load a flat page in my browser then change it through admin and then do a refresh (within the cache timeout) there is no change in the page--as expected. However when I stat a new session in a different browser and load the page (still within the timeout) the app is hit instead of the cache, with the Isn't the cache key generated from the URL? it seems that the session state is getting in there somewhere, which is causing a cache miss. Any ideas? thanks MIDDLEWARE_CLASSES = ( 'django.middleware.cache.UpdateCacheMiddleware', 'django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.middleware.gzip.GZipMiddleware', 'django.middleware.http.ConditionalGetMiddleware', 'django.middleware.doc.XViewMiddleware', 'ittybitty.middleware.IttyBittyURLMiddleware', 'django.contrib.flatpages.middleware.FlatpageFallbackMiddleware', 'maintenancemode.middleware.MaintenanceModeMiddleware', 'djangodblog.middleware.DBLogMiddleware', 'SSL.middleware.SSLRedirect', #SSL middleware to handle SSL 'django.middleware.cache.FetchFromCacheMiddleware', )

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  • Problems with South/Django: not recognizing the Django App

    - by christmasgorilla
    I've got a Django project on my machine and when I try to use South to migrate the data schema, I get several odd errors. Example: $ python manage.py convert_to_south thisLocator /Library/Python/2.6/site-packages/registration/models.py:4: DeprecationWarning: the sha module is deprecated; use the hashlib module instead import sha /Users/cm/code/thisLocator/../thisLocator/batches/models.py:6: DeprecationWarning: the md5 module is deprecated; use hashlib instead import md5 There is no enabled application matching 'thisLocator'. I've followed the South documentation. Settings.py has it in the installed apps, I can run import south from the manage.py shell. Everyone else on my team is calling the app thisLocator. Am I doing something really stupid?

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  • Django comparing model instances for equality

    - by orokusaki
    I understand that, with a singleton situation, you can perform such an operation as: spam == eggs and if spam and eggs are instances of the same class with all the same attribute values, it will return True. In a Django model, this is natural because two separate instances of a model won't ever be the same unless they have the same .pk value. The problem with this is that if a reference to an instance has attributes that have been updated by middleware somewhere along the way and it hasn't been saved, and you're trying to it to another variable holding a reference to an instance of the same model, it will return False of course because they have different values for some of the attributes. Obviously I don't need something like a singleton , but I'm wondering if there some official Djangonic (ha, a new word) method for checking this, or if I should simply check that the .pk value is the same with: spam.pk == eggs.pk I'm sorry if this was a huge waste of time, but it just seems like there might be a method for doing this, and something I'm missing that I'll regret down the road if I don't find it.

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  • django admin gives warning "Field 'X' doesn't have a default value"

    - by noam
    I have created two models out of an existing legacy DB , one for articles and one for tags that one can associate with articles: class Article(models.Model): article_id = models.AutoField(primary_key=True) text = models.CharField(max_length=400) class Meta: db_table = u'articles' class Tag(models.Model): tag_id = models.AutoField(primary_key=True) tag = models.CharField(max_length=20) article=models.ForeignKey(Article) class Meta: db_table = u'article_tags' I want to enable adding tags for an article from the admin interface, so my admin.py file looks like this: from models import Article,Tag from django.contrib import admin class TagInline(admin.StackedInline): model = Tag class ArticleAdmin(admin.ModelAdmin): inlines = [TagInline] admin.site.register(Article,ArticleAdmin) The interface looks fine, but when I try to save, I get: Warning at /admin/webserver/article/382/ Field 'tag_id' doesn't have a default value

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  • I keep Getting KeyError: 'tried' Whenever I Tried to Run Django Dev Server from Remote Machine

    - by Spikie
    I am running django on python2.6.1, and did start the django web server like this manage.py runserver 192.0.0.1:8000 then tried to connect to the django dev web server on http://192.0.0.1:8000/ keep getting this message on the remote computer Traceback (most recent call last): File "C:\Python26\Lib\site-packages\django\core\servers\basehttp.py", line 279, in run self.result = application(self.environ, self.start_response) File "C:\Python26\Lib\site-packages\django\core\servers\basehttp.py", line 651, in call return self.application(environ, start_response) File "C:\Python26\lib\site-packages\django\core\handlers\wsgi.py", line 241, in call response = self.get_response(request) File "C:\Python26\lib\site-packages\django\core\handlers\base.py", line 115, in get_response return debug.technical_404_response(request, e) File "C:\Python26\Lib\site-packages\django\views\debug.py", line 247, in technical_404_response tried = exception.args[0]['tried'] KeyError: 'tried' what i am doing wrong ? it seen to work ok if i run http://192.0.0.1:8000/ on the computer that runs the Django web server and have that ip 192.0.0.1:8000

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  • Testing a Django view cause "AttributeError: 'NoneType' object has no attribute 'handler500'" error

    - by jack
    I just wanted to start testing a Django view using the code below: from django.test.client import Client c = Client() response = c.get('/search/keyword') print response.content It just throws out following error message: "/usr/local/lib/python2.6/dist-packages/django/test/client.py", line 286, in get response = self.request(**r) File "/usr/local/lib/python2.6/dist-packages/django/test/client.py", line 230, in request response = self.handler(environ) File "/usr/local/lib/python2.6/dist-packages/django/test/client.py", line 74, in __call__ response = self.get_response(request) File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/base.py", line 143, in get_response return self.handle_uncaught_exception(request, resolver, exc_info) File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/base.py", line 178, in handle_uncaught_exception callback, param_dict = resolver.resolve500() File "/usr/local/lib/python2.6/dist-packages/django/core/urlresolvers.py", line 268, in resolve500 return self._resolve_special('500') File "/usr/local/lib/python2.6/dist-packages/django/core/urlresolvers.py", line 258, in _resolve_special callback = getattr(self.urlconf_module, 'handler%s' % view_type) AttributeError: 'NoneType' object has no attribute 'handler500' The view works in browser. What's wrong with above code?

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  • How to limit choice field options based on another choice field in django admin

    - by umnik700
    I have the following models: class Category(models.Model): name = models.CharField(max_length=40) class Item(models.Model): name = models.CharField(max_length=40) category = models.ForeignKey(Category) class Demo(models.Model): name = models.CharField(max_length=40) category = models.ForeignKey(Category) item = models.ForeignKey(Item) In the admin interface when creating a new Demo, after user picks category from the dropdown, I would like to limit the number of choices in the "items" drop-down. If user selects another category then the item choices should update accordingly. I would like to limit item choices right on the client, before it even hits the form validation on the server. This is for usability, because the list of items could be 1000+ being able to narrow it down by category would help to make it more manageable. Is there a "django-way" of doing it or is custom JavaScript the only option here?

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  • Edit the opposite side of a many to many relationship with django generic form

    - by Ed
    I have two models: class Actor(models.Model): name = models.CharField(max_length=30, unique = True) event = models.ManyToManyField(Event, blank=True, null=True) class Event(models.Model): name = models.CharField(max_length=30, unique = True) long_description = models.TextField(blank=True, null=True) In a previous question: http://stackoverflow.com/questions/2503243/django-form-linking-2-models-by-many-to-many-field, I created an EventForm with a save function: class EventForm(forms.ModelForm): class Meta: model = Event def save(self, commit=True): instance = forms.ModelForm.save(self) instance.actors_set.clear() for actor in self.cleaned_data['actors']: instance.actors_set.add(actors) return instance This allowed me to add m2m links from the other side of the defined m2m connection. Now I want to edit the entry. I've been using a generic function: def generic_edit(request, modelname, object_id): modelname = modelname.lower() form_class = form_dict[modelname] return update_object(request, form_class = form_class, object_id = object_id, template_name = 'createdit.html' ) but this pulls in all the info except the many-to-many selections saved to this object. I think I need to do something similar to this: http://stackoverflow.com/questions/1700202/editing-both-sides-of-m2m-in-admin-page, but I haven't figured it out. How do I use the generic update_object to edit the other side of many-to-many link?

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  • How do I find the "concrete class" of a django model baseclass

    - by Mr Shark
    I'm trying to find the actual class of a django-model object, when using model-inheritance. Some code to describe the problem: class Base(models.model): def basemethod(self): ... class Child_1(Base): pass class Child_2(Base): pass If I create various objects of the two Child classes and the create a queryset containing them all: Child_1().save() Child_2().save() (o1, o2) = Base.objects.all() I want to determine if the object is of type Child_1 or Child_2 in basemethod, I can get to the child object via o1.child_1 and o2.child_2 but that reconquers knowledge about the childclasses in the baseclass. I have come up with the following code: def concrete_instance(self): instance = None for subclass in self._meta.get_all_related_objects(): acc_name = subclass.get_accessor_name() try: instance = self.__getattribute__(acc_name) return instance except Exception, e: pass But it feels brittle and I'm not sure of what happens when if I inherit in more levels.

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  • how to change display text in django admin foreignkey dropdown

    - by FurtiveFelon
    Hi all, I have a task list, with ability to assign users. So i have foreignkey to User model in the database. However, the default display is username in the dropdown menu, i would like to display full name (first last) instead of the username. If the foreignkey is pointing to one of my own classes, i can just change the str function in the model, but User is a django authentication model, so i can't easily change it directly right? Anyone have any idea how to accomplish this? Thanks a lot!

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  • Django QuerySet ordering by expression

    - by Andrew
    How can i use order_by like order_by('field1'*'field2') For example i have items with price listed in different currencies, so to order items - i have to make currency conversion. class Currency(models.Model): code = models.CharField(max_length=3, primary_key=True) rateToUSD = models.DecimalField(max_digits=20,decimal_places=10) class Item(models.Model): priceRT = models.DecimalField(max_digits=15, decimal_places=2, default=0) cur = models.ForeignKey(Currency) I would like to have something like: Item.objects.all().order_by(F('priceRT')*F('cur__rateToUSD')) But unfortunately it doesnt work, i also faild with annotate. How can i permorm QuerySet ordering by result of value multiplication of 2 model's fields.

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  • Django get_FOO_display and distinct()

    - by datakid
    I've seen answers to both halves of my question, but I can't work out how to marry the two. I have a book model, and a translatedBook model. The translatedBook has a langage set up as model choices in the usual way: LANGUAGES = ( (u'it', u'Italian'), (u'ja', u'Japanese'), (u'es', u'Spanish'), (u'zh-cn', u'Simplified Chinese'), (u'zh-tw', u'Traditional Chinese'), (u'fr', u'French'), (u'el', u'Greek'), (u'ar', u'Arabic'), (u'bg', u'Bulgarian'), (u'bn', u'Bengali'), etc I know that to get "Italian" I have to do translatedBook.get_language_display on a Book object. But how do I get a list of distinct languages in their long format? I've tried: lang_avail = TargetText.objects.values('language').distinct().order_by('language') lang_avail = TargetText.objects.distinct().order_by('language').values('language'). lang_avail = TargetText.objects.all().distinct('language').order_by('language') but I can't seem to get what I want - which is a list like: "English, Italian, Simplified Chinese, Spanish" The final lang_avail listed above didn't return the list of 5, it returned the list of 355 (ie, # of books) with multiple repeats....

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  • django related_name for field clashes.

    - by Absolute0
    I am getting a field clash in my models: class Visit(models.Model): user = models.ForeignKey(User) visitor = models.ForeignKey(User) Error: One or more models did not validate: profiles.visit: Accessor for field 'user' clashes with related field 'User.visit_set'. Add a related_name argument to the definition for 'user'. profiles.visit: Accessor for field 'visitor' clashes with related field 'User.visit_set'. Add a related_name argument to the definition for 'visitor'. what would be a sensible 'related_field' to use on visitor field? This model basically represents the visits that take place to a particular user's profile. Also should I replace any of the ForeignKey's with a ManyToManyField? The logic is a bit confusing. Edit: This seems to fix it, but I am unsure if its what I want. :) class Visit(models.Model): user = models.ForeignKey(User) visitor = models.ForeignKey(User, related_name='visitors')

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  • Django finding which field matched in a multiple OR query

    - by Greg Hinch
    I've got a couple models which are set up something like this: class Bar(models.Model): baz = models.CharField() class Foo(models.Model): bar1 = models.ForeignKey(Bar) bar2 = models.ForeignKey(Bar) bar3 = models.ForeignKey(Bar) And elsewhere in the code, I end up with an instance of Bar, and need to find the Foo it is attached to in some capacity. Right now I came up with doing a multiple OR query using Q, something like this: foo_inst = Foo.objects.get(Q(bar1=bar_inst) | Q(bar2=bar_inst) | Q(bar3=bar_inst)) What I need to figure out is, which of the 3 cases actually hit, at least the name of the member (bar1, bar2, or bar3). Is there a good way to do this? Is there a better way to structure the query to glean that information?

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