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  • Cocoa equivalent of the Carbon method getPtrSize

    - by Michael Minerva
    I need to translate the a carbon method into cocoa into and I am having trouble finding any documentation about what the carbon method getPtrSize really does. From the code I am translating it seems that it returns the byte representation of an image but that doesn't really match up with the name. Could someone give me a good explanation of this method or link me to some documentation that describes it. The code I am translating is in a common lisp implementation called MCL that has a bridge to carbon (I am translating into CCL which is a common lisp implementation with a Cocoa bridge). Here is the MCL code (#_before a method call means that it is a carbon method): (defmethod COPY-CONTENT-INTO ((Source inflatable-icon) (Destination inflatable-icon)) ;; check for size compatibility to avoid disaster (unless (and (= (rows Source) (rows Destination)) (= (columns Source) (columns Destination)) (= (#_getPtrSize (image Source)) (#_getPtrSize (image Destination)))) (error "cannot copy content of source into destination inflatable icon: incompatible sizes")) ;; given that they are the same size only copy content (setf (is-upright Destination) (is-upright Source)) (setf (height Destination) (height Source)) (setf (dz Destination) (dz Source)) (setf (surfaces Destination) (surfaces Source)) (setf (distance Destination) (distance Source)) ;; arrays (noise-map Source) ;; accessor makes array if needed (noise-map Destination) ;; ;; accessor makes array if needed (dotimes (Row (rows Source)) (dotimes (Column (columns Source)) (setf (aref (noise-map Destination) Row Column) (aref (noise-map Source) Row Column)) (setf (aref (altitudes Destination) Row Column) (aref (altitudes Source) Row Column)))) (setf (connectors Destination) (mapcar #'copy-instance (connectors Source))) (setf (visible-alpha-threshold Destination) (visible-alpha-threshold Source)) ;; copy Image: slow byte copy (dotimes (I (#_getPtrSize (image Source))) (%put-byte (image Destination) (%get-byte (image Source) i) i)) ;; flat texture optimization: do not copy texture-id -> destination should get its own texture id from OpenGL (setf (is-flat Destination) (is-flat Source)) ;; do not compile flat textures: the display list overhead slows things down by about 2x (setf (auto-compile Destination) (not (is-flat Source))) ;; to make change visible we have to reset the compiled flag (setf (is-compiled Destination) nil))

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  • Jquery image preview plugin issue...

    - by Pandiya Chendur
    I have a problem with an image preview that comes up when you hover over a thumbnail. I can change the distance between the preview and the cursor, but if a thumbnail is close to the side of the window, the preview cant fit and you only see part of it.. hope that makes sense... is there a way to make it so that if the preview doesnt fit, it will show up on the other side of the cursor?.... Here is the script... this.imagePreview = function() { /* CONFIG */ xOffset = 10; yOffset = 30; // these 2 variable determine popup's distance from the cursor // you might want to adjust to get the right result /* END CONFIG */ $("a.preview").hover(function(e) { this.t = this.title; this.title = ""; var c = (this.t != "") ? "<br/>" + this.t : ""; $("body").append("<p id='preview'> <img src='" + this.href + "' alt='Image preview' />" + c + "</p>"); $("#preview") .css("top", (e.pageY - xOffset) + "px") .css("left", (e.pageX + yOffset) + "px") .fadeIn("slow"); }, function() { this.title = this.t; $("#preview").remove(); }); $("a.preview").mousemove(function(e) { $("#preview") .css("top", (e.pageY - xOffset) + "px") .css("left", (e.pageX + yOffset) + "px"); }); }; // starting the script on page load $(document).ready(function() { imagePreview(); }); EDIT: see what i am getting, http://img202.imageshack.us/img202/4991/browserpreviewf.jpg my image at the right corner of the page so when i hover the img my preview goes even further right that is besides the page scrollbar half the preview is available.... How to get the preview to the left of the cursor..

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  • Pass table as parameter to SQLCLR TV-UDF

    - by Skeolan
    We have a third-party DLL that can operate on a DataTable of source information and generate some useful values, and we're trying to hook it up through SQLCLR to be callable as a table-valued UDF in SQL Server 2008. Taking the concept here one step further, I would like to program a CLR Table-Valued Function that operates on a table of source data from the DB. I'm pretty sure I understand what needs to happen on the T-SQL side of things; but, what should the method signature look like in the .NET (C#) code? What would be the parameter datatype for "table data from SQL Server?" e.g. /* Setup */ CREATE TYPE InTableType AS TABLE (LocationName VARCHAR(50), Lat FLOAT, Lon FLOAT) GO CREATE TYPE OutTableType AS TABLE (LocationName VARCHAR(50), NeighborName VARCHAR(50), Distance FLOAT) GO CREATE ASSEMBLY myCLRAssembly FROM 'D:\assemblies\myCLR_UDFs.dll' WITH PERMISSION_SET = EXTERNAL_ACCESS GO CREATE FUNCTION GetDistances(@locations InTableType) RETURNS OutTableType AS EXTERNAL NAME myCLRAssembly.GeoDistance.SQLCLRInitMethod GO /* Execution */ DECLARE @myTable InTableType INSERT INTO @myTable(LocationName, Lat, Lon) VALUES('aaa', -50.0, -20.0) INSERT INTO @myTable(LocationName, Lat, Lon) VALUES('bbb', -20.0, -50.0) SELECT * FROM @myTable DECLARE @myResult OutTableType INSERT INTO @myResult MyCLRTVFunction @myTable --returns a table result calculated using the input The lat/lon - distance thing is a silly example that should of course be better handled entirely in SQL; but I hope it illustrates the general intent of table-in - table-out through a table-valued UDF tied to a SQLCLR assembly. I am not certain this is possible; what would the SQLCLRInitMethod method signature look like in the C#? public class GeoDistance { [SqlFunction(FillRowMethodName = "FillRow")] public static IEnumerable SQLCLRInitMethod(<appropriateType> myInputData) { //... } public static void FillRow(...) { //... } } If it's not possible, I know I can use a "context connection=true" SQL connection within the C# code to have the CLR component query for the necessary data given the relevant keys; but that's sensitive to changes in the DB schema. So I hope to just have SQL bundle up all the source data and pass it to the function. Bonus question - assuming this works at all, would it also work with more than one input table?

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  • Beginner problems with references to arrays in python 3.1.1

    - by Protean
    As part of the last assignment in a beginner python programing class, I have been assigned a traveling sales man problem. I settled on a recursive function to find each permutation and the sum of the distances between the destinations, however, I am have a lot of problems with references. Arrays in different instances of the Permute and Main functions of TSP seem to be pointing to the same reference. from math import sqrt class TSP: def __init__(self): self.CartisianCoordinates = [['A',[1,1]], ['B',[2,2]], ['C',[2,1]], ['D',[1,2]], ['E',[3,3]]] self.Array = [] self.Max = 0 self.StoredList = ['',0] def Distance(self, i1, i2): x1 = self.CartisianCoordinates[i1][1][0] y1 = self.CartisianCoordinates[i1][1][1] x2 = self.CartisianCoordinates[i2][1][0] y2 = self.CartisianCoordinates[i2][1][1] return sqrt(pow((x2 - x1), 2) + pow((y2 - y1), 2)) def Evaluate(self): temparray = [] Data = [] for i in range(len(self.CartisianCoordinates)): Data.append([]) for i1 in range(len(self.CartisianCoordinates)): for i2 in range(len(self.CartisianCoordinates)): if i1 != i2: temparray.append(self.Distance(i1, i2)) else: temparray.append('X') Data[i1] = temparray temparray = [] self.Array = Data self.Max = len(Data) def Permute(self,varray,index,vcarry,mcarry): #Problem Class array = varray[:] carry = vcarry[:] for i in range(self.Max): print ('ARRAY:', array) print (index,i,carry,array[index][i]) if array[index][i] != 'X': carry[0] += self.CartisianCoordinates[i][0] carry[1] += array[index][i] if len(carry) != self.Max: temparray = array[:] for j in range(self.Max):temparray[j][i] = 'X' index = i mcarry += self.Permute(temparray,index,carry,mcarry) else: return mcarry print ('pass',mcarry) return mcarry def Main(self): out = [] self.Evaluate() for i in range(self.Max): array = self.Array[:] #array appears to maintain the same reference after each copy, resulting in an incorrect array being passed to Permute after the first iteration. print (self.Array[:]) for j in range(self.Max):array[j][i] = 'X' print('I:', i, array) out.append(self.Permute(array,i,[str(self.CartisianCoordinates[i][0]),0],[])) return out SalesPerson = TSP() print(SalesPerson.Main()) It would be greatly appreciated if you could provide me with help in solving the reference problems I am having. Thank you.

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  • Pass data from one form to another on a seperate page

    - by Micanio
    I am building a price/distance calculator with Google Maps API and am trying to pass the info from the calculator to a booking form on a separate page. My first form has 2 submit buttons - one to make the calculation, and one to submit the relevant data to the booking form. I'm stuck trying to make the 2nd button work. Once the API calculation has been made, I get 4 values - From, To, Cost, Distance. I am trying to pass the From, To and Cost values into my booking form by clicking the second button. But I can;t seem to get it to work. I've tried POST and GET but I think I may have been doing something wrong with both. Any help is appreciated. Code for API form: <script type="text/javascript" src="http://maps.google.com/maps?file=api&amp;v=2&amp;key=ABQIAAAAwCUxKrPl8_9WadET5dc4KxTqOwVK5HCwTKtW27PjzpqojXnJORQ2kUsdCksByD4hzcGXiOxvn6C4cw&sensor=true"></script> <script type="text/javascript"> var geocoder = null; var location1 = null; var location2 = null; var gDir = null; var directions = null; var total = 0; function roundNumber(num, dec) { var result = Math.floor(num*Math.pow(10 ,dec))/Math.pow(10,dec); return result; } function from(form) { address1=form.start.options[form.start.selectedIndex].value form.address1.value=address1 form.address1.focus() } function to(form) { address2=form.end.options[form.end.selectedIndex].value form.address2.value=address2 form.address2.focus() } function initialize() { var map = new GMap2(document.getElementById("map_canvas")); map.setCenter(new GLatLng(54.019066,-1.381531),9); map.setMapType(G_NORMAL_MAP); geocoder = new GClientGeocoder(); gDir = new GDirections(map); GEvent.addListener(gDir, "load", function() { var drivingDistanceMiles = gDir.getDistance().meters / 1609.344; var drivingDistanceKilometers = gDir.getDistance().meters / 1000; var miles = drivingDistanceMiles.toFixed(0); //var cost = (((miles - 1) * 1.9) + 3.6).toFixed(2); var meters = gDir.getDistance().meters.toFixed(1); if(miles < 70){ var cost = miles *1.75; } if(miles >70){ var cost = miles *1.2; } document.getElementById('from').innerHTML = '<strong>From: </strong>' + location1.address; document.getElementById('to').innerHTML = '<strong>To: </strong>' + location2.address; document.getElementById('cost').innerHTML = '<span class="fare"><strong>Estimated Taxi FARE:</strong>' + ' £' + cost.toFixed(2) + '</span>'; document.getElementById('miles').innerHTML = '<strong>Distance: </strong>' + miles + ' Miles'; }); } function showLocation() // start of possible values for address not recognized on google search // values for address1 { if (document.forms[0].address1.value == "heathrow" || document.forms[0].address1.value == "Heathrow" || document.forms[0].address1.value == "heathrow airport" || document.forms[0].address1.value == "Heathrow Airport" || document.forms[0].address1.value == "London Heathrow" || document.forms[0].address1.value =="london heathrow" ) { (document.forms[0].address1.value = "Heathrow Airport"); } if (document.forms[0].address2.value == "heathrow" || document.forms[0].address2.value == "Heathrow" || document.forms[0].address2.value == "heathrow airport" || document.forms[0].address2.value == "Heathrow Airport" || document.forms[0].address2.value == "London Heathrow" || document.forms[0].address2.value =="london heathrow" ) { (document.forms[0].address2.value = "Heathrow Airport"); } geocoder.getLocations(document.forms[0].address1.value + document.forms[0].uk.value || document.forms[0].start.value + document.forms[0].uk.value, function (response) { if (!response || response.Status.code != 200) { alert("Sorry, we were unable to find the first address"); } else { location1 = {lat: response.Placemark[0].Point.coordinates[1], lon: response.Placemark[0].Point.coordinates[0], address: response.Placemark[0].address}; geocoder.getLocations(document.forms[0].address2.value + document.forms[0].uk.value, function (response) { if (!response || response.Status.code != 200) { alert("Sorry, we were unable to find the second address"); } else { location2 = {lat: response.Placemark[0].Point.coordinates[1], lon: response.Placemark[0].Point.coordinates[0], address: response.Placemark[0].address}; gDir.load('from: ' + location1.address + ' to: ' + location2.address); } }); } }); } </script> <style> #quote { font-family: Georgia, "Times New Roman", Times, serif; } </style> </head> <body style="background-color: rgb(255, 255, 255);" onUnload="GUnload()" onLoad="initialize()"> <div id="sidebar"> <!--MAPS--> <div id="calc_top"></div> <div id="calc_body"> <div id="calc_inside"> <span style="font-size: 16px; font-weight: bold;">Get A Quote Now</span> <p class="disclaimer">Fares can be calculated using either Area, Exact Address or Postcode, when entering address please include both road name and area i.e. <em>Harrogate Road, Ripon</em>. You can also select a pickup point and destination from the dropdown boxes. </p> <form onSubmit="showLocation(); return false;" action="#" id="booking_form"> <p> <select onChange="from(this.form)" name="start"> <option selected="selected">Select a Pickup Point</option> <option value="Leeds Bradford Airport">Leeds Bradford Airport</option> <option value="Manchester Airport">Manchester Airport</option> <option value="Teesside International Airport">Teeside Airport</option> <option value="Liverpool John Lennon Airport">Liverpool Airport</option> <option value="East Midlands Airport">East Midlands Airport</option> <option value="Heathrow International Airport">Heathrow Airport</option> <option value="Gatwick Airport">Gatwick Airport</option> <option value="Stanstead Airport">Stanstead Airport</option> <option value="Luton International Airport">Luton Airport</option> </select> </p> <p> <input type="text" value="From" name="address1"><br> <p> <select onChange="to(this.form)" name="end"> <option selected="selected">Select a Destination</option> <option value="Leeds Bradford Airport">Leeds Bradford Airport</option> <option value="Manchester Airport">Manchester Airport</option> <option value="Teesside International Airport">Teeside Airport</option> <option value="Liverpool John Lennon Airport">Liverpool Airport</option> <option value="East Midlands Airport">East Midlands Airport</option> <option value="Heathrow International Airport">Heathrow Airport</option> <option value="Gatwick Airport">Gatwick Airport</option> <option value="Stanstead Airport">Stanstead Airport</option> <option value="Luton International Airport">Luton Airport</option> </select> </p> <input type="text" value="To" name="address2"><br> <input type="hidden" value=" uk" name="uk"> <br> <input type="submit" value="Get Quote"> <input type="button" value="Reset" onClick="resetpage()"><br /><br /> <input type="submit" id="CBSubmit" value="Confirm and Book" action=""/> </p> </form> <p id="from"><strong>From:</strong></p> <p id="to"><strong>To:</strong></p> <p id="miles"><strong>Distance: </strong></p> <p id="cost"><span class="fare"><strong>Estimated Taxi FARE:</strong></span></p> <p id="results"></p> <div class="style4" style="width: 500px; height: 500px; position: relative; background-color: rgb(229, 227, 223);" id="map_canvas"></div> </div> </div> Code for Booking Form: <form method="post" action="contactengine.php" id="contact_form"> <p> <label for="Name" id="Name">Name:</label> <input type="text" name="Name" /> <label for="Email" id="Email">Email:</label> <input type="text" name="Email" /> <label for="tel" id="tel">Tel No:</label> <input type="text" name="tel" /><br /><br /> <label for="from" id="from">Pickup Point:</label> <input type="text" name="from" value="" /><br /><br /> <label for="to" id="to">Destination:</label> <input type="text" name="to" value=""/><br /> <label for="passengers" id="passengers">No. of passengers</label> <input type="text" name="passengers" /><br /><br /> <label for="quote" id="quote">Price of journey:</label> <input type="text" name="quote" value="" /><br /><br /> <label for="Message" id="Message">Any other info:</label> <textarea name="Message" rows="20" cols="40"></textarea> <br /> Are you an account holder?<br /> <label for="account" id="yes" /> Yes:</label> <input type="radio" class="radio" value="yes" name="account"> <label for="account" id="yes" /> No:</label> <input type="radio" class="radio" value="no" name="account"> </p> <small>Non-account holders will have to pay a £5 booking fee when confirming thier booking</small> <input type="submit" name="submit" value="Submit" class="submit-button" /> </p> </form> Thanks in advance

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  • How to find minimum cut-sets for several subgraphs of a graph of degrees 2 to 4

    - by Tore
    I have a problem, Im trying to make A* searches through a grid based game like pacman or sokoban, but i need to find "enclosures". What do i mean by enclosures? subgraphs with as few cut edges as possible given a maximum size and minimum size for number of vertices that act as soft constraints. Alternatively you could say i am looking to find bridges between subgraphs, but its generally the same problem. Given a game that looks like this, what i want to do is find enclosures so that i can properly find entrances to them and thus get a good heuristic for reaching vertices inside these enclosures. So what i want is to find these colored regions on any given map. The reason for me bothering to do this and not just staying content with the performance of a simple manhattan distance heuristic is that an enclosure heuristic can give more optimal results and i would not have to actually do the A* to get some proper distance calculations and also for later adding competitive blocking of opponents within these enclosures when playing sokoban type games. Also the enclosure heuristic can be used for a minimax approach to finding goal vertices more properly. Do you know of a good algorithm for solving this problem or have any suggestions in things i should explore?

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  • Display object in just a certain viewport

    - by PSilo
    Hi I got 4 viewports and one large that I can switch between now I got an object namely the camera and the cameras target position that I show with rendering a sphere at those locations. I want to show the cameras position in 3 of my viewports but not in the last which is the camera display but at the moment I got an all or nothing scenario. void display(int what) { if(what==5){ glMatrixMode(GL_MODELVIEW); glLoadIdentity(); camControll();} if(what==1){ glMatrixMode(GL_MODELVIEW); glLoadIdentity(); gluLookAt(75,15,-5,0,5,-5,0,1,0);} if(what==2){ glMatrixMode(GL_MODELVIEW); glLoadIdentity(); gluLookAt(0,110,0,0,0,0,1,0,0);} if(what==3){ glMatrixMode(GL_PROJECTION); glLoadIdentity(); gluPerspective(45.0f, float(320) / float(240), 0.1f, 100.0f); glMatrixMode(GL_MODELVIEW); glLoadIdentity(); camControll();} if(what==4){ glMatrixMode(GL_MODELVIEW); glLoadIdentity(); gluLookAt(185,75,25,0,28,0,0,1,0);} //glMatrixMode(GL_MODELVIEW); //glLoadIdentity(); ////gluLookAt(cos(shared.time) * shared.distance, 10, sin(shared.time) * shared.distance, 0, 0, 0, 0, 1, 0); ////ca.orbitYaw(0.05); //ca.lookAt(); glClearColor(0, 0, 0, 1); glClear(GL_COLOR_BUFFER_BIT|GL_DEPTH_BUFFER_BIT); drawScene(); // scene that all views should render drawCamera(); / camera position that only certain views should render glutSwapBuffers(); } I'm thinking that perhaps I could do one sweep for first the 3 viewports and then call glutSwapBuffers() and then do the other viewport without the camera position but some stuttering I previously had was traced to glutSwapBuffers() being called for each viewport so I guess there has to be another way only that I cant figure it out.

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  • Ray Generation Inconsistency

    - by Myx
    I have written code that generates a ray from the "eye" of the camera to the viewing plane some distance away from the camera's eye: R3Ray ConstructRayThroughPixel(...) { R3Point p; double increments_x = (lr.X() - ul.X())/(double)width; double increments_y = (ul.Y() - lr.Y())/(double)height; p.SetX( ul.X() + ((double)i_pos+0.5)*increments_x ); p.SetY( lr.Y() + ((double)j_pos+0.5)*increments_y ); p.SetZ( lr.Z() ); R3Vector v = p-camera_pos; R3Ray new_ray(camera_pos,v); return new_ray; } ul is the upper left corner of the viewing plane and lr is the lower left corner of the viewing plane. They are defined as follows: R3Point org = scene->camera.eye + scene->camera.towards * radius; R3Vector dx = scene->camera.right * radius * tan(scene->camera.xfov); R3Vector dy = scene->camera.up * radius * tan(scene->camera.yfov); R3Point lr = org + dx - dy; R3Point ul = org - dx + dy; Here, org is the center of the viewing plane with radius being the distance between the viewing plane and the camera eye, dx and dy are the displacements in the x and y directions from the center of the viewing plane. The ConstructRayThroughPixel(...) function works perfectly for a camera whose eye is at (0,0,0). However, when the camera is at some different position, not all needed rays are produced for the image. Any suggestions what could be going wrong? Maybe something wrong with my equations? Thanks for the help.

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  • Java: Match tokens between two strings and return the number of matched tokens

    - by Cryssie
    Need some help to find the number of matched tokens between two strings. I have a list of string stored in ArrayList (example given below): Line 0 : WRB VBD NN VB IN CC RB VBP NNP Line 1 : WDT NNS VBD DT NN NNP NNP Line 2 : WRB MD PRP VB DT NN IN NNS POS JJ NNS Line 3 : WDT NN VBZ DT NN IN DT JJ NN IN DT NNP Line 4 : WP VBZ DT JJ NN IN NN Here, you can see each string consists of a bunch of tokens separated by spaces. So, there's three things I need to work with.. Compare the first token (WRB) in Line 0 to the tokens in Line 1 to see if they match. Move on to the next tokens in Line 0 until a match is found. If there's a match, mark the matched tokens in Line 1 so that it will not be matched again. Return the number of matched tokens between Line 0 and Line 1. Return the distance of the matched tokens. Example: token NN is found on position 3 on line 0 and position 5 on Line 1. Distance = |3-5| = 2 I've tried using split string and store it to String[] but String[] is fixed and doesn't allow shrinking or adding of new elements. Tried Pattern Matcher but with disasterous results. Tried a few other methods but there's some problems with my nested for loops..(will post part of my coding if it will help). Any advice or pointers on how to solve this problem this would be very much appreciated. Thank you very much.

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  • How is a relative JMP (x86) implemented in an Assembler?

    - by Pindatjuh
    While building my assembler for the x86 platform I encountered some problems with encoding the JMP instruction: enc inst size in bytes EB cb JMP rel8 2 E9 cw JMP rel16 4 (because of 0x66 16-bit prefix) E9 cd JMP rel32 5 ... (from my favourite x86 instruction website, http://siyobik.info/index.php?module=x86&id=147) All are relative jumps, where the size of each encoding (operation + operand) is in the third column. Now my original (and thus fault because of this) design reserved the maximum (5 bytes) space for each instruction. The operand is not yet known, because it's a jump to a yet unknown location. So I've implemented a "rewrite" mechanism, that rewrites the operands in the correct location in memory, if the location of the jump is known, and fills the rest with NOPs. This is a somewhat serious concern in tight-loops. Now my problem is with the following situation: b: XXX c: JMP a e: XXX ... XXX d: JMP b a: XXX (where XXX is any instruction, depending on the to-be assembled program) The problem is that I want the smallest possible encoding for a JMP instruction (and no NOP filling). I have to know the size of the instruction at c before I can calculate the relative distance between a and b for the operand at d. The same applies for the JMP at c: it needs to know the size of d before it can calculate the relative distance between e and a. How do existing assemblers implement this, or how would you implement this? This is what I am thinking which solves the problem: First encode all the instructions to opcodes between the JMP and it's target, and if this region contains a variable-sized opcode, use the maximum size, i.e. 5 for JMP. Then in some conditions, the JMP is oversized (because it may fit in a smaller encoding): so another pass will search for oversized JMPs, shrink them, and move all instructions ahead), and set absolute branching instructions (i.e. external CALLs) after this pass is completed. I wonder, perhaps this is an over-engineered solution, that's why I ask this question.

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  • Using JQuery to insert new cells in a table row?

    - by Michael Smith
    I know that JQuery is a very powerful library and was just wondering if it had the following capability that I really need. Lets say I need to insert new cells into a table row, I know how to do this basic task, but I need to insert my cells in a highly unusual way due to some of the requirements that are needed for the new cells. I need to be able to insert cells a certain distance into the row, For example, if a row was 1000pixels wide, is there a feature in JQuery that would allow me to insert the cell 250pixels into the row and have a cell width of 50pixels and insert another cell 500pixels into the row with a cell width of 100pixels. I know how to set a cells width using JQuery, just not distance into a row. The values wont ever be the exact same as above though because they are actually read from a database, so for example, one cell would have the following values: CELL_01 $start=100; $finish=150; the above would mean a new cell is needed that needs to be inserted 100pixels into the row and has a width of 50pixels, I just cant seem to find a way to implement this feature into my application. How could I accomplish this task? Sorry for such a strange question, but i just cant seem to get this working. Thanks!

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  • JAVA Casting error

    - by user1612725
    Im creating a program that uses Dijksrtras algorithm, im using nodes that represent cities on an imported map, and you can create edges between two cities on the map. My problem is every edge has a "weight" where it will represent distance in minutes and i have a function where i want to see the distance between the two edges. But i keep getting the error "Cannot cast from Stad to Edge" at the line Edge<Stad> selectedEdge = (Edge) fvf.visaFörbLista.getSelectedValue(); where "Stad" represents the city and "Edge" an edge. FormVisaförbindelse fvf = new FormVisaförbindelse(); for(;;){ try{ int svar = showConfirmDialog(null, fvf, "Ändra Förbindelser", JOptionPane.OK_CANCEL_OPTION); if (svar != YES_OPTION) return; if (fvf.visaFörbLista.isSelectionEmpty() == true){ showMessageDialog(mainMethod.this, "En Förbindelse måste valjas.","Fel!", ERROR_MESSAGE); return; } Edge<Stad> selectedEdge = (Edge) fvf.visaFörbLista.getSelectedValue(); FormÄndraförbindelse faf = new FormÄndraförbindelse(); faf.setförbNamn(selectedEdge.getNamn()); for(;;){ try{ int svar2 = showConfirmDialog(mainMethod.this, faf, "Ändra Förbindelse", OK_CANCEL_OPTION); if (svar2 != YES_OPTION) return; selectedEdge.setVikt(faf.getförbTid()); List<Edge<Stad>> edges = lg.getEdgesBetween(sB, sA); for (Edge<Stad> edge : edges){ if (edge.getNamn()==selectedEdge.getNamn()){ edge.setVikt(faf.getförbTid()); } } return; } catch(NumberFormatException e){ showMessageDialog(mainMethod.this, "Ogiltig inmatning.","Fel!", ERROR_MESSAGE); }

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  • Recursion Problems in Prolog

    - by Humble_Student
    I'm having some difficulties in prolog, I'm trying to write a predicate that will return all paths between two cities, although at the moment it returns the first path it finds on an infinite loop. Not sure where I'm going wrong but I've been trying to figure this out all day and I'm getting nowhere. Any help that could be offered would be appreciated. go:- repeat, f([],0,lon,spa,OP,OD), write(OP), write(OD), fail. city(lon). city(ath). city(spa). city(kol). path(lon,1,ath). path(ath,3,spa). path(spa,2,kol). path(lon,1,kol). joined(X,Y,D):- path(X,D,Y);path(Y,D,X). f(Ci_Vi,Di,De,De,PaO,Di):- append([De],Ci_Vi,PaO), !. f(Cities_Visited,Distance,Start,Destination,Output_Path,Output_Distance):- repeat, city(X), joined(Start,X,D), not_member(X,Cities_Visited), New_Distance is Distance + D, f([Start|Cities_Visited],New_Distance,X,Destination,Output_Path,Output_Distance). not_member(X,List):- member(X,List), !, fail. not_member(X,List). The output I'm expecting here is [spa,ath,lon]4 [spa,kol,lon]3. Once again, any help would be appreciated. Many thanks in advance.

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  • How should I generate the partitions / pairs for the Chinese Postman problem?

    - by Simucal
    I'm working on a program for class that involves solving the Chinese Postman problem. Our assignment only requires us to write a program to solve it for a hard-coded graph but I'm attempting to solve it for the general case on my own. The part that is giving me trouble is generating the partitions of pairings for the odd vertices. For example, if I had the following labeled odd verticies in a graph: 1 2 3 4 5 6 I need to find all the possible pairings / partitions I can make with these vertices. I've figured out I'll have i paritions given: n = num of odd verticies k = n / 2 i = ((2k)(2k-1)(2k-2)...(k+1))/2 So, given the 6 odd verticies above, we will know that we need to generate i = 15 partitions. The 15 partions would look like: 1 2 3 4 5 6 1 2 3 5 4 6 1 2 3 6 4 5 ... 1 6 ... Then, for each partition, I take each pair and find the shortest distance between them and sum them for that partition. The partition with the total smallest distance between its pairs is selected, and I then double all the edges between the shortest path between the odd vertices (found in the selected partition). These represent the edges the postman will have to walk twice. At first I thought I had worked out an appropriate algorithm for generating these partitions / pairs but it is flawed. I found it wasn't a simple permutation/combination problem. Does anyone who has studied this problem before have any tips that can help point me in the right direction for generating these partitions?

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  • postgres - ERROR: operator does not exist

    - by cino21122
    Again, I have a function that works fine locally, but moving it online yields a big fat error... Taking a cue from a response in which someone had pointed out the number of arguments I was passing wasn't accurate, I double-checked in this situation to be certain that I am passing 5 arguments to the function itself... Query failed: ERROR: operator does not exist: point <@> point HINT: No operator matches the given name and argument type(s). You may need to add explicit type casts. The query is this: BEGIN; SELECT zip_proximity_sum('zc', (SELECT g.lat FROM geocoded g LEFT JOIN masterfile m ON g.recordid = m.id WHERE m.zip = '10050' ORDER BY m.id LIMIT 1), (SELECT g.lon FROM geocoded g LEFT JOIN masterfile m ON g.recordid = m.id WHERE m.zip = '10050' ORDER BY m.id LIMIT 1), (SELECT m.zip FROM geocoded g LEFT JOIN masterfile m ON g.recordid = m.id WHERE m.zip = '10050' ORDER BY m.id LIMIT 1) ,10); The PG function is this: CREATE OR REPLACE FUNCTION zip_proximity_sum(refcursor, numeric, numeric, character, numeric) RETURNS refcursor AS $BODY$ BEGIN OPEN $1 FOR SELECT r.zip, point($2,$3) <@> point(g.lat, g.lon) AS distance FROM geocoded g LEFT JOIN masterfile r ON g.recordid = r.id WHERE (geo_distance( point($2,$3),point(g.lat,g.lon)) < $5) ORDER BY r.zip, distance; RETURN $1; END; $BODY$ LANGUAGE 'plpgsql' VOLATILE COST 100;

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  • diffuculty in appending images dynamically in an Custom List View

    - by ganesh
    Hi I have written an custom List view which binds images according to the result from a feed @Override public View getView(int position, View convertView, ViewGroup parent) { ViewHolder holder; if (convertView == null) { convertView = mInflater.inflate(R.layout.row_for_stopnames, null); holder = new ViewHolder(); holder.name = (TextView)convertView.findViewById(R.id.stop_name); holder.dis = (TextView)convertView.findViewById(R.id.distance); holder.route_one=(ImageView)convertView.findViewById(R.id.one); holder.route_two=(ImageView)convertView.findViewById(R.id.two); holder.route_three=(ImageView)convertView.findViewById(R.id.three); convertView.setTag(holder); } else { holder = (ViewHolder) convertView.getTag(); } holder.name.setText(elements.get(position).get("stop_name")); holder.dis.setText(elements.get(position).get("distance")); String[] route_txt=elements.get(position).get("route_name").split(","); for(int i=0;i<route_txt.length;i++) { if(i==0) { holder.route_one.setBackgroundResource(Utils.getRouteImage().get(stop_txt[0])); } else if(i==1) { holder.route_two.setBackgroundResource(Utils.getRouteImage().get(stop_txt[1])); } else if(i==2) { holder.route_three.setBackgroundResource(Utils.getRouteImage().get(stop_txt[2])); } } convertView.setOnClickListener(new OnItemClickListener(position,elements)); return convertView; } class ViewHolder { TextView name; TextView dis; ImageView route_one; ImageView route_two; ImageView route_three; } for every stop name there may be route_names, maximum of three routes.I have to bind images according to the number of route names.This is what I tried to do by the above code .This works fine until I start scrolling up and down .When I do so the route images gets displayed where it does not want to be,this behaviour is unpredictable.I will be glad if someone explain me why this happens,and the best way to do this.The getRouteImage method of Utils class returns HashMap with key String and value a drawable

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  • Why doesn't IB see my IBAction?

    - by Dan Ray
    I've been staring at this for way too long. There's nothing fancy happening here, and I've done this dozens of times, yet Interface Builder steadfastly refuses to provide me an action target for -(IBAction)slideDirections. I'm at the point where I'm willing to post publicly and feel stupid. So let 'er rip. Here's my .h: #import <UIKit/UIKit.h> #import <MapKit/MapKit.h> @interface PulseDetailController : UIViewController { NSDictionary *pulse; IBOutlet MKMapView *map; IBOutlet UIWebView *directions; IBOutlet UIView *directionsSlider; BOOL directionsExtended; IBOutlet UILabel *vendor; IBOutlet UILabel *offer; IBOutlet UILabel *offerText; IBOutlet UILabel *hours; IBOutlet UILabel *minutes; IBOutlet UILabel *seconds; IBOutlet UILabel *distance } @property (nonatomic, retain) NSDictionary *pulse; @property (nonatomic, retain) MKMapView *map; @property (nonatomic, retain) UIWebView *directions; @property (nonatomic, retain) UIView *directionsSlider; @property (nonatomic) BOOL directionsExtended; @property (nonatomic, retain) UILabel *vendor; @property (nonatomic, retain) UILabel *offer; @property (nonatomic, retain) UILabel *offerText; @property (nonatomic, retain) UILabel *hours; @property (nonatomic, retain) UILabel *minutes; @property (nonatomic, retain) UILabel *seconds; @property (nonatomic, retain) UILabel *distance; -(IBAction)slideDirections; @end

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  • NHibernate complex order query

    - by manu08
    Here's my simplified domain public class Notification { public Guid ID { get; set; } public string Name { get; set; } public IEnumerable<Location> Locations { get; set; } } public class Location { public Guid Id { get; set; } public string Name { get; set; } public decimal Longitude { get; set; } public decimal Latitude { get; set; } } Notifications and Locations have a many-to-many relationship (defined in table LocationsOnNotification). What I'd like to do is query for the nearest 10 Notifications from a given longitude and latitude. I've been trying to use ICriteria, but I'm not sure how to specify the ordering correctly: return Session.CreateCriteria<Notification>() .SetFirstResult(firstIndex) .SetMaxResults(maxResults) .AddOrder(Order.Asc( WHAT GOES HERE! )) .List<Notification>(); What I've been thinking of so far is adding a formula property to the Location mapping; something like this: <property name='Distance' formula='lots of geometry'/> But I'm not sure if that can take in parameters (since I'd need to pass in the user's location to calculate the distance), plus I'm not sure how to specify it in the Order.Asc clause given that it's a property on a many-to-many association class. Any ideas? Or perhaps I should take a different approach altogether. Thanks in advance!

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  • COCOS2D - Animation Stops During Move

    - by maiko
    Hey guys! I am trying to run a "Walk" style animation on my main game sprite. The animations work fine, and my sprite is hooked up to my joystick all fine and dandy. However, I think where I setup the call for my walk animations are wrong. Because everytime the sprite is moving, the animation stops. I know putting the animation in such a weak if statement is probably bad, but please tell me how I could get my sprite to animate properly while it is being moved by the joystick. The sprite faces the right direction, so I can tell the action's first frame is being called, however, it doesn't animate until I stop touching my joystick. Here is How I call the action: //WALK LEFT if (joypadCap.position.x <= 69 /*&& joypadCap.position.y < && joypadCap.position.y 40 */ ) { [tjSprite runAction:walkLeft]; }; //WALK RIGHT if ( joypadCap.position.x = 71 /* && joypadCap.position.y < 100 && joypadCap.position.y 40 */) { [tjSprite runAction:walkRight]; }; THIS: is the how the joystick controls the character: CGPoint newLocation = ccp(tjSprite.position.x - distance/8 * cosf(touchAngle), tjSprite.position.y - distance/8 * sinf(touchAngle)); tjSprite.position = newLocation; Please help. Any alternative ways to call the characters walk animation would be greatly appreciated!

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  • Showing latex commands in text string using mathjax

    - by robezy
    I have a text string, for ex. 'A vehicle travels from A to B, distance {$d} km at constant speed. While returning back to A on same path it {$variation} its speed by {$v} km/hr. The total time of journey is {$t} hours. Find the original speed of vehicle.' The variables in the curly brackets are to be replaced by appropriate latex equation. I'm using php's preg_replace to replace the variables with latex commands. Unfortunately, my latex commands are coming as it is. It is not processed by mathjax. For ex, above text becomes A vehicle travels from A to B, distance 1 km at constant speed. While returning back to A on same path it increased its speed by (\frac{3}{2}) km/hr. The total time of journey is 1 hours. Find the original speed of vehicle. The frac is show as it is. What is wrong here? Please ask me if you need any more info. Thanks

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  • How do I create a graph from this datastructure?

    - by Shawn Mclean
    I took this data structure from this A* tutorial: public interface IHasNeighbours<N> { IEnumerable<N> Neighbours { get; } } public class Path<TNode> : IEnumerable<TNode> { public TNode LastStep { get; private set; } public Path<TNode> PreviousSteps { get; private set; } public double TotalCost { get; private set; } private Path(TNode lastStep, Path<TNode> previousSteps, double totalCost) { LastStep = lastStep; PreviousSteps = previousSteps; TotalCost = totalCost; } public Path(TNode start) : this(start, null, 0) { } public Path<TNode> AddStep(TNode step, double stepCost) { return new Path<TNode>(step, this, TotalCost + stepCost); } public IEnumerator<TNode> GetEnumerator() { for (Path<TNode> p = this; p != null; p = p.PreviousSteps) yield return p.LastStep; } IEnumerator IEnumerable.GetEnumerator() { return this.GetEnumerator(); } } I have no idea how to create a simple graph with. How do I add something like the following undirected graph using C#: Basically I'd like to know how to connect nodes. I have my own datastructures that I can already determine the neighbors and the distance. I'd now like to convert that into this posted datastructure so I can run it through the AStar algorithm. I was seeking something more like: Path<EdgeNode> startGraphNode = new Path<EdgeNode>(tempStartNode); startGraphNode.AddNeighbor(someOtherNode, distance);

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  • In Powerpoint 2007, how can I position a Callout's Tail programatically?

    - by Rorschach
    I'm looking at the XML and this is what it has for the Callout object's coordinates and geometry: <p:spPr> <a:xfrm> <a:off x="2819400" y="5181600"/> // X,Y Position of Callout Box <a:ext cx="609600" cy="457200"/> // Width,Height of Callout Box </a:xfrm> <a:prstGeom prst="wedgeRectCallout"> <a:avLst> <a:gd name="adj1" fmla="val 257853"/> // X Position Of Tail <a:gd name="adj2" fmla="val -532360"/> // Y Position of Tail </a:avLst> </a:prstGeom> <a:solidFill> <a:schemeClr val="accent1"> <a:alpha val="50000"/> </a:schemeClr> </a:solidFill> </p:spPr> What I'm having trouble with is the formula for telling it to place the tail at a particular coordinate on the slide. I've tried this to calculate it, but it does not work correctly. //This gives me the distance between the Coordinate and the Center of the Callout. DistanceX = Coordinate.X - (Callout.X + Callout.X_Ext)/2 DistanceY = Coordinate.Y - (Callout.Y + Callout.Y_Ext)/2 But, the geometric value is not the distance between the two points. Anybody know what the formula is for calculating this?

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  • MySql "comments" parameter as descriptor?

    - by Nick
    So, I'm trying to learn a lot at once, and this place is really helpful! I'm making a little running log website for myself and maybe a few other people, and I have it so that the user can add workouts for each day. With each workout, I have a variety of information the user can fill out for the workout, such as running distance, time, quality of run, course, etc... I store this in a MySql database as a table with fields titled "distance", "time", "runquality", etc... Now, these field titles don't match up with what I want displayed on the running log, so I was thinking of using the "Comments" attribute for a field to store its human-readable title--thus the field "runquality" would have "Quality of run" as its comment, and then I would pull the comment with a SQL query and display it instead of the field name. Is this a good theoretical/practical way of going about it? And what sort of SQL would I use to pull the comment for the field anyway? Secondly, suppose I want to add the ability for the user to create their own workout descriptors. So say a user wants to add a "temperature" descriptor for their workout. Should I create a script that adds fields to my workout table, or should I create a separate table listing only workout descriptors and somehow link the descriptor table with the "contents" table? I haven't learned any theory about database design or anything so any help is appreciated!

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  • How can I split a LINESTRING into two LINESTRINGs at a given point?

    - by sabbour
    Hello, I'm trying to write a function that will split a LINESTRING into two LINESTRINGs given the split point. What I'm trying to achieve is a function that given a LINESTRING and a distance, it will return N LINESTRINGS for the original linestring splitted at multiples of that distance. This is what I have so far (I'm using SQL Server Spatial Tools from CodePlex): DECLARE @testLine geography; DECLARE @slicePoint geography; SET @testLine = geography::STGeomFromText('LINESTRING (34.5157942 28.5039665, 34.5157079 28.504725, 34.5156881 28.5049565, 34.5156773 28.505082, 34.5155642 28.5054437, 34.5155498 28.5054899, 34.5154937 28.5058826, 34.5154643 28.5060218, 34.5153968 28.5063415, 34.5153322 28.5065338, 34.5152031 28.5069178, 34.5150603 28.5072288, 34.5148716 28.5075501, 34.5146106 28.5079974, 34.5143617 28.5083813, 34.5141373 28.5086414, 34.5139954 28.5088441, 34.5138874 28.5089983, 34.5138311 28.5091054, 34.5136783 28.5093961, 34.5134336 28.5097531, 34.51325 28.5100794, 34.5130256 28.5105078, 34.5128754 28.5107957, 34.5126258 28.5113222, 34.5123984 28.5117673)', 4326) DECLARE @pointOne geography; declare @result table (segment geography) DECLARE @sliceDistance float DECLARE @nextSliceAt float SET @sliceDistance = 100 -- slice every 100 meters SET @nextSliceAt = @sliceDistance SELECT @pointOne = @testLine.STStartPoint() WHILE(@nextSliceAt < @testLine.STLength()) BEGIN SELECT @slicePoint = dbo.LocateAlongGeog(@testLine,@nextSliceAt) DECLARE @subLineString geography; SET @subLineString = geography::STGeomFromText('LINESTRING (' + dbo.FloatToVarchar(@pointOne.Long) + ' ' + dbo.FloatToVarchar(@pointOne.Lat) + ',' + dbo.FloatToVarchar(@slicePoint.Long) + ' ' + dbo.FloatToVarchar(@slicePoint.Lat) +')', 4326) insert into @result SELECT @subLineString SET @pointOne = @slicePoint set @nextSliceAt = @nextSliceAt + @sliceDistance END SET @subLineString = geography::STGeomFromText('LINESTRING (' + dbo.FloatToVarchar(@pointOne.Long) + ' ' + dbo.FloatToVarchar(@pointOne.Lat) + ',' + dbo.FloatToVarchar(@testLine.STEndPoint().Long) + ' ' + dbo.FloatToVarchar(@testLine.STEndPoint().Lat) +')', 4326) insert into @result SELECT @subLineString select * from @result I know it is not the best looking code, but there is another problem. The above code approximates the resulting LINESTRING because it does not follow the curvature of the original LINESTRING as it only takes into consideration the start and end points when creating the new segment. Is there a way take a substring out of the original LINESTRING given the start and end points?

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  • Increasing figure size in Matplotlib

    - by Anirudh
    I am trying to plot a graph from a distance matrix. The code words fine and gives me a image in 800 * 600 pixels. The image being too small, All the nodes are packed together. I want increase the size of the image. so I added the following line to my code - figure(num=None, figsize=(10, 10), dpi=80, facecolor='w', edgecolor='k') After this all I get is a blank 1000 * 1000 image file. My overall code - import networkx as nx import pickle import matplotlib.pyplot as plt print "Reading from pickle." p_file = open('pickles/names') Names = pickle.load(p_file) p_file.close() p_file = open('pickles/distance') Dist = pickle.load(p_file) p_file.close() G = nx.Graph() print "Inserting Nodes." for n in Names: G.add_node(n) print "Inserting Edges." for i in range(601): for j in range(601): G.add_edge(Names[i],Names[j],weight=Dist[i][j]) print "Drawing Graph." nx.draw(G) print "Saving Figure." #plt.figure(num=None, figsize=(10, 10)) plt.savefig('new.png') print "Success!"

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