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  • Django: making raw SQL query, passing multiple/repeated params?

    - by AP257
    Hopefully this should be a fairly straightforward question, I just don't know enough about Python and Django to answer it. I've got a raw SQL query in Django that takes six different parameters, the first two of which (centreLat and centreLng) are each repeated: query = "SELECT units, (SQRT(((lat-%s)*(lat-%s)) + ((lng-%s)*(lng-%s)))) AS distance FROM places WHERE lat<%s AND lat>%s AND lon<%s AND lon>%s ORDER BY distance;" params = [centreLat,centreLng,swLat,neLat,swLng,neLng] places = Place.objects.raw(query, params) How do I structure the params object and the query string so they know which parameters to repeat and where?

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  • image focus calculation

    - by Oren Mazor
    Hi folks, I'm trying to develop an image focusing algorithm for some test automation work. I've chosen to use AForge.net, since it seems like a nice mature .net friendly system. Unfortunately, I can't seem to find information on building autofocus algorithms from scratch, so I've given it my best try: take image. apply sobel edge detection filter, which generates a greyscale edge outline. generate a histogram and save the standard dev. move camera one step closer to subject and take another picture. if the standard dev is smaller than previous one, we're getting more in focus. otherwise, we've past the optimal distance to be taking pictures. is there a better way? update: HUGE flaw in this, by the way. as I get past the optimal focus point, my "image in focus" value continues growing. you'd expect a parabolic-ish function looking at distance/focus-value, but in reality you get something that's more logarithmic

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  • How to page while maintaining the querystring values in ASP.Net Mvc 2

    - by Picflight
    I am using the pager provided by Martijin Boland to implementing paging in my Asp.Net Mvc 2 application. My form uses the GET method to send all parameters to the querystring, it is a search form with several form elements. <% using (Html.BeginForm("SearchResults", "Search", FormMethod.Get)) {%> On the SearchResults View I am trying to implement paging: <div class="pager"> <%= Html.Pager(Model.PageSize, Model.PageNumber, Model.TotalItemCount, new { Request.QueryString })%> </div> The Html.Pager has some overloads which I am not too clear on how to use. The Request.QueryString makes the querystring look like this: http://localhost:1155/Search/SearchResults?QueryString=Distance%3D10%26txtZip%3D%26cb&page=2 Should it not be like this? http://localhost:1155/Search/SearchResults?Distance=20&txtZip=10021&page=2

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  • What's an efficient way of calculating the nearest point?

    - by Griffo
    I have objects with location data stored in Core Data, I would like to be able to fetch and display just the nearest point to the current location. I'm aware there are formulas which will calculate the distance from current lat/long to a stored lat/long, but I'm curious about the best way to perform this for a set of 1000+ points stored in Core Data. I know I could just return the points from Core Data to an array and then loop through that looking for the min value for distance between the points but I'd imagine there's a more efficient method, possibly leveraging Core Data in some way. Any insight would be appreciated. EDIT: I don't know how I missed this on my initial search but this SO question suggests just iterating through an array of Core Data objects but limiting the array size with a bounding box based on the current location. Is this the best I can do?

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  • What is the relaxation condition in graph theory

    - by windopal
    Hi, I'm trying to understand the main concepts of graph theory and the algorithms within it. Most algorithms seem to contain a "Relaxation Condition" I'm unsure about what this is. Could some one explain it to me please. An example of this is dijkstras algorithm, here is the pseudo-code. 1 function Dijkstra(Graph, source): 2 for each vertex v in Graph: // Initializations 3 dist[v] := infinity // Unknown distance function from source to v 4 previous[v] := undefined // Previous node in optimal path from source 5 dist[source] := 0 // Distance from source to source 6 Q := the set of all nodes in Graph // All nodes in the graph are unoptimized - thus are in Q 7 while Q is not empty: // The main loop 8 u := vertex in Q with smallest dist[] 9 if dist[u] = infinity: 10 break // all remaining vertices are inaccessible from source 11 remove u from Q 12 for each neighbor v of u: // where v has not yet been removed from Q. 13 alt := dist[u] + dist_between(u, v) 14 if alt < dist[v]: // Relax (u,v,a) 15 dist[v] := alt 16 previous[v] := u 17 return dist[] Thanks

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  • Comparing (similar) images with Python/PIL

    - by Attila Oláh
    I'm trying to calculate the similarity (read: Levenshtein distance) of two images, using Python 2.6 and PIL. I plan to use the python-levenshtein library for fast comparison. Main question: What is a good strategy for comparing images? My idea is something like: Convert to RGB (transparent - white) (or maybe convert to monochrome?) Scale up the smaller one to the larger one's size Convert each channel (= the only channel, if converted to monochrome) to a sequence (item value = color value of the pixel) Calculate the Levenshtein distance between the two sequences Of course, this will not handle cases like mirrored images, cropped images, etc. But for basic comparison, this should be useful. Is there a better strategy documented somewhere?

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  • Objective C / iPhone comparing 2 CLLocations /GPS coordinates help

    - by user289503
    Ok , so thanks to Claus Broch I made some progress with comparing two GPS locations. I need to be able to say "IF currentlocation IS EQUAL TO (any GPS position from a list ) THEN do something My code at the moment is : CLLocationCoordinate2D bonusOne; bonusOne.latitude = 37.331689; bonusOne.longitude = -122.030731; Which is the simulators GPS location at Infinite Loop CLLocation *loc1 = [[CLLocation alloc] initWithLatitude:bonusOne.latitude longitude:bonusOne.longitude]; double distance = [loc1 getDistanceFrom:newLocation]; if(distance <= 10000000) { Then do something } Any number under 10000000 and it assumes that there is no match. Any ideas ? Thanks is advance.

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  • Question on multi-probe Local Sensitive Hashing

    - by Yijinsei
    Hey guys sorry to be asking this kind noob question, but because I really need some guidance on how to use Multi probe LSH pretty urgently, so I did not do much research myself. I realize there is a lib call LSHKIT available that implemented that algorithm, but I have trouble trying to figure out how to use it. Right now, I have a few thousand feature vector 296 dimension, each representing an image. The vector is used to query an user input image, to retrieve the most similar image. The method I used to derive the distance between vector is euclidean distance. I know this might be a rather noob question, but do you guys have knowledge on how should i implement multi probe LSH? I am really very grateful to any answer or response.

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  • Closest Approach question for math/physics heads

    - by Kyle
    I'm using a Segment to Segment closest approach method which will output the closest distance between two segments of length. These objects are moving at variable speed each, so even when it succeeds I'm currently using a 10-step method and calculating the distance between 2 spheres as they move along the two segments. So, basically the length of each segment is the object's traverse in the physics step, and the radius is the objects radius. By stepping, I can tell where they collide, and if they collide (Sort of; for the MOST part.).. I get the feeling that there could be something better. While I sort of believe that the first closest approach call is required, I think that the method immediately following it is a TAD weak. Can anyone help me out? I can illustrate this if needed. Thanks alot!

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  • Trilateration using 3 latitude and longitude points, and 3 distances

    - by nohat
    There exists an unknown target location (latitude and longitude co-ordinates). I have 3 latitude and longitude co-ordinate pairs and for each pair a distance in kilometers to the target location. How can I calculate the co-ordinates of the target location? For example, say I have the following data points 37.418436,-121.963477 0.265710701754km 37.417243,-121.961889 0.234592423446km 37.418692,-121.960194 0.0548954278262km What I'd like is what would the guts of the function that takes that as input and returns 37.417959,-121.961954 as output look like? I understand how to calculate the distance between two points, from http://www.movable-type.co.uk/scripts/latlong.html I understand the general principle that with three circles you get exactly one point of overlap. What I'm hazy on is the math needed to calculate that point with this input.

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  • C: sprintf and recursion

    - by Shinka
    In C, is it possible to use recursion within the sprintf function ? For some reason I get a segmentation fault when I do it: inline char *TreeNode_toString(const TreeNode *node) { char *out; if(TreeNode_isExternal(node)) // If the node has no children... { sprintf(out, "%s:%.2f", node->name, node->distance); } else // The node is strictly binary, so it will have two non-null children { char *l = TreeNode_toString(node->l); // l = left child char *r = TreeNode_toString(node->r); // r = right child sprintf(out, "(%s,%s):%.2f", l, r, node->distance); } return out; }

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  • agent-based simulation: performance issue: Python vs NetLogo & Repast

    - by max
    I'm replicating a small piece of Sugarscape agent simulation model in Python 3. I found the performance of my code is ~3 times slower than that of NetLogo. Is it likely the problem with my code, or can it be the inherent limitation of Python? Obviously, this is just a fragment of the code, but that's where Python spends two-thirds of the run-time. I hope if I wrote something really inefficient it might show up in this fragment: UP = (0, -1) RIGHT = (1, 0) DOWN = (0, 1) LEFT = (-1, 0) all_directions = [UP, DOWN, RIGHT, LEFT] # point is just a tuple (x, y) def look_around(self): max_sugar_point = self.point max_sugar = self.world.sugar_map[self.point].level min_range = 0 random.shuffle(self.all_directions) for r in range(1, self.vision+1): for d in self.all_directions: p = ((self.point[0] + r * d[0]) % self.world.surface.length, (self.point[1] + r * d[1]) % self.world.surface.height) if self.world.occupied(p): # checks if p is in a lookup table (dict) continue if self.world.sugar_map[p].level > max_sugar: max_sugar = self.world.sugar_map[p].level max_sugar_point = p if max_sugar_point is not self.point: self.move(max_sugar_point) Roughly equivalent code in NetLogo (this fragment does a bit more than the Python function above): ; -- The SugarScape growth and motion procedures. -- to M ; Motion rule (page 25) locals [ps p v d] set ps (patches at-points neighborhood) with [count turtles-here = 0] if (count ps > 0) [ set v psugar-of max-one-of ps [psugar] ; v is max sugar w/in vision set ps ps with [psugar = v] ; ps is legal sites w/ v sugar set d distance min-one-of ps [distance myself] ; d is min dist from me to ps agents set p random-one-of ps with [distance myself = d] ; p is one of the min dist patches if (psugar >= v and includeMyPatch?) [set p patch-here] setxy pxcor-of p pycor-of p ; jump to p set sugar sugar + psugar-of p ; consume its sugar ask p [setpsugar 0] ; .. setting its sugar to 0 ] set sugar sugar - metabolism ; eat sugar (metabolism) set age age + 1 end On my computer, the Python code takes 15.5 sec to run 1000 steps; on the same laptop, the NetLogo simulation running in Java inside the browser finishes 1000 steps in less than 6 sec. EDIT: Just checked Repast, using Java implementation. And it's also about the same as NetLogo at 5.4 sec. Recent comparisons between Java and Python suggest no advantage to Java, so I guess it's just my code that's to blame? EDIT: I understand MASON is supposed to be even faster than Repast, and yet it still runs Java in the end.

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  • HTTP Digest Authentication Fails With URL Parameters (CakePHP)

    - by NathanGaskin
    I have a RESTful API set up and working with CakePHP using mapResources() and parseExtensions(). Authentication is handled by CakePHP's security component using HTTP Digest Authentication. Everything works fine, unless I add parameters to the url, in the form: http://example.com/locations.xml?distance=4 Which causes the authentication to always fail. Any ideas? Edit: This seems to be an issue with the regex in parseDigestAuthData(). There's a semi-fix here: http://old.nabble.com/paginator-conflicts-with-Security-%3ErequireLogin---td16301573.html which now allows me to use the format: http://example.com/locations/index/distance:4/.xml But that's not RESTful and doesn't look all that pretty. Still, getting closer!

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  • Finding coordinates of a point between two points?

    - by Nicros
    Doing some 3D stuff in wpf- want to use a simpler test to see if everything is working (before moving to curves). The basic question is given two points x1,y1,z1 and x2,y2,z2 I have calculated the distance between the points. But how to find the coordinates of another point (x3,y3,z3) that lies on that line at some distance? I.e. if my line is 100 long between -50,0,0 and 50,0,0 what are the coordinates of the point at 100 * 0.1 along the line? I think this is a simple formula but I haven't found it yet....

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  • Python KMeans clustering words

    - by sadawd
    Dear Everyone I am interested to perform kmeans clustering on a list of words with the distance measure being Leveshtein. 1) I know there are a lot of frameworks out there, including scipy and orange that has a kmeans implementation. However they all require some sort of vector as the data which doesn't really fit me. 2) I need a good clustering implementation. I looked at python-clustering and realize that it doesn't a) return the sum of all the distance to each centroid, and b) it doesn't have any sort of iteration limit or cut off which ensures the quality of the clustering. python-clustering and the clustering algorithm on daniweb doesn't really work for me. Can someone find me a good lib? Google hasn't been my friend

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  • mysql birthday reminder, leap year

    - by moodh
    Hi, I'm trying to sort out a result set that gives the 5 closest users sorted by upcoming birthday. This works perfectly until leap years comes into play. For example: May 15th - 96 days left May 15th - 97 days left The top result is a birth at 1987 and the lower is from 1988. u_birth is stored as yyyy-mm-dd. Is there a simple way to sort this problem without having to rewrite the entire query? SELECT u_birth, IF( DAYOFYEAR( u_birth ) >= DAYOFYEAR( NOW() ), DAYOFYEAR( u_birth ) - DAYOFYEAR( NOW() ), DAYOFYEAR( u_birth ) - DAYOFYEAR( NOW() ) + DAYOFYEAR( CONCAT( YEAR( NOW() ), '-12-31' ) ) ) AS distance FROM (blog_users) WHERE `s_agehide` = 0 ORDER BY distance ASC LIMIT 5 This query is taken and modified from the mysql manual: http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#c7489

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  • Adding an overlay to Google maps with path taken

    - by user341652
    Hi, I am trying to write a class to track a person's location(s), and to draw the path they've taken on a MapView. This feature of the program is for the user to track their speed, distance, path, etc. while running/cycling (or whatever else) using their Android phone. This is my first Android application, and I am not sure how to do the Overlay object for the MapView. I also wanted to see if anyone had opinions on the GPS-Tracking part I have written (if it would work, if there is a better way of doing it, code examples would be helpful). I currently have this for my GPSTrackerService: package org.drexel.itrain.logic; import java.util.Vector; import org.drexel.itrain.Constants; import android.app.Notification; import android.app.NotificationManager; import android.app.Service; import android.content.Context; import android.content.Intent; import android.content.SharedPreferences; import android.location.GpsSatellite; import android.location.GpsStatus; import android.location.Location; import android.location.LocationListener; import android.location.LocationManager; import android.location.GpsStatus.Listener; import android.os.Binder; import android.os.Bundle; import android.os.IBinder; import android.preference.PreferenceManager; public class GPSTrackingService extends Service { private static final int MAX_REASONABLE_SPEED = 60; private static final String TAG = "OGT.TrackingService"; private Context mContext; private LocationManager mLocationManager; private NotificationManager mNotificationManager; private Notification mNotification; private int mSatellites = 0; private int mTrackingState = Constants.GPS_TRACKING_UNKNOWN; private float mCurrentSpeed = 0; private float mTotalDistance = 0; private Location mPreviousLocation; private Vector<Location> mTrackedLocations; private LocationListener mLocationListener = null; private Listener mStatusListener = null; private IBinder binder = null; @Override public void onCreate() { super.onCreate(); this.mContext = getApplicationContext(); this.mLocationManager = (LocationManager) this.mContext.getSystemService( Context.LOCATION_SERVICE ); this.mNotificationManager = (NotificationManager) this.mContext.getSystemService( Context.NOTIFICATION_SERVICE ); this.mTrackedLocations = new Vector<Location>(); this.binder = new Binder(); SharedPreferences sharedPreferences = PreferenceManager.getDefaultSharedPreferences(this.mContext); binder = new Binder(); if(mTrackingState != Constants.GPS_TRACKING_UNKNOWN) { createListeners(); } } @Override public void onDestroy() { destroyListeneres(); } @Override public IBinder onBind(Intent intent) { return binder; } @Override public boolean onUnbind(Intent intent) { return true; } public boolean acceptLocation(Location proposedLocation) { if(!(proposedLocation.hasSpeed() || proposedLocation.hasAccuracy())) { return false; } else if(proposedLocation.getSpeed() >= MAX_REASONABLE_SPEED) { return false; } return true; } public void updateNotification() { //TODO Alert that no GPS sattelites are available (or are available) } public void startTracking() { this.mTrackingState = Constants.GPS_TRACKING_STARTED; this.mTotalDistance = 0; this.mCurrentSpeed = 0; this.mTrackedLocations = new Vector<Location>(); this.mPreviousLocation = null; createListeners(); } public void pauseTracking() { this.mTrackingState = Constants.GPS_TRACKING_PAUSED; this.mPreviousLocation = null; this.mCurrentSpeed = 0; } public void resumeTracking() { if(this.mTrackingState == Constants.GPS_TRACKING_STOPPED){ this.startTracking(); } this.mTrackingState = Constants.GPS_TRACKING_STARTED; } public void stopTracking() { this.mTrackingState = Constants.GPS_TRACKING_STOPPED; destroyListeneres(); } private void createListeners() { /** * LocationListener receives locations from */ this.mLocationListener = new LocationListener() { @Override public void onStatusChanged(String provider, int status, Bundle extras) { // TODO Auto-generated method stub } @Override public void onProviderEnabled(String provider) { // TODO Auto-generated method stub } @Override public void onProviderDisabled(String provider) { // TODO Auto-generated method stub } @Override public void onLocationChanged(Location location) { if(mTrackingState == Constants.GPS_TRACKING_STARTED && acceptLocation(location)) { if(mPreviousLocation != null) { //Add the distance between the new location and the previous location mTotalDistance += mPreviousLocation.distanceTo(location); } if(location.hasSpeed()) { mCurrentSpeed = location.getSpeed(); } else { mCurrentSpeed = -1; //-1 means speed N/A } mPreviousLocation = location; mTrackedLocations.add(location); } } }; /** * Receives updates reguarding the GPS Status */ this.mStatusListener = new GpsStatus.Listener() { @Override public synchronized void onGpsStatusChanged(int event) { switch( event ) { case GpsStatus.GPS_EVENT_SATELLITE_STATUS: { GpsStatus status = mLocationManager.getGpsStatus( null ); mSatellites = 0; Iterable<GpsSatellite> list = status.getSatellites(); for( GpsSatellite satellite : list ) { if( satellite.usedInFix() ) { mSatellites++; } } updateNotification(); break; } default: break; } } }; } /** * Destroys the LocationListenere and the GPSStatusListener */ private void destroyListeneres() { this.mLocationListener = null; this.mStatusListener = null; } /** * Gets the total distance traveled by the * * @return the total distance traveled (in meters) */ public float getDistance() { return mTotalDistance; } /** * Gets the current speed of the last good location * * @return the current speed (in meters/second) */ public float getSpeed() { return mCurrentSpeed; } } Any assistance would be much appreciated. This is my group's first Android app, and we are a little pressed for time at the moment. The project is for a class, and is available from SourceForge (currently called iTrain, soon to be renamed). Thanks in Advance, Steve

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  • Algorithm for finding symmetries of a tree

    - by Paxinum
    I have n sectors, enumerated 0 to n-1 counterclockwise. The boundaries between these sectors are infinite branches (n of them). The sectors live in the complex plane, and for n even, sector 0 and n/2 are bisected by the real axis, and the sectors are evenly spaced. These branches meet at certain points, called junctions. Each junction is adjacent to a subset of the sectors (at least 3 of them). Specifying the junctions, (in pre-fix order, lets say, starting from junction adjacent to sector 0 and 1), and the distance between the junctions, uniquely describes the tree. Now, given such a representation, how can I see if it is symmetric wrt the real axis? For example, n=6, the tree (0,1,5)(1,2,4,5)(2,3,4) have three junctions on the real line, so it is symmetric wrt the real axis. If the distances between (015) and (1245) is equal to distance from (1245) to (234), this is also symmetric wrt the imaginary axis. The tree (0,1,5)(1,2,5)(2,4,5)(2,3,4) have 4 junctions, and this is never symmetric wrt either imaginary or real axis, but it has 180 degrees rotation symmetry if the distance between the first two and the last two junctions in the representation are equal. Edit: This is actually for my research. I have posted the question at mathoverflow as well, but my days in competition programming tells me that this is more like an IOI task. Code in mathematica would be excellent, but java, python, or any other language readable by a human suffices. Here are some examples (pretend the double edges are single and we have a tree) http://www2.math.su.se/~per/files.php?file=contr_ex_1.pdf http://www2.math.su.se/~per/files.php?file=contr_ex_2.pdf http://www2.math.su.se/~per/files.php?file=contr_ex_5.pdf Example 1 is described as (0,1,4)(1,2,4)(2,3,4)(0,4,5) with distances (2,1,3). Example 2 is described as (0,1,4)(1,2,4)(2,3,4)(0,4,5) with distances (2,1,1). Example 5 is described as (0,1,4,5)(1,2,3,4) with distances (2). So, given the description/representation, I want to find some algorithm to decide if it is symmetric wrt real, imaginary, and rotation 180 degrees. The last example have 180 degree symmetry. (These symmetries corresponds to special kinds of potential in the Schroedinger equation, which has nice properties in quantum mechanics.)

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  • select for update problem in jdbc

    - by kartiku
    I'm having a problem with select for update in jdbc. The table i'm trying to update is the smalldb table, i'm having problems-- i'm using select for update which does a lock on the selected row the update statement is -- String updateQ = "UPDATE libra.smalldb SET hIx = ? WHERE name = ?"; the select statement is -- rs = stmt1.executeQuery("SELECT hIx FROM libra.smalldb for update"); rs0 = stmt2.executeQuery("SELECT name,aff FROM libra.smalldb"); the second statement is because i need those fields as well. Here is the complete code -- import java.sql.*; import java.util.ArrayList; import java.util.Collections; public class Jdbcexample1 { /** * @param args */ public static void main(String[] args) { Connection con = null; try { Class.forName("com.mysql.jdbc.Driver").newInstance(); con = DriverManager.getConnection("jdbc:mysql:///test", "root", "*****"); //String url = "jdbc:msql://200.210.220.1:1114/Demo"; //Connection conn = DriverManager.getConnection(url,"",""); Statement stmt1 = con.createStatement(); Statement stmt2 = con.createStatement(); Statement stmt3 = con.createStatement(); Statement stmt4 = con.createStatement(); ResultSet rs0; ResultSet rs; ResultSet rs1; ResultSet rs2; String name; String hIx; int hIxInt; StringBuffer sb = new StringBuffer(); String affiliationSmall; ArrayList<String> affiliation = new ArrayList<String>(); ArrayList<Float> matchValues = new ArrayList<Float>(); ArrayList<Integer> hixValues = new ArrayList<Integer>(); ArrayList<Integer> idValues = new ArrayList<Integer>(); boolean moreFlag = false; String queryString; int tmpIdx; String name1; //get the hix at that index where the similarity is maximum int tmpHidx = 0; int tmpHix = 0; int id = 0; int count; int tmpidIdx = 0; //rs = stmt.executeQuery("SELECT id FROM libra.researchint WHERE id = 910887"); // Get name, affiliation , hIx from smalldb //rs = stmt1.executeQuery("SELECT name,aff,hIx FROM libra.smalldb"); // String cursorName = "OUR_CURSOR"; // stmt1.setCursorName(cursorName); //rs = stmt1.executeQuery("SELECT name,aff,hIx FROM libra.smalldb for update"); rs = stmt1.executeQuery("SELECT hIx FROM libra.smalldb for update"); rs0 = stmt2.executeQuery("SELECT name,aff FROM libra.smalldb"); while ( rs.next() && rs0.next() ) { //String lastName = rs.getString("id"); hIx = rs.getString("hIx"); hIxInt = Integer.parseInt(hIx); //if hIx if (hIxInt==-1) continue; //name = rs.getString("name"); name = rs0.getString("name"); name1 = new String(name); System.out.println(name); //affiliationSmall = rs.getString("aff"); affiliationSmall = rs0.getString("aff"); //name = "\"" +name+ "\""; // Get matching names from large faculty table //String queryString = "SELECT id,name,hIx FROM libra.faculty WHERE name = " +name; //name = does not work names are similar but not same (in faculty and // smalldb) String query = "SELECT id,name,hIx FROM libra.faculty WHERE name like ?"; //String query = "SELECT id,name,hIx FROM libra.faculty for update of hIx WHERE name like ?"; PreparedStatement prepStmt = con.prepareStatement(query); String[] nameArr = name.split(" "); StringBuffer tmpSb = new StringBuffer(); for(int idx = 0;idx<nameArr.length;idx++) { tmpSb.append(nameArr[idx] + "%"); } name = tmpSb.toString(); prepStmt.setString(1, name); rs1 = prepStmt.executeQuery(); //Try to get matching names from faculty big db //Execute the query on faculty table //rs1 = stmt2.executeQuery(queryString); if(rs1.isClosed()) continue; count = 0; matchValues.clear(); affiliation.clear(); while(rs1.next()) { //name = rs1.getString("name"); id = Integer.parseInt(rs1.getString("id")); //idValues.add(id); tmpHix = Integer.parseInt(rs1.getString("hIx")); queryString = "SELECT aff FROM libra.affiliation WHERE id = "+id; rs2 = stmt3.executeQuery(queryString); //affiliation = rs1.getString("aff"); sb.delete(0, sb.length()); while (rs2.next()) { //Concatenate it to the same string using a stringbuffer sb.append(rs2.getString("aff")); //affiliation.add(rs2.getString("aff")); } affiliation.add(sb.toString()); count++; // if(count1) // { // moreFlag = true; // //Call fuzzy match function, store the distance values and select the // //affiliation that has the minimum distance from affiliationSmall // // //problem is here, affiliation.get Index: 2, Size: 2 // // matchValues.add(fuzzyMatch(affiliationSmall,affiliation.get(count))); // hixValues.add(tmpHix); // idValues.add(id); // } }//end of while rs1 -> faculty rs1.close(); int idx = 0; if(count>1) { moreFlag = true; //Call fuzzy match function, store the distance values and select the //affiliation that has the minimum distance from affiliationSmall //problem is here, affiliation.get Index: 2, Size: 2 matchValues.add(fuzzyMatch(affiliationSmall,affiliation.get(idx))); hixValues.add(tmpHix); idValues.add(id); idx++; } if(moreFlag) { Object obj = Collections.max(matchValues); float maxVal = Float.parseFloat(obj.toString()); //int tmpIdx = matchValues.indexOf(new Float(maxVal)); //get the index at which similarity between affiliation strings is maximum, //as returned by fuzzyMatch //int tmpIdx = matchValues.indexOf(maxVal); tmpIdx = matchValues.indexOf(maxVal); //get the hix at that index where the similarity is maximum //int tmpHidx = hixValues.get(tmpIdx); tmpHidx = hixValues.get(tmpIdx); tmpidIdx = idValues.get(tmpIdx); //update the smalldb table String updateQ = "UPDATE libra.smalldb SET hIx = ? WHERE name = ?"; //String updateQ = "UPDATE libra.smalldb SET hIx = ? WHERE current of "+cursorName; //PreparedStatement prepStmt1 = con.prepareStatement("UPDATE libra.smalldb SET hIx = ? WHERE current of "+cursorName); PreparedStatement prepStmt1 = con.prepareStatement(updateQ); //PreparedStatement prepStmt1 = con.prepareStatement(updateQ); prepStmt1.setString(2, name1); prepStmt1.setString(1, Integer.toString(tmpHidx)); prepStmt1.executeUpdate(updateQ); //prepStmt1.execute(); //stmt4.executeUpdate(updateQ); }//end of if //For matching names get the affiliation based on id from affiliation table //con.close(); //System.out.println(lastName); System.out.println(name); }//end of while rs -> smalldb rs.close(); // String updateQ = "UPDATE libra.smalldb1 SET hIx = "+Integer.toString(tmpHidx)+ "WHERE id = "+Integer.toString(tmpidIdx); // stmt4.executeUpdate(updateQ); con.close(); } catch (Exception e) { System.err.println("Got an exception! "); System.err.println(e.getMessage()); e.printStackTrace(); } } public static float fuzzyMatch(String affiliationSmall, String affiliation) { //float distance = 0; String[] temp = null; temp = affiliationSmall.split(" "); int index; //int index1 = affiliation.indexOf(affiliationSmall); int matchCount = 0; for (int idx = 0;idx<temp.length; idx++) { index = affiliation.indexOf(temp[idx]); if (index!=-1) { matchCount++; } } float tmpFloat = matchCount/temp.length; //int[] aff1= new int[affiliation1.length()]; //int[] aff2 = new int[affiliation2.length()]; return tmpFloat; } } i think it is because of the second select statement (rs0) Here is the error- Got an exception! You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '?' at line 1 com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '?' at line 1 at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) at sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source) at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source) at java.lang.reflect.Constructor.newInstance(Unknown Source) at com.mysql.jdbc.Util.handleNewInstance(Util.java:409) at com.mysql.jdbc.Util.getInstance(Util.java:384) at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1054) at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3562) at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3494) at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1960) at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2114) at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2690) at com.mysql.jdbc.StatementImpl.executeUpdate(StatementImpl.java:1648) at com.mysql.jdbc.StatementImpl.executeUpdate(StatementImpl.java:1567) at Jdbcexample1.main(Jdbcexample1.java:184)

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