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  • Hibernate Search + Spring

    - by Zane
    I'm trying to integrate Hibernate Search with Spring, but I can't seem to index anything. I was able to get Hibernate Search to work without Spring, but I'm having a problem integrating it with Spring. Any help would be much appreciated. Below is my springmvc-servlet.xml: <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"> <property name="entityManagerFactory" ref="entityManagerFactory" /> </bean> <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean"> <property name="persistenceUnitName" value="enewsclipsPersistenceUnit" /> </bean> And here is my DAO class: @Repository public class SearchDaoImpl implements SearchDao { JpaTemplate jpaTemplate; @Autowired public SearchDaoImpl(EntityManagerFactory entityManagerFactory) { this.jpaTemplate = new JpaTemplate(entityManagerFactory); } @SuppressWarnings("unchecked") public void updateSearchIndex() { /* Implement the callback method */ jpaTemplate.execute(new JpaCallback() { public Object doInJpa(EntityManager em) throws PersistenceException { List<Article> articles = em.createQuery("select a from Article a").getResultList(); FullTextEntityManager ftEm = Search.getFullTextEntityManager(em); ftEm.getTransaction().begin(); for(Article article : articles) { System.out.println("Indexing Item " + article.getTitle()); ftEm.index(article); } ftEm.getTransaction().commit(); return null; } }); } } I think that it may have to do with the transactions but I'm not exactly sure. If you could just point me in the right direction, that would be helpful too! Thank you.

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  • Hibernate Exception Fixed By Alt+Tab

    - by Lee Theobald
    Hi all, I've got a very curious problem in Hibernate that I would like some opinions on. In my code if I do the following: Go to page A Click a link on page A to be taken to page B Click on data item on page B Exception thrown I get an error telling me: failed to lazily initialize a collection of role: XYZ, no session or session was closed Fair enough. But when I do the same thing but add an alt+tab in the middle, everything is fine. E.g. Go to page A Click a link on page A to be taken to page B Hit ALt+Tab to switch to another application Hit ALt+Tab to switch back to the web browser Click on data item on page B Everything is fine. I'm a little confused as to how switching focus from my application makes it act as I want it to. Does anyone have any light to shine on the subject? I don't think it's a locking issue as even if I do the second set of steps quicker than the first, still no error. It's a Seam application using Hibernate 3.3.2.GA & 3.4.0.GA.

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  • Changing the Hibernate 3 settings

    - by Bogdanel
    I use Hibernate3 and Hibernate Tools 3.2.4 to generate hbm.xml and java files and I want to use List instead of HashSet(...). I've tried to modify the hbm.xml files, putting list instead of set. Is there any way to specify to hibernate tools that I want to generate automatically a list not a HashSet? This is an exemple: Java class public class Test implements java.io.Serializable { private Long testId; private Course course; private String testName; private Set<Question> questions = new HashSet<Question>( 0 ); } Test.hbm.xml: <set name="questions" inverse="true" lazy="true" table="questions" fetch="select"> <key> <column name="test_id" not-null="true" /> </key> <one-to-many class="com.app.objects.Question" /> ... </set> I thought that I could find a clue in the "reveng.xml" file, but I failed.

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  • Catch hibernate exceptions with errorpage handler?

    - by membersound
    I'm catching all exceptions within: java.lang.Throwable /page.xhtml java.lang.Error /page.xhtml But what If I get eg a hibernate ex: org.hibernate.exception.ConstraintViolationException Do I have to define error-pages for EVERY maybe occuring exception? Can't I just say "catch every exception"? Update Redirect on a 404 works. But on a throwable does not! <servlet> <servlet-name>Faces Servlet</servlet-name> <servlet-class>javax.faces.webapp.FacesServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>Faces Servlet</servlet-name> <url-pattern>*.jsf</url-pattern> <url-pattern>*.xhtml</url-pattern> </servlet-mapping> <error-page> <exception-type>java.lang.Throwable</exception-type> <location>/error.xhtml</location> </error-page> <error-page> <error-code>404</error-code> <location>/error.xhtml</location> </error-page>

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  • Hibernate Session flush behaviour [ and Spring @Transactional ]

    - by EugeneP
    I use Spring and Hibernate in a web-app, SessionFactory is injected into a DAO bean, and then this DAO is used in a Servlet through webservicecontext. DAO methods are transactional, inside one of the methods I use ... getCurrentSession().save(myObject); One servlet calls this method with an object passed. The update seems to not be flushed at once, it takes about 5 seconds to see the changes in the database. The servlet's method in which that DAO's update method is called, takes a fraction of second to complete. After the @Transactional method of DAO is completed, flushing may NOT happen ? It does not seem to be a rule [ I already see it ]. Then the question is this: what to do to force the session to flush after every DAO method? It may not be a good thing to do, but talking about a Service layer, some methods must end with immediate flush, and Hibernate Session behavior is not predictable. So what to do to guarantee that my @Transactional method persists all the changes after the last line of that method code? getCurrentSession().flush() is the only solution? p.s. I read somewhere that @Transactional IS ASSOCIATED with a DB Transaction. Method returns, transaction must be committed. I do not see this happens.

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  • Hibernate many-to-one - bad usage?

    - by DaveA
    Just trying out Hibernate (with Annotations) and I'm having problems with my mappings. I have two entity classes, AudioCD and Artist. @Entity public class AudioCD implements CatalogItem { @Id @GeneratedValue(strategy = GenerationType.AUTO) private int id; private String title; @ManyToOne(cascade = { CascadeType.ALL }, optional = false) private Artist artist; .... } @Entity @Table(uniqueConstraints = { @UniqueConstraint(columnNames = { "name" }) }) public class Artist { @Id @GeneratedValue(strategy = GenerationType.AUTO) private int id; @Column(nullable = false) private String name; ..... } I get AudioCD objects from an external source. When I try to persist the AudioCD the Artist gets persisted as well, just like I want to happen. If I try persisting another different CD, but Artist already exists I get errors due to constraint violations. I want Hibernate to recognise that the Artist already exists and shouldn't be inserted again. Can this be done via annotations? Or do I have to manage the persistence of the AudioCD and Artist seperately?

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  • hibernate empty collection in component

    - by Jurgen H
    I have a component mapped using Hibernate. If all fields in the component in the database are null, the component itself is set to null by hibernate. This is the expected behavior and also what I need. The problem I have, is that when I add a bag to that component, the bag is initialized to an empty list. This means the component has a non null value... resulting in the component being created. Any idea how to fix this? <class name="foo.bar.Entity" table="Entity"> <id name="id" column="id"> <generator class="native" /> </id> <property name="departure" column="departure_time" /> <property name="arrival" column="arrival_time" /> <component name="statistics"> <bag name="linkStatistics" lazy="false" cascade="all" > <key column="entity_id" not-null="true" /> <one-to-many class="foo.bar.LinkStatistics" /> </bag> <property name="loggedTime" column="logged_time" /> ... </component> A criteria with Restirctions.isNull("statistics") does return the expected values.

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  • Hibernate CreateSQL Query Problem

    - by Shaded
    Hello All I'm trying to use hibernates built in createsql function but it seems that it doesn't like the following query. List =hibernateSession.createSQLQuery("SELECT number, location FROM table WHERE other_number IN (SELECT f.number FROM table2 AS f JOIN table3 AS g on f.number = g.number WHERE g.other_number = " + var + ") ORDER BY number").addEntity(Table.class).list(); I have a feeling it's from the nested select statement, but I'm not sure. The inner select is used elsewhere in the code and it returns results fine. This is my mapping for the first table: <hibernate-mapping> <class name="org.efs.openreports.objects.Table" table="table"> <id name="id" column="other_number" type="java.lang.Integer"> <generator class="native"/> </id> <property name="number" column="number" not-null="true" unique="true"/> <property name="location" column="location" not-null="true" unique="true"/> </class> </hibernate-mapping> And the .java public class Table implements Serializable { private Integer id;//panel_facility private Integer number; private String location; public Table() { } public void setId(Integer id) { this.id = id; } public Integer getId() { return id; } public void setNumber(Integer number) { this.number = number; } public Integer number() { return number; } public String location() { return location; } public void setLocation(String location) { this.location = location; } } Any suggestions? Edit (Added mapping)

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  • hibernate annotation bi-directional mapping

    - by smithystar
    I'm building a web application using Spring framework and Hibernate with annotation and get stuck with a simple mapping between two entities. I'm trying to create a many-to-many relationship between User and Course. I followed one of the Hibernate tutorials and my implementation is as follows: User class: @Entity @Table(name="USER") public class User { private Long id; private String email; private String password; private Set<Course> courses = new HashSet<Course>(0); @Id @GeneratedValue @Column(name="USER_ID") public Long getId() { return id; } public void setId(Long id) { this.id = id; } @Column(name="USER_EMAIL") public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } @Column(name="USER_PASSWORD") public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @ManyToMany(cascade = CascadeType.ALL) @JoinTable(name = "USER_COURSE", joinColumns = { @JoinColumn(name = "USER_ID") }, inverseJoinColumns = { @JoinColumn(name = "COURSE_ID") }) public Set<Course> getCourses() { return courses; } public void setCourses(Set<Course> courses) { this.courses = courses; } } Course class: @Entity @Table(name="COURSE") public class Course { private Long id; private String name; @Id @GeneratedValue @Column(name="COURSE_ID") public Long getId() { return id; } public void setId(Long id) { this.id = id; } @Column(name="NAME") public String getName() { return name; } public void setName(String name) { this.name = name; } } The problem is that this implementation only allows me to go one way user.getCourses() What do I need to change, so I can go in both directions? user.getCourses() course.getUsers() Any help would be appreciated.

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  • Hibernate 1:M relationship ,row order, constant values table and concurrency

    - by EugeneP
    table A and B need to have 1:M relationship a and b are added during application runtime, so A created, then say 4 B's created. Each B instance has to come in order, so that I could later extract them in the same order as I added them. The app will be a web-app running on Tomcat, so 10 instances may work simultaneously. So my question are: 1) How to preserve inserting order, so that I could extract B instances that A references in the same order as I persisted them. That's tricky, because we add to a Collection and then it gets saved (am I right?). So, it depends on how Hibernate saves it, what if it changes the order in what we added instances? I've seen something like LIST instead of SET when describing relationships, is that what I need? 2) How to add a 3-rd column to B so that I could differentiate the instances, something like SEX(M,F,U) in B table. Do I need a special table, or there's and easy way to describe constants in Hibernate. What do you recommend? 3) Talking about concurrency, what methods do you recommend to use? There should be no collisions in the db and as you see, there might easily be some if rows are not inserted (PK added) right where it is invoked without delays ?

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  • How to use JOIN using Hibernate's session.createSQLQuery()

    - by javauser71
    Hi All, I have two Entity (tables) - Employee & Project. An Employee can have multiple Projects. Project table's CREATOR_ID field refers to Employee table's ID field. Employee entity maintains a list of Project. Using EntityManager following query works fine - "entityManager.createQuery("select e from EmployeeDTO e, ProjectDTO p where p.id = ?1 and p.creator.id=e.id"); But since I have the LAZY association relationship, I get error: "Could not initialize proxy - no Session" if I try to access Project info from Employee entity. This is expected and so I am using Hibernate's Session to create query as shown below. Session session = HibernateUtil.getSessionFactory().openSession(); org.hibernate.Query q = session.createSQLQuery("SELECT E FROM EMPLOYEE_TAB E, PROJECT_TAB P WHERE P.ID = " + projectId + " AND P.CREATOR_ID = E.ID") .addEntity("EmployeeDTO ", EmployeeDTO.class) .addEntity("ProjectDTO", ProjectDTO.class); But I get error like: "Column 'E' is either not in any table in the FROM list or appears within a join specification and is outside the scope of the join specification..." Can anyone suggest what will be the right JOIN syntax for such case? If I use ("SELECT * FROM EMPLOYEE_TAB E, ........") - it gives other error: "java.lang.ClassCastException: [Ljava.lang.Object; cannot be cast to com.im.server.dto.EmployeeDTO". Thanks in advance.

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  • Interfaces with hibernate annotations

    - by molleman
    Hello i am wondering how i would be able to annotate an interface @Entity @Table(name = "FOLDER_TABLE") public class Folder implements Serializable, Hierarchy { @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(name = "folder_id", updatable = false, nullable = false) private int fId; @Column(name = "folder_name") private String folderName; @OneToMany(cascade = CascadeType.ALL) @JoinTable(name = "FOLDER_JOIN_FILE_INFORMATION_TABLE", joinColumns = { @JoinColumn(name = "folder_id") }, inverseJoinColumns = { @JoinColumn(name = "file_information_id") }) private List< Hierarchy > fileInformation = new ArrayList< Hierarchy >(); above and below are 2 classes that implement an interface called Hierarchy, the folder class has a list of Hierarchyies being a folder or a fileinformation class @Entity @Table(name = "FILE_INFORMATION_TABLE") public class FileInformation implements Serializable, Hierarchy { @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(name = "file_information_id", updatable = false, nullable = false) private int ieId; @Column (name = "location") private String location; i have serached the web for someway to annotate or a workaround but i cannot map the interface which is simply this public interface Hierarchy { } i get a mapping exeception on the List of hierarchyies with a folder but i dont know how to map the class correctly

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  • mappedBy reference an unknown target entity property - hibernate error

    - by tommy
    first, my classes: User package com.patpuc.model; import java.util.List; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.Id; import javax.persistence.OneToMany; import javax.persistence.Table; import com.patpuc.model.RolesMap; @Entity @Table(name = "users") public class User { @Id @Column(name = "USER_ID", unique = true, nullable = false) private int user_id; @Column(name = "NAME", nullable = false) private String name; @Column(name = "SURNAME", unique = true, nullable = false) private String surname; @Column(name = "USERNAME_U", unique = true, nullable = false) private String username_u; // zamiast username @Column(name = "PASSWORD", unique = true, nullable = false) private String password; @Column(name = "USER_DESCRIPTION", nullable = false) private String userDescription; @Column(name = "AUTHORITY", nullable = false) private String authority = "ROLE_USER"; @Column(name = "ENABLED", nullable = false) private int enabled; @OneToMany(mappedBy = "rUser") private List<RolesMap> rolesMap; public List<RolesMap> getRolesMap() { return rolesMap; } public void setRolesMap(List<RolesMap> rolesMap) { this.rolesMap = rolesMap; } /** * @return the user_id */ public int getUser_id() { return user_id; } /** * @param user_id * the user_id to set */ public void setUser_id(int user_id) { this.user_id = user_id; } /** * @return the name */ public String getName() { return name; } /** * @param name * the name to set */ public void setName(String name) { this.name = name; } /** * @return the surname */ public String getSurname() { return surname; } /** * @param surname * the surname to set */ public void setSurname(String surname) { this.surname = surname; } /** * @return the username_u */ public String getUsername_u() { return username_u; } /** * @param username_u * the username_u to set */ public void setUsername_u(String username_u) { this.username_u = username_u; } /** * @return the password */ public String getPassword() { return password; } /** * @param password * the password to set */ public void setPassword(String password) { this.password = password; } /** * @return the userDescription */ public String getUserDescription() { return userDescription; } /** * @param userDescription * the userDescription to set */ public void setUserDescription(String userDescription) { this.userDescription = userDescription; } /** * @return the authority */ public String getAuthority() { return authority; } /** * @param authority * the authority to set */ public void setAuthority(String authority) { this.authority = authority; } /** * @return the enabled */ public int getEnabled() { return enabled; } /** * @param enabled * the enabled to set */ public void setEnabled(int enabled) { this.enabled = enabled; } @Override public String toString() { StringBuffer strBuff = new StringBuffer(); strBuff.append("id : ").append(getUser_id()); strBuff.append(", name : ").append(getName()); strBuff.append(", surname : ").append(getSurname()); return strBuff.toString(); } } RolesMap.java package com.patpuc.model; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.ManyToOne; import javax.persistence.Table; import com.patpuc.model.User; @Entity @Table(name = "roles_map") public class RolesMap { private int rm_id; private String username_a; private String username_l; //private String username_u; private String password; private int role_id; @ManyToOne @JoinColumn(name="username_u", nullable=false) private User rUser; public RolesMap(){ } /** * @return the user */ public User getUser() { return rUser; } /** * @param user the user to set */ public void setUser(User rUser) { this.rUser = rUser; } @Id @Column(name = "RM_ID", unique = true, nullable = false) public int getRmId() { return rm_id; } public void setRmId(int rm_id) { this.rm_id = rm_id; } @Column(name = "USERNAME_A", unique = true) public String getUsernameA() { return username_a; } public void setUsernameA(String username_a) { this.username_a = username_a; } @Column(name = "USERNAME_L", unique = true) public String getUsernameL() { return username_l; } public void setUsernameL(String username_l) { this.username_l = username_l; } @Column(name = "PASSWORD", unique = true, nullable = false) public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @Column(name = "ROLE_ID", unique = true, nullable = false) public int getRoleId() { return role_id; } public void setRoleId(int role_id) { this.role_id = role_id; } } when i try run this on server i have exception like this: Error creating bean with name 'SessionFactory' defined in ServletContext resource [/WEB-INF/classes/baseBeans.xml]: Invocation of init method failed; nested exception is org.hibernate.AnnotationException: mappedBy reference an unknown target entity property: com.patpuc.model.RolesMap.users in com.patpuc.model.User.rolesMap But i don't exaclu know what i'm doing wrong. Can somebody help me fix this problem?

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  • Ignore Hibernate @Where annotation

    - by Zecrates
    I have an Entity which has an association to another Entity annotated with @Where, like so public class EntityA { @OneToMany @Where(...) private List<EntityB> entityBList; } Recently the inevitable has happened, I need to load EntityB's that don't conform to the @Where clause. I could remove the @Where annotation, but it is used a lot, so ideally I don't want to do that. Apart from loading the list of EntityB's manually, with another query, what are my options? Can I tell Hibernate to ignore the @Where annotation?

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  • question on database query using hibernate in java with annotations

    - by molleman
    Hello, simple question regarding HQL(Hibernate query language) so i have user class , that can hold a list of Projects, how do i take this out of the database depending on a username, this is how i take out my user String username = "stephen"; YFUser user = (YFUser) session.createQuery("select u FROM YFUser u where u.username = :username").setParameter("username", name).uniqueResult(); but i want to take out the list of projects here is the projects list within the class YFUser(my user class); how would i query the database to get this list of projects @Entity @Table(name = "yf_user_table") public class YFUser implements Serializable,ILightEntity { ......... @OneToMany(cascade = CascadeType.ALL,fetch = FetchType.LAZY) @JoinTable(name = "YFUSER_JOIN_PROJECT", joinColumns = { @JoinColumn(name = "user_id") }, inverseJoinColumns = { @JoinColumn(name = "project_id") }) private List<Project> projects = new ArrayList<Project>();

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  • Simplest one-to-many Map case in Hibernate doesn't work in MySQL

    - by Malvolio
    I think this is pretty much the simplest case for mapping a Map (that is, an associative array) of entities. @Entity @AccessType("field") class Member { @Id protected long id; @OneToMany(cascade = CascadeType.ALL, fetch=FetchType.LAZY) @MapKey(name = "name") private Map<String, Preferences> preferences = new HashMap<String, Preferences>(); } @Entity @AccessType("field") class Preferences { @ManyToOne Member member; @Column String name; @Column String value; } This looks like it should work, and it does, in HSQL. In MySQL, there are two problems: First, it insists that there be a table called Members_Preferences, as if this were a many-to-many relationship. Second, it just doesn't work: since it never populates Members_Preferences, it never retrieves the Preferences. [My theory is, since I only use HSQL in memory-mode, it automatically creates Members_Preferences and never really has to retrieve the preferences map. In any case, either Hibernate has a huge bug in it or I'm doing something wrong.]

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  • Mapping enum to a table with hibernate annotation

    - by Thierry-Dimitri Roy
    I have a table DEAL and a table DEAL_TYPE. I would like to map this code: public class Deal { DealType type; } public enum DealType { BASE("Base"), EXTRA("Extra"); } The problem is that the data already exist in the database. And I'm having a hard time mapping the classes to the database. The database looks something like that: TABLE DEAL { Long id; Long typeId; } TABLE DEAL_TYPE { Long id; String text; } I know I could use a simple @OneToMany relationship from deal to deal type, but I would prefer to use an enum. Is this possible? I almost got it working by using a EnumType.ORDINAL type. But unfortunately, my IDs in my deal type table are not sequential, and do not start at 1. Any suggestions?

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  • Howto check if a object is connected to another in hibernate

    - by codevourer
    Imagine two domain object classes, A and B. A has a bidirectional one-to-many relationship to B. A is related to thousands of B. The relations must be unique, it's not possible to have a duplicate. To check if an instance of B is already connected to a given instance of A, we could perform an easy INNER JOIN but this will only ensure the already persisted relations. What about the current transient relations? class A { @OneToMany private List<B> listOfB; } If we access the listOfB and perform a check of contains() this will fetch all the connected instances of B lazy from the datasource. I only want to validate them by their primary-key. Is there an easy solution where I can do things like "Does this instance of A is connected with this instance of B?" Without loading all these data into memory and perform a based on collections?

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  • 1:M relationship in Hibernate and cascading operations

    - by EugeneP
    Table SUBCOURSE references COURSE COURSE(id, name) SUBCOURSE(id, course_id, name) So, 1:M. Hibernate generates for Course: @OneToMany(fetch = FetchType.LAZY, mappedBy = "course", cascade = CascadeType.ALL) public Set getSubCourses() { return this.subCourses; } for Subcourse it generates @ManyToOne(fetch = FetchType.LAZY) @JoinColumn(name = "course_id", nullable = false) public Course getCourse() { return this.course; } Now the problem is that cascading does not work as expected. I want to create a collection of SubCourse objects (Set), fill it and then bind it to setSubCourses() of Course object. Though, having ManyToOne thing in a Subcourses table, I need to manually setCourse() before adding to collection on each object. If I do not do so, an exception is raised. What can you recommend me?

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  • Optional parameters with named query in Hibernate?

    - by Ickster
    Is there any way to specify optional parameters (such as when search parameters are provided from a form and not all parameters are required) in a named query when using Hibernate? I'm using a native SQL query, but the question is probably applicable to named HQL queries as well. I'm pretty sure the answer to this is 'no', but I haven't find the definitive answer in the documentation yet.

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  • Storing Objects in columns using Hibernate JPA

    - by user210791
    Is it possible to store something like the following using only one table? Right now, what hibernate will do is create two tables, one for Families and one for people. I would like for the familymembers object to be serialized into the column in the database. @Entity(name = "family") class Family{ private final List<Person> familyMembers; } class Person{ String firstName, lastName; int age; }

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  • Hibernate: Criteria vs. HQL

    - by cretzel
    What are the pros and cons of using Criteria or HQL? The Criteria API is a nice object-oriented way to express queries in Hibernate, but sometimes Criteria Queries are more difficult to understand/build than HQL. When do you use Criteria and when HQL? What do you prefer in which use cases? Or is it just a matter of taste?

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  • How to map XMLType with JPA/Hibernate

    - by Moorthy
    How to persist XMLType column via JPA/Hibernate? As per oracle documentation, there are two ways in declaring storage clause for XMLType. They are, LOB and Object-Relational. I dont want to go with LOB. I have schema and register into database. I have not have example on how to design my Entity for XMLType. Does any one know please share it?

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  • Hibernate GenericDAO for parent/child relationships and DAO/DTO patterns

    - by Marco
    Hi, I'm looking for a Generic DAO implementation in Hibernate that includes parent/child relationship management (adding, removing, getting childs, setting parents, etc). Actually the most used generic DAO on the web is the one i found on http://community.jboss.org/wiki/GenericDataAccessObjects. And also, i was looking for some DAO/DTO sample implementations and design patterns. Do you know some good resources out there?

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