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  • Using LINQ to XML, how can I join two sets of data based on ordinal position?

    - by Donald Hughes
    Using LINQ to XML, how can I join two sets of data based on ordinal position? <document> <set1> <value>A</value> <value>B</value> <value>C</value> </set1> <set2> <value>1</value> <value>2</value> <value>3</value> </set2> </document> Based on the above fragment, I would like to join the two sets together such that "A" and "1" are in the same record, "B" and "2" are in the same record, and "C" and "3" are in the same record.

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  • Cannot validate xml doc againest a xsd schema (Cannot find the declaration of element 'replyMessage

    - by Daziplqa
    Hi Guyz, I am using the following code to validate an an XML file against a XSD schema package com.forat.xsd; import java.io.IOException; import java.net.URL; import javax.xml.XMLConstants; import javax.xml.transform.Source; import javax.xml.transform.stream.StreamSource; import javax.xml.validation.Schema; import javax.xml.validation.SchemaFactory; import javax.xml.validation.Validator; import org.xml.sax.ErrorHandler; import org.xml.sax.SAXException; import org.xml.sax.SAXParseException; public class XSDValidate { public void validate(String xmlFile, String xsd_url) { try { SchemaFactory factory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI); Schema schema = factory.newSchema(new URL(xsd_url)); Validator validator = schema.newValidator(); ValidationHandler handler = new ValidationHandler(); validator.setErrorHandler(handler); validator.validate(getSource(xmlFile)); if (handler.errorsFound == true) { System.err.println("Validation Error : "+ handler.exception.getMessage()); }else { System.out.println("DONE"); } } catch (SAXException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } } private Source getSource(String resource) { return new StreamSource(XSDValidate.class.getClassLoader().getResourceAsStream(resource)); } private class ValidationHandler implements ErrorHandler { private boolean errorsFound = false; private SAXParseException exception; public void error(SAXParseException exception) throws SAXException { this.errorsFound = true; this.exception = exception; } public void fatalError(SAXParseException exception) throws SAXException { this.errorsFound = true; this.exception = exception; } public void warning(SAXParseException exception) throws SAXException { } } /* * Test */ public static void main(String[] args) { new XSDValidate().validate("com/forat/xsd/reply.xml", "https://ics2wstest.ic3.com/commerce/1.x/transactionProcessor/CyberSourceTransaction_1.53.xsd"); // return error } } As appears, It is a standard code that try to validate the following XML file: <?xml version="1.0" encoding="UTF-8"?> <replyMessage xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <merchantReferenceCode>XXXXXXXXXXXXX</merchantReferenceCode> <requestID>XXXXXXXXXXXXX</requestID> <decision>XXXXXXXXXXXXX</decision> <reasonCode>XXXXXXXXXXXXX</reasonCode> <requestToken>XXXXXXXXXXXXX </requestToken> <purchaseTotals> <currency>XXXXXXXXXXXXX</currency> </purchaseTotals> <ccAuthReply> <reasonCode>XXXXXXXXXXXXX</reasonCode> <amount>XXXXXXXXXXXXX</amount> <authorizationCode>XXXXXXXXXXXXX</authorizationCode> <avsCode>XXXXXXXXXXXXX</avsCode> <avsCodeRaw>XXXXXXXXXXXXX</avsCodeRaw> <authorizedDateTime>XXXXXXXXXXXXX</authorizedDateTime> <processorResponse>0XXXXXXXXXXXXX</processorResponse> <authRecord>XXXXXXXXXXXXX </authRecord> </ccAuthReply> </replyMessage> Against the following XSD : https://ics2wstest.ic3.com/commerce/1.x/transactionProcessor/CyberSourceTransaction_1.53.xsd The error is : Validation Error : cvc-elt.1: Cannot find the declaration of element 'replyMessage'. Could you please help me!

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  • How do I return pure XML from asmx web service?

    - by User
    I want an asmx webservice with a method GetPeople() that returns the following XML (NOT a SOAP response): <People> <Person> <FirstName>Sara</FirstName> <LastName>Smith</LastName> </Person> <Person> <FirstName>Bill</FirstName> <LastName>Wilson</LastName> </Person> <People/> How can I do this?

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  • .NET and XML: How can I read nested namespaces (<abc:xyz:name attr="value"/>)?

    - by Entrase
    Suppose there is an element in XML data: <abc:xyz:name attr="value"/> I'm trying to read it with XmlReader. The problem is that I get XmlException that says The ‘:’ character, hexadecimal value 0x3A, cannot be included in a name I have already declared "abc" namespace. I have also tried adding "abc:xyz" and "xyz" namespaces. But this doesn't help at all. I could replace some text before parsing but there may be some more elegant solution. So what should I do? Here is my code: XmlReaderSettings settings = new XmlReaderSettings() NameTable nt = new NameTable(); XmlNamespaceManager nsmgr = new XmlNamespaceManager(nt); nsmgr.AddNamespace("abc", ""); nsmgr.AddNamespace("xyz", ""); XmlParserContext context = new XmlParserContext(null, nsmgr, null, XmlSpace.None); // So this reader can't read <abc:xyz:name attr="value"/> XmlReader reader = XmlReader.Create(path, settings, context);“

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  • Deleting xml file using radio value

    - by ???? ???
    i using php to delete file, but i got table loop like this: <table border="0" width="100%" cellpadding="0" cellspacing="0" id="product-table"> <tr class="bg_tableheader"> <th class="table-header-check"><a id="toggle-all" ></a> </th> <th class="table-header-check"><a href="#"><font color="white">Username</font></a> </th> <th class="table-header-check"><a href="#"><font color="white">First Name</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Last Name</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Email</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Group</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Birthday</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Gender</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Age</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Country</font></a></th> </tr> <?php $files = glob('users/*.xml'); foreach($files as $file){ $xml = new SimpleXMLElement($file, 0, true); echo ' <tr> <td></td> <form action="" method="post"> <td class="alternate-row1"><input type="radio" name="file_name" value="'. basename($file, '.xml') .'" />'. basename($file, '.xml') .'</td> <td>'. $xml->name .'&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp</td> <td class="alternate-row1">'. $xml->lastname .'</td> <td>'. $xml->email .'</td> <td class="alternate-row1">'. $xml->level .'</td> <td>'. $xml->birthday .'</td> <td class="alternate-row1">'. $xml->gender .'</td> <td>'. $xml->age .'</td> <td class="alternate-row1">'. $xml->country .'</td> </tr>'; } ?> </table> </div> <?php if(isset($_POST['file_name'])){ unlink('users/'.$_POST['file_name']); } ?> <input type="submit" value="Delete" /> </form> so as you can see i got radio value set has basename (xml file name) but from some reason it not working, any idea why is that? Thanks in advance.

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  • Retrieve XML from URL

    - by Pl4za
    I am having some problems retrieving a xml from url with the following code: private static String getAlbumArt(String artistName, String albumName){ try{ XMLParser xml_parser = new XMLParser(); String xml = xml_parser.getXmlFromUrl(getAlbumURL(artistName, albumName)); Document doc = xml_parser.getDomElement(xml); NodeList N = doc.getElementsByTagName("album"); Node node = N.item(0); NodeList N2 = node.getChildNodes(); System.out.println("1------"); for (int i = 0; i < N2.getLength(); i++) { Node detailNode = N2.item(i); if (detailNode.getNodeType() == Node.ELEMENT_NODE) { System.out.println("2------"); if (detailNode.getNodeName().equalsIgnoreCase("image")) { String sizeVal = ((Element) detailNode).getAttribute("size"); String url = detailNode.getTextContent(); if (sizeVal.equalsIgnoreCase("large")) { return url; } } } } } catch (Exception e){ } return null; } The xml function which i call in the above code: public String getXmlFromUrl(String url) { String xml = null; try { DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); xml = EntityUtils.toString(httpEntity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return xml; } getAlbumURL: public static String getAlbumURL(String artist, String album){ return URL_METHOD + METHOD_GETALBUM + AMPERSAND + API_KEY + AMPERSAND + PARAM_ARTIST + artist + AMPERSAND + PARAM_ALBUM + album; } XMLparser: public class XMLParser { // constructor public XMLParser() { } //Get XML from URL public String getXmlFromUrl(String url) { String xml = null; try { DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); xml = EntityUtils.toString(httpEntity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return xml; } //Get dom element public Document getDomElement(String xml){ Document doc = null; DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); try { DocumentBuilder db = dbf.newDocumentBuilder(); InputSource is = new InputSource(); is.setCharacterStream(new StringReader(xml)); doc = db.parse(is); } catch (ParserConfigurationException e) { Log.e("Error: ", e.getMessage()); return null; } catch (SAXException e) { Log.e("Error: ", e.getMessage()); return null; } catch (IOException e) { Log.e("Error: ", e.getMessage()); return null; } return doc; } //Get nod element public final String getElementValue(Node elem ) { Node child; if( elem != null){ if (elem.hasChildNodes()){ for( child = elem.getFirstChild(); child != null; child = child.getNextSibling() ){ if( child.getNodeType() == Node.TEXT_NODE ){ return child.getNodeValue(); } } } } return ""; } //Get element value public String getValue(Element item, String str) { NodeList nlList = item.getElementsByTagName(str).item(0).getChildNodes(); Node nValue = (Node) nlList.item(0); return nValue.getNodeValue(); } } Any ideas ? I seriously don't know what is wrong.. I used this before and it worked.

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  • XML Schema - how do you conditionally require address elements? (street, city, state, etc)

    - by Sly
    If an address can be composed of child elements: Street, City, State, PostalCode...how do you allow this XML: <Address> <Street>Somestreet</Street> <PostalCode>zip</PostalCode> </Address> and allow this: <Address> <Street>Somestreet</Street> <City>San Jose</City> <State>CA</State> </Address> but not this: <Address> <Street>Somestreet</Street> <City>San Jose</City> </Address> What schema will do such things!?

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  • Web.xml: Are url-pattern tags relative to each other?

    - by sixtyfootersdude
    <servlet-mapping> <servlet-name>myName</servlet-name> <url-pattern>/aName</url-pattern> </servlet-mapping> <security-constraint> <web-resource-collection> ... <url-pattern> /* </url-pattern> </web-resource-collection> ... </security-constraint> This is an excerpt from web.xml (using it to configure a jboss/tomcat webservice). Just wondering if the url-pattern in web-resource-collection is relative to the url-pattern in servlet-mapping.

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  • How could I do something like this in a XML schema?

    - by chobo2
    Hi I want to mass create some users and I want to set the users timezone automatically. However I am using timezones generated by this Dictionary<string, TimeZoneInfo> storeZoneName = TimeZoneInfo.GetSystemTimeZones().ToDictionary(z => z.DisplayName); So I need the names to be exactly like the ones this list returns. So can I put like a constraint on that xml node that the name has to exactly match one of the names. So I am guessing I will need to write this list somewhere in the file and that's what I am not sure if you can do something like that in a schema.

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  • Web.xml: Are url-pattern tags relitive to each other?

    - by sixtyfootersdude
    <servlet-mapping> <servlet-name>myName</servlet-name> <url-pattern>/aName</url-pattern> </servlet-mapping> <security-constraint> <web-resource-collection> ... <url-pattern> /* </url-pattern> </web-resource-collection> ... </security-constraint> This is an excerpt from web.xml (using it to configure a jboss/tomcat webservice). Just wondering if the url-pattern in web-resource-collection is relative to the url-pattern in servlet-mapping.

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  • how to filter data from xml file for displaying only selected as nodes in treeview

    - by michale
    I have an xml file named "books.xml" provided in the link "http://msdn.microsoft.com/en-us/library/windows/desktop/ms762271(v=vs.85).aspx". What my requirement was to disaplay only the <title> from xml information as nodes in tree view. But when i did the following coding its displaying all the values as nodes like "catalog" as rootnode, book as parent node for all then author,title,genre etc as nodes but i want only root node catalogue and title as nodes not even book. Can any body guide me what modification i need to do in the exisitng logic for displaying title as nodes OpenFileDialog dlg = new OpenFileDialog(); dlg.Title = "Open XML document"; dlg.Filter = "XML Files (*.xml)|*.xml"; dlg.FileName = Application.StartupPath + "\\..\\..\\Sample.xml"; if (dlg.ShowDialog() == DialogResult.OK) { try { //Just a good practice -- change the cursor to a //wait cursor while the nodes populate this.Cursor = Cursors.WaitCursor; //First, we'll load the Xml document XmlDocument xDoc = new XmlDocument(); xDoc.Load(dlg.FileName); //Now, clear out the treeview, //and add the first (root) node treeView1.Nodes.Clear(); treeView1.Nodes.Add(new TreeNode(xDoc.DocumentElement.Name)); TreeNode tNode = new TreeNode(); tNode = (TreeNode)treeView1.Nodes[0]; //We make a call to addTreeNode, //where we'll add all of our nodes addTreeNode(xDoc.DocumentElement, tNode); //Expand the treeview to show all nodes treeView1.ExpandAll(); } catch (XmlException xExc) //Exception is thrown is there is an error in the Xml { MessageBox.Show(xExc.Message); } catch (Exception ex) //General exception { MessageBox.Show(ex.Message); } finally { this.Cursor = Cursors.Default; //Change the cursor back } }} //This function is called recursively until all nodes are loaded private void addTreeNode(XmlNode xmlNode, TreeNode treeNode) { XmlNode xNode; TreeNode tNode; XmlNodeList xNodeList; if (xmlNode.HasChildNodes) //The current node has children { xNodeList = xmlNode.ChildNodes; for (int x = 0; x <= xNodeList.Count - 1; x++) //Loop through the child nodes { xNode = xmlNode.ChildNodes[x]; treeNode.Nodes.Add(new TreeNode(xNode.Name)); tNode = treeNode.Nodes[x]; addTreeNode(xNode, tNode); } } else //No children, so add the outer xml (trimming off whitespace) treeNode.Text = xmlNode.OuterXml.Trim(); }

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  • How can I create the XML::Simple data structure using a Perl XML SAX parser?

    - by DVK
    Summary: I am looking a fast XML parser (most likely a wrapper around some standard SAX parser) which will produce per-record data structure 100% identical to those produced by XML::Simple. Details: We have a large code infrastructure which depends on processing records one-by-one and expects the record to be a data structure in a format produced by XML::Simple since it always used XML::Simple since early Jurassic era. An example simple XML is: <root> <rec><f1>v1</f1><f2>v2</f2></rec> <rec><f1>v1b</f1><f2>v2b</f2></rec> <rec><f1>v1c</f1><f2>v2c</f2></rec> </root> And example rough code is: sub process_record { my ($obj, $record_hash) = @_; # do_stuff } my $records = XML::Simple->XMLin(@args)->{root}; foreach my $record (@$records) { $obj->process_record($record) }; As everyone knows XML::Simple is, well, simple. And more importantly, it is very slow and a memory hog—due to being a DOM parser and needing to build/store 100% of data in memory. So, it's not the best tool for parsing an XML file consisting of large amount of small records record-by-record. However, re-writing the entire code (which consist of large amount of "process_record"-like methods) to work with standard SAX parser seems like an big task not worth the resources, even at the cost of living with XML::Simple. I'm looking for an existing module which will probably be based on a SAX parser (or anything fast with small memory footprint) which can be used to produce $record hashrefs one by one based on the XML pictured above that can be passed to $obj->process_record($record) and be 100% identical to what XML::Simple's hashrefs would have been. I don't care much what the interface of the new module is; e.g whether I need to call next_record() or give it a callback coderef accepting a record.

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  • XML pass values to timer, AS3

    - by VideoDnd
    My timer has three variables that I can trace to the output window, but don't know how to pass them to the timer. How to I pass the XML values to my timer? Purpose I want to test with an XML document, before I try connecting it to an XML socket. myXML <?xml version="1.0" encoding="utf-8"?> <SESSION> <TIMER TITLE="speed">100</TIMER> <COUNT TITLE="starting position">-77777</COUNT> <FCOUNT TITLE="ramp">1000</FCOUNT> </SESSION> myFlash //myTimer 'instance of mytext on stage' /* fields I want to change with XML */ //CHANGE TO 100 var timer:Timer = new Timer(10); //CHANGE TO -77777 var count:int = 0; //CHANGE TO 1000 var fcount:int = 0; timer.addEventListener(TimerEvent.TIMER, incrementCounter); timer.start(); function incrementCounter(event:TimerEvent) { count++; fcount=int(count*count/1000);//starts out slow... then speeds up mytext.text = formatCount(fcount); } function formatCount(i:int):String { var fraction:int = i % 100; var whole:int = i / 100; return ("0000000" + whole).substr(-7, 7) + "." + (fraction < 10 ? "0" + fraction : fraction); } //LOAD XML var myXML:XML; var myLoader:URLLoader = new URLLoader(); myLoader.load(new URLRequest("time.xml")); myLoader.addEventListener(Event.COMPLETE, processXML); //PARSE XML function processXML(e:Event):void { myXML = new XML(e.target.data); trace(myXML.ROGUE.*); trace(myXML); //TEXT var text:TextField = new TextField(); text.text = myXML.TIMER.*; text.textColor = 0xFF0000; addChild(text); } RESOURCES OReilly's ActionScript 3.0 Cookbook, Chapter 12 Strings, Chapter 20 XML

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  • Parsing XML with the PHP XMLReader

    - by coffeecoder
    Hi Guys, I am writing program that reads in some XML from the $_POST variable and then parses using the PHP XMLReader and the data extracted input into a database. I am using the XMLReader as the XML supplied will more than likely be too big to place into memory. However I am having some issues, my XML and basic code as are follows: '<?xml version="1.0"?> <data_root> <data> <info>value</info> </data> <action>value</action> </data_root>' $request = $_REQUEST['xml']; $reader = new XMLReader(); $reader->XML($request); while($reader->read()){ //processing code } $reader->close() My problem is that the code will work perfectly if the XML being passed does not have the <?xml version="1.0"?> line, but if i include it, and it will be included when the application goes into a live production environment, the $reader->read() code for the while loop does not work and the XML is not parsed within the while loop. Has anyone seen similar behaviour before or knows why this could be happening? Thanks in advance.

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  • Will JSON replace XML as a data format?

    - by 13ren
    When I first saw XML, I thought it was basically a representation of trees. Then I thought: the important thing isn't that it's a particularly good representation of trees, but that it is one that everyone agrees on. Just like ASCII. And once established, it's hard to displace due to network effects. The new alternative would have to be much better (maybe 10 times better) to displace it. Of course, ASCII has been (mostly) replaced by Unicode, for internationalization. According to google trends, XML has a x43 lead, but is declining - while JSON grows. Will JSON replace XML as a data format? (edited) for which tasks? for which programmers/industries? NOTES: S-expressions (from lisp) are another representation of trees, but which has not gained mainstream adoption. There are many, many other proposals, such as YAML and Protocol Buffers (for binary formats). I can see JSON dominating the space of communicating with client-side AJAX (AJAJ?), and this possibly could back-spread into other systems transitively. XML, being based on SGML, is better than JSON as a document format. I'm interested in XML as a data format. XML has an established ecosystem that JSON lacks, especially ways of defining formats (XML Schema) and transforming them (XSLT). XML also has many other standards, esp for web services - but their weight and complexity can arguably count against XML, and make people want a fresh start (similar to "web services" beginning as a fresh start over CORBA).

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  • How to read utf-8 xml from vbs and get correct character code

    - by vkjr
    I'm trying to read xml file from vbs script. Xml is encoded in utf-8 and has appropriate header From vbs script I use microsoft xmldom parser to read xml: Dim objXMLDoc Set objXMLDoc = CreateObject( "Microsoft.XMLDOM" ) objXMLDoc.load("vbs_strings.xml") Inside xml I'm trying to write character by code using &#nnn; notation. Then I read this character from vbscript and try to get it's code using Asc() function. For some characters it works fine and read code is equal to one written. But for some characters Asc() always returns code 63. What could it be? Examples: If xml contains <section>&#195;<section> and in script I have Section variable for representing this xml node then code: Asc(Section.Text) will return value 195 and it's ok. If xml contains <section>&#110;<section> then code: Asc(Section.Text) will return value 110 and it's ok. But if xml contains <section>&#130;<section> or <section>&#156;<section> or <section>&#140;<section> Asc(Section.Text) will return value 63 and it's definitely not good. Do you know why?

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  • How do you remove invalid hexadecimal characters from an XML-based data source prior to constructing

    - by Oppositional
    Is there any easy/general way to clean an XML based data source prior to using it in an XmlReader so that I can gracefully consume XML data that is non-conformant to the hexadecimal character restrictions placed on XML? Note: The solution needs to handle XML data sources that use character encodings other than UTF-8, e.g. by specifying the character encoding at the XML document declaration. Not mangling the character encoding of the source while stripping invalid hexadecimal characters has been a major sticking point. The removal of invalid hexadecimal characters should only remove hexadecimal encoded values, as you can often find href values in data that happens to contains a string that would be a string match for a hexadecimal character. Background: I need to consume an XML-based data source that conforms to a specific format (think Atom or RSS feeds), but want to be able to consume data sources that have been published which contain invalid hexadecimal characters per the XML specification. In .NET if you have a Stream that represents the XML data source, and then attempt to parse it using an XmlReader and/or XPathDocument, an exception is raised due to the inclusion of invalid hexadecimal characters in the XML data. My current attempt to resolve this issue is to parse the Stream as a string and use a regular expression to remove and/or replace the invalid hexadecimal characters, but I am looking for a more performant solution.

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  • xml declaration not being omitted from page

    - by Mark Schultheiss
    I have an XSLT transform I am using to process an XML file, inserting it into the body of my aspx page. Reference the following for background information: background on xml/xslt I have the following in my xml file: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl" xmlns:myCustomStrings="urn:customStrings"> <xsl:output method="xml" version="2.0" media-type="text/html" omit-xml-declaration="yes" indent="yes" />...unrelated stuff left out here Here is the output that is relevent: <div id="example" /> <?xml version="1.0" encoding="utf-8"?><div xmlns:myCustomStrings="urn:customStrings"><div id="imFormBody" class="imFormBody"> My question relates to the output, specifically to the <?xml version="1.0" encoding="utf-8"?> which is getting included in the output anyway. Is the issue related to the custom method I have used? If so, I don't really see the need to include the xml part as the namespace is in the div tag. Is there a way to ensure that this extra stuff gets left out as I asked it to?

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  • XML problem in the basic menu example

    - by arakn0
    Hi there, I am trying to create an app with some menus, an I am following the basic example available in the official android site: http://developer.android.com/guide/topics/ui/menus.html My problems appear when I define the menu in the XML. After creating the folder res/menu and creating the menu_option.xml file from eclipse.... The project (in general) gives an error that can be read from the Problems tab: Unparsed aapt error(s)! Check the console for output Android Packaging Problem So, changing to the Console tab to get more information about the problem, this can be read: [2010-06-02 11:35:54 - TestAudio] Error in an XML file: aborting build. [2010-06-02 11:35:54 - TestAudio] W/ResourceType(11566): Bad XML block: header size 63327 or total size -144759824 is larger than data size 0 [2010-06-02 11:35:54 - TestAudio] /home/User/workspace/TestAudio/res/menu/options_menu.xml:1: error: Error parsing XML: no element found The strange thing is that eclipse recognizes the menu items that I've defined in the XML,I can reference them in the code with no problems and my main activity builds. (and the rest of the files too). Could it be that when eclipse creates a file, for some reason, the Android SDK has problems to read it, or something similar?? The XML code is exactly the same as the one in the example, so I don't really know what is happening. The code in options_menu.xml is this: <menu xmlns:android="http://schemas.android.com/apk/res/android" <item android:id="@+id/new_game" android:title="New Game" / <item android:id="@+id/quit" android:title="Quit" / </menu Thanks in advance for your help!

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  • jQuery XML loading and then innerfade effect

    - by Ryan Max
    Hello, I think I can explain myself without code, so for brevity's sake here we go: I am using jquery to pull data from an xml and put it into a ul on the page with each xml entry as a li. This is working great! However, what I am trying to do afterwards is use the innerfade plugin to make a simple animation between each of the li's. It's not working though, as it is still just loading the static list with each item visible (whereas if innerfade was working it would only display the first....then fade into the second, etc) It's not an innerfade problem however, because if I add the list in manually to the page (not injecting it with jquery) then the innerfade works fine. I'm relatively new to DOM scripting, so I think I am missing something here. I'm not quite sure how jQuery sequences everything, and I'm having trouble phrasing my question in a search engine friendly manner so here I am. Is it possible to have jquery pull the data from xml, then inject it into the page, then have innerfade work it's magic? Or am I thinking about this the wrong way? xml code: $.ajax({ type: "GET", url: "xml/playlist.xml", dataType: "xml", success: function(xml) { $(xml).find('song').each(function(){ var name = $(this).attr('title'); var date = $(this).attr('artist'); var message = $(this).attr('path'); $('<li></li>').html('<span id="an_name">'+name+'</span><span id="an_date">'+date+'</span><span id="an_message">'+message+'</span>').appendTo('#anniversary'); }); } }); innerfade code: <script type="text/javascript"> jQuery.noConflict(); jQuery(document).ready( function(){ jQuery('#anniversary').innerfade({ speed: 1000, timeout: 5000, type: 'sequence', }); });

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  • ListView Parsing Persian xml

    - by Namikaze Minato
    I used a tutorial about listview parsing xm from internet and using LasyAdapter shows the items in listview. When I add persian characters in xml (into one of childnodes) the result is some boxes in listview (after showing the text in listview). The format of xml is UTF-8, too. I used typeface too (but didn't work). Besides when I type Pwesian into the application it shows alright but it can't show Persiann content parsed from xml. Thanks in advance. I updated the post with original XMLparser (which was the problem). public String getXmlFromUrl(String url) { String xml = null; try { // defaultHttpClient DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); xml = EntityUtils.toString(httpEntity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } // return XML return xml; } public Document getDomElement(String xml) { Document doc = null; DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); try { DocumentBuilder db = dbf.newDocumentBuilder(); InputSource is = new InputSource(); is.setCharacterStream(new StringReader(xml)); doc = db.parse(is); } catch (ParserConfigurationException e) { Log.e("Error: ", e.getMessage()); return null; } catch (SAXException e) { Log.e("Error: ", e.getMessage()); return null; } catch (IOException e) { Log.e("Error: ", e.getMessage()); return null; } return doc; }

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  • Groovy and XML: Not able to insert processing instruction

    - by rhellem
    Scenario Need to update some attributes in an existing XML-file. The file contains a XSL processing instruction, so when the XML is parsed and updated I need to add the instruction before writing it to a file again. Problem is - whatever I do - I'm not able to insert the processing instruction Based on the Java-example found at rgagnon.com I have created the code below Example code ## import groovy.xml.* def xml = '''|<something> | <Settings> | </Settings> |</something>'''.stripMargin() def document = DOMBuilder.parse( new StringReader( xml ) ) def pi = document.createProcessingInstruction('xml-stylesheet', 'type="text/xsl" href="Bp8DefaultView.xsl"'); document.insertBefore(pi, document.documentElement) println document.documentElement Creates output <?xml version="1.0" encoding="UTF-8"?> <something> <Settings> </Settings> </something> What I want <?xml version="1.0" encoding="UTF-8"?> <?xml-stylesheet type="text/xsl" href="Bp8DefaultView.xsl"?> <something> <Settings> </Settings> </something>

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  • Storing data in XML or MongoDB

    - by user766473
    Here is my usecase. 1.Have some data, which I am storing now in the xml files. The data that I am storing is not persistent i.e I would be deleting the user data once the user logs out. 2.My server communicates with the client using the XML requests and responses. So initially we decided, since we are sending the XML as response, lets store it in XML so that conversion from database to XML format time is saved. 3.Client will request for XML based on some filter conditions. So will have to use XQUERY. 4.Maximum of 100 entries will be there in an XML, atleast as of now. Now I would like to hear some advice on whether I should use XML or mongodb. My Concerns : 1. How good is it to store temporary data in mongodb and delete/take backup once done with session 2. Conversion from mongodb json format to XML. 3. Handling the changes in the schema design. Cant use any other DB than mongodb. As some persistent operation or still done on mongodb. Thanks in advance.

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