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  • Is there any difference between SQL running in code vs the MySQL command line?

    - by MJB
    I have a SQL update statement I am running from inside a PHP program. It is prepared and then executed. When I run it in PHP, it reports a constraint violation. When I run the exact same statement from the command line (which I am getting via dBug()), it works with no errors. This sounds impossible, so I keep looking for differences between the statements. The only thing I can see is that when I execute it with an array of arguments, they all appear to be chars, when some should be integers. Any suggestions for where to look? I can post the code, but that does not seem like it would be helpful, because the code works.

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  • How can I join 3 tables with mysql & php?

    - by steven
    check out the page [url]http://www.mujak.com/test/test3.php[/url] It pulls the users Post,username,xbc/xlk tags etc which is perfect... BUT since I am pulling information from a MyBB bulletin board system, its quite different. When replying, people are are allowed to change the "Thread Subject" by simplying replying and changing it. I dont want it to SHOW the changed subject title, just the original title of all posts in that thread. By default it repies with "RE:thread title". They can easily edit this and it will show up in the "Subject" cell & people wont know which thread it was posted in because they changed their thread to when replying to the post. So I just want to keep the orginial thread title when they are replying. Make sense~?? Tables:mybb_users Fields:uid,username Tables:mybb_userfields Fields:ufid Tables:mybb_posts Fields:pid,tid,replyto,subject,ufid,username,uid,message Tables:mybb_threads Fields:tid,fid,subject,uid,username,lastpost,lastposter,lastposteruid I haev tried multiple queries with no success: $result = mysql_query(" SELECT * FROM mybb_users LEFT JOIN (mybb_posts, mybb_userfields, mybb_threads) ON ( mybb_userfields.ufid=mybb_posts.uid AND mybb_threads.tid=mybb_posts.tid AND mybb_users.uid=mybb_userfields.ufid ) WHERE mybb_posts.fid=42"); $result = mysql_query(" SELECT * FROM mybb_users LEFT JOIN (mybb_posts, mybb_userfields, mybb_threads) ON ( mybb_userfields.ufid=mybb_posts.uid AND mybb_threads.tid=mybb_posts.tid AND mybb_users.uid=mybb_posts.uid ) WHERE mybb_threads.fid=42"); $result = mysql_query(" SELECT * FROM mybb_posts LEFT JOIN (mybb_userfields, mybb_threads) ON ( mybb_userfields.ufid=mybb_posts.uid AND mybb_threads.tid=mybb_posts.tid ) WHERE mybb_posts.fid=42");

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  • How to translate this 2 queries from Mysql to Postgresql? :

    - by xRobot
    How can I translate this 2 queries in postgresql ? : CREATE TABLE `example` ( `id` int(10) unsigned NOT NULL auto_increment, `from` varchar(255) NOT NULL default '0', `message` text NOT NULL, `lastactivity` timestamp NULL default '0000-00-00 00:00:00', `read` int(10) unsigned NOT NULL, PRIMARY KEY (`id`), KEY `from` (`from`) ) DEFAULT CHARSET=utf8; Query: SELECT * FROM table_1 LEFT OUTER JOIN table_2 ON ( table_1.id = table_2.id ) WHERE (table_1.lastactivity > NOW()-100);

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  • How do I update my primary key in MySQL?

    - by Wesley
    Ok, this is probably really simple, but I just can't figure it out. I have a primary key in a table that goes from 1-5,000. I need to manually update that id (for other table update purposes) so that it says 5,000-10,000. Can't I manually update this column? Please help!!! Thank you

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  • How do I update the members of a MySQL SET Type?

    - by MachinationX
    I have a table of values, with one of the columns being of type SET. If it currently has the members ('a', 'b', 'c', 'd'), how do I add 'e' to the possible values? I realize that using a SET type is a little strange, and I'm unclear why one would use it instead of a foreign key to another table with the values of the set, but I didn't design the database in question, and can't change it that much. Thanks for your help!

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  • how to compare two tables fields name with another value in mysql?

    - by I Like PHP
    I have two tables table_school school_open_time|school_close_time|school_day 8:00 AM | 9:00PM | Monday 10:00 AM | 7:00PM | Wednesday table_college college_open_time|college_close_time|college_day 10:00 AM | 8:00PM | Monday 10:00 AM | 9:00PM | Tuesday 10:00 AM | 5:00PM | Wednesday Now I want to select school_open_time school_close time, college_open_time and college_close_time according to today (means college_day=school_day=today), and also if there is no row for a specific day in any of one table then it display blank field ( LEFT JOIN , I think I can use). Please suggest me best and optimized query for this. UPDATE: if there is no open time and close time for school then college_open_time and college_close_time has to be returned( not to be filled in database,just return) as school_open_time and school_close_time. and there always must be college_open_time and college_close_time for a given day MORE UPDATE: i m using below query SELECT college_open_time,college_close_time ,school_open_time, school_close_time FROM tbl_college LEFT JOIN tbl_school ON school_owner_id=college_owner_id WHERE college_owner_id='".$_session['user_id']."' AND college_day='".date('l',time())."'"; it return single row (left hand having some value and right hand having blank value) when there is no row of a given day in table_school, BUT display seven rows with same value on left hand side(college_open_time, college_close_time) and 6 blank row on right hand side (school_open_time and school_close_time) i need only one row when both table have a row of a given day but using above query take only first row of corresponding table_school where school_owner_id is 50(let), it not see the condition that school_day name should be given day

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  • MYSQL - SQL query Getting single record for the similar records and populating other columns with which has more length

    - by Bujji
    Here is my case , I have a database table with below fields name place_code email phone address details estd others and example data if you look at the above example table First three records are talking about XYZ and place code 1020 . I want create a single record for these three records based on substring(name,1,4) place_code ( I am lucky here for all the similar records satisfies this condition and unique in the table .) For the other columns which record column length has max . For example again for the above 3 records email should be [email protected] , phone should be 657890 and details should be "testdetails" This should be done for all the table . (Some has single records and some has max 10 records ) Any help on query that helps me to get the desired result ? Thank You Regards Kiran

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  • How do I test the speed of a mySQL query?

    - by Chris
    I have a select and query like below... $sql = "SELECT * FROM notifications WHERE to_id='".$userid."' AND (alert_read != '1' OR user_read != '1') ORDER BY alert_time DESC"; $result = mysql_query($sql); how do I test how long the query took to run?

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  • MySQL: How to copy rows, but change a few fields?

    - by Andrew
    I have a large number of rows that I would like to copy, but I need to change one field. I can select the rows that I want to copy: select * from Table where Event_ID = "120" Now I want to copy all those rows and create new rows while setting the Event_ID to 155. How can I accomplish this?

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  • MySQL Query to receive random combinations from two tables.

    - by Michael
    Alright, here is my issue, I have two tables, one named firstnames and the other named lastnames. What I am trying to do here is to find 100 of the possible combinations from these names for test data. The firstnames table has 5494 entries in a single column, and the lastnames table has 88799 entries in a single column. The only query that I have been able to come up with that has some results is: select * from (select * from firstnames order by rand()) f LEFT JOIN (select * from lastnames order by rand()) l on 1=1 limit 10; The problem with this code is that it selects 1 firstname and gives every lastname that could go with it. While this is plausible, I will have to set the limit to 500000000 in order to get all the combinations possible without having only 20 first names(and I'd rather not kill my server). However, I only need 100 random generations of entries for test data, and I will not be able to get that with this code. Can anyone please give me any advice?

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  • Can anyone help me with a complex sum, 3 table join mysql query?

    - by Scarface
    Hey guys I have a query and it works fine, but I want to add another table to the mix. The invite table I want to add has two fields: username and user_invite. Much like this site, I am using a point system to encourage diligent users. The current query which is displayed below adds the up votes and down votes based on the user in question: $creator. I want to count the number of entries for that same user from the invite table, and add 50 for each row it finds to the current output/sum of my query. Is this possible with one query, or do I need two? "SELECT *, SUM(IF(points_id = \"1\", 1,0))-SUM(IF(points_id = \"2\", 1,0)) AS 'total' FROM points LEFT JOIN post ON post.post_id=points.points_id WHERE post.creator='$creator'"

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  • MySQL - Combine two fields to create a unix timestamp?

    - by Dan
    Hi, I'm trying to retrieve a UNIX timestamp from a query by combining a date and a time field in the table, however it keeps returning as zero. SELECT *, UNIX_TIMESTAMP(startdate starttime) AS start, UNIX_TIMESTAMP(enddate endtime) AS end FROM mytable; Can anyone help me out? Thanks.

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  • MySQL - accessing a table sum and compare to another table?

    - by assignment_operator
    This is for a homework assignment. I just plain don't understand how to do it. The instructions for this particular question is: List the branch name for all branches that have at least one book that has at least 4 copies on hand. Where the tables in question are: Branch: BranchName | BranchId Henry Downtown | 1 16 Riverview | 2 Henry On The Hill | 3 Inventory: BookId | BranchId | OnHand 1 | 1 | 2 2 | 3 | 4 3 | 1 | 8 4 | 3 | 1 5 | 1 | 2 6 | 2 | 3 From what I understand, I can get the number of OnHand per branch name with: SELECT BranchName, SUM(OnHand) FROM Branch B, Inventory I WHERE B.BranchId = I.BranchId GROUP BY BranchName; but I don't get how I'd do the comparison between the sum of OnHand per branch and 4. Any help would be appreciated, guys!

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  • PHP, MySQL - would results-array shuffle be quicker than "select... order by rand()"?

    - by sombe
    I've been reading a lot about the disadvantages of using "order by rand" so I don't need update on that. I was thinking, since I only need a limited amount of rows retrieved from the db to be randomized, maybe I should do: $r = $db->query("select * from table limit 500"); for($i;$i<500;$i++) $arr[$i]=mysqli_fetch_assoc($r); shuffle($arr); (i know this only randomizes the 500 first rows, be it). would that be faster than $r = $db->("select * from table order by rand() limit 500"); let me just mention, say the db tables were packed with more than...10,000 rows. why don't you do it yourself?!? - well, i have, but i'm looking for your experienced opinion. thanks!

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  • How do I drop 'NOT NULL' from a column in MySQL?

    - by Will
    A show create table command shows the following: 'columnA' varchar(6) NOT NULL DEFAULT ''; How do I modify that column so that the not null is removed? I need it to be: 'columnA' varchar(6) DEFAULT NULL; I thought the following would work, but it has no effect: ALTER TABLE tbl_name MODIFY columnA varchar(6) DEFAULT NULL;

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  • MySQL: Query to obtain recipes using all given ingredients.

    - by John_A
    hi I have the following simplified tables: CREATE TABLE recipe(id int, name varchar(25)); CREATE TABLE ingredient(name varchar(25)); CREATE TABLE uses_ingredient(recipe_id int, name varchar(25)); I want to make a query that returns all id's of recipes that contain both Chicken and Cream. I have tried SELECT recipe_id FROM uses_ingredient INNER JOIN (SELECT * FROM ingredient WHERE name="Chicken" OR name="Cream") USING (name) GROUP BY recipe_id HAVING COUNT(recipe_id) >= (SELECT COUNT(*) FROM theme); which gives me :"ERROR 1248 (42000): Every derived table must have its own alias" and is probably wrong too. Next I tried SELECT recipe_id FROM (SELECT * FROM ingredient WHERE name="Chicken" OR name="Cream") AS t INNER JOIN uses_ingredient USING (name) GROUP BY recipe_id HAVING COUNT(recipe_id)>= (SELECT COUNT(*) FROM t); which gives "ERROR 1146 (42S02): Table 'recipedb.t' doesn't exist" I want to avoid creating temporary tables including using ENGINE=MEMORY.

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