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  • How to insert values using Joins in asp.net stroed procedure?

    - by Samba Siva
    CREATE PROC [dbo].[K_HRM_Insert_VehicleAssign] @vehiclename varchar(50), @empname varchar(50), @updatedby varchar(50), @updatedon datetime as begin insert into K_MasterEmpDetails ME inner join K_HRM_Vehicle_Assign VA on VA.[empname+id] = ME.Firstname +' '+ME.Lastname+' - '+ME.kjlid as ME.Employee (VA.vehiclename,ME.Employee,VA.updatedby,VA.updatedon)values(@vehiclename,@empname, @updatedby,getdate()) end I am getting an error near ME...please help me

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  • how to make datagrid Visibility is Collapsed in codebehind

    - by prince23
    hi i have data grid. now here i am checking the condition if Companyrows.count is zero . if count is zero make data grid.visible is false. List<Employee> Companyrows = new List<Employee>(); if (Companyrows.Count == 0) { dgrdRowDetail.Visibility = "Collapsed"; // getting error // convert type 'string' to 'System.Windows.Visibility' } else { dgrdRowDetail.ItemsSource = Companyrows; } any help how to solve this issue would be great thank you

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  • Oracle join issue

    - by acadia
    Hello, I have 3 tables and I am joining these 2 tables as follows: SELECT EMP.FNAME,EMP.LNAME,EMP.AGE,EMPD.TQ,EMPD.TA,CTY.CITY_NAME FROM EMPLOYEE EMP,EMPLOYEE_DETAIL EMPD, CITY CTY WHERE EMP.EMP_ID=EMPD.EMP_ID AND EMPD_CITY_ID=CTY.CITY_ID I want to display records even if City record is not in CITY table. For eg. if City_ID record for say 10 is not in City table but there is an employee detail record with City_id 10 it should display City_name as null instead of not displaying the record at all. Appreciate your help

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  • [C#] RegEx search for two pattern strings and cut what's between

    - by gsharp
    I'm trying to write a little SQL Helper. I have a query like this stored in a string: DECLARE @V1 INT --ignore DECLARE @V11 INT DECLARE @V12 INT --endignore DECLARE @V2 INT --ignore SELECT * FROM SampleTable INNER JOIN AnotherSampleTable ...... --endignore SELECT * From Employee ORDER BY LastName My helper method should cut everything what's between --ignore and --endignore The result string should look like: DECLARE @V1 INT DECLARE @V2 INT SELECT * From Employee ORDER BY LastName How can achieve my result with RegEx?

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  • I can't able to edit my column name after saving

    - by Midhun M
    I create a new table of employee now I want to edit one of the column name in that table. I can edit but while saving a pop up window asks to save some text file. How may I resolve this? Is it possible to edit without creating a new table? The text file is /* Friday, August 22, 20144:32:53 PM User: Server: MIDHUN\SQLEXPRESS Database: LinQ Application: */ employee

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  • sql user defined function

    - by nectar
    for a table valued function in sql why cant we write sql statements inside begin and end tags like- create function dbo.emptable() returns Table as BEGIN --it throws an error return (select id, name, salary from employee) END go while in scalar valued function we can use these tags like create function dbo.countemp() returns int as begin return (select count(*) from employee) end go is there any specific rule where we should use BEGIN & END tags

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  • selecting number of rows from resultset

    - by sap
    Suppose a query "select * from employee" returns 80 rows. I need to display middle rows that is from 20th row to 50th row. I know, like to display first 20 rows we have option like "select top 20 * from employee" but if we need middle rows how to get it in MS SQL specifically. I m new to this SQL queries...Can anybody answer to this question.

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  • Is it possible to have variable find conditions for both the key and value?

    - by DarrenD
    I'm trying to pass in both the field and the value in a find call: @employee = Employee.find(:all, :conditions => [ '? = ?', params[:key], params[:value].to_i) The output is SELECT * FROM `employees` WHERE ('is_manager' = 1) Which returns no results, however when I try this directly in mysqsl using the same call without the '' around is_manager, it works fine. How do I convert my params[:key] value to a symbol so that the resulting SQL call looks like: SELECT * FROM `employees` WHERE (is_manager = 1) Thanks, D

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  • Multiple reference in SQL

    - by AGarofoli
    Hi! I'm working on a db but i'm kinda new to this so i've bumped into a problem today. I've got some tables: OFFICE, ROOM, EMPLOYEE and DOCUMENT. Document must specify the sender, which can be a single employee, an entire room or an entire office so it must have a reference to the primary keys of those tables. Should I do a "parallel" table for handle it (for example i've done one for handle the multiple recipients documents) or there is another way? Thank you

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  • Is Social Media The Vital Skill You Aren’t Tracking?

    - by HCM-Oracle
    By Mark Bennett - Originally featured in Talent Management Excellence The ever-increasing presence of the workforce on social media presents opportunities as well as risks for organizations. While on the one hand, we read about social media embarrassments happening to organizations, on the other we see that social media activities by workers and candidates can enhance a company’s brand and provide insight into what individuals are, or can become, influencers in the social media sphere. HR can play a key role in helping organizations make the most value out of the activities and presence of workers and candidates, while at the same time also helping to manage the risks that come with the permanence and viral nature of social media. What is Missing from Understanding Our Workforce? “If only HP knew what HP knows, we would be three-times more productive.”  Lew Platt, Former Chairman, President, CEO, Hewlett-Packard  What Lew Platt recognized was that organizations only have a partial understanding of what their workforce is capable of. This lack of understanding impacts the company in several negative ways: 1. A particular skill that the company needs to access in one part of the organization might exist somewhere else, but there is no record that the skill exists, so the need is unfulfilled. 2. As market conditions change rapidly, the company needs to know strategic options, but some options are missed entirely because the company doesn’t know that sufficient capability already exists to enable those options. 3. Employees may miss out on opportunities to demonstrate how their hidden skills could create new value to the company. Why don’t companies have that more complete picture of their workforce capabilities – that is, not know what they know? One very good explanation is that companies put most of their efforts into rating their workforce according to the jobs and roles they are filling today. This is the essence of two important talent management processes: recruiting and performance appraisals.  In recruiting, a set of requirements is put together for a job, either explicitly or indirectly through a job description. During the recruiting process, much of the attention is paid towards whether the candidate has the qualifications, the skills, the experience and the cultural fit to be successful in the role. This makes a lot of sense.  In the performance appraisal process, an employee is measured on how well they performed the functions of their role and in an effort to help the employee do even better next time, they are also measured on proficiency in the competencies that are deemed to be key in doing that job. Again, the logic is impeccable.  But in both these cases, two adages come to mind: 1. What gets measured is what gets managed. 2. You only see what you are looking for. In other words, the fact that the current roles the workforce are performing are the basis for measuring which capabilities the workforce has, makes them the only capabilities to be measured. What was initially meant to be a positive, i.e. identify what is needed to perform well and measure it, in order that it can be managed, comes with the unintended negative consequence of overshadowing the other capabilities the workforce has. This also comes with an employee engagement price, for the measurements and management of workforce capabilities is to typically focus on where the workforce comes up short. Again, it makes sense to do this, since improving a capability that appears to result in improved performance benefits, both the individual through improved performance ratings and the company through improved productivity. But this is based on the assumption that the capabilities identified and their required proficiencies are the only attributes of the individual that matter. Anything else the individual brings that results in high performance, while resulting in a desired performance outcome, often goes unrecognized or underappreciated at best. As social media begins to occupy a more important part in current and future roles in organizations, businesses must incorporate social media savvy and innovation into job descriptions and expectations. These new measures could provide insight into how well someone can use social media tools to influence communities and decision makers; keep abreast of trends in fast-moving industries; present a positive brand image for the organization around thought leadership, customer focus, social responsibility; and coordinate and collaborate with partners. These measures should demonstrate the “social capital” the individual has invested in and developed over time. Without this dimension, “short cut” methods may generate a narrow set of positive metrics that do not have real, long-lasting benefits to the organization. How Workforce Reputation Management Helps HR Harness Social Media With hundreds of petabytes of social media data flowing across Facebook, LinkedIn and Twitter, businesses are tapping technology solutions to effectively leverage social for HR. Workforce reputation management technology helps organizations discover, mobilize and retain talent by providing insight into the social reputation and influence of the workforce while also helping organizations monitor employee social media policy compliance and mitigate social media risk.  There are three major ways that workforce reputation management technology can play a strategic role to support HR: 1. Improve Awareness and Decisions on Talent Many organizations measure the skills and competencies that they know they need today, but are unaware of what other skills and competencies their workforce has that could be essential tomorrow. How about whether your workforce has the reputation and influence to make their skills and competencies more effective? Many organizations don’t have insight into the social media “reach” their workforce has, which is becoming more critical to business performance. These features help organizations, managers, and employees improve many talent processes and decision making, including the following: Hiring and Assignments. People and teams with higher reputations are considered more valuable and effective workers. Someone with high reputation who refers a candidate also can have high credibility as a source for hires.   Training and Development. Reputation trend analysis can impact program decisions regarding training offerings by showing how reputation and influence across the workforce changes in concert with training. Worker reputation impacts development plans and goal choices by helping the individual see which development efforts result in improved reputation and influence.   Finding Hidden Talent. Managers can discover hidden talent and skills amongst employees based on a combination of social profile information and social media reputation. Employees can improve their personal brand and accelerate their career development.  2. Talent Search and Discovery The right technology helps organizations find information on people that might otherwise be hidden. By leveraging access to candidate and worker social profiles as well as their social relationships, workforce reputation management provides companies with a more complete picture of what their knowledge, skills, and attributes are and what they can in turn access. This more complete information helps to find the right talent both outside the organization as well as the right, perhaps previously hidden talent, within the organization to fill roles and staff projects, particularly those roles and projects that are required in reaction to fast-changing opportunities and circumstances. 3. Reputation Brings Credibility Workforce reputation management technology provides a clearer picture of how candidates and workers are viewed by their peers and communities across a wide range of social reputation and influence metrics. This information is less subject to individual bias and can impact critical decision-making. Knowing the individual’s reputation and influence enables the organization to predict how well their capabilities and behaviors will have a positive effect on desired business outcomes. Many roles that have the highest impact on overall business performance are dependent on the individual’s influence and reputation. In addition, reputation and influence measures offer a very tangible source of feedback for workers, providing them with insight that helps them develop themselves and their careers and see the effectiveness of those efforts by tracking changes over time in their reputation and influence. The following are some examples of the different reputation and influence measures of the workforce that Workforce Reputation Management could gather and analyze: Generosity – How often the user reposts other’s posts. Influence – How often the user’s material is reposted by others.  Engagement – The ratio of recent posts with references (e.g. links to other posts) to the total number of posts.  Activity – How frequently the user posts. (e.g. number per day)  Impact – The size of the users’ social networks, which indicates their ability to reach unique followers, friends, or users.   Clout – The number of references and citations of the user’s material in others’ posts.  The Vital Ingredient of Workforce Reputation Management: Employee Participation “Nothing about me, without me.” Valerie Billingham, “Through the Patient’s Eyes”, Salzburg Seminar Session 356, 1998 Since data resides primarily in social media, a question arises: what manner is used to collect that data? While much of social media activity is publicly accessible (as many who wished otherwise have learned to their chagrin), the social norms of social media have developed to put some restrictions on what is acceptable behavior and by whom. Disregarding these norms risks a repercussion firestorm. One of the more recognized norms is that while individuals can follow and engage with other individual’s public social activity (e.g. Twitter updates) fairly freely, the more an organization does this unprompted and without getting permission from the individual beforehand, the more likely the organization risks a totally opposite outcome from the one desired. Instead, the organization must look for permission from the individual, which can be met with resistance. That resistance comes from not knowing how the information will be used, how it will be shared with others, and not receiving enough benefit in return for granting permission. As the quote above about patient concerns and rights succinctly states, no one likes not feeling in control of the information about themselves, or the uncertainty about where it will be used. This is well understood in consumer social media (i.e. permission-based marketing) and is applicable to workforce reputation management. However, asking permission leaves open the very real possibility that no one, or so few, will grant permission, resulting in a small set of data with little usefulness for the company. Connecting Individual Motivation to Organization Needs So what is it that makes an individual decide to grant an organization access to the data it wants? It is when the individual’s own motivations are in alignment with the organization’s objectives. In the case of workforce reputation management, when the individual is motivated by a desire for increased visibility and career growth opportunities to advertise their skills and level of influence and reputation, they are aligned with the organizations’ objectives; to fill resource needs or strategically build better awareness of what skills are present in the workforce, as well as levels of influence and reputation. Individuals can see the benefit of granting access permission to the company through multiple means. One is through simple social awareness; they begin to discover that peers who are getting more career opportunities are those who are signed up for workforce reputation management. Another is where companies take the message directly to the individual; we think you would benefit from signing up with our workforce reputation management solution. Another, more strategic approach is to make reputation management part of a larger Career Development effort by the company; providing a wide set of tools to help the workforce find ways to plan and take action to achieve their career aspirations in the organization. An effective mechanism, that facilitates connecting the visibility and career growth motivations of the workforce with the larger context of the organization’s business objectives, is to use game mechanics to help individuals transform their career goals into concrete, actionable steps, such as signing up for reputation management. This works in favor of companies looking to use workforce reputation because the workforce is more apt to see how it fits into achieving their overall career goals, as well as seeing how other participation brings additional benefits.  Once an individual has signed up with reputation management, not only have they made themselves more visible within the organization and increased their career growth opportunities, they have also enabled a tool that they can use to better understand how their actions and behaviors impact their influence and reputation. Since they will be able to see their reputation and influence measurements change over time, they will gain better insight into how reputation and influence impacts their effectiveness in a role, as well as how their behaviors and skill levels in turn affect their influence and reputation. This insight can trigger much more directed, and effective, efforts by the individual to improve their ability to perform at a higher level and become more productive. The increased sense of autonomy the individual experiences, in linking the insight they gain to the actions and behavior changes they make, greatly enhances their engagement with their role as well as their career prospects within the company. Workforce reputation management takes the wide range of disparate data about the workforce being produced across various social media platforms and transforms it into accessible, relevant, and actionable information that helps the organization achieve its desired business objectives. Social media holds untapped insights about your talent, brand and business, and workforce reputation management can help unlock them. Imagine - if you could find the hidden secrets of your businesses, how much more productive and efficient would your organization be? Mark Bennett is a Director of Product Strategy at Oracle. Mark focuses on setting the strategic vision and direction for tools that help organizations understand, shape, and leverage the capabilities of their workforce to achieve business objectives, as well as help individuals work effectively to achieve their goals and navigate their own growth. His combination of a deep technical background in software design and development, coupled with a broad knowledge of business challenges and thinking in today’s globalized, rapidly changing, technology accelerated economy, has enabled him to identify and incorporate key innovations that are central to Oracle Fusion’s unique value proposition. Mark has over the course of his career been in charge of the design, development, and strategy of Talent Management products and the design and development of cutting edge software that is better equipped to handle the increasingly complex demands of users while also remaining easy to use. Follow him @mpbennett

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  • Securing an ASP.NET MVC 2 Application

    - by rajbk
    This post attempts to look at some of the methods that can be used to secure an ASP.NET MVC 2 Application called Northwind Traders Human Resources.  The sample code for the project is attached at the bottom of this post. We are going to use a slightly modified Northwind database. The screen capture from SQL server management studio shows the change. I added a new column called Salary, inserted some random salaries for the employees and then turned off AllowNulls.   The reporting relationship for Northwind Employees is shown below.   The requirements for our application are as follows: Employees can see their LastName, FirstName, Title, Address and Salary Employees are allowed to edit only their Address information Employees can see the LastName, FirstName, Title, Address and Salary of their immediate reports Employees cannot see records of non immediate reports.  Employees are allowed to edit only the Salary and Title information of their immediate reports. Employees are not allowed to edit the Address of an immediate report Employees should be authenticated into the system. Employees by default get the “Employee” role. If a user has direct reports, they will also get assigned a “Manager” role. We use a very basic empId/pwd scheme of EmployeeID (1-9) and password test$1. You should never do this in an actual application. The application should protect from Cross Site Request Forgery (CSRF). For example, Michael could trick Steven, who is already logged on to the HR website, to load a page which contains a malicious request. where without Steven’s knowledge, a form on the site posts information back to the Northwind HR website using Steven’s credentials. Michael could use this technique to give himself a raise :-) UI Notes The layout of our app looks like so: When Nancy (EmpID 1) signs on, she sees the default page with her details and is allowed to edit her address. If Nancy attempts to view the record of employee Andrew who has an employeeID of 2 (Employees/Edit/2), she will get a “Not Authorized” error page. When Andrew (EmpID 2) signs on, he can edit the address field of his record and change the title and salary of employees that directly report to him. Implementation Notes All controllers inherit from a BaseController. The BaseController currently only has error handling code. When a user signs on, we check to see if they are in a Manager role. We then create a FormsAuthenticationTicket, encrypt it (including the roles that the employee belongs to) and add it to a cookie. private void SetAuthenticationCookie(int employeeID, List<string> roles) { HttpCookiesSection cookieSection = (HttpCookiesSection) ConfigurationManager.GetSection("system.web/httpCookies"); AuthenticationSection authenticationSection = (AuthenticationSection) ConfigurationManager.GetSection("system.web/authentication"); FormsAuthenticationTicket authTicket = new FormsAuthenticationTicket( 1, employeeID.ToString(), DateTime.Now, DateTime.Now.AddMinutes(authenticationSection.Forms.Timeout.TotalMinutes), false, string.Join("|", roles.ToArray())); String encryptedTicket = FormsAuthentication.Encrypt(authTicket); HttpCookie authCookie = new HttpCookie(FormsAuthentication.FormsCookieName, encryptedTicket); if (cookieSection.RequireSSL || authenticationSection.Forms.RequireSSL) { authCookie.Secure = true; } HttpContext.Current.Response.Cookies.Add(authCookie); } We read this cookie back in Global.asax and set the Context.User to be a new GenericPrincipal with the roles we assigned earlier. protected void Application_AuthenticateRequest(Object sender, EventArgs e){ if (Context.User != null) { string cookieName = FormsAuthentication.FormsCookieName; HttpCookie authCookie = Context.Request.Cookies[cookieName]; if (authCookie == null) return; FormsAuthenticationTicket authTicket = FormsAuthentication.Decrypt(authCookie.Value); string[] roles = authTicket.UserData.Split(new char[] { '|' }); FormsIdentity fi = (FormsIdentity)(Context.User.Identity); Context.User = new System.Security.Principal.GenericPrincipal(fi, roles); }} We ensure that a user has permissions to view a record by creating a custom attribute AuthorizeToViewID that inherits from ActionFilterAttribute. public class AuthorizeToViewIDAttribute : ActionFilterAttribute{ IEmployeeRepository employeeRepository = new EmployeeRepository(); public override void OnActionExecuting(ActionExecutingContext filterContext) { if (filterContext.ActionParameters.ContainsKey("id") && filterContext.ActionParameters["id"] != null) { if (employeeRepository.IsAuthorizedToView((int)filterContext.ActionParameters["id"])) { return; } } throw new UnauthorizedAccessException("The record does not exist or you do not have permission to access it"); }} We add the AuthorizeToView attribute to any Action method that requires authorization. [HttpPost][Authorize(Order = 1)]//To prevent CSRF[ValidateAntiForgeryToken(Salt = Globals.EditSalt, Order = 2)]//See AuthorizeToViewIDAttribute class[AuthorizeToViewID(Order = 3)] [ActionName("Edit")]public ActionResult Update(int id){ var employeeToEdit = employeeRepository.GetEmployee(id); if (employeeToEdit != null) { //Employees can edit only their address //A manager can edit the title and salary of their subordinate string[] whiteList = (employeeToEdit.IsSubordinate) ? new string[] { "Title", "Salary" } : new string[] { "Address" }; if (TryUpdateModel(employeeToEdit, whiteList)) { employeeRepository.Save(employeeToEdit); return RedirectToAction("Details", new { id = id }); } else { ModelState.AddModelError("", "Please correct the following errors."); } } return View(employeeToEdit);} The Authorize attribute is added to ensure that only authorized users can execute that Action. We use the TryUpdateModel with a white list to ensure that (a) an employee is able to edit only their Address and (b) that a manager is able to edit only the Title and Salary of a subordinate. This works in conjunction with the AuthorizeToViewIDAttribute. The ValidateAntiForgeryToken attribute is added (with a salt) to avoid CSRF. The Order on the attributes specify the order in which the attributes are executed. The Edit View uses the AntiForgeryToken helper to render the hidden token: ......<% using (Html.BeginForm()) {%><%=Html.AntiForgeryToken(NorthwindHR.Models.Globals.EditSalt)%><%= Html.ValidationSummary(true, "Please correct the errors and try again.") %><div class="editor-label"> <%= Html.LabelFor(model => model.LastName) %></div><div class="editor-field">...... The application uses View specific models for ease of model binding. public class EmployeeViewModel{ public int EmployeeID; [Required] [DisplayName("Last Name")] public string LastName { get; set; } [Required] [DisplayName("First Name")] public string FirstName { get; set; } [Required] [DisplayName("Title")] public string Title { get; set; } [Required] [DisplayName("Address")] public string Address { get; set; } [Required] [DisplayName("Salary")] [Range(500, double.MaxValue)] public decimal Salary { get; set; } public bool IsSubordinate { get; set; }} To help with displaying readonly/editable fields, we use a helper method. //Simple extension method to display a TextboxFor or DisplayFor based on the isEditable variablepublic static MvcHtmlString TextBoxOrLabelFor<TModel, TProperty>(this HtmlHelper<TModel> htmlHelper, Expression<Func<TModel, TProperty>> expression, bool isEditable){ if (isEditable) { return htmlHelper.TextBoxFor(expression); } else { return htmlHelper.DisplayFor(expression); }} The helper method is used in the view like so: <%=Html.TextBoxOrLabelFor(model => model.Title, Model.IsSubordinate)%> As mentioned in this post, there is a much easier way to update properties on an object. Download Demo Project VS 2008, ASP.NET MVC 2 RTM Remember to change the connectionString to point to your Northwind DB NorthwindHR.zip Feedback and bugs are always welcome :-)

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  • User Experience Highlights in PeopleSoft and PeopleTools: Direct from Jeff Robbins

    - by mvaughan
    By Kathy Miedema, Oracle Applications User Experience  This is the fifth in a series of blog posts on the user experience (UX) highlights in various Oracle product families. The last posted interview was with Nadia Bendjedou, Senior Director, Product Strategy on upcoming Oracle E-Business Suite user experience highlights. You’ll see themes around productivity and efficiency, and get an early look at the latest mobile offerings coming through these product lines. Today’s post is on the user experience in PeopleSoft and PeopleTools. To learn more about what’s ahead, attend PeopleSoft or PeopleTools OpenWorld presentations.This interview is with Jeff Robbins, Senior Director, PeopleSoft Development. Jeff Robbins Q: How would you describe the vision you have for the user experience of PeopleSoft?A: Intuitive – Specifically, customers use PeopleSoft to help their employees do their day-to-day work, and the UI (user interface) has been helpful and assistive in that effort. If it’s not obvious what they need to do a task, then the UI isn’t working. So the application needs to make it simple for users to find information they need, complete a task, do all the things they are responsible for, and it really helps when the UI just makes sense. Productive – PeopleSoft is a tool used to support people to do their work, and a lot of users are measured by how much work they’re able to get done per hour, per day, etc. The UI needs to help them be as productive as possible, and can’t make them waste time or energy. The UI needs to reflect the type of work necessary for a task -- if it's data entry, the UI needs to assist the user to get information into the system. For analysts, the UI needs help users assess or analyze information in a particular way. Innovative – The concept of the UI being innovative is something we’ve been working on for years. It’s not just that we want to be seen as innovative, the fact is that companies are asking their employees to do more than they’ve ever asked before. More often companies want to roll out processes as employee or manager self-service, where an employee is responsible to review and maintain their own data. So we’ve had to reinvent, and ask,  “How can we modify the ways an employee interacts with our applications so that they can be more productive and efficient – even with tasks that are entirely unfamiliar?”  Our focus on innovation has forced us to design new ways for users to interact with the entire application.Q: How are the UX features you have delivered so far resonating with customers?  A: Resonating very well. We’re hearing tremendous responses from users, managers, decision-makers -- who are very happy with the improved user experience. Many of the individual features resonate well. Some have really hit home, others are better than they used to be but show us that there’s still room for improvement.A couple innovations really stand out; features that have a significant effect on how users interact with PeopleSoft.First, the deployment of PeopleSoft in a way that’s more like a consumer website with the PeopleSoft Home page and Dashboards.  This new approach is very web-centric, where users feel they’re coming to a website rather than logging into an enterprise application.  There’s lots of information from all around the organization collected in a way that feels very familiar to users. In order to do your job, you can come to this web site rather than having to learn how to log into an application and figure out a complicated menu. Companies can host these really rich web sites for employees that are home pages for accessing critical tasks and information. The UI elements of incorporating search into the whole navigation process is another hit. Rather than having to log in and choose a task from a menu, users come to the web site and begin a task by simply searching for data: themselves, another employee, a customer record, whatever.  The search results include the data along with a set of actions the user might take, completely eliminating the need to hunt through a complicated system menu. Search-centric navigation is really sitting well with customers who are trying to deploy an intuitive set of systems. Q: Are any UX highlights more popular than you expected them to be?  A: We introduced a feature called Pivot Grid in the last release, which is a combination of an interactive grid, like an Excel Pivot Table, along with a dynamic visual chart that automatically graphs the data. I wasn’t certain at first how extensively this would be used. It looked like an innovative tool, but it wasn’t clear how it would be incorporated in business process applications. The fact is that everyone who sees Pivot Grids is thrilled with that kind of interactivity.  It reflects the amount of analytical thinking customers are asking employees to do. Employees can’t just enter data any more. They must interact with it, analyze it, and make decisions. Pivot Grids fit into this way of working. Q: What can you tell us about PeopleSoft’s mobile offerings?A: A lot of customers are finding that mobile is the chief priority in their organization.  They tell us they want their employees to be able to access company information from their mobile devices.  Of course, not everyone has the same requirements, so we’re working to make sure we can help our customers accomplish what they’re trying to do.  We’ve already delivered a number of mobile features.  For instance, PeopleSoft home pages, dashboards and workcenters all work well on an iPad, straight out of the box.  We’ve delivered a number of key functions and tasks for mobile workers – those who are responsible for using a mobile device to manage inventory, for example.  Customers tell us they also need a holistic strategy, one that allows their employees to access nearly every task from a mobile device.  While we don’t expect users to do extensive data entry from their smartphone, it makes sense that they have access to company information and systems while away from their desk.  That’s where our strategy is going now.  We plan to unveil a number of new mobile offerings at OpenWorld.  Some will be available then, some shortly after. Q: What else are you working on now that you think is going to be exciting to customers at Oracle OpenWorld?A: Our next release -- the big thing is PeopleSoft 9.2, and we’ll be talking about the huge amount of work that’s gone into the next versions. A new toolset, 8.53, will be coming, and there’s a lot to talk about there, and the next generation of PeopleSoft 9.2.  We have a ton of new stuff coming.Q: What do you want PeopleSoft customers to know? A: We have been focusing on the user experience in PeopleSoft as a very high priority for the last 4 years, and it’s had interesting effects. One thing is that the application is better, more usable.  We’ve made visible improvements. Another aspect is that in customers’ minds, the PeopleSoft brand is being reinvigorated. Customers invested in PeopleSoft years ago, and then they weren’t sure where PeopleSoft was going.  This investment in the UI and overall user experience keeps PeopleSoft current, innovative and fresh.  Customers  are able to take advantage of a lot of new features, even on the older applications, simply by upgrading their PeopleTools. The interest in that ability has been tremendous. Knowing they have a lot of these features available -- right now, that’s pretty huge. There’s been a tremendous amount of positive response, just on the fact that we’re focusing on the user experience. Editor’s note: For more on PeopleSoft and PeopleTools user experience highlights, visit the Usable Apps web site.To find out more about these enhancements at Openworld, be sure to check out these sessions: GEN8928     General Session: PeopleSoft Update and Product RoadmapCON9183     PeopleSoft PeopleTools Technology Roadmap CON8932     New Functional PeopleSoft PeopleTools Capabilities for the Line-of-Business UserCON9196     PeopleSoft PeopleTools Roadmap: Mobile ApplicationsCON9186     Case Study: Delivering a Groundbreaking User Interface with PeopleSoft PeopleTools

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  • Failure to toubleshoot a juju charm deployment

    - by Bruno Pereira
    My environments.yaml looks like this: environments: test: type: local control-bucket: juju-a14dfae3830142d9ac23c499395c2785999 admin-secret: 6608267bbd6b447b8c90934167b2a294999 default-series: oneiric juju-origin: distro data-dir: /home/bruno/projects/juju juju bootstrap runs perfect: 2011-11-22 19:19:31,999 INFO Bootstrapping environment 'test' (type: local)... 2011-11-22 19:19:32,004 INFO Checking for required packages... 2011-11-22 19:19:33,584 INFO Starting networking... 2011-11-22 19:19:34,058 INFO Starting zookeeper... 2011-11-22 19:19:34,283 INFO Starting storage server... 2011-11-22 19:19:40,051 INFO Initializing zookeeper hierarchy 2011-11-22 19:19:40,247 INFO Starting machine agent (origin: distro)... [sudo] password for bruno: 2011-11-22 19:23:16,054 INFO Environment bootstrapped 2011-11-22 19:23:16,079 INFO 'bootstrap' command finished successfully Deploy from a known good charm is accepted (tried it with one that I am trying to create): juju deploy --repository=/home/bruno/projects/charms_repo/ local:teamspeak 2011-11-22 19:28:49,929 INFO Charm deployed as service: 'teamspeak' 2011-11-22 19:28:49,962 INFO 'deploy' command finished successfully After this I can see that juju debug-log shows activity and I can see the network indicator going on and off and activity on my hard-disk. Wait... Looking at juju status I get: services: teamspeak: charm: local:oneiric/teamspeak-1 relations: {} units: teamspeak/0: machine: 0 public-address: 192.168.122.226 relations: {} state: start_error juju debug-log does not help and I have no files under /var/log/juju or /var/lib/juju. Last juju debug-log only shows this: 2011-11-22 19:45:20,790 Machine:0: juju.agents.machine DEBUG: Units changed old:set(['wordpress/0']) new:set(['wordpress/0', 'teamspeak/0']) 2011-11-22 19:45:20,823 Machine:0: juju.agents.machine DEBUG: Starting service unit: teamspeak/0 ... 2011-11-22 19:45:21,137 Machine:0: juju.agents.machine DEBUG: Downloading charm local:oneiric/teamspeak-1 to /home/bruno/projects/juju/bruno-test/charms 2011-11-22 19:45:22,115 Machine:0: juju.agents.machine DEBUG: Starting service unit teamspeak/0 2011-11-22 19:45:22,133 Machine:0: unit.deploy INFO: Creating container teamspeak-0... 2011-11-22 19:47:04,586 Machine:0: unit.deploy INFO: Container created for teamspeak/0 2011-11-22 19:47:04,781 Machine:0: unit.deploy DEBUG: Charm extracted into container 2011-11-22 19:47:04,801 Machine:0: unit.deploy DEBUG: Starting container... 2011-11-22 19:47:07,086 Machine:0: unit.deploy INFO: Started container for teamspeak/0 2011-11-22 19:47:07,107 Machine:0: juju.agents.machine INFO: Started service unit teamspeak/0 How can I troubleshot what is happening here?

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  • TGIF: Engagement Wrap-up

    - by Michael Snow
    We've had a very busy week here at Oracle and as we build up to Oracle OpenWorld starting in less than 10 days - it doesn't look like things will be slowing down. Engagement is definitely in the air this week. Our friend, John Mancini published a great article entitled: "The World of Engagement" on his Digital Landfill blog yesterday and we hosted a great webcast with R "Ray" Wang from Constellation Research yesterday on the "9 C's of Engagement". 12.00 Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-family:"Calibri","sans-serif"; mso-bidi-font-family:"Times New Roman";} I wanted to wrap-up the week with some key takeaways from our webcast yesterday with Ray Wang. If you missed the webcast yesterday, fear not - it is now available  On-Demand. We'll leave you this week with lots of questions about how to navigate these churning waters of engagement. Stay tuned to the Oracle WebCenter Social Business Thought Leaders Webcast Series as we fuel this dialogue. 12.00 Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Calibri","sans-serif"; mso-bidi-font-family:"Times New Roman";} Company Culture Does company support a culture of putting customer satisfaction ahead of profits? Does culture promote creativity and cross functional employee collaboration? Does culture accept different views of multi-generational workforce? Does culture promote employee training and skills development Does culture support upward mobility and long term retention? Does culture support work-life balance? Does the culture provide rewards for employee for outstanding customer support? Channels What are the current primary channels for customer communications? What do you think will be the primary channels in two years? Is company developing support model for emerging channels? Do all channels consistently deliver the same level of customer support? Do you know the cost per transaction across all channels? Do you engage customers proactively across multiple channels? Do all channels have access to the same customer information? Community Does company extend customer support into virtual communities of interest? Does company facilitate educating users through its virtual communities? Does company mine its customer’s experience into useful data? Does company increase the value for customers through using data to deliver new products and services? Does company support two way interactions with its customers through communities of interest? Does company actively support social CRM, online communities and social media markets? Credibility Does company market its trustworthiness through external certificates such as business licenses, BBB certificates or other validations? Does company promote trust through customer testimonials and case studies on ethical business practices? Does company promote truthful market campaigns Does company make it easy for customers to complain? Does company build its reputation for standing behind its products with guarantees for satisfaction? Does company protect its customer data with high security measures> Content What sources do you use to create customer content? Does company mine social media and blogs for customer content? How does your company sort, store and retain its customer content? How frequently does content get updated? What external sources do you use for customer content? How many responses are typically received from a knowledge management system inquiry? Does your company use customer content to design and develop new product and services? Context Does your company market to customers in clusters or individually? Does your company customize its messages and personalize them to specific needs of each individual customer? Does your company store customer data based on their past behaviors, purchases, sentiment analysis and current activities? Does your company manage customer context according to channels used? For example identify personal use channels versus business channels? What is your frequency of collecting customer activities across various touch points? How is your customer data stored and analyzed? Is contextual data used for future customer outreach? Cadence Which channels does your company measure-web site visits, phone calls, IVR, store visits, face to face, social media? Does company make effective use of cross channel marketing to promote more frequent customer engagement? Does your company rate the patterns relevant for your product or service and monitor usage against this pattern? Does your company measure the frequency of both online and offline channels? Does your company apply metrics to the frequency of customer engagements with product or services revenues? Does your company consolidate data for customer engagement across various channels for a complete view of its customer? Catalyst Does company offer coupon discounts? Does company have a customer loyalty program or a VIP membership program? Does company mine customer data to target specific groups of buyers? Do internal employees serve as ambassadors for customer programs? Does company drive loyalty through social media loyalty programs? Does company build rewards based on using loyalty data? Does company offer an employee incentive program to drive customer loyalty?

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  • NHibernate Pitfalls: Cascades

    - by Ricardo Peres
    This is part of a series of posts about NHibernate Pitfalls. See the entire collection here. For entities that have associations – one-to-one, one-to-many, many-to-one or many-to-many –, NHibernate needs to know what to do with their related entities, in three particular moments: when saving, updating or deleting. In particular, there are two possible behaviors: either ignore these related entities or cascade changes to them. NHibernate allows setting the cascade behavior for each association, and the default behavior is not to cascade (ignore). The possible cascade options are: None Ignore, this is the default Save-Update If the entity is being saved or updated, also save any related entities that are either not saved or have been modified and associate these related entities to the root entity. Generally safe Delete If the entity is being deleted, also delete the related entities. This is only useful for parent-child relations Delete-Orphan Identical to Delete, with the addition that if once related entity is removed from the association – orphaned –, also delete it. Also only for parent-child All Combination of Save-Update and Delete, usually that’s what we want (for parent-child relations, of course) All-Delete-Orphan Same as All plus delete any related entities who lose their relationship In summary, Save-Update is generally what you want in most cases. As for the Delete variations, they should only be used if the related entities depend on the root entity (parent-child), so that deleting the root entity and not their related entities would result in a constraint violation on the database.

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  • Nested Entities and calculation on leaf entity property - SQL or NoSQL approach

    - by Chandu
    I am working on a hobby project called Menu/Recipe Management. This is how my entities and their relations look like. A Nutrient has properties Code and Value An Ingredient has a collection of Nutrients A Recipe has a Collection of Ingredients and occasionally can have a collection of other recipes A Meal has a Collection of Recipes and Ingredients A Menu has a Collection of Meals The relations can be depicted as In one of the pages, for a selected menu I need to display the effective nutrients information calculated based on its constituents (Meals, Recipes, Ingredients and the corresponding nutrients). As of now am using SQL Server to store the data and I am navigating the chain from my C# code, starting from each meal of the menu and then aggregating the nutrient values. I think this is not an efficient way as this calculation is being done every time the page is requested and the constituents change occasionally. I was thinking about a having a background service that maintains a table called MenuNutrients ({MenuId, NutrientId, Value}) and will populate/update this table with the effective nutrients when any of the component (Meal, Recipe, Ingredient) changes. I feel that a GraphDB would be a good fit for this requirement, but my exposure to NoSQL is limited. I want to know what are the alternative solutions/approaches to this requirement of displaying the nutrients of a given menu. Hope my description of the scenario is clear.

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  • Mysql - Help me change this single complex query to use temporary tables

    - by sandeepan-nath
    About the system: - There are tutors who create classes and packs - A tags based search approach is being followed.Tag relations are created when new tutors register and when tutors create packs (this makes tutors and packs searcheable). For details please check the section How tags work in this system? below. Following is the concerned query Can anybody help me suggest an approach using temporary tables. We have indexed all the relevant fields and it looks like this is the least time possible with this approach:- SELECT SUM(DISTINCT( t.tag LIKE "%Dictatorship%" OR tt.tag LIKE "%Dictatorship%" OR ttt.tag LIKE "%Dictatorship%" )) AS key_1_total_matches , SUM(DISTINCT( t.tag LIKE "%democracy%" OR tt.tag LIKE "%democracy%" OR ttt.tag LIKE "%democracy%" )) AS key_2_total_matches , COUNT(DISTINCT( od.id_od )) AS tutor_popularity, CASE WHEN ( IF(( wc.id_wc > 0 ), ( wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date > '2010-06-01 22:00:56' AND wccp.status = 1 AND ( wccp.country_code = 'IE' OR wccp.country_code IN ( 'INT' ) ) ), 0) ) THEN 1 ELSE 0 END AS 'classes_published' , CASE WHEN ( IF(( lp.id_lp > 0 ), ( lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND ( lpcp.country_code = 'IE' OR lpcp.country_code IN ( 'INT' ) ) ), 0) ) THEN 1 ELSE 0 END AS 'packs_published', td . *, u . * FROM tutor_details AS td JOIN users AS u ON u.id_user = td.id_user LEFT JOIN learning_packs_tag_relations AS lptagrels ON td.id_tutor = lptagrels.id_tutor LEFT JOIN learning_packs AS lp ON lptagrels.id_lp = lp.id_lp LEFT JOIN learning_packs_categories AS lpc ON lpc.id_lp_cat = lp.id_lp_cat LEFT JOIN learning_packs_categories AS lpcp ON lpcp.id_lp_cat = lpc.id_parent LEFT JOIN learning_pack_content AS lpct ON ( lp.id_lp = lpct.id_lp ) LEFT JOIN webclasses_tag_relations AS wtagrels ON td.id_tutor = wtagrels.id_tutor LEFT JOIN webclasses AS wc ON wtagrels.id_wc = wc.id_wc LEFT JOIN learning_packs_categories AS wcc ON wcc.id_lp_cat = wc.id_wp_cat LEFT JOIN learning_packs_categories AS wccp ON wccp.id_lp_cat = wcc.id_parent LEFT JOIN order_details AS od ON td.id_tutor = od.id_author LEFT JOIN orders AS o ON od.id_order = o.id_order LEFT JOIN tutors_tag_relations AS ttagrels ON td.id_tutor = ttagrels.id_tutor LEFT JOIN tags AS t ON t.id_tag = ttagrels.id_tag LEFT JOIN tags AS tt ON tt.id_tag = lptagrels.id_tag LEFT JOIN tags AS ttt ON ttt.id_tag = wtagrels.id_tag WHERE ( u.country = 'IE' OR u.country IN ( 'INT' ) ) AND CASE WHEN ( ( tt.id_tag = lptagrels.id_tag ) AND ( lp.id_lp > 0 ) ) THEN lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND ( lpcp.country_code = 'IE' OR lpcp.country_code IN ( 'INT' ) ) ELSE 1 END AND CASE WHEN ( ( ttt.id_tag = wtagrels.id_tag ) AND ( wc.id_wc > 0 ) ) THEN wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date > '2010-06-01 22:00:56' AND wccp.status = 1 AND ( wccp.country_code = 'IE' OR wccp.country_code IN ( 'INT' ) ) ELSE 1 END AND CASE WHEN ( od.id_od > 0 ) THEN od.id_author = td.id_tutor AND o.order_status = 'paid' AND CASE WHEN ( od.id_wc > 0 ) THEN od.can_attend_class = 1 ELSE 1 END ELSE 1 END AND ( t.tag LIKE "%Dictatorship%" OR t.tag LIKE "%democracy%" OR tt.tag LIKE "%Dictatorship%" OR tt.tag LIKE "%democracy%" OR ttt.tag LIKE "%Dictatorship%" OR ttt.tag LIKE "%democracy%" ) GROUP BY td.id_tutor HAVING key_1_total_matches = 1 AND key_2_total_matches = 1 ORDER BY tutor_popularity DESC, u.surname ASC, u.name ASC LIMIT 0, 20 The problem The results returned by the above query are correct (AND logic working as per expectation), but the time taken by the query rises alarmingly for heavier data and for the current data I have it is like 10 seconds as against normal query timings of the order of 0.005 - 0.0002 seconds, which makes it totally unusable. Somebody suggested in my previous question to do the following:- create a temporary table and insert here all relevant data that might end up in the final result set run several updates on this table, joining the required tables one at a time instead of all of them at the same time finally perform a query on this temporary table to extract the end result All this was done in a stored procedure, the end result has passed unit tests, and is blazing fast. I have never worked with temporary tables till now. Only if I could get some hints, kind of schematic representations so that I can start with... Is there something faulty with the query? What can be the reason behind 10+ seconds of execution time? How tags work in this system? When a tutor registers, tags are entered and tag relations are created with respect to tutor's details like name, surname etc. When a Tutors create packs, again tags are entered and tag relations are created with respect to pack's details like pack name, description etc. tag relations for tutors stored in tutors_tag_relations and those for packs stored in learning_packs_tag_relations. All individual tags are stored in tags table. The explain query output:- Please see this screenshot - http://www.test.examvillage.com/Explain_query_improved.jpg

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  • Dropdown dependent values to be fetch from multiple models using ajax in Yii

    - by newuser
    I searched all the documentation over Yii but not got the answer of it.So I came here finally. I have the following schema Table Schools +------------------+--------------+------+-----+---------------------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+--------------+------+-----+---------------------+----------------+ | id | int(10) | NO | PRI | NULL | auto_increment | | school_name | varchar(100) | NO | | | | +------------------+--------------+------+-----+---------------------+----------------+ Table Students +------------------+--------------+------+-----+---------------------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+--------------+------+-----+---------------------+----------------+ | id | int(10) | NO | PRI | NULL | auto_increment | | school_id | int(10) | NO | FK | | | | student_name | varchar(100) | NO | | | | | roll_no | varchar(80) | NO | | | | | class | varchar(20) | NO | | | | | | subjects | varchar(100) | NO | | | | +------------------+--------------+------+-----+---------------------+----------------+ I have made models and CRUD for the both models.In models my relation is like this In Students.php the relation is like public function relations() { // NOTE: you may need to adjust the relation name and the related // class name for the relations automatically generated below. return array( 'School' => array(self::BELONGS_TO,'Schools','school_id'), ); } In Schools.php the relation is like public function relations() { // NOTE: you may need to adjust the relation name and the related // class name for the relations automatically generated below. return array( 'student' => array(self::HAS_MANY, 'Students', 'school_id'), ); } Now I made the two models rendered in a single page so that I can enter all the respective fields in a single form. In the _form.php file of Students I have made some change in student_name like this <div class="row"> <?php echo $form->labelEx($model,'student_name'); ?> <?php echo $form->dropdownList($model,'student_name', CHtml::listData(Students::model()->findAll(), 'id', 'student_name'), array('empty'=>array('Select'=>'--Select One---'))); ?> <?php echo $form->error($model,'student_name'); ?> Now for this piece of code I got all the student name from the Student model. So my problem is when I am getting the student name from the dropdown list and going to select a student it will also fetch all the respective values of the student to be rendered in the _form.php without click on save button.So that user don't have to put it again manually. I think ajax and json encode will work here but don't know how to make them work here. [Update] Here is StudentsController code public function actionDisCoor() { $model = School::model()->findByPk($_POST['Students']['student_id']); $data=CHtml::listData($data,'id','name'); foreach($data as $value=>$name) { echo CHtml::tag('option',array('value'=>$value),CHtml::encode($name),true); } } Here is _form.php code for Students <div class="row"> <?php echo $form->labelEx($model,'student_name'); ?> <?php $List = CHtml::listData(Students::model()->findAll(), 'id', 'student_name'); ?> <?php echo $form->dropdownList($model,'student_name',$List, array('onChange'=>CHtml::ajax(array( 'url' => CController::createUrl('DisCoor'), 'type' => 'POST', 'update'=>'#school_id', )),'style'=>'width:180px;' ) )?> <?php echo $form->error($model,'student_name'); ?> </div> After all that when I saw in firebug I got the error.Here is the screen shot

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  • Mysql - help me optimize this query (improved question)

    - by sandeepan-nath
    About the system: - There are tutors who create classes and packs - A tags based search approach is being followed.Tag relations are created when new tutors register and when tutors create packs (this makes tutors and packs searcheable). For details please check the section How tags work in this system? below. Following is the concerned query SELECT SUM(DISTINCT( t.tag LIKE "%Dictatorship%" )) AS key_1_total_matches, SUM(DISTINCT( t.tag LIKE "%democracy%" )) AS key_2_total_matches, COUNT(DISTINCT( od.id_od )) AS tutor_popularity, CASE WHEN ( IF(( wc.id_wc > 0 ), ( wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date > '2010-06-01 22:00:56' AND wccp.status = 1 AND ( wccp.country_code = 'IE' OR wccp.country_code IN ( 'INT' ) ) ), 0) ) THEN 1 ELSE 0 END AS 'classes_published', CASE WHEN ( IF(( lp.id_lp > 0 ), ( lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND ( lpcp.country_code = 'IE' OR lpcp.country_code IN ( 'INT' ) ) ), 0) ) THEN 1 ELSE 0 END AS 'packs_published', td . *, u . * FROM tutor_details AS td JOIN users AS u ON u.id_user = td.id_user LEFT JOIN learning_packs_tag_relations AS lptagrels ON td.id_tutor = lptagrels.id_tutor LEFT JOIN learning_packs AS lp ON lptagrels.id_lp = lp.id_lp LEFT JOIN learning_packs_categories AS lpc ON lpc.id_lp_cat = lp.id_lp_cat LEFT JOIN learning_packs_categories AS lpcp ON lpcp.id_lp_cat = lpc.id_parent LEFT JOIN learning_pack_content AS lpct ON ( lp.id_lp = lpct.id_lp ) LEFT JOIN webclasses_tag_relations AS wtagrels ON td.id_tutor = wtagrels.id_tutor LEFT JOIN webclasses AS wc ON wtagrels.id_wc = wc.id_wc LEFT JOIN learning_packs_categories AS wcc ON wcc.id_lp_cat = wc.id_wp_cat LEFT JOIN learning_packs_categories AS wccp ON wccp.id_lp_cat = wcc.id_parent LEFT JOIN order_details AS od ON td.id_tutor = od.id_author LEFT JOIN orders AS o ON od.id_order = o.id_order LEFT JOIN tutors_tag_relations AS ttagrels ON td.id_tutor = ttagrels.id_tutor JOIN tags AS t ON ( t.id_tag = ttagrels.id_tag ) OR ( t.id_tag = lptagrels.id_tag ) OR ( t.id_tag = wtagrels.id_tag ) WHERE ( u.country = 'IE' OR u.country IN ( 'INT' ) ) AND CASE WHEN ( ( t.id_tag = lptagrels.id_tag ) AND ( lp.id_lp 0 ) ) THEN lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND ( lpcp.country_code = 'IE' OR lpcp.country_code IN ( 'INT' ) ) ELSE 1 END AND CASE WHEN ( ( t.id_tag = wtagrels.id_tag ) AND ( wc.id_wc 0 ) ) THEN wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date '2010-06-01 22:00:56' AND wccp.status = 1 AND ( wccp.country_code = 'IE' OR wccp.country_code IN ( 'INT' ) ) ELSE 1 END AND CASE WHEN ( od.id_od 0 ) THEN od.id_author = td.id_tutor AND o.order_status = 'paid' AND CASE WHEN ( od.id_wc 0 ) THEN od.can_attend_class = 1 ELSE 1 END ELSE 1 END GROUP BY td.id_tutor HAVING key_1_total_matches = 1 AND key_2_total_matches = 1 ORDER BY tutor_popularity DESC, u.surname ASC, u.name ASC LIMIT 0, 20 The problem The results returned by the above query are correct (AND logic working as per expectation), but the time taken by the query rises alarmingly for heavier data and for the current data I have it is like 25 seconds as against normal query timings of the order of 0.005 - 0.0002 seconds, which makes it totally unusable. It is possible that some of the delay is being caused because all the possible fields have not yet been indexed. The tag field of tags table is indexed. Is there something faulty with the query? What can be the reason behind 20+ seconds of execution time? How tags work in this system? When a tutor registers, tags are entered and tag relations are created with respect to tutor's details like name, surname etc. When a Tutors create packs, again tags are entered and tag relations are created with respect to pack's details like pack name, description etc. tag relations for tutors stored in tutors_tag_relations and those for packs stored in learning_packs_tag_relations. All individual tags are stored in tags table. The explain query output:- Please see this screenshot - http://www.test.examvillage.com/Explain_query.jpg

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  • Mysql - help me optimize this query

    - by sandeepan-nath
    About the system: -The system has a total of 8 tables - Users - Tutor_Details (Tutors are a type of User,Tutor_Details table is linked to Users) - learning_packs, (stores packs created by tutors) - learning_packs_tag_relations, (holds tag relations meant for search) - tutors_tag_relations and tags and orders (containing purchase details of tutor's packs), order_details linked to orders and tutor_details. For a more clear idea about the tables involved please check the The tables section in the end. -A tags based search approach is being followed.Tag relations are created when new tutors register and when tutors create packs (this makes tutors and packs searcheable). For details please check the section How tags work in this system? below. Following is a simpler representation (not the actual) of the more complex query which I am trying to optimize:- I have used statements like explanation of parts in the query select SUM(DISTINCT( t.tag LIKE "%Dictatorship%" )) as key_1_total_matches, SUM(DISTINCT( t.tag LIKE "%democracy%" )) as key_2_total_matches, td., u., count(distinct(od.id_od)), if (lp.id_lp > 0) then some conditional logic on lp fields else 0 as tutor_popularity from Tutor_Details AS td JOIN Users as u on u.id_user = td.id_user LEFT JOIN Learning_Packs_Tag_Relations AS lptagrels ON td.id_tutor = lptagrels.id_tutor LEFT JOIN Learning_Packs AS lp ON lptagrels.id_lp = lp.id_lp LEFT JOIN `some other tables on lp.id_lp - let's call learning pack tables set (including Learning_Packs table)` LEFT JOIN Order_Details as od on td.id_tutor = od.id_author LEFT JOIN Orders as o on od.id_order = o.id_order LEFT JOIN Tutors_Tag_Relations as ttagrels ON td.id_tutor = ttagrels.id_tutor JOIN Tags as t on (t.id_tag = ttagrels.id_tag) OR (t.id_tag = lptagrels.id_tag) where some condition on Users table's fields AND CASE WHEN ((t.id_tag = lptagrels.id_tag) AND (lp.id_lp 0)) THEN `some conditions on learning pack tables set` ELSE 1 END AND CASE WHEN ((t.id_tag = wtagrels.id_tag) AND (wc.id_wc 0)) THEN `some conditions on webclasses tables set` ELSE 1 END AND CASE WHEN (od.id_od0) THEN od.id_author = td.id_tutor and some conditions on Orders table's fields ELSE 1 END AND ( t.tag LIKE "%Dictatorship%" OR t.tag LIKE "%democracy%") group by td.id_tutor HAVING key_1_total_matches = 1 AND key_2_total_matches = 1 order by tutor_popularity desc, u.surname asc, u.name asc limit 0,20 ===================================================================== What does the above query do? Does AND logic search on the search keywords (2 in this example - "Democracy" and "Dictatorship"). Returns only those tutors for which both the keywords are present in the union of the two sets - tutors details and details of all the packs created by a tutor. To make things clear - Suppose a Tutor name "Sandeepan Nath" has created a pack "My first pack", then:- Searching "Sandeepan Nath" returns Sandeepan Nath. Searching "Sandeepan first" returns Sandeepan Nath. Searching "Sandeepan second" does not return Sandeepan Nath. ====================================================================================== The problem The results returned by the above query are correct (AND logic working as per expectation), but the time taken by the query on heavily loaded databases is like 25 seconds as against normal query timings of the order of 0.005 - 0.0002 seconds, which makes it totally unusable. It is possible that some of the delay is being caused because all the possible fields have not yet been indexed, but I would appreciate a better query as a solution, optimized as much as possible, displaying the same results ========================================================================================== How tags work in this system? When a tutor registers, tags are entered and tag relations are created with respect to tutor's details like name, surname etc. When a Tutors create packs, again tags are entered and tag relations are created with respect to pack's details like pack name, description etc. tag relations for tutors stored in tutors_tag_relations and those for packs stored in learning_packs_tag_relations. All individual tags are stored in tags table. ==================================================================== The tables Most of the following tables contain many other fields which I have omitted here. CREATE TABLE IF NOT EXISTS users ( id_user int(10) unsigned NOT NULL AUTO_INCREMENT, name varchar(100) NOT NULL DEFAULT '', surname varchar(155) NOT NULL DEFAULT '', PRIMARY KEY (id_user) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=636 ; CREATE TABLE IF NOT EXISTS tutor_details ( id_tutor int(10) NOT NULL AUTO_INCREMENT, id_user int(10) NOT NULL DEFAULT '0', PRIMARY KEY (id_tutor), KEY Users_FKIndex1 (id_user) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=51 ; CREATE TABLE IF NOT EXISTS orders ( id_order int(10) unsigned NOT NULL AUTO_INCREMENT, PRIMARY KEY (id_order), KEY Orders_FKIndex1 (id_user), ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=275 ; ALTER TABLE orders ADD CONSTRAINT Orders_ibfk_1 FOREIGN KEY (id_user) REFERENCES users (id_user) ON DELETE NO ACTION ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS order_details ( id_od int(10) unsigned NOT NULL AUTO_INCREMENT, id_order int(10) unsigned NOT NULL DEFAULT '0', id_author int(10) NOT NULL DEFAULT '0', PRIMARY KEY (id_od), KEY Order_Details_FKIndex1 (id_order) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=284 ; ALTER TABLE order_details ADD CONSTRAINT Order_Details_ibfk_1 FOREIGN KEY (id_order) REFERENCES orders (id_order) ON DELETE NO ACTION ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS learning_packs ( id_lp int(10) unsigned NOT NULL AUTO_INCREMENT, id_author int(10) unsigned NOT NULL DEFAULT '0', PRIMARY KEY (id_lp), KEY Learning_Packs_FKIndex2 (id_author), KEY id_lp (id_lp) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=23 ; CREATE TABLE IF NOT EXISTS tags ( id_tag int(10) unsigned NOT NULL AUTO_INCREMENT, tag varchar(255) DEFAULT NULL, PRIMARY KEY (id_tag), UNIQUE KEY tag (tag), KEY id_tag (id_tag), KEY tag_2 (tag), KEY tag_3 (tag) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3419 ; CREATE TABLE IF NOT EXISTS tutors_tag_relations ( id_tag int(10) unsigned NOT NULL DEFAULT '0', id_tutor int(10) DEFAULT NULL, KEY Tutors_Tag_Relations (id_tag), KEY id_tutor (id_tutor), KEY id_tag (id_tag) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; ALTER TABLE tutors_tag_relations ADD CONSTRAINT Tutors_Tag_Relations_ibfk_1 FOREIGN KEY (id_tag) REFERENCES tags (id_tag) ON DELETE NO ACTION ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS learning_packs_tag_relations ( id_tag int(10) unsigned NOT NULL DEFAULT '0', id_tutor int(10) DEFAULT NULL, id_lp int(10) unsigned DEFAULT NULL, KEY Learning_Packs_Tag_Relations_FKIndex1 (id_tag), KEY id_lp (id_lp), KEY id_tag (id_tag) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; ALTER TABLE learning_packs_tag_relations ADD CONSTRAINT Learning_Packs_Tag_Relations_ibfk_1 FOREIGN KEY (id_tag) REFERENCES tags (id_tag) ON DELETE NO ACTION ON UPDATE NO ACTION; =================================================================================== Following is the exact query (this includes classes also - tutors can create classes and search terms are matched with classes created by tutors):- select count(distinct(od.id_od)) as tutor_popularity, CASE WHEN (IF((wc.id_wc 0), ( wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date '2010-06-01 22:00:56' AND wccp.status = 1 AND (wccp.country_code='IE' or wccp.country_code IN ('INT'))), 0)) THEN 1 ELSE 0 END as 'classes_published', CASE WHEN (IF((lp.id_lp 0), (lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND (lpcp.country_code='IE' or lpcp.country_code IN ('INT'))),0)) THEN 1 ELSE 0 END as 'packs_published', td . * , u . * from Tutor_Details AS td JOIN Users as u on u.id_user = td.id_user LEFT JOIN Learning_Packs_Tag_Relations AS lptagrels ON td.id_tutor = lptagrels.id_tutor LEFT JOIN Learning_Packs AS lp ON lptagrels.id_lp = lp.id_lp LEFT JOIN Learning_Packs_Categories AS lpc ON lpc.id_lp_cat = lp.id_lp_cat LEFT JOIN Learning_Packs_Categories AS lpcp ON lpcp.id_lp_cat = lpc.id_parent LEFT JOIN Learning_Pack_Content as lpct on (lp.id_lp = lpct.id_lp) LEFT JOIN Webclasses_Tag_Relations AS wtagrels ON td.id_tutor = wtagrels.id_tutor LEFT JOIN WebClasses AS wc ON wtagrels.id_wc = wc.id_wc LEFT JOIN Learning_Packs_Categories AS wcc ON wcc.id_lp_cat = wc.id_wp_cat LEFT JOIN Learning_Packs_Categories AS wccp ON wccp.id_lp_cat = wcc.id_parent LEFT JOIN Order_Details as od on td.id_tutor = od.id_author LEFT JOIN Orders as o on od.id_order = o.id_order LEFT JOIN Tutors_Tag_Relations as ttagrels ON td.id_tutor = ttagrels.id_tutor JOIN Tags as t on (t.id_tag = ttagrels.id_tag) OR (t.id_tag = lptagrels.id_tag) OR (t.id_tag = wtagrels.id_tag) where (u.country='IE' or u.country IN ('INT')) AND CASE WHEN ((t.id_tag = lptagrels.id_tag) AND (lp.id_lp 0)) THEN lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND (lpcp.country_code='IE' or lpcp.country_code IN ('INT')) ELSE 1 END AND CASE WHEN ((t.id_tag = wtagrels.id_tag) AND (wc.id_wc 0)) THEN wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date '2010-06-01 22:00:56' AND wccp.status = 1 AND (wccp.country_code='IE' or wccp.country_code IN ('INT')) ELSE 1 END AND CASE WHEN (od.id_od0) THEN od.id_author = td.id_tutor and o.order_status = 'paid' and CASE WHEN (od.id_wc 0) THEN od.can_attend_class=1 ELSE 1 END ELSE 1 END AND 1 group by td.id_tutor order by tutor_popularity desc, u.surname asc, u.name asc limit 0,20 Please note - The provided database structure does not show all the fields and tables as in this query

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  • Can this Query be corrected or different table structure needed? (database dumps provided)

    - by sandeepan
    This is a bit lengthy but I have provided sufficient details and kept things very clear. Please see if you can help. (I will surely accept answer if it solves my problem) I am sure a person experienced with this can surely help or suggest me to decide the tables structure. About the system:- There are tutors who create classes A tags based search approach is being followed Tag relations are created/edited when new tutors registers/edits profile data and when tutors create classes (this makes tutors and classes searcheable).For simplicity, let us consider only tutor name and class name are the fields which are matched against search keywords. In this example, I am considering - tutor "Sandeepan Nath" has created a class called "first class" tutor "Bob Cratchit" has created a class called "new class" Desired search results- AND logic to be appied on the search keywords and match against class and tutor data(class name + tutor name), in other words, All those classes be shown such that all the search terms are present in the class name or its tutor name. Example to be clear - Searching "first class" returns class with id_wc = 1. Working Searching "Sandeepan class" should also return class with id_wc = 1. Not working in System 2. Problem with profile editing and searching To tell in one sentence, I am facing a conflict between the ease of profile edition (edition of tag relations when tutor profiles are edited) and the ease of search logic. In the beginning, we had one table structure and search was easy but tag edition logic was very clumsy and unmaintainable(Check System 1 in the section below) . So we created separate tag relations tables to make profile edition simpler but search has become difficult. Please dump the tables so that you can run the search query I have given below and see the results. System 1 (previous system - search easy - profile edition difficult):- Only one table called All_Tag_Relations table had the all the tag relations. The tags table below is common to both systems 1 and 2. CREATE TABLE IF NOT EXISTS `all_tag_relations` ( `id_tag_rel` int(10) NOT NULL AUTO_INCREMENT, `id_tag` int(10) unsigned NOT NULL DEFAULT '0', `id_tutor` int(10) DEFAULT NULL, `id_wc` int(10) unsigned DEFAULT NULL, PRIMARY KEY (`id_tag_rel`), KEY `All_Tag_Relations_FKIndex1` (`id_tag`), KEY `id_wc` (`id_wc`), KEY `id_tag` (`id_tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `all_tag_relations` (`id_tag_rel`, `id_tag`, `id_tutor`, `id_wc`) VALUES (1, 1, 1, NULL), (2, 2, 1, NULL), (3, 1, 1, 1), (4, 2, 1, 1), (5, 3, 1, 1), (6, 4, 1, 1), (7, 6, 2, NULL), (8, 7, 2, NULL), (9, 6, 2, 2), (10, 7, 2, 2), (11, 5, 2, 2), (12, 4, 2, 2); CREATE TABLE IF NOT EXISTS `tags` ( `id_tag` int(10) unsigned NOT NULL AUTO_INCREMENT, `tag` varchar(255) DEFAULT NULL, PRIMARY KEY (`id_tag`), UNIQUE KEY `tag` (`tag`), KEY `id_tag` (`id_tag`), KEY `tag_2` (`tag`), KEY `tag_3` (`tag`), KEY `tag_4` (`tag`), FULLTEXT KEY `tag_5` (`tag`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; INSERT INTO `tags` (`id_tag`, `tag`) VALUES (1, 'Sandeepan'), (2, 'Nath'), (3, 'first'), (4, 'class'), (5, 'new'), (6, 'Bob'), (7, 'Cratchit'); Please note that for every class, the tag rels of its tutor have to be duplicated. Example, for class with id_wc=1, the tag rel records with id_tag_rel = 3 and 4 are actually extras if you compare with the tag rel records with id_tag_rel = 1 and 2. System 2 (present system - profile edition easy, search difficult) Two separate tables Tutors_Tag_Relations and Webclasses_Tag_Relations have the corresponding tag relations data (Please dump into a separate database)- CREATE TABLE IF NOT EXISTS `tutors_tag_relations` ( `id_tag_rel` int(10) NOT NULL AUTO_INCREMENT, `id_tag` int(10) unsigned NOT NULL DEFAULT '0', `id_tutor` int(10) DEFAULT NULL, PRIMARY KEY (`id_tag_rel`), KEY `All_Tag_Relations_FKIndex1` (`id_tag`), KEY `id_tag` (`id_tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `tutors_tag_relations` (`id_tag_rel`, `id_tag`, `id_tutor`) VALUES (1, 1, 1), (2, 2, 1), (3, 6, 2), (4, 7, 2); CREATE TABLE IF NOT EXISTS `webclasses_tag_relations` ( `id_tag_rel` int(10) NOT NULL AUTO_INCREMENT, `id_tag` int(10) unsigned NOT NULL DEFAULT '0', `id_tutor` int(10) DEFAULT NULL, `id_wc` int(10) DEFAULT NULL, PRIMARY KEY (`id_tag_rel`), KEY `webclasses_Tag_Relations_FKIndex1` (`id_tag`), KEY `id_wc` (`id_wc`), KEY `id_tag` (`id_tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `webclasses_tag_relations` (`id_tag_rel`, `id_tag`, `id_tutor`, `id_wc`) VALUES (1, 3, 1, 1), (2, 4, 1, 1), (3, 5, 2, 2), (4, 4, 2, 2); CREATE TABLE IF NOT EXISTS `tags` ( `id_tag` int(10) unsigned NOT NULL AUTO_INCREMENT, `tag` varchar(255) DEFAULT NULL, PRIMARY KEY (`id_tag`), UNIQUE KEY `tag` (`tag`), KEY `id_tag` (`id_tag`), KEY `tag_2` (`tag`), KEY `tag_3` (`tag`), KEY `tag_4` (`tag`), FULLTEXT KEY `tag_5` (`tag`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; INSERT INTO `tags` (`id_tag`, `tag`) VALUES (1, 'Sandeepan'), (2, 'Nath'), (3, 'first'), (4, 'class'), (5, 'new'), (6, 'Bob'), (7, 'Cratchit'); CREATE TABLE IF NOT EXISTS `all_tag_relations` ( `id_tag_rel` int(10) NOT NULL AUTO_INCREMENT, `id_tag` int(10) unsigned NOT NULL DEFAULT '0', `id_tutor` int(10) DEFAULT NULL, `id_wc` int(10) unsigned DEFAULT NULL, PRIMARY KEY (`id_tag_rel`), KEY `All_Tag_Relations_FKIndex1` (`id_tag`), KEY `id_wc` (`id_wc`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; insert into All_Tag_Relations select NULL,id_tag,id_tutor,NULL from Tutors_Tag_Relations; insert into All_Tag_Relations select NULL,id_tag,id_tutor,id_wc from Webclasses_Tag_Relations; Here you can see how easily tutor first name can be edited only in one place. But search has become really difficult, so on being advised to use a Temporary table, I am creating one at every search request, then dumping all the necessary data and then searching from it, I am creating this All_Tag_Relations table at search run time. Here I am just dumping all the data from the two tables Tutors_Tag_Relations and Webclasses_Tag_Relations. But, I am still not able to get classes if I search with tutor name This is the query which searches "first class". Running them on both the systems shows correct results (returns the class with id_wc = 1). SELECT wtagrels.id_wc,SUM(DISTINCT( wtagrels.id_tag =3)) AS key_1_total_matches, SUM(DISTINCT( wtagrels.id_tag =4)) AS key_2_total_matches FROM all_tag_relations AS wtagrels WHERE ( wtagrels.id_tag =3 OR wtagrels.id_tag =4 ) GROUP BY wtagrels.id_wc HAVING key_1_total_matches = 1 AND key_2_total_matches = 1 LIMIT 0, 20 But, searching for "Sandeepan class" works only with the 1st system Here is the query which searches "Sandeepan class" SELECT wtagrels.id_wc,SUM(DISTINCT( wtagrels.id_tag =1)) AS key_1_total_matches, SUM(DISTINCT( wtagrels.id_tag =4)) AS key_2_total_matches FROM all_tag_relations AS wtagrels WHERE ( wtagrels.id_tag =1 OR wtagrels.id_tag =4 ) GROUP BY wtagrels.id_wc HAVING key_1_total_matches = 1 AND key_2_total_matches = 1 LIMIT 0, 20 Can anybody alter this query and somehow do a proper join or something to get correct results. That solves my problem in a nice way. As you can figure out, the reason why it does not work in system 2 is that in system 1, for every class, one additional tag relation linking class and tutor name is present. e.g. for class first class, (records with id_tag_rel 3 and 4) which returns the class on searching with tutor name. So, you see the trade-off between the search and profile edition difficulty with the two systems. How do I overcome both. I have to reach a conclusion soon. So far my reasoning is it is definitely not good from a code maintainability point of view to follow the single tag rel table structure of system one, because in a real system while editing a field like "tutor qualifications", there can be as many records in tag rels table as there are words in qualification of a tutor (one word in a field = one tag relation). Now suppose a tutor has 100 classes. When he edits his qualification, all the tag rel rows corresponding to him are deleted and then as many copies are to be created (as per the new qualification data) as there are classes. This becomes particularly difficult if later more searcheable fields are added. The code cannot be robust. Is the best solution to follow system 2 (edition has to be in one table - no extra work for each and every class) and somehow re-create the all_tag_relations table like system 1 (from the tables tutor_tag_relations and webclasses_tag_relations), creating the extra tutor tag rels for each and every class by a tutor (which is currently missing in system 2's temporary all_tag_relations table). That would be a time consuming logic script. I doubt that table can be recreated without resorting to PHP sript (mysql alone cannot do that). But the problem is that running all this at search time will make search definitely slow. So, how do such systems work? How are such situations handled? I thought about we can run a cron which initiates that PHP script, say every 1 minute and replaces the existing all_tag_relations table as per new tag rels from tutor_tag_relations and webclasses_tag_relations (replaces means creates a new table, deletes the original and renames the new one as all_tag_relations, otherwise search won't work during that period- or is there any better way to that?). Anyway, the result would be that any changes by tutors will reflect in search in the next 1 minute and not immediately. An alternateve would be to initate that PHP script every time a tutor edits his profile. But here again, since many users may edit their profiles concurrently, will the creation of so many tables be a burden and can mysql make the server slow? Any help would be appreciated and working solution will be accepted as answer. Thanks, Sandeepan

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  • Can this Query can be corrected or different table structure needed? (question is clear, detailed, d

    - by sandeepan
    This is a bit lengthy but I have provided sufficient details and kept things very clear. Please see if you can help. (I will surely accept answer if it solves my problem) I am sure a person experienced with this can surely help or suggest me to decide the tables structure. About the system:- There are tutors who create classes A tags based search approach is being followed Tag relations are created/edited when new tutors registers/edits profile data and when tutors create classes (this makes tutors and classes searcheable).For simplicity, let us consider only tutor name and class name are the fields which are matched against search keywords. In this example, I am considering - tutor "Sandeepan Nath" has created a class called "first class" tutor "Bob Cratchit" has created a class called "new class" Desired search results- AND logic to be appied on the search keywords and match against class and tutor data(class name + tutor name), in other words, All those classes be shown such that all the search terms are present in the class name or its tutor name. Example to be clear - Searching "first class" returns class with id_wc = 1. Working Searching "Sandeepan class" should also return class with id_wc = 1. Not working in System 2. Problem with profile editing and searching To tell in one sentence, I am facing a conflict between the ease of profile edition (edition of tag relations when tutor profiles are edited) and the ease of search logic. In the beginning, we had one table structure and search was easy but tag edition logic was very clumsy and unmaintainable(Check System 1 in the section below) . So we created separate tag relations tables to make profile edition simpler but search has become difficult. Please dump the tables so that you can run the search query I have given below and see the results. System 1 (previous system - search easy - profile edition difficult):- Only one table called All_Tag_Relations table had the all the tag relations. The tags table below is common to both systems 1 and 2. CREATE TABLE IF NOT EXISTS `all_tag_relations` ( `id_tag_rel` int(10) NOT NULL AUTO_INCREMENT, `id_tag` int(10) unsigned NOT NULL DEFAULT '0', `id_tutor` int(10) DEFAULT NULL, `id_wc` int(10) unsigned DEFAULT NULL, PRIMARY KEY (`id_tag_rel`), KEY `All_Tag_Relations_FKIndex1` (`id_tag`), KEY `id_wc` (`id_wc`), KEY `id_tag` (`id_tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `all_tag_relations` (`id_tag_rel`, `id_tag`, `id_tutor`, `id_wc`) VALUES (1, 1, 1, NULL), (2, 2, 1, NULL), (3, 1, 1, 1), (4, 2, 1, 1), (5, 3, 1, 1), (6, 4, 1, 1), (7, 6, 2, NULL), (8, 7, 2, NULL), (9, 6, 2, 2), (10, 7, 2, 2), (11, 5, 2, 2), (12, 4, 2, 2); CREATE TABLE IF NOT EXISTS `tags` ( `id_tag` int(10) unsigned NOT NULL AUTO_INCREMENT, `tag` varchar(255) DEFAULT NULL, PRIMARY KEY (`id_tag`), UNIQUE KEY `tag` (`tag`), KEY `id_tag` (`id_tag`), KEY `tag_2` (`tag`), KEY `tag_3` (`tag`), KEY `tag_4` (`tag`), FULLTEXT KEY `tag_5` (`tag`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; INSERT INTO `tags` (`id_tag`, `tag`) VALUES (1, 'Sandeepan'), (2, 'Nath'), (3, 'first'), (4, 'class'), (5, 'new'), (6, 'Bob'), (7, 'Cratchit'); Please note that for every class, the tag rels of its tutor have to be duplicated. Example, for class with id_wc=1, the tag rel records with id_tag_rel = 3 and 4 are actually extras if you compare with the tag rel records with id_tag_rel = 1 and 2. System 2 (present system - profile edition easy, search difficult) Two separate tables Tutors_Tag_Relations and Webclasses_Tag_Relations have the corresponding tag relations data (Please dump into a separate database)- CREATE TABLE IF NOT EXISTS `tutors_tag_relations` ( `id_tag_rel` int(10) NOT NULL AUTO_INCREMENT, `id_tag` int(10) unsigned NOT NULL DEFAULT '0', `id_tutor` int(10) DEFAULT NULL, PRIMARY KEY (`id_tag_rel`), KEY `All_Tag_Relations_FKIndex1` (`id_tag`), KEY `id_tag` (`id_tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `tutors_tag_relations` (`id_tag_rel`, `id_tag`, `id_tutor`) VALUES (1, 1, 1), (2, 2, 1), (3, 6, 2), (4, 7, 2); CREATE TABLE IF NOT EXISTS `webclasses_tag_relations` ( `id_tag_rel` int(10) NOT NULL AUTO_INCREMENT, `id_tag` int(10) unsigned NOT NULL DEFAULT '0', `id_tutor` int(10) DEFAULT NULL, `id_wc` int(10) DEFAULT NULL, PRIMARY KEY (`id_tag_rel`), KEY `webclasses_Tag_Relations_FKIndex1` (`id_tag`), KEY `id_wc` (`id_wc`), KEY `id_tag` (`id_tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `webclasses_tag_relations` (`id_tag_rel`, `id_tag`, `id_tutor`, `id_wc`) VALUES (1, 3, 1, 1), (2, 4, 1, 1), (3, 5, 2, 2), (4, 4, 2, 2); CREATE TABLE IF NOT EXISTS `tags` ( `id_tag` int(10) unsigned NOT NULL AUTO_INCREMENT, `tag` varchar(255) DEFAULT NULL, PRIMARY KEY (`id_tag`), UNIQUE KEY `tag` (`tag`), KEY `id_tag` (`id_tag`), KEY `tag_2` (`tag`), KEY `tag_3` (`tag`), KEY `tag_4` (`tag`), FULLTEXT KEY `tag_5` (`tag`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; INSERT INTO `tags` (`id_tag`, `tag`) VALUES (1, 'Sandeepan'), (2, 'Nath'), (3, 'first'), (4, 'class'), (5, 'new'), (6, 'Bob'), (7, 'Cratchit'); CREATE TABLE IF NOT EXISTS `all_tag_relations` ( `id_tag_rel` int(10) NOT NULL AUTO_INCREMENT, `id_tag` int(10) unsigned NOT NULL DEFAULT '0', `id_tutor` int(10) DEFAULT NULL, `id_wc` int(10) unsigned DEFAULT NULL, PRIMARY KEY (`id_tag_rel`), KEY `All_Tag_Relations_FKIndex1` (`id_tag`), KEY `id_wc` (`id_wc`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; insert into All_Tag_Relations select NULL,id_tag,id_tutor,NULL from Tutors_Tag_Relations; insert into All_Tag_Relations select NULL,id_tag,id_tutor,id_wc from Webclasses_Tag_Relations; Here you can see how easily tutor first name can be edited only in one place. But search has become really difficult, so on being advised to use a Temporary table, I am creating one at every search request, then dumping all the necessary data and then searching from it, I am creating this All_Tag_Relations table at search run time. Here I am just dumping all the data from the two tables Tutors_Tag_Relations and Webclasses_Tag_Relations. But, I am still not able to get classes if I search with tutor name This is the query which searches "first class". Running them on both the systems shows correct results (returns the class with id_wc = 1). SELECT wtagrels.id_wc,SUM(DISTINCT( wtagrels.id_tag =3)) AS key_1_total_matches, SUM(DISTINCT( wtagrels.id_tag =4)) AS key_2_total_matches FROM all_tag_relations AS wtagrels WHERE ( wtagrels.id_tag =3 OR wtagrels.id_tag =4 ) GROUP BY wtagrels.id_wc HAVING key_1_total_matches = 1 AND key_2_total_matches = 1 LIMIT 0, 20 But, searching for "Sandeepan class" works only with the 1st system Here is the query which searches "Sandeepan class" SELECT wtagrels.id_wc,SUM(DISTINCT( wtagrels.id_tag =1)) AS key_1_total_matches, SUM(DISTINCT( wtagrels.id_tag =4)) AS key_2_total_matches FROM all_tag_relations AS wtagrels WHERE ( wtagrels.id_tag =1 OR wtagrels.id_tag =4 ) GROUP BY wtagrels.id_wc HAVING key_1_total_matches = 1 AND key_2_total_matches = 1 LIMIT 0, 20 Can anybody alter this query and somehow do a proper join or something to get correct results. That solves my problem in a nice way. As you can figure out, the reason why it does not work in system 2 is that in system 1, for every class, one additional tag relation linking class and tutor name is present. e.g. for class first class, (records with id_tag_rel 3 and 4) which returns the class on searching with tutor name. So, you see the trade-off between the search and profile edition difficulty with the two systems. How do I overcome both. I have to reach a conclusion soon. So far my reasoning is it is definitely not good from a code maintainability point of view to follow the single tag rel table structure of system one, because in a real system while editing a field like "tutor qualifications", there can be as many records in tag rels table as there are words in qualification of a tutor (one word in a field = one tag relation). Now suppose a tutor has 100 classes. When he edits his qualification, all the tag rel rows corresponding to him are deleted and then as many copies are to be created (as per the new qualification data) as there are classes. This becomes particularly difficult if later more searcheable fields are added. The code cannot be robust. Is the best solution to follow system 2 (edition has to be in one table - no extra work for each and every class) and somehow re-create the all_tag_relations table like system 1 (from the tables tutor_tag_relations and webclasses_tag_relations), creating the extra tutor tag rels for each and every class by a tutor (which is currently missing in system 2's temporary all_tag_relations table). That would be a time consuming logic script. I doubt that table can be recreated without resorting to PHP sript (mysql alone cannot do that). But the problem is that running all this at search time will make search definitely slow. So, how do such systems work? How are such situations handled? I thought about we can run a cron which initiates that PHP script, say every 1 minute and replaces the existing all_tag_relations table as per new tag rels from tutor_tag_relations and webclasses_tag_relations (replaces means creates a new table, deletes the original and renames the new one as all_tag_relations, otherwise search won't work during that period- or is there any better way to that?). Anyway, the result would be that any changes by tutors will reflect in search in the next 1 minute and not immediately. An alternateve would be to initate that PHP script every time a tutor edits his profile. But here again, since many users may edit their profiles concurrently, will the creation of so many tables be a burden and can mysql make the server slow? Any help would be appreciated and working solution will be accepted as answer. Thanks, Sandeepan

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