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  • WPF InotifyPropertyChanged and view models

    - by Joel Barsotti
    So I think I'm doing something pretty basic. I know why this doesn't work, but it seems like there should be a straight foward way to make it work. code: private string fooImageRoot; // .... public BitmapImage FooImage { get { URI imageURI = new URI(Path.Combine(fooImageRoot, CurrentFooTypes.FooObject.FooImageName)); return imageURI; } } So CurrentFOoTypes and FooObject also supports INotifyPropertyChanged. So If I bind a TextBlock to CurrentFooTypes.FooObject.FooImageName, if either fooObject or FooImageName change the textblock updates. How can I subscribe my viewmodel object to recieve updates in a similiar fasion.

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  • Using proxy models

    - by smallB
    I've created Proxy model by subclassing QAbstractProxyModel and connected it as a model to my view. I also set up source model for this proxy model. Unfortunately something is wrong because I'm not getting anything displayed on my listView (it works perfectly when I have my model supplied as a model to view but when I supply this proxy model it just doesn't work). Here are some snippets from my code: #ifndef FILES_PROXY_MODEL_H #define FILES_PROXY_MODEL_H #include <QAbstractProxyModel> #include "File_List_Model.h" class File_Proxy_Model: public QAbstractProxyModel { public: explicit File_Proxy_Model(File_List_Model* source_model) { setSourceModel(source_model); } virtual QModelIndex mapFromSource(const QModelIndex & sourceIndex) const { return index(sourceIndex.row(),sourceIndex.column()); } virtual QModelIndex mapToSource(const QModelIndex & proxyIndex) const { return index(proxyIndex.row(),proxyIndex.column()); } virtual int columnCount(const QModelIndex & parent = QModelIndex()) const { return sourceModel()->columnCount(); } virtual int rowCount(const QModelIndex & parent = QModelIndex()) const { return sourceModel()->rowCount(); } virtual QModelIndex index(int row, int column, const QModelIndex & parent = QModelIndex()) const { return createIndex(row,column); } virtual QModelIndex parent(const QModelIndex & index) const { return QModelIndex(); } }; #endif // FILES_PROXY_MODEL_H //and this is a dialog class: Line_Counter::Line_Counter(QWidget *parent) : QDialog(parent), model_(new File_List_Model(this)), proxy_model_(new File_Proxy_Model(model_)), sel_model_(new QItemSelectionModel(proxy_model_,this)) { setupUi(this); setup_mvc_(); } void Line_Counter::setup_mvc_() { listView->setModel(proxy_model_); listView->setSelectionModel(sel_model_); }

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  • Working with nested models in ROR

    - by user487429
    Hi there, I'm trying to create an application where users can freely create shops and associated shop item for a specific shop is displayed when a show action is called but I seem to be doing something wrong. Any help here will be appreciated. I have attached shots of my code below. class ShopItem < ActiveRecord::Base belongs_to :shop def self.find_shop_items_for_sale find(:all, :order => "title", :conditions => ["shop_id = ?", @shop.id]) end end class Shop < ActiveRecord::Base has_many :shop_items end #Controllers class ShopsController < ApplicationController def new @shop = Shop.new end def create @shop = Shop.new(params[:shop]) @shop.user_id = current_user.id respond_to do |format| if @shop.save flash[:notice] = "Successfully created shop." format.html {redirect_to(all_shops_shops_url)} format.xml {render :xml => @shop, :status => :created, :location => @shop } else format.html {render :action => 'new'} format.xml { render :xml => @shop.errors, :status => :unprocessable_entity } end end end def show @shop = Shop.find(params[:id]) @shop_items = ShopItem.find_shop_items_for_sale @shop_cart = find_shop_cart end class ShopItemsController < ApplicationController def user @per_page ||= 5 @user = User.find(params[:id]) @shop_items = ShopItem.find(:all, :conditions=>["user_id = ?", @user.id], :order=>"id desc") end def show @shop_item = ShopItem.find(params[:id]) @shop = @shop_item.shop respond_to do |format| format.html # show.html.erb format.xml { render :xml => @shop_item } end end # GET /shop_items/new # GET /shop_items/new.xml def new @shop_item = ShopItem.new @shop = Shop.find(params[:id]) #@shop_items = ShopItem.paginate(:all, :condition=>["shop_id] = ?", @shop.id], :order=> "id desc", :page => params[:page],:per_page => @per_page) @shop_items = ShopItem.find(:all, :conditions=>["shop_id = ?", @shop.id], :order=> "id desc") @shop_item.shop_id = params[:id] respond_to do |format| format.html # new.html.erb format.xml { render :xml => @shop_item } end end # GET /shop_items/1/edit def edit @shop_item = ShopItem.find(params[:id]) end # POST /shop_items # POST /shop_items.xml def create @shop_item = ShopItem.new(params[:shop_item]) @shop_item.user_id = current_user.id respond_to do |format| if @shop_item.save flash[:notice] = 'Shop item was successfully created.' format.html { redirect_to(@shop_item) } format.xml { render :xml => @shop_item, :status => :created, :location => @shop_item } else @shop = Shop.find(@shop_item.shop_id) #@shop_items = ShopItem.paginate(:all, :condition =>["shop_id = ?", @shop.id], :order=> "id desc" , :page => params[:page], :per_page => @per_page) @shop_items = ShopItem.find(:all, :conditions =>["shop_id = ?", @shop.id], :order=> "id desc") format.html { render :action => "new" } format.xml { render :xml => @shop_item.errors, :status => :unprocessable_entity } end end end

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  • Expire models in Rails

    - by Koning Baard XIV
    I'm creating a simple paste-bin in Ruby on Rails, which will have an expire-feature. With this, people can select a date when the paste will be deleted automatically. How can I implement this? I was thinking of a cronjob, but maybe there is a more platform-independent way, by defining this in the model itself. Can anyone help me? Thanks.

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  • how to save related models with non-null foreign key

    - by Fortress
    I have a model called user which has_one email. I put the foreign key (NOT NULL) inside users table. Now I'm trying to save it in the following way: @email = Email.new(params[:email]) @email.user = User.new(params[:user]) @email.save This raises a db exception, because the foreign key constraint is not met (NULL is inserted into email_id). How can I elegantly solve this or is my data modeling wrong?

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  • Cross-referencing UML models in VS 2010

    - by cheaster
    I am just starting to explore/use the UML modeling support in Visual Studio 2010 Umltimate. I have created two model projects within a single solution. Let's call them Model A and Model B. I have some data types (classes) defined in Model B. I want to use them as return types for operations in Model A. However, I cannot figure out how to make the types defined in Model B show up in Model A when attempting to set return type on an operation. Any help/suggestions would be greatly appreciated! Thanks!

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  • Caching Models in rails

    - by jules
    I have a rails application, with a model that is a kind of repository. The records stored in the DB for that model are (almost) never changed, but are read all the time. Also there is not a lot of them. I would like to store these records in cache, in a generic way. I would like to do something like acts_as_cached, but here are the issue I have: I can not find a decent documentation for acts as cached (neither can I find it's repository) I don't want to use memcached, but something simpler (static variable, or something like that). Do you have any idea of what gems I could use to do that ? Thanks

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  • pass parameter from controller to models condition

    - by Alex
    I'm trying to bind a param to a join via a named scope., but I'm getting an error. What is the correct way to do that? has_one :has_voted, :class_name => 'Vote', :conditions => ['ip = :userIp'] # named scopes scope :with_vote, lambda {|ip| { :include => [:has_voted], # like this ?? :conditions => [:has_voted => {:conditions => {:userIp => ip}} ] }} Idea.with_vote(request.ip).all I believe I need the condition definition in the model for it to appear in the ON clause of a JOIN, rather then in the WHERE one. Edit I'm trying to get the following query select Ideas.*, Votes.* from Ideas left outer join Votes on Votes.Idea_id = Idea.id AND Votes.ip = {request.ip}

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  • Dynamic Views based on view models

    - by Joe
    I have an asp.net mvc 2 app. I need to display the same page to each user. But each user has different rights to the data. IE some can see but not edit some data, some cannot edit nor see the data. Ideally data that cannot be seen nor edited is whitespace on the view. For security reasons I want my viewmodels to be sparse as possible. By that I mean if a field cannot be seen nor edited , that field should not be on the viewmodel. Obviously I can write view for each view model but that seems wasteful. So here is my idea/wishlist Can I decorate the viewmodel with attributes and hook into a pre render event of the html helpers and tell it to do &nbsp; instead??? Can I have the html helpers output &nbsp; for entries not found on the viewmodel?? or can I easily convert a view built into code then programaticlly build the markup and then put into the render engine to be processed and viewd as html on client side??

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  • CakePHP pagination with HABTM models

    - by nickf
    I'm having some problems with creating pagination with a HABTM relationship. First, the tables and relationships: requests (id, to_location_id, from_location_id) locations (id, name) items_locations (id, item_id, location_id) items (id, name) So, a Request has a Location the request is coming from and a Location the Request is going to. For this question, I'm only concerned about the "to" location. Request --belongsTo--> Location* --hasAndBelongsToMany--> Item (* as "ToLocation") In my RequestController, I want to paginate all the Items in a Request's ToLocation. // RequestsController var $paginate = array( 'Item' => array( 'limit' => 5, 'contain' => array( "Location" ) ) ); // RequestController::add() $locationId = 21; $items = $this->paginate('Item', array( "Location.id" => $locationId )); And this is failing, because it is generating this SQL: SELECT COUNT(*) AS count FROM items Item WHERE Location.id = 21 I can't figure out how to make it actually use the "contain" argument of $paginate... Any ideas?

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  • how do I instrospect appengine's datastore models?

    - by python for ever
    in order to dynamically create a form, i have to find the property types of a model's properties at runtime. appengine docs says that Model.properties() will return a dictionary of properties name and their class type. when i use this method in my code, only the name is returned and the classtype value is always empty.

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  • How do I install Ubuntu 12.04 PPC on a PowerPC G4 from commands line or fix the graphical mode?

    - by Gerardo Rodríguez
    Good afternoon. I'm new to this Linux world so I hope someone can help me . I recently got a Mac as a gift, a PowerPC G4 , which has 1GB of RAM but came with no optical drive or hard drive. So I put a dvd burner and a hard drive of 40 GB I got. Then download an iso of Ubuntu 12.04 for PowerPC and burned onto a CD. I'm trying to install from Open Firmware ( as I haven't a Mac keyboard, I use one standard ) . Finally, the Installation CD boots , but on live mode and after the Ubuntu 12.04 screen I get a message that there is a problem with my graphics adapter but I can continue with minimal graphics and give me the command line . My question is that how do I install through a text or if there is any way to fix this problem to run the graphical mode and so can continue the installation of Ubuntu, and if once installed Ubuntu the problem will be fixed or what? I would appreciate if you help me , as I mentioned before, there is almost nothing of Ubuntu but I think it will be easier than trying to get the Mac OS X proper . Spend good.

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  • Two graphical entities, smooth blending between them (e.g. asphalt and grass)

    - by Gabriel Conrad
    Supposedly in a scenario there are, among other things, a tarmac strip and a meadow. The tarmac has an asphalt texture and its model is a triangle strip long that might bifurcate at some point into other tinier strips, and suppose that the meadow is covered with grass. What can be done to make the two graphical entities seem less cut out from a photo and just pasted one on top of the other at the edges? To better understand the problem, picture a strip of asphalt and a plane covered with grass. The grass texture should also "enter" the tarmac strip a little bit at the edges (i.e. feathering effect). My ideas involve two approaches: put two textures on the tarmac entity, but that involves a serious restriction in how the strip is modeled and its texture coordinates are mapped or try and apply a post-processing filter that mimics a bloom effect where "grass" is used instead of light. This could be a terrible failure to achieve correct results. So, is there a better or at least a more obvious way that's widely used in the game dev industry?

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  • JSON Serialization of a Django inherited model

    - by Simon Morris
    Hello, I have the following Django models class ConfigurationItem(models.Model): path = models.CharField('Path', max_length=1024) name = models.CharField('Name', max_length=1024, blank=True) description = models.CharField('Description', max_length=1024, blank=True) active = models.BooleanField('Active', default=True) is_leaf = models.BooleanField('Is a Leaf item', default=True) class Location(ConfigurationItem): address = models.CharField(max_length=1024, blank=True) phoneNumber = models.CharField(max_length=255, blank=True) url = models.URLField(blank=True) read_acl = models.ManyToManyField(Group, default=None) write_acl = models.ManyToManyField(Group, default=None) alert_group= models.EmailField(blank=True) The full model file is here if it helps. You can see that Company is a child class of ConfigurationItem. I'm trying to use JSON serialization using either the django.core.serializers.serializer or the WadofStuff serializer. Both serializers give me the same problem... >>> from cmdb.models import * >>> from django.core import serializers >>> serializers.serialize('json', [ ConfigurationItem.objects.get(id=7)]) '[{"pk": 7, "model": "cmdb.configurationitem", "fields": {"is_leaf": true, "extension_attribute_10": "", "name": "", "date_modified": "2010-05-19 14:42:53", "extension_attribute_11": false, "extension_attribute_5": "", "extension_attribute_2": "", "extension_attribute_3": "", "extension_attribute_1": "", "extension_attribute_6": "", "extension_attribute_7": "", "extension_attribute_4": "", "date_created": "2010-05-19 14:42:53", "active": true, "path": "/Locations/London", "extension_attribute_8": "", "extension_attribute_9": "", "description": ""}}]' >>> serializers.serialize('json', [ Location.objects.get(id=7)]) '[{"pk": 7, "model": "cmdb.location", "fields": {"write_acl": [], "url": "", "phoneNumber": "", "address": "", "read_acl": [], "alert_group": ""}}]' >>> The problem is that serializing the Company model only gives me the fields directly associated with that model, not the fields from it's parent object. Is there a way of altering this behaviour or should I be looking at building a dictionary of objects and using simplejson to format the output? Thanks in advance ~sm

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  • How to save to Django Model that Have Mulitple Foreign Keys Fields

    - by Spikie
    I have Models for business Apps class staff_name(models.Model): TITLE_CHOICES = ( ('Mr', 'Mr'), ('Miss', 'Miss'), ( 'Mrs', 'Mrs'), ( 'chief', 'chief'), ) titlename = models.CharField(max_length=10,choices=TITLE_CHOICES) firstname = models.CharField(max_length=150) surname = models.CharField(max_length=150) date = models.DateTimeField(auto_now=True) class meta: ordering = ["date"] get_latest_by = "date" class inventory_transaction(models.Model): stock_in = models.DecimalField(blank=True, null=True,max_digits=8, decimal_places=2) stock_out = models.DecimalField(blank=True,null=True,max_digits=8, decimal_places=2) Number_container = models.ForeignKey(container_identity) staffs = models.ForeignKey(staff_name) goods_details = models.ForeignKey(departments) balance = models.DecimalField(max_digits=8, decimal_places=2) date = models.DateTimeField(auto_now=True) What i want to accomplish is check if the staff have made entry to the table before if yes add the value for the stock in plus (last) balance field and assign to balance if no just assign stock in value to balance field and save these are my codes These are my codes: try: s = staffname.staffs_set.all().order_by("-date").latest() # staffname is the instant of the class model staff_name e = s.staffs_set.create(stockin=vdataz,balance=s.balance + vdataz ) # e is the instant of the class model inventory_transaction e.save e.staffs.add(s) e.from_container.add(containersno) e.goods_details.add(department) except ObjectDoesNotExist: e = staff_name.objects.create(stockin=vdataz,balance=vdataz ) e.save e.staffs.add(staffname) e.from_container.add(containersno) e.goods_details.add(department) I will really appreciate a solution Thanks I hope it make more sense now. iam on online if you need more explanation just ask in the comment.Thank you for your help

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  • Using map() on a _set in a template?

    - by Stuart Grimshaw
    I have two models like this: class KPI(models.Model): """KPI model to hold the basic info on a Key Performance Indicator""" title = models.CharField(blank=False, max_length=100) description = models.TextField(blank=True) target = models.FloatField(blank=False, null=False) group = models.ForeignKey(KpiGroup) subGroup = models.ForeignKey(KpiSubGroup, null=True) unit = models.TextField(blank=True) owner = models.ForeignKey(User) bt_measure = models.BooleanField(default=False) class KpiHistory(models.Model): """A historical log of previous KPI values.""" kpi = models.ForeignKey(KPI) measure = models.FloatField(blank=False, null=False) kpi_date = models.DateField() and I'm using RGraph to display the stats on internal wallboards, the handy thing is Python lists get output in a format that Javascript sees as an array, so by mapping all the values into a list like this: def f(x): return float(x.measure) stats = map(f, KpiHistory.objects.filter(kpi=1) then in the template I can simply use {{ stats }} and the RGraph code sees it as an array which is exactly what I want. [87.0, 87.5, 88.5, 90] So my question is this, is there any way I can achieve the same effect using Django's _set functionality to keep the amount of data I'm passing into the template, up until now I've been passing in a single KPI object to be graphed but now I want to pass in a whole bunch so is there anything I can do with _set {{ kpi.kpihistory_set }} dumps the whole model out, but I just want the measure field. I can't see any of the built in template methods that will let me pull out just the single field I want. How have other people handled this situation?

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  • Django - How best to handle ValidationErrors after form.save(commit=False)

    - by orokusaki
    This is a fragment of my code from a view: if form.is_valid(): instance = form.save(commit=False) try: instance.account = request.account instance.full_clean() except ValidationError, e: # Do something with the errors here... I don't know what the best thing to do here is, but I certainly don't want to do it 180 times. This is an utter mess. Who would want to handle validation errors manually in every view. If you're not modifying the instance after save(commit=False), you don't have to worry about this, but what about in my case where every model has a foreign key to account which is set behind the scenes and hidden from the user? Any help is really appreciated.

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  • Customizing Django form widgets? - Django

    - by RadiantHex
    Hi folks, I'm having a little problem here! I have discovered the following as being the globally accepted method for customizing Django admin field. from django import forms from django.utils.safestring import mark_safe class AdminImageWidget(forms.FileInput): """ A ImageField Widget for admin that shows a thumbnail. """ def __init__(self, attrs={}): super(AdminImageWidget, self).__init__(attrs) def render(self, name, value, attrs=None): output = [] if value and hasattr(value, "url"): output.append(('<a target="_blank" href="%s">' '<img src="%s" style="height: 28px;" /></a> ' % (value.url, value.url))) output.append(super(AdminImageWidget, self).render(name, value, attrs)) return mark_safe(u''.join(output)) I need to have access to other field of the model in order to decide how to display the field! For example: If I am keeping track of a value, let us call it "sales". If I wish to customize how sales is displayed depending on another field, let us call it "conversion rate". I have no obvious way of accessing the conversion rate field when overriding the sales widget! Any ideas to work around this would be highly appreciated! Thanks :)

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  • why are read only form fields in django a bad idea?

    - by jamida
    I've been looking for a way to create a read-only form field and every article I've found on the subject comes with a statement that "this is a bad idea". Now for an individual form, I can understand that there are other ways to solve the problem, but using a read only form field in a modelformset seems like a completely natural idea. Consider a teacher grade book application where the teacher would like to be able to enter all the students' (note the plural students) grades with a single SUBMIT. A modelformset could iterate over all the student-grades in such a way that the student name is read-only and the grade is the editable field. I like the power and convenience of the error checking and error reporting you get with a modelformset but leaving the student name editable in such a formset is crazy. Since the expert django consensus is that read-only form fields are a bad idea, I was wondering what the standard django best practice is for the example student-grade example above?

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  • Change user email in Django without using django-profiles

    - by mridang
    Hi guys, In my Django application I would like the user to be able to change the email address. I've seen solution of StackOverflow pointing people to django-profiles. Unfortunately I don't want to use a full fledged profile module to accomplish a tiny feat of changing the users email. Has anyone seen this implemented anywhere. The email address verification procedure by sending a confirmation email is a requisite in this scenario. I've spent a great a deal of time trying to a find a solution that works but to no avail. Cheers.

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  • *UPDATED* help with django and accented characters?

    - by Asinox
    Hi guys, i have a problem with my accented characters, Django admin save my data without encoding to something like "&aacute;" Example: if im trying a word like " Canción ", i would like to save in this way: Canci&oacute;n, and not Canción. im usign Sociable app: {% load sociable_tags %} {% get_sociable Facebook TwitThis Google MySpace del.icio.us YahooBuzz Live as sociable_links with url=object.get_absolute_url title=object.titulo %} {% for link in sociable_links %} <a href="{{ link.link }}"><img alt="{{ link.site }}" title="{{ link.site }}" src="{{ link.image }}" /></a> {% endfor %} But im getting error if my object.titulo (title of the article) have a accented word. aught KeyError while rendering: u'\xfa' Any idea ? i had in my SETTING: DEFAULT_CHARSET = 'utf-8' i had in my mysql database: utf8_general_ci COMPLETED ERROR: Traceback: File "C:\wamp\bin\Python26\lib\site-packages\django\core\handlers\base.py" in get_response 100. response = callback(request, *callback_args, **callback_kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\views\generic\date_based.py" in object_detail 366. response = HttpResponse(t.render(c), mimetype=mimetype) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in render 173. return self._render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in _render 167. return self.nodelist.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in render 796. bits.append(self.render_node(node, context)) File "C:\wamp\bin\Python26\lib\site-packages\django\template\debug.py" in render_node 72. result = node.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\loader_tags.py" in render 125. return compiled_parent._render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in _render 167. return self.nodelist.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in render 796. bits.append(self.render_node(node, context)) File "C:\wamp\bin\Python26\lib\site-packages\django\template\debug.py" in render_node 72. result = node.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\loader_tags.py" in render 62. result = block.nodelist.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in render 796. bits.append(self.render_node(node, context)) File "C:\wamp\bin\Python26\lib\site-packages\django\template\debug.py" in render_node 72. result = node.render(context) File "C:\wamp\bin\Python26\lib\site-packages\sociable\templatetags\sociable_tags.py" in render 37. 'link': sociable.genlink(site, **self.values), File "C:\wamp\bin\Python26\lib\site-packages\sociable\sociable.py" in genlink 20. values['title'] = quote_plus(kwargs['title']) File "C:\wamp\bin\Python26\lib\urllib.py" in quote_plus 1228. s = quote(s, safe + ' ') File "C:\wamp\bin\Python26\lib\urllib.py" in quote 1222. res = map(safe_map.__getitem__, s) Exception Type: TemplateSyntaxError at /noticia/2010/jun/10/matan-domingo-paquete-en-la-avenida-san-vicente-de-paul/ Exception Value: Caught KeyError while rendering: u'\xfa' thanks, sorry with my English

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  • Numerology with Python And Django

    - by Asinox
    Hi guys, i have a function that give me the result that im expecting in console mode, but if i try to use the function with Django, the page never load and just have a loop calculating and never end. Any idea ? *sorry with my english Console function (WORK GREAT): def sum_digitos(n): sum = 0; while n != 0: sum += n % 10 n /= 10 if sum > 9: x = str(sum) y =list(x) sum = int(y[0]) + int(y[1]) return sum print sum_digitos(2461978) Django views: def Calcular(request): if request.method == 'POST': form = NumerologiaForm(request.POST) if form.is_valid(): sum = 0; ano = str(request.POST['fecha_year']) mes = str(request.POST['fecha_month']) dia = str(request.POST['fecha_day']) data = dia + mes + ano fecha = int(data) while fecha != 0: f = fecha sum += f % 10 f /= 10 if sum > 9: x = str(sum) y =list(x) sum = int(y[0]) + int(y[1]) resultado = get_object_or_404(Numero,numero = sum) return HttpResponseRedirect(resultado.get_absolute_url()) else: form = NumerologiaForm() return render_to_response('numerologiaForm.html',{'form':form})

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  • XML Serialization is not including milliseconds in datetime field from Rails model

    - by revgum
    By default, the datetime field from the database is being converted and stripping off the milliseconds: some_datetime = "2009-11-11T02:19:36Z" attribute_before_type_cast('some_datetime') = "2009-11-11 02:19:36.145" If I try to overrride the accessor for this attribute like; def some_datetime attribute_before_type_cast('some_datetime') end when I try "to_xml" for that model, I get the following error: NoMethodError (undefined method `xmlschema' for "2009-11-11 02:19:36.145":String): I have tried to parse the String to a Time object but can't get one to include the milliseconds; def some_datetime Time.parse(attribute_before_type_cast('some_datetime').sub(/\s/,"T").sub(/$/,"Z")) end Can anyone help get get a datetime with milliseconds rendered by to_xml?

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  • How to add manytomany field to flatpage admin

    - by valya
    Hello! I have a site with Flatpages, and now I need to be able to add galleries (Gallery model) to the page. This is going to be ManyToManyField, so there is no need to change the flatpages table. But I still can't define ManyToManyField in proxy class. I can define ManyToManyField in Gallery model, but it isn't comfortable for the client. How can I change FlatPage Admin to add a ManyToManyField from Galleries model?

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