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• How to set image Tag URLs programmatically in ASP.NET C# inside of a ListView Control?

  - by loyalpenguin

  Hi, I know how you can set an tag's url attribute programmatically in c#, but it seems when I try to access the image element inside of a tag I cannot access it. The is residing in the . NOTE: I am only having this issue inside the Now the ListView tag is also databound.(this is probably why I cannot access, because it isn't guaranteed that it will even exist perhaps). How can I get around this so that I can display my images programmatically or is there a better solution? Here's the source: <asp:ListView ID="ListView_Comments" runat="server" DataKeyNames="ReviewID,ProductID,Rating" DataSourceID="EDS_CommentsList"> <ItemTemplate> <tr style="background-color:#EDECB3;color: #000000;"> <td><%# Eval("CustomerName") %></td> <td> <img src='Styles/Images/ReviewRating_d<%# Eval("Rating") %>.gif' alt=""> <br /> </td> <td> <%# Eval("Comments") %> </td> </tr> </ItemTemplate> <AlternatingItemTemplate> <tr style="background-color:#F8F8F8;"> <td><%# Eval("CustomerName") %></td> <td> <img id="rateImage" src="" alt="" runat="server" /> ......

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• Is there a programmatic way to transform a sequence of image files into a PDF?

  - by Salim Fadhley

  I have a sequence of JPG images. Each of the scans is already cropped to the exact size of one page. They are sequential pages of a valuable and out of print book. The publishing application requires that these pages be submitted as a single PDF file. I could take each of these images and just past them into a word-processor (e.g. OpenOffice) - unfortunately the problem here is that it's a very big book and I've got quite a few of these books to get through. It would obviously be time-consuming. This is volunteer work! My second idea was to use LaTeX - I could make a very simple document that consists of nothing more than a series of in-line image includes. I'm sure that this approach could be made to work, it's just a little on the complex side for something which seems like a very simple job. It occurred to me that there must be a simpler way - so any suggestions? I'm on Ubuntu 9.10, my primary programming language is Python, but if the solution is super-simple I'd happily adopt any technology that works.

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• What is fastest way to backup a disk image over LAN?

  - by David Balažic

  Sometimes I boot sysrescd or a similar live linux on a PC to backup the hardrive over local network to my server. I noticed many times, that the transfer speed is not optimal (slower than HDD and network speed). Any rules of thumb what to do and what to avoid? What I typically do is something like: dd bs=16M if=/dev/sda | nc ... # on client nc ... | dd bs=16M of=/destination/disk/backup1 # on server I also "throw" in lzop (other are way too slow) and sometimes on the fly md5sum calculation (both of uncompressed and compress source). I try to add (m)buffer (or other alternatives) to improve throughput (and get a progress indicator). I noticed that even with enough free CPU, adding commands to the pipeline slows things down. Typically the destination is on a NTFS volume (accessed via ntfs-3g, with the _big_writes_ option).

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• how do I get a new line, after using float:left?

  - by codeman73

  What I am trying to do is have rows of images, 6 images in each row. Some of these images need to have another image floating on top of them (flush with the lower-right corner). I was able to get that to work from this thread: http://stackoverflow.com/questions/48474/how-do-i-position-one-image-on-top-of-another-in-html However, now I'm unable to get the new row after the 6th image. Neither <BR> or <P> create a new line. They simply push the next image down several pixels, but the image is still in the same line. It seems like the float style is interfering with the <BR> and/or <P>. I tried using different styles for the image that starts a new row, like float:none and display:block, but neither worked. The odd thing is that the new line starts after the 7th image. Here's what I'm using so far: <style type="text/css"> .containerdiv { float: left; position: relative; } .containerdivNewLine { float: none; display: block; position: relative; } .cornerimage { position: absolute; bottom: 0; right: 0; } </style> <div class="containerdiv"> <img border="0" height="188" src="myImg" width="133" /> <img class="cornerimage" height="140" src="imageOnTop" width="105" /> </div> For the 7th image, when I'm trying to start a new row, I'm simply replacing the 'containerdiv' class with 'containerdivNewLine'.

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• pulling a value from NSMutableDictionary

  - by Jared Gross

  I have a dictionary array with a key:@"titleLabel". I am trying to load a pickerView with ONE instance of each @"titleLabel" key so that if there are multiple objects with the same @"titleLabel" only one title will be displayed. I've done some research on this forum and looked at apples docs but haven't been able to put the puzzle together. Below is my code but I am having trouble pulling the values. Right now when I run this code it throws an error Incompatible pointer types sending 'PFObject *' to parameter of type 'NSString' which i understand but am just not sure how to remedy. Cheers! else { // found messages! self.objectsArray = objects; NSMutableDictionary *dict = [[NSMutableDictionary alloc] init]; for(id obj in self.objectsArray){ PFObject *key = [self.objectsArray valueForKey:@"titleLabel"]; if(![dict objectForKey:@"titleLabel"]){ [dict setValue:obj forKey:key]; } } for (id key in dict) { NSLog(@"Objects array is %d", [self.objectsArray count]); NSLog(@"key: %@, value: %@ \n", key, [dict objectForKey:key]); } [self.pickerView reloadComponent:0]; } }];` Here is where I define the PFObject and keys: PFObject *image = [PFObject objectWithClassName:@"Images"]; [image setObject:file forKey:@"file"]; [image setObject:fileType forKey:@"fileType"]; [image setObject:title forKey:@"titleLabel"]; [image setObject:self.recipients forKey:@"recipientIds"]; [image setObject:[[PFUser currentUser] objectId] forKey:@"senderId"]; [image setObject:[[PFUser currentUser] username] forKey:@"senderName"]; [image saveInBackground];

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• How do you burn an ISO image on a Mac?

  - by Keith Sirmons

  Is there a utility built into the Mac software to allow for burning ISO downloaded from the internet. Or.. Is there a better utility on the Net for performing this function?

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• How do I convert a .vhd disk image to work with VMWare Fusion 2?

  - by Paul D. Waite

  I’ve just installed VMWare Fusion 2 on my Mac. Microsoft makes available some Virtual PC disk images containing different versions of IE, so that us humble web developers can test our code on them: http://www.microsoft.com/downloads/details.aspx?FamilyId=21EABB90-958F-4B64-B5F1-73D0A413C8EF&displaylang=en I want to convert these .vhd files to work with VMWare Fusion 2. Note: VMWare Fusion 3 can import .vhd files natively (File Import). This works just fine on the Microsoft IE compatibility VMs. I’ve tried VMWare Converter Standalone on Windows, but it doesn’t work with .vhd files (as of the current version, 4.0.1). Any ideas? VMWare’s website is confused corporate hell.

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• PHP: imagepng is creating inordinately large files

  - by Rafael

  I'm using a simple thumbnailing script I wrote and it's pretty standard: $imgbuffer = imagecreatetruecolor($thumbwidth, $thumbheight); switch($type) { case 1: $image = imagecreatefromgif($img); break; case 2: $image = imagecreatefromjpeg($img); break; case 3: $image = imagecreatefrompng($img); break; case 6: $image = imagecreatefrombmp($img); break; case 15: $image = imagecreatefromwbmp($img); break; default: return log_error("Tried to create thumbnail from $img: not a valid image"); } imagecopyresampled($imgbuffer, $image, 0, 0, 0, 0, $thumbwidth, $thumbheight, $width, $height); $output = imagepng($imgbuffer, "$album/thumbs/$imgname.png", 9); 9 is the lowest quality setting, yet from a 400 x 600 JPEG image (at 56kB) I'm getting a thumbnail 27 kB in size (140 x 140). Using imagejpeg (quality of 80) instead of imagepng it's about 4kB. How can this be, especially at the lowest quality setting for imagepng? I tried using imagecopy instead of imagecopyresampled, and imagecreate instead of the true color version. Unfortunately the images come out mangled somehow. Is there any way to get PNG thumbnails of a reasonably small file size (about 4 kB at 140 x 140)? Or do I have to use JPEG?

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• Android: Problems downloading images and converting to bitmaps

  - by Mike

  Hi all, I am working on an application that downloads images from a url. The problem is that only some images are being correctly downloaded and others are not. First off, here is the problem code: public Bitmap downloadImage(String url) { HttpClient client = new DefaultHttpClient(); HttpResponse response = null; try { response = client.execute(new HttpGet(url)); } catch (ClientProtocolException cpe) { Log.i(LOG_FILE, "client protocol exception"); return null; } catch (IOException ioe) { Log.i(LOG_FILE, "IOE downloading image"); return null; } catch (Exception e) { Log.i(LOG_FILE, "Other exception downloading image"); return null; } // Convert images from stream to bitmap object try { Bitmap image = BitmapFactory.decodeStream(response.getEntity().getContent()); if(image==null) Log.i(LOG_FILE, "image conversion failed"); return image; } catch (Exception e) { Log.i(LOG_FILE, "Other exception while converting image"); return null; } } So what I have is a method that takes the url as a string argument and then downloads the image, converts the HttpResponse stream to a bitmap by means of the BitmapFactory.decodeStream method, and returns it. The problem is that when I am on a slow network connection (almost always 3G rather than Wi-Fi) some images are converted to null--not all of them, only some of them. Using a Wi-Fi connection works perfectly; all the images are downloaded and converted properly. Does anyone know why this is happening? Or better, how can I fix this? How would I even go about testing to determine the problem? Any help is awesome; thank you!

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• Physical Debian to VMWare: vmware-converter, dd-image or otherwise?

  - by Dabu

  we have two debian Lenny production machines, both running larger commercial websites. Now these machines need to be moved, and in the process, they need to be virtualized to VMWare ESX. If you believe the internet information, there are several ways to accomplish this. The easiest for us would be to use our weekly dd backup where the whole disk, however, I have no experience with this kind of technology and if it is really possible. The second best way would be via an application on the source machine virtualizing it and generating an ESX compatible VM. However, the software is beta and unsupported, and after installation, nothing really works (the /etc/init.d/vmware-converter script doesn't actually do anything, start and stop reply with success messages, yet ps shows that there are no new processes). The worst way with the most work would be to install a new machine and set it up manually, copying files and databases as needed. This part is clear in it's execution, and my question(s) do not touch this. Is my 1st way possible? Has anyone done this yet, or better, has a page with instructions? Or is there a help page that explains how to correctly install, run and use the vmware-converter tool using a Debian installation (it's possible that I dod something wrong during installation already)? Thank you.

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• How to combine these two PHP arrays ?

  - by Annan

  I have two arrays in php that are part of an image management system. weighted_images A multidimensional array. Each sub array is an associative array with keys of 'weight' (for ordering by) and 'id' (the id of the image). array( 156 => array('weight'=>1, 'id'=>156), 784 => array('weight'=>-2, 'id'=>784), ) images This array is user input. It's an array of image ids. array(784, 346, 748) I want to combine them in to a single array of ids ordered by the weight of the image. If an image doesn't have a weight append to the end. It's not a particularly hard problem however my solution is far from elegant and can't help thinking that there must be a better way to do this. $t_images = array(); foreach ($weighted_images as $wi) { if ( in_array($wi['id'], $images) ) { $t_images[$wi['weight']] = $wi['id']; } } foreach ($images as $image) { if ( !$weighted_images[$image] ) { $t_images[] = $image; } } $images = $t_images; Question: Is there a better way to do this?

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• Memory allocation for a matrix in C

  - by Snogzvwtr

  Why is the following code resulting in Segmentation fault? (I'm trying to create two matrices of the same size, one with static and the other with dynamic allocation) #include <stdio.h> #include <stdlib.h> //Segmentation fault! int main(){ #define X 5000 #define Y 6000 int i; int a[X][Y]; int** b = (int**) malloc(sizeof(int*) * X); for(i=0; i<X; i++){ b[i] = malloc (sizeof(int) * Y); } } Weirdly enough, if I comment out one of the matrix definitions, the code runs fine. Like this: #include <stdio.h> #include <stdlib.h> //No Segmentation fault! int main(){ #define X 5000 #define Y 6000 int i; //int a[X][Y]; int** b = (int**) malloc(sizeof(int*) * X); for(i=0; i<X; i++){ b[i] = malloc (sizeof(int) * Y); } } or #include <stdio.h> #include <stdlib.h> //No Segmentation fault! int main(){ #define X 5000 #define Y 6000 int i; int a[X][Y]; //int** b = (int**) malloc(sizeof(int*) * X); //for(i=0; i<X; i++){ // b[i] = malloc (sizeof(int) * Y); //} } I'm running gcc on Linux on a 32-bit machine.

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• Problems with multi-line comments jquery

  - by c0mrade

  Hello, I'm making a image website with a bunch of images on the website, and below every image there is possibility of commenting the image and after that comments gets displayed without page loading and the comment content, the problem is when I have long comments which break the current line they don't get displayed since my comment box css overflow is hidden. Here is example : This is a comment - This is displayed properly This is a comment This is a comment This is a comment - this is not displayed properly since it break line. Here is the jQuery code for this : $.ajax({ type: "POST", url: "<?=base_url()?>imagesform/post_comment", data: datas, success: function () { $("#image-comments-" + image_id).attr("class", "comments"); $("#image-comments-" + image_id).append("<li id=\"new_append_" + image_id+ "\">" + $("#image").find(".comment").val() + "</li>").children(':last').height($('.comments li:last').height()).hide().slideDown(500, function () { var bodyHeight = $('html').height(); $('.addComment').fadeOut(300, function () { $('html').height(bodyHeight); }); }); alert($("#image").find(".comment").val()); } }); Here the $("#image").find(".comment").val() is the value of the text-area in which comment is inputted, when I alert it the whole multi line input is there put its not being appended to the li properly, that is part when I get confused, any suggestions why only part of the inputted string is appended?

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• How to access variables in shared memory

  - by user1723361

  I am trying to create a shared memory segment containing three integers and an array. The segment is created and a pointer is attached, but when I try to access the values of the variables (whether changing, printing, etc.) I get a segmentation fault. Here is the code I tried: #include <stdio.h> #include <stdbool.h> #include <stdlib.h> #include <errno.h> #include <sys/types.h> #include <sys/ipc.h> #include <sys/sem.h> #define SIZE 10 int* shm_front; int* shm_end; int* shm_count; int* shm_array; int shm_size = 3*sizeof(int) + sizeof(shm_array[SIZE]); int main(int argc, char* argsv[]) { int shmid; //create shared memory segment if((shmid = shmget(IPC_PRIVATE, shm_size, 0644)) == -1) { printf("error in shmget"); exit(1); } //obtain the pointer to the segment if((shm_front = (int*)shmat(shmid, (void *)0, 0)) == (void *)-1) { printf("error in shmat"); exit(1); } //move down the segment to set the other pointers shm_end = shm_front + 1; shm_count = shm_front + 2; shm_array = shm_front + 3; //tests on shm //*shm_end = 10; //gives segmentation fault //printf("\n%d", *shm_front); //gives segmentation fault //clean-up //get rid of shared memory shmdt(shm_front); shmctl(shmid, IPC_RMID, NULL); //printf("\n\n"); return 0; } I tried accessing the shared memory by dereferencing the pointer to the struct, but got a segmentation fault each time.

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• Is there a way to make IE7 default to ms-image-mode:bicubic?

  - by Mark Ransom

  Internet Explorer 7 uses a rather crude method to resize images by default. There's a CSS tag img { -ms-interpolation-mode: bicubic; } to get better results, but I'm unable to change the source of the page. IE8 uses the better method as the default, but this is a corporate environment that is unable to upgrade at this moment. Is there anything in the options or a registry hack to change the default resizing mode in IE7?

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• Access images for my project when it is embedded in another project

  - by Vaccano

  I have the following situation: ProjectA needs to show an image on a UserControl. It has the image in its project (can be a Resource or whatever). But ProjectA is just a dll. It is used by ProjectB (via Prism). So doing this in ProjectA works for design time (if the MyImage.png file is set to "Resource" compile action): <Image Source="pack://application:,,,/ProjectA;component/MyImage.png"></Image> But at run time, all that is copied to ProjectB is the dll (and that is all I want copied. So MyImage.png is present in the running folder... and it does not show an image. I thought that Making it Resource would embed it but it does not seem to work. I also tried to use a Resources.resx and that does not seem to work at all (or I can't find the way to bind the image in xaml). How can I put the image inside my dll and then reference it from there (or some other non-file system dependent way to get the image)?

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• Is there a quality, file-size, or other benefit to JPEG sizes being multiples of 8px or 16px?

  - by davebug

  The JPEG compression encoding process splits a given image into blocks of 8x8 pixels, working with these blocks in future lossy and lossless compressions. [source] It is also mentioned that if the image is a multiple 1MCU block (defined as a Minimum Coded Unit, 'usually 16 pixels in both directions') that lossless alterations to a JPEG can be performed. [source] I am working with product images and would like to know both if, and how much benefit can be derived from using multiples of 16 in my final image size (say, using an image with size 480px by 360px) vs. a non-multiple of 16 (such as 484x362). In this example I am not interested in further alterations, editing, or recompression of the final image. To try to get closer to a specific answer where I know there must be largely generalities: Given a 480x360 image that is 64k and saved at maximum quality in Photoshop [example]: Can I expect any quality loss from an image that is 484x362 What amount of file size addition can I expect (for this example, the additional space would be white pixels) Are there any other disadvantages to growing larger than the 8px grid? I know it's arbitrary to use that specific example, but it would still be helpful (for me and potentially any others pondering an image size) to understand what level of compromise I'd be dealing with in breaking the non-8px grid. The key issue here is a debate I've had is whether 8-pixel divisible images are higher quality than images that are not divisible by 8-pixels.

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• How can i pull an image and data from a Database?

  - by user1851377

  I am trying to pull data from a Database using C#.net and use a Foreach loop to make it visible on a page. Every time i run the code i only get one item that shows up when i know that there is at least 7 items in the DB. i have placed the code below for the C#. SqlConnection oConnection = new SqlConnection(ConfigurationManager.ConnectionStrings["HomeGrownEnergyConnectionString"].ToString()); string sqlEnergy = "Select * from Product p where p.ProductTypeId=3"; SqlCommand oCmd = new SqlCommand(sqlEnergy, oConnection); DataTable dtenergy = new DataTable(); SqlDataAdapter oDa = new SqlDataAdapter(oCmd); try { oConnection.Open(); ; oDa.Fill(dtenergy); } catch (Exception ex) { lblnodata.Text = ex.Message; return; } finally { oConnection.Close(); } DataTableReader results = dtenergy.CreateDataReader(); if (results.HasRows) { results.Read(); foreach(DataRow result in dtenergy.Rows) { byte[] imgProd = result["ThumnailLocation"] as byte[]; ID.Text = result["ProductID"].ToString(); Name.Text = result["Name"].ToString(); price.Text = FormatPriceColumn(result["Price"].ToString()); } } Here is the code for the asp.net. <div> <asp:Image ID="imgProd" CssClass="ProdImg" runat="server" /> <asp:Label runat="server" ID="ID" /> <asp:Label runat="server" ID="Name" /> <asp:Label runat="server" ID="price" /> <asp:TextBox ID="txtQty" MaxLength="3" runat="server" Width="30px" /> <asp:Button runat="server" ID="Addtocart" Text="Add To Cart" CommandName="AddToCart" ItemStyle-CssClass="btnCol" /> If someone could please help me that would be great thanks.

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• Tool to create unscaled call-out from a thumbnail image?

  - by Mal Ross

  I'm creating an online tutorial for some software and need to include screenshots. In particular, I want to highlight the position and appearance of a given control in a large screen. Given that I haven't got the space to show the screen at full resolution (at least, not alongside the tutorial text), I figured I would use a kind of call-out from a thumbnail. Here's my poor first effort, made in Paint.NET: Given how long this took me to craft, I'd really like to find a tool to speed things up (and make them look a little more professional!). Preferably a free one, too - or one that has a downloadable trial. The exact style it produces isn't that important, provided it achieves the desired effect. Can anyone help me out? Thanks, Mal. P.S. I'm using Windows Vista.

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• Certain websites do not open. Instead a 1*1 image gets displayed

  - by Ranjith - SR2GF

  When I try to visit certain websites like www.bidvertiser.com, www.buysellads.com, a white page shows up, the title bar displays the site name followed by (1x1) in brackets. When I right click, 'View Source' option appears disabled. The Save As.. option shows the file type to be gif. However, when I preview the site in Google search results ( by moving the mouse over ) the screenshot of the site displays well. This happens on all the three browsers on my computer: Chrome, Firefox and IE. What is the problem and how can it be resolved? EDIT: At some point of time, they probably worked on my computer! I think it is a more general problem. The same happens when I click on certain links in Google search results.

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• Read all sub directories within a certain folder to display a random image.

  - by Andy

  I have this code i have been using....but i need a conditional where it will read all the sub directories of /bg to select an image as opposed to a specific folder if they were on a subpage. Heres my code so far which works perfectly for all subpages to display specific images: //This would tell us its on the homepage if it helps: $this->level() == 0 //This is the code so far $path = '/home/sites/mydomain.co.uk/public_html/public/images/bg/'.$this->slug; $homepagefile = URL_PUBLIC.'public/images/bg/'.$this->slug.'/main.jpg'; $bgimagearray = array(); $iterator = new DirectoryIterator($path); foreach ($iterator as $fileinfo) { if ($fileinfo->isFile() && !preg_match('\.jpg$/', $fileinfo->getFilename())) { $bgimagearray[] = "'" . $fileinfo->getFilename() . "'"; } } $bgimage = array_rand($bgimagearray); ?> <div id="bg"> <div> <table cellspacing="0" cellpadding="0"> <tr> <td><img src="<?php echo $file.trim($bgimagearray[$bgimage], "'"); ?>" alt=""/></td> </tr> </table> </div> </div> Any help would be appreciated, im sure its not rocket science but ive tried a few ways and cant get my head around it. Thanks in advance.

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• How to force client browser to download images from server rather using its cache

  - by anonim.developer

  Assume a simple aspx data entry page in which admin user can upload an image as well as some other data. They are stored in database and the next time admin visits that page to edit record, image data fetched and a preview generated and saved to disk (using GDI+) and the preview is shown in an image control. This procedure works fine for the first time however if the image changes (a new one uploaded) the next time the page is surfed it shows previously uploaded image. I debugged the application and everything works correct. The new image data is in database and new preview is stored in Temp location however the page shows previous one. If I refresh the page it shows the new image preview. I should mention that preview is always saved to disk with one name (id of each record as the name). I think that is because of IE and other browsers use client cache instead of loading images each time a page is surfed. I wonder if there is a way to force the client browser to refresh itself so the newly uploaded image is shown without user intervention. Thanks and appreciation in advance,

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• jQuery toggle() with unknown initial state

  - by Jason Morhardt

  I have a project that I am working on that uses a little image to mark a record as a favorite on multiple rows in a table. The data gets pulled from a DB and the image is based on whether or not that item is a favorite. One image for a favorite, a different image if not a favorite. I want the user to be able to toggle the image and make it a favorite or not. Here's my code: $(function () { $('.FavoriteToggle').toggle( function () { $(this).find("img").attr({src:"../../images/icons/favorite.png"}); var ListText = $(this).find('.FavoriteToggleIcon').attr("title"); var ListID = ListText.match(/\d+/); $.ajax({ url: "include/AJAX.inc.php", type: "GET", data: "action=favorite&ItemType=0&ItemID=" + ListID, success: function () {} }); }, function () { $(this).find("img").attr({src:"../../images/icons/favorite_not.png"}); var ListText = $(this).find('.FavoriteToggleIcon').attr("title"); var ListID = ListText.match(/\d+/); $.ajax({ url: "include/AJAX.inc.php", type: "GET", data: "action=favorite&ItemType=0&ItemID=" + ListID, success: function () {} }); } ); }); Works great if the initial state is not a favorite. But you have to double click to get the image to change if it IS a favorite initially. This causes the AJAX to fire twice and essentially make it a favorite then not a favorite before the image responds. The user thinks he's made it a favorite because the image changed, but in fact, it's not. Help anybody?

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• BitmapFactory.decodeFile out of memory with images 2400x2400

  - by alasarr

  I need to send an image from a file to a server. The server request the image in a resolution of 2400x2400. What I'm trying to do is: 1) Get a Bitmap using BitmapFactory.decodeFile using the correct inSampleSize. 2) Compress the image in JPEG with a quality of 40% 3) Encode the image in base64 4) Sent to the server I cannot achieve the first step, it throws an out of memory exception. I'm sure the inSampleSize is correct but I suppose even with inSampleSize the Bitmap is huge (around 30 MB in DDMS). Any ideas how can do it? Can I do these steps without created a bitmap object? I mean doing it on filesystem instead of RAM memory. This is the current code: // The following function calculate the correct inSampleSize Bitmap image = Util.decodeSampledBitmapFromFile(imagePath, width,height); // compressing the image ByteArrayOutputStream baos = new ByteArrayOutputStream(); image.compress(Bitmap.CompressFormat.JPEG, 40, baos); // encode image String encodedImage = Base64.encodeToString(baos.toByteArray(),Base64.DEFAULT));

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• More than one JPanel in a Frame / having a brackground Image and another Layer with Components on the top

  - by user1905203

  I've got a JFrame with a JPanel in which there is a JLabel with an ImageIcon(). Everything's working perfectly, problem is i now want to add another JPanel with all the other stuff like buttons and so on to the JFrame. But it still shows the background Image on top and nothing with the second JPanel. Can someone help me? Here is an extract of my code: JFrame window = new JFrame("Http Download"); /* * Background Section */ JPanel panel1 = new JPanel(); JLabel lbl1 = new JLabel(); /* * Component Section */ JPanel panel2 = new JPanel(); JLabel lbl2 = new JLabel(); /* * Dimension Section */ Dimension windowSize = new Dimension(800, 600); Dimension screen = Toolkit.getDefaultToolkit().getScreenSize(); public HTTPDownloadGUI() { window.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); panel1.setLayout(null); panel1.setSize(windowSize); panel1.setOpaque(false); panel2.setLayout(null); panel2.setSize(windowSize); panel2.setOpaque(false); lbl1.setSize(windowSize); lbl1.setLocation(0, 0); lbl1.setIcon(new ImageIcon(getClass().getResource("bg1.png"))); panel1.add(lbl1); lbl2.setBounds(0, 0, 100, 100); //lbl2.setIcon(new ImageIcon(getClass().getResource("bg2.png"))); lbl2.setBackground(Color.GREEN); panel2.add(lbl2); panel1.add(panel2); window.add(panel1); int X = (screen.width / 2) - (windowSize.width / 2); int Y = (screen.height / 2) - (windowSize.height / 2); window.setBounds(X,Y , windowSize.width, windowSize.height); window.setVisible(true); }

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