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  • How to exit from Native video player in Blackberry?

    - by Rajapandian
    Hi, I created one blackberry application which will play a video on a button click.This is my code, invocation=new Invocation("file:///SDCard/Blackberry/videos/PlayingVideo/funny.mp4"); registry=Registry.getRegistry("net.rim.device.api.content.BlackBerryContentHandler"); try { registry.invoke(invocation); } catch(Exception e) { } Now i can play the Video file.After clicking the Back button the native player is going to the background.It always running in the background.But i want to close that player.I have no idea about how to do it.Anybody knows please help me.

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  • How to resolve this PostgreSQL error on OS 10.6 (Snow Leopard)

    - by wgpubs
    I followed the instructions for setting up postgresql from this site All seems to go fine until I try: createuser --superuser myname -U postgres I get the following exception: createuser: could not connect to database postgres: could not connect to server: No such file or directory Is the server running locally and accepting connections on Unix domain socket "/tmp/.s.PGSQL.5432"? For the life of me I can't figure out how to resolve this. Any ideas???

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  • Store more than 24 hours in a DateTime

    - by Rob
    I work in a bizarre and irrational industry where we need to be able to represent the time of day as 06:00:00 to 30:00:00 instead of 0:00:00 to 24:00:00. Is there any way to do this using the DateTime type? If I try to construct a date time with an hour value greater than 24 it throws an exception.

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  • cannot access sql server after publishing site in iis7

    - by vinu
    I am created a website using visual studio 2010. On the time of the development of website I am able to access the database.. but after publishing the site using IIS7..i was unable to access the database..the exception occured during that time was "the connection is in the closed state".in IIS7 When I changed the application pool identity to localsystem, it worked. Data base is installed in the same machine. and server is SQL SERVER 2008 R2

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  • wamp can't put offline!!

    - by user343570
    when i wana put it offline it say: "Could not execute menu item (internal error) [Exception] Could not perform service action: The service has not been started." all froums said to me:u must under Apache open the httpd.conf and change the lines #Listen 12.34.56.78:80 Listen 80 to #Listen 12.34.56.78:80 Listen 8080 save the file and you are done. but my httpd.conf is blank!!!i need it

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  • xstream handles non-english character

    - by Yan Cheng CHEOK
    I have the following code : /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package helloworld; import com.thoughtworks.xstream.XStream; import java.io.File; import java.io.FileOutputStream; import java.io.InputStream; import java.io.OutputStream; import javax.swing.JOptionPane; /** * * @author yccheok */ public class Test { @SuppressWarnings("unchecked") public static <A> A fromXML(Class c, File file) { XStream xStream = new XStream(); InputStream inputStream = null; try { inputStream = new java.io.FileInputStream(file); Object object = xStream.fromXML(inputStream); if (c.isInstance(object)) { return (A)object; } } catch (Exception exp) { exp.printStackTrace(); } finally { if (inputStream != null) { try { inputStream.close(); inputStream = null; } catch (java.io.IOException exp) { exp.printStackTrace(); return null; } } } return null; } @SuppressWarnings("unchecked") public static <A> A fromXML(Class c, String filePath) { return (A)fromXML(c, new File(filePath)); } public static boolean toXML(Object object, File file) { XStream xStream = new XStream(); OutputStream outputStream = null; try { outputStream = new FileOutputStream(file); xStream.toXML(object, outputStream); } catch (Exception exp) { exp.printStackTrace(); return false; } finally { if (outputStream != null) { try { outputStream.close(); outputStream = null; } catch (java.io.IOException exp) { exp.printStackTrace(); return false; } } } return true; } public static boolean toXML(Object object, String filePath) { return toXML(object, new File(filePath)); } public static void main(String args[]) { String s = "\u6210\u4EA4\u91CF"; // print ??? System.out.println(s); // fine! show ??? JOptionPane.showMessageDialog(null, s); toXML(s, "C:\\A.XML"); String o = fromXML(String.class, "C:\\A.XML"); // show ??? JOptionPane.showMessageDialog(null, o); } } I run the following code through command prompt in Windows Vista. 1) May I know why System.out.println unable to print out Chinese Character in console? 2) I open up the xstream file. The saved value is <string>???</string> How can I make xstream save Chinese Character correctly? Thanks.

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  • Re-define File::dirname ruby method

    - by jrhicks
    I'm trying to redefine the File.dirname method to first change %20s to spaces. But the following gives me an error class File old_dirname = instance_method(:dirname) define_method(:dirname) { |s| s = s.gsub("%20"," ") old_dirname.bind(self).call(s) } end This trhows a NameError exception: undefined method 'dirname' for class 'File' What is the right way to do this?

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  • Convert C# Lambda to vb.net

    - by Joven
    Need Help in converting this to VB.NET public void GetCustomers(Action<IEnumerable<Customer>> onSuccess, Action<Exception> onFail) { Manager.Customers.ExecuteAsync(op => { if (op.CompletedSuccessfully) { if (onSuccess != null) onSuccess(op.Results); } else { if (onFail != null) { op.MarkErrorAsHandled(); onFail(op.Error); } } } ); }

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  • How do i cast an object to a string when object is not a string?

    - by acidzombie24
    I have class A, B, C. They all can implicitly convert to a string public static implicit operator A(string sz_) { ... return sz; } I have code that does this object AClassWhichImplicitlyConvertsToString { ... ((KnownType)(String)AClassWhichImplicitlyConvertsToString).KnownFunc() } The problem is, AClassWhichImplicitlyConvertsToString isnt a string even though it can be typecast into one implicitly. I get a bad cast exception. How do i say its ok as long as the class has an operator to convert into a string?

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  • Zend Framework Module Based Error Handling

    - by cnkt
    Zend_Controller_Plugin_ErrorHandler always forwards to ErrorController::errorAction() in the default module but i want it be module aware. For example when a exception throws it must be call the module's ErrorController like Admin_ErrorController:errorAction. How can i do this? Thanks.

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  • Losing session after Login - Java

    - by Patrick Villela
    I'm building an application that needs to login to a certain page and make a navigation. I can login, provided that the response contains a string that identifies it. But, when I navigate to the second page, I can't see the page as a logged user, only as anonymous. I'll provide my code. import java.net.*; import java.security.*; import java.security.cert.*; import javax.net.ssl.*; import java.io.*; import java.util.*; public class PostTest { static HttpsURLConnection conn = null; private static class DefaultTrustManager implements X509TrustManager { @Override public void checkClientTrusted(X509Certificate[] arg0, String arg1) throws CertificateException {} @Override public void checkServerTrusted(X509Certificate[] arg0, String arg1) throws CertificateException {} @Override public X509Certificate[] getAcceptedIssuers() { return null; } } public static void main(String[] args) { try { SSLContext ctx = SSLContext.getInstance("TLS"); ctx.init(new KeyManager[0], new TrustManager[] {new DefaultTrustManager()}, new SecureRandom()); SSLContext.setDefault(ctx); String data = URLEncoder.encode("txtUserName", "UTF-8") + "=" + URLEncoder.encode(/*username*/, "UTF-8"); data += "&" + URLEncoder.encode("txtPassword", "UTF-8") + "=" + URLEncoder.encode(/*password*/", "UTF-8"); data += "&" + URLEncoder.encode("envia", "UTF-8") + "=" + URLEncoder.encode("1", "UTF-8"); connectToSSL(/*login url*/); conn.setDoOutput(true); OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream()); wr.write(data); wr.flush(); BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); String line; String resposta = ""; while((line = rd.readLine()) != null) { resposta += line + "\n"; } System.out.println("valid login -> " + resposta.contains(/*string that assures me I'm looged in*/)); connectToSSL(/*first navigation page*/); rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); while((line = rd.readLine()) != null) { System.out.println(line); } } catch(Exception e) { e.printStackTrace(); } } private static void connectToSSL(String address) { try { URL url = new URL(address); conn = (HttpsURLConnection) url.openConnection(); conn.setHostnameVerifier(new HostnameVerifier() { @Override public boolean verify(String arg0, SSLSession arg1) { return true; } }); } catch(Exception ex) { ex.printStackTrace(); } } } Any further information, just ask. Thanks in advance.

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  • Visual Studio stack trace in notepad++

    - by LoveMeSomeCode
    This is probably just a setting I'm not seeing, but when I get a stack trace out of Visual Studio's exception helper dialog, it has \r\n after each "line" in the call stack. When I copy this and paste it into Notepad++, it shows up as literally \r\n, visible in the document. Of course I'd like these to be interpreted as CR LF, so everything's on a different line. Anyone know how to do this?

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  • Java return to position N in call stack.

    - by Finbarr
    Using the return keyword in Java code will return execution to the last piece of calling code in the call stack. If object foo calls baz.bar(), the return keyword in the bar method will continue code execution in foo. Let's say I have object foo that calls foofoo that calls foofoofoo in the above scenario, and foofoofoo calls baz.bar(). Is there anyway in Java to use the return keyword, or something else, so that the code in the bar method can return all the way back up to foo? (WITHOUT THROWING AN EXCEPTION)

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  • How to rectify this issues: asp.net PageRequestManagerParserErrorException

    - by sameer
    i have a search panel where on click of search button im getting this exception this is for the first time, subsequent click it result the proper result. Can any one explain how solve the issue. error message: Sys.WebForms.PageRequestManagerParserErrorException: The Message received from the server could not be parsed.Coommon causes for this error are when the response is modified by Calls to Repose.Write(), response filters,HttpModules, or server trace is enabled. Details:Error Parsing near ' | '.

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  • which version of the code below is right?

    - by TheVillageIdiot
    Hi I found this function in a utilities code file: Version 1: public static bool IsValidLong(string strLong) { bool result = true; try { long tmp = long.Parse(strLong); } catch (Exception ex) { result = false; } return result; } I want to replace this (and validators for other types) with following: Version 2: public static bool IsValidLong(string strLong) { long l; return long.TryParse(strLong, out l); } which version is better and why?

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  • Server.Transfer does not work?

    - by trnTash
    I want to redirect to another page using Server.Transfer and I have this simple code: if (Page.IsPostBack) { try { Server.Transfer("AnotherPage.aspx"); } catch (Exception) { throw ; } } But I'm getting an error: "Error executing child request for AnotherPage.aspx.". Could not find the solution on the net. Just to mention, Response.Redirect works flawlessly.

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  • Swing UI does not have native OS look

    - by Virat Kadaru
    I am building an application in java swing and I am using the following code to give the UI a native OS look try { UIManager.setLookAndFeel( UIManager.getSystemLookAndFeelClassName()); } catch (Exception e) { e.printStackTrace(); } On a OS X, the look is fine, but on windows (XP and 7) the buttons look like this. I have used this exact same code on other projects and it works fine. But in this particular project I get a completely different look. Thanks in advance!

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  • Why sockets does not die when server dies? Why socket dies when server is alive?

    - by Roman
    I try to play with sockets a bit. For that I wrote very simple "client" and "server" applications. Client: import java.net.*; public class client { public static void main(String[] args) throws Exception { InetAddress localhost = InetAddress.getLocalHost(); System.out.println("before"); Socket clientSideSocket = null; try { clientSideSocket = new Socket(localhost,12345,localhost,54321); } catch (ConnectException e) { System.out.println("Connection Refused"); } System.out.println("after"); if (clientSideSocket != null) { clientSideSocket.close(); } } } Server: import java.net.*; public class server { public static void main(String[] args) throws Exception { ServerSocket listener = new ServerSocket(12345); while (true) { Socket serverSideSocket = listener.accept(); System.out.println("A client-request is accepted."); } } } And I found a behavior that I cannot explain: I start a server, than I start a client. Connection is successfully established (client stops running and server is running). Then I close the server and start it again in a second. After that I start a client and it writes "Connection Refused". It seems to me that the server "remember" the old connection and does not want to open the second connection twice. But I do not understand how it is possible. Because I killed the previous server and started a new one! I do not start the server immediately after the previous one was killed (I wait like 20 seconds). In this case the server "forget" the socket from the previous server and accepts the request from the client. I start the server and then I start the client. Connection is established (server writes: "A client-request is accepted"). Then I wait a minute and start the client again. And server (which was running the whole time) accept the request again! Why? The server should not accept the request from the same client-IP and client-port but it does!

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  • How to properly clean up JDBC resources in Java?

    - by user523086
    What is considered best practices when cleaning up JDBC resources and why? I kept the example short, thus just the cleaning up of the ResultSet. finally { if(rs != null) try{ rs.close(); } catch(SQLException ignored) {} } versus finally { try{ rs.close(); } catch(Exception ignored) {} } Personally I favour the second option since it is a bit shorter. Any input on this is much appreciated.

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  • How to get an instance of instance System.Diagnostics.Process by processID on a remote machine

    - by Tomas1
    Hi all, I want to run & control a process remotely, I found the best way is the WMI APIs, The WMI gives me information about the remote process but I need more control like waiting it and getting the standard output and errors, how can I do that, and can I get an instance of System.Diagnostics.Process class by instance ID remotely? note: I tried to get an instance of the Process by Process.GetProcessByPID and passign machineName parameter, but and Exception has thrown. Thanks in advance.

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  • Integration tests - "no exceptions are thrown" approach. Does it make sense?

    - by Andrew Florko
    Sometimes integration tests are rather complex to write or developers have no enough time to check output - does it make sense to write tests that make sure "no exceptions are thrown" only? Such tests provide some input parameters set(s) and doesn't check the result, but only make sure code not failed with exception? May be such tests are not very useful but appropriate in situations when you have no time?

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  • Running a Java program with input from a file

    - by Katy
    I am writing a program that reads the input from a file and then prints it to the screen. When I run it without taking the input from the file, it works perfectly fine. However, every time I try to run it from the file it gives me an "Exception in thread "main" java.util.NoSuchElementException: No line found at" error that occurs every place the input is suppose to be read. I have no idea what is going on.

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