fred 22 - Page 26 - Developer IT

port forwarding with socks over proxy

- by Oz123

I am trying to browse a wiki that runs on a server inside one domain from another domain. The wiki is accessible only on the LAN, but I need to browse it from another LAN to which I connect with an SSH tunnel ... Here is my setup and the steps I did so far: ~.ssh/confing on wikihost: Host gateway User kisteuser Port 443 Hostname gateway.companydomain.com ProxyCommand /home/myuser/bin/ssh-https-tunnel %h %p # ssh-https-tunnel: # http://ttcplinux.sourceforge.net/tools/stunnel Protocol 2 IdentityFile ~/.ssh/key_dsa LocalForward 11069 localhost:11069 Host server1 User kisteuser Hostname localhost Port 11069 LocalForward 8022 server1:22 LocalForward 17001 server1:7100 LocalForward 8080 www-proxy:3128 RemoteForward 11069 localhost:22 from wikihost myuser@wikihost: ssh -XC -t gateway.companydomain.com ssh -L11069:localhost:22 server1 on another terminal: ssh gateway.companydomain.com Now, on my companydomain I would like to start firefox and browse the wiki on wikihost. I did: [email protected] ~ $ ssh gateway Have a lot of fun... kisteuser@gateway ~ $ ssh -D 8383 localhost user@localhost's password: user@wikiserver:~> My .ssh/config on that side looks like that: host server1 localforward 11069 localhost:11069 host localhost user myuser port 11069 host wikiserver forwardagent yes user myuser port 11069 hostname localhost Now, I started firefox on the server called gateway, and edited the proxy settings to use SOCKSv5, specifying that the proxy should be gateway and use the port 8383... kisteuser@gateway ~ $ LANG=C firefox -P --no-remote And, now I get the following error popping in the Terminal of wikiserver: myuser@wikiserver:~> channel 3: open failed: connect failed: Connection refused channel 3: open failed: connect failed: Connection refused channel 3: open failed: connect failed: Connection refused Confused? Me too ... Please help me understand how to properly build the tunnels and browse the wiki over SOCKS protocol. update: I managed to browse the wiki on wikiserver with the following changes: host wikiserver forwardagent yes user myuser port 11069 hostname localhost localforward 8339 localhost:8443 Now when I ssh gateway I launch Firefox and go to localhost:8339 and I hit the start page of the wiki, which is served on Port 8443. Now I ask myself is SOCKS really needed? Can someone elaborate on that ?

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Ubuntu Pound Reverse Proxy Load Balancing Based off active server load?

- by Andrew

I have Pound installed on a loadbalancer. It seems to work okay, except that it randomly assigns the backend server to forward the request to. I've put 1 backend machine under so much load that it went into using swap, and I can't even ssh into it to test this scenareo. I would like the loadbalancer to realize that the machine is overloaded, and send it to a different backend machine. However it doesn't. I've read the man page and it seems like the directive "DynScale 1" is what would monitor this, but it still redirects to the overloaded server. I've also put in "HAport 22" to the backend figuring since I can't ssh in, neither could the loadbalancer and it would consider the backend server dead until it gets rid of the load and responds, but that didn't help either. If anyone could help with this, I'd appreciate it. My current config is below. ###################################################################### ## global options: User "www-data" Group "www-data" #RootJail "/chroot/pound" ## Logging: (goes to syslog by default) ## 0 no logging ## 1 normal ## 2 extended ## 3 Apache-style (common log format) LogLevel 3 ## check backend every X secs: Alive 5 DynScale 1 Client 1200 TimeOut 1500 # poundctl control socket Control "/var/run/pound/poundctl.socket" ###################################################################### ## listen, redirect and ... to: ## redirect all requests on port 80 to SSL ListenHTTP Address 192.168.1.XX Port 80 Service Redirect "https://xxx.com/" End End ListenHTTPS Address 192.168.1.XX Port 443 Cert "/files/www.xxx.com.pem" Service BackEnd Address 192.168.1.1 Port 80 HAport 22 End BackEnd Address 192.168.1.2 Port 80 HAport 22 End End End

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Timely automatic unexpected reboot on ubuntu desktop

- by ahmad

We have a remote linux server (ubuntu desktop). The system log indicates the system has been restarted on the timely fashion. Here is a part of the last output: ut pts/0 192.169.50.2-sta Sat Nov 24 22:17 still logged in reboot system boot 2.6.32-21-generi Sat Nov 24 22:04 - 22:17 (00:13) ut pts/0 server.local Sat Nov 24 21:36 - crash (00:27) reboot system boot 2.6.32-21-generi Sat Nov 24 15:55 - 22:17 (06:21) reboot system boot 2.6.32-21-generi Fri Nov 23 18:02 - 22:17 (1+04:14) reboot system boot 2.6.32-21-generi Fri Nov 23 10:39 - 22:17 (1+11:38) reboot system boot 2.6.32-21-generi Fri Nov 23 04:18 - 22:17 (1+17:59) reboot system boot 2.6.32-21-generi Fri Nov 23 03:57 - 22:17 (1+18:20) reboot system boot 2.6.32-21-generi Thu Nov 22 20:38 - 22:17 (2+01:38) reboot system boot 2.6.32-21-generi Thu Nov 22 11:13 - 22:17 (2+11:03) reboot system boot 2.6.32-21-generi Thu Nov 22 08:12 - 22:17 (2+14:05) reboot system boot 2.6.32-21-generi Wed Nov 21 11:16 - 22:17 (3+11:00) reboot system boot 2.6.32-21-generi Tue Nov 20 22:36 - 22:17 (3+23:41) reboot system boot 2.6.32-21-generi Tue Nov 20 14:12 - 22:17 (4+08:05) reboot system boot 2.6.32-21-generi Tue Nov 20 11:32 - 22:17 (4+10:44) reboot system boot 2.6.32-21-generi Tue Nov 20 01:52 - 22:17 (4+20:25) reboot system boot 2.6.32-21-generi Tue Nov 20 00:22 - 22:17 (4+21:55) reboot system boot 2.6.32-21-generi Mon Nov 19 17:27 - 22:17 (5+04:50) It looks the system is set to be restarted at 22:17. Can anyone guide me why this happens? Thanks in advance.

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How do I Forward root's email to an external email address?

- by ErebusBat

I have a small server (Ubuntu 10.04) at my house and I would like to forward root's email to my gmail hosted domain to get security notifications and what not. I ripped everything out and started from scratch and ran into some other issues. I now have sendmail working in the sense that I can mail [email protected] and get the mail. HOWEVER, adding an address to /root/.forward does not actually forward the message. I get the following in my logs: Dec 22 14:04:37 batcave sendmail[4695]: oBML4bAT004695: to=<root@batcave>, ctladdr=aburns (1000/1000), delay=00:00:00, xdelay=00:00:00, mailer=relay, pri=30075, relay=[127.0.0.1] [127.0.0.1], dsn=2.0.0, stat=Sent (oBML4bJ9004696 Message accepted for delivery) Dec 22 14:04:39 batcave sm-mta[4698]: STARTTLS=client, relay=[69.145.248.18], version=TLSv1/SSLv3, verify=FAIL, cipher=DES-CBC3-SHA, bits=168/168 Dec 22 14:04:40 batcave sm-mta[4698]: oBML4bJ9004696: to=<[email protected]>, ctladdr=<[email protected]> (1000/1000), delay=00:00:03, xdelay=00:00:03, mailer=relay, pri=120336, relay=[69.145.248.18] [69.145.248.18], dsn=2.0.0, stat=Sent (OK 01/D4-00853-216621D4) You can see where my local sendmail instance accepts it then hands it off to my ISP, but with the wrong address ([email protected]).

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I need a reverse proxy solution for SSH

- by Bond

Hi here is a situation I have a server in a corporate data center for a project. I have an SSH access to this machine at port 22.There are some virtual machines running on this server and then at the back of every thing many other Operating systems are working. Now Since I am behind the data centers firewall my supervisor asked me if I can do some thing by which I can give many people on Internet access to these virtual machines directly. I know if I were allowed to get traffic on port other than 22 then I can do a port forwarding. But since I am not allowed this so what can be a solution in this case. The people who would like to connect might be complete idiots.Who may be happy just by opening putty at their machines or may be even filezilla.I have configured an Apache Reverse Proxy for redirecting the Internet traffic to the virtual machines on these hosts.But I am not clear as for SSH what can I do.So is there some thing equivalent to an Apache Reverse Proxy which can do similar work for SSH in this situation. I do not have firewall in my hands or any port other than 22 open and in fact even if I request they wont allow to open.2 times SSH is not some thing that my supervisor wants.

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Iptables ignoring a rule in the config file

- by Overdeath

I see lot of established connections to my apache server from the ip 188.241.114.22 which eventually causes apache to hang . After I restart the service everything works fine. I tried adding a rule in iptables -A INPUT -s 188.241.114.22 -j DROP but despite that I keep seeing connections from that IP. I'm using centOS and i'm adding the rule like thie: iptables -A INPUT -s 188.241.114.22 -j DROP Right afther that I save it using: service iptables save Here is the output of iptables -L -v ` Chain INPUT (policy ACCEPT 120K packets, 16M bytes) pkts bytes target prot opt in out source destination 0 0 DROP all -- any any lg01.mia02.pccwbtn.net anywhere 0 0 DROP all -- any any c-98-210-5-174.hsd1.ca.comcast.net anywhere 0 0 DROP all -- any any c-98-201-5-174.hsd1.tx.comcast.net anywhere 0 0 DROP all -- any any lg01.mia02.pccwbtn.net anywhere 0 0 DROP all -- any any www.dabacus2.com anywhere 0 0 DROP all -- any any 116.255.163.100 anywhere 0 0 DROP all -- any any 94.23.119.11 anywhere 0 0 DROP all -- any any 164.bajanet.mx anywhere 0 0 DROP all -- any any 173-203-71-136.static.cloud-ips.com anywhere 0 0 DROP all -- any any v1.oxygen.ro anywhere 0 0 DROP all -- any any 74.122.177.12 anywhere 0 0 DROP all -- any any 58.83.227.150 anywhere 0 0 DROP all -- any any v1.oxygen.ro anywhere 0 0 DROP all -- any any v1.oxygen.ro anywhere Chain FORWARD (policy ACCEPT 0 packets, 0 bytes) pkts bytes target prot opt in out source destination Chain OUTPUT (policy ACCEPT 186K packets, 224M bytes) pkts bytes target prot opt in out source destination `

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How can I fill (not replace) TAB with Spaces in MSWord?

- by Morteza

How can I fill (not replace) TAB with Spaces in MS Office Word? In other word, have a look at the following pic: 1 -> 222 -> 3 111 -> 2 -> 333 11 -> 22 -> 33 11 -> 2222 -> 3333 Suppose that - is indicated one TAB. As you see, each column is justified from left. I need to fill each TAB with Spaces, so that the justification not be confused. If I use 'Find & Replace' option to change each TABs to a specific number of Spaces, justification will be confused because each column have its own character number. In other word, if I change each TAB with 6 Spaces, the above will be changed to the follow: 1 222 3 111 2 333 11 22 33 11 2222 3333 My need is as follow (each dot indicate a Space): 1......222......3 111....2........333 11.....22.......33 11.....2222.....3333

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How To Boot with "mem=1024m" Argument using GRUB - Ubuntu 10.04

- by nicorellius

I am still working on this question. This new one is a different question so I thought it would be good to post a new question. Is this the proper protocol or should I have just edited the other question? I'm running Ubuntu 10.04 with the kernel 2.6.32-22-generic on a Toshiba Satellite laptop. When I enter the GRUB menu (I have Ubuntu 9.10 installed as well), I can choose which kernel to boot. I use scroll down to the one I want and press "e" and I expect to be able to enter mem=1024m and force the kernel to use this much memory. But when I run cat /proc/meminfo or look in the process manager after booting wth this argument I still see all the RAM: ~2 GB. Am I using this boot argument incorrectly? The boot configuration (before I add anything) looks like this: insmod ext2 set root=(hd0,1) search --no-floppy --fs-uuid --set 10270f21-1c42-494b-bd3f-813c23f6d\ 518 linux /boot/vmlinuz-2.6.32-22-generic root=UUID=10270f21-1c42-494b-b\ d3f-813c23f6d518 ro quiet splash initrd /boot/initrd.img-2.6.32-22-generic The way I did this was that I added the mem=1024m after the last line and pressed Ctrl+x (Emacs save and boot the kernel) and the system booted. I tried adding mem=1024m to the end and the beginning of this list and it appeared to not change the RAM allocation.

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Access an external SSH server through a restrictive proxy [on hold]

- by Cyrille

I'm a software developer. I wish to access my computer at home through SSH. For example, I sometime need to access my personal projects source code to check how I handled specific problems. Unfortunately, I currently work under an over-restrictive and anti-productive proxy that waste a hell of a lot of everyone's time (We often have to visit websites from our smartphones or use a web proxy to check very legitimates websites for answers, and don't get me started on other "security" overkill features we have to cope with...). Well, back to the subject, I can access my home computer from my phone (SSH, port 22 and 80 both redirected by router on port 22). It works, but it's quite uncomfortable. From my office computer, this is what I tried so far: export http_proxy=http://user:pass@proxyip:8080 echo "user:pass" > ~/.corkscrew-auth echo "ProxyCommand corkscrew proxyip 8080 %h %p /home/me/.corkscrew-auth" > ~/.ssh/config ssh 82.23.34.56 -l me -p 80 Proxy could not open connnection to 82.23.34.56: Forbidden ssh_exchange_identification: Connection closed by remote host (same without -p 80) Without corkscrew: ssh: connect to host 82.23.34.56 port 80: Connection timed out ssh: connect to host 82.23.34.56 port 22: Connection timed out Any other idea ?

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Enabling http access on port 80 for centos 6.3 from console

- by Hugo

Have a centos 6.3 box running on Parallels and I'm trying to open port 80 to be accesible from outside tried the gui solution from this post and it works, but I need to get it done from a script. Tried to do this: sudo /sbin/iptables -A INPUT -p tcp -m state --state NEW -m tcp --dport 80 -j ACCEPT sudo /sbin/iptables-save sudo /sbin/service iptables restart This creates exactly the same iptables entries as the GUI tool except it does not work: $ telnet xx.xxx.xx.xx 80 Trying xx.xxx.xx.xx... telnet: connect to address xx.xxx.xx.xx: Connection refused telnet: Unable to connect to remote host UPDATE: $ netstat -ntlp (No info could be read for "-p": geteuid()=500 but you should be root.) Active Internet connections (only servers) Proto Recv-Q Send-Q Local Address Foreign Address State PID/Program name tcp 0 0 0.0.0.0:3306 0.0.0.0:* LISTEN - tcp 0 0 127.0.0.1:6379 0.0.0.0:* LISTEN - tcp 0 0 0.0.0.0:111 0.0.0.0:* LISTEN - tcp 0 0 0.0.0.0:80 0.0.0.0:* LISTEN - tcp 0 0 0.0.0.0:22 0.0.0.0:* LISTEN - tcp 0 0 127.0.0.1:631 0.0.0.0:* LISTEN - tcp 0 0 127.0.0.1:25 0.0.0.0:* LISTEN - tcp 0 0 0.0.0.0:37439 0.0.0.0:* LISTEN - tcp 0 0 :::111 :::* LISTEN - tcp 0 0 :::22 :::* LISTEN - tcp 0 0 ::1:631 :::* LISTEN - tcp 0 0 :::60472 :::* LISTEN - $ sudo cat /etc/sysconfig/iptables # Generated by iptables-save v1.4.7 on Wed Dec 12 18:04:25 2012 *filter :INPUT ACCEPT [0:0] :FORWARD ACCEPT [0:0] :OUTPUT ACCEPT [5:640] -A INPUT -m state --state RELATED,ESTABLISHED -j ACCEPT -A INPUT -p icmp -j ACCEPT -A INPUT -i lo -j ACCEPT -A INPUT -p tcp -m state --state NEW -m tcp --dport 22 -j ACCEPT -A INPUT -j REJECT --reject-with icmp-host-prohibited -A INPUT -p tcp -m state --state NEW -m tcp --dport 80 -j ACCEPT -A FORWARD -j REJECT --reject-with icmp-host-prohibited COMMIT # Completed on Wed Dec 12 18:04:25 2012

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sql server uninstallation issue

- by angel

I'm unable to remove SQL Server 2008 sp1 completely from my system. I'm using windows 7 ultimate. Everytime I try uninstalling it i get the following error. How can I remove it? here is the log: Overall summary: Final result: Failed: see details below Exit code (Decimal): -2068643839 Exit facility code: 1203 Exit error code: 1 Exit message: Failed: see details below Start time: 2013-06-24 21:10:38 End time: 2013-06-24 21:21:17 Requested action: Uninstall Log with failure: C:\Program Files\Microsoft SQL Server\100\Setup Bootstrap\Log\20130624_210908\sql_rs_Cpu64_1.log Exception help link: http://go.microsoft.com/fwlink?LinkId=20476&ProdName=Microsoft+SQL+Server&EvtSrc=setup.rll&EvtID=50000&ProdVer=10.0.1600.22 Machine Properties: Machine name: ABHI-PC Machine processor count: 4 OS version: Windows Vista OS service pack: Service Pack 1 OS region: United States OS language: English (United States) OS architecture: x64 Process architecture: 64 Bit OS clustered: No Product features discovered: Product Instance Instance ID Feature Language Edition Version Clustered Sql Server 2008 MSSQLSERVER MSRS10.MSSQLSERVER Reporting Services 1033 Enterprise Edition 10.0.1600.22 No Sql Server 2008 Management Tools - Basic 10.0.1600.22 No Package properties: Description: SQL Server Database Services 2008 SQLProductFamilyCode: {628F8F38-600E-493D-9946-F4178F20A8A9} ProductName: SQL2008 Type: RTM Version: 10 SPLevel: 0 Installation edition: ENTERPRISE User Input Settings: ACTION: Uninstall CONFIGURATIONFILE: C:\Program Files\Microsoft SQL Server\100\Setup Bootstrap\Log\20130624_210908\ConfigurationFile.ini FEATURES: RS,SSMS,SNAC_SDK,CE_RUNTIME,CE_TOOLS,SNAC HELP: False INDICATEPROGRESS: False INSTANCEID: INSTANCENAME: MSSQLSERVER MEDIASOURCE: QUIET: False QUIETSIMPLE: False X86: False Configuration file: C:\Program Files\Microsoft SQL Server\100\Setup Bootstrap\Log\20130624_210908\ConfigurationFile.ini Detailed results: Feature: SQL Client Connectivity Status: Skipped MSI status: Passed Configuration status: Passed Feature: SQL Client Connectivity SDK Status: Skipped MSI status: Passed Configuration status: Passed Feature: Reporting Services Status: Failed: see logs for details MSI status: Passed Configuration status: Failed: see details below Configuration error code: 0xFFD65603 Configuration error description: Input string was not in a correct format. Configuration log: C:\Program Files\Microsoft SQL Server\100\Setup Bootstrap\Log\20130624_210908\Detail.txt Feature: SQL Compact Edition Tools Status: Passed MSI status: Passed Configuration status: Passed Feature: SQL Compact Edition Runtime Status: Skipped MSI status: Passed Configuration status: Passed Feature: Management Tools - Basic Status: Failed: see logs for details MSI status: Passed Configuration status: Passed Rules with failures: Global rules: There are no scenario-specific rules. Rules report file: C:\Program Files\Microsoft SQL Server\100\Setup Bootstrap\Log\20130624_210908\SystemConfigurationCheck_Report.htm

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Reverse NAT Setup for Hyper-V on Win 2008 R2

- by sukru

I'm trying to setup a Linux server behind a Windows Hyper-V host that will help supply some of the services (SSH, HTTPS, etc). However getting RRAS configured for reverse NAT (port forwarding) turned out to be a non trivial task. As a staring point, I tried forwarding port 22 (SSH) to the virtual machine. The virtual machine is on a public interface (i.e.: it also has a visible IP on the same network as the host). On RRAS management console I tried to add a rule, by adding "Local Area Connection" to NAT pool (Public Interface - Enable Nat), and an incoming rule for port 22 - :22. I also tried with the same port enabled on Windows Firewall (and not). The NAT management page tells there are "1 mappings" and "30+ Outbound packets transleted". However all other counters (Inbound packets translated, and respective rejected ones) are always zero. (I'm trying to access the server from an external machine). I can directly access the service if I give the VM's public IP, but not the host's one. Is there a way to enable this on RRAS?

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CentOS and OpenSSH [on hold]

- by Stephen

I've recently installed CentOS 6 on an old Dell PC. I'm trying to setup OpenSSH at the moment, I been following some tutorials (http://www.youtube.com/watch?v=QKafb0koJEg) on You Tube, while they have been very helpful I'm at the point where I need to ask some questions. My goal here is to be able to access the server from my work computer and from my personal laptop (which will be on the same home network as the server). I've installed OpenSSH with no issues. So the first thing I was advised to do was port forwarding. So in the sshd_config file, I've changed Port 22 to Port xxxx (where xxxx is a obviously a four digit value). I then restart the sshd service. I've also configured my router for forward port 22 onto xxxx. Is there anything else I need to do? I've generated the keys on my laptop, and I'm trying to copy them to the server as follows: scp id_rsa.pub xxxxxxxx@localhost:.ssh/authorized_keys but this command fails with the following error message: ssh: connect to host localhost port 22: Connection refused lost connection Any help appreciated. Regards...

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Iptables state tracking

- by complexgeek

Hi there. I've just taken over administration of a fairly complex firewall ruleset for a firewall box running Fedora Core 12, and there's one thing about it that is puzzling me. When I run nmap on the gateway from outside the network, I see all the expected services, but also sunrpc on port 111. The INPUT chain has DEFAULT DROP set, and there is no rule allowing port 111. As best I can tell (watching the packet counters before/during/after the scan) it's being allowed by the rule: "-m state --state RELATED,ESTABLISHED -j ACCEPT" but I don't understand why a brand new TCP connection would be considered RELATED or ESTABLISHED. Any suggestions would be greatly appreciated. EDIT: Conntrack modules: nf_conntrack_netlink 14925 0 nfnetlink 3479 1 nf_conntrack_netlink nf_conntrack_irc 5206 1 nf_nat_irc nf_conntrack_proto_udplite 3138 0 nf_conntrack_h323 62110 1 nf_nat_h323 nf_conntrack_proto_dccp 6878 0 nf_conntrack_sip 16921 1 nf_nat_sip nf_conntrack_proto_sctp 11131 0 nf_conntrack_pptp 10673 1 nf_nat_pptp nf_conntrack_sane 5458 0 nf_conntrack_proto_gre 6574 1 nf_conntrack_pptp nf_conntrack_amanda 2796 1 nf_nat_amanda nf_conntrack_ftp 11741 1 nf_nat_ftp nf_conntrack_tftp 4665 1 nf_nat_tftp nf_conntrack_netbios_ns 1534 0 nf_conntrack_ipv6 18504 2 ipv6 279399 40 ip6t_REJECT,nf_conntrack_ipv6 INPUT chain on the filter table: -A INPUT -s 192.168.200.10/32 -p tcp -m tcp --dport 22 -m state --state NEW,ESTABLISHED -j ACCEPT -A INPUT -s 127.0.0.0/8 -i lo -j ACCEPT -A INPUT -p udp -m udp --sport 67:68 --dport 67:68 -j ACCEPT -A INPUT -d 192.168.200.5/32 -i eth0 -j ACCEPT -A INPUT -d 192.168.1.2/32 -i eth0 -j ACCEPT -A INPUT -d {public_ip}/32 -i ppp0 -p tcp -m multiport --dports 22,80,443 -j ACCEPT -A INPUT -d {public_ip}/32 -i ppp0 -p tcp -m multiport --sports 22,25,80,443 -j ACCEPT -A INPUT -d {public_ip}/32 -i ppp0 -p udp -m udp --dport 1194 -j ACCEPT -A INPUT -d {public_ip}/32 -i ppp0 -p udp -m udp --sport 1194 -j ACCEPT -A INPUT -d {public_ip}/32 -i ppp0 -p udp -m multiport --sports 53,123 -j ACCEPT -A INPUT -d {public_ip}/32 -i ppp0 -p icmp -m icmp --icmp-type 8 -j ACCEPT -A INPUT -i eth0 -m state --state NEW -j ACCEPT -A INPUT -d {public_ip}/32 -m state --state NEW -j ACCEPT -A INPUT -m state --state RELATED,ESTABLISHED -j ACCEPT eth0 is connected to the internal network, eth3 is connected to an ADSL modem in bridge mode, ppp0 is the WAN connection tunneled over eth3.

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Why Does Private Access Remain Non-Private in .NET Within a Class?

- by AMissico

While cleaning some code today written by someone else, I changed the access modifier from Public to Private on a class variable/member/field. I expected a long list of compiler errors that I use to "refactor/rework/review" the code that used this variable. Imagine my surprise when I didn't get any errors. After reviewing, it turns out that another instance of the Class can access the private members of another instance declared within the Class. Totally unexcepted. Is this normal? I been coding in .NET since the beginning and never ran into this issue, nor read about it. I may have stumbled onto it before, but only "vaguely noticed" and move on. Can anyone explain this behavoir to me? Am I doing something wrong? I found this behavior in both C# and VB.NET. The code seems to take advantage of the ability to access private variables. Sincerely, Totally Confused Class Foo Private _int As Integer Private _foo As Foo Private _jack As Jack Private _fred As Fred Public Sub SetPrivate() _foo = New Foo _foo._int = 3 'TOTALLY UNEXPECTED _jack = New Jack '_jack._int = 3 'expected compile error because Foo doesn't know Jack _fred = New Fred '_fred._int = 3 'expected compile error because Fred hides from Foo End Sub Private Class Fred Private _int As Integer End Class End Class Class Jack Private _int As Integer End Class

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Rename files and directories using substitution and variables

- by rednectar

I have found several similar questions that have solutions, except they don't involve variables. I have a particular pattern in a tree of files and directories - the pattern is the word TEMPLATE. I want a script file to rename all of the files and directories by replacing the word TEMPLATE with some other name that is contained in the variable ${newName} If I knew that the value of ${newName} was say "Fred lives here", then the command find . -name '*TEMPLATE*' -exec bash -c 'mv "$0" "${0/TEMPLATE/Fred lives here}"' {} \; will do the job However, if my script is: newName="Fred lives here" find . -name '*TEMPLATE*' -exec bash -c 'mv "$0" "${0/TEMPLATE/${newName}}"' {} \; then the word TEMPLATE is replaced by null rather than "Fred lives here" I need the "" around $0 because there are spaces in the path name, so I can't do something like: find . -name '*TEMPLATE*' -exec bash -c 'mv "$0" "${0/TEMPLATE/"${newName}"}"' {} \; Can anyone help me get this script to work so that all files and directories that contain the word TEMPLATE have TEMPLATE replaced by whatever the value of ${newName} is eg, if newName="A different name" and a I had directory of /foo/bar/some TEMPLATE directory/with files then the directory would be renamed to /foo/bar/some A different name directory/with files and a file called some TEMPLATE file would be renamed to some A different name file

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How can I spot subtle Lisp syntax mistakes?

- by Marius Andersen

I'm a newbie playing around with Lisp (actually, Emacs Lisp). It's a lot of fun, except when I seem to run into the same syntax mistakes again and again. For instance, here's something I've encountered several times. I have some cond form, like (cond ((foo bar) (qux quux)) ((or corge (grault warg)) (fred) (t xyzzy))) and the default clause, which returns xyzzy, is never carried out, because it's actually nested inside the previous clause: (cond ((foo bar) (qux quux)) ((or corge (grault warg)) (fred)) (t xyzzy)) It's difficult for me to see such errors when the difference in indentation is only one space. Does this get easier with time? I also have problems when there's a large distance between the (mal-)indented line and the line it should be indented against. let forms with a lot of complex bindings, for example, or an unless form with a long conditional: (defun test () (unless (foo bar (qux quux) (or corge (grault warg) (fred)))) xyzzy) It turns out xyzzy was never inside the unless form at all: (defun test () (unless (foo bar (qux quux) (or corge (grault warg) (fred))) xyzzy)) I auto-indent habitually and use parenthesis highlighting to avoid counting parentheses. For the most part it works like a breeze, but occasionally, I discover my syntax mistakes only by debugging. What can I do?

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Recommendations for a Hex Viewer Control for Windows.Forms?

- by Fred F.

I need ability to display content in Hex View, like this from WinHex Offset 0 1 2 3 4 5 6 7 8 9 A B C D E F 00000000 EF BB BF 0D 0A 4D 69 63 72 6F 73 6F 66 74 20 56 ï»¿..Microsoft V 00000010 69 73 75 61 6C 20 53 74 75 64 69 6F 20 53 6F 6C isual Studio Sol 00000020 75 74 69 6F 6E 20 46 69 6C 65 2C 20 46 6F 72 6D ution File, Form 00000030 61 74 20 56 65 72 73 69 6F 6E 20 31 30 2E 30 30 at Version 10.00 00000040 0D 0A 23 20 56 69 73 75 61 6C 20 53 74 75 64 69 ..# Visual Studi 00000050 6F 20 32 30 30 38 0D 0A 50 72 6F 6A 65 63 74 28 o 2008..Project( 00000060 22 7B 46 31 38 34 42 30 38 46 2D 43 38 31 43 2D "{F184B08F-C81C- 00000070 34 35 46 36 2D 41 35 37 46 2D 35 41 42 44 39 39 45F6-A57F-5ABD99 Please recommend a control. Thank you.

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fullCalendar json with php in "agendaWeek"

- by Dennis

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PHP Curl and Curl

- by mithunmo

Hi , I am able to send a get request using PHP Curl . But the same thing when i try from command line in Linux (/usr/bin/curl ) I am unable to do so. Please find below my PHP curl that is working $url = "http://172.20.22.26"; $headers = array("Host: 172.20.22.26", "User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.0.1) Gecko/2008070208 Firefox/3.0.1", "Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8", "Accept-Language: en-us,en;q=0.5", "Accept-Encoding: gzip,deflate", "Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7", "Keep-Alive: 300", "Connection: keep-alive", "Authorization: Basic bWl0aHVuOm1pdGh1bg==" ); $ch = curl_init(); curl_setopt($ch,CURLOPT_URL,'http://172.20.22.26'); curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); // RETURN THE CONTENTS OF THE CALL curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,5); curl_setopt($ch,CURLOPT_AUTOREFERER,TRUE); curl_setopt($ch, CURLOPT_HTTPHEADER, $headers); $store = curl_exec($ch); ?> But the similar thing when I try to give in command line ( not using php ) it does not work . I get an error "curl: (18) transfer closed with outstanding read data remaining" and the GET request is not complete Please find below the command I am using curl -u mithun:mithun -H "Host: 172.20.22.29,Accept:text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8,Accept-Language:en-us,en;q=0.5,Accept-Encoding:gzip,deflate,Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7,Keep-Alive: 300,connection: keep-alive,Authorization: Basic bWl0aHVuOm1pdGh1bg==" http://172.20.22.29 The output i get curl: (18) transfer closed with outstanding read data remaining <frameset frameborder="0" framespacing="0" border="0" cols="220,*"><frameset frameborder="0" framespacing="0" border="0" rows="68,89%"><frame src="top.htm" name="top" scrolling=no noresize target=top marginwidth=2 marginheight=2><frame src="View.htm" name="left" target=left marginheight=1 scrolling=auto noresize marginwidth=5></frameset><frameset frameborder="0" framespacing="0" border="0" rows="68,*"><frame src="top2.htm" name="top2" target=top2 scrolling=no><frame src="sys_status.htm" name="right" target="_self"></frameset></frameset>[qateam@bras-1-cwmp08 usr]$

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dynamic programming [closed]

- by shruti

the input to this problem is a sequence S of integers(not necessarily positive). the problem is to find consecutive subsequence of S with maximum sum using dynamic programming. consecutive means that you are not allowed to skip numbers. for example: if the input was 12,-14,1,23,-6,22,-34,-13. the output would be 1,23,-6,22.

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Unix diff to only print relevant diff

- by mkal

I have these two files File:11 11 12345 File:22 123 456 Output of diff 11 22 2c2 < 456123 --- > 789 Output to be < 456123 > 789 I want it to not print 2c2 and "--" line. I looked at the man page but could not locate any help. Any ideas? The file has more than 1K lines

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MSBuild appears to only use old output files for custom build tools

- by sixlettervariables

I have an ANTLR grammar file as part of a C# project file and followed the steps outlined in the User Manual. <Project ...> <PropertyGroup> <Antlr3ToolPath>$(ProjectDir)tools\antlr-3.1.3\lib</Antlr3ToolPath> <AntlrCleanupPath>$(ProjectDir)AntlrCleanup\$(OutputPath)</AntlrCleanupPath> </PropertyGroup> <ItemGroup> <Antlr3 Include="Grammar\Foo.g"> <OutputFiles>FooLexer.cs;FooParser.cs</OutputFiles> </Antlr3> <Antlr3 Include="Grammar\Bar.g"> <OutputFiles>BarLexer.cs;BarParser.cs</OutputFiles> </Antlr3> </ItemGroup> <Target Name="GenerateAntlrCode" Inputs="@(Antlr3)" Outputs="%(Antlr3.OutputFiles)"> <Exec Command="java -cp %22$(Antlr3ToolPath)\antlr-3.1.3.jar%22 org.antlr.Tool -message-format vs2005 @(Antlr3Input)" Outputs="%(Antlr3Input.OutputFiles)" /> <Exec Command="%22$(AntlrCleanupPath)\AntlrCleanup.exe%22 @(Antlr3Input) %(Antlr3Input.OutputFiles)" /> </Target> <ItemGroup>  <Compile Include="Grammar\FooLexer.cs"> <AutoGen>True</AutoGen> <DesignTime>True</DesignTime> <DependentUpon>Foo.g</DependentUpon> </Compile> <Compile Include="Grammar\FooParser.cs"> <AutoGen>True</AutoGen> <DesignTime>True</DesignTime> <DependentUpon>Foo.g</DependentUpon> </Compile>  </ItemGroup> </Project> For whatever reason, the Compile steps only use old versions of the code, no amount of tweaking appears to help.

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PHP object access using string

- by Rob Waring

Hi all, I have an object in PHP with some very odd property names. I just need to know how to access a property when it's name is "//www.w3.org/1999/02/22-rdf-syntax-ns#type". I found something that suggested $object->{'//www.w3.org/1999/02/22-rdf-syntax-ns#type'}; but that doesn't seem to work. Thanks in advance Rob

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PHP/Java Bridge java.lang.NoSuchMethodException

- by m1sk

I have setup PHP/Java Bridge with working examples in netbeans tomcat directory. What doesnt work is using custom JAR Here is my code: package com.micha; public class Hello1Bean { public Hello1Bean() {} String hi() {return "This is my hello message";} String hello(String name) {return "Hello" + name;} } And the php code <!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title></title> </head> <body> <?php require_once ("java/Java.inc"); $world = new Java("com.micha.Hello1Bean"); echo java_values($world->hi()); echo "Hello Working Thingy\n\n"; ?> </body> </html> When I check http://localhost:8084/JavaBridge/mytest.php: javax.servlet.ServletException: java.lang.RuntimeException: PHP Fatal error: Uncaught [[o:Exception]:"java.lang.Exception: Invoke failed: [[o:Hello1Bean]]->hi. Cause: java.lang.NoSuchMethodException: hi(). Candidates: [] VM: 1.6.0_25@http://java.sun.com/" at: #-6 php.java.bridge.JavaBridge.checkM(JavaBridge.java:1085) #-5 php.java.bridge.JavaBridge.Invoke(JavaBridge.java:1024) #-4 php.java.bridge.Request.handleRequest(Request.java:417) #-3 php.java.bridge.Request.handleRequests(Request.java:500) #-2 php.java.bridge.http.ContextRunner.run(ContextRunner.java:145) #-1 php.java.bridge.ThreadPool$Delegate.run(ThreadPool.java:60) #0 C:\Users\Micha\.netbeans\7.1.2\apache-tomcat-7.0.22.0_base\webapps\JavaBridge\java\Java.inc(232): java_ThrowExceptionProxyFactory->getProxy(2, 'com.micha.Hello...', 'T', true) #1 C:\Users\Micha\.netbeans\7.1.2\apache-tomcat-7.0.22.0_base\webapps\JavaBridge\java\Java.inc(360): java_Arg->getResult(true) #2 C:\Users\Micha\.netbeans\7.1.2\apache-tomcat-7.0.22.0_base\webapps\JavaBridge\java\Java.inc(366): java_Client->getWrappedResult(true) #3 C:\Users\Micha\.netbean in C:\Users\Micha\.netbeans\7.1.2\apache-tomcat-7.0.22.0_base\webapps\JavaBridge\java\Java.inc on line 195 php.java.servlet.fastcgi.FastCGIServlet.handle(FastCGIServlet.java:499) php.java.servlet.fastcgi.FastCGIServlet.doGet(FastCGIServlet.java:521) javax.servlet.http.HttpServlet.service(HttpServlet.java:621) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) org.netbeans.modules.web.monitor.server.MonitorFilter.doFilter(MonitorFilter.java:393) php.java.servlet.PhpCGIFilter.doFilter(PhpCGIFilter.java:126) Before I had a ClassNotFoundException so it knows there is a a class but for some odd reason I cant call the function. ( if I replace "com.micha.Hello1Bean" with some class that doesnt exist then I get that exception)

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