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  • File Segmentation when trying to write in a file

    - by user1286390
    I am trying in C language to use the method of bisection to find the roots of some equation, however when I try to write every step of this process in a file I get the problem "Segmentation fault". This might be an idiot fault that I did, however I have been trying to solve this for a long time. I am compiling using gcc and that is the code: #include <stdio.h> #include <stdlib.h> #include <math.h> #define R 1.0 #define h 1.0 double function(double a); void attractor(double *a1, double *a2, double *epsilon); void attractor(double *a1, double *a2, double *epsilon) { FILE* bisection; double a2_copia, a3, fa1, fa2; bisection = fopen("bisection-part1.txt", "w"); fa1 = function(*a1); fa2 = function(*a2); if(function(*a1) - function(*a2) > 0.0) *epsilon = function(*a1) - function(*a2); else *epsilon = function(*a2) - function(*a1); fprintf(bisection, "a1 a2 fa1 fa2 epsilon\n"); a2_copia = 0.0; if(function(*a1) * function(*a2) < 0.0 && *epsilon >= 0.00001) { a3 = *a2 - (*a2 - *a1); a2_copia = *a2; *a2 = a3; if(function(*a1) - function(*a2) > 0.0) *epsilon = function(*a1) - function(*a2); else *epsilon = function(*a2) - function(*a1); if(function(*a1) * function(*a2) < 0.0 && *epsilon >= 0.00001) { fprintf(bisection, "%.4f %.4f %.4f %.4f %.4f\n", *a1, *a2, function(*a1), function(*a1), *epsilon); attractor(a1, a2, epsilon); } else { *a2 = a2_copia; *a1 = a3; if(function(*a1) - function(*a2) > 0) *epsilon = function(*a1) - function(*a2); else *epsilon = function(*a2) - function(*a1); if(function(*a1) * function(*a2) < 0.0 && *epsilon >= 0.00001) { fprintf(bisection, "%.4f %.4f %.4f %.4f %.4f\n", *a1, *a2, function(*a1), function(*a1), *epsilon); attractor(a1, a2, epsilon); } } } fa1 = function(*a1); fa2 = function(*a2); if(function(*a1) - function(*a2) > 0.0) *epsilon = function(*a1) - function(*a2); else *epsilon = function(*a2) - function(*a1); fprintf(bisection, "%.4f %.4f %.4f %.4f %.4f\n", a1, a2, fa1, fa2, epsilon); } double function(double a) { double fa; fa = (a * cosh(h / (2 * a))) - R; return fa; } int main() { double a1, a2, fa1, fa2, epsilon; a1 = 0.1; a2 = 0.5; fa1 = function(a1); fa2 = function(a2); if(fa1 - fa2 > 0.0) epsilon = fa1 - fa2; else epsilon = fa2 - fa1; if(epsilon >= 0.00001) { fa1 = function(a1); fa2 = function(a2); attractor(&a1, &a2, &epsilon); fa1 = function(a1); fa2 = function(a2); if(fa1 - fa2 > 0.0) epsilon = fa1 - fa2; else epsilon = fa2 - fa1; } if(epsilon < 0.0001) printf("Vanish at %f", a2); else printf("ERROR"); return 0; } Thanks anyway and sorry if this question is not suitable.

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  • Line by Line explanation of "Javascript: Good Parts" example?

    - by Matrym
    I'm reading "Javascript: The Good Parts" and am totally baffled by what's really going on here. A more detailed and/or simplified explanation would be greatly appreciated. // BAD EXAMPLE // Make a function that assigns event handler functions to an array of nodes the wrong way. // When you click on a node, an alert box is supposed to display the ordinal of the node. // But it always displays the number of nodes instead. var add_the_handlers = function (nodes) { var i; for (i = 0; i < nodes.length; i += 1) { nodes[i].onclick = function (e) { alert(i); } } }; // END BAD EXAMPLE The add_the_handlers function was intended to give each handler a unique number (i). It fails because the handler functions are bound to the variable i, not the value of the variable i at the time the function was made: // BETTER EXAMPLE // Make a function that assigns event handler functions to an array of nodes the right way. // When you click on a node, an alert box will display the ordinal of the node. var add_the_handlers = function (nodes) { var i; for (i = 0; i < nodes.length; i += 1) { nodes[i].onclick = function (i) { return function (e) { alert(i); }; }(i); } }; Now, instead of assigning a function to onclick, we define a function and immediately invoke it, passing in i. That function will return an event handler function that is bound to the value of i that was passed in, not to the i defined in add_the_handlers. That returned function is assigned to onclick.

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  • SQL SERVER – Puzzle to Win Print Book – Explain Value of PERCENTILE_CONT() Using Simple Example

    - by pinaldave
    From last several days I am working on various Denali Analytical functions and it is indeed really fun to refresh the concept which I studied in the school. Earlier I wrote article where I explained how we can use PERCENTILE_CONT() to find median over here SQL SERVER – Introduction to PERCENTILE_CONT() – Analytic Functions Introduced in SQL Server 2012. Today I am going to ask question based on the same blog post. Again just like last time the intention of this puzzle is as following: Learn new concept of SQL Server 2012 Learn new concept of SQL Server 2012 even if you are on earlier version of SQL Server. On another note, SQL Server 2012 RC0 has been announced and available to download SQL SERVER – 2012 RC0 Various Resources and Downloads. Now let’s have fun following query: USE AdventureWorks GO SELECT SalesOrderID, OrderQty, ProductID, PERCENTILE_CONT(0.5) WITHIN GROUP (ORDER BY ProductID) OVER (PARTITION BY SalesOrderID) AS MedianCont FROM Sales.SalesOrderDetail WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY SalesOrderID DESC GO The above query will give us the following result: The reason we get median is because we are passing value .05 to PERCENTILE_COUNT() function. Now run read the puzzle. Puzzle: Run following T-SQL code: USE AdventureWorks GO SELECT SalesOrderID, OrderQty, ProductID, PERCENTILE_CONT(0.9) WITHIN GROUP (ORDER BY ProductID) OVER (PARTITION BY SalesOrderID) AS MedianCont FROM Sales.SalesOrderDetail WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY SalesOrderID DESC GO Observe the result and you will notice that MidianCont has different value than before, the reason is PERCENTILE_CONT function has 0.9 value passed. For first four value the value is 775.1. Now run following T-SQL code: USE AdventureWorks GO SELECT SalesOrderID, OrderQty, ProductID, PERCENTILE_CONT(0.1) WITHIN GROUP (ORDER BY ProductID) OVER (PARTITION BY SalesOrderID) AS MedianCont FROM Sales.SalesOrderDetail WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY SalesOrderID DESC GO Observe the result and you will notice that MidianCont has different value than before, the reason is PERCENTILE_CONT function has 0.1 value passed. For first four value the value is 709.3. Now in my example I have explained how the median is found using this function. You have to explain using mathematics and explain (in easy words) why the value in last columns are 709.3 and 775.1 Hint: SQL SERVER – Introduction to PERCENTILE_CONT() – Analytic Functions Introduced in SQL Server 2012 Rules Leave a comment with your detailed answer by Nov 25's blog post. Open world-wide (where Amazon ships books) If you blog about puzzle’s solution and if you win, you win additional surprise gift as well. Prizes Print copy of my new book SQL Server Interview Questions Amazon|Flipkart If you already have this book, you can opt for any of my other books SQL Wait Stats [Amazon|Flipkart|Kindle] and SQL Programming [Amazon|Flipkart|Kindle]. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Function, SQL Puzzle, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • JSF Custom EL function works only on the first load of the page.

    - by jsfQ
    I created a ( JSP-based) custom EL function to use in the rendered tag. The function will return a boolean to decide if a page component needs to be rendered on a page or not. I import it onto the jsp page using <%@ taglib uri = "/WEB-INF/mine.tld" prefix = "g" %. Everything works perfect on the first load of the jsp page. Once a button is clicked, the form submits and then I am getting errors like 'No ClassLoaders found for: the class which implements my EL function' and 'Function not found'. What is going on here? What will be a fix?

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  • Can T-SQL function return user-defined table type?

    - by abatishchev
    I have my own type: CREATE TYPE MyType AS TABLE ( foo INT ) and a function receiving it as a parameter: CREATE FUNCTION Test ( @in MyType READONLY ) RETURNS @return MyType AS ... can it return MyType or only TABLE repeating MyType's structure: CREATE FUNCTION Test ( @in MyType READONLY ) RETURNS @return TABLE (foo INT) AS ... ?

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  • Passing a value from one function to another in jquery...

    - by Pandiya Chendur
    Consider these jquery statements... $(document).ready(function() { getRecordspage(0, itemsPerPage); $(".pager").pagination(maxNumberOfElementsHere, { //my def }); }); I get the value for maxNumberOfElementsHere from getRecordspage function... How to pass that value from getRecordspage function to the next one $(".pager").pagination(maxNumberOfElementsHere.... Any suggestion...

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  • Compatibility issues with <a> and calling a function(); across different web browsers

    - by Matthew
    Hi, I am new to javascript. I wrote the following function rollDice() to produce 5 random numbers and display them. I use an anchor with click event to call the function. Problem is, in Chrome it won't display, works fine in IE, in firefox the 5 values display and then the original page w/anchor appears! I am suspicious that my script tag is too general but I am really lost. Also if there is a display function that doesn't clear the screen first that would be great. diceArray = new Array(5) function rollDice() { var i; for(i=0; i<5; i++) { diceArray[i]=Math.round(Math.random() * 6) % 6 + 1; document.write(diceArray[i]); } } when I click should display 5 rand variables

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  • Whats the scope of a c function defined within objective-c class?

    - by roja
    I was reading up about bypassing objective-c's messaging to gain performance (irrelevant to this specific question) when i found an interesting bit of code: #import <Cocoa/Cocoa.h> @interface Fib : NSObject { } - (long long) cFib: (NSUInteger) number; @end @implementation Fib // c implementation of fib long long cFibIMP(NSUInteger number) { return (number < 3) ? 1 : cFib(number - 1) + cFib(number - 2); } // method wrapper for c implementation of fib - (long long) cFib: (NSUInteger) number { return cFibIMP(number); } @end My question is; when using c function, within an objective-c object, what scope is the c function (cFibIMP in this particular case) placed in? Does the objective-c class encapsulate the c function removing change of name-clash or is the c function simply dumped into the global scope of the whole objective-c program?

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  • Get a list/tuple/dict of the arguments passed to a function?

    - by digitala
    Given the following function: def foo(a, b, c): pass How would one obtain a list/tuple/dict/etc of the arguments passed in, without having to build the structure myself? Specifically, I'm looking for Python's version of JavaScript's arguments keyword or PHP's func_get_args() method. What I'm not looking for is a solution using *args or **kwargs; I need to specify the argument names in the function definition (to ensure they're being passed in) but within the function I want to work with them in a list- or dict-style structure.

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  • I need someone for explain this ASP function to me.

    - by Ronnie Chester Lynwood
    Hello! I've got an ASP document that 5 years old. Actually I'm working with PHP but I must use ASP for a Windows Application. So I need someone to explain this function to me. Thanks anyway. //DNS SETTINGS ARE INCLUDED ALREADY. function Check_Is_Web_Locked() dim cmdDB , Ret OpenDatabase Set cmdDB = Server.CreateObject("ADODB.Command") With cmdDB .ActiveConnection = DBCon .CommandText = "TICT_CHECK_WEB_STATUS" .CommandType = adCmdStoredProc .Parameters.Append .CreateParameter("RETURN_VALUE", adInteger, adParamReturnValue, 0) .Execute,,adExecuteNoRecords Ret = Trim(.Parameters("RETURN_VALUE")) End With Set cmdDB = Nothing CloseDatabase Check_Is_Web_Locked = Ret end function What does this functions do? Is "TICT_CHECK_WEB_STATUS" a StoredProcedure? If it's what are the coulumns that function looking for?

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  • PHP static function self:: in joomla JFactory class explanation?

    - by Carbon6
    Hi I'm looking at the code of Joomla and trying to figure out what exactly happends in this function. index.php makes a call to function $app = JFactory::getApplication('site'); jfactory.php code public static function getApplication($id = null, $config = array(), $prefix='J') { if (!self::$application) { jimport('joomla.application.application'); self::$application = JApplication::getInstance($id, $config, $prefix); } return self::$application; } application.php code.. public static function getInstance($client, $config = array(), $prefix = 'J') { static $instances; if (!isset($instances)) { $instances = array(); } ....... more code ........ return $instances[$client]; } Now I cannot figure out in function getApplication why is self:$application used. self::$application = JApplication::getInstance($id, $config, $prefix); $application is always null, what is the purpose of using this approach. I tryied modifying it to $var = JApplication::getInstance($id, $config, $prefix); and returnig it but it doesn't work. I would be very glad if someone with more knowledge could explain what is happening here detailed as possible. Many thanks.

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  • Assign C++ instance method to a global-function-pointer ?

    - by umanga
    Greetings, My project structure is as follows: \- base (C static library) callbacks.h callbacks.c paint_node.c . . * libBase.a \-app (C++ application) main.cpp In C library 'base' , I have declared global-function-pointer as: in singleheader file callbacks.h #ifndef CALLBACKS_H_ #define CALLBACKS_H_ extern void (*putPixelCallBack)(); extern void (*putImageCallBack)(); #endif /* CALLBACKS_H_ */ in single C file they are initialized as callbacks.c #include "callbacks.h" void (*putPixelCallBack)(); void (*putImageCallBack)(); Other C files access this callback-functions as: paint_node.c #include "callbacks.h" void paint_node(node *node,int index){ //Call callbackfunction . . putPixelCallBack(node->x,node->y,index); } I compile these C files and generate a static library 'libBase.a' Then in C++ application, I want to assign C++ instance method to this global function-pointer: I did something like follows : in Sacm.cpp file #include "Sacm.h" extern void (*putPixelCallBack)(); extern void (*putImageCallBack)(); void Sacm::doDetection() { putPixelCallBack=(void(*)())&paintPixel; //call somefunctions in 'libBase' C library } void Sacm::paintPixel(int x,int y,int index) { qpainter.begin(this); qpainter.drawPoint(x,y); qpainter.end(); } But when compiling it gives the error: sacmtest.cpp: In member function ‘void Sacm::doDetection()’: sacmtest.cpp:113: error: ISO C++ forbids taking the address of an unqualified or parenthesized non-static member function to form a pointer to member function. Say ‘&Sacm::paintPixel’ sacmtest.cpp:113: error: converting from ‘void (Sacm::)(int, int, int)’ to ‘void ()()’ Any tips?

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  • How to inline a function for only release build.

    - by Benjamin
    // common.h // This is foo funtion. It has a body. __inline void foo() { /* something */ } // a.cpp #include "common.h" // for foo function // Call foo // b.cpp #include "common.h" // for foo function // Call foo I would like to inline the foo function only when I build for release. -I dont want to inline functions for Debug build. I tried it but linker errors annoyed me. In this case, foo function's body is defined in common.h header file. so if I just do //common.h #if !defined(_DEBUG) __inline #endif void foo() { /* something */ } I will be met a link error in DEBUG build. Because two modules try to include common.h. I have no idea to solve it. Is it possible?

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  • How to use two parameters pointing to the same structure in one function ?

    - by ZaZu
    Hey guys, I have my code below that consits of a structure, a main, and a function. The function is supposed to display two parameters that have certain values, both of which point to the same structure. The problem I dont know how to add the SECOND parameter onto the following code : #include<stdio.h> #define first 500 #define sec 500 struct trial{ int f; int r; float what[first][sec]; }; int trialtest(trial *test); main(){ trial test; trialtest(&test); } int trialtest(trial *test){ int z,x,i; for(i=0;i<5;i++){ printf("%f,(*test).what[z][x]); } return 0; } I need to add a new parameter test_2 there (IN THE SAME FUNCTION) using this code : for(i=0;i<5;i++){ printf("%f,(*test_2).what[z][x]); How does int trialtest(trial *test) changes ? and how does it change in main ? I know that I should declare test_2 as well, like this : trial test,test_2; But what about passing the address in the function ? I do not need to edit it right ? trialtest(&test); --- This will remain the same ? So please, tell me how would I use test_2 as a parameter pointing to the same structure as test, both in the same function.. Thank you !! Please tell me if you need more clarification

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  • Why is this std::bind not converted to std::function?

    - by dauphic
    Why is the nested std::bind in the below code not implicitly converted to an std::function<void()> by any of the major compilers (VS2010/2012, gcc, clang)? Is this standard behavior, or a bug? #include <functional> void bar(int, std::function<void()>) { } void foo() { } int main() { std::function<void(int, std::function<void()>)> func; func = std::bind(bar, 5, std::bind(foo)); std::cin.get(); return 0; }

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  • Any way in C++ to forward declare a function prototype?

    - by jsyjr
    I make regular use of forward class declarations and pointers to such classes. I now have a need to pass a function pointer through a number of layers. I would prefer to include the header that declares my function pointer's prototype only into the module that dereferences a function pointer rather than into each layer that simply passes along that pointer value. Is this possible?

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  • C - What is the proper format to allow a function to show an error was encountered?

    - by BrainSteel
    I have a question about what a function should do if the arguments to said function don't line up quite right, through no fault of the function call. Since that sentence doesn't make much sense, I'll offer my current issue. To keep it simple, here is the most relevant and basic function I have. float getYValueAt(float x, PHYS_Line line, unsigned short* error) *error = 0; if(x < line.start.x || x > line.end.x){ *error = 1; return -1; } if(line.slope.value != 0){ //line's equation: y - line.start.y = line.slope.value(x - line.start.x) return line.slope.value * (x - line.start.x) + line.start.y; } else if(line.slope.denom == 0){ if(line.start.x == x) return line.start.y; else{ *error = 1; return -1; } } else if(line.slope.num == 0){ return line.start.y; } } The function attempts to find the point on a line, given a certain x value. However, under some circumstances, this may not be possible. For example, on the line x = 3, if 5 is passed as a value, we would have a problem. Another problem arises if the chosen x value is not within the interval the line is on. For this, I included the error pointer. Given this format, a function call could work as follows: void foo(PHYS_Line some_line){ unsigned short error = 0; float y = getYValueAt(5, some_line, &error); if(error) fooey(); else do_something_with_y(y); } My question pertains to the error. Note that the value returned is allowed to be negative. Returning -1 does not ensure that an error has occurred. I know that it is sometimes preferred to use the following method to track an error: float* getYValueAt(float x, PHYS_Line line); and then return NULL if an error occurs, but I believe this requires dynamic memory allocation, which seems even less sightly than the solution I was using. So, what is standard practice for an error occurring?

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  • [PHP] How to pass array as multiple parameters to function?

    - by vbklv
    I have a parameters array: $params[1] = 'param1'; $params[2] = 'param2'; $params[3] = 'param3'; ... $params[N] = 'paramN'; I have a caller to various functions: $method->$function( $params ); How can I parse the $params array, so multiple (and unlimited) parameters can be passed to any function: $method->$function( $param[1], $param[2], ..., $param[N] );

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  • How to create a function and pass in variable length argument list?

    - by Jian Lin
    We can create a function p in the following code: var p = function() { }; if (typeof(console) != 'undefined' && console.log) { p = function() { console.log(arguments); }; } but the arguments are passed like an array to console.log, instead of passed one by one as in console.log(arguments[0], arguments[1], arguments[2], ... Is there a way to expand the arguments and pass to console.log like the way above? Note that if the original code were var p = function() { }; if (typeof(console) != 'undefined' && console.log) { p = console.log; } then it works well on Firefox and IE 8 but not on Chrome.

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  • jquery - How to reference two div elements for a single function?

    - by Ben
    I Have a function that references a specific input text box. I would like to extend the function to be used by two specific input text boxes. Rather than duplicate the code for the other text box, can anyone advise on how to reference the other? Here it uses #Tags, but if i wanted it to reference #Tags2 also, how could I do that? $(function () { $('#Tags').tagSuggest({ separator: ", ", tagContainer: 'div', tags: ["tag1","tag2"] }); });

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  • how to .call() on the unnamed function in javascript?

    - by Anonymous
    Let's suppose I have button #click, And suppose I bind the on click event as follows: $('#click').click(function(){ alert('own you'+'whatever'+$(this).attr('href')); }); But I want this to refer to some other element, let's say #ahref. If it was a named function I would simply refer it by name: foo.call('#ahref'); How could I use .call() though, if the function is called inline and does not have a name?

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  • Haskell: How to compose `not` with a function of arbitrary arity?

    - by Hynek -Pichi- Vychodil
    When I have some function of type like f :: (Ord a) => a -> a -> Bool f a b = a > b I should like make function which wrap this function with not. e.g. make function like this g :: (Ord a) => a -> a -> Bool g a b = not $ f a b I can make combinator like n f = (\a -> \b -> not $ f a b) But I don't know how. *Main> let n f = (\a -> \b -> not $ f a b) n :: (t -> t1 -> Bool) -> t -> t1 -> Bool Main> :t n f n f :: (Ord t) => t -> t -> Bool *Main> let g = n f g :: () -> () -> Bool What am I doing wrong? And bonus question how I can do this for function with more and lest parameters e.g. t -> Bool t -> t1 -> Bool t -> t1 -> t2 -> Bool t -> t1 -> t2 -> t3 -> Bool

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  • How to declare a pointer to a variable as a parameter of a function in C++?

    - by Keand64
    I have a function that takes a pointer to a D3DXVECTOR3, but I have no reason to declare this beforehand. The most logical solution to me was using new: Function( //other parameters, new D3DXVECTOR3(x, y, 0)); but I don't know how I would go about deleting it, beign intitialized in a function. My next thought was to use the & operator, like so: Function( //other parameters, &D3DVECTOR3(x, y, 0)); but I don't know if this is a valid way to go about doing this. (It doesn't get an error, but neither does int *x; x = 50;). So should I use new, &, or some other technique I'm overlooking?

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  • How to make a function retun after 5 second passes in python?

    - by alwbtc
    I want to write a function which will return after 5 seconds no matter what: def myfunction(): while passed_time < 5_seconds: do1() do2() do3() . . return I mean, this function run for 5 seconds only, after 5 seconds, it should end, and continue with other function: myfunction() otherfunction() ----> This should start 5 seconds after myfunction() is executed. Best Regards

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  • Get a list/tuple/dict of *all* the arguments passed to a function?

    - by Phillip Oldham
    Given the following function: def foo(a, b, c): pass How would one obtain a list/tuple/dict/etc of the arguments passed in? Specifically, I'm looking for Python's version of JavaScript's arguments keyword or PHP's func_get_args() method. What I'm not looking for is a solution using *args or **kwargs; I need to specify the argument names in the function definition (to ensure they're being passed in) but within the function I want to work with them in a list- or dict-style structure.

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