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  • Finding N contiguous zero bits in an integer to the left of the MSB position of another integer

    - by James Morris
    The problem is: given an integer val1 find the position of the highest bit set (Most Significant Bit) then, given a second integer val2 find a contiguous region of unset bits, with the minimum number of zero bits given by width to the left of the position (ie, in the higher bits). Here is the C code for my solution: typedef unsigned int t; unsigned const t_bits = sizeof(t) * CHAR_BIT; _Bool test_fit_within_left_of_msb( unsigned width, t val1, t val2, unsigned* offset_result) { unsigned offbit = 0; unsigned msb = 0; t mask; t b; while(val1 >>= 1) ++msb; while(offbit + width < t_bits - msb) { mask = (((t)1 << width) - 1) << (t_bits - width - offbit); b = val2 & mask; if (!b) { *offset_result = offbit; return true; } if (offbit++) /* this conditional bothers me! */ b <<= offbit - 1; while(b <<= 1) offbit++; } return false; } Aside from faster ways of finding the MSB of the first integer, the commented test for a zero offbit seems a bit extraneous, but necessary to skip the highest bit of type t if it is set. I have also implemented similar algorithms but working to the right of the MSB of the first number, so they don't require this seemingly extra condition. How can I get rid of this extra condition, or even, are there far more optimal solutions? Edit: Some background not strictly required. The offset result is a count of bits from the high bit, not from the low bit as maybe expected. This will be part of a wider algorithm which scans a 2D array for a 2D area of zero bits. Here, for testing, the algorithm has been simplified. val1 represents the first integer which does not have all bits set found in a row of the 2D array. From this the 2D version would scan down which is what val2 represents. Here's some output showing success and failure: t_bits:32 t_high: 10000000000000000000000000000000 ( 2147483648 ) --------- ----------------------------------- *** fit within left of msb test *** ----------------------------------- val1: 00000000000000000000000010000000 ( 128 ) val2: 01000001000100000000100100001001 ( 1091569929 ) msb: 7 offbit:0 + width: 8 = 8 mask: 11111111000000000000000000000000 ( 4278190080 ) b: 01000001000000000000000000000000 ( 1090519040 ) offbit:8 + width: 8 = 16 mask: 00000000111111110000000000000000 ( 16711680 ) b: 00000000000100000000000000000000 ( 1048576 ) offbit:12 + width: 8 = 20 mask: 00000000000011111111000000000000 ( 1044480 ) b: 00000000000000000000000000000000 ( 0 ) offbit:12 iters:10 ***** found room for width:8 at offset: 12 ***** ----------------------------------- *** fit within left of msb test *** ----------------------------------- val1: 00000000000000000000000001000000 ( 64 ) val2: 00010000000000001000010001000001 ( 268469313 ) msb: 6 offbit:0 + width: 13 = 13 mask: 11111111111110000000000000000000 ( 4294443008 ) b: 00010000000000000000000000000000 ( 268435456 ) offbit:4 + width: 13 = 17 mask: 00001111111111111000000000000000 ( 268402688 ) b: 00000000000000001000000000000000 ( 32768 ) ***** mask: 00001111111111111000000000000000 ( 268402688 ) offbit:17 iters:15 ***** no room found for width:13 ***** (iters is the count of iterations of the inner while loop)

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  • How to perform simple collision detection?

    - by Rob
    Imagine two squares sitting side by side, both level with the ground like so: A simple way to detect if one is hitting the other is to compare the location of each side. They are touching if all of the following are false: The right square's left side is to the right of the left square's right side. The right square's right side is to the left of the left square's left side. The right square's bottom side is above the left square's top side. The right square's top side is below the left square's bottom side. If any of those are true, the squares are not touching. But consider a case like this, where one square is at a 45 degree angle: Is there an equally simple way to determine if those squares are touching?

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  • Too Many Left Outer Joins in Entity Framework 4?

    - by Adam
    I have a product entity, which has 0 or 1 "BestSeller" entities. For some reason when I say: db.Products.OrderBy(p = p.BestSeller.rating).ToList(); the SQL I get has an "extra" outer join (below). And if I add on a second 0 or 1 relation ship, and order by both, then I get 4 outer joins. It seems like each such entity is producing 2 outer joins rather than one. LINQ to SQL behaves exactly as you'd expect, with no extra join. Has anyone else experienced this, or know how to fix it? SELECT [Extent1].[id] AS [id], [Extent1].[ProductName] AS [ProductName] FROM [dbo].[Products] AS [Extent1] LEFT OUTER JOIN [dbo].[BestSeller] AS [Extent2] ON [Extent1].[id] = [Extent2].[id] LEFT OUTER JOIN [dbo].[BestSeller] AS [Extent3] ON [Extent2].[id] = [Extent3].[id] ORDER BY [Extent3].[rating] ASC

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  • how to add column in SQL Query that incl. LEFT OUTER JOIN

    - by radbyx
    I have this Query: SELECT p.ProductName, dt.MaxTimeStamp, p.Responsible FROM Product p LEFT JOIN (SELECT ProductID, MAX(TimeStamp) AS MaxTimeStamp FROM StateLog WHERE State = 0 GROUP BY ProductID, Status) dt ON p.ProductID = dt.ProductID ORDER BY p.ProductName; It works like it should, but now I need to SELECT "State" out too. The tricky part is, that I only want the lastest "TimeStamp" where "State" was false. But now I also need the "State" for the lastest "TimeStamp". I tried this: SELECT p.ProductName, dt.State, dt.MaxTimeStamp, p.Responsible FROM Product p LEFT JOIN (SELECT ProductID, MAX(TimeStamp) AS MaxTimeStamp, State FROM StateLog WHERE State = 0 GROUP BY ProductID, Status) dt ON p.ProductID =dt.ProductID ORDER BY p.ProductName; But it didn't work, because it gave me the "State" for the lastest "TimeStamp". So I hope there is some clever heads out there that can help me. I'm guessing that this is either very simple or very hard to solve.

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  • How to make margin be relative to the center of the UIElement and not its top-left corner in a Grid?

    - by Nockawa
    I'd like the Margin property to reference the center of the UIElement and not the top-left corner. That way when I change the width/height of the UIElement it stays in the same spot. Is there a way to configure this behavior or I'll have to rely on Binding to make the adjustment ? Thanks. For instance if I change the Width/Height of the following rectangle, its center will move. <Grid> <Rectangle Fill="#FF991C1C" Width="10" Height="40" HorizontalAlignment="Left" Margin="90,161,0,0" VerticalAlignment="Top"/> </Grid>

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  • how do I align contents of a centered div to the left?

    - by Paul
    I have centered a div inside another div but want to left justify the contents of the centered inner div. How can I do this? My current HTML looks like this: <div style="border: solid 1px #ff0000;text-align:center;"> <div style="border:solid 1px #00ff00;"> <img src="/some_url_1/" style="width: 80px; height 80px; border: 0"/> <img src="/some_url_2/" style="width: 80px; height 80px; border: 0"/> </div> </div> Currently the images are centered inside the inner div but I would like them aligned to the left inside of the centered inner div. Any idea what I'm missing?

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  • How can I do a left outer join where both tables have a where clause?

    - by cdeszaq
    Here's the scenario: I have 2 tables: CREATE TABLE dbo.API_User ( id int NOT NULL, name nvarchar(255) NOT NULL, authorization_key varchar(255) NOT NULL, is_active bit NOT NULL ) ON [PRIMARY] CREATE TABLE dbo.Single_Sign_On_User ( id int NOT NULL IDENTITY (1, 1), API_User_id int NOT NULL, external_id varchar(255) NOT NULL, user_id int NULL ) ON [PRIMARY] What I am trying to return is the following: is_active for a given authorization_key The Single_Sign_On_User.id that matches the external_id/API_User_id pair if it exists or NULL if there is no such pair When I try this query: SELECT Single_Sign_On_User.id, API_User.is_active FROM API_User LEFT OUTER JOIN Single_Sign_On_User ON Single_Sign_On_User.API_User_id = API_User.id WHERE Single_Sign_On_User.external_id = 'test_ext_id' AND API_User.authorization_key = 'test' where the "test" API_User record exists but the "test_ext_id" record does not, and with no other values in either table, I get no records returned. When I use: SELECT Single_Sign_On_User.id, API_User.is_active FROM API_User LEFT OUTER JOIN Single_Sign_On_User ON Single_Sign_On_User.API_User_id = API_User.id WHERE API_User.authorization_key = 'test' I get the results I expect (NULL, 1), but that query doesn't allow me to find the "test_ext_id" record if it exists but would give me all records associated with the "test" API_User record. How can I get the results I am after?

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  • How to get top/left x/y of image map with javascript / jquery?

    - by jpea
    Using jQuery's position() or offset(), I can't seeme to get the top/left coordinates of an image map area. It works in FF, but nothing else - no webkit, IE, Opera. $('area').bind("click",function(){ alert($(this).position().left); }); <area shape="rect" coords="14,25,205,150" href="#"> Anyone know of a different way to access these? Normally I would just take the coords and split(",") but there are a bunch of multi-faceted area's on these pages.

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  • Laptop monitor stopped working and can't be re-enabled on a Dell Latitude E6410

    - by xektrum
    I'm using Ubuntu 12.04 (upgraded from 11.10), everything seemed to work fine until today when my laptop monitor suddenly stopped working. Here are the facts: My laptop is a Dell Latitude E6410, Intel graphics. External Monitor is attached through a docking station. Everything worked fine for about 6-7 month, then upgraded to 12.04 Issue started today after a week of upgrade. I think the issue started after I ran CounterStrike 1.6, both monitors blinked and then only the attached monitor which is connected to a docking station continued to work I thought at first that was a transient issue but then I've rebooted, removed the battery but the same happens. Laptop Monitor and external monitor work fine up to login screen, but after I login it goes black Whenever I try to re-enable laptop monitor from Display Manager I get errors: The selected configuration for displays could not be applied could not set the configuration for CRTC 63 Not sure what technical details are required but here are some: $ xrandr Screen 0: minimum 320 x 200, current 3120 x 1050, maximum 8192 x 8192 eDP1 connected (normal left inverted right x axis y axis) 1440x900 60.0 + 40.0 VGA1 disconnected (normal left inverted right x axis y axis) HDMI1 connected 1680x1050+0+0 (normal left inverted right x axis y axis) 474mm x 296mm 1680x1050 60.0*+ 1280x1024 75.0 60.0 1152x864 75.0 1024x768 75.1 60.0 800x600 75.0 60.3 640x480 75.0 60.0 720x400 70.1 DP1 disconnected (normal left inverted right x axis y axis) HDMI2 disconnected (normal left inverted right x axis y axis) DP2 disconnected (normal left inverted right x axis y axis) $ tail /var/log/Xorg.0.log [ 8367.132] (WW) intel(0): flip queue failed: Device or resource busy [ 8367.132] (WW) intel(0): Page flip failed: Device or resource busy [ 8367.174] (WW) intel(0): flip queue failed: Device or resource busy [ 8367.174] (WW) intel(0): Page flip failed: Device or resource busy [ 8367.174] (WW) intel(0): flip queue failed: Device or resource busy [ 8367.174] (WW) intel(0): Page flip failed: Device or resource busy [ 8367.265] (WW) intel(0): flip queue failed: Device or resource busy [ 8367.265] (WW) intel(0): Page flip failed: Device or resource busy [ 8367.265] (WW) intel(0): flip queue failed: Device or resource busy [ 8367.265] (WW) intel(0): Page flip failed: Device or resource busy I'm using gnome-shell, and the only ways I've been able to get both display working have been: 1) Booting with laptop disconnected from docking and then re attach external with VGA instead of DVI, but only worked for a session. 2) Removing xserver-xorg-video-intel, but then I gnome-shell is gone as well as dri I would appreciate any suggestions. Regards, ============================= WORKAROUND FOUND ============================= So I have tried few things and here is what worked: I've installed a newer version of xserver-xorg-video-intel (2.19 vs 2.17) from ppa:xorg-edgers/ppa, it didn't work at first, it was only showing low graphics mode, so I tried with a different linux-image 3.0.0-19-generic-pae instead of 3.2.0-24-generic-pae, which I believe is 12.04 precise default, then everything started to work again, Now I've installed 3.4.0-1-generic-pae from same ppa and everything goes flawless so I believe the issue is either with linux-image 3.0.0-19-generic-pae or xserver-xorg-video-intel 2.17. Hope this helps someone in the future. PS: Now xrandr shows multiple modes for my laptop monitor $ xrandr Screen 0: minimum 320 x 200, current 3120 x 1050, maximum 8192 x 8192 eDP1 connected 1440x900+1680+0 (normal left inverted right x axis y axis) 303mm x 189mm 1440x900 60.0*+ 59.9 40.0 1360x768 59.8 60.0 1152x864 60.0 1024x768 60.0 800x600 60.3 56.2 640x480 59.9 VGA1 disconnected (normal left inverted right x axis y axis) HDMI1 connected 1680x1050+0+0 (normal left inverted right x axis y axis) 474mm x 296mm 1680x1050 60.0*+ 1280x1024 75.0 60.0 1152x864 75.0 1024x768 75.1 60.0 800x600 75.0 60.3 640x480 75.0 60.0 720x400 70.1 DP1 disconnected (normal left inverted right x axis y axis) HDMI2 disconnected (normal left inverted right x axis y axis) DP2 disconnected (normal left inverted right x axis y axis)

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  • Smarty Tag help [closed]

    - by ntechi
    I am using an engine, where for forums Vbulletin is used and for Other thiiings social engine 3 is used, This was done by some professionals In one of the page I am having popular tags(In Social Engine) Its too long I want shortened it, How can I do it? here is my code {* SHOW POPULAR TAGS START *} <tr> <td align="left" valign="top"><img src="images/spacer.gif" alt="" width="1" height="10" /></td> </tr> <tr> <td align="left" valign="top"><table width="220" border="0" align="left" cellpadding="0" cellspacing="0"> <tr> <td width="12" align="left" valign="top"><img src="images/blog_belowtl.jpg" alt="" width="12" height="10" /></td> <td width="196" align="left" valign="top" background="images/blog_belowtbg.jpg"><img src="images/spacer.gif" width="1" height="10" /></td> <td width="12" align="right" valign="top"><img src="images/blog_belowtr.jpg" alt="" width="12" height="10" /></td> </tr> <tr> <td align="left" valign="top" background="images/blog_belowlbg.jpg" style="background-repeat: repeat-y;">&nbsp;</td> <td align="left" valign="top"><table width="196" border="0" align="left" cellpadding="0" cellspacing="0"> <tr> <td align="left" valign="top" > {*<div class="articletags" > {foreach from=$popular_tags item=poptag} <a class="tag{$poptag.class}" href="articles.php?tag={$poptag.name}">{$poptag.name}</a> {/foreach} </div>*} {foreach from=$popular_tags item=poptag} {if $poptag.count == '1' } {assign var=cssClass value='tahoma15_cloud'} {elseif $poptag.count == '2' } {assign var=cssClass value='tahoma12bold_cloud'} {elseif $poptag.count == '3'} {assign var=cssClass value='tahoma13bold_cloud'} {elseif $poptag.count == '4'} {assign var=cssClass value='tahoma14bold_cloud'} {elseif $poptag.count == '5'} {assign var=cssClass value='tahoma15_cloud'} {else} {assign var=cssClass value='tahoma18bold_cloud'} {/if} <span class="{$cssClass}"><a href="articles.php?tag={$poptag.name}" class="{$cssClass}">{$poptag.name}</a></span> {/foreach} </td> </tr> </table></td> <td align="left" valign="top" background="images/blog_belowrbg.jpg" style="background-repeat: repeat-y;">&nbsp;</td> </tr> <tr> <td align="left" valign="top"><img src="images/blog_belowbl.jpg" alt="" width="12" height="10" /></td> <td align="left" valign="top" background="images/blog_belowbbg.jpg"><img src="images/spacer.gif" alt="" width="1" height="10" /></td> <td align="right" valign="top"><img src="images/blog_belowbr.jpg" alt="" width="12" height="10" /></td> </tr> </table></td> </tr> {* SHOW POPULAR TAGS END *} You can check the lenght of this tag, on this link http://www.managementparadise.com/articles.php Currently it is displaying very long on the widget area I am new on this, so any help will be appreciated :)

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  • Why does an error appear every time I try to open the Ubuntu Software Center? [duplicate]

    - by askubuntu7639
    This question already has an answer here: How do I remove a broken software source? 3 answers There is a glitch on the Ubuntu Software Center and whenever I open it an error appears and it keeps loading and never opens. Why does this happen? I have installed Ubuntu 13.04 on a disk and partitioned it. Please help me and ask for excess information if you need it. If you know of any duplicates please show me them!! This is the output of a question someone asked me. SystemError: E:Type '<!DOCTYPE' is not known on line 1 in source list /etc/apt/sources.list.d/medibuntu.list This next output is the output of cat /etc/apt/sources.list.d/medibuntu.list </div> <div style="float:left;"> <div class="textwidget"><script type="text/javascript"><!-- google_ad_client = "ca-pub-2917661377128354"; /* 160X600 Sidebar UX */ google_ad_slot = "9908287444"; google_ad_width = 160; google_ad_height = 600; //-- Recent Comments <article> <div style="float:left; display:block; margin:0 10px 10px 0; border:1px solid #CCCCCC; padding:3px; width:35px; height:35px;"><img alt='' src='http://0.gravatar.com/avatar/ae5f4503d5f167f1cf62d3e36e8242b6?s=35&amp;d=&amp;r=G' class='avatar avatar-35 photo' height='35' width='35' /></div> <div style="float:left;"> <h4 class="author">Richard Syme</h4> <p class="meta"> <time datetime="2013-09-24" pubdate>September 24, 2013</time> | <a class="permalink" href="http://www.unixmen.com/how-to-customize-you-vlc-hot-keys/#comment-13732">#</a> </p> </div> <div class="content" style="float:left;"><p>I dont have a clear button under the hotkeys. All i want to do is get rid of all hotkeys.</p> </article> <article> <div style="float:left; display:block; margin:0 10px 10px 0; border:1px solid #CCCCCC; padding:3px; width:35px; height:35px;"><img alt='' src='http://1.gravatar.com/avatar/ffabde94437e996a506e31e981bcf8fc?s=35&amp;d=&amp;r=G' class='avatar avatar-35 photo' height='35' width='35' /></div> <div style="float:left;"> <h4 class="author">Abin Thomas Mathew</h4> <p class="meta"> <time datetime="2013-09-24" pubdate>September 24, 2013</time> | <a class="permalink" href="http://www.unixmen.com/install-lamp-server-in-centos-6-4-rhel-6-4/#comment-13727">#</a> </p> </div> <div class="content" style="float:left;"><p>Simple and easy to follow tutorial to install and start of phpMyAdmin. Thank you</p> </article> <article> <div style="float:left; display:block; margin:0 10px 10px 0; border:1px solid #CCCCCC; padding:3px; width:35px; height:35px;"><img alt='' src='http://0.gravatar.com/avatar/499ccc1154e9b8569b87413434220b91?s=35&amp;d=&amp;r=G' class='avatar avatar-35 photo' height='35' width='35' /></div> <div style="float:left;"> <h4 class="author">SK</h4> <p class="meta"> <time datetime="2013-09-24" pubdate>September 24, 2013</time> | <a class="permalink" href="http://www.unixmen.com/munich-giving-ubuntu-linux-cds-citizens/#comment-13725">#</a> </p> </div> <div class="content" style="float:left;"><p>I have Bosslinux and i used it for a while. Now i swiched to Ubuntu 13.04.</p> </article> <article> <div style="float:left; display:block; margin:0 10px 10px 0; border:1px solid #CCCCCC; padding:3px; width:35px; height:35px;"><img alt='' src='http://1.gravatar.com/avatar/3dc2f7140bdd857dcdfe815a6e29aa6b?s=35&amp;d=&amp;r=G' class='avatar avatar-35 photo' height='35' width='35' /></div> <div style="float:left;"> <h4 class="author">Anon</h4> <p class="meta"> <time datetime="2013-09-24" pubdate>September 24, 2013</time> | <a class="permalink" href="http://www.unixmen.com/linus-torvalds-talks-backdoor-linuxcon/#comment-13724">#</a> </p> </div> <div class="content" style="float:left;"><p>Do you know how much extra bloat is in Ubuntu these days? How the hell does anyone really know?</p> </article> <article> <div style="float:left; display:block; margin:0 10px 10px 0; border:1px solid #CCCCCC; padding:3px; width:35px; height:35px;"><img alt='' src='http://1.gravatar.com/avatar/9dd28d1cf5efe754fa58b53c1e6de401?s=35&amp;d=&amp;r=G' class='avatar avatar-35 photo' height='35' width='35' /></div> <div style="float:left;"> <h4 class="author"><a href="http://ambitiousgeeks.blogspot.com/" onclick="javascript:_gaq.push(['_trackEvent','outbound-commentauthor','http://ambitiousgeeks.blogspot.com']);" rel='external nofollow' class='url'>Ambition</a></h4> <p class="meta"> <time datetime="2013-09-24" pubdate>September 24, 2013</time> | <a class="permalink" href="http://www.unixmen.com/linus-torvalds-talks-backdoor-linuxcon/#comment-13723">#</a> </p> </div> <div class="content" style="float:left;"><p>True :)</p> </article> </div> <div style="float:left;"> &nbsp;<script type="text/javascript"> window.___gcfg = {lang: 'en-US'}; (function() {var po = document.createElement("script"); po.type = "text/javascript"; po.async = true;po.src = "https://apis.google.com/js/plusone.js"; var s = document.getElementsByTagName("script")[0]; s.parentNode.insertBefore(po, s); })(); <div class="execphpwidget"></div> </div> <div class="module2"> <div class="recentPost"> <h3 class="module-title2">Favorite Links</h3> <ul class='xoxo blogroll'> http://www.iticy.com']);"Cheap Hosting http://www.tuxmachines.org']);"TuxMachines.org http://www.ubuntugeek.com']);"UbuntuGeek.com http://www.stelinuxhost.com']);"Webdesign & SEO </ul> <img src="http://180016988.r.cdn77.net/wp-content/themes/unimax/images/bigLine.jpg" alt="" /> </div> </div> <div align="center" style="min-height:610px;"> <div class="execphpwidget"></div> <div class="textwidget"><a rel="license" href="http://creativecommons.org/licenses/by-nc-nd/3.0/deed.en_US" onclick="javascript:_gaq.push(['_trackEvent','outbound-widget','http://creativecommons.org']);"><img alt="Creative Commons License" style="border-width:0" src="http://i.creativecommons.org/l/by-nc-nd/3.0/88x31.png" /></a><br />This work by <a xmlns:cc="http://creativecommons.org/ns#" href="unixmen.com" property="cc:attributionName" rel="cc:attributionURL">unixmen.com</a> is licensed under a <a rel="license" href="http://creativecommons.org/licenses/by-nc-nd/3.0/deed.en_US" >Creative Commons Attribution-NonCommercial-NoDerivs 3.0 Unported License</a>.</div> </div> </div> <!-- #primary .widget-area --> </div> Unixmen Archive Select Month September 2013 August 2013 July 2013 June 2013 May 2013 April 2013 March 2013 February 2013 January 2013 December 2012 November 2012 October 2012 September 2012 August 2012 July 2012 June 2012 May 2012 April 2012 March 2012 February 2012 January 2012 December 2011 November 2011 October 2011 September 2011 August 2011 July 2011 June 2011 May 2011 April 2011 March 2011 February 2011 January 2011 December 2010 November 2010 October 2010 September 2010 August 2010 July 2010 June 2010 May 2010 April 2010 March 2010 February 2010 January 2010 December 2009 November 2009 October 2009 September 2009 August 2009 July 2009 June 2009 May 2009 April 2009 March 2009 February 2009 January 2009 December 2008 Tags Cloudandroid apache browser Centos chrome command line Debian eyecandy Fedora firefox games gaming gnome google karmic koala kde libreoffice Linux linux distribution LinuxMint lucid lynx maverick meerkat mysql news oneiric ocelot openoffice opensource opensuse oracle ppa Precise Pangolin release RHEL security server software themes tools ubuntu unix upgrade virtualbox vlc windows wine Unixmen Twitts Firefox 16, a treat for developers http://t.co/cnd27CzT Ubuntu 12.10 ‘Quantal Quetzal’: Beta 2 Sneak Peek http://t.co/hd4LwDOy Top 5 security Myths about Linux; and their realities http://t.co/zO1LgHST About Us Advertising Sitemap Privacy Contact Us Hire Us Copyright © 2008-2013 Unixmen.com . Maintained by Unixmen . /* */ jQuery(document).on('ready post-load', easy_fancybox_handler ); http://www.w3-edge.com/wordpress-plugins/ Page Caching using apc Database Caching 3/186 queries in 0.035 seconds using apc Content Delivery Network via 180016988.r.cdn77.net Served from: www.unixmen.com @ 2013-09-25 01:38:14 by W3 Total Cache

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  • Windows Phone 7 : Dragging and flicking UI controls

    - by TechTwaddle
    Who would want to flick and drag UI controls!? There might not be many use cases but I think some concepts here are worthy of a post. So we will create a simple silverlight application for windows phone 7, containing a canvas element on which we’ll place a button control and an image and then, as the title says, drag and flick the controls. Here’s Mainpage.xaml, <Grid x:Name="LayoutRoot" Background="Transparent">   <Grid.RowDefinitions>     <RowDefinition Height="Auto"/>     <RowDefinition Height="*"/>   </Grid.RowDefinitions>     <!--TitlePanel contains the name of the application and page title-->   <StackPanel x:Name="TitlePanel" Grid.Row="0" Margin="12,17,0,28">     <TextBlock x:Name="ApplicationTitle" Text="KINETICS" Style="{StaticResource PhoneTextNormalStyle}"/>     <TextBlock x:Name="PageTitle" Text="drag and flick" Margin="9,-7,0,0" Style="{StaticResource PhoneTextTitle1Style}"/>   </StackPanel>     <!--ContentPanel - place additional content here-->   <Grid x:Name="ContentPanel" Grid.Row="1" >     <Canvas x:Name="MainCanvas" HorizontalAlignment="Stretch" VerticalAlignment="Stretch">       <Canvas.Background>         <LinearGradientBrush StartPoint="0 0" EndPoint="0 1">           <GradientStop Offset="0" Color="Black"/>           <GradientStop Offset="1.5" Color="BlanchedAlmond"/>         </LinearGradientBrush>       </Canvas.Background>     </Canvas>   </Grid> </Grid> the second row in the main grid contains a canvas element, MainCanvas, with its horizontal and vertical alignment set to stretch so that it occupies the entire grid. The canvas background is a linear gradient brush starting with Black and ending with BlanchedAlmond. We’ll add the button and image control to this canvas at run time. Moving to Mainpage.xaml.cs the Mainpage class contains the following members, public partial class MainPage : PhoneApplicationPage {     Button FlickButton;     Image FlickImage;       FrameworkElement ElemToMove = null;     double ElemVelX, ElemVelY;       const double SPEED_FACTOR = 60;       DispatcherTimer timer; FlickButton and FlickImage are the controls that we’ll add to the canvas. ElemToMove, ElemVelX and ElemVelY will be used by the timer callback to move the ui control. SPEED_FACTOR is used to scale the velocities of ui controls. Here’s the Mainpage constructor, // Constructor public MainPage() {     InitializeComponent();       AddButtonToCanvas();       AddImageToCanvas();       timer = new DispatcherTimer();     timer.Interval = TimeSpan.FromMilliseconds(35);     timer.Tick += new EventHandler(OnTimerTick); } We’ll look at those AddButton and AddImage functions in a moment. The constructor initializes a timer which fires every 35 milliseconds, this timer will be started after the flick gesture completes with some inertia. Back to AddButton and AddImage functions, void AddButtonToCanvas() {     LinearGradientBrush brush;     GradientStop stop1, stop2;       Random rand = new Random(DateTime.Now.Millisecond);       FlickButton = new Button();     FlickButton.Content = "";     FlickButton.Width = 100;     FlickButton.Height = 100;       brush = new LinearGradientBrush();     brush.StartPoint = new Point(0, 0);     brush.EndPoint = new Point(0, 1);       stop1 = new GradientStop();     stop1.Offset = 0;     stop1.Color = Colors.White;       stop2 = new GradientStop();     stop2.Offset = 1;     stop2.Color = (Application.Current.Resources["PhoneAccentBrush"] as SolidColorBrush).Color;       brush.GradientStops.Add(stop1);     brush.GradientStops.Add(stop2);       FlickButton.Background = brush;       Canvas.SetTop(FlickButton, rand.Next(0, 400));     Canvas.SetLeft(FlickButton, rand.Next(0, 200));       MainCanvas.Children.Add(FlickButton);       //subscribe to events     FlickButton.ManipulationDelta += new EventHandler<ManipulationDeltaEventArgs>(OnManipulationDelta);     FlickButton.ManipulationCompleted += new EventHandler<ManipulationCompletedEventArgs>(OnManipulationCompleted); } this function is basically glorifying a simple task. After creating the button and setting its height and width, its background is set to a linear gradient brush. The direction of the gradient is from top towards bottom and notice that the second stop color is the PhoneAccentColor, which changes along with the theme of the device. The line,     stop2.Color = (Application.Current.Resources["PhoneAccentBrush"] as SolidColorBrush).Color; does the magic of extracting the PhoneAccentBrush from application’s resources, getting its color and assigning it to the gradient stop. AddImage function is straight forward in comparison, void AddImageToCanvas() {     Random rand = new Random(DateTime.Now.Millisecond);       FlickImage = new Image();     FlickImage.Source = new BitmapImage(new Uri("/images/Marble.png", UriKind.Relative));       Canvas.SetTop(FlickImage, rand.Next(0, 400));     Canvas.SetLeft(FlickImage, rand.Next(0, 200));       MainCanvas.Children.Add(FlickImage);       //subscribe to events     FlickImage.ManipulationDelta += new EventHandler<ManipulationDeltaEventArgs>(OnManipulationDelta);     FlickImage.ManipulationCompleted += new EventHandler<ManipulationCompletedEventArgs>(OnManipulationCompleted); } The ManipulationDelta and ManipulationCompleted handlers are same for both the button and the image. OnManipulationDelta() should look familiar, a similar implementation was used in the previous post, void OnManipulationDelta(object sender, ManipulationDeltaEventArgs args) {     FrameworkElement Elem = sender as FrameworkElement;       double Left = Canvas.GetLeft(Elem);     double Top = Canvas.GetTop(Elem);       Left += args.DeltaManipulation.Translation.X;     Top += args.DeltaManipulation.Translation.Y;       //check for bounds     if (Left < 0)     {         Left = 0;     }     else if (Left > (MainCanvas.ActualWidth - Elem.ActualWidth))     {         Left = MainCanvas.ActualWidth - Elem.ActualWidth;     }       if (Top < 0)     {         Top = 0;     }     else if (Top > (MainCanvas.ActualHeight - Elem.ActualHeight))     {         Top = MainCanvas.ActualHeight - Elem.ActualHeight;     }       Canvas.SetLeft(Elem, Left);     Canvas.SetTop(Elem, Top); } all it does is calculate the control’s position, check for bounds and then set the top and left of the control. OnManipulationCompleted() is more interesting because here we need to check if the gesture completed with any inertia and if it did, start the timer and continue to move the ui control until it comes to a halt slowly, void OnManipulationCompleted(object sender, ManipulationCompletedEventArgs args) {     FrameworkElement Elem = sender as FrameworkElement;       if (args.IsInertial)     {         ElemToMove = Elem;           Debug.WriteLine("Linear VelX:{0:0.00}  VelY:{1:0.00}", args.FinalVelocities.LinearVelocity.X,             args.FinalVelocities.LinearVelocity.Y);           ElemVelX = args.FinalVelocities.LinearVelocity.X / SPEED_FACTOR;         ElemVelY = args.FinalVelocities.LinearVelocity.Y / SPEED_FACTOR;           timer.Start();     } } ManipulationCompletedEventArgs contains a member, IsInertial, which is set to true if the manipulation was completed with some inertia. args.FinalVelocities.LinearVelocity.X and .Y will contain the velocities along the X and Y axis. We need to scale down these values so they can be used to increment the ui control’s position sensibly. A reference to the ui control is stored in ElemToMove and the velocities are stored as well, these will be used in the timer callback to access the ui control. And finally, we start the timer. The timer callback function is as follows, void OnTimerTick(object sender, EventArgs e) {     if (null != ElemToMove)     {         double Left, Top;         Left = Canvas.GetLeft(ElemToMove);         Top = Canvas.GetTop(ElemToMove);           Left += ElemVelX;         Top += ElemVelY;           //check for bounds         if (Left < 0)         {             Left = 0;             ElemVelX *= -1;         }         else if (Left > (MainCanvas.ActualWidth - ElemToMove.ActualWidth))         {             Left = MainCanvas.ActualWidth - ElemToMove.ActualWidth;             ElemVelX *= -1;         }           if (Top < 0)         {             Top = 0;             ElemVelY *= -1;         }         else if (Top > (MainCanvas.ActualHeight - ElemToMove.ActualHeight))         {             Top = MainCanvas.ActualHeight - ElemToMove.ActualHeight;             ElemVelY *= -1;         }           Canvas.SetLeft(ElemToMove, Left);         Canvas.SetTop(ElemToMove, Top);           //reduce x,y velocities gradually         ElemVelX *= 0.9;         ElemVelY *= 0.9;           //when velocities become too low, break         if (Math.Abs(ElemVelX) < 1.0 && Math.Abs(ElemVelY) < 1.0)         {             timer.Stop();             ElemToMove = null;         }     } } if ElemToMove is not null, we get the top and left values of the control and increment the values with their X and Y velocities. Check for bounds, and if the control goes out of bounds we reverse its velocity. Towards the end, the velocities are reduced by 10% every time the timer callback is called, and if the velocities reach too low values the timer is stopped and ElemToMove is made null. Here’s a short video of the program, the video is a little dodgy because my display driver refuses to run the animations smoothly. The flicks aren’t always recognised but the program should run well on an actual device (or a pc with better configuration), You can download the source code from here: ButtonDragAndFlick.zip

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  • Exporting a non public Type through public API

    - by sachin
    I am trying to follow Trees tutorial at: http://cslibrary.stanford.edu/110/BinaryTrees.html Here is the code I have written so far: package trees.bst; import java.util.ArrayList; import java.util.List; import java.util.StringTokenizer; /** * * @author sachin */ public class BinarySearchTree { Node root = null; class Node { Node left = null; Node right = null; int data = 0; public Node(int data) { this.left = null; this.right = null; this.data = data; } } public void insert(int data) { root = insert(data, root); } public boolean lookup(int data) { return lookup(data, root); } public void buildTree(int numNodes) { for (int i = 0; i < numNodes; i++) { int num = (int) (Math.random() * 10); System.out.println("Inserting number:" + num); insert(num); } } public int size() { return size(root); } public int maxDepth() { return maxDepth(root); } public int minValue() { return minValue(root); } public int maxValue() { return maxValue(root); } public void printTree() { //inorder traversal System.out.println("inorder traversal:"); printTree(root); System.out.println("\n--------------"); } public void printPostorder() { //inorder traversal System.out.println("printPostorder traversal:"); printPostorder(root); System.out.println("\n--------------"); } public int buildTreeFromOutputString(String op) { root = null; int i = 0; StringTokenizer st = new StringTokenizer(op); while (st.hasMoreTokens()) { String stNum = st.nextToken(); int num = Integer.parseInt(stNum); System.out.println("buildTreeFromOutputString: Inserting number:" + num); insert(num); i++; } return i; } public boolean hasPathSum(int pathsum) { return hasPathSum(pathsum, root); } public void mirror() { mirror(root); } public void doubleTree() { doubleTree(root); } public boolean sameTree(BinarySearchTree bst) { //is this tree same as another given tree? return sameTree(this.root, bst.getRoot()); } public void printPaths() { if (root == null) { System.out.println("print path sum: tree is empty"); } List pathSoFar = new ArrayList(); printPaths(root, pathSoFar); } ///-------------------------------------------Public helper functions public Node getRoot() { return root; } //Exporting a non public Type through public API ///-------------------------------------------Helper Functions private boolean isLeaf(Node node) { if (node == null) { return false; } if (node.left == null && node.right == null) { return true; } return false; } ///----------------------------------------------------------- private boolean sameTree(Node n1, Node n2) { if ((n1 == null && n2 == null)) { return true; } else { if ((n1 == null || n2 == null)) { return false; } else { if ((n1.data == n2.data)) { return (sameTree(n1.left, n2.left) && sameTree(n1.right, n2.right)); } } } return false; } private void doubleTree(Node node) { //create a copy //bypass the copy to continue looping if (node == null) { return; } Node copyNode = new Node(node.data); Node temp = node.left; node.left = copyNode; copyNode.left = temp; doubleTree(copyNode.left); doubleTree(node.right); } private void mirror(Node node) { if (node == null) { return; } Node temp = node.left; node.left = node.right; node.right = temp; mirror(node.left); mirror(node.right); } private void printPaths(Node node, List pathSoFar) { if (node == null) { return; } pathSoFar.add(node.data); if (isLeaf(node)) { System.out.println("path in tree:" + pathSoFar); pathSoFar.remove(pathSoFar.lastIndexOf(node.data)); //only the current node, a node.data may be duplicated return; } else { printPaths(node.left, pathSoFar); printPaths(node.right, pathSoFar); } } private boolean hasPathSum(int pathsum, Node node) { if (node == null) { return false; } int val = pathsum - node.data; boolean ret = false; if (val == 0 && isLeaf(node)) { ret = true; } else if (val == 0 && !isLeaf(node)) { ret = false; } else if (val != 0 && isLeaf(node)) { ret = false; } else if (val != 0 && !isLeaf(node)) { //recurse further ret = hasPathSum(val, node.left) || hasPathSum(val, node.right); } return ret; } private void printPostorder(Node node) { //inorder traversal if (node == null) { return; } printPostorder(node.left); printPostorder(node.right); System.out.print(" " + node.data); } private void printTree(Node node) { //inorder traversal if (node == null) { return; } printTree(node.left); System.out.print(" " + node.data); printTree(node.right); } private int minValue(Node node) { if (node == null) { //error case: this is not supported return -1; } if (node.left == null) { return node.data; } else { return minValue(node.left); } } private int maxValue(Node node) { if (node == null) { //error case: this is not supported return -1; } if (node.right == null) { return node.data; } else { return maxValue(node.right); } } private int maxDepth(Node node) { if (node == null || (node.left == null && node.right == null)) { return 0; } int ldepth = 1 + maxDepth(node.left); int rdepth = 1 + maxDepth(node.right); if (ldepth > rdepth) { return ldepth; } else { return rdepth; } } private int size(Node node) { if (node == null) { return 0; } return 1 + size(node.left) + size(node.right); } private Node insert(int data, Node node) { if (node == null) { node = new Node(data); } else if (data <= node.data) { node.left = insert(data, node.left); } else { node.right = insert(data, node.right); } //control should never reach here; return node; } private boolean lookup(int data, Node node) { if (node == null) { return false; } if (node.data == data) { return true; } if (data < node.data) { return lookup(data, node.left); } else { return lookup(data, node.right); } } public static void main(String[] args) { BinarySearchTree bst = new BinarySearchTree(); int treesize = 5; bst.buildTree(treesize); //treesize = bst.buildTreeFromOutputString("4 4 4 6 7"); treesize = bst.buildTreeFromOutputString("3 4 6 3 6"); //treesize = bst.buildTreeFromOutputString("10"); for (int i = 0; i < treesize; i++) { System.out.println("Searching:" + i + " found:" + bst.lookup(i)); } System.out.println("tree size:" + bst.size()); System.out.println("maxDepth :" + bst.maxDepth()); System.out.println("minvalue :" + bst.minValue()); System.out.println("maxvalue :" + bst.maxValue()); bst.printTree(); bst.printPostorder(); int pathSum = 10; System.out.println("hasPathSum " + pathSum + ":" + bst.hasPathSum(pathSum)); pathSum = 6; System.out.println("hasPathSum " + pathSum + ":" + bst.hasPathSum(pathSum)); pathSum = 19; System.out.println("hasPathSum " + pathSum + ":" + bst.hasPathSum(pathSum)); bst.printPaths(); bst.printTree(); //bst.mirror(); System.out.println("Tree after mirror function:"); bst.printTree(); //bst.doubleTree(); System.out.println("Tree after double function:"); bst.printTree(); System.out.println("tree size:" + bst.size()); System.out.println("Same tree:" + bst.sameTree(bst)); BinarySearchTree bst2 = new BinarySearchTree(); bst2.buildTree(treesize); treesize = bst2.buildTreeFromOutputString("3 4 6 3 6"); bst2.printTree(); System.out.println("Same tree:" + bst.sameTree(bst2)); System.out.println("---"); } } Now the problem is that netbeans shows Warning: Exporting a non public Type through public API for function getRoot(). I write this function to get root of tree to be used in sameTree() function, to help comparison of "this" with given tree. Perhaps this is a OOP design issue... How should I restructure the above code that I do not get this warning and what is the concept I am missing here?

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  • How do I make the left and right gutters different colors with 960.gs?

    - by Andrew Arrow
    How do I make the left and right gutters different colors with 960.gs? When I try something simple like: <div style="background-color: green"> <div class="container_16"> <div class="grid_16"> test </div> </div> </div> <div style="background-color: cyan"> <div class="container_16"> <div class="grid_16"> test </div> </div> </div> The green and cyan colors are ignored. Seems like the "grid_16" class removes the color for some reason? My goal is being able to have different sections of the page in different colors all the way across the page, even past 960 pixels. So if someone makes their browser 1200px the left and right sides have the right color and the rest of the grid system is all contained within the 960 pixels in the middle. I could add a background color to 'body' to do this for just 1 color, but I want multiple colors in the page. Like different colored horizontal stripes. Thanks.

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  • CSS style to create an HTML with an image on left and input text boxes on right that fills all space

    - by dafi
    I need to create an HTML page (a JqueryUI dialog but this isn't the problem) containing an image on left (size is fixed to 75x75) and on right some input text boxes, input boxes must resize to all remaining space. You can see an example at http://img683.imageshack.us/img683/5412/19483174.jpg The problem is that when I resize the dialog controls move under image as shown at http://img510.imageshack.us/img510/4817/44749696.jpg How can I resolve this problem in all browser and if possible using only CSS? Below I show my HTML code and the CSS I'm using HTML code <div id="dialog-form" title="Modify Post"> <form action=""> <fieldset> <img id="dialog-modify-thumb" src="http://dummyimage.com/75x75/000/fff" alt="" width="75" height="75"/> <div id="dialog-modify-controls"> <label for="dialog-modify-caption">Caption</label> <input type="text" name="dialog-modify-caption" id="dialog-modify-caption"/> <br/> <label for="dialog-modify-tags">Tags</label> <input type="text" name="dialog-modify-tags" id="dialog-modify-tags"/> <br/> <label for="dialog-modify-publish-date">Publish Date</label> <input type="text" name="dialog-modify-publish-date" id="dialog-modify-publish-date"/> </div> </fieldset> </form> </div> The CSS #dialog-modify-thumb { margin-right: 3px; border: 1px solid; display: block; float:left; } #dialog-form input[type='text'] { width: 100%; } #dialog-modify-controls { float: right; width:100%; }

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  • Absolute positioning in IE6, using left: 0; and right: 0; simultaneously

    - by Zane
    Here is my website: http://dagwaging.110mb.com/ View it in any good browser, then in IE6. It dies in IE6. It seems that in IE6, one can't do this: div { position: absolute; left: 0px; right: 0px; } or this: div { position: absolute; top: 0px; bottom: 0px; } Absolute positions cannot be set for left and right or top and bottom at the same time. This is terrible, because that is pretty much the basis of my site design. The HTML can be viewed on the site, and the CSS is in /style.css. I'd like to fix this without invalidating my CSS or HTML. Can this be done? Another problem is that my content uses min-width and max-width to avoid over-stretching or compressing the content within. IE6 can't do min-width, so how can I replicate this behavior?

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  • Correlate GROUP BY and LEFT JOIN on multiple criteria to show latest record?

    - by Sunbird
    In a simple stock management database, quantity of new stock is added and shipped until quantity reaches zero. Each stock movement is assigned a reference, only the latest reference is used. In the example provided, the latest references are never shown, the stock ID's 1,4 should have references charlie, foxtrot respectively, but instead show alpha, delta. How can a GROUP BY and LEFT JOIN on multiple criteria be correlated to show the latest record? http://sqlfiddle.com/#!2/6bf37/107 CREATE TABLE stock ( id tinyint PRIMARY KEY, quantity int, parent_id tinyint ); CREATE TABLE stock_reference ( id tinyint PRIMARY KEY, stock_id tinyint, stock_reference_type_id tinyint, reference varchar(50) ); CREATE TABLE stock_reference_type ( id tinyint PRIMARY KEY, name varchar(50) ); INSERT INTO stock VALUES (1, 10, 1), (2, -5, 1), (3, -5, 1), (4, 20, 4), (5, -10, 4), (6, -5, 4); INSERT INTO stock_reference VALUES (1, 1, 1, 'Alpha'), (2, 2, 1, 'Beta'), (3, 3, 1, 'Charlie'), (4, 4, 1, 'Delta'), (5, 5, 1, 'Echo'), (6, 6, 1, 'Foxtrot'); INSERT INTO stock_reference_type VALUES (1, 'Customer Reference'); SELECT stock.id, SUM(stock.quantity) as quantity, customer.reference FROM stock LEFT JOIN stock_reference AS customer ON stock.id = customer.stock_id AND stock_reference_type_id = 1 GROUP BY stock.parent_id

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  • CSS with Aligned LI within a UL

    - by Alex
    I am trying to have some LIs within a UL align left, right, and center within a page. For the life of me, I can't figure out how to keep something "centered" on the same line as a left and right aligned LI. <style> ul { margin:1em 0; padding:0 } ul li{ display:inline-block; white-space:nowrap; margin:5px } ul li.left{ float: left; text-align:left; } ul li.center{ float:left; text-align: center; } ul li.right{ float: right; text-align:right; } </style> <ul> <li class="left">left</li> <li class="center">center</li> <li class="right">right</li> </ul> <ul> <li class="left">left</li> <li class="right">right</li> </ul> <ul> <li class="left">left</li> </ul> Can anyone help? BTW, I've trying to avoid DIVs. Thanks!

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  • Setting the correct orientation for scrollbars in right-to-left pages.

    - by Daniel Lew
    I'm working with right-to-left layouts at the moment (think Hebrew or Arabic). In RTL, the page is generally flipped horizontally. However, I can't figure out how to change the orientation of the scrollbars. I would assume that the scrollbars should appear on the left side of a scrollable element, not the right side like it does in an LTR layout. Here is an example page where the scrollbar still appears on the right: <html dir="rtl"> <body> <div style="height: 100px; overflow: auto;"> <p>This is some text</p> <p>This is some text</p> <p>This is some text</p> <p>This is some text</p> <p>This is some text</p> </body> </html> Is the orientation of a scrollbar a browser locale setting, and thus is not something I should be concerned about, or is there a way to set the orientation of the scrollbar? (I'm not interested in implementing my own JavaScript scrollbar; if it turns out this is just a limitation of browsers then I'd rather live with that than add complexity to the page.)

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  • How can I exclude LEFT JOINed tables from TOP in SQL Server?

    - by Kalessin
    Let's say I have two tables of books and two tables of their corresponding editions. I have a query as follows: SELECT TOP 10 * FROM (SELECT hbID, hbTitle, hbPublisherID, hbPublishDate, hbedID, hbedDate FROM hardback LEFT JOIN hardbackEdition on hbID = hbedID UNION SELECT pbID, pbTitle, pbPublisher, pbPublishDate, pbedID, pbedDate FROM paperback Left JOIN paperbackEdition on pbID = pbedID ) books WHERE hbPublisherID = 7 ORDER BY hbPublishDate DESC If there are 5 editions of the first two hardback and/or paperback books, this query only returns two books. However, I want the TOP 10 to apply only to the number of actual book records returned. Is there a way I can select 10 actual books, and still get all of their associated edition records? In case it's relevant, I do not have database permissions to CREATE and DROP temporary tables. Thanks for reading! Update To clarify: The paperback table has an associated table of paperback editions. The hardback table has an associated table of hardback editions. The hardback and paperback tables are not related to each other except to the user who will (hopefully!) see them displayed together.

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