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  • how do I find the number of xml children in AS3

    - by vasion
    so live docs says this for calling .lenght() on an XML object For XML objects, this method always returns the integer 1. The length() method of the XMLList class returns a value of 1 for an XMLList object that contains only one value. i called it on an xml that looked like this: <xml> <picture>1</picture> <picture>2</picture> </xml> and it reallt returned 1. how do i get the number of children in my xml?

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  • Remote XML retrieval

    - by rrrfusco
    I'm retrieving a remote XML file with wget -O remotefile localfile with a cron tab. Every so often the local file becomes malformed probably because of double whitespace (according to firefox) between the CDATA tags. Sometimes the parser gives an error for ' > ' missing, but upon checking the xml file the ' > ' exists... The remote xml file never gives malformed errors when called in the url. EDIT It seems CDATA is not parsed by the xml parser. (w3schools) Is there a way to set wget to retain wellformed XML? If not wget, What is a good way to continously retrieve a remote XML file and keep it well formed?

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  • parsing xml attribute value

    - by vbNewbie
    I have been parsing xml content using the xmlreader and cannot use the xml document but so far it works getting all elementcontent except for the attribute contents. I need to parse the link below found in the following entry; <title>XXXX UUUUUU posted a</title> <category term="NotePosted" label="Note Posted"/> <link rel="alternate" type="html" href="http://www.dfsddsfdsf.com/profile.php?id=sdfdfsfdsdfddfsfd&amp;v=wall&amp;story_dbid=dssdfasdfdasfdsafafafa"/> <source>......... <source> I need the href tag in the link attribute but it keeps coming back null. While ureader.Read If ureader.HasAttributes Then fId = ureader.GetAttribute("href") If fId.Contains("?v=wall&amp") Then fIdList.Add(fId) Exit While End If If String.IsNullOrEmpty(fId) Then fId = "NOTHING" End If End If End While

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  • Write an xml file from the specified node?

    - by Googler
    Hi all, This is my xml file Input: <world> <patent> <xml>a</xml> <java>333</java> <jaxb>111</jaxb> </patent> </world> I need the read the above xml file and reproduce the following the output Output: <patent> <xml>a</xml> <java>333</java> <jaxb>111</jaxb> </patent> I dont need the world element. How to achieve this using Xpath. Can anyone help me on this?

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  • parsing a xml to get some values

    - by Joan Silverstone
    Hello, i have this xml: http://www.managerleague.com/export_data.pl?data=transfers&output=xml&hide_header=0 These are player sales from a browser game. I want to save some fields from these sales. I am fetching that xml with curl and storing on my server. Then do the following: $xml_str = file_get_contents('salespage.xml'); $xml = new SimpleXMLElement($xml_str); $items = $xml->xpath('*/transfer'); print_r($items); foreach($items as $item) { echo $item['buyerTeamname'], ': ', $item['sellerTeamname'], "\n"; } The array is empty and i cant seem to get anything from it. What am i doing wrong?

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  • Maven Grails web.xml

    - by dunn less
    Might be a stupid question, but in my current maven project i do not have a web.xml in my /web-app/WEB-INF folder. There is no web-xml in my project and never has been, im trying to add it but my application is non-responsive to anything written in the web.xml. What am i missing?, iv tried specifying the path to it through the config.groovy like: grails.project.web.xml="web-app/WEB-INF/web.xml" Am i missing something? Do i need to specify the web.xml in some other config file in order to make my project utilize it ?

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  • php, extract data from a non-standard xml document

    - by Michael
    I have some kind xml content I need to extract the information and store it into database <xml file="136000000-136100000"> <Id>136000000</Id> <Name>Sem Serxy</Na me> <Email>[email protected]</Email> <DateRegistration>10/13/2010 1:49:30 AM</DateRegistration> </xml> <xml file="136000000-136100000"> <Id>136000001</Id> <Name>God Deckor</Name> <Email>[email protected]</Email> If I try simple xml load is not working as the document doesn't seem to be valid xml. I can use regex to extract the info with preg_match_all but I feel this is not the right way as the data is already well structured. Any other method ?

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  • Is the XML processing instructions node mandatory ?

    - by ereOn
    I had a discussion with a colleague of mine about the XML processing instructions node (I'm talking about this = <?xml version="1.0" encoding="UTF-8"?>). I believe that for something to be called "valid XML", it requires a processing instructions node. My colleague states that the processing instruction node is optionnal, since the default encoding is UTF-8 and the version is always 1.0. This make sense, but what does the standard says ? In short, given the following file: <books> <book id="1"><title>Title</title></book> </book> Can we say that: It is valid XML ? It is a valid XML node ? It is a valid XML document ? Thank you very much.

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  • XML/XSL nub: Is it possible to create an COMPOSITE XML/XSLT document?

    - by jmweekes
    I have just recently (like 2 days) started using XSLT documents with XML. I understand the basics and am able to generate a formatted document using an .XML document that references a separate .XSLT document. My question, as in the subject, is "Is it possible to create a SINGLE, composite document that contains both the XML data and XSLT processing/formatting/styling and displays as formatted HTML?" I am writing a desktop application in which I need to generate a formatted document on the fly from XML stored in the database. I want to do this without creating or referencing any actual physical files. I will generate a text string containing the XML/XSLT document and feed this to a WebBrowser component for formatted display. Hopefully what I want to do doesn't totally go against the whole XML/XSLT methodology. Any information, direction or suggestions will be greatly appreciated.

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  • Xml schema, how to make sure one element exists with a specific attribute value

    - by pexxxy
    How do I enforce the existing of an element with a specific attribute value in the XML? For example: <events> <event type="system" desc="this is a system event"/> <event type="bla1" desc="this is bla1 event"/> <event type="bla2" desc="this is bla2 event"/> </events> I need a rule to make sure the event element with type attribute = 'system' exists (once). All other event elements are optional;

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  • Xml Serialization and the [Obsolete] Attribute

    - by PSteele
    I learned something new today: Starting with .NET 3.5, the XmlSerializer no longer serializes properties that are marked with the Obsolete attribute.  I can’t say that I really agree with this.  Marking something Obsolete is supposed to be something for a developer to deal with in source code.  Once an object is serialized to XML, it becomes data.  I think using the Obsolete attribute as both a compiler flag as well as controlling XML serialization is a bad idea. In this post, I’ll show you how I ran into this and how I got around it. The Setup Let’s start with some make-believe code to demonstrate the issue.  We have a simple data class for storing some information.  We use XML serialization to read and write the data: public class MyData { public int Age { get; set; } public string FirstName { get; set; } public string LastName { get; set; } public List<String> Hobbies { get; set; }   public MyData() { this.Hobbies = new List<string>(); } } Now a few simple lines of code to serialize it to XML: static void Main(string[] args) { var data = new MyData {    FirstName = "Zachary", LastName = "Smith", Age = 50, Hobbies = {"Mischief", "Sabotage"}, }; var serializer = new XmlSerializer(typeof (MyData)); serializer.Serialize(Console.Out, data); Console.ReadKey(); } And this is what we see on the console: <?xml version="1.0" encoding="IBM437"?> <MyData xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Age>50</Age> <FirstName>Zachary</FirstName> <LastName>Smith</LastName> <Hobbies> <string>Mischief</string> <string>Sabotage</string> </Hobbies> </MyData>   The Change So we decided to track the hobbies as a list of strings.  As always, things change and we have more information we need to store per-hobby.  We create a custom “Hobby” object, add a List<Hobby> to our MyData class and we obsolete the old “Hobbies” list to let developers know they shouldn’t use it going forward: public class Hobby { public string Name { get; set; } public int Frequency { get; set; } public int TimesCaught { get; set; }   public override string ToString() { return this.Name; } } public class MyData { public int Age { get; set; } public string FirstName { get; set; } public string LastName { get; set; } [Obsolete("Use HobbyData collection instead.")] public List<String> Hobbies { get; set; } public List<Hobby> HobbyData { get; set; }   public MyData() { this.Hobbies = new List<string>(); this.HobbyData = new List<Hobby>(); } } Here’s the kicker: This serialization is done in another application.  The consumers of the XML will be older clients (clients that expect only a “Hobbies” collection) as well as newer clients (that support the new “HobbyData” collection).  This really shouldn’t be a problem – the obsolete attribute is metadata for .NET compilers.  Unfortunately, the XmlSerializer also looks at the compiler attribute to determine what items to serialize/deserialize.  Here’s an example of our problem: static void Main(string[] args) { var xml = @"<?xml version=""1.0"" encoding=""IBM437""?> <MyData xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema""> <Age>50</Age> <FirstName>Zachary</FirstName> <LastName>Smith</LastName> <Hobbies> <string>Mischief</string> <string>Sabotage</string> </Hobbies> </MyData>"; var serializer = new XmlSerializer(typeof(MyData)); var stream = new StringReader(xml); var data = (MyData) serializer.Deserialize(stream);   if( data.Hobbies.Count != 2) { throw new ApplicationException("Hobbies did not deserialize properly"); } } If you run the code above, you’ll hit the exception.  Even though the XML contains a “<Hobbies>” node, the obsolete attribute prevents the node from being processed.  This will break old clients that use the new library, but don’t yet access the HobbyData collection. The Fix This fix (in this case), isn’t too painful.  The XmlSerializer exposes events for times when it runs into items (Elements, Attributes, Nodes, etc…) it doesn’t know what to do with.  We can hook in to those events and check and see if we’re getting something that we want to support (like our “Hobbies” node). Here’s a way to read in the old XML data with full support of the new data structure (and keeping the Hobbies collection marked as obsolete): static void Main(string[] args) { var xml = @"<?xml version=""1.0"" encoding=""IBM437""?> <MyData xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema""> <Age>50</Age> <FirstName>Zachary</FirstName> <LastName>Smith</LastName> <Hobbies> <string>Mischief</string> <string>Sabotage</string> </Hobbies> </MyData>"; var serializer = new XmlSerializer(typeof(MyData)); serializer.UnknownElement += serializer_UnknownElement; var stream = new StringReader(xml); var data = (MyData)serializer.Deserialize(stream);   if (data.Hobbies.Count != 2) { throw new ApplicationException("Hobbies did not deserialize properly"); } }   static void serializer_UnknownElement(object sender, XmlElementEventArgs e) { if( e.Element.Name != "Hobbies") { return; }   var target = (MyData) e.ObjectBeingDeserialized; foreach(XmlElement hobby in e.Element.ChildNodes) { target.Hobbies.Add(hobby.InnerText); target.HobbyData.Add(new Hobby{Name = hobby.InnerText}); } } As you can see, we hook in to the “UnknownElement” event.  Once we determine it’s our “Hobbies” node, we deserialize it ourselves – as well as populating the new HobbyData collection.  In this case, we have a fairly simple solution to a small change in XML layout.  If you make more extensive changes, it would probably be easier to do some custom serialization to support older data. A sample project with all of this code is available from my repository on bitbucket. Technorati Tags: XmlSerializer,Obsolete,.NET

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  • How to find attribute value

    - by Pramodh
    Hi, I need to find an inner text of an element inside an XmlDocument and return it's Xpath. for example, searching for "ThisText" inside : <xml> <xml2 val="ThisText"></xml2> </xml> should return the Xpath of xml2 what's the most efficient way of doing this in c#?

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  • Extracting an attribute value with beautifulsoup

    - by Barnabe
    I am trying to extract the content of a single "value" attribute in a specific "input" tag on a webpage. I use the following code: import urllib f = urllib.urlopen("http://58.68.130.147") s = f.read() f.close() from BeautifulSoup import BeautifulStoneSoup soup = BeautifulStoneSoup(s) inputTag = soup.findAll(attrs={"name" : "stainfo"}) output = inputTag['value'] print str(output) I get a TypeError: list indices must be integers, not str even though from the Beautifulsoup documentation i understand that strings should not be a problem here... but i a no specialist and i may have misunderstood. Any suggestion is greatly appreciated! Thanks in advance.

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  • Attributes of attributevalue element in SAML 2 Attribute Statement

    - by AJ
    I am building a web service that receives a SAML attribute query and responds with an attribute statement. I know I can return one or multiple values of a SAML attribute. I have some values that are dependent on the other attribute values. I need to show that relationship. Let us say, the query is for the Subject Dave and the return values are his company and job title. Dave can work at multiple companies with job title at each company. I have two options of sending this data back: Send this as a complextype by defining an attribute organization and return xml within that attribute. <saml:Attribute name="company"> <saml:AttributeValue> <company name="company1" jobtitle="CIO"/> <company name="company2" jobtitle="VP"/> </saml:AttributeValue> Try to send multiple values of attributes somehow sending a reference in attributevalue element. <saml:Attribute name="company"> <attributeValue>company1</attributeValue> <attributeValue>company2</attributeValue> </saml:Attribute> <saml:Attribute name="jobTitle> <attributeValue company="company1">CIO</attributeValue> <attributeValue company="company2">VP</attributeValue> </saml:Attribute> Which approach will you prefer? Why? I am biased towards second approach as it does not require client to know about any schema. It does require them to know about non-standard attribute company in the attribute value.

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  • Given an XML which contains a representation of a graph, how to apply it DFS algorithm? [on hold]

    - by winston smith
    Given the followin XML which is a directed graph: <?xml version="1.0" encoding="iso-8859-1" ?> <!DOCTYPE graph PUBLIC "-//FC//DTD red//EN" "../dtd/graph.dtd"> <graph direct="1"> <vertex label="V0"/> <vertex label="V1"/> <vertex label="V2"/> <vertex label="V3"/> <vertex label="V4"/> <vertex label="V5"/> <edge source="V0" target="V1" weight="1"/> <edge source="V0" target="V4" weight="1"/> <edge source="V5" target="V2" weight="1"/> <edge source="V5" target="V4" weight="1"/> <edge source="V1" target="V2" weight="1"/> <edge source="V1" target="V3" weight="1"/> <edge source="V1" target="V4" weight="1"/> <edge source="V2" target="V3" weight="1"/> </graph> With this classes i parsed the graph and give it an adjacency list representation: import java.io.IOException; import java.util.HashSet; import java.util.LinkedList; import java.util.Collection; import java.util.Iterator; import java.util.logging.Level; import java.util.logging.Logger; import practica3.util.Disc; public class ParsingXML { public static void main(String[] args) { try { // TODO code application logic here Collection<Vertex> sources = new HashSet<Vertex>(); LinkedList<String> lines = Disc.readFile("xml/directed.xml"); for (String lin : lines) { int i = Disc.find(lin, "source=\""); String data = ""; if (i > 0 && i < lin.length()) { while (lin.charAt(i + 1) != '"') { data += lin.charAt(i + 1); i++; } Vertex v = new Vertex(); v.setName(data); v.setAdy(new HashSet<Vertex>()); sources.add(v); } } Iterator it = sources.iterator(); while (it.hasNext()) { Vertex ver = (Vertex) it.next(); Collection<Vertex> adyacencias = ver.getAdy(); LinkedList<String> ls = Disc.readFile("xml/graphs.xml"); for (String lin : ls) { int i = Disc.find(lin, "target=\""); String data = ""; if (lin.contains("source=\""+ver.getName())) { Vertex v = new Vertex(); if (i > 0 && i < lin.length()) { while (lin.charAt(i + 1) != '"') { data += lin.charAt(i + 1); i++; } v.setName(data); } i = Disc.find(lin, "weight=\""); data = ""; if (i > 0 && i < lin.length()) { while (lin.charAt(i + 1) != '"') { data += lin.charAt(i + 1); i++; } v.setWeight(Integer.parseInt(data)); } if (v.getName() != null) { adyacencias.add(v); } } } } for (Vertex vert : sources) { System.out.println(vert); System.out.println("adyacencias: " + vert.getAdy()); } } catch (IOException ex) { Logger.getLogger(ParsingXML.class.getName()).log(Level.SEVERE, null, ex); } } } This is another class: import java.util.Collection; import java.util.Objects; public class Vertex { private String name; private int weight; private Collection ady; public Collection getAdy() { return ady; } public void setAdy(Collection adyacencias) { this.ady = adyacencias; } public String getName() { return name; } public void setName(String nombre) { this.name = nombre; } public int getWeight() { return weight; } public void setWeight(int weight) { this.weight = weight; } @Override public int hashCode() { int hash = 7; hash = 43 * hash + Objects.hashCode(this.name); hash = 43 * hash + this.weight; return hash; } @Override public boolean equals(Object obj) { if (obj == null) { return false; } if (getClass() != obj.getClass()) { return false; } final Vertex other = (Vertex) obj; if (!Objects.equals(this.name, other.name)) { return false; } if (this.weight != other.weight) { return false; } return true; } @Override public String toString() { return "Vertice{" + "name=" + name + ", weight=" + weight + '}'; } } And finally: /** * * @author user */ /* -*-jde-*- */ /* <Disc.java> Contains the main argument*/ import java.io.*; import java.util.LinkedList; /** * Lectura y escritura de archivos en listas de cadenas * Ideal para el uso de las clases para gráficas. * * @author Peralta Santa Anna Victor Miguel * @since Julio 2011 */ public class Disc { /** * Metodo para lectura de un archivo * * @param fileName archivo que se va a leer * @return El archivo en representacion de lista de cadenas */ public static LinkedList<String> readFile(String fileName) throws IOException { BufferedReader file = new BufferedReader(new FileReader(fileName)); LinkedList<String> textlist = new LinkedList<String>(); while (file.ready()) { textlist.add(file.readLine().trim()); } file.close(); /* for(String linea:textlist){ if(linea.contains("source")){ //String generado = linea.replaceAll("<\\w+\\s+\"", ""); //System.out.println(generado); } }*/ return textlist; }//readFile public static int find(String linea,String palabra){ int i,j; boolean found = false; for(i=0,j=0;i<linea.length();i++){ if(linea.charAt(i)==palabra.charAt(j)){ j++; if(j==palabra.length()){ found = true; return i; } }else{ continue; } } if(!found){ i= -1; } return i; } /** * Metodo para la escritura de un archivo * * @param fileName archivo que se va a escribir * @param tofile la lista de cadenas que quedaran en el archivo * @param append el bit que dira si se anexa el contenido o se empieza de cero */ public static void writeFile(String fileName, LinkedList<String> tofile, boolean append) throws IOException { FileWriter file = new FileWriter(fileName, append); for (int i = 0; i < tofile.size(); i++) { file.write(tofile.get(i) + "\n"); } file.close(); }//writeFile /** * Metodo para escritura de un archivo * @param msg archivo que se va a escribir * @param tofile la cadena que quedaran en el archivo * @param append el bit que dira si se anexa el contenido o se empieza de cero */ public static void writeFile(String msg, String tofile, boolean append) throws IOException { FileWriter file = new FileWriter(msg, append); file.write(tofile); file.close(); }//writeFile }// I'm stuck on what can be the best way to given an adjacency list representation of the graph how to apply it Depth-first search algorithm. Any idea of how to aproach to complete the task?

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  • Manually parse string as XAML Attribute

    - by bitbonk
    How does the XAML Parser convert the string "Red" in Foreground="Red" to a SolidColorBrush? Allthough I know the Types have System.ComponentModel.TypeConverter defined, I doupt that the WPF XAML parser acutally always uses those to convert the string to the brush. Are there any XAML APIs apart from XamlReader.Load (wich wants a valid xml string) that I could use to parse a single string as if it where an attibute for a certain property?

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  • PHP: Writing non-english characters to XML - encoding problem

    - by Dean
    Hello, I wrote a small PHP script to edit the site news XML file. I used DOM to manipulate the XML (Loading, writing, editing). It works fine when writing English characters, but when non-English characters are written, PHP throws an error when trying to load the file. If I manually type non-English characters into the file - it's loaded perfectly fine, but if PHP writes the non-English characters the encoding goes wrong, although I specified the utf-8 encoding. Any help is appreciated. Errors: Warning: DOMDocument::load() [domdocument.load]: Entity 'times' not defined in filepath Warning: DOMDocument::load() [domdocument.load]: Input is not proper UTF-8, indicate encoding ! Bytes: 0x91 0x26 0x74 0x69 in filepath Here are the functions responsible for loading and saving the file (self-explanatory): function get_tags_from_xml(){ // Load news entries from XML file for display $errors = Array(); if(!$xml_file = load_news_file()){ // Load file // String indicates error presence $errors = "file not found"; return $errors; } $taglist = $xml_file->getElementsByTagName("text"); return $taglist; } function set_news_lang(){ // Sets the news language global $news_lang; if($_POST["news-lang"]){ $news_lang = htmlentities($_POST["news-lang"]); } elseif($_GET["news-lang"]){ $news_lang = htmlentities($_GET["news-lang"]); } else{ $news_lang = "he"; } } function load_news_file(){ // Load XML news file for proccessing, depending on language global $news_lang; $doc = new DOMDocument('1.0','utf-8'); // Create new XML document $doc->load("news_{$news_lang}.xml"); // Load news file by language $doc->formatOutput = true; // Nicely format the file return $doc; } function save_news_file($doc){ // Save XML news file, depending on language global $news_lang; $doc->saveXML($doc->documentElement); $doc->save("news_{$news_lang}.xml"); } Here is the code for writing to XML (add news): <?php ob_start()?> <?php include("include/xml_functions.php")?> <?php include("../include/functions.php")?> <?php get_lang();?> <?php //TODO: ADD USER AUTHENTICATION! if(isset($_POST["news"]) && isset($_POST["news-lang"])){ set_news_lang(); $news = htmlentities($_POST["news"]); $xml_doc = load_news_file(); $news_list = $xml_doc->getElementsByTagName("text"); // Get all existing news from file $doc_root_element = $xml_doc->getElementsByTagName("news")->item(0); // Get the root element of the new XML document $new_news_entry = $xml_doc->createElement("text",$news); // Create the submited news entry $doc_root_element->appendChild($new_news_entry); // Append submited news entry $xml_doc->appendChild($doc_root_element); save_news_file($xml_doc); header("Location: /cpanel/index.php?lang={$lang}&news-lang={$news_lang}"); } else{ header("Location: /cpanel/index.php?lang={$lang}&news-lang={$news_lang}"); } ?> <?php ob_end_flush()?>

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  • xml schema building

    - by amanrahahla
    in xml can any concept inhert the attribute of the main concept as an example: can textbook take the same attribute of book and how? another question if the attribute is a compound noun (i mean two or more words) such as family line it gave me an error when i save it as xml how can i deal with this situation?

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  • FileNotFoundException, altough the XML file should be deployed

    - by Bernhard V
    Hi, I've got problems starting my WAR application on a local JBoss. After two other EARs are deployed and the TomcatDeployer begins deploying the WAR, I'm getting the following error message: 2010-04-28 10:01:56,605 ERROR [org.jboss.ejb.plugins.LogInterceptor] [] [main] EJBException in method: public abstract at.sozvers.stp.zpv.ejb.lea.rwsuc.EJBLeaRegelwerkSuchenRemote at.sozvers.stp.zpv.ejb.lea.rwsuc.EJBLeaRegelwerkSuchenHome.create() throws javax.ejb.CreateException,java.rmi.RemoteException, causedBy: javax.ejb.EJBException: org.springframework.beans.factory.access.BootstrapException: Unable to initialize group definition. Group resource name [classpath*:applicationContext.xml], factory key [contextService]; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'contextService' defined in URL [jar:file:/C:/ta30/nutzb/jboss-4.2.3.GA.ZPV/server/default/deploy/deploy.last/zpv-app-web-frontend-1.0-SNAPSHOT.war/WEB-INF/lib/zpv-comp-ejb-modules-1.0-SNAPSHOT-client.jar!/applicationContext.xml]: Instantiation of bean failed; nested exception is org.springframework.beans.BeanInstantiationException: Could not instantiate bean class [org.springframework.context.support.ClassPathXmlApplicationContext]: Constructor threw exception; nested exception is org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from class path resource [at/sozvers/stp/zpv/dao/ContextBasic.xml]; nested exception is java.io.FileNotFoundException: class path resource [at/sozvers/stp/zpv/dao/ContextBasic.xml] cannot be opened because it does not exist The sad thing is that the resource at/sozvers/stp/zpv/dao/ContextBasic.xml actually is placed in a JAR in one of my EAR files which should be deployed before the WAR. And at least I get a message that the deployment of the EAR has been successful. I also looked into the JAR with my file archiver and the ContextBasic.xml is indeed there at the right place. Is there a way for me to get sure that the JAR, not the EAR as a whole, is really deployed to the JBoss? I'm already starting to lose my head about this issue. Thank you. Bernhard

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  • virsh XML interface allocation

    - by Kaushik Koneru
    I am trying to launch VM using a XML. This VM will be having 5 interfaces each connected to certain bridge. Issue here is allocation of these interfaces is random. My XML <interface type='bridge'> <mac address='52:54:00:9f:14:b3'/> <source bridge='br0'/> <target dev='vnet1'/> <model type='e1000'/> <alias name='net0'/> <address type='pci' domain='0x0000' bus='0x00' slot='0x03' function='0x0'/> </interface> <interface type='bridge'> <mac address='52:54:00:9f:14:b4'/> <source bridge='br1'/> <target dev='vnet2'/> <model type='e1000'/> <alias name='net1'/> <address type='pci' domain='0x0000' bus='0x00' slot='0x10' function='0x0'/> </interface> <interface type='bridge'> <mac address='52:54:00:9f:14:b5'/> <source bridge='br2'/> <target dev='vnet2'/> <model type='e1000'/> <alias name='net3'/> <address type='pci' domain='0x0000' bus='0x00' slot='0x12' function='0x0'/> </interface> <interface type='bridge'> <mac address='52:54:00:9f:14:c4'/> <source bridge='br3'/> <target dev='vnet3'/> <model type='e1000'/> <alias name='net4'/> <address type='pci' domain='0x0000' bus='0x00' slot='0x18' function='0x0'/> </interface> Allocation of interfaces are random mean e th6 will be connected to br3 ; eth7 -- br4 eth8 -- br2 eth9 -- br0. Is there any way to make it static?? At the same time is there anyway of assigning IP Address to these eth interfaces through XML file itself??

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  • Is Berkeley DB XML a viable database backend?

    - by w00t
    Apparently, BDB-XML has been around since at least 2003 but I only recently stumbled upon it on Oracle's website: Berkeley DB XML. Here's the blurb: Oracle Berkeley DB XML is an open source, embeddable XML database with XQuery-based access to documents stored in containers and indexed based on their content. Oracle Berkeley DB XML is built on top of Oracle Berkeley DB and inherits its rich features and attributes. Like Oracle Berkeley DB, it runs in process with the application with no need for human administration. Oracle Berkeley DB XML adds a document parser, XML indexer and XQuery engine on top of Oracle Berkeley DB to enable the fastest, most efficient retrieval of data. To me it seems that the underlying ideas are technically sound and probably more mature than the newer document-based DBs like CouchDB or MongoDB. It has support for C, C++, Ruby and Perl, as far as I can determine. It even has HA-capabilities like automatic replication using a master/slave model with automatic election. However, I can't seem to find any projects that use it. Is there something fundamentally wrong with it? Is the license too onerous? Is it too complicated? Why is it not being used?

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  • In-document schema declarations and lxml

    - by shylent
    As per the official documentation of lxml, if one wants to validate a xml document against a xml schema document, one has to construct the XMLSchema object (basically, parse the schema document) construct the XMLParser, passing the XMLSchema object as its schema argument parse the actual xml document (instance document) using the constructed parser There can be variations, but the essense is pretty much the same no matter how you do it, - the schema is specified 'externally' (as opposed to specifying it inside the actual xml document). If you follow this procedure, the validation occurs, sure enough, but if I understand it correctly, that completely ignores the whole idea of the schemaLocation and noNamespaceSchemaLocation attributes from xsi. This introduces a whole bunch of limitations, starting with the fact, that you have to deal with instance<-schema relation all by yourself (either store it externally or write some hack to retrieve the schema location from the root element of the instance document), you can not validate the document using multiple schemata (say, when each schema governs its own namespace) and so on. So the question is: maybe I am missing something completely trivial or doing it wrong? Or are my statements about lxml's limitations regarding schema validation true? To recap, I'd like to be able to: have the parser use the schema location declarations in the instance document at parse/validation time use multiple schemata to validate a xml document declare schema locations on non-root elements (not of extreme importance) Maybe I should look for a different library? Although, that'd be a real shame, - lxml is a de-facto xml processing library for python and is regarded by everyone as the best one in terms of performace/features/convenience (and rightfully so, to a certain extent)

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  • Preserving CDATA Editing Xml File using Microsoft Word 2003

    - by Samuel
    I have an xml file that I need to edit using Microsoft Word 2003. Everything works fine but the CDATA section is lost and is converted to normal html. For example <Description> <![CDATA[ <i> ]]> </Description> Gets converted to <Description> <i> </Description> Is there any way to preserve the CDATA section while editing in MS Word. I want to fix some typos and grammer in the xml file so I am using this approach. Thanks

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  • FileNotFoundException, although the XML file should be deployed

    - by Bernhard V
    Hi, I've got problems starting my WAR application on a local JBoss. After two other EARs are deployed and the TomcatDeployer begins deploying the WAR, I'm getting the following error message: 2010-04-28 10:01:56,605 ERROR [org.jboss.ejb.plugins.LogInterceptor] [] [main] EJBException in method: public abstract at.sozvers.stp.zpv.ejb.lea.rwsuc.EJBLeaRegelwerkSuchenRemote at.sozvers.stp.zpv.ejb.lea.rwsuc.EJBLeaRegelwerkSuchenHome.create() throws javax.ejb.CreateException,java.rmi.RemoteException, causedBy: javax.ejb.EJBException: org.springframework.beans.factory.access.BootstrapException: Unable to initialize group definition. Group resource name [classpath*:applicationContext.xml], factory key [contextService]; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'contextService' defined in URL [jar:file:/C:/ta30/nutzb/jboss-4.2.3.GA.ZPV/server/default/deploy/deploy.last/zpv-app-web-frontend-1.0-SNAPSHOT.war/WEB-INF/lib/zpv-comp-ejb-modules-1.0-SNAPSHOT-client.jar!/applicationContext.xml]: Instantiation of bean failed; nested exception is org.springframework.beans.BeanInstantiationException: Could not instantiate bean class [org.springframework.context.support.ClassPathXmlApplicationContext]: Constructor threw exception; nested exception is org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from class path resource [at/sozvers/stp/zpv/dao/ContextBasic.xml]; nested exception is java.io.FileNotFoundException: class path resource [at/sozvers/stp/zpv/dao/ContextBasic.xml] cannot be opened because it does not exist The sad thing is that the resource at/sozvers/stp/zpv/dao/ContextBasic.xml actually is placed in a JAR in one of my EAR files which should be deployed before the WAR. And at least I get a message that the deployment of the EAR has been successful. I also looked into the JAR with my file archiver and the ContextBasic.xml is indeed there at the right place. Is there a way for me to get sure that the JAR, not the EAR as a whole, is really deployed to the JBoss? I'm already starting to lose my head about this issue. Thank you. Bernhard

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  • XML Comparison?

    - by CrazyNick
    I got a books.xml file from http://msdn.microsoft.com/en-us/library/ms762271(VS.85).aspx and just saved it with two different names, removed few lines from the second file and tried to compare the files using the below powershell code: clear-host $xml = New-Object XML $xml = [xml](Get-Content D:\SharePoint\Powershell\Comparator\Comparator_Config.xml) $xml.config.compare | ForEach-Object { $strFile1 = get-Content $.source; $strFile2 = get-Content $.destination; $diff  = Compare-Object $strFile1 $strFile2; $result1 = $diff | where {$.SideIndicator -eq "<=" } | select InputObject; $result2 = $diff | where {$.SideIndicator -eq "=" } | select InputObject; Write-host "nEntries are differ in First web.config filen"; $result1 | ForEach-Object {write-host $.InputObject}; Write-host "nEntries are differ in Second web.config filen" ;$result2 | ForEach-Object {write-host $.InputObject}; $.parameters | ForEach-Object { write-host $.parameter } } and it is working perfectly and giving me the below results: Entries are differ in First web.config file < price36.95< /price < descriptionMicrosoft Visual Studio 7 is explored in depth, looking at how Visual Basic, Visual C++, C#, and ASP+ are integrated into a comprehensive development environment.< /description Entries are differ in Second web.config file < price< /price < description< /description however I wan to know the root node of the above mentioned nodes, is that possible to find? if so, how?

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