Search Results

Search found 20264 results on 811 pages for 'xml attribute'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 24/811 | < Previous Page | 20 21 22 23 24 25 26 27 28 29 30 31  | Next Page >

  • Retrieve MS SQL database or table struture in XML

    - by clutch
    Is there a way to export the database schema in well formed XML of a MS 2000 SQL Server. I'm looking for just the structure not the data and the more detailed the better. The XML may be used in a migration processes. I'm more familiar with MySQL then with SQL Server so please be detailed if you hav time. Thanks

    Read the article

  • Search in multiple xml files

    - by Ram
    I have a windows Xp Sp2 system where the windows explorer search is not able to find the text in xml files. Is there some setting that enable the search in xml files? It finds in text in text / doc files in the same folder.

    Read the article

  • Notepad++ Reindent XML breaks lines.

    - by C. Ross
    I'm attempting to use Notepad++ TextFX HTMLTidy - Tidy: Reindent XML. This works well with the following exception. Lines longer than 70 character are wrapped, breaking the validity of my xml. This: <RevieweeDepartmentName>BB AAAAAAAAAA AAAAAAAAAA AAAA</RevieweeDepartmentName> Becomes this: <RevieweeDepartmentName>BB AAAAAAAAAA AAAAAAAAAA AAAA</RevieweeDepartmentName> How can I get it to stop this behavior?

    Read the article

  • Retrieve MS SQL database or table structure in XML

    - by clutch
    Is there a way to export the database schema in well formed XML of a MS 2000 SQL Server. I'm looking for just the structure not the data and the more detailed the better. The XML may be used in a migration processes. I'm more familiar with MySQL then with SQL Server so please be detailed if you have time. Thanks

    Read the article

  • php object : get value of attribute by computed name

    - by groovehunter
    hi simple question - How do I access an attribute of an object by name, if i compute the name at runtime? Ie. i loop over keys and want to get each value of the attributes "field_".$key In python there is getattribute(myobject, attrname) It works, of course, with eval("$val=$myobject-".$myattr.";"); but IMO this is ugly!! TIA florian

    Read the article

  • Scala xhtml attribute breaks because of a question mark

    - by portoalet
    I had a problem with <iframe id="iframe1" src='http://stockcharts.com/h-sc/ui?s=MT&p=D&yr=2&mn=0&dy=0&id=p43321191731' width="300px" height="300px"></iframe> in Lift web framework (Scala) version Message: java.util.NoSuchElementException scala.RandomAccessSeq$$anon$13.next(RandomAccessSeq.scala:165) scala.xml.parsing.MarkupParser$class.normalizeAttributeValue(MarkupParser.scala:1191) It turned out the question mark ? in the iframe src attribute caused this. What can I do to fix this quickly?

    Read the article

  • select attribute mysql

    - by Viet Tran
    I have there mysql table: **product (id,name)** 1 Samsung 2 Toshiba 3 Sony **attribute (id,name,parentid)** 1 Size 0 2 19" 1 3 17" 1 4 15" 1 5 Color 0 6 White 1 7 Black 2 **attribute2product (id,productid,attributeid)** 1 1 2 2 1 6 3 2 2 4 2 7 5 3 3 6 3 7 And listed them like: Size -- 19" (2 product(s)) -- 17" (1 product) -- 15" (0 product) Color -- White (1 product) -- Black (2 product(s)) Please help me to filter product, eg: when I choose the Size 19" (that product id 1 and 2 have), this will display: Size -- 19" Color -- White (1 product) -- Black (1 product) Thanks,

    Read the article

  • get JSON object attribute name

    - by Laurent Luce
    I know that I can retrieve "session" by using item.fields.name but what if I don't know in advance that the attribute is called "name". How can I retrieve the list of the attributes names in fields first. [ { "pk": 2, "model": "auth.group", "fields": { "name": "session" } } ]

    Read the article

  • Should all new web projects build their backend based on xml/json result sets?

    - by Blankman
    If you were building a new Saas project, would it make sense to start with all of the backend services returning xml/json? Because these days you need to build for both the web and mobile devices, and having a backend that is build from the start to return xml and json, you are ready to go mobile (all services have the business logic, so you won't be repeating anything). Now the web would be MVC, so the controller would just be routing the request to your service backend, and converting the json or xml to html. The obviousl downside is that you have to build a backend, and then another web project that calls your backend. But this also goes to you favor as it forces you to seperate your concerns, and not leak business logic in your controller/view layer. Thoughts?

    Read the article

  • Mixing Silverlight-Specific System.Xml.Linq dll with Non-Silverlight System.Xml.Linq dll

    - by programatique
    I have a Logic layer that references Silverlight's System.Xml.Linq dll and a GUI that is in WPF (hence using the non-Silverlight System.Xml.Linq dll). When I attempt to pass an XElement from GUI project to a method in the Logic project, I am getting (basically) "XElement is not of type XElement" errors. To complicate matter, I am unable to edit the Logic layer project. The Non-Silverlight DLL is at: C:\Program Files (x86)\Reference Assemblies\Microsoft\Framework\v3.5\System.Xml.Linq.dll THe Silverlight DLL is at: C:\Program Files (x86)\Microsoft SDKs\Silverlight\v3.0\Libraries\Client\System.Xml.Linq.dll I am new to C# but I'm fairly sure my issue is that I am referencing different DLL's to access the System.Xml.Linq namespace. I attempted to replace my non-Silverlight System.Xml.Linq.dll with the Silverlight's System.Xml.Linq.dll, but received assembly errors. Is there any way to resolve this short of scrapping my WPF GUI project and creating a Silverlight project?

    Read the article

  • Invalid XML in persistence.xml : Init method

    - by James.Elsey
    I'm getting the following error when I try to startup my application on google app engine: Failed startup of context com.google.apphosting.utils.jetty.RuntimeAppEngineWebAppContext@8fcc7b{/,/base/data/home/apps/sales-tracker/3.340980411948080671} org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'clientDao' defined in ServletContext resource [/WEB-INF/applicationContext.xml]: Cannot resolve reference to bean 'entityManagerFactory' while setting bean property 'entityManagerFactory'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in ServletContext resource [/WEB-INF/applicationContext.xml]: Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Invalid XML in persistence unit from URL [file:/base/data/home/apps/sales-tracker/3.340980411948080671/WEB-INF/classes/META-INF/persistence.xml] at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveReference(BeanDefinitionValueResolver.java:275) at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveValueIfNecessary(BeanDefinitionValueResolver.java:104) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.applyPropertyValues(AbstractAutowireCapableBeanFactory.java:1245) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.populateBean(AbstractAutowireCapableBeanFactory.java:1010) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:472) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory$1.run(AbstractAutowireCapableBeanFactory.java:409) at java.security.AccessController.doPrivileged(Native Method) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:380) at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:264) at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:261) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:185) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:164) at org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:429) at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:728) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:380) at org.springframework.web.context.ContextLoader.createWebApplicationContext(ContextLoader.java:255) at org.springframework.web.context.ContextLoader.initWebApplicationContext(ContextLoader.java:199) at org.springframework.web.context.ContextLoaderListener.contextInitialized(ContextLoaderListener.java:45) at org.mortbay.jetty.handler.ContextHandler.startContext(ContextHandler.java:548) at org.mortbay.jetty.servlet.Context.startContext(Context.java:136) at org.mortbay.jetty.webapp.WebAppContext.startContext(WebAppContext.java:1250) at org.mortbay.jetty.handler.ContextHandler.doStart(ContextHandler.java:517) at org.mortbay.jetty.webapp.WebAppContext.doStart(WebAppContext.java:467) at org.mortbay.component.AbstractLifeCycle.start(AbstractLifeCycle.java:50) at com.google.apphosting.runtime.jetty.AppVersionHandlerMap.createHandler(AppVersionHandlerMap.java:191) at com.google.apphosting.runtime.jetty.AppVersionHandlerMap.getHandler(AppVersionHandlerMap.java:168) at com.google.apphosting.runtime.jetty.JettyServletEngineAdapter.serviceRequest(JettyServletEngineAdapter.java:123) at com.google.apphosting.runtime.JavaRuntime.handleRequest(JavaRuntime.java:243) at com.google.apphosting.base.RuntimePb$EvaluationRuntime$6.handleBlockingRequest(RuntimePb.java:5485) at com.google.apphosting.base.RuntimePb$EvaluationRuntime$6.handleBlockingRequest(RuntimePb.java:5483) at com.google.net.rpc.impl.BlockingApplicationHandler.handleRequest(BlockingApplicationHandler.java:24) at com.google.net.rpc.impl.RpcUtil.runRpcInApplication(RpcUtil.java:398) at com.google.net.rpc.impl.Server$2.run(Server.java:852) at com.google.tracing.LocalTraceSpanRunnable.run(LocalTraceSpanRunnable.java:56) at com.google.tracing.LocalTraceSpanBuilder.internalContinueSpan(LocalTraceSpanBuilder.java:536) at com.google.net.rpc.impl.Server.startRpc(Server.java:807) at com.google.net.rpc.impl.Server.processRequest(Server.java:369) at com.google.net.rpc.impl.ServerConnection.messageReceived(ServerConnection.java:442) at com.google.net.rpc.impl.RpcConnection.parseMessages(RpcConnection.java:319) at com.google.net.rpc.impl.RpcConnection.dataReceived(RpcConnection.java:290) at com.google.net.async.Connection.handleReadEvent(Connection.java:474) at com.google.net.async.EventDispatcher.processNetworkEvents(EventDispatcher.java:831) at com.google.net.async.EventDispatcher.internalLoop(EventDispatcher.java:207) at com.google.net.async.EventDispatcher.loop(EventDispatcher.java:103) at com.google.net.rpc.RpcService.runUntilServerShutdown(RpcService.java:251) at com.google.apphosting.runtime.JavaRuntime$RpcRunnable.run(JavaRuntime.java:404) at java.lang.Thread.run(Unknown Source) Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in ServletContext resource [/WEB-INF/applicationContext.xml]: Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Invalid XML in persistence unit from URL [file:/base/data/home/apps/sales-tracker/3.340980411948080671/WEB-INF/classes/META-INF/persistence.xml] at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1338) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:473) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory$1.run(AbstractAutowireCapableBeanFactory.java:409) at java.security.AccessController.doPrivileged(Native Method) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:380) at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:264) at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:261) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:185) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:164) at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveReference(BeanDefinitionValueResolver.java:269) ... 47 more Caused by: java.lang.IllegalArgumentException: Invalid XML in persistence unit from URL [file:/base/data/home/apps/sales-tracker/3.340980411948080671/WEB-INF/classes/META-INF/persistence.xml] at org.springframework.orm.jpa.persistenceunit.PersistenceUnitReader.readPersistenceUnitInfos(PersistenceUnitReader.java:151) at org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager.readPersistenceUnitInfos(DefaultPersistenceUnitManager.java:303) at org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager.preparePersistenceUnitInfos(DefaultPersistenceUnitManager.java:275) at org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager.afterPropertiesSet(DefaultPersistenceUnitManager.java:260) at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:192) at org.springframework.orm.jpa.AbstractEnti My persistence.xml looks as follows, as taken from the GAE documentation <?xml version="1.0" encoding="UTF-8" ?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"version="1.0"> <persistence-unit name="transactions-optional"> <provider>org.datanucleus.store.appengine.jpa.DatastorePersistenceProvider</provider> <properties> <property name="datanucleus.NontransactionalRead" value="true" /> <property name="datanucleus.NontransactionalWrite" value="true" /> <property name="datanucleus.ConnectionURL" value="appengine" /> </properties> </persistence-unit> </persistence> Is there something wrong with my persistence file? Or could my errors be caused elsewhere? Can someone please give me some pointers thanks

    Read the article

  • Parsing XML using xml.etree.cElementTree

    - by Andre
    I have the following XML in a string named 'xml': <?xml version="1.0" encoding="ISO-8859-1"?> <Book> <Page> <Text>Blah</Text> </Page> </Book> I'm trying to get the value Blah out of it but I'm having trouble with xml.etree.cElementTree. I've tried the find() and findtext() methods but nothing. Eventually I did this: import xml.etree.cElementTree as ET ... root = ET.fromstring(xml) element = root.getchildren()[0].getchildren()[0] Element now equals the element, which is what I want (for this solution anyway), but how do I get the inner text from it? element.text does not work. Any ideas? PS: I am using Python 2.5 atm. As an extra question: what is a better way to parse xml strings in python?

    Read the article

  • find xml element by attribute

    - by Moudy
    Using JQuery or Javascript how would I return 'Mary Boone' from the xml below starting out with the show 'id' attribute of '2'? I'm thinking something along the lines of - var result = xml.getElementByAttribute("2").gallery.text(); the XML: <shows> <show id="1"> <artist>Andreas Gursky</artist> <gallery>Matthew Marks</gallery> <medium>photography</medium> </show> <show id="2"> <artist>Eric Fischl</artist> <gallery>Mary Boone</gallery> <medium>painting</medium> </show> </shows>

    Read the article

  • Getting started with XSD validation with C#

    - by Rosarch
    Here is my first attempt at validating XML with XSD. The XML file to be validated: <?xml version="1.0" encoding="utf-8" ?> <config xmlns="Schemas" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="config.xsd"> <levelVariant> <filePath>SampleVariant</filePath> </levelVariant> <levelVariant> <filePath>LegendaryMode</filePath> </levelVariant> <levelVariant> <filePath>AmazingMode</filePath> </levelVariant> </config> The XSD, located in "Schemas/config.xsd" relative to the XML file to be validated: <?xml version="1.0" encoding="utf-8" ?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified"> <xs:element name="config"> <xs:complexType> <xs:sequence> <xs:element name="levelVariant"> <xs:complexType> <xs:sequence> <xs:element name="filePath" type="xs:anyURI"> </xs:element> </xs:sequence> </xs:complexType> </xs:element> </xs:sequence> </xs:complexType> </xs:element> </xs:schema> Right now, I just want to validate the XML file precisely as it appears currently. Once I understand this better, I'll expand more. Do I really need so many lines for something as simple as the XML file as it currently exists? The validation code in C#: public void SetURI(string uri) { XElement toValidate = XElement.Load(Path.Combine(PATH_TO_DATA_DIR, uri) + ".xml"); // begin confusion string schemaURI = toValidate.Attributes("xmlns").First().ToString() + toValidate.Attributes("xsi:noNamespaceSchemaLocation").First().ToString(); XmlSchemaSet schemas = new XmlSchemaSet(); schemas.Add("", XmlReader.Create( SOMETHING )); XDocument toValidateDoc = new XDocument(toValidate); toValidateDoc.Validate(schemas, null); // end confusion root = toValidate; } Any illumination would be appreciated.

    Read the article

  • Getting started with XSD validation with .NET

    - by Rosarch
    Here is my first attempt at validating XML with XSD. The XML file to be validated: <?xml version="1.0" encoding="utf-8" ?> <config xmlns="Schemas" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="config.xsd"> <levelVariant> <filePath>SampleVariant</filePath> </levelVariant> <levelVariant> <filePath>LegendaryMode</filePath> </levelVariant> <levelVariant> <filePath>AmazingMode</filePath> </levelVariant> </config> The XSD, located in "Schemas/config.xsd" relative to the XML file to be validated: <?xml version="1.0" encoding="utf-8" ?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified"> <xs:element name="config"> <xs:complexType> <xs:sequence> <xs:element name="levelVariant"> <xs:complexType> <xs:sequence> <xs:element name="filePath" type="xs:anyURI"> </xs:element> </xs:sequence> </xs:complexType> </xs:element> </xs:sequence> </xs:complexType> </xs:element> </xs:schema> Right now, I just want to validate the XML file precisely as it appears currently. Once I understand this better, I'll expand more. Do I really need so many lines for something as simple as the XML file as it currently exists? The validation code in C#: public void SetURI(string uri) { XElement toValidate = XElement.Load(Path.Combine(PATH_TO_DATA_DIR, uri) + ".xml"); // begin confusion // exception here string schemaURI = toValidate.Attributes("xmlns").First().ToString() + toValidate.Attributes("xsi:noNamespaceSchemaLocation").First().ToString(); XmlSchemaSet schemas = new XmlSchemaSet(); schemas.Add(null, schemaURI); XDocument toValidateDoc = new XDocument(toValidate); toValidateDoc.Validate(schemas, null); // end confusion root = toValidate; } Running the above code gives this exception: The ':' character, hexadecimal value 0x3A, cannot be included in a name. Any illumination would be appreciated.

    Read the article

  • Querying Visual Studio project files using T-SQL and Powershell

    - by jamiet
    Earlier today I had a need to get some information out of a Visual Studio project file and in this blog post I’m going to share a couple of ways of going about that because I’m pretty sure I won’t be the only person that ever wants to do this. The specific problem I was trying to solve was finding out how many objects in my database project (i.e. in my .dbproj file) had any warnings suppressed but the techniques discussed below will work pretty well for any Visual Studio project file because every such file is simply an XML document, hence it can be queried by anything that can query XML documents. Ever heard the phrase “when all you’ve got is hammer everything looks like a nail”? Well that’s me with querying stuff – if I can write SQL then I’m writing SQL. Here’s a little noddy database project I put together for demo purposes: Two views and a stored procedure, nothing fancy. I suppressed warnings for [View1] & [Procedure1] and hence the pertinent part my project file looks like this:   <ItemGroup>    <Build Include="Schema Objects\Schemas\dbo\Views\View1.view.sql">      <SubType>Code</SubType>      <SuppressWarnings>4151,3276</SuppressWarnings>    </Build>    <Build Include="Schema Objects\Schemas\dbo\Views\View2.view.sql">      <SubType>Code</SubType>    </Build>    <Build Include="Schema Objects\Schemas\dbo\Programmability\Stored Procedures\Procedure1.proc.sql">      <SubType>Code</SubType>      <SuppressWarnings>4151</SuppressWarnings>    </Build>  </ItemGroup>  <ItemGroup> Note the <SuppressWarnings> elements – those are the bits of information that I am after. With a lot of help from folks on the SQL Server XML forum  I came up with the following query that nailed what I was after. It reads the contents of the .dbproj file into a variable of type XML and then shreds it using T-SQL’s XML data type methods: DECLARE @xml XML; SELECT @xml = CAST(pkgblob.BulkColumn AS XML) FROM   OPENROWSET(BULK 'C:\temp\QueryingProjectFileDemo\QueryingProjectFileDemo.dbproj' -- <-Change this path!                    ,single_blob) AS pkgblob                    ;WITH XMLNAMESPACES( 'http://schemas.microsoft.com/developer/msbuild/2003' AS ns) SELECT  REVERSE(SUBSTRING(REVERSE(ObjectPath),0,CHARINDEX('\',REVERSE(ObjectPath)))) AS [ObjectName]        ,[SuppressedWarnings] FROM   (        SELECT  build.query('.') AS [_node]        ,       build.value('ns:SuppressWarnings[1]','nvarchar(100)') AS [SuppressedWarnings]        ,       build.value('@Include','nvarchar(1000)') AS [ObjectPath]        FROM    @xml.nodes('//ns:Build[ns:SuppressWarnings]') AS R(build)        )q And here’s the output: And that’s it – an easy way of discovering which warnings have been suppressed and for which objects in your database projects. I won’t bother going over the code as it is fairly self-explanatory – peruse it at your leisure.   Once I had the SQL above I figured I’d share it around a little in case it was ever useful to anyone else; hence I’m writing this blog post and I also posted it on the Visual Studio Database Development Tools forum at FYI: Discover which objects have had warnings suppressed. Luckily Kevin Goode saw the thread and he posted a different solution to the same problem, one that uses Powershell. The advantage of Kevin’s Powershell approach is that it is easy to analyse many .dbproj files at the same time. Below is Kevin’s code which I have tweaked ever so slightly so that it produces the same results as my SQL script (I just want any object that had had a warning suppressed whereas Kevin was querying specifically for warning 4151):   cd 'C:\Temp\QueryingProjectFileDemo\' cls $projects = ls -r -i *.dbproj Foreach($project in $projects) { $xml = new-object System.Xml.XmlDocument $xml.set_PreserveWhiteSpace( $true ) $xml.Load($project) #$xpath = @{Start="/e:Project/e:ItemGroup/e:Build[e:SuppressWarnings=4151]/@Include"} #$xpath = @{Start="/e:Project/e:ItemGroup/e:Build[contains(e:SuppressWarnings,'4151')]/@Include"} $xpath = @{Start="/e:Project/e:ItemGroup/e:Build[e:SuppressWarnings]/@Include"} $ns = @{ e = "http://schemas.microsoft.com/developer/msbuild/2003" } $xml | Select-Xml -XPath $xpath.Start -Namespace $ns |Select -Expand Node | Select -expand Value } and here’s the output: Nice reusable Powershell and SQL scripts – not bad for an evening’s work. Thank you to Kevin for allowing me to share his code. Don’t forget that these techniques can easily be adapted to query any Visual Studio project file, they’re only XML documents after all! Doubtless many people out there already have code for doing this but nonetheless here is another offering to the great script library in the sky. Have fun! @Jamiet

    Read the article

  • XmlWriter and lower ASCII characters

    - by Rick Strahl
    Ran into an interesting problem today on my CodePaste.net site: The main RSS and ATOM feeds on the site were broken because one code snippet on the site contained a lower ASCII character (CHR(3)). I don't think this was done on purpose but it was enough to make the feeds fail. After quite a bit of debugging and throwing in a custom error handler into my actual feed generation code that just spit out the raw error instead of running it through the ASP.NET MVC and my own error pipeline I found the actual error. The lovely base exception and error trace I got looked like this: Error: '', hexadecimal value 0x03, is an invalid character. at System.Xml.XmlUtf8RawTextWriter.InvalidXmlChar(Int32 ch, Byte* pDst, Boolean entitize)at System.Xml.XmlUtf8RawTextWriter.WriteElementTextBlock(Char* pSrc, Char* pSrcEnd)at System.Xml.XmlUtf8RawTextWriter.WriteString(String text)at System.Xml.XmlWellFormedWriter.WriteString(String text)at System.Xml.XmlWriter.WriteElementString(String localName, String ns, String value)at System.ServiceModel.Syndication.Rss20FeedFormatter.WriteItemContents(XmlWriter writer, SyndicationItem item, Uri feedBaseUri)at System.ServiceModel.Syndication.Rss20FeedFormatter.WriteItem(XmlWriter writer, SyndicationItem item, Uri feedBaseUri)at System.ServiceModel.Syndication.Rss20FeedFormatter.WriteItems(XmlWriter writer, IEnumerable`1 items, Uri feedBaseUri)at System.ServiceModel.Syndication.Rss20FeedFormatter.WriteFeed(XmlWriter writer)at System.ServiceModel.Syndication.Rss20FeedFormatter.WriteTo(XmlWriter writer)at CodePasteMvc.Controllers.ApiControllerBase.GetFeed(Object instance) in C:\Projects2010\CodePaste\CodePasteMvc\Controllers\ApiControllerBase.cs:line 131 XML doesn't like extended ASCII Characters It turns out the issue is that XML in general does not deal well with lower ASCII characters. According to the XML spec it looks like any characters below 0x09 are invalid. If you generate an XML document in .NET with an embedded &#x3; entity (as mine did to create the error above), you tend to get an XML document error when displaying it in a viewer. For example, here's what the result of my  feed output looks like with the invalid character embedded inside of Chrome which displays RSS feeds as raw XML by default: Other browsers show similar error messages. The nice thing about Chrome is that you can actually view source and jump down to see the line that causes the error which allowed me to track down the actual message that failed. If you create an XML document that contains a 0x03 character the XML writer fails outright with the error: '', hexadecimal value 0x03, is an invalid character. The good news is that this behavior is overridable so XML output can at least be created by using the XmlSettings object when configuring the XmlWriter instance. In my RSS configuration code this looks something like this:MemoryStream ms = new MemoryStream(); var settings = new XmlWriterSettings() { CheckCharacters = false }; XmlWriter writer = XmlWriter.Create(ms,settings); and voila the feed now generates. Now generally this is probably NOT a good idea, because as mentioned above these characters are illegal and if you view a raw XML document you'll get validation errors. Luckily though most RSS feed readers however don't care and happily accept and display the feed correctly, which is good because it got me over an embarrassing hump until I figured out a better solution. How to handle extended Characters? I was glad to get the feed fixed for the time being, but now I was still stuck with an interesting dilemma. CodePaste.net accepts user input for code snippets and those code snippets can contain just about anything. This means that ASP.NET's standard request filtering cannot be applied to this content. The code content displayed is encoded before display so for the HTML end the CHR(3) input is not really an issue. While invisible characters are hardly useful in user input it's not uncommon that odd characters show up in code snippets. You know the old fat fingering that happens when you're in the middle of a coding session and those invisible characters do end up sometimes in code editors and then end up pasted into the HTML textbox for pasting as a Codepaste.net snippet. The question is how to filter this text? Looking back at the XML Charset Spec it looks like all characters below 0x20 (space) except for 0x09 (tab), 0x0A (LF), 0x0D (CR) are illegal. So applying the following filter with a RegEx should work to remove invalid characters:string code = Regex.Replace(item.Code, @"[\u0000-\u0008,\u000B,\u000C,\u000E-\u001F]", ""); Applying this RegEx to the code snippet (and title) eliminates the problems and the feed renders cleanly.© Rick Strahl, West Wind Technologies, 2005-2012Posted in .NET  XML   Tweet !function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0];if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src="//platform.twitter.com/widgets.js";fjs.parentNode.insertBefore(js,fjs);}}(document,"script","twitter-wjs"); (function() { var po = document.createElement('script'); po.type = 'text/javascript'; po.async = true; po.src = 'https://apis.google.com/js/plusone.js'; var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(po, s); })();

    Read the article

  • XML DATATYPE (series 1)

    New to SQL Server 2005, is The XML data type, which lets you store XML documents and fragments in a SQL Server database. An XML fragment is an XML instance that is missing a single top-level element. You can create columns and variables of the XML type and store XML instances in them. Note that the stored representation of XML data type instances cannot exceed 2 GB.

    Read the article

  • Utility to LOGICALLY compare two xml files?

    - by Matthew
    Right now we are attempting to build golden configurations for our environment. One piece of software that we use relies on large XML files to contain the bulk of its configuration. We want tot ake our lab environment, catalog it as our "golden configuration" and then be able to audit against that configuration in the future. Since diff is bytewise comparison and NOT logical comparison, we can't use it to compare files in this case (XML is unordered, so it won't work). What I am looking for is something that can parse the two XML files, and compare them element by element. So far we have yet to find any utilities that can do this. OS doesn't matter, I can do it on anything where it will work. The preference is something off the shelf. Any ideas? Edit: One issue we have run into is one vendor's config files will occasionally mention the same element several times, each time with different attributes. Whatever diff utility we use would need to be able to identify either the set of attributes or identify them all as part of one element. Tall order :)

    Read the article

  • Nmap XML parsing with Powershell

    - by Craig620
    I am trying to parse the XML output from NMAP and isolate just the hostadddress and the vendor from the osmatch. I've actually done that with the following: select-xml -path nmap.xml -xpath "nmaprun/host/address/@addr|nmaprun/host/os/osmatch/osclass/@vendor" | select -expandproperty node Which produces: #text ----- 10.20.30.1 HP 10.20.30.2 Linux 10.20.30.3 HP What I was not expecting is that it would jam it all into a single column.Silly me would like the address in one column, and the vendor in another column. I Would like: #addr #vendor ----- ------- 10.20.30.1 HP 10.20.30.2 Linux 10.20.30.3 HP In the several hours I spent learning xpath today, I also realized that this file has a single address for each host, but multiple OS guesses for each host. I would also like to use only the first osGuess in the output. Tired using: -xpath "(nmaprun/host/os/osmatch/osclass/@vendor)[1]" But that truncates the whole data set to a single line of output, instead of only limiting the only the first osclass element of each host. Changing the parens to surround only the @vendor element like .../(@vendor)[1] and .../(@vendor[1]) but both fail with "Expression must evaluate to a node-set." Thanks in advance

    Read the article

  • WCF: VS2010 confuses system.xml.xmlelement with system.xml.linq.xelement?

    - by Chau
    I have created a WCF service with one method which returns a System.Xml.XmlElement: using System.Xml; ... public XmlElement Execute(...) { XmlNode node = ...; return (XmlElement)node; } When I try to access the service deployed on my server WCFServiceClient service = new WCFServiceClient("WSHttpBinding_IWCFService"); XmlElement node = service.Execute(...); I get the error: Cannot implicitly convert type 'System.Xml.Linq.XElement' to 'System.Xml.XmlElement' Searching my service solution, I cannot see any reference to System.Xml.Linq.XElement. Is it wrong of me to expect a System.Xml.Xmlelement or is VS 2010 fooling around with me? Thanks in advance.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 20 21 22 23 24 25 26 27 28 29 30 31  | Next Page >