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  • How do I use Content.Load() with raw XML files?

    - by xnanewb
    I'm using the Content.Load() mechanism to load core game definitions from XML files. It works fine, though some definitions should be editable/moddable by the players. Since the content pipeline compiles everything into xnb files, that doesn't work for now. I've seen that the inbuild XNA Song content processor does create 2 files. 1 xnb file which contains meta data for the song and 1 wma file which contains the actual data. I've tried to rebuild that mechanism (so that the second file is the actual xml file), but for some reason I can't use the namespace which contains the IntermediateSerializer class to load the xml (obviously the namespace is only available in a content project?). How can I deploy raw, editable xml files and load them with Content.Load()?

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  • Using Simple XML and getting NoClassDefFoundError in Android

    - by Berat Onur Ersen
    I'm trying to use Simple XML to convert my java objects to XML format in my Android application. I'm getting NoClassDefFoundError at line Serializer serializer = new Persister(); java.lang.NoClassDefFoundError: org.simpleframework.xml.core.Persister I have simple-xml-2.6.1.jar in project class path and when I got NoClassDefFoundError I also put these 3 jars in classpath stax-1.2.0.jar stax-api-1.0.1.jar xpp3-1.1.3_8.jar but made no use. Still having NoClassDefFoundError. Any kind of help will be appreciated.Thank you.

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  • Serialize .Net object to json, controlled using xml attributes

    - by sprocketonline
    I have a .Net object which I've been serializing to Xml and is decorated with Xml attributes. I would now like to serialize the same object to Json, preferably using the Newtonsoft Json.Net library. I'd like to go directly from the .Net object in memory to a Json string (without serializing to Xml first). I do not wish to add any Json attributes to the class, but instead would like for the Json serializer use the existing Xml attributes. [XmlRoot("hello")] public class world{ [XmlIgnore] public int ignoreMe{ get; } [XmlElement("foo")] public int bar{ get; } [XmlElement("marco")] public int polo{ get; } } becomes "hello":{ "foo":0, "marco":0 }

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  • WCF contracts - namespaces and SerializationExceptions

    - by qntmfred
    I am using a third party web service that offers the following calls and responses http://api.athirdparty.com/rest/foo?apikey=1234 <response> <foo>this is a foo</foo> </response> and http://api.athirdparty.com/rest/bar?apikey=1234 <response> <bar>this is a bar</bar> </response> This is the contract and supporting types I wrote [ServiceContract] [XmlSerializerFormat] public interface IFooBarService { [OperationContract] [WebGet( BodyStyle = WebMessageBodyStyle.Bare, ResponseFormat = WebMessageFormat.Xml, UriTemplate = "foo?key={apikey}")] FooResponse GetFoo(string apikey); [OperationContract] [WebGet( BodyStyle = WebMessageBodyStyle.Bare, ResponseFormat = WebMessageFormat.Xml, UriTemplate = "bar?key={apikey}")] BarResponse GetBar(string apikey); } [XmlRoot("response")] public class FooResponse { [XmlElement("foo")] public string Foo { get; set; } } [XmlRoot("response")] public class BarResponse { [XmlElement("bar")] public string Bar { get; set; } } and then my client looks like this static void Main(string[] args) { using (WebChannelFactory<IFooBarService> cf = new WebChannelFactory<IFooBarService>("thirdparty")) { var channel = cf.CreateChannel(); FooResponse result = channel.GetFoo("1234"); } } When I run this I get the following exception Unable to deserialize XML body with root name 'response' and root namespace '' (for operation 'GetFoo' and contract ('IFooBarService', 'http://tempuri.org/')) using XmlSerializer. Ensure that the type corresponding to the XML is added to the known types collection of the service. If I comment out the GetBar operation from IFooBarService, it works fine. I know I'm missing an important concept here - just don't know quite what to look for. What is the proper way to construct my contract types, so that they can be properly deserialized?

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  • Getting an invalidoperationexception when deserialising XML

    - by Paul Johnson
    Hi, I'm writing a simple proof of concept application to load up an XML file and depending on the very simple code, create a window and put something into it (it's for a much larger project). Due to limitations in Mono, I'm having to run in this way. The code I currently have looks like this using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Windows.Forms; using System.IO; using System.Collections; using System.Xml; using System.Xml.Serialization; namespace form_from_xml { public class xmlhandler : Form { public void loaddesign() { FormData f; f = null; try { string path_env = Path.GetDirectoryName(Application.ExecutablePath) + Path.DirectorySeparatorChar; // code dies on the line below XmlSerializer s = new XmlSerializer(typeof(FormData)); TextReader r = new StreamReader(path_env + "designer-test.xml"); f = (FormData)s.Deserialize(r); r.Close(); } catch (System.IO.FileNotFoundException) { MessageBox.Show("Unable to find the form file", "File not found", MessageBoxButtons.OK); } } } [XmlRoot("Forms")] public class FormData { private ArrayList formData; public FormData() { formData = new ArrayList(); } [XmlElement("Element")] public Elements[] elements { get { Elements[] elements = new Elements[formData.Count]; formData.CopyTo(elements); return elements; } set { if (value == null) return; Elements[] elements = (Elements[])value; formData.Clear(); foreach (Elements element in elements) formData.Add(element); } } public int AddItem(Elements element) { return formData.Add(element); } } public class Elements { [XmlAttribute("formname")] public string name; [XmlAttribute("winxsize")] public int winxs; [XmlAttribute("winysize")] public int winys; [XmlAttribute("type")] public object type; [XmlAttribute("xpos")] public int xpos; [XmlAttribute("ypos")] public int ypos; [XmlAttribute("externaldata")] public bool external; [XmlAttribute("externalplace")] public string externalplace; [XmlAttribute("text")] public string text; [XmlAttribute("questions")] public bool questions; [XmlAttribute("questiontype")] public object qtype; [XmlAttribute("numberqs")] public int numberqs; [XmlAttribute("answerfile")] public string ansfile; [XmlAttribute("backlink")] public int backlink; [XmlAttribute("forwardlink")] public int forwardlink; public Elements() { } public Elements(string fn, int wx, int wy, object t, int x, int y, bool ext, string extpl, string te, bool q, object qt, int num, string ans, int back, int end) { name = fn; winxs = wx; winys = wy; type = t; xpos = x; ypos = y; external = ext; externalplace = extpl; text = te; questions = q; qtype = qt; numberqs = num; ansfile = ans; backlink = back; forwardlink = end; } } } With a very simple xmlhandler xml = new xmlhander(); xml.loaddesign(); attached to a winform button. Everything is in the same namespace and the xml file actually exists. This is annoying me now - can anyone spot the error of my ways? Paul

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  • Sorting the output from XmlSerializer in C#

    - by prosseek
    In this post, I could get an XML file generated based on C# class. Can I reorder the XML elements based on its element? My code uses var ser = new XmlSerializer(typeof(Module)); ser.Serialize(WriteFileStream, report, ns); WriteFileStream.Close(); to get the XML file, but I need to have the XML file sorted based on a BlocksCovered variable. public class ClassInfo { public string ClassName; public int BlocksCovered; public int BlocksNotCovered; public double CoverageRate; public ClassInfo() {} public ClassInfo(string ClassName, int BlocksCovered, int BlocksNotCovered, double CoverageRate) { this.ClassName = ClassName; this.BlocksCovered = BlocksCovered; this.BlocksNotCovered = BlocksNotCovered; this.CoverageRate = CoverageRate; } } [XmlRoot("Module")] public class Module { [XmlElement("Class")] public List<ClassInfo> ClassInfoList; public int BlocksCovered; public int BlocksNotCovered; public string moduleName; public Module() { ClassInfoList = new List<ClassInfo>(); BlocksCovered = 0; BlocksNotCovered = 0; moduleName = ""; } } Module report = new Module(); ... TextWriter WriteFileStream = new StreamWriter(xmlFileName); XmlSerializerNamespaces ns = new XmlSerializerNamespaces(); ns.Add("", ""); var ser = new XmlSerializer(typeof(Module)); ser.Serialize(WriteFileStream, report, ns); WriteFileStream.Close();

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  • Using LINQ to XML, how can I join two sets of data based on ordinal position?

    - by Donald Hughes
    Using LINQ to XML, how can I join two sets of data based on ordinal position? <document> <set1> <value>A</value> <value>B</value> <value>C</value> </set1> <set2> <value>1</value> <value>2</value> <value>3</value> </set2> </document> Based on the above fragment, I would like to join the two sets together such that "A" and "1" are in the same record, "B" and "2" are in the same record, and "C" and "3" are in the same record.

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  • How to deserialize null array to null in c#?

    - by Aen Sidhe
    Here is my class: public class Command { [XmlArray(IsNullable = true)] public List<Parameter> To { get; set; } } When I serialize an object of this class: var s = new XmlSerializer(typeof(Command)); s.Serialize(Console.Out, new Command()); it prints as expected (xml header and default MS namespaces are omitted): <Command><To xsi:nil="true" /></Command> When I took this xml and tried to deserialize it I got stucked, because it always print "Not null": var t = s.Deserialize(...); if (t.To == null) Console.WriteLine("Null"); else Console.WriteLine("Not null"); How to force deserializer to make my list null, if it is null in xml?

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  • Cannot validate xml doc againest a xsd schema (Cannot find the declaration of element 'replyMessage

    - by Daziplqa
    Hi Guyz, I am using the following code to validate an an XML file against a XSD schema package com.forat.xsd; import java.io.IOException; import java.net.URL; import javax.xml.XMLConstants; import javax.xml.transform.Source; import javax.xml.transform.stream.StreamSource; import javax.xml.validation.Schema; import javax.xml.validation.SchemaFactory; import javax.xml.validation.Validator; import org.xml.sax.ErrorHandler; import org.xml.sax.SAXException; import org.xml.sax.SAXParseException; public class XSDValidate { public void validate(String xmlFile, String xsd_url) { try { SchemaFactory factory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI); Schema schema = factory.newSchema(new URL(xsd_url)); Validator validator = schema.newValidator(); ValidationHandler handler = new ValidationHandler(); validator.setErrorHandler(handler); validator.validate(getSource(xmlFile)); if (handler.errorsFound == true) { System.err.println("Validation Error : "+ handler.exception.getMessage()); }else { System.out.println("DONE"); } } catch (SAXException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } } private Source getSource(String resource) { return new StreamSource(XSDValidate.class.getClassLoader().getResourceAsStream(resource)); } private class ValidationHandler implements ErrorHandler { private boolean errorsFound = false; private SAXParseException exception; public void error(SAXParseException exception) throws SAXException { this.errorsFound = true; this.exception = exception; } public void fatalError(SAXParseException exception) throws SAXException { this.errorsFound = true; this.exception = exception; } public void warning(SAXParseException exception) throws SAXException { } } /* * Test */ public static void main(String[] args) { new XSDValidate().validate("com/forat/xsd/reply.xml", "https://ics2wstest.ic3.com/commerce/1.x/transactionProcessor/CyberSourceTransaction_1.53.xsd"); // return error } } As appears, It is a standard code that try to validate the following XML file: <?xml version="1.0" encoding="UTF-8"?> <replyMessage xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <merchantReferenceCode>XXXXXXXXXXXXX</merchantReferenceCode> <requestID>XXXXXXXXXXXXX</requestID> <decision>XXXXXXXXXXXXX</decision> <reasonCode>XXXXXXXXXXXXX</reasonCode> <requestToken>XXXXXXXXXXXXX </requestToken> <purchaseTotals> <currency>XXXXXXXXXXXXX</currency> </purchaseTotals> <ccAuthReply> <reasonCode>XXXXXXXXXXXXX</reasonCode> <amount>XXXXXXXXXXXXX</amount> <authorizationCode>XXXXXXXXXXXXX</authorizationCode> <avsCode>XXXXXXXXXXXXX</avsCode> <avsCodeRaw>XXXXXXXXXXXXX</avsCodeRaw> <authorizedDateTime>XXXXXXXXXXXXX</authorizedDateTime> <processorResponse>0XXXXXXXXXXXXX</processorResponse> <authRecord>XXXXXXXXXXXXX </authRecord> </ccAuthReply> </replyMessage> Against the following XSD : https://ics2wstest.ic3.com/commerce/1.x/transactionProcessor/CyberSourceTransaction_1.53.xsd The error is : Validation Error : cvc-elt.1: Cannot find the declaration of element 'replyMessage'. Could you please help me!

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  • .NET and XML: How can I read nested namespaces (<abc:xyz:name attr="value"/>)?

    - by Entrase
    Suppose there is an element in XML data: <abc:xyz:name attr="value"/> I'm trying to read it with XmlReader. The problem is that I get XmlException that says The ‘:’ character, hexadecimal value 0x3A, cannot be included in a name I have already declared "abc" namespace. I have also tried adding "abc:xyz" and "xyz" namespaces. But this doesn't help at all. I could replace some text before parsing but there may be some more elegant solution. So what should I do? Here is my code: XmlReaderSettings settings = new XmlReaderSettings() NameTable nt = new NameTable(); XmlNamespaceManager nsmgr = new XmlNamespaceManager(nt); nsmgr.AddNamespace("abc", ""); nsmgr.AddNamespace("xyz", ""); XmlParserContext context = new XmlParserContext(null, nsmgr, null, XmlSpace.None); // So this reader can't read <abc:xyz:name attr="value"/> XmlReader reader = XmlReader.Create(path, settings, context);“

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  • Using XSD file in VS2005

    - by xt_20
    Hello all I want to write an XML file. I have created an XSD file named XMLSchema.xsd, and run the command 'xsd /c XMLSchema.xsd' which generated a c# class file. Now, how do I use this file to generate XML files? Part of my code: <?xml version="1.0" encoding="utf-8"?> <xs:schema id="XMLSchema" targetNamespace="http://tempuri.org/XMLSchema.xsd" elementFormDefault="qualified" xmlns="http://tempuri.org/XMLSchema.xsd" > <xs:element name="root"> <xs:complexType> <xs:sequence> <xs:element name="Audit"> <xs:complexType> ... which generates a c# class 'root'. How do I call 'root' from my C# web program? Thanks

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  • Deleting xml file using radio value

    - by ???? ???
    i using php to delete file, but i got table loop like this: <table border="0" width="100%" cellpadding="0" cellspacing="0" id="product-table"> <tr class="bg_tableheader"> <th class="table-header-check"><a id="toggle-all" ></a> </th> <th class="table-header-check"><a href="#"><font color="white">Username</font></a> </th> <th class="table-header-check"><a href="#"><font color="white">First Name</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Last Name</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Email</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Group</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Birthday</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Gender</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Age</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Country</font></a></th> </tr> <?php $files = glob('users/*.xml'); foreach($files as $file){ $xml = new SimpleXMLElement($file, 0, true); echo ' <tr> <td></td> <form action="" method="post"> <td class="alternate-row1"><input type="radio" name="file_name" value="'. basename($file, '.xml') .'" />'. basename($file, '.xml') .'</td> <td>'. $xml->name .'&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp</td> <td class="alternate-row1">'. $xml->lastname .'</td> <td>'. $xml->email .'</td> <td class="alternate-row1">'. $xml->level .'</td> <td>'. $xml->birthday .'</td> <td class="alternate-row1">'. $xml->gender .'</td> <td>'. $xml->age .'</td> <td class="alternate-row1">'. $xml->country .'</td> </tr>'; } ?> </table> </div> <?php if(isset($_POST['file_name'])){ unlink('users/'.$_POST['file_name']); } ?> <input type="submit" value="Delete" /> </form> so as you can see i got radio value set has basename (xml file name) but from some reason it not working, any idea why is that? Thanks in advance.

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  • Retrieve XML from URL

    - by Pl4za
    I am having some problems retrieving a xml from url with the following code: private static String getAlbumArt(String artistName, String albumName){ try{ XMLParser xml_parser = new XMLParser(); String xml = xml_parser.getXmlFromUrl(getAlbumURL(artistName, albumName)); Document doc = xml_parser.getDomElement(xml); NodeList N = doc.getElementsByTagName("album"); Node node = N.item(0); NodeList N2 = node.getChildNodes(); System.out.println("1------"); for (int i = 0; i < N2.getLength(); i++) { Node detailNode = N2.item(i); if (detailNode.getNodeType() == Node.ELEMENT_NODE) { System.out.println("2------"); if (detailNode.getNodeName().equalsIgnoreCase("image")) { String sizeVal = ((Element) detailNode).getAttribute("size"); String url = detailNode.getTextContent(); if (sizeVal.equalsIgnoreCase("large")) { return url; } } } } } catch (Exception e){ } return null; } The xml function which i call in the above code: public String getXmlFromUrl(String url) { String xml = null; try { DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); xml = EntityUtils.toString(httpEntity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return xml; } getAlbumURL: public static String getAlbumURL(String artist, String album){ return URL_METHOD + METHOD_GETALBUM + AMPERSAND + API_KEY + AMPERSAND + PARAM_ARTIST + artist + AMPERSAND + PARAM_ALBUM + album; } XMLparser: public class XMLParser { // constructor public XMLParser() { } //Get XML from URL public String getXmlFromUrl(String url) { String xml = null; try { DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); xml = EntityUtils.toString(httpEntity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return xml; } //Get dom element public Document getDomElement(String xml){ Document doc = null; DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); try { DocumentBuilder db = dbf.newDocumentBuilder(); InputSource is = new InputSource(); is.setCharacterStream(new StringReader(xml)); doc = db.parse(is); } catch (ParserConfigurationException e) { Log.e("Error: ", e.getMessage()); return null; } catch (SAXException e) { Log.e("Error: ", e.getMessage()); return null; } catch (IOException e) { Log.e("Error: ", e.getMessage()); return null; } return doc; } //Get nod element public final String getElementValue(Node elem ) { Node child; if( elem != null){ if (elem.hasChildNodes()){ for( child = elem.getFirstChild(); child != null; child = child.getNextSibling() ){ if( child.getNodeType() == Node.TEXT_NODE ){ return child.getNodeValue(); } } } } return ""; } //Get element value public String getValue(Element item, String str) { NodeList nlList = item.getElementsByTagName(str).item(0).getChildNodes(); Node nValue = (Node) nlList.item(0); return nValue.getNodeValue(); } } Any ideas ? I seriously don't know what is wrong.. I used this before and it worked.

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  • XML Schema - how do you conditionally require address elements? (street, city, state, etc)

    - by Sly
    If an address can be composed of child elements: Street, City, State, PostalCode...how do you allow this XML: <Address> <Street>Somestreet</Street> <PostalCode>zip</PostalCode> </Address> and allow this: <Address> <Street>Somestreet</Street> <City>San Jose</City> <State>CA</State> </Address> but not this: <Address> <Street>Somestreet</Street> <City>San Jose</City> </Address> What schema will do such things!?

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  • Web.xml: Are url-pattern tags relative to each other?

    - by sixtyfootersdude
    <servlet-mapping> <servlet-name>myName</servlet-name> <url-pattern>/aName</url-pattern> </servlet-mapping> <security-constraint> <web-resource-collection> ... <url-pattern> /* </url-pattern> </web-resource-collection> ... </security-constraint> This is an excerpt from web.xml (using it to configure a jboss/tomcat webservice). Just wondering if the url-pattern in web-resource-collection is relative to the url-pattern in servlet-mapping.

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  • How could I do something like this in a XML schema?

    - by chobo2
    Hi I want to mass create some users and I want to set the users timezone automatically. However I am using timezones generated by this Dictionary<string, TimeZoneInfo> storeZoneName = TimeZoneInfo.GetSystemTimeZones().ToDictionary(z => z.DisplayName); So I need the names to be exactly like the ones this list returns. So can I put like a constraint on that xml node that the name has to exactly match one of the names. So I am guessing I will need to write this list somewhere in the file and that's what I am not sure if you can do something like that in a schema.

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  • Web.xml: Are url-pattern tags relitive to each other?

    - by sixtyfootersdude
    <servlet-mapping> <servlet-name>myName</servlet-name> <url-pattern>/aName</url-pattern> </servlet-mapping> <security-constraint> <web-resource-collection> ... <url-pattern> /* </url-pattern> </web-resource-collection> ... </security-constraint> This is an excerpt from web.xml (using it to configure a jboss/tomcat webservice). Just wondering if the url-pattern in web-resource-collection is relative to the url-pattern in servlet-mapping.

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  • How does versioning work when using Boost Serialization for Derived Classes?

    - by Venkata Adusumilli
    When a Client serializes the following data: InternationalStudent student; student.id("Client ID"); student.firstName("Client First Name"); student.country("Client Country"); the Server receives the following: ID = "Client ID" Country = "Client First Name" instead of the following: ID = "Client ID" Country = "Client Country" The only difference between the Server and Client classes is the First Name of the Student. How can we make the Server ignore First Name recieved from the Client and process the Country? Server Side Classes class Student { public: Student(){} virtual ~Student(){} public: std::string id() { return idM; } void id(std::string id) { idM = id; } protected: friend class boost::serialization::access; protected: std::string idM; protected: template<class A> void serialize(A& archive, const unsigned int /*version*/) { archive & BOOST_SERIALIZATION_NVP(idM); } }; class InternationalStudent : public Student { public: InternationalStudent() {} ~InternationalStudent() {} public: std::string country() { return countryM; } void country(std::string country) { countryM = country; } protected: friend class boost::serialization::access; protected: std::string countryM; protected: template<class A> void serialize(A& archive, const unsigned int /*version*/) { archive & BOOST_SERIALIZATION_NVP(boost::serialization::base_object<Student>(*this)); archive & BOOST_SERIALIZATION_NVP(countryM); } }; Client Side Classes class Student { public: Student(){} virtual ~Student(){} public: std::string id() { return idM; } void id(std::string id) { idM = id; } std::string firstName() { return firstNameM; } void firstName(std::string name) { firstNameM = name; } protected: friend class boost::serialization::access; protected: std::string idM; std::string firstNameM; protected: template<class A> void serialize(A& archive, const unsigned int /*version*/) { archive & BOOST_SERIALIZATION_NVP(idM); if (version >=1) { archive & BOOST_SERIALIZATION_NVP(firstNameM); } } }; BOOST_CLASS_VERSION(Student, 1) class InternationalStudent : public Student { public: InternationalStudent() {} ~InternationalStudent() {} public: std::string country() { return countryM; } void country(std::string country) { countryM = country; } protected: friend class boost::serialization::access; protected: std::string countryM; protected: template<class A> void serialize(A& archive, const unsigned int /*version*/) { archive & BOOST_SERIALIZATION_NVP(boost::serialization::base_object<Student>(*this)); archive & BOOST_SERIALIZATION_NVP(countryM); } };

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  • how to filter data from xml file for displaying only selected as nodes in treeview

    - by michale
    I have an xml file named "books.xml" provided in the link "http://msdn.microsoft.com/en-us/library/windows/desktop/ms762271(v=vs.85).aspx". What my requirement was to disaplay only the <title> from xml information as nodes in tree view. But when i did the following coding its displaying all the values as nodes like "catalog" as rootnode, book as parent node for all then author,title,genre etc as nodes but i want only root node catalogue and title as nodes not even book. Can any body guide me what modification i need to do in the exisitng logic for displaying title as nodes OpenFileDialog dlg = new OpenFileDialog(); dlg.Title = "Open XML document"; dlg.Filter = "XML Files (*.xml)|*.xml"; dlg.FileName = Application.StartupPath + "\\..\\..\\Sample.xml"; if (dlg.ShowDialog() == DialogResult.OK) { try { //Just a good practice -- change the cursor to a //wait cursor while the nodes populate this.Cursor = Cursors.WaitCursor; //First, we'll load the Xml document XmlDocument xDoc = new XmlDocument(); xDoc.Load(dlg.FileName); //Now, clear out the treeview, //and add the first (root) node treeView1.Nodes.Clear(); treeView1.Nodes.Add(new TreeNode(xDoc.DocumentElement.Name)); TreeNode tNode = new TreeNode(); tNode = (TreeNode)treeView1.Nodes[0]; //We make a call to addTreeNode, //where we'll add all of our nodes addTreeNode(xDoc.DocumentElement, tNode); //Expand the treeview to show all nodes treeView1.ExpandAll(); } catch (XmlException xExc) //Exception is thrown is there is an error in the Xml { MessageBox.Show(xExc.Message); } catch (Exception ex) //General exception { MessageBox.Show(ex.Message); } finally { this.Cursor = Cursors.Default; //Change the cursor back } }} //This function is called recursively until all nodes are loaded private void addTreeNode(XmlNode xmlNode, TreeNode treeNode) { XmlNode xNode; TreeNode tNode; XmlNodeList xNodeList; if (xmlNode.HasChildNodes) //The current node has children { xNodeList = xmlNode.ChildNodes; for (int x = 0; x <= xNodeList.Count - 1; x++) //Loop through the child nodes { xNode = xmlNode.ChildNodes[x]; treeNode.Nodes.Add(new TreeNode(xNode.Name)); tNode = treeNode.Nodes[x]; addTreeNode(xNode, tNode); } } else //No children, so add the outer xml (trimming off whitespace) treeNode.Text = xmlNode.OuterXml.Trim(); }

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  • How can I create the XML::Simple data structure using a Perl XML SAX parser?

    - by DVK
    Summary: I am looking a fast XML parser (most likely a wrapper around some standard SAX parser) which will produce per-record data structure 100% identical to those produced by XML::Simple. Details: We have a large code infrastructure which depends on processing records one-by-one and expects the record to be a data structure in a format produced by XML::Simple since it always used XML::Simple since early Jurassic era. An example simple XML is: <root> <rec><f1>v1</f1><f2>v2</f2></rec> <rec><f1>v1b</f1><f2>v2b</f2></rec> <rec><f1>v1c</f1><f2>v2c</f2></rec> </root> And example rough code is: sub process_record { my ($obj, $record_hash) = @_; # do_stuff } my $records = XML::Simple->XMLin(@args)->{root}; foreach my $record (@$records) { $obj->process_record($record) }; As everyone knows XML::Simple is, well, simple. And more importantly, it is very slow and a memory hog—due to being a DOM parser and needing to build/store 100% of data in memory. So, it's not the best tool for parsing an XML file consisting of large amount of small records record-by-record. However, re-writing the entire code (which consist of large amount of "process_record"-like methods) to work with standard SAX parser seems like an big task not worth the resources, even at the cost of living with XML::Simple. I'm looking for an existing module which will probably be based on a SAX parser (or anything fast with small memory footprint) which can be used to produce $record hashrefs one by one based on the XML pictured above that can be passed to $obj->process_record($record) and be 100% identical to what XML::Simple's hashrefs would have been. I don't care much what the interface of the new module is; e.g whether I need to call next_record() or give it a callback coderef accepting a record.

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  • XML pass values to timer, AS3

    - by VideoDnd
    My timer has three variables that I can trace to the output window, but don't know how to pass them to the timer. How to I pass the XML values to my timer? Purpose I want to test with an XML document, before I try connecting it to an XML socket. myXML <?xml version="1.0" encoding="utf-8"?> <SESSION> <TIMER TITLE="speed">100</TIMER> <COUNT TITLE="starting position">-77777</COUNT> <FCOUNT TITLE="ramp">1000</FCOUNT> </SESSION> myFlash //myTimer 'instance of mytext on stage' /* fields I want to change with XML */ //CHANGE TO 100 var timer:Timer = new Timer(10); //CHANGE TO -77777 var count:int = 0; //CHANGE TO 1000 var fcount:int = 0; timer.addEventListener(TimerEvent.TIMER, incrementCounter); timer.start(); function incrementCounter(event:TimerEvent) { count++; fcount=int(count*count/1000);//starts out slow... then speeds up mytext.text = formatCount(fcount); } function formatCount(i:int):String { var fraction:int = i % 100; var whole:int = i / 100; return ("0000000" + whole).substr(-7, 7) + "." + (fraction < 10 ? "0" + fraction : fraction); } //LOAD XML var myXML:XML; var myLoader:URLLoader = new URLLoader(); myLoader.load(new URLRequest("time.xml")); myLoader.addEventListener(Event.COMPLETE, processXML); //PARSE XML function processXML(e:Event):void { myXML = new XML(e.target.data); trace(myXML.ROGUE.*); trace(myXML); //TEXT var text:TextField = new TextField(); text.text = myXML.TIMER.*; text.textColor = 0xFF0000; addChild(text); } RESOURCES OReilly's ActionScript 3.0 Cookbook, Chapter 12 Strings, Chapter 20 XML

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  • Recursive XSD Help

    - by Alon
    Hi, i'm trying to learn a little bit XSD and I'm trying to create a XSD for this xml: <Document> <TextBox Name="Username" /> <TextBox Name="Password" /> </Document> ... so there's an element, which is an abstract complex type. Every element have elements and so on. Document and TextBox are extending Element. I trid this: <?xml version="1.0" encoding="utf-8" ?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xs:element name="Document"> <xs:complexType> <xs:complexContent> <xs:extension base="Element"> </xs:extension> </xs:complexContent> </xs:complexType> </xs:element> <xs:complexType name="Element" abstract="true"> <xs:sequence minOccurs="0" maxOccurs="unbounded"> <xs:element name="Element" type="Element"></xs:element> </xs:sequence> </xs:complexType> <xs:complexType name="TextBox"> <xs:complexContent> <xs:extension base="Element"> <xs:attribute name="Name" type="xs:string" /> </xs:extension> </xs:complexContent> </xs:complexType> </xs:schema> I compiled it to C# with Xsd2Code, and now I try to deserialize it: var serializer = new XmlSerializer(typeof(Document)); var document = (Document)serializer.Deserialize(new FileStream("Document1.xml", FileMode.Open)); foreach (var element in document.Element1) { Console.WriteLine(((TextBox)element).Name); } Console.ReadLine(); and it dosen't print anything. When I try to serialize it like so: var serializer = new XmlSerializer(typeof(Document)); var document = new Document(); document.Element1 = new List<Element>(); document.Element1.Add(new TextBox() { Name = "abc" }); serializer.Serialize(new FileStream("d.xml", FileMode.Create), document); ...the output is: <?xml version="1.0"?> <Document xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Element1> <Element xsi:type="TextBox"> <Element1 /> <Name>abc</Name> </Element> </Element1> </Document> When it should be: <Document> <TextBox Name="abc" /> </Document> Any ideas how to fix the xsd or another code generator? Thanks.

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  • Parsing XML with the PHP XMLReader

    - by coffeecoder
    Hi Guys, I am writing program that reads in some XML from the $_POST variable and then parses using the PHP XMLReader and the data extracted input into a database. I am using the XMLReader as the XML supplied will more than likely be too big to place into memory. However I am having some issues, my XML and basic code as are follows: '<?xml version="1.0"?> <data_root> <data> <info>value</info> </data> <action>value</action> </data_root>' $request = $_REQUEST['xml']; $reader = new XMLReader(); $reader->XML($request); while($reader->read()){ //processing code } $reader->close() My problem is that the code will work perfectly if the XML being passed does not have the <?xml version="1.0"?> line, but if i include it, and it will be included when the application goes into a live production environment, the $reader->read() code for the while loop does not work and the XML is not parsed within the while loop. Has anyone seen similar behaviour before or knows why this could be happening? Thanks in advance.

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  • Will JSON replace XML as a data format?

    - by 13ren
    When I first saw XML, I thought it was basically a representation of trees. Then I thought: the important thing isn't that it's a particularly good representation of trees, but that it is one that everyone agrees on. Just like ASCII. And once established, it's hard to displace due to network effects. The new alternative would have to be much better (maybe 10 times better) to displace it. Of course, ASCII has been (mostly) replaced by Unicode, for internationalization. According to google trends, XML has a x43 lead, but is declining - while JSON grows. Will JSON replace XML as a data format? (edited) for which tasks? for which programmers/industries? NOTES: S-expressions (from lisp) are another representation of trees, but which has not gained mainstream adoption. There are many, many other proposals, such as YAML and Protocol Buffers (for binary formats). I can see JSON dominating the space of communicating with client-side AJAX (AJAJ?), and this possibly could back-spread into other systems transitively. XML, being based on SGML, is better than JSON as a document format. I'm interested in XML as a data format. XML has an established ecosystem that JSON lacks, especially ways of defining formats (XML Schema) and transforming them (XSLT). XML also has many other standards, esp for web services - but their weight and complexity can arguably count against XML, and make people want a fresh start (similar to "web services" beginning as a fresh start over CORBA).

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