Search Results

Search found 5884 results on 236 pages for 'bash scripting'.

Page 27/236 | < Previous Page | 23 24 25 26 27 28 29 30 31 32 33 34  | Next Page >

  • BASH: Find highest numbered filename in a directory where names start with digits (ls, sed)

    - by Jake
    I have a directory with files that look like this: 001_something.php 002_something_else.php 004_xyz.php 005_do_good_to_others.php I ultimately want to create a new, empty PHP file whose name starts with the next number in the series. LIST=`exec ls $MY_DIR | sed 's/\([0-9]\+\).*/\1/g' | tr '\n' ' '` The preceding code gives me a string like this: LIST='001 002 004 005 ' I want to grab that 005, increment by one, and then use that number to generate the new filename. How do I do that in BASH?

    Read the article

  • Bash: trim a parameter from both ends

    - by Andrey Kazak
    Greetings! This are well know Bash parameter expansion patterns: ${parameter#word}, ${parameter##word} and ${parameter%word}, ${parameter%%word} I need to chop one part from the beginning and anoter part from the trailing of the parameter. Could you advice something for me please?

    Read the article

  • Bash edit file and keep last 500 lines

    - by Lizard
    I am looking to create a cron job that opens a directory loops through all the logs i have created and deletes all lines but keep the last 500 for example. I was thinking of something along the lines of tail -n 500 filename > filename Would this work? I also not sure how to loop through a directory in bash Thanks in advance.

    Read the article

  • get bash history to vi

    - by nameanyone
    When I try to read bash history into vim, I get nothing. :r !history If I just execute the command, i.e. :!history instead of history I get a snapshot of my terminal as it looked before I started vim. How can I read the output of "history" into vim? Reading the contents of .bash_history won't do as I save history with timestamps: HISTTIMEFORMAT='%Y.%m.%d %R '

    Read the article

  • Inline comments for bash?

    - by Lajos Nagy
    I'd like to be able to comment out a single flag in a one-line command. Bash only seems to have `from # till end-of-line' comments. I'm looking at tricks like: ls -l $([ ] && -F is turned off) -a /etc It's ugly, but better than nothing. Anybody has any better suggestions?

    Read the article

  • Bash script, read values from stdin pipe

    - by gmatt
    I'm trying to get bash to process data from stdin that gets piped it, but no luck, what I mean is none of the following work: echo "hello world" | test=($(< /dev/stdin)); echo test=$test test= echo "hello world" | read test; echo test=$test test= echo "hello world" | test=`cat`; echo test=$test test= where I want the output to be test=hello world. Note I've tried putting "" quotes around "$test" that doesn't work either.

    Read the article

  • bash completion for Subversion

    - by khmarbaise
    I've tried to load bash_completion in my bash (3.2.25), it does not work. No message etc. I've used the following in my .bashrc if [ -f ~/.bash_completion ]; then . ~/.bash_completion fi I also tried to use .bash_profile instead, but with the same result. So the problem is why does it not work? Any idea? Hints?

    Read the article

  • Recursive follow files in bash

    - by user328955
    I have files which contain file names pointing to other files. These files contain further file names pointing further files and so on. I need a bash script which follows each files recursively and logs into file every touched file during the run. file1: file2 file3 file2: file4 file3: file5 file4 and file5 are empty. Result: file1 file2 file4 file3 file5

    Read the article

  • Batch equivilant of Bash backticks

    - by MiffTheFox
    When working with Bash, I can put the output of one command into another command like so: my_command `echo Test` would be the same thing as my_command Test (Obviously, this is just a non-practical example.) I'm just wondering if you can do the same thing in Batch.

    Read the article

  • bash: assign grep regex results to array

    - by Ryan
    Hello everyone, I am trying to assign a regular expression result to an array inside of a bash script but I am unsure whether that's possible, or if I'm doing it entirely wrong. The below is what I want to happen, however I know my syntax is incorrect: indexes[4]=$(echo b5f1e7bfc2439c621353d1ce0629fb8b | grep -o '[a-f0-9]\{8\}') such that: index[1]=b5f1e7bf index[2]=c2439c62 index[3]=1353d1ce index[4]=0629fb8b Any links, or advice, would be wonderful :)

    Read the article

  • BASH Arithmetic Expressions

    - by Arko
    I had used several ways to do some simple integer arithmetic in BASH (3.2). But I can't figure out the best (preferred) way to do it. result=`expr 1 + 2` result=$(( 1 + 2 )) let "result = 1 + 2" What are the fundamental differences between those expressions? Is there other ways to do the same? Is the use of a tool like bc mandatory for floating point arithmetic? result=`echo "7/354" | bc`

    Read the article

  • [bash] Escape a string for sed search pattern

    - by Alexander Gladysh
    In my bash script I have an external (received from user) string, which I should use in sed pattern. REPLACE="<funny characters here>" sed "s/KEYWORD/$REPLACE/g" How can I escape the $REPLACE string so it would be safely accepted by sed as a literal replacement? NOTE: The KEYWORD is a dumb substring with no matches etc. It is not supplied by user.

    Read the article

  • Variable assignment in bash

    - by Werner
    Hi, this is probably a very stupid question; in a bash script, given the output of, for instance; awk '{print $7}' temp it gives 0.54546 I would like to give this to a variable, so I tried: read ENE <<< $(awk '{print $7}' temp) but I get Syntax error: redirection unexpected Could you tell me why, and what is the easiest way to do this assignment? Thanks

    Read the article

  • Source operator doesn't work in if construction in bash

    - by Igor
    Hello, I'd like to include a config file in my bash script with 2 conditions: 1) the config file name is constructed on-the-fly and stored in variable, and 2) in case if config file doesn't exist, the script should fail: config.cfg: CONFIGURED=yes test.sh: #!/bin/sh $CFG=config.cfg echo Source command doesn't work here: [ -f $CFG ] && ( source $CFG ) || (echo $CFG doesnt exist; exit 127) echo $CONFIGURED echo ... but works here: source $CFG echo $CONFIGURED What's wrong in [...] statement?

    Read the article

< Previous Page | 23 24 25 26 27 28 29 30 31 32 33 34  | Next Page >