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  • DataColumn.Expression Power

    - by Graham
    the following code Dim dc = New DataColumn(name, GetType(Double), "[col1] ^ [col2]") produces the following error: The expression contains unsupported operator '^'. Is this right, is the power operand not support in datacolumn expressions??? Anyone have an idea how i'd write this?

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  • Why does this expression not work? JSF

    - by Nitesh Panchal
    Hello, I have a simple problem on .xhtml page. This expression is not working :- <a href="Photos.jsf?albumId=#{item.albumId}&blogId=#{PhotoAlbumsCommonBean.blogId}"> photos </a> I get this error :- Error Parsing /Common/PhotoAlbums.xhtml: Error Traced[line: 20] The reference to entity "blogId" must end with the ';' delimiter. & is causing some kind of error. Thanks in advance :)

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  • Regex expression in plain english

    - by Sebi
    I'm working on a new Java project and therefore im reading the already existing code. On a very important part of the code if found the following regex expression and i can't really tell what they are doing. Anybody can explain in plain english what they do?? 1) [^,]*|.+(,).+ 2) (\()?\d+(?(1)\))

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  • C# regular expression

    - by vert
    How would I write a regular expression (C#) which will check a given string to see if any of its characters are characters OTHER than the following: a-z A-Z Æ æ Å å Ø ø - ' Thanks!

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  • Using Regular Expression in VC++

    - by Benit
    Hi , I am finding Email ids in mu project, where I am preprocessing the input using some Regular Expression. RegExpPhone6.RegComp("[\[\{\(][ -]?[s][h][i][f][t][ -]?[+-][2][ -]?[\]\}\)]"); Here while I am compiling i am getting a warning msg like Warning 39 warning C4129: ')' : unrecognized character escape sequence How can i resolve this ? Why this is occuring and Where will it affect? Kindly help me...

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  • PHP regular expression for positive number with 0 or 2 decimal places

    - by Peter
    Hi I am trying to use the following regular expression to check whether a string is a positive number with either zero decimal places, or 2: ^\d+(\.(\d{2}))?$ When I try to match this using preg_match, I get the error: Warning: preg_match(): No ending delimiter '^' found in /Library/WebServer/Documents/lib/forms.php on line 862 What am I doing wrong?

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  • using regular expression in Java

    - by Mrityunjay
    Hi, i need to check a string that should contain only ABCDEFG characters, in any sequence and with only 7 characters. Please let me know the correct way of using regular expression. as corrently i am using String abs = "ABPID"; if(!Pattern.matches("[[ABCDEFG]", abs)) System.out.println("Error"); i am using the following code which works when i use the String abcdefg but for other cases it fails. please help me out.

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  • Using s/// in an expression

    - by mikeY
    I got a headache looking for this: How do you use s/// in an expression as opposed to an assignment. To clarify what I mean, I'm looking for a perl equivalent of python's re.sub(...) when used in the following context: newstring = re.sub('ab', 'cd', oldstring) The only way I know how to do this in perl so far is: $oldstring =~ s/ab/cd/; $newstring = $oldstring; Note the extra assignment.

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  • split twice in the same expression?

    - by UcanDoIt
    Imagine I have the following: inFile = "/adda/adas/sdas/hello.txt" # that instruction give me hello.txt Name = inFile.name.split("/") [-1] # that one give me the name I want - just hello Name1 = Name.split(".") [0] Is there any chance to simplify that doing the same job in just one expression?

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  • Regular Expression :match string containing only non repeating words

    - by nash
    I have this situation(Java code): 1) a string such as : "A wild adventure" should match. 2) a string with adjacent repeated words: "A wild wild adventure" shouldn't match. With this regular expression: .* \b(\w+)\b\s*\1\b.* i can match strings containing adjacent repeated words. How to reverse the situation i.e how to match strings which do not contain adjacent repeat words

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  • Regular Expression

    - by Malcolm
    I want regular expression that checks that the string doesnt start with an empty space. Some what like this i want to do : Is the below ValidationExpression right for it : string ValidationExpression = @"/^[^ ]/"; if (!String.IsNullOrEmpty(GroupName) && !Regex.IsMatch(GroupName, ValidationExpression)) { }

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  • perl: generating permutations from a regular expression

    - by wibble
    I know you can generate all permutations from a list, using glob or Algorithm::Permute for example - but how do you generate all possible permutations from a regular expression? i want to do like: @perms = permute( "/\s[A-Z][0-9][0-9]/" ); sub permute( $regex ) { # code - put all permutations of above regex in a list return @list; }

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  • java regular expression

    - by BSingh
    I am trying to write a regular expression for somethin like s1 = I am at Boston at Dowtown s2 = I am at Miami I am interested in the words after at eg: Boston, Downtown, Miami I have not been successful in creating a regex for that. Somethin like > .*? (at \w+)+.* gives just Boston in s1 (Downtown is missed). it just matches the first "at" Any suggestions

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  • Regular expression for pipe delimited and double quoted string

    - by Hiren Amin
    I have a string something like this: "2014-01-23 09:13:45|\"10002112|TR0859657|25-DEC-2013>0000000000000001\"|10002112" I would like to split by pipe apart from anything wrapped in double quotes so I have something like (similar to how csv is done): [0] => 2014-01-23 09:13:45 [1] => 10002112|TR0859657|25-DEC-2013>0000000000000001 [2] => 10002112 I would like to know if there is a regular expression that can do this?

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  • Optimizing python link matching regular expression

    - by Matt
    I have a regular expression, links = re.compile('<a(.+?)href=(?:"|\')?((?:https?://|/)[^\'"]+)(?:"|\')?(.*?)>(.+?)</a>',re.I).findall(data) to find links in some html, it is taking a long time on certain html, any optimization advice? One that it chokes on is http://freeyourmindonline.net/Blog/

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  • regular expression

    - by xyz
    I need regular expression to match braces correct e.g for every open one close one abc{abc{bc}xyz} I need it get all it from {abc{bc}xyz} not get {abc{bc} I tried this ({.*?})

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