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• using Hibernate to loading 20K products, modifying the entity and updating to db

  - by Blankman

  I am using hibernate to update 20K products in my database. As of now I am pulling in the 20K products, looping through them and modifying some properties and then updating the database. so: load products foreach products session begintransaction productDao.MakePersistant(p); session commit(); As of now things are pretty slow compared to your standard jdbc, what can I do to speed things up? I am sure I am doing something wrong here.

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• Using hibernate with annotations, i want a one-many relationship to be sorted

  - by Chris

  Using hibernate with annotations, i want a one-many relationship to be sorted by the 'created' field on the 'many' table. So far i've got this, which always ends up in a random order: // The notes @OneToMany @JoinColumn(name="task_id") Set<TaskNote> notes; public Set<TaskNote> getNotes() {return notes;} public void setNotes(Set<TaskNote> notes) {this.notes = notes;}

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• Hibernate - Knowing when hitting database vs cache

  - by Marty Pitt

  Given all the smarts around Hibernate and it's various caching strategies, how do I know if a certain operation is resulting in a physical database hit, or coming from the cache?

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• How to test if a table is empty, using Hibernate

  - by landon9720

  Using Hibernate, what is the most efficient way to determine if a table is empty or non-empty? In other words, does the table have 0, or more than 0 rows? I could execute the HQL query select count(*) from tablename and then check if result is 0 or non-0, but this isn't optimal as I would be asking the database for more detail than I really need.

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• Hibernate subclass with foreign key relationships

  - by shikarishambu

  I need some help defining the following object hierarchy/ database relationship in Hibernate From the object sense – Agent is inherited from Person and Agency is inherited from Organization. they are inherited from Party which can have multiple Addresses associated with it The database consists of Agent - ID - Name -PartyID (references Party.ID) Agency -ID -Name -PartyID (references Party.ID) Address -AddrID -PartyID (references Party.ID) -Street Party. -PartyID

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• Hibernate (JPA) Entity with Static collection as a member

  - by Kyle Partridge

  Is it possible to have a static collection as a member of a hibernate entity? Say I have an object Question: public class Question { private String category; ... } Would it be possible to populate a static Set<String> that is a distinct set of all categories in the Database? I know I could just query this, but I was wondering if there was a more elegant solution, as it seems like something that other people may have come across.

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• How to fix hibernate / suspend with proprietary nVidia driver?

  - by Chris

  Hi, I've just got an Dell Precision M6500 that comes with an nVidia card. Together with Kubunutu 10.10 and the proprietary nvidia driver suspend to disk or RAM does not work. It's allways ending with a running system and a locked screen (i.e. I can just enter my password and everything is as before - it's never sleeping) Can someone please help me to debug this issue? Where should I look for information? None of the log files seem to show an obvious error... Thanks, Chris

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• Struts2 Hibernate Login with User table and group table

  - by J2ME NewBiew

  My problem is, i have a table User and Table Group (this table use to authorization for user - it mean when user belong to a group like admin, they can login into admincp and other user belong to group member, they just only read and write and can not login into admincp) each user maybe belong to many groups and each group has been contain many users and they have relationship are many to many I use hibernate for persistence storage. and struts 2 to handle business logic. When i want to implement login action from Struts2 how can i get value of group member belong to ? to compare with value i want to know? Example I get user from username and password then get group from user class but i dont know how to get value of group user belong to it mean if user belong to Groupid is 1 and in group table , at column adminpermission is 1, that user can login into admincp, otherwise he can't my code: User.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import java.util.Date; import java.util.HashSet; import java.util.Set; import javax.persistence.CascadeType; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.JoinTable; import javax.persistence.ManyToMany; import javax.persistence.Table; import javax.persistence.Temporal; /** * * @author Administrator */ @Entity @Table(name="User") public class User implements Serializable{ private static final long serialVersionUID = 2575677114183358003L; private Long userId; private String username; private String password; private String email; private Date DOB; private String address; private String city; private String country; private String avatar; private Set<Group> groups = new HashSet<Group>(0); @Column(name="dob") @Temporal(javax.persistence.TemporalType.DATE) public Date getDOB() { return DOB; } public void setDOB(Date DOB) { this.DOB = DOB; } @Column(name="address") public String getAddress() { return address; } public void setAddress(String address) { this.address = address; } @Column(name="city") public String getCity() { return city; } public void setCity(String city) { this.city = city; } @Column(name="country") public String getCountry() { return country; } public void setCountry(String country) { this.country = country; } @Column(name="email") public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } @ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL) @JoinTable(name="usergroup",joinColumns={@JoinColumn(name="userid")},inverseJoinColumns={@JoinColumn( name="groupid")}) public Set<Group> getGroups() { return groups; } public void setGroups(Set<Group> groups) { this.groups = groups; } @Column(name="password") public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @Id @GeneratedValue @Column(name="iduser") public Long getUserId() { return userId; } public void setUserId(Long userId) { this.userId = userId; } @Column(name="username") public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } @Column(name="avatar") public String getAvatar() { return avatar; } public void setAvatar(String avatar) { this.avatar = avatar; } } Group.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.Table; /** * * @author Administrator */ @Entity @Table(name="Group") public class Group implements Serializable{ private static final long serialVersionUID = -2722005617166945195L; private Long idgroup; private String groupname; private String adminpermission; private String editpermission; private String modpermission; @Column(name="adminpermission") public String getAdminpermission() { return adminpermission; } public void setAdminpermission(String adminpermission) { this.adminpermission = adminpermission; } @Column(name="editpermission") public String getEditpermission() { return editpermission; } public void setEditpermission(String editpermission) { this.editpermission = editpermission; } @Column(name="groupname") public String getGroupname() { return groupname; } public void setGroupname(String groupname) { this.groupname = groupname; } @Id @GeneratedValue @Column (name="idgroup") public Long getIdgroup() { return idgroup; } public void setIdgroup(Long idgroup) { this.idgroup = idgroup; } @Column(name="modpermission") public String getModpermission() { return modpermission; } public void setModpermission(String modpermission) { this.modpermission = modpermission; } } UserDAO /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.dao; import java.util.List; import org.dejavu.software.model.User; import org.dejavu.software.util.HibernateUtil; import org.hibernate.Query; import org.hibernate.Session; /** * * @author Administrator */ public class UserDAO extends HibernateUtil{ public User addUser(User user){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); session.save(user); session.getTransaction().commit(); return user; } public List<User> getAllUser(){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); List<User> user = null; try { user = session.createQuery("from User").list(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } public User checkUsernamePassword(String username, String password){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); User user = null; try { Query query = session.createQuery("from User where username = :name and password = :password"); query.setString("username", username); query.setString("password", password); user = (User) query.uniqueResult(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } } AdminLoginAction /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.view; import com.opensymphony.xwork2.ActionSupport; import org.dejavu.software.dao.UserDAO; import org.dejavu.software.model.User; /** * * @author Administrator */ public class AdminLoginAction extends ActionSupport{ private User user; private String username,password; private String role; private UserDAO userDAO; public AdminLoginAction(){ userDAO = new UserDAO(); } @Override public String execute(){ return SUCCESS; } @Override public void validate(){ if(getUsername().length() == 0){ addFieldError("username", "Username is required"); }if(getPassword().length()==0){ addFieldError("password", getText("Password is required")); } } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } public String getRole() { return role; } public void setRole(String role) { this.role = role; } public User getUser() { return user; } public void setUser(User user) { this.user = user; } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } } other question. i saw some example about Login, i saw some developers use interceptor, im cant understand why they use it, and what benefit "Interceptor" will be taken for us? Thank You Very Much!

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• Adding JBoss repository to m2eclipse, no latest Hibernate version

  - by Robert

  I'm trying to add JBoss repository to m2eclipse, mainly for Hibernate. It seems to work, but it can't find the latest version of Hibernate (3.5.1), only 3.5.0beta. I looked at some other packages, and they all seem a couple of months behind. What could be causing this? I'm running latest m2eclipse, and i guess latest Eclipse (it just says 20100218-1602, eclipse people think it's funny to not include version in the about dialog), on ubuntu 9.10. This is my settings.xml <settings> <profiles> <profile> <id>jboss-maven2-release-repository</id> <activation> <activeByDefault>true</activeByDefault> </activation> <repositories> <repository> <id>jboss-maven2-release-repository</id> <url>http://repository.jboss.org/maven2</url> <releases> <enabled>true</enabled> </releases> <snapshots> <enabled>false</enabled> </snapshots> </repository> <repository> <id>jboss-snapshots</id> <url>http://snapshots.jboss.org/maven2</url> <releases> <enabled>false</enabled> </releases> <snapshots> <enabled>true</enabled> </snapshots> </repository> </repositories> <pluginRepositories> <pluginRepository> <id>jboss-releases</id> <url>http://repository.jboss.org/maven2</url> <releases> <enabled>true</enabled> </releases> <snapshots> <enabled>false</enabled> </snapshots> </pluginRepository> <pluginRepository> <id>jboss-snapshots</id> <url>http://snapshots.jboss.org/maven2</url> <releases> <enabled>false</enabled> </releases> <snapshots> <enabled>true</enabled> </snapshots> </pluginRepository> </pluginRepositories> </profile> </profiles>

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• Tomcat/Hibernate Problem "SEVERE: Error listenerStart"

  - by JSteve

  I downloaded working example of hibernate (with maven) and installed it on my tomcat, it worked. Then I created a new web project in MyEclipse, added hibernate support and moved all source files (no jar) to this new project and fixed package/paths wherever was necessary. My servlets are responding correctly but when I add "Listener" in web.xml, tomcat returns error "Error ListenerStart" on startup and my application doesn't start. I've carefully checked all packages, paths and classes, they look good. Error message is also not telling anything more except these two words Here is complete tomcat startup log: 17-Jun-2010 12:13:37 PM org.apache.coyote.http11.Http11Protocol init INFO: Initializing Coyote HTTP/1.1 on http-8810 17-Jun-2010 12:13:37 PM org.apache.catalina.startup.Catalina load INFO: Initialization processed in 293 ms 17-Jun-2010 12:13:37 PM org.apache.catalina.core.StandardService start INFO: Starting service Catalina 17-Jun-2010 12:13:37 PM org.apache.catalina.core.StandardEngine start INFO: Starting Servlet Engine: Apache Tomcat/6.0.20 17-Jun-2010 12:13:37 PM org.apache.catalina.core.StandardContext start SEVERE: Error listenerStart 17-Jun-2010 12:13:37 PM org.apache.catalina.core.StandardContext start SEVERE: Context [/addressbook] startup failed due to previous errors 17-Jun-2010 12:13:37 PM org.apache.coyote.http11.Http11Protocol start INFO: Starting Coyote HTTP/1.1 on http-8810 17-Jun-2010 12:13:37 PM org.apache.jk.common.ChannelSocket init INFO: JK: ajp13 listening on /0.0.0.0:8009 17-Jun-2010 12:13:37 PM org.apache.jk.server.JkMain start INFO: Jk running ID=0 time=0/22 config=null 17-Jun-2010 12:13:37 PM org.apache.catalina.startup.Catalina start INFO: Server startup in 446 ms My web.xml is: <?xml version="1.0" encoding="UTF-8"?> <web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> <listener> <listener-class>addressbook.util.SessionFactoryInitializer</listener-class> </listener> <filter> <filter-name>Session Interceptor</filter-name> <filter-class>addressbook.util.SessionInterceptor</filter-class> </filter> <filter-mapping> <filter-name>Session Interceptor</filter-name> <servlet-name>Country Manager</servlet-name> </filter-mapping> <servlet> <servlet-name>Country Manager</servlet-name> <servlet-class>addressbook.managers.CountryManagerServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>Country Manager</servlet-name> <url-pattern>/countrymanager</url-pattern> </servlet-mapping> </web-app> Can somebody either help me figure out what I am doing wrong? or point to some resource where I may get some precise solution of my problem?

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• No improvement in speed when using Ehcache with Hibernate

  - by paddydub

  I'm getting no improvement in speed when using Ehcache with Hibernate Here are the results I get when i run the test below. The test is reading 80 Stop objects and then the same 80 Stop objects again using the cache. On the second read it is hitting the cache, but there is no improvement in speed. Any idea's on what I'm doing wrong? Speed Test: First Read: Reading stops 1-80 : 288ms Second Read: Reading stops 1-80 : 275ms Cache Info: elementsInMemory: 79 elementsInMemoryStore: 79 elementsInDiskStore: 0 JunitCacheTest public class JunitCacheTest extends TestCase { static Cache stopCache; public void testCache() { ApplicationContext context = new ClassPathXmlApplicationContext("beans-hibernate.xml"); StopDao stopDao = (StopDao) context.getBean("stopDao"); CacheManager manager = new CacheManager(); stopCache = (Cache) manager.getCache("ie.dataStructure.Stop.Stop"); //First Read for (int i=1; i<80;i++) { Stop toStop = stopDao.findById(i); } //Second Read for (int i=1; i<80;i++) { Stop toStop = stopDao.findById(i); } System.out.println("elementsInMemory " + stopCache.getSize()); System.out.println("elementsInMemoryStore " + stopCache.getMemoryStoreSize()); System.out.println("elementsInDiskStore " + stopCache.getDiskStoreSize()); } public static Cache getStopCache() { return stopCache; } } HibernateStopDao @Repository("stopDao") public class HibernateStopDao implements StopDao { private SessionFactory sessionFactory; @Transactional(readOnly = true) public Stop findById(int stopId) { Cache stopCache = JunitCacheTest.getStopCache(); Element cacheResult = stopCache.get(stopId); if (cacheResult != null){ return (Stop) cacheResult.getValue(); } else{ Stop result =(Stop) sessionFactory.getCurrentSession().get(Stop.class, stopId); Element element = new Element(result.getStopID(),result); stopCache.put(element); return result; } } } ehcache.xml <cache name="ie.dataStructure.Stop.Stop" maxElementsInMemory="1000" eternal="false" timeToIdleSeconds="5200" timeToLiveSeconds="5200" overflowToDisk="true"> </cache> stop.hbm.xml <class name="ie.dataStructure.Stop.Stop" table="stops" catalog="hibernate3" mutable="false" > <cache usage="read-only"/> <comment></comment> <id name="stopID" type="int"> <column name="STOPID" /> <generator class="assigned" /> </id> <property name="coordinateID" type="int"> <column name="COORDINATEID" not-null="true"> <comment></comment> </column> </property> <property name="routeID" type="int"> <column name="ROUTEID" not-null="true"> <comment></comment> </column> </property> </class> Stop public class Stop implements Comparable<Stop>, Serializable { private static final long serialVersionUID = 7823769092342311103L; private Integer stopID; private int routeID; private int coordinateID; }

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• Hibernate - strange order of native SQL parameters

  - by Xorty

  Hello, I am trying to use native MySQL's MD5 crypto func, so I defined custom insert in my mapping file. <hibernate-mapping package="tutorial"> <class name="com.xorty.mailclient.client.domain.User" table="user"> <id name="login" type="string" column="login"></id> <property name="password"> <column name="password" /> </property> <sql-insert>INSERT INTO user (login,password) VALUES ( ?, MD5(?) )</sql-insert> </class> </hibernate-mapping> Then I create User (pretty simple POJO with just 2 Strings - login and password) and try to persist it. session.beginTransaction(); // we have no such user in here yet User junitUser = (User) session.load(User.class, "junit_user"); assert (null == junitUser); // insert new user junitUser = new User(); junitUser.setLogin("junit_user"); junitUser.setPassword("junitpass"); session.save(junitUser); session.getTransaction().commit(); What actually happens? User is created, but with reversed parameters order. He has login "junitpass" and "junit_user" is MD5 encrypted and stored as password. What did I wrong? Thanks EDIT: ADDING POJO class package com.xorty.mailclient.client.domain; import java.io.Serializable; /** * POJO class representing user. * @author MisoV * @version 0.1 */ public class User implements Serializable { /** * Generated UID */ private static final long serialVersionUID = -969127095912324468L; private String login; private String password; /** * @return login */ public String getLogin() { return login; } /** * @return password */ public String getPassword() { return password; } /** * @param login the login to set */ public void setLogin(String login) { this.login = login; } /** * @param password the password to set */ public void setPassword(String password) { this.password = password; } /** * @see java.lang.Object#toString() * @return login */ @Override public String toString() { return login; } /** * Creates new User. * @param login User's login. * @param password User's password. */ public User(String login, String password) { setLogin(login); setPassword(password); } /** * Default constructor */ public User() { } /** * @return hashCode * @see java.lang.Object#hashCode() */ @Override public int hashCode() { final int prime = 31; int result = 1; result = prime * result + ((null == login) ? 0 : login.hashCode()); result = prime * result + ((null == password) ? 0 : password.hashCode()); return result; } /** * @param obj Compared object * @return True, if objects are same. Else false. * @see java.lang.Object#equals(java.lang.Object) */ @Override public boolean equals(Object obj) { if (this == obj) { return true; } if (obj == null) { return false; } if (!(obj instanceof User)) { return false; } User other = (User) obj; if (login == null) { if (other.login != null) { return false; } } else if (!login.equals(other.login)) { return false; } if (password == null) { if (other.password != null) { return false; } } else if (!password.equals(other.password)) { return false; } return true; } }

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• Hibernate: Dirty Checking and Only Update of Dirty Attributes?

  - by jens

  Hello Experts, in "good old JDBC days" I wrote a lot of SQL Queries that did very targeted updates of only the "attributes/members" that were actually changed: For Example having an object with the following members: public String name; public String address; public Date date; If only date was changed in some Business Method I would only issue an SQL UPDATE for the date member. ==It seems however (thats my "impression" of hibernate) that when working with a standard Hibernate mapping (mapping the full class), even updates of only one single member lead to a full update of the object in SQL Statements generated by Hibernate. My Questions are: 1.) Is this observation correct, that hibernate DOES NOT intelligently check (in a fully mapped class), what member(s) where changed and then only issue updates for the specific changed members, but rather always will update (in the generated SQL Update Statement) all mapped members (of a class), even if they were not changed (in case the object is dirty due to one member being dirty...) 2.) What can I do to make Hibernate only update those members, that have been changed? I am searching for a solution to have hibernate only update the member that actually changed. (I know hibernate does some big work on doing dirty-checking, but as far as I know this dirtychecking is only relevant to identify if the object as whole is dirty, not what single member is dirty.) Thank you very much! Jens

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• Single Table Per Class Hierarchy with an abstract superclass using Hibernate Annotations

  - by Andy Hull

  I have a simple class hierarchy, similar to the following: @Entity @Table(name="animal") @Inheritance(strategy=InheritanceType.SINGLE_TABLE) @DiscriminatorColumn(name="animal_type", discriminatorType=DiscriminatorType.STRING) public abstract class Animal { } @Entity @DiscriminatorValue("cat") public class Cat extends Animal { } @Entity @DiscriminatorValue("dog") public class Dog extends Animal { } When I query "from Animal" I get this exception: "org.hibernate.InstantiationException: Cannot instantiate abstract class or interface: Animal" If I make Animal concrete, and add a dummy discriminator... such as @DiscriminatorValue("animal")... my query returns my cats and dogs as instances of Animals. I remember this being trivial with HBM based mappings but I think I'm missing something when using annotations. Can anyone help? Thanks!

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• Detach an entity from a JPA persistence context (JPA 2.0 / Hibernate / EJB 3 / J2EE 6)

  - by Julien

  Hi, I wrote a stateless EJB method allowing to get an entity in "read-only" mode. The way to do this is to get the entity with the EntityManager then detach it (using the JPA 2.0 EntityManager). My code is the following: @PersistenceContext private EntityManager entityManager; public T getEntity(int entityId, Class<T> specificClass, boolean readOnly) throws Exception{ try{ T entity = (T)entityManager.find(specificClass, entityId); if (readOnly){ entityManager.detach(entity); } return entity; }catch (Exception e){ logger.error("", e); throw e; } } Getting the entity works fine, but the call to the detach method returns the following error: GRAVE: javax.ejb.EJBException at ... Caused by: java.lang.AbstractMethodError: org.hibernate.ejb.EntityManagerImpl.detach(Ljava/lang/Object;)V at com.sun.enterprise.container.common.impl.EntityManagerWrapper.detach(EntityManagerWrapper.java:973) at com.mycomp.dal.MyEJB.getEntity(MyEJB.java:37) I can't get more information and don't understand what the problem is... Could somebody help ?

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• JPA/Hibernate and MySQL transaction isolation level

  - by armandino

  I have a native query that does a batch insert into a MySQL database: String sql = "insert into t1 (a, b) select x, y from t2 where x = 'foo'"; EntityTransaction tx = entityManager.getTransaction(); try { tx.begin(); int rowCount = entityManager.createNativeQuery(sql).executeUpdate(); tx.commit(); return rowCount; } catch(Exception ex) { tx.rollback(); log.error(...); } This query causes a deadlock: while it reads from t2 with insert .. select, another process tries to insert a row into t2. I don't care about the consistency of reads from t2 when doing an insert .. select and want to set the transaction isolation level to READ_UNCOMMITTED. How do I go about setting it in JPA backed by Hibernate?

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• org.hibernate.MappingException: No Dialect mapping for JDBC type: 2002

  - by Moli

  Hi at all, I'm having a issue trying to get working a JPA nativeQuery. I'm having a org.hibernate.MappingException: No Dialect mapping for JDBC type: 2002 when a try to do a nativeQuery and get a geometry field type. I use oracle and org.hibernatespatial.oracle.OracleSpatial10gDialect. The geom fields is mapped as: @Column(name="geometry") @Type(type = "org.hibernatespatial.GeometryUserType") private Geometry geometry; List<Object> listFeatures= new LinkedList<Object>(); Query query= entityManager.createNativeQuery( "SELECT "+ slots +" , geometry FROM edtem_features feature, edtem_dades dada WHERE" + " feature."+ tematic.getIdGeomField() +" = dada."+ tematic.getIdDataField()+ " AND dada.capesid= "+ tematic.getCapa().getId() + " AND feature.geometriesid= "+ tematic.getGeometria().getId()); listFeatures.addAll( query.getResultList()); Anybody knows a solution? or how to force the type of the geometry to get wroking this... MANY Thanks in advance. Moli

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• [hibernate - jpa ] good practices and bad practices

  - by blow

  Hi all, i have some questions about interaction with hibernate. openSession or getCurrentSession (without jta, thread insted)? How mix session operations with swing gui? Is good have something like this in a javabean class? public void actionPerformed(ActionEvent event) { // session code } Can i add methods to my entities that contains hql queries or is a bad practice? For example: // This method is in an entity MyOtherEntity.java class public int getDuration(){ Session session=HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); int sum=(Integer)session.createQuery("select sum(e.duration) as duration from MyEntity as e where e.myOtherEntity.id=:id group by e.name"). .setLong("id", getId()); .uniqueResult(); return sum; } In alternative how can i do this in a better and elegant way? Thanks.

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• Bean is not instantiating while using hibernate interceptor

  - by amit sharma

  I am using hibernate interceptor with spring framework,but when i pass a bean reference of DAO class its not instantiating the bean. My interceptor class has: private IMyService myService; // and getters and setters while application-context.xml having entries: <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> <property name="entityInterceptor" ref="logInterceptor"></property> </bean> <bean name="logInterceptor" class="com.amit.project.Utility.TableLogInterceptor" > <property name="myService" ref="myService"/> </bean> <bean name="myService" class="com.amit.project.service.impl.MyService"> But my bean is not instantiating in class, showing null. entityInterceptor is not allowing to do that or anything else? plz suggest a way if anybody knows.

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• Tips for resolving Hibernate/JPA EntityNotFoundException

  - by Damo

  I'm running into a problem with Hibernate where when trying to delete a group of Entities I encounter the following error: javax.persistence.EntityNotFoundException: deleted entity passed to persist: [com.locuslive.odyssey.entity.FreightInvoiceLine#<null>] These are not normally so difficult to track down as they are usually caused by an entity being deleted but not being removed from a Collection that it is a member of. In this case I have removed the entity from every list that I can think of (it's a complex datamodel). I've put JBoss logging into Trace and I can see the collections that are being cascaded. However I can't seem to find the Collection containing the entity that I'm deleting. Does anyone have any tips for resolving this particular Exception? Thanks.

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• Unique items in Hibernate collections

  - by Rickard Lindberg

  I have defined a collection in Hibernate like this: ... public class Item { ... @ElementCollection List<Object> relatedObjects; } It creates a mapping table with colums item_id and object_id. The problem is that object_id seems to be unique. In other words I can not have two different items being related to the same object. But that is what I want. I would like the combination of item_id and object_id to be unique. How do I do that?

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• Hibernate, EHCache, Read-Write cache, adding item to a list

  - by Walter White

  Hi all, I have an entity that has a collection in it. The collection is a OneToMany unidirectional relationship storing who viewed a particular file. The problem I am having is that after I load the entity and try to update the collection, I don't get any errors, but the collection is never updated: Entity: @OneToMany(cascade = CascadeType.PERSIST) @JoinTable protected List<User> users; File Servlet @In private EntityQuery<File> File_findById; ... File file = File_findById(fileId); file.getUsers().add(user); session.update(file); Even though I call session.update(file) and I see stuff in hibernate logs, I don't see anything in the database indicating that it was saved. Walter

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• NULL handling with subselect in Hibernate Criteria API

  - by Jens Schauder

  I'm constructing a Hibernate Criterion, using a subselect as follows DetachedCriteria subselect = DetachedCriteria.forClass(NhmCode.class, "sub"); // the subselect selecting the maximum 'validFrom' subselect.add(Restrictions.le("validFrom", new Date())); // it should be in the past (null needs handling here) subselect.add(Property.forName("sub.lifeCycle").eqProperty("this.id")); // join to owning entity subselect.setProjection(Projections.max("validFrom")); // we are only interested in the maximum validFrom Conjunction resultCriterion = Restrictions.conjunction(); resultCriterion.add(Restrictions.ilike(property, value)); // I have other Restrictions as well resultCriterion.add(Property.forName("validFrom").eq(subselect)); // this fails when validFrom and the subselect return NULL return resultCriterion; It works ok so far, but the restriction on the last line before the return statement is false when validFrom and subselect result in NULL. What I need is a version which handles this case as true. Possibly by applying a NVL or coalesce or similar. How do I do this?

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• Postgresql 8.4 reading OID style BLOBs with Hibernate

  - by peter

  I am getting this weird case when querying Postgres 8.4 for some records with Blobs (of type OIDs) with Hibernate. The query does return all right but when my code wants to read the content of the BLOB with the simple code below, it gets 0 bytes back public static byte[] readBlob(Blob blob) throws Exception { InputStream is = null; try { is = blob.getBinaryStream(); return org.apache.commons.io.IOUtils.toByteArray(is); } finally { if (is != null) try { is.close(); } catch(Exception e) {} } } Funny think is that I am getting this behavior only since I've started adding more then one such records to the table. The underlying JDBC library is type 3 (postgresq 8.4-701). Can someone give me a hint as to how to solve this issue? Thanks Peter

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• Hibernate configuration files not found by Axis2

  - by DanJo519

  I am writing a web service to be deployed on Tomcat using Axis2. I am using Hibernate3 to persist data between the web service and a MySQL database. When running the application through by IDE, the method I am exposing through Axis2 works as intended, however when I deploy the .aar to Tomcat, I receive a SOAP Error claiming that hibernate.cfg.xml cannot be found. However, inside the .aar, I clearly see that all the configuration file and all the mapping files are included. I have determined a workaround: If I place the resulting files from the Netbeans build/class folder into the axis2/WEB-INF/class folder, then the application works as expected. My question, then, is is there a better way to deploy my application so that Axis2 will pick up the configuration and mapping files through the deployed .aar without my manually having to copy the contents of the build/class folder into the axis2/WEB-INF/class folder?

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