Search Results

Search found 1096 results on 44 pages for 'never quit'.

Page 27/44 | < Previous Page | 23 24 25 26 27 28 29 30 31 32 33 34  | Next Page >

• Why do my Xcode default font starts to look ugly after some time, until I restart?

  - by mystify

  I plugged in an external monitor. All resolutions match perfectly. MacBookPro LCD is closed. After about 10 minutes my fonts in Xcode start to look very bad. Only in Xcode. When I restart the mac and don't use an external monitor, fonts look all right again. When I attach the monitor again, fonts look nice. Then I close XCode and reopen it: Fonts suck. All other fonts look great. It seems like Xcode isn't antialiasing them properly after something happens. For my observation it happens when I quit and reopen Xcode while an external monitor is in use. Only way to fix it then is to completely reboot. Is there a fix for this problem?

  Read the article

• Git in terminal

  - by goodcow

  I tried making my first repo on github. I copy pasted their code while on the directory of my entire system (I think that was a mistake). As a result, the terminal line always says ~ git:(master) ? before every command. It does not go away even when I quit terminal. I am using zsh. The code I pasted was: touch README.md git init git add README.md git commit -m "first commit" git remote add origin https://github.com/***/***.git git push -u origin master On top of that, I can't even seem to figure out how to add my files to the repo. Help on how to not always have git:(master) before every bash command and how to make a repo? Thanks!

  Read the article

• Saving Excel Spreadsheet using Interop C#

  - by Wesley

  static void Main() { Application excelapp = new Application(); Workbook book = excelapp.Workbooks.Open(@"C:\HWYFAB.xlsx", 0, false, 5, "", "", false, XlPlatform.xlWindows , "", true, false, 0, true, false, false); Worksheet sheet = (Worksheet)book.Sheets[1]; Range cell = (Range)sheet.Cells[3, 2]; Console.WriteLine(cell.Text); cell.ClearContents(); book.Close(true, "HWYFAB.xlsx", false); excelapp.Quit(); } This program runs and exits as expected. It does print the correct value that's in cell B3 to the console. When closing it asks if I want to replace the existing file. I click yes. When I open the spreadsheet in Excel, the value is still in cell B3 despite the cell.ClearContents(). Any thoughts?

  Read the article

• Is it possible to create a jdbc connection without a password (using postgresql 'trust')?

  - by mojones

  I am using jdbc to connect to a postgresql database in a java application (actually the app is written in Groovy). I have postgresql set up to use the 'trust' authentication method. Is it possible to open a jdbc connection without specifying a password? When I try to use the normal constructor with a blank password, it fails with Exception in thread "Thread-2" org.postgresql.util.PSQLException: FATAL: password authentication failed for user "myuser" Even though, from the command line, this works fine psql -U myuser mydatabase Welcome to psql 8.3.5, the PostgreSQL interactive terminal. Type: \copyright for distribution terms \h for help with SQL commands \? for help with psql commands \g or terminate with semicolon to execute query \q to quit

  Read the article

• Windows Forms Unhandled-Exception Dialog

  - by Michael

  I want to get Default Windows Forms Unhandled-Exception Dialog whenever my C# application encounters U-E. In vs 2005 when I turn off jit Debugging in app.conf like this: <configuration> <system.windows.forms jitDebugging="false" /> <configuration> the application behaves correctly and shows Windows Forms U-E default dialog, with Continue, Quit, call stack and all. However in vs 2008, on the same machine or different, even though I diable jit I still get Default .NET Unhandled-Exception Dialog, with Debug, Send Report and Don't Send buttons. How can I make my vs 2008 app act like the one I make in vs 2005, to show Windows Forms U-E dialog box? Please do not recommend to use AppDomain.CurrentDomain.UnhandledException += new UnhandledExceptionEventHandler(CurrentDomain_UnhandledException); just because I don't use custom handler in my vs 2005 project, why would I use in vs 2008? I want to let this job do CLR. Any help is appreciated

  Read the article

• What can cause the language bar to disappear in a win32 application?

  - by user4484

  When I run my Win32 application the Windows language bar (which is visible in all other applications) disappears after about 5 seconds. It reappears if I quit my application or alt-tab to a different application. If I alt-tab back into my application, it disappears again after five seconds. The switch key doesn't work either. It seems as if the system somehow has concluded that my application doesn't "support" the language bar. Is there something I need to do to for the language bar to be enabled? Or something I shouldn't be doing that can cause it to disappear? The application has a single custom window (where I draw DirectX graphics). I've looked through the arguments to CreateWindow and RegisterClass as well as the window messages that I handle (instead of passing to DefWindowProc) but nothing seems to be directly related to the language bar. I've only tested this on Windows 7.

  Read the article

• C++: Why does space always terminate a string when read?

  - by Nullw0rm

  Using type std::string to accept a sentence, for practise (I haven't worked with strings in C++ much) I'm checking if a character is a vowel or not. I got this: for(i = 0; i <= analyse.length(); i++) { if(analyse[i] == 'a' || analyse[i] == 'e' [..etc..]) { ...vowels++; } else { ... ...consenents++; } This works fine if the string is all one word, but the second I add a space (IE: aeio aatest) it will only count the first block and count the space as a consenent, and quit reading the sentence (exiting the for loop or something). Does a space count as no character == null? Or some oddity with std::string?, It would be helpful to know why that is happening!

  Read the article

• NSCurrentLocaleDidChangeNotification on iPhone OS

  - by 0xced

  While the NSCurrentLocaleDidChangeNotification perfectly makes sense on Mac OS X, I don't see how you can possibly receive it on iPhone OS. In order to change the locale, you have to quit the running application, then change it in Settings ? General ? International ? Region Format. At that point, your app is not running, so how could it receive the notification? I first thought this notification was leftover from the Mac OS X documentation, but then I found this in Apple Push Notification Service Programming Guide: The application might send its provider the preferred language every time the user changes something in the current locale. To do this, you can listen for the notification named NSCurrentLocaleDidChangeNotification and, in your notification-handling method, get the code identifying the preferred language and send that to your provider. So, how do you trigger this notification on iPhone OS?

  Read the article

• Will Emacs --batch run in cron will hang when require user input?

  - by J Spen

  I have a job in crontab that requires emacs --batch but if the file is currently open it requests (s, p, q) to (steal, quit, etc...) which is fine if this file is being edited to not run the script but I want to make sure it kills the cron running script so it's not sitting in the background taking up memory. I have the output set to go to a log file so I can see this happening but no way to tell whether the script was terminated even though asked for user input. Does cron terminate these scripts and how to check the PID to make sure?

  Read the article

• JQuery: After adding some AJAX, some of the jquery code no longer works

  - by fwaokda

  Here's a pastebin link to my entire jQuery code. [ http://pastebin.com/w57ma5Gx ] The "Thumbnails" section was working fine before I added the ajax sections. Anyone can help me with why it quit working? And if I need to I can post another question but figured I'd try it here first. Whats a better way of writing the ajax code where it executes once upon loading the page and then every time I click the $("a#next") link afterwards? Right now I just repasted the code outside of the next link and that works, but seems silly to have the same code in two different places like that. Thanks!

  Read the article

• Prism : Add a window in a region

  - by esylvestre

  Hi, I'm new working with Prism with WPF, and I have a question which I can't find answer. Why it is impossible to add a window in a Region ? I can understand there's a good reason, so I will need another solution to my problem. It is quite simple, I got a LoginView (Window) which I want to appear first. For the previous reason, in my Region, I added a MainView (UserControl) where I just show my LoginView on the Loaded event. The problem if the user quit the application or if he cancels his login, the MainView is still showing up. It seems a stupid problem, but I can't find a smart solution. Thanks for your time.

  Read the article

• poplib and email module will not reloop through a message if it has alread read it

  - by user1440925

  I'm currently trying to write a script that gets messages from my gmail account but I'm noticing a problem. If poplib loops through a message in my inbox it will never loop through it again. Here is my code import poplib, string, email user = "[email protected]" password = "p0ckystyx" message = "" mail = poplib.POP3_SSL('pop.gmail.com') mail.user(user) mail.pass_(password) iMessageCount = len(mail.list()[1]) message = "" msg = mail.retr(iMessageCount) str = string.join(msg[1], "\n") frmMail = email.message_from_string(str) for part in frmMail.walk(): if part.get_content_type() == "text/plain": print part.get_payload() mail.quit() Every time I run this script it goes to the next newest email and just skips over the email that was shown last time it was run.

  Read the article

• How can i pass an object to a new thread generated anonymously in a button listener

  - by WaterBoy

  I would like to pass an object (docket for printing) to a new thread which will print the docket. My code is: private final Button.OnClickListener cmdPrintOnClickListener = new Button.OnClickListener() { public void onClick(View v) { new Thread(new Runnable() { public void run() { enableTestButton(false); Looper.prepare(); doConnectionTest(); Looper.loop(); Looper.myLooper().quit(); } }).start(); } }; How do I pass the object to it? Also - I need to generate the object in the UI thread, just before starting the new thread so where could I put this method (e.g. getDocketObject()) in relation to my code below thanks, anton

  Read the article

• Is there an autorelease pool in class methods?

  - by mystify

  I have an class method which generates an UIView, like this: + (UIImage*)imageWithFileName:(NSString*)imgFile { UIImage *img = nil; NSBundle *appBundle = [NSBundle mainBundle]; NSString *resourcePath = [appBundle pathForResource:imgFile ofType:nil]; if (resourcePath != nil) { NSURL *imageURL = [NSURL fileURLWithPath:resourcePath]; NSData *data = [[NSData alloc] initWithContentsOfURL:imageURL]; img = [UIImage imageWithData:data]; // should be autoreleased!! [data release]; } return img; } However, when I use this, the image data is NEVER freed. There is definitely a memory bug with this, although I didn't break any memory management rule I am aware of. My guess is that because this is a class method which gets called from instance methods, There is no active autorelease pool in place or it's one that only gets drained when I quit the app. Could that be right?

  Read the article

• Batch Script [Loop through file names]

  - by Kyl3

  Hi, I would like a batch script to all the text documents in a folder. This is what I have managed so far @ECHO off title Test set dir1=C:\Users\Family\Desktop\Example :Start cls echo 1. test loop echo 2. Quit set /p choice=I choose (1,2): if %choice%==1 goto test if %choice%==2 exit :test cls echo running loop test FOR %%n in (%dir1% *.txt) DO echo %dir1%\%%n echo Done pause What I would like outputted is running loop test C:\Users\Family\Desktop\Example\doc 1.txt C:\Users\Family\Desktop\Example\doc 2.txt Done But I Get this running loop test C:\Users\Family\Desktop\Example\C:\Users\Family\Desktop\Example C:\Users\Family\Desktop\Example\doc 1.txt C:\Users\Family\Desktop\Example\doc 2.txt Done Thanks in advance Kyle

  Read the article

• program to determine number of duplicates in a sentence

  - by bhavna raghuvanshi

  public class duplicate { public static void main(String[] args)throws IOException { System.out.println("Enter words separated by spaces ('.' to quit):"); Set<String> s = new HashSet<String>(); Scanner input = new Scanner(System.in); while (true) { String token = input.next(); if (".".equals(token)) break; if (!s.add(token)) System.out.println("Duplicate detected: " + token); } System.out.println(s.size() + " distinct words:\n" + s); } } my program detects and prints duplicate words but i need to print the number of duplicate words also. pls help me do it.

  Read the article

• When should we use * and & and . and -> ?

  - by uzay95

  Why we are using * character when we are creating button but we aren't adding it to app instance? #include <QApplication> #include <QPushButton> int main(int argc,char *argv[]) { QApplication app(argc,argv); QPushButton *button = new QPushButton("Button Text"); QObject::connect(button,SIGNAL(clicked()),&app,SLOT(quit())); button->show(); return app.exec(); } When should we use * and & and . and - ?

  Read the article

• Whats wrong with this C program?

  - by Prab

  It should give me the number of inputs entered by the user. But it gives 100. I compiled with gcc. #include <stdio.h> int arr[100]; int count=0; int max=100; int main(){ int i, input; printf("Enter integer values one by one, q to quit.\n"); for(i=0;i<max;i++){ scanf("%d",&input); arr[i]=input; if(input=='q')break; count++; } printf("You entered %d values.\n",count); return 0; }

  Read the article

• Running the script for the 2-nd time, the messages are not retrieved from the mail server

  - by Max Li

  I read the mails from my gmail account with the code following below. import poplib pop_conn = poplib.POP3_SSL('pop.gmail.com') pop_conn.user('user') # result: '+OK send PASS' pop_conn.pass_('password') # result: '+OK Welcome.' print pop_conn.list()[1] pop_conn.quit() It shows me 1 message as expected. However, if I run this script for the second time, I get 0 messages as result. On the server the message is still there and unread. How can I get all the messages also running the script for the second time? For me it behaves as an email client that doesn't download the same mail twice. Is there some flag to force the program to download everything again? I use python 2.7.x on ubuntu 12.10

  Read the article

• why number 9 in kill -9 command in unix?

  - by Alby

  I understand it's off topic, I couldn't find anywhere online and I was thinking maybe programming gurus in the community might know this. I usually use kill -9 pid to kill the job. I always wondered the origin of 9. I looked it up online, and it says "9 Means KILL signal that is not catchable or ignorable. In other words it would signal process (some running application) to quit immediately" (source: http://wiki.answers.com/Q/What_does_kill_-9_do_in_unix_in_its_entirety) But, why 9? and what about the other numbers? is there any historical significance or because of the architecture of Unix? Thanks!

  Read the article

• Checking for an "end of line" in a C-string

  - by Numerator

  I would really love your help with the following problem: I want to get as an input from the user a maximum length of 30 chars string and check whether it contains an end of line. This is what I tried to write so far: int main(void) { int i; char* command = (char*)calloc(31, sizeof(char)); while (0 < 1) { scanf("%s", command); for (i = 0; i <= strlen(command); ++i) { if (command[i] == '\n') printf("here"); } if (strcmp(command, "quit") == 0) break; } The idea is to check whether the command given by the user as input is "legal" - that is of length < 31. when i run this code, it never prints "here" regardless of the length of input.

  Read the article

• How to break a loop when inputting unspecified raw_input?

  - by user1874510

  I want to write an interface using a while loop and raw_input. My code looks like this: while True: n = raw_input("'p' = pause, 'u' = unpause, 'p' = play 's' = stop, 'q' = quit) if n.strip() == 'p': mp3.pause() if n.strip() == 'u': mp3.unpause() if n.strip() == 'p': mp3.play() if n.strip() == 's': mp3.stop() if n.strip() == 'q': break But I want it to break if I input anything that isn't specified in the raw_input. if not raw_input: break Returns and IndentationError: unindent does not match any outer indentation level. if not raw_input: break Does not return any error but doesn't work as I want it to. As far as I know, it does nothing at all. Also, if there's a cleaner way to write my loop, I love to hear it.

  Read the article

• Failure retrieving contents of directory

  - by Bondye

  Currently I have a couple of websites. My problem is that if I login on 1 specific domain with any of my programs (using notepadd++, FileZilla and Netbeans) the program stops at the content listing. I had it correctly running, (I'm working on a project on this domain for more than a year now) and suddenly I broke it somehow. This only happens on 1 specific domain, all other domains (from other hosts) are working. My colleague (next to me with same ip address) is able to login on this domain. Notepadd++ says: Failure retrieving contents of directory Filezilla says: Failed to retrieve directory listing Netbean popups: Upload files on save failed. (Because I have the setting upload on save enabled.) What I tried: First I thought it's my firewall, I disabled firewall but no result. Also notice that all other domain are working. Maby a blacklist with my ip address? No my colleague has the same ip address. Could anyone help me on this? Notepad++ Log [NppFTP] Everything initialized -> TYPE I Connecting -> Quit 220 ProFTPD 1.3.3e Server ready. -> USER username 331 Password required for domain -> PASS *HIDDEN* 230 User username logged in -> TYPE A 200 Type set to A -> MODE S 200 Mode set to S -> STRU F 200 Structure set to F -> CWD /domains/domain.nl/ 250 CWD command successful Connected -> CWD /domains/domain.nl/ 250 CWD command successful -> PASV 227 Entering Passive Mode (194,247,31,xx,137,xx). -> LIST -al Failure retrieving contents of directory /domains/domain.nl/ Filezilla log Status: Verbinden met 194.247.xx.xx:21... Status: Verbinding aangemaakt, welkomstbericht afwachten... Antwoord: 220 ProFTPD 1.3.3e Server ready. Commando: USER username Antwoord: 331 Password required for username Commando: PASS ******** Antwoord: 230 User username logged in Commando: SYST Antwoord: 215 UNIX Type: L8 Commando: FEAT Antwoord: 211-Features: Antwoord: MDTM Antwoord: MFMT Antwoord: LANG en-US;ja-JP;zh-TW;it-IT;fr-FR;zh-CN;ru-RU;bg-BG;ko-KR Antwoord: TVFS Antwoord: UTF8 Antwoord: AUTH TLS Antwoord: MFF modify;UNIX.group;UNIX.mode; Antwoord: MLST modify*;perm*;size*;type*;unique*;UNIX.group*;UNIX.mode*;UNIX.owner*; Antwoord: PBSZ Antwoord: PROT Antwoord: REST STREAM Antwoord: SIZE Antwoord: 211 End Commando: OPTS UTF8 ON Antwoord: 200 UTF8 set to on Status: Verbonden Status: Mappenlijst ophalen... Commando: PWD Antwoord: 257 "/" is the current directory Commando: TYPE I Antwoord: 200 Type set to I Commando: PASV Antwoord: 227 Entering Passive Mode (194,247,31,xx,xxx,xx). Commando: MLSD Fout: Verbinding verloren Fout: Ontvangen van mappenlijst is mislukt Sorry that it's dutch.

  Read the article

• Turn Non-Resizeable Windows into Rezieable Windows

  - by Asian Angel

  Are you frustrated with Windows app windows that can not be resized at all? Now you can apply some “attitude adjustment” and resize those windows with ResizeEnable. Before Everyone is familiar with the many app windows in their Windows OS that simply can not be resized. What you need is cooperation, not attitude. For our example we chose the “Taskbar and Start Menu Properties Window”…notice the cursor in the lower right corner. No resizing satisfaction available at all… After The program comes in a zip file with three files as shown here. Once you have unzipped the program place it in an appropriate “Program Files Folder”, create a shortcut, and you are ready to go. There will be a “System Tray Icon” with only two “Context Menu” items…“About & Quit”. Here is a quick look at the “About Window” that tells you exactly what ResizeEnable does. Notice that it does state that you may occasionally have a window that may not respond correctly. Now back to our “Taskbar and Start Menu Properties Window”. Notice the resizing cursor in the lower right corner….time for some fun! During our test the “Taskbar and Start Menu Properties Window” was suddenly a dream to resize. Daring to stretch the window even further…now that is what you call “stretching” the window out in comparison to its’ original size! Think of all the windows that will be much easier to work with now… Conclusion If you have been frustrated with non-resizeable windows then ResizeEnable will certainly bring a smile to your face as you watch those windows suddenly become a lot more cooperative. This is definitely one app that is worth adding to your system. Links Download ResizeEnable (zip file) Similar Articles Productive Geek Tips Quick Tip: Resize Any Textbox or Textarea in FirefoxTurn on Remote Desktop in Windows 7 or VistaSave 1-4% More Battery Life With Windows Vista Battery SaverQuick Tip: Disable Search History Display in Windows 7Turn Off Windows Explorer Click Sounds in Windows 7 or Vista TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional New Stinger from McAfee Helps Remove ‘FakeAlert’ Threats Google Apps Marketplace: Tools & Services For Google Apps Users Get News Quick and Precise With Newser Scan for Viruses in Ubuntu using ClamAV Replace Your Windows Task Manager With System Explorer Create Talking Photos using Fotobabble

  Read the article

• Best development architecture for a small team of programmers

  - by Tio

  Hi all.. I'm in the first month of work in a new company.. and after I met the two programmer's and asked how things are organized in terms of projects inside the company, they simply shrug their shoulders, and said that nothing is organized.. I think my jaw hit the ground that same time.. ( I know some, of you think I should quit, but I'm on a privileged position, I'm the most experienced there, so there's room for me to grow inside the company, and I'm taking the high road ).. So I talked to the IT guy, and one of the programmers, and maybe this week I'm going to get a server all to myself to start organizing things. I've used various architectures in my previous work experiences, on one I was developing in a server on the network ( no source control of course ).. another experience I had was developing in my local computer, with no server on the network, just source control. And at home, I have a mix of the two, everything I code is on a server on the network, and I have those folders under source control, and I also have a no-ip account configured on that server so I can access it everywhere and I can show the clients anything. For me I think this last solution ( the one I have at home ) is the best: Network server with LAMP stack. The server as a public IP so we can access it by domain name. And use subdomains for each project. Everybody works directly on the network server. I think the problem arises, when two or more people want to work on the same project, in this case the only way to do this is by using source control and local repositories, this is great, but I think this turns development a lot more complicated. In the example I gave, to make a change to the code, I would simply need to open the file in my favorite editor, make the change, alter the database, check in the changes into source control and presto all done. Using local repositories, I would have to get the latest version, run the scripts on the local database to update it, alter the file, alter the database, check in the changes to the network server, update the database on the network server, see if everything is running well on the network server, and presto all done, to me this seems overcomplicated for a change on a simple php page. I could share the database for the local development and for the network server, that sure would help. Maybe the best way to do this is just simply: Network server with LAMP stack ( test server so to speak ), public server accessible trough the web. LAMP stack on every developer computer ( minus the database ) We develop locally, test, then check in the changes into the server test and presto. What do you think? Maybe I should start doing this at home.. Thanks and best regards...

  Read the article

< Previous Page | 23 24 25 26 27 28 29 30 31 32 33 34  | Next Page >