Search Results

Search found 25400 results on 1016 pages for 'enable manual correct'.

Page 272/1016 | < Previous Page | 268 269 270 271 272 273 274 275 276 277 278 279  | Next Page >

  • Time complexity of a certain program

    - by HokageSama
    In a discussion with my friend i am not able to predict correct and tight time complexity of a program. Program is as below. /* This Function reads input array "input" and update array "output" in such a way that B[i] = index value of nearest greater value from A[i], A[i+1] ... A[n], for all i belongs to [1, n] Time Complexity: ?? **/ void createNearestRightSidedLargestArr(int* input, int size, int* output){ if(!input || size < 1) return; //last element of output will always be zero, since no element is present on its right. output[size-1] = -1; int curr = size - 2; int trav; while(curr >= 0){ if(input[curr] < input[curr + 1]){ output[curr] = curr + 1; curr--; continue; } trav = curr + 1; while( input[ output [trav] ] < input[curr] && output [trav] != -1) trav = output[trav]; output[curr--] = output[trav]; } } I said time complexity is O(n^2) but my friend insists that this is not correct. What is the actual time complexity?

    Read the article

  • Mysql Syntax :You have an error in your SQL syntax....

    - by jasmine
    I have written very very very!!! simple function: function editCategory() { $ID = urlencode($_GET['id']); $cname = mysql_fix_string($_POST['cname']); $kabst = mysql_fix_string($_POST['kabst']); $kselect = $_POST['kselect']; $subsl = $_POST['subsl']; $kradio = $_POST['kradio']; $ksubmit = $_POST['ksubmit']; if (isset($ksubmit)) { $query = "UPDATE category SET name = '$cname', description = '$kabst', published = '$kselect', home = '$kradio', subcat = '$subsl' WHERE id = $ID "; $result = mysql_query($query); if (mysql_affected_rows () == 1) { echo "ok"; } else{ echo mysql_error(); } } } error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 what is wrong? :(

    Read the article

  • object not found error with dynamic web forms with (jquery) javscript script

    - by deostroll
    In a normal aspx page I've set up a jquery tab system. When a particular tab shows up I wire up an ajax call to get another html page with the following content. It is simply a form with some javascript inside of it. <!-- demo.htm --> <form method="post" action="post.aspx"> <div id="fields"> Class: <input id="txtclass" name="txtclass" type="text"/> Grade: <input id="txtgrade" name="txtgrade" type="text"/> <input id="btnupdate" value="Update"/> </div> <div id="update"> Reason:<br/> <input id="txtreason" name="txtreason" type="text"/> <br/> Comments:<br/> <textarea id="txtcomments" name="txtcomments"></textarea> <br/> <input type="button" id="btnsave" value="Save"/> </div> <script type="text/javascript"> $(function(){ //all textboxes should be disabled $('#fields input').each(function(i,j){ if(! $(this).is(':button') ) $(this).attr('disabled', 'disabled') }); //update div should be hidden $('#update).hide(); //click event of btnupdate should // be set to show the update div contents // and enable input fields $('#btnupdate').click(function(){ //enable all textboxes $('#fields input').each(function(i,j){ $(this).attr('disabled', ''); }); //hide btnupdate $('#btnupdate').hide(); //show div update $('#update').show(); }); }); </script> </form> The script executes normally and the form is shown as intended. The btnupdate is supposed to show the contents in the update div and load the form for accepting user input. Whenever I hit btnupdate button I get an object not found exception on IE 8. IE 8 asks if it should start up its in-built debuggger. But, even in this debugger I cannot see what the problem is...However on clicking "No" in that dialog the button click function executes properly, and the form is displayed as intended. Is there a better way to resolve the problem?

    Read the article

  • Calling a SLSB with Seam security from a servlet

    - by wilth
    Hello, I have an existing application written in SEAM that uses SEAM Security (http://docs.jboss.org/seam/2.1.1.GA/reference/en-US/html/security.html). In a stateless EJB, I might find something like this: @In Identity identity; ... if(identity.hasRole("admin")) throw new AuthException(); As far as I understand, Seam injects the Identity object from the SessionContext of the servlet that invokes the EJB (this happens "behind the scenes", since Seam doesn't really use servlets) and removes it after the call. Is this correct? Is it now possible to access this EJB from another servlet (in this case, that servlet is the server side of a GWT application)? Do I have to "inject" the correct Identity instance? If I don't do anything, Seam injects an instance, but doesn't correctly correlate the sessions and instances of Identity (so the instances of Identity are shared between sessions and sometimes calls get new instances etc.). Any help and pointers are very welcome - thanks! Technology: EJB3, Seam 2.1.2. The servlets are actually the server-side of a GWT app, although I don't think this matters much. I'm using JBoss 5.

    Read the article

  • Difference between normal and magic setters and getters

    - by Saif Bechan
    I am using a magic getter/setter class for my session variables, but I don't see any difference between normal setters and getters. The code: class session { public function __set($name, $value) { $_SESSION[$name] = $value; } public function __unset($name) { unset($_SESSION[$name]); } public function __get($name) { if(isset($_SESSION[$name])) { return $_SESSION[$name]; } } } Now the first thing I noticed is that I have to call $session->_unset('var_name') to remove the variable, nothing 'magical' about that. Secondly when I try to use $session->some_var this does not work. I can only get the session variable using $_SESSION['some_var']. I have looked at the PHP manual but the functions look the same as mine. Am I doing something wrong, or is there not really anything magic about these functions.

    Read the article

  • NSMutableObject from existing custom class

    - by A.S.
    Hello there. I have an existing class that has methods to deserialise from XML in my code. Now I need to create correct CoreData model from that class. It's objects will be created not only from CoreData storage but also by deserializing XML (somehow like instance->title = [[NSString stringWithUTF8String: (const char *)subNode->children->content] retain; ) without saving to CoreData, and sometimes I need to save it. What is the correct steps to modify existing class to do that except of adding CoreData framework and making my class an NSManagedObject instead of NSObject? Class sample: @interface TSTSong : NSManagedObject<NTSerializableObject> { NSString *identifier; NSString *title; float length; NSURL *previewURL; NSString *author; NSURL *coverURL; NSString *appStoreId; BOOL isPurchased; NSURL *bannerURL; NSDecimalNumber *priceValue; NSLocale *priceLocale; } P.S. I'm noob, so I'f I'm doing smth. wrong - please let me know. Sorry for my english.

    Read the article

  • FTP in NetBeans 6.1

    - by Ross
    Is there an FTP browser hiding away in NetBeans 6.1? The help manual doesn't even suggest FTP exists. All I've been able to find so far is a tree viewer in the Services panel (no edit controls) and the ability to upload projects, folders and specific files from the Projects/Files views. Is there anywhere to delete or rename or will I have to keep switching back to my browser? I can see from the previews that there's a nice FTP controller in 6.5 but I'm not desperate enough to completely convert to a beta (yet).

    Read the article

  • Factory Method Pattern clarification

    - by nettguy
    My understanding of Factory Method Pattern is (Correct me if i am wrong) Factory Method Pattern "Factory Method allow the client to delegates the product creation (Instance Creation) to the subclass". There are two situation in which we can go for creating Factory Method pattern. (i) When the client is restricted to the product (Instance) creation. (ii) There are multiple products available.But a decision to be made which product instance need to be returned. If you want to create Abstract Method pattern You need to have abstract product Concrete Product Factory Method to return the appropriate product. Example : public enum ORMChoice { L2SQL, EFM, LS, Sonic } //Abstract Product public interface IProduct { void ProductTaken(); } //Concrete Product public class LinqtoSql : IProduct { public void ProductTaken() { Console.WriteLine("OR Mapping Taken:LinqtoSql"); } } //concrete product public class Subsonic : IProduct { public void ProductTaken() { Console.WriteLine("OR Mapping Taken:Subsonic"); } } //concrete product public class EntityFramework : IProduct { public void ProductTaken() { Console.WriteLine("OR Mapping Taken:EntityFramework"); } } //concrete product public class LightSpeed : IProduct { public void ProductTaken() { Console.WriteLine("OR Mapping Taken :LightSpeed"); } } public class Creator { //Factory Method public IProduct ReturnORTool(ORMChoice choice) { switch (choice) { case ORMChoice.EFM:return new EntityFramework(); break; case ORMChoice.L2SQL:return new LinqtoSql(); break; case ORMChoice.LS:return new LightSpeed(); break; case ORMChoice.Sonic:return new Subsonic(); break; default: return null; } } } **Client** Button_Click() { Creator c = new Creator(); IProduct p = c.ReturnORTool(ORMChoice.L2SQL); p.ProductTaken(); } Is my understanding of Factory Method is correct?

    Read the article

  • Using MySQL as data source in Microsoft SQL Server Analysis Services

    - by coldilocks
    Hi, I have installed the latest .net connector (http://www.mysql.com/downloads/connector/net/), I can add MySQL databases as Data Sources, I can even browse through the data from Business Intelligence Studio. The problem is that I CANNOT create a datasource view, or if I do create one without tables, trying to add them after the fact gives me the same error. Specifically it looks like the data source view wizard tries to submit queries against the MySQL database using square brackets/braces, and the query bombs. I get an error message like: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '[my_db].[cheatType]' at line 2 So, in summary, has anyone been able to create a data source view using MySQL tables and, if so, can they please show me how this can be done. Thanks for any help!

    Read the article

  • mcrypt_decrypt return strange code

    - by Jin Yong
    I tried to encrypt an array then decrypt it back to string by calling a function, it's seem return the correct value if I does all encrypt and decrypt at once time in the function, however, if I return the encrypt value, then call the function again to decrypt it will return me some strange code. Exmaple: public main() { $dataArray = array("one"=>1, "two"=>2, "three"=>3); $a = $this->encryptDecryptInfo(json_encode($dataArray),$this->key); var_dump($a); } public function encryptDecryptInfo($text,$key) { $iv = mcrypt_create_iv(mcrypt_get_iv_size(MCRYPT_RIJNDAEL_256, $text= base64_encode(mcrypt_encrypt(MCRYPT_RIJNDAEL_256, $key, $text, MCRYPT_MODE_CFB, $iv)); return mcrypt_decrypt(MCRYPT_RIJNDAEL_256, $key, base64_decode($text), MCRYPT_MODE_CFB, $iv); } This will return me the correct value which is string(27) "{"one":1,"two":2,"three":3}" Exmaple 2: public main() { $dataArray = array("one"=>1, "two"=>2, "three"=>3); $a = $this->encryptDecryptInfo(json_encode($dataArray),$this->key,"encrypt"); $b = $this->encryptDecryptInfo($a,$this->key,"decrypt"); var_dump($b); } public function encryptDecryptInfo($text,$key,$type) { $iv = mcrypt_create_iv(mcrypt_get_iv_size(MCRYPT_RIJNDAEL_256, MCRYPT_MODE_CFB), MCRYPT_RAND); if($type == "encrypt") return base64_encode(mcrypt_encrypt(MCRYPT_RIJNDAEL_256, $key, $text, MCRYPT_MODE_CFB, $iv)); else return mcrypt_decrypt(MCRYPT_RIJNDAEL_256, $key, base64_decode($text), MCRYPT_MODE_CFB, $iv); } However if I do my code in this way, it will return me strange value which is like this string(27) "?ÔérôŸY éXgíœÈÐN*é౜CµÖ" .Deos anyone know why this is happen?

    Read the article

  • Pushing to a UITable inside a UIView from a UITableview

    - by Michael Robinson
    I can firgure out how to push a UIView from a Tableview and have the "child" details appear. Here is the view I'm trying to load: Here is the code that checks for children and either pushes a itemDetail.xib or an additional UITable, I want to use the above .xib but load the correct contents "tableDataSource" into the UItable: - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { //Get the dictionary of the selected data source. NSDictionary *dictionary = [self.tableDataSource objectAtIndex:indexPath.row]; //Get the children of the present item. NSArray *Children = [dictionary objectForKey:@"Children"]; if([Children count] == 0) { ItemDetailViewController *dvController = [[ItemDetailViewController alloc] initWithNibName:@"ItemDetailView" bundle:[NSBundle mainBundle]]; [self.navigationController pushViewController:dvController animated:YES]; [dvController release]; } else { //Prepare to tableview. FirstTab *rvController = [[FirstTab alloc] initWithNibName:@"FirstView" bundle:[NSBundle mainBundle]]; //Increment the Current View rvController.CurrentLevel += 1; //Set the title; rvController.CurrentTitle = [dictionary objectForKey:@"Title"]; //Push the new table view on the stack [self.navigationController pushViewController:rvController animated:YES]; rvController.tableDataSource = Children; [rvController release]; } } Thanks for the help. I see lots of stuff on this but can't find the correct push instructions.

    Read the article

  • What is the prefered or accepted method for testing proxy settings?

    - by Mike Webb
    I have a lot of trouble with the internet connectivity in the program I am working on and it all seems to spawn from some issue with the proxy settings. Most of the issues at this point are fixed, but the issue I am having now is that my method of testing the proxy settings makes some users wait for long periods of time. Here is what I do: System.Net.WebClient webClnt = new System.Net.WebClient(); webClnt.Proxy = proxy; webClnt.Credentials = proxy.Credentials; byte[] tempBytes; try { tempBytes = webClnt.DownloadData(url.Address); } catch { //Invalid proxy settings //Code to handle the exception goes here } This is the only way that I've found to test if the proxy settings are correct. I tried making a web service call to our web service, but no proxy settings are needed when making the call. It will work even if I have bogus proxy settings. The above method, though, has no timeout member that I can set that I can find and I use the DownloadData as opposed to the DownloadDataAsync because I need to wait til the method is done so that I can know if the settings are correct before continuing on in the program. Any suggestions on a better method or a work around for this method is appreciated. Mike

    Read the article

  • Questions about the MVC architecture

    - by ah123
    I started coding a considerably complicated web application, and it became quite a mess. So I figured I'd try to organize it in a better way. MVC seemed appropriate. I've never used MVC before, and researching about it I'm trying to consolidate a better perception of it (and my questions obviously reflect what I think I've learned so far). My questions are slightly JavaScript oriented: What object should make "AJAX" requests? The Controller or the Model? (seperation -- should the Model just store/manipulate the data, should it not care/know where the data came from, or should it be the one fetching it?) Should the Model call View functions providing them with data as arguments or should the View query (reference) the Model within itself? (seperation principles in mind, "the View shouldn't care/know where it gets the data from" -- is that correct?) In general, should the View "know" of the Model's existance, and vice-versa? Is the Controller the only thing gluing them together or is that simply incorrect? (I really doubt that statement is generally correct) There's a good chance I'd want to port this into a desktop/mobile application, so I would like to seperate components in a way that will allow me to achieve that task, replacing the current source of the data, HTTP requests, with DB access, and replacing the View. Maybe every approach that I've asked about is still "valid" MVC and it's just up to me to choose. I understand that nothing is set in stone, I'm just trying to have a (better) general idea in my head.

    Read the article

  • ISP Config 3 - squirrel login error & how to add an smtp server for sending mails

    - by A Prasetyo
    Hi, Case #1: I have ISPConfig3 running, sending email through telnet server.mydomain.com 25 are possible. Receiving email also possible. BUT!! problem occurs when I try to login to squirrel... I've been awaken for 2 days now and still couldn't figured out why logging in into squirrel always having an error: ERROR: Connection dropped by IMAP server. here is the /var/log/mail.log: Jun 3 00:23:27 server-01 imapd: Connection, ip=[::ffff:127.0.0.1] Jun 3 00:23:27 server-01 imapd: chdir /var/vmail/mydomain.com/info: Permission denied Jun 3 00:23:27 server-01 imapd: [email protected]: Permission denied I did chmod 777 & still doesn't work, only another message appeared Jun 3 00:24:28 server-01 imapd: Connection, ip=[::ffff:127.0.0.1] Jun 3 00:24:28 server-01 imapd: [email protected]: Account's mailbox directory is not owned by the correct uid or gid Try to do telnet to IMAP port telnet mydomain.com 143 Trying 63.105.102.48... Connected to mydomain.com. Escape character is '^]'. OK [CAPABILITY IMAP4rev1 UIDPLUS CHILDREN NAMESPACE THREAD=ORDEREDSUBJECT THREAD=REFERENCES SORT QUOTA IDLE ACL ACL2=UNION STARTTLS] Courier-IMAP ready. Copyright 1998-2008 Double Precision, Inc. See COPYING for distribution information. login [email protected] mypassword login NO Error in IMAP command received by server. and give no result... -_- I checked mysql.sock, I checked username and password in mysql db, everything is correct.. anyone can help? PLEASE?! Case #2: Does anyone know how to set or to view SMTP settings in ISPConfig 3? thank you..

    Read the article

  • Block javascript Alert box

    - by Frank
    Hello, I'm working on a website using extensively javascript. The code I'm working on also rely on other big javascript libs. The thing is that somewhere in these libraries, some alert box are poping. I was wondering if there are some way to disable the javascript alert box on the fly and re-enable it later. Thanks

    Read the article

  • Is Streaming Video possible with Sql Filestream?

    - by Lieven Cardoen
    We have stored all media in Sql Filestream, but now we'll need Video and Audio streaming... Will this be possible with Sql Filestream or will I have to take all of the Video and Audio out of the database? Which technology would you use to enable Video/Audio Streaming? WebORB FluorineFX Wowza (way better I think than the first two) IIS Media (haven't looked into this yet)

    Read the article

  • Inheritance of list-style-type property in Firefox (bug in Firebug?)

    - by Marcel Korpel
    Let's have a look at some comments on a page generated by Wordpress (it's not a site I maintain, I'm just wondering what's going on here). As these pages might disappear in the near future, I've put some screenshots online. Here's what I saw: Obviously, the list-item markers shouldn't be there. So I decided to look at the source using Firebug. As you can see, Firebug claims that the list-style property (containing none) is inherited from ol.commentlist. But if that's the case, why are the circle and the square visible? When checking the computed style, Firebug shows the list-style-types correctly. What's the correct behaviour? I just did a quick check in Chromium, whose Web Inspector gave a better view of reality (the list item markers were also displayed in this browser): According to WebKit, list-style of ol.commentlist isn't inherited, only the default value of list-style-type from the rendering engine. So, we may conclude that the output of both browsers is correct and that Firefox (Firebug) shows an incorrect representation of inherited styles. What does the CSS specification say? Inheritance will transfer the list-style values from OL and UL elements to LI elements. This is the recommended way to specify list style information. Not much about the inheritance of ol properties to uls. Is Firebug wrong in this respect? BTW, I managed to let the markers disappear by just changing line 312 of style.css to ol.commentlist, li.commentlist, ul.children { When also explicitly defining the list-style of ul.children to none, the markers are not painted. You can have a look at screenshots of Firebug and WebKit's Web Inspector in this case, if you like.

    Read the article

  • apc.cache_by_default with CodeIgniter

    - by Dennis
    I'm trying to use APC (Alternative PHP Cache) on my localhost with wamp 2, PHP 5.3 and CodeIgniter 1.7.2, however If I turn on cache_by_default and enable apc.stat the server will crash and I get the following error: [apc-error] Cannot redeclare class ci_benchmark in C:\wamp\www\k\mvc\codeigniter\Common.php on line 127. What can I do to fix this issue?

    Read the article

  • Why doesn't git commit -a add new files?

    - by splintor
    I'm a bit new to git, and I fail to understand why git commit -a only stages changed and deleted files but not new files. Can anyone explain why is it like this, and why there is no other commit flag to enable adding files and committing in one command? BTW, hg commit -A adds both new and deleted files to the commit

    Read the article

  • Installing ant; clearly misunderstanding JAVA_HOME

    - by StormShadow
    Hey all, I am installing ant on a Windows XP machine, and am following the instructions at Apache's manual site. It said to set JAVA_HOME, so I checked, saw there was no environment variable named JAVA_HOME, made one, and set it to "C:\Program Files\Java\jdk1.6.0_19" When I try to run ant debug, however, it tells me that JAVA_HOME is currently set to "C:\Program Files\Java\jre6" I'm guessing JAVA_HOME isn't an environment variable. But if it isn't one, I'm at a loss as to where to start looking for it. Anybody know? Edit: Oh yeah - it's bugging me for tools.jar as well, but I'm guessing that when I fix the JAVA_HOME issue, that will help the terminal find tools.jar as well. Or maybe I'm wrong. Thanks

    Read the article

  • how to 'scale' these three tables?

    - by iddqd
    I have the following Tables: Players id playerName Weapons id type otherData Weapons2Player id playersID_reference weaponsID_reference That was nice and simple. Now I need to SELECT items from the Weapons table, according to some of their characteristics that i previously just packed into the otherData column (since it was only needed on the client side). The problem is, that the types have varying characteristics - but also a lot of similar data. So I'm trying to decide on the following possibilities, all of which have their pros and cons. Solution A Kill the Weapons table, and create a new table for each Weapon-Type: Weapons_Swords id bladeType damage otherData Weapons_Guns id accuracy damage ammoType otherData But how will i Link these to the Players ? create Weapons_Swords2Players, Weapons_Guns2Players for each weapon-type? (Will result in a lot more JOINS when loading the player with all his weapons...and it's also more complicated to insert a new player) or add another column to Weapons2Players called WeaponsTypeTable, then do sub-selects to the correct Weapons sub-table (seems easier, but not really right, slightly easier insert i guess) Solution B Keep the Weapons table, and add all the fields i need to it. The Problem is that then there will be NULL fields, since not all Weapon-Types use all fields (can't be right) Weapons id type accuracy damage ammoType bladeType otherData This seems to be pretty basic stuff, but i just can't decide what's best. Or is there a correct Solution C? many thanks.

    Read the article

  • Mercurial: can't host on BitBucket.org with an error SSH, OpenSSH?

    - by raychenon
    For a new project, I created a new repo inside the project's folder. This is the first time I see this error. Following this guide 3.6 Share the repository http://tortoisehg.bitbucket.org/manual/1.0/quick.html In destination path : https://bitbucket.org/$myaccount/$myrepo I get this: abort: cannot create new http repository [command interrupted] In command line I do the equivalent: hg push https://bitbucket.org/$myaccount/$myrepo error SSH-2.0-OpenSSH_5.3 Previously I cloned a HG project on bitbucket.org with no problem. I changed without any results in the Global Settings Proxy Host : https://bitbucket.org/$myaccount user : password :

    Read the article

  • git: Is it possible to save the packed objects of a dry run and push them later?

    - by shovavnik
    I'm trying to push a bunch of commits that contain a lot of code and a few thousand MP3 and PDF files besides (ranging from 5-40 MB each). Git successfully packs the objects: C:\MyProject> git push Counting objects: 7582, done. Delta compression using up to 2 threads. Compressing objects: 100% (7510/7510), done. But it fails to send the push for some as yet unknown reason. The problem is that it takes it a very long time to repack the files (I'm on a battery-powered laptop and it took about 20 minutes to pack). So I guess my question can be phrases thus: Is it possible to save the packed objects created in a dry run? Once saved, is it possible to push those packed objects and avoid repacking? I looked it up in the git manual and elsewhere and couldn't find anything conclusive. Any help or pointers are appreciated.

    Read the article

< Previous Page | 268 269 270 271 272 273 274 275 276 277 278 279  | Next Page >