Search Results

Search found 2192 results on 88 pages for 'chip ga con'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 28/88 | < Previous Page | 24 25 26 27 28 29 30 31 32 33 34 35  | Next Page >

  • ClassNotFoundException com.mysql.jdbc.Driver

    - by Dusk
    This question might have asked here number of times . After doing some google search for the above error and doing some update, I can't understand why I'm still getting that error. I've already put my driver-- mysql-connector-java-5.1.5-bin in the classpath: Java_Home\jre\lib\ Java_Home\jre\lib\ext\ Java_Home\lib and the code which I'm using to connect to mysql database is: try{ Class.forName("com.mysql.jdbc.Driver"); Connection con=DriverManager.getConnection("jdbc:mysql://localhost:3306/mail","root",""); Statement stmt = con.createStatement(); ResultSet rs = stmt.executeQuery("select message_body from deadletter"); String dbtime; while (rs.next()) { dbtime = rs.getString(1); System.out.println(dbtime); } con.close(); } catch (SQLException e) { System.out.println("Connection Failed! Check output console"); e.printStackTrace(); } } and the complete stacktrace of the above exception is: java.lang.ClassNotFoundException: com.mysql.jdbc:Driver at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:307) at java.lang.ClassLoader.loadClass(ClassLoader.java:307) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301) at java.lang.ClassLoader.loadClass(ClassLoader.java:252) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:169) at mail.main(mail.java:114) Now, what's wrong I'm doing here?

    Read the article

  • Trouble making login page?

    - by Ken
    Okay, so I want to make a simple login page. I've created a register page successfully, but i can't get the login thing down. login.php: <?php session_start(); include("mainmenu.php"); $usrname = mysql_real_escape_string($_POST['usrname']); $password = md5($_POST['password']); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } mysql_select_db("users", $con) or die(mysql_error()); $login = "SELECT * FROM `users` WHERE (usrname = '$usrname' AND password = '$password')"; $result = mysql_query($login); if(mysql_num_rows($result) == 1 { $_SESSION = true; header('Location: indexlogin.php'); } else { echo = "Wrong username or password." ; } ?> indexlogin.php just echoes "Login successful." What am I doing wrong? Oh, and just FYI- my database is "users" and my table is "data".

    Read the article

  • drop down and post data to data base

    - by DAFFODIL
    This is a form which retrieves data from db and displays them in table. At the beginning of each row there will be a check box. If there are 10 rows fetched, I ii check 5 rows and insert them in to diff db but here when, I click drop down box data is getting in to db automatically,bcoz I use onchange event. Any alternative to prevent this to happen. Data should be inserted only when, I click submit button. Any help will be appreciated <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("form1", $con); error_reporting(E_ALL ^ E_NOTICE); $nam=$_REQUEST['select1']; $row=mysql_query("select * from inv where name='$nam'"); while($row1=mysql_fetch_array($row)) { $Name=$row1['Name']; $Address =$row1['Address']; $City=$row1['City']; $Pincode=$row1['Pincode']; $No=$row1['No']; $Date=$row1['Date']; $DCNo=$row1['DCNo']; $DcDate=$row1['DcDate']; $YourOrderNo=$row1['YourOrderNo']; $OrderDate=$row1['OrderDate']; $VendorCode=$row1['VendorCode']; $SNo=$row1['SNo']; $descofgoods=$row1['descofgoods']; $Qty=$row1['Qty']; $Rate=$row1['Rate']; $Amount=$row1['Amount']; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Untitled Document</title> <script type="text/javascript"> function ram(id) { var q=document.getElementById('qty_'+id).value; var r=document.getElementById('rate_'+id).value; document.getElementById('amt_'+id).value=q*r; } </script> </head> <body> <form id="form1" name="form1" method="post" action=""> <table width="1315" border="0"> <script type="text/javascript"> function g() { form1.submit(); } </script> <tr> <th>Name</th> <th align="left"><select name="select1" onchange="g();"> <option value="" selected="selected">select</option> <?php $row=mysql_query("select Name from inv "); while($row1=mysql_fetch_array($row)) { ?> <option value="<?php echo $row1['Name'];?>"><?php echo $row1['Name'];?></option> <?php } ?> </select></th> </tr> <tr> <th>Address</th> <th align="left"><textarea name="Address"><?php echo $Address;?></textarea></th> </tr> <tr> <th>City</th> <th align="left"><input type="text" name="City" value='<?php echo $City;?>' /></th> </tr> <tr> <th>Pincode</th> <th align="left"><input type="text" name="Pincode" value='<?php echo $Pincode;?>'></th> </tr> <tr> <th>No</th> <th align="left"><input type="text" name="No2" value='<?php echo $No;?>' readonly="" /></th> </tr> <tr> <th>Date</th> <th align="left"><input type="text" name="Date" value='<?php echo $Date;?>' /></th> </tr> <tr> <th>DCNo</th> <th align="left"><input type="text" name="DCNo" value='<?php echo $DCNo;?>' readonly="" /></th> </tr> <tr> <th>DcDate:</th> <th align="left"><input type="text" name="DcDate" value='<?php echo $DcDate;?>' /></th> </tr> <tr> <th>YourOrderNo</th> <th align="left"><input type="text" name="YourOrderNo" value='<?php echo $YourOrderNo;?>' readonly="" /></th> </tr> <tr> <th>OrderDate</th> <th align="left"><input type="text" name="OrderDate" value='<?php echo $OrderDate;?>' /></th> </tr> <tr> <th width="80">VendorCode</th> <th width="1225" align="left"><input type="text" name="VendorCode" value='<?php echo $VendorCode;?>' readonly="" /></th> </tr> </table> <table width="1313" border="0"> <tr> <td width="44">&nbsp;</td> <td width="71">SNO</td> <td width="527">DESCRIPTION</td> <td width="214">QUANTITY</td> <td width="214">RATE/UNIT</td> <td width="217">AMOUNT</td> </tr> <?php $i=1; $row=mysql_query("select * from inv where Name='$nam'"); while($row1=mysql_fetch_array($row)) { $SNo=$row1['SNo']; $descofgoods=$row1['descofgoods']; $Qty=$row1['Qty']; $Rate=$row1['Rate']; $Amount=$row1['Amount']; ?> <tr> <td><input type="checkbox" name="checkbox" value="checkbox" checked="checked"/></td> <td><input type="text" name="No[<?php echo $i?>]" value='<?php echo $SNo;?>' readonly=""/></td> <td><input type="text" name="descofgoods[<?php echo $i?>]" value='<?php echo $descofgoods;?>' /></td> <td><input type="text" name="qty[<?php echo $i?>]" maxlength="50000000" id="qty_<?PHP echo($i) ?>"/></td> <td><input type="text" name="Rate[<?php echo $i?>]" value='<?php echo $Rate;?>' id="rate_<?PHP echo($i) ?>" onclick="ram('<?PHP echo($i) ?>')";></td> <td><input type="text" name="Amount[<?php echo $i?>]" id="amt_<?PHP echo($i) ?>"/></td> </tr> <?php $i++;} ?> <tr> <td><input type="submit" value="submit" header("location:values to be brought for print page.php");/></td> </tr> </table> <label></label> </form> </body> </html> <?php /*error_reporting(E_ALL ^ E_NOTICE); $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("form1", $con); /*if(checked=checkbox) { mysql_query="INSERT INTO invo (Name, Address, City, Pincode, No, Date, DCNo, DcDate, YourOrderNo, OrderDate, VendorCode, SNo, descofgoods, Qty, Rate, Amount) VALUES ('$_POST[Name]','$_POST[Address]','$_POST[City]','$_POST[Pincode]','$_POST[No]','$_POST[Date]','$_POST[DCNo]','$_POST[DcDate]','$_POST[YourOrderNo]','$_POST[OrderDate]','$_POST[VendorCode]','$_POST[SNo]','$_POST[descofgoods]','$_POST[qty]','$_POST[Rate]','$_POST[Amount]')"; } else { header("location:values to be brought for print page.php"); }*/ header("ins.php"); ?>

    Read the article

  • Java MySQL Query Problem MySQLSyntaxErrorException When Creating a Table

    - by Aqib Mushtaq
    I fairly new to MySQL with Java, but I have executed a few successful INSERT queries however cannot seem to get the CREATE TABLE query to execute without getting the 'MySQLSyntaxErrorException' exception. My code is as follows: import java.sql.*; Statement stmt; Class.forName("com.mysql.jdbc.Driver"); String url = "jdbc:mysql://localhost:3306/mysql"; Connection con = DriverManager.getConnection(url, "root", "password"); stmt = con.createStatement(); String tblSQL = "CREATE TABLE IF NOT EXISTS \'dev\'.\'testTable\' (\n" + " \'id\' int(11) NOT NULL AUTO_INCREMENT,\n" + " \'date\' smallint(6) NOT NULL\n" + ") ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;"; stmt.executeUpdate(tblSQL); stmt.close(); con.close(); And the error is as follows: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''dev'.'testTable' ( 'id' int(11) NOT NULL AUTO_INCREMENT, 'date' smallint(6) N' at line 1 I would appreciate it if anyone could spot the mistake in this query, as I've tried executing this within phpMyAdmin and it works as it should. Thanks in advance.

    Read the article

  • How to send check boxes ID in gridview in one string for mass update.

    - by SmartDev
    hi , I have a grid which has check boxes and when selecting the top chek box select all will select all the check box in gridview and would update .for this im using for loop where it exceutes every time and this is taking lot of time cuase there are more thn 100 records in grid . try { string StrOutputMessageDisplayDocReqCsu = string.Empty; string strid = string.Empty; string strflag = string.Empty; string strSelected = string.Empty; for (int j = 0; j < GdvDocReqMU.Rows.Count; j++) { CheckBox Chkupdate = (CheckBox)GdvDocReqMU.Rows[j].Cells[1].FindControl("chkDR"); if (Chkupdate != null) { if (Chkupdate.Checked) { strid = ((Label)GdvDocReqMU.Rows[j].FindControl("lblIDDocReqCsu")).Text; strflag = ((Label)GdvDocReqMU.Rows[j].FindControl("lblStatusDocReqCsu")).Text; cmd = new SqlCommand("sp_Update_v1", con); cmd.CommandType = CommandType.StoredProcedure; cmd.Parameters.AddWithValue("@id", strSelected); cmd.Parameters.AddWithValue("@flag", DdlStatusDocReqMU.SelectedValue); cmd.Parameters.AddWithValue("@notes", txtnotesDocReqMU.Text); cmd.Parameters.AddWithValue("@user", strUseridDRAhk); cmd.Parameters.Add(new SqlParameter("@message", SqlDbType.VarChar, 100, ParameterDirection.Output, false, 0, 50, "message", DataRowVersion.Default, null)); cmd.UpdatedRowSource = UpdateRowSource.OutputParameters; con.Open(); cmd.ExecuteNonQuery(); con.Close(); } } } //} //StrOutputMessageDisplayDocReqCsu += (string)cmd.Parameters["@message"].Value + "<br/>"; //lbldbmessDocReqAhk.Text += StrOutputMessageDisplayDocReqCsu + "<br>"; GetgridDocReq(); } catch (Exception ex) { lbldbmessDocReqAhk.Text = ex.Message.ToString(); }

    Read the article

  • Using jquery Autocomplete on textbox control in c#

    - by Abid Ali
    When I run this code I get alert saying Error. My Code: <script type="text/javascript"> debugger; $(document).ready(function () { SearchText(); }); function SearchText() { $(".auto").autocomplete({ source: function (request, response) { $.ajax({ type: "POST", contentType: "application/json; charset=utf-8", url: "Default.aspx/GetAutoCompleteData", data: "{'fname':'" + document.getElementById('txtCategory').value + "'}", dataType: "json", success: function (data) { response(data.d); }, error: function (result) { alert("Error"); } }); } }); } </script> [WebMethod] public static List<string> GetAutoCompleteData(string CategoryName) { List<string> result = new List<string>(); using (SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["DbConnection"].ConnectionString)) { using (SqlCommand cmd = new SqlCommand("select fname from tblreg where fname LIKE '%'+@CategoryText+'%'", con)) { con.Open(); cmd.Parameters.AddWithValue("@CategoryText", CategoryName); SqlDataReader dr = cmd.ExecuteReader(); while (dr.Read()) { result.Add(dr["fname"].ToString()); } return result; } } } I want to debug my function GetAutoCompleteData but breakpoint is not fired at all. What's wrong in this code? Please guide. I have attached screen shot above.

    Read the article

  • POSTmethod and PHP- login verification

    - by Neethusha
    I wrote a code for login verification..I got output with GET. But i need output with POST since it is more secure.pls let me know if there is any error in my code. javascript code: var xml; function verifyusernamepasswd(pass) { //pass is password that will be passed as parameter xml=new XMLHttpRequest(); var url="http://localhost/loginvalidate.php"; var para="q="+username+"&p="+pass;//username is global xml.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xml.setRequestHeader("Content-length", para.length); xml.setRequestHeader("Connection", "close"); xml.open("POST",url,true); xml.onreadystatechange=statechanged1; xml.send(para); } function statechanged1() { if(xml.readyState==4) alert(xml.responseText); } php code: <?php $username=$_POST["q"]; $password=$_POST["p"]; $con=mysql_connect("localhost","root","blaze"); if(!$con) { die('Could not connect: '.mysql.error()); } mysql_select_db("BLAZE",$con) or die("No such Db"); $result=mysql_query("SELECT Passwword FROM USERTABLE WHERE Userhandle='$username'"); if($result==null) echo "false"; else if($result!=null) { $row=mysql_fetch_array($result); if((strcmp($row['Passwword'],$password)==0)) echo "true"; else echo "false"; } ?> the verification does not return anything, cos my alert is not displayed at all...pls tell me whats wrong....

    Read the article

  • MySQL query returning mysql_error

    - by Sebastian
    This returns mysql_error: <?php $name = $_POST['inputName2']; $email = $_POST['inputEmail2']; $instruments = $_POST['instruments']; $city = $_POST['inputCity']; $country = $_POST['inputCountry']; $distance = $_POST['distance']; // ^^ These all echo properly ^^ // CONNECT TO DB $dbhost = "xxx"; $dbname = "xxx"; $dbuser = "xxx"; $dbpass = "xxx"; $con = mysqli_connect("$dbhost", "$dbuser", "$dbpass", "$dbname"); if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } $query = "INSERT INTO depfinder (name, email, instrument1, instrument2, instrument3, instrument4, instrument5, city, country, max_distance) VALUES ($name, $email, $instruments[0], $instruments[1], $instruments[2], $instruments[3], $instruments[4], $city, $country, $max_distance)"; $result = mysqli_query($con, $query) or die(mysqli_error($con)); // script fails here if (!$result) { echo "There was a problem with the signup process. Please try again later."; } else { echo "Success"; } } ?> N.B. I'm not sure whether it's relevant, but the user may not choose five instruments so some $instrument[] array values may be empty. Bonus question: is my script secure enough or is there more I could do?

    Read the article

  • JDBC going to the wrong address

    - by DCSoft
    When I try and connect it my mysql database with JDBC in java, it doesn't go to my web server. Here is the code String dbtime; String dbUrl = "jdbc:mysql://184.172.176.18:3306/dcsoft_dcsoft_balloon"; String dbUser = "myuser"; String dcPass = "mypass"; String dbClass = "com.mysql.jdbc.Driver"; String query = "Select * FROM users"; try { Class.forName("com.mysql.jdbc.Driver"); Connection con = DriverManager.getConnection(dbUrl, dbUser, dcPass); Statement stmt = con.createStatement(); ResultSet rs = stmt.executeQuery(query); while (rs.next()) { dbtime = rs.getString(1); System.out.println(dbtime); } //end while con.close(); } //end try catch(ClassNotFoundException e) { e.printStackTrace(); } catch(SQLException e) { e.printStackTrace(); } This code is supposed to go to my web server but it gives this error java.sql.SQLException: Access denied for user 'dcsoft_dcsoft_java'@'jamesposse.force9.co.uk' (using password: YES) jamesposse.force9.co.uk is the not the address im trying to connect to I'm trying to connect to 184.172.176.18:3306. Thanks.

    Read the article

  • trying to backup mysql database using php

    - by user225269
    I got this code from this site: http://www.php-mysql-tutorial.com/wikis/mysql-tutorials/using-php-to-backup-mysql-databases.aspx But I'm just a beginner so I don't know what the config.php and opendb.php suppose to mean. Do I have to create those 2 files in order for this code to work? If yes, then how do I create it, it isn't included in the site how to create it. <?php include 'config.php'; include 'opendb.php'; $tableName = 'mypet'; $backupFile = 'backup/mypet.sql'; $query = "SELECT * INTO OUTFILE '$backupFile' FROM $tableName"; $result = mysql_query($query); include 'closedb.php'; ?> can I just include these lines on the top code so that I will not be putting the include 'opendb.php' anymore: $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("Hospital", $con);

    Read the article

  • Learning OOP in PHP, trying to refactor my code. Can't connect to database anymore.

    - by Cortopasta
    Thought I understood how classes work, then I tried this code: class user { var $dbcon; var $dbinfo; var $con; var $error; function dbConnect() { $this->dbinfo['server'] = "localhost"; $this->dbinfo['database'] = "foolish_faith"; $this->dbinfo['user'] = "user"; $this->dbinfo['password'] = "password"; $this->con = "mysql:host=".$dbinfo['server']."; dbname=".$dbinfo['database']; $this->dbcon = new PDO($con, $dbinfo['user'], $dbinfo['password']); $this->dbcon->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $this->error = $this->dbcon->errorInfo(); if ($error[0] != "") { print "Error!"; print_r($error); } } } Now it just spits out this error: Fatal error: Uncaught exception 'PDOException' with message 'invalid data source name' in E:\PortableApps\xampp\htdocs\dbcon.php:24 Stack trace: #0 E:\PortableApps\xampp\htdocs\dbcon.php(24): PDO-__construct('', NULL, NULL) #1 E:\PortableApps\xampp\htdocs\login.php(4): user-dbConnect() #2 {main} thrown in E:\PortableApps\xampp\htdocs\dbcon.php on line 24 Can anybody see what I'm doing wrong, as I'm sure it has to do with my lack of knowledge when it comes to classes?

    Read the article

  • how to add data in Table of Jasper Report using Java

    - by Areeb Gillani
    i am here to ask you just a simple question that i am trying to pass data to a jasper report using java but i dont know how to to, because the table data is very dynamic thats y cannot pass sql query. any idea for this. i have a 2D array of object type, where i have all the data... so how can i pass that... Thanx in advance...!:) ConnectionManager con = new ConnectionManager(); con.establishConnection(); String fileName = "Pmc_Bill.jrxml"; String outFileName = "OutputReport.pdf"; HashMap params = new HashMap(); params.put("PName", pname); params.put("PSerial", psrl); params.put("PGender",pgen); params.put("PPhone",pph); params.put("PAge",page); params.put("PRefer",pref); params.put("PDateR",dateNow); try { JasperReport jasperReport = JasperCompileManager.compileReport(fileName); if(jasperReport != null ) System.out.println("so far so good "); // Fill the report using an empty data source JasperPrint jasperPrint = JasperFillManager.fillReport(jasperReport, params, new JRTableModelDataSource(tbl.getModel()));//con.connection); try{ JasperExportManager.exportReportToPdfFile(jasperPrint, outFileName); System.out.printf("File exported sucessfully"); }catch(Exception e){ e.printStackTrace(); } JasperViewer.viewReport(jasperPrint); } catch (JRException e) { JOptionPane.showMessageDialog(null, e); e.printStackTrace(); System.exit(1); }

    Read the article

  • How to load data on option box in php

    - by user225269
    I'm having trouble loading the mysql data on the html form option box using php. Here's my code: <?php $con = mysql_connect("localhost","myuname","mypassword"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $idnum= mysql_real_escape_string($_POST['idnum']); $result = mysql_query("SELECT * FROM student WHERE IDNO='$idnum'"); ?> <?php while ( $row = mysql_fetch_array($result) ) { ?> <tr> <td width="30" height="35"><font size="2">*I D Number:</td> <td width="30"><input name="idnum" type="text" maxlength="5" value="<?php echo $row["IDNO"]; ?>" readonly="readonly"></td> </tr> My problem is loading it here: <td><font size="2">Gender</td> <td> <select name="gender" id="gender"> <font size="2"> <option value="<?php echo $line['IDNO']; ?> "><?php $line['GENDER'] ; ?></option> </select></td></td> The table looks like this: IDNO | GENDER 123 | M 321 | F What am I supposed to do?To load the exact gender corresponding to the IDNO?

    Read the article

  • How would i output a message that says "values inserted to table" ?

    - by ranlo
    <?php error_reporting(0); $con=mysql_connect("localhost","root",""); if (!$con) { die('could not connect:'.mysql_error()); } mysql_select_db("final?orgdocs",$con); $org_name = $_POST["org_name"]; $org_type = $_POST["org_type"]; $org_code = $_POST["org_code"]; $description = $_POST["description"]; $stmt = "INSERT INTO organization VALUES('".$org_name."','".$org_type."','".$org_code."','".$description."')"; $result = mysql_query("SELECT * FROM organization WHERE org_name = '$org_name' "); echo '<TABLE BORDER = "1">'; $result1 = $result; while ($row = mysql_fetch_array($result1)){ echo '<TR>'.'<TD>'.'Organization Name'.'</TD>'.'<TD>'.'Organization Type'.'</TD>'.'<TD>'.'Organization Code'.'</TD>'.'<TD>'.'Description'.'</TD>'.'<TD>'.'Constitution'.'</TD>'; echo '</TR>'; echo '<TR>'.'<TD>'.$row['org_name'].'</TD>'.'<TD>'.$row['org_type'].'</TD>'; echo '<TD>'.$row['org_code'].'</TD>'.'<TD>'.$row['description'].'</TD>'.'<TD>'; echo '</TR>'; } echo '</TABLE>'; ?>

    Read the article

  • PHP Dropdown menu [closed]

    - by rShetty
    <br><h2>Select a Tag</h2></br> <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("portal", $con); $query = "SELECT tag_name FROM tags"; $result = mysql_query($query); ?> <select name="tag_name" id="abc"> <option size=30 selected>Select</option> <?php while($array = mysql_fetch_assoc($result)){ ?> <option value ="<?php echo $array['tag_name'];?>"><?php echo $array['tag_name'];?> </option> <?php } ?> </select> <br><br> This is a snippet of code for getting the dropdown menu in the page. I have a database named portal and table named tags with tag_name as the attribute. Do help me to find the error in the program. I am not getting the tag_names in the dropdown menu

    Read the article

  • PHP login, getting wrong count value from query / fetch array

    - by Chris
    Hello, *EDIT*Thanks to the comments below it has been figured out that the problem lies with the md5, without everything works as it should. But how do i implent the md5 then? I am having some troubles with the following code below to login. The database and register system are already working. The problem lies that it does not find any result at all in the query. IF the count is 0 it should redirect the user to a secured page. But this only works if i write count = 0, but this should be 0 , only if the user name and password is found he should be directed to the secure (startpage) of the site after login. For example root (username) root (password) already exists but i cannot seem to properly login with it. <?php session_start(); if (!empty($_POST["send"])) { $username = ($_POST["username"]); $password = (md5($_POST["password"])); $count = 0; $con = mysql_connect("localhost" , "root", ""); mysql_select_db("testdb", $con); $result = mysql_query("SELECT name, password FROM user WHERE name = '".$username."' AND password = '".$password."' ") or die("Error select statement"); $count = mysql_num_rows($result); if($count > 0) // always goes the to else, only works with >=0 but then the data is not found in the database, hence incorrect { $row = mysql_fetch_array($result); $_SESSION["username"] = $row["name"]; header("Location: StartPage.php"); } else { echo "Wrong login data, please try again"; } mysql_close($con); } ?>

    Read the article

  • How to create festival calendar in ASP.net

    - by Atul
    I want to make a festival calendar using asp.net from that I used two ajax calendar and one textbox it is a festival textbox where we enter festival which FromDate and ToDate respectively. I want to do this as following point If I enter in textbox Christmas and Choose Fromdate=25/12/2011 and ToDate=31/12/2011 then it will be valid If I choose fromDate=25/12/2011 and ToDate=24/12/2011 then it will invalid If I choose Fromdate=25/12/2011 and Todate=28/12/2011 then also it is invalid because it coming in between 25/12/2011 and 31/12/2011 If I Choose fromdate=1/1/2011 and ToDate=1/1/2011 then it is valid If I choose fromdate=21/12/2011 and 25/12/2011 then it is invalid because of already Christmas done in 1/1/2011 And all date should show in gridview like 25-dec-2011 format Here is my code: DateTime dt1 = Convert.ToDateTime(txt_fromdate.Text); DateTime dt2 = Convert.ToDateTime(txt_todate.Text); if (dt1 > dt2) { con.Open(); com = new SqlCommand("BTNN_MovieDB_Festival_Details_Insert", con); com.Parameters.Add("@fromdate", SqlDbType.VarChar).Value = dateformat_mmdd(txt_fromdate.Text.ToString().Trim()); com.Parameters.Add("@todate", SqlDbType.VarChar).Value = dateformat_mmdd(txt_todate.Text.ToString().Trim()); com.Parameters.Add("@return", SqlDbType.VarChar).Direction = ParameterDirection.ReturnValue; com.ExecuteNonQuery(); con.Close(); showdata(); } else if (dt1 < dt2) { lblerror.Text = "ToDate should be greater than FromDate"; }

    Read the article

  • jQuery: change a css value if a option is selected

    - by Ivan Castellanos
    I'm trying to make an option dropdown menu and I got stuck when I try to show a textbox if the option 'other' is selected. there's what I have: <span id="con-country"><label for="country">Country: </label> <select name="country" required="required"> <option value="usa">United States</option> <option value="uk">United Kingdom</option> <option id="other" value="other">Other</option> </select> </span> <span id="con-specify"> <label for="specify">Specify: </label> <input type="text" name="specify" id="c-specify" required="required"></input> </span> CSS: #con-specify{ margin-left: 50px; display: none; } Simple huh?, the problem is that I don't know how to do the code in jQuery So, if the user select other in the menu, then the textbox should appear, how can I do that?

    Read the article

  • Telerik is First to Announce Support for Microsoft Silverlight Analytics Framework

    Yesterday at MIX 10 conference Microsoft announced the Microsoft Silverlight Analytics Framework Beta. The Silverlight Analytics Framework (SAF) is a new open-source framework to allow designers and developers to integrate web analytics into Silverlight applications in a consistent manner. Supporting out-of-browser and offline scenarios, Microsoft built this framework in conjunction with a number of web analytics services and control vendors to support multiple analytics services simultaneously without degrading application performance. Because the SAF is enabled as a set of behaviors in Microsoft Expression Blend, designers and developers can visually instrument their designs and configure A/B testing rapidly without writing any code. Telerik is proud to be the first control vendor to support the Silverlight Analytics Framework. RadControls for Silverlight can be used with the framework out of the box. The suite offers Silverlight Analytics Framework handlers and behavior, helping developers to fine tune the values sent to the analytics providers. Because the analytics framework is using the Managed Extensibility Framework (MEF) for composition, you don't need to change the way you use the controls to benefit from the Telerik handlers. Just add a reference to the Telerik assemblies that contains the handlers. Here is the code that you need to declare to use RadTreeView: <UserControl x:Class="Telerik.SLAF.MainPage"         xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"         xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"         xmlns:i="clr-namespace:System.Windows.Interactivity;assembly=System.Windows.Interactivity"         xmlns:ga="clr-namespace:Google.WebAnalytics;assembly=Google.WebAnalytics"         xmlns:sa="clr-namespace:Microsoft.WebAnalytics.Behaviors;assembly=Microsoft.WebAnalytics.Behaviors"         xmlns:ic="clr-namespace:Microsoft.Expression.Interactivity.Core;assembly=Microsoft.Expression.Interactions"         xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"         xmlns:telerikNavigation="clr-namespace:Telerik.Windows.Controls;assembly=Telerik.Windows.Controls.Navigation">        <Grid x:Name="LayoutRoot">         <i:Interaction.Behaviors>             <ga:GoogleAnalytics ProfileId="--Your GA ProfileId" Category="Demo" />         </i:Interaction.Behaviors>         <telerikNavigation:RadTreeView>             <i:Interaction.Triggers>                 <i:EventTrigger EventName="SelectionChanged">                     <sa:TrackAction />                 </i:EventTrigger>             </i:Interaction.Triggers>             <telerikNavigation:RadTreeViewItem Header="Item1">             </telerikNavigation:RadTreeViewItem>             <telerikNavigation:RadTreeViewItem Header="Item2" />             <telerikNavigation:RadTreeViewItem Header="Item3" />         </telerikNavigation:RadTreeView>     </Grid> </UserControl> Download the Telerik Microsoft Silverlight Analytics Framework Handlers and the sample project. This is our first Beta release - please drop us a line with any feedback you have or even better if you are at MIX10 - come visit us at the booth in the "Commons" hall so we can discuss it in person. Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

    Read the article

  • How do I get an Enter USB TV Box TV tuner aka Gadmei UTV302 to work?

    - by Subhash
    Has anyone had any success in using the Enter USB TV Box from Enter Multimedia? It comes bundled with software that works in Windows. I have had no luck using it in Ubuntu 10.10. Update 1 Here is the output from lsusb Bus 007 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 006 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 005 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 004 Device 003: ID 093a:2510 Pixart Imaging, Inc. Optical Mouse Bus 004 Device 002: ID 046d:c312 Logitech, Inc. DeLuxe 250 Keyboard Bus 004 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 003 Device 001: ID 1d6b:0002 Linux Foundation 2.0 root hub Bus 002 Device 001: ID 1d6b:0002 Linux Foundation 2.0 root hub Bus 001 Device 006: ID 1f71:3301 Bus 001 Device 001: ID 1d6b:0002 Linux Foundation 2.0 root hub I can't find the Enter USB TV Box listed in this. In the dmesg tail command, I found something that seems to be related to the card: usb 1-5: new high speed USB device using ehci_hcd and address 6 usb 1-5: config 1 interface 0 altsetting 1 bulk endpoint 0x83 has invalid maxpacket 256 Update 2 From Windows I learned that this USB TV tuner uses some chipset from Gadmei corporation. All computer stores in India sell Enter USB TV Box if you ask for an USB TV tuner. No other brand seems to be interested in this market. Update 3 I learned that this TV tuner is rebranded version of Gadmei UTV302 (USB TV Tuner Box). Update 4 I tried adding em28xx as the chipset (as suggested by user BOBBO below) for the tuner but that did not work. I went back to my Pinnacle PCTV internal card. I don't think the tuner referred by UbuntuForums (Gadmei UTV 330) and the tuner that I have (Gadmei UTV 302) are the same. My USB tuner is several times bigger. My tuner seems to be a newer device with a newer tuner chip. I will submit details of this device to the LinuxTV developers this weekend. Update 5 I opened the tuner box and found that it uses a tuner from a Chinese company - Tenas. Model is TNF 8022-DFA. Update 6 Tuner chip specs (retrived from supplier directory) for Tenas TNF 8022-DFA. Supply voltage: true 5V device(low power dissipation) Control system: I2C bus control of tuning, address selection Tuning system: PLL controlled tuning Receiving system: system PAL D/K,IF(Intermediate Frequency): 38MHz Receiving channels: full frequency range from channel DS1 (49.75MHz) to channel DS57 (863.25MHz); Use Texas Instruments SN761678 IC solution, with mini install size Update 7 Reverse side of the circuit board. Picture of the TV tuner

    Read the article

  • New Netra SPARC T3 Servers

    - by Ferhat Hatay
    Today at the Mobile World Congress 2011, Oracle announced two new carrier-grade NEBS Level 3- certified servers: Oracle’s Netra SPARC T3-1 rackmount server and Oracle’s Netra SPARC T3-1BA ATCA blade server bringing the performance, scalability and power efficiency of the newest SPARC T3 processor to the communications market.    The Netra SPARC T3-1 server enclosure has a compact 20inch-deep carrier-grade rack-optimized design The new Netra SPARC T3 servers further expand Oracle’s complete portfolio for the communications industry, which includes carrier-grade servers, storage and application software to run operations support systems and service delivery platforms with easy migration capabilities and unmatched investment protection via the binary compatibility guarantee of the Oracle Solaris operating system. With advanced reliability, networking and security features built-in to Oracle Solaris – the most widely deployed carrier-grade OS – the systems announced today are uniquely suited for mission-critical core network infrastructure and service delivery. The world’s first carrier-grade system using the 16-core, 128-thread SPARC T3 processor, the Netra SPARC T3-1 server supports 2x the I/O bandwidth, 2x the memory and is 35 percent faster than the previous generation. With integrated on-chip 10 Gigabit Ethernet, on-chip cryptographic acceleration, and built-in, no-cost Oracle VM Server for SPARC and Oracle Solaris Containers for virtualization, the Netra SPARC T3-1 server is an ideal platform for consolidation, offering 128 virtual systems in a single server. As the next generation Netra SPARC ATCA blade, Netra SPARC T3-1BA ATCA blade server brings the PICMG 3.0 compatibility, NEBS Level 3 Certification, ETSI compliance and the Netra business practices to the customer solution. The Netra SPARC T3-1BA ATCA blade server can be mixed in the Sun Netra CT900 blade chassis with other ATCA UltraSPARC and x86 blades.     The Netra SPARC T3-1BA ATCA blade server   The Netra SPARC T3-1BA ATCA blade server delivers industry-leading scalability, density and cost efficiency with up to 36 SPARC T3 processors (3456 processing threads) in a single rack – a 50 percent increase over the previous generation. The Netra SPARC T3-1BA blade server also offers high-bandwidth and high-capacity I/O, with greater memory capacity to tackle the increasing business demands of the communications industry. For service providers faced with the rapid growth of broadband networks and the dramatic surge in global smartphone adoption, the new Netra SPARC T3 systems deliver continuous availability with massive scalability, tested and certified to run in the harshest conditions. More information Oracle’s Sun Netra Servers Scaling Throughput and Managing TCO with Oracle’s Netra SPARC T3-1 Servers Enabling End-to-End 10 Gigabit Ethernet in Oracle's Sun Netra ATCA Product Family Data Sheet: Netra SPARC T3-1BA ATCA Blade Server Data Sheet: Netra SPARC T3-1 Server Oracle Solaris: The Carrier Grade Operating System

    Read the article

  • Game Boy Generates Music In An Unexpected Way [Video]

    - by Jason Fitzpatrick
    When we saw a link about a Game Boy generated melody we assumed it was a chip-tune track generated by the Game Boy’s sound processor. We were pleasantly surprised to see the Game Boy itself was the instrument. [via Geeks Are Sexy] Reader Request: How To Repair Blurry Photos HTG Explains: What Can You Find in an Email Header? The How-To Geek Guide to Getting Started with TrueCrypt

    Read the article

  • ath9k driver does not weak up

    - by shantanu
    I know this is common question but i found no suitable answer, so i am asking this again. I installed ubuntu 11.10. I found the bug for ath9k, so set first network boot from BIOS menu. That's worked. I have upgraded to 12.04 yesterday. Now ath9k is creating problem again. First network boot is still enable. ath9k works at start. But failed(connect again and again) after couple of minutes. dmesg show error that it can not weak up in 500us. So i tried #compat-wireless-3.5.1-1. But result is same. I have also added #nohwcrypt=1 option in /etc/modeprob.d/ath9k.conf. Still no luck. I tried #rmmod and then modprobe sudo modprobe ath9k nohwcrypt=1 dmesg shows me error: [ 400.690086] ath9k: Driver unloaded [ 406.214329] ath9k 0000:06:00.0: enabling device (0000 -> 0002) [ 406.214348] ath9k 0000:06:00.0: PCI INT A -> GSI 17 (level, low) -> IRQ 17 [ 406.214368] ath9k 0000:06:00.0: setting latency timer to 64 [ 406.428517] ath9k 0000:06:00.0: Failed to initialize device [ 406.428852] ath9k 0000:06:00.0: PCI INT A disabled [ 406.428887] ath9k: probe of 0000:06:00.0 failed with error -5 dmesg error when driver fail: 355.023521] ath: Chip reset failed [ 355.023524] ath: Unable to reset channel, reset status -22 [ 355.023556] ath: Unable to set channel [ 355.088569] ath: Failed to stop TX DMA, queues=0x10f! [ 355.122708] ath: DMA failed to stop in 10 ms AR_CR=0xffffffff AR_DIAG_SW=0xffffffff DMADBG_7=0xffffffff [ 355.122714] ath: Could not stop RX, we could be confusing the DMA engine when we start RX up [ 355.263962] ath: Chip reset failed [ 355.263966] ath: Unable to reset channel (2437 MHz), reset status -22 [ 358.996063] ath: Failed to wakeup in 500us [ 364.004182] ath: Failed to wakeup in 500us I can not install fresh ubuntu because i have lots of application installed. System : Acer Aspire 4250 AMD dual core 1.6GHZ Atheros Communications Inc. AR9485 Wireless Network Adapter (rev 01) EDITED Now i am in serious problem. No wifi device is not showing in ifconfig or lshw commands. Only ether-net interface shows. I tried (FN + WIFI) several times to enable the device but nothing helps. Now I have installed fresh ubuntu 12.04. Please help lshw -c network: *-network description: Ethernet interface product: 82566DC Gigabit Network Connection vendor: Intel Corporation physical id: 19 bus info: pci@0000:00:19.0 logical name: eth0 version: 02 serial: 00:19:d1:7a:8e:f9 size: 100Mbit/s capacity: 1Gbit/s width: 32 bits clock: 33MHz capabilities: pm msi bus_master cap_list ethernet physical tp 10bt 10bt-fd 100bt 100bt-fd 1000bt-fd autonegotiation configuration: autonegotiation=on broadcast=yes driver=e1000e driverversion=2.0.0-k duplex=full firmware=1.1-0 ip=192.168.1.114 latency=0 link=yes multicast=yes port=twisted pair speed=100Mbit/s resources: irq:45 memory:90300000-9031ffff memory:90324000-90324fff ioport:20c0(size=32) rfkill command does not show anything but no error.

    Read the article

  • Ubuntu server spontaneous reboot

    - by user1941407
    I have got two ubuntu 12.04 servers(xeon e3). Sometimes(several days) each server spontaneously reboots. HDDs and other hardware are ok. Which logfile can help find a reason of the problem? UPDATED. hardware: xeon e3 processor, intel server motherboard, 32gb ddr3 ecc, mdadm mirror hdd raid for system, mdadm ssd raid for database(postgres). Both servers have similar (not identical) components. Smart is OK. It seems that the problem is in the software. Python process and database are running on this servers. Syslog (time of reboot): Aug 23 13:42:23 xeon hddtemp[1411]: /dev/sdc: WDC WD15NPVT-00Z2TT0: 34 C Aug 23 13:42:23 xeon hddtemp[1411]: /dev/sdd: WDC WD15NPVT-00Z2TT0: 34 C Aug 23 13:43:24 xeon hddtemp[1411]: /dev/sdc: WDC WD15NPVT-00Z2TT0: 34 C Aug 23 13:43:24 xeon hddtemp[1411]: /dev/sdd: WDC WD15NPVT-00Z2TT0: 34 C Aug 23 13:44:14 xeon sensord: Chip: acpitz-virtual-0 Aug 23 13:44:14 xeon sensord: Adapter: Virtual device Aug 23 13:44:14 xeon sensord: temp1: 27.8 C Aug 23 13:44:14 xeon sensord: temp2: 29.8 C Aug 23 13:44:14 xeon sensord: Chip: coretemp-isa-0000 Aug 23 13:44:14 xeon sensord: Adapter: ISA adapter Aug 23 13:44:14 xeon sensord: Physical id 0: 37.0 C Aug 23 13:44:14 xeon sensord: Core 0: 37.0 C Aug 23 13:44:14 xeon sensord: Core 1: 37.0 C Aug 23 13:44:14 xeon sensord: Core 2: 37.0 C Aug 23 13:44:14 xeon sensord: Core 3: 37.0 C Aug 23 13:44:24 xeon hddtemp[1411]: /dev/sdc: WDC WD15NPVT-00Z2TT0: 34 C Aug 23 13:44:24 xeon hddtemp[1411]: /dev/sdd: WDC WD15NPVT-00Z2TT0: 34 C Aug 23 13:47:01 xeon kernel: imklog 5.8.6, log source = /proc/kmsg started. Aug 23 13:47:01 xeon rsyslogd: [origin software="rsyslogd" swVersion="5.8.6" x-pid="582" x-info="http://www.rsyslog.com"] start Aug 23 13:47:01 xeon rsyslogd: rsyslogd's groupid changed to 103 Aug 23 13:47:01 xeon rsyslogd: rsyslogd's userid changed to 101 Aug 23 13:47:00 xeon rsyslogd-2039: Could not open output pipe '/dev/xconsole' [try http://www.rsyslog.com/e/2039 ] Aug 23 13:47:01 xeon kernel: [ 0.000000] Initializing cgroup subsys cpuset Aug 23 13:47:01 xeon kernel: [ 0.000000] Initializing cgroup subsys cpu Aug 23 13:47:01 xeon kernel: [ 0.000000] Initializing cgroup subsys cpuacct Aug 23 13:47:01 xeon kernel: [ 0.000000] Linux version 3.11.0-26-generic (buildd@komainu) (gcc version 4.6.3 (Ubuntu/Linaro 4.6.3-1ubuntu5) ) #45~precise1-Ubuntu SMP Tue Jul 15 04:02:35 UTC 2014 (Ubuntu 3.11.0-26.45~precise1-generic 3.11.10.12) Aug 23 13:47:01 xeon kernel: [ 0.000000] Command line: BOOT_IMAGE=/boot/vmlinuz-3.11.0-26-generic root=UUID=0daa7f53-6c74-47d2-873e-ebd339cd39b0 ro splash quiet vt.handoff=7 Aug 23 13:47:01 xeon kernel: [ 0.000000] KERNEL supported cpus: Aug 23 13:47:01 xeon kernel: [ 0.000000] Intel GenuineIntel Aug 23 13:47:01 xeon kernel: [ 0.000000] AMD AuthenticAMD Aug 23 13:47:01 xeon kernel: [ 0.000000] Centaur CentaurHauls Aug 23 13:47:01 xeon kernel: [ 0.000000] e820: BIOS-provided physical RAM map: Aug 23 13:47:01 xeon kernel: [ 0.000000] BIOS-e820: [mem 0x0000000000000000-0x000000000009bbff] usable Aug 23 13:47:01 xeon kernel: [ 0.000000] BIOS-e820: [mem 0x000000000009bc00-0x000000000009ffff] reserved Dmseg - nothing strange.

    Read the article

  • 6 Facts About GlassFish Announcement

    - by Bruno.Borges
    Since Oracle announced the end of commercial support for future Oracle GlassFish Server versions, the Java EE world has started wondering what will happen to GlassFish Server Open Source Edition. Unfortunately, there's a lot of misleading information going around. So let me clarify some things with facts, not FUD. Fact #1 - GlassFish Open Source Edition is not dead GlassFish Server Open Source Edition will remain the reference implementation of Java EE. The current trunk is where an implementation for Java EE 8 will flourish, and this will become the future GlassFish 5.0. Calling "GlassFish is dead" does no good to the Java EE ecosystem. The GlassFish Community will remain strong towards the future of Java EE. Without revenue-focused mind, this might actually help the GlassFish community to shape the next version, and set free from any ties with commercial decisions. Fact #2 - OGS support is not over As I said before, GlassFish Server Open Source Edition will continue. Main change is that there will be no more future commercial releases of Oracle GlassFish Server. New and existing OGS 2.1.x and 3.1.x commercial customers will continue to be supported according to the Oracle Lifetime Support Policy. In parallel, I believe there's no other company in the Java EE business that offers commercial support to more than one build of a Java EE application server. This new direction can actually help customers and partners, simplifying decision through commercial negotiations. Fact #3 - WebLogic is not always more expensive than OGS Oracle GlassFish Server ("OGS") is a build of GlassFish Server Open Source Edition bundled with a set of commercial features called GlassFish Server Control and license bundles such as Java SE Support. OGS has at the moment of this writing the pricelist of U$ 5,000 / processor. One information that some bloggers are mentioning is that WebLogic is more expensive than this. Fact 3.1: it is not necessarily the case. The initial edition of WebLogic is called "Standard Edition" and falls into a policy where some “Standard Edition” products are licensed on a per socket basis. As of current pricelist, US$ 10,000 / socket. If you do the math, you will realize that WebLogic SE can actually be significantly more cost effective than OGS, and a customer can save money if running on a CPU with 4 cores or more for example. Quote from the price list: “When licensing Oracle programs with Standard Edition One or Standard Edition in the product name (with the exception of Java SE Support, Java SE Advanced, and Java SE Suite), a processor is counted equivalent to an occupied socket; however, in the case of multi-chip modules, each chip in the multi-chip module is counted as one occupied socket.” For more details speak to your Oracle sales representative - this is clearly at list price and every customer typically has a relationship with Oracle (like they do with other vendors) and different contractual details may apply. And although OGS has always been production-ready for Java EE applications, it is no secret that WebLogic has always been more enterprise, mission critical application server than OGS since BEA. Different editions of WLS provide features and upgrade irons like the WebLogic Diagnostic Framework, Work Managers, Side by Side Deployment, ADF and TopLink bundled license, Web Tier (Oracle HTTP Server) bundled licensed, Fusion Middleware stack support, Oracle DB integration features, Oracle RAC features (such as GridLink), Coherence Management capabilities, Advanced HA (Whole Service Migration and Server Migration), Java Mission Control, Flight Recorder, Oracle JDK support, etc. Fact #4 - There’s no major vendor supporting community builds of Java EE app servers There are no major vendors providing support for community builds of any Open Source application server. For example, IBM used to provide community support for builds of Apache Geronimo, not anymore. Red Hat does not commercially support builds of WildFly and if I remember correctly, never supported community builds of former JBoss AS. Oracle has never commercially supported GlassFish Server Open Source Edition builds. Tomitribe appears to be the exception to the rule, offering commercial support for Apache TomEE. Fact #5 - WebLogic and GlassFish share several Java EE implementations It has been no secret that although GlassFish and WebLogic share some JSR implementations (as stated in the The Aquarium announcement: JPA, JSF, WebSockets, CDI, Bean Validation, JAX-WS, JAXB, and WS-AT) and WebLogic understands GlassFish deployment descriptors, they are not from the same codebase. Fact #6 - WebLogic is not for GlassFish what JBoss EAP is for WildFly WebLogic is closed-source offering. It is commercialized through a license-based plus support fee model. OGS although from an Open Source code, has had the same commercial model as WebLogic. Still, one cannot compare GlassFish/WebLogic to WildFly/JBoss EAP. It is simply not the same case, since Oracle has had two different products from different codebases. The comparison should be limited to GlassFish Open Source / Oracle GlassFish Server versus WildFly / JBoss EAP. But the message now is much clear: Oracle will commercially support only the proprietary product WebLogic, and invest on GlassFish Server Open Source Edition as the reference implementation for the Java EE platform and future Java EE 8, as a developer-friendly community distribution, and encourages community participation through Adopt a JSR and contributions to GlassFish. In comparison Oracle's decision has pretty much the same goal as to when IBM killed support for Websphere Community Edition; and to when Red Hat decided to change the name of JBoss Community Edition to WildFly, simplifying and clarifying marketing message and leaving the commercial field wide open to JBoss EAP only. Oracle can now, as any other vendor has already been doing, focus on only one commercial offer. Some users are saying they will now move to WildFly, but it is important to note that Red Hat does not offer commercial support for WildFly builds. Although the future JBoss EAP versions will come from the same codebase as WildFly, the builds will definitely not be the same, nor sharing 100% of their functionalities and bug fixes. This means there will be no company running a WildFly build in production with support from Red Hat. This discussion has also raised an important and interesting information: Oracle offers a free for developers OTN License for WebLogic. For other environments this is different, but please note this is the same policy Red Hat applies to JBoss EAP, as stated in their download page and terms. Oracle had the same policy for OGS. TL;DR; GlassFish Server Open Source Edition isn’t dead. Current and new OGS 2.x/3.x customers will continue to have support (respecting LSP). WebLogic is not necessarily more expensive than OGS. Oracle will focus on one commercially supported Java EE application server, like other vendors also limit themselves to support one build/product only. Community builds are hardly supported. Commercially supported builds of Open Source products are not exactly from the same codebase as community builds. What's next for GlassFish and the Java EE community? There are conversations in place to tackle some of the community desires, most of them stated by Markus Eisele in his blog post. We will keep you posted.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 24 25 26 27 28 29 30 31 32 33 34 35  | Next Page >