Search Results

Search found 2255 results on 91 pages for 'formatting'.

Page 28/91 | < Previous Page | 24 25 26 27 28 29 30 31 32 33 34 35  | Next Page >

  • How to display a DateTime with chosen date parts, but in the order of the FormatProvider?

    - by Stephane
    I want to display the date in the order that the culture provides, but with the elements I want only. The DateTime.Tostring() method has a list of patterns that are very useful but I would like a very small change in it. The CultureInfo used in the following the following code are chosen as example, I don't want to rely on a specific list of CultureInfo, if possible var now = DateTime.Now; string nowString = now.ToString("m", CultureInfo.GetCultureInfo("en-us")); Console.WriteLine(nowString); nowString = now.ToString("m", CultureInfo.GetCultureInfo("fr-FR")); Console.WriteLine(nowString); displays : April 12 12 avril I would like a pattern that display the abbreviation of the month and the day, but that keeps the correct order from the specified CultureInfo. using the pattern "MMM dd" will always display the month's abbreviation first, followed by the day, breaking the french order for example. Any way to achieve that without too much custom code?

    Read the article

  • How do you obtain a formatted date and time for the current locale in C?

    - by jwaddell
    What C function should I call to obtain a formatted date and time for the locale where the program is being executed? I'm asking this question because I have run into a problem using the ClamAV daemon API. The VERSION command returns the date and time of the latest virus definitions, but the code uses a call to ctime to format it. As far as I can tell ctime does not format the datetime according to the current locale and uses the English abbreviations for days of the week and the month in the returned string. This causes problems as my Java program which uses the ClamAV API does respect the current locale and thus expects the day of the week and month name to have the local abbreviations. The datetime format would need to be in the same format as that produced by ctime: Www Mmm dd hh:mm:ss yyyy Where Www is the weekday, Mmm the month in letters, dd the day of the month, hh:mm:ss the time, and yyyy the year. I could rewrite the Java program to always assume English dates but I'd be happier to submit a patch to ClamAV as it seems like a bug on their side to me.

    Read the article

  • Gnuplot axis scale units

    - by Kami
    I have the following data in a log file: 1270719764.323778250 926 vm-mystery1 1073744528 0 1 1270719764.323815250 926 vm-mystery1 1073746080 0 1 1270719764.323842250 926 vm-mystery1 1075968992 0 1 The first column is a UNIX date that I want to use for my x-axis in a gnuplot graph. My graph looks ugly because the first unit in the x-axis is 1.27072e+09. I would like to have the x-axis looks like the following : x axis [(first row date - first row date) ; (last row date - first row date)] displaying ticks in mili seconds. How to do this ?

    Read the article

  • Microsoft Word Document Controls not accepting carriage returns

    - by Scott
    So, I have a Microsoft Word 2007 Document with several Plain Text Format (I have tried Rich Text Format as well) controls which accept input via XML. For carriage returns, I had the string being passed through XML containing "\r\n" when I wanted a carriage return, but the word document ignored that and just kept wrapping things on the same line. I also tried replacing the \r\n with System.Environment.NewLine in my C# mapper, but that just put in \r\n anyway, which still didn't work. Note also that on the control itself I have set it to "Allow Carriage Returns (Multiple Paragrpahs)" in the control properties. This is the XML for the listMapper <Field id="32" name="32" fieldType="SimpleText"> <DataSelector path="/Data/DB/DebtProduct"> <InputField fieldType="" path="/Data/DB/Client/strClientFirm" link="" type=""/> <InputField fieldType="" path="strClientRefDebt" link="" type=""/> </DataSelector> <DataMapper formatString="{0} Account Number: {1}" name="SimpleListMapper" type=""> <MapperData> </MapperData> </DataMapper> </Field> Note that this is the listMapper C# where I actually map the list (notice where I try and append the system.environment.newline) namespace DocEngine.Core.DataMappers { public class CSimpleListMapper:CBaseDataMapper { public override void Fill(DocEngine.Core.Interfaces.Document.IControl control, CDataSelector dataSelector) { if (control != null && dataSelector != null) { ISimpleTextControl textControl = (ISimpleTextControl)control; IContent content = textControl.CreateContent(); CInputFieldCollection fileds = dataSelector.Read(Context); StringBuilder builder = new StringBuilder(); if (fileds != null) { foreach (List<string> lst in fileds) { if (CanMap(lst) == false) continue; if (builder.Length > 0 && lst[0].Length > 0) builder.Append(Environment.NewLine); if (string.IsNullOrEmpty(FormatString)) builder.Append(lst[0]); else builder.Append(string.Format(FormatString, lst.ToArray())); } content.Value = builder.ToString(); textControl.Content = content; applyRules(control, null); } } } } } Does anybody have any clue at all how I can get MS Word 2007 (docx) to quit ignoring my newline characters??

    Read the article

  • Why am I getting a ParseException when using SimpleDateFormat to format a date and then parse it?

    - by Greg
    I have been debugging some existing code for which unit tests are failing on my system, but not on colleagues' systems. The root cause is that SimpleDateFormat is throwing ParseExceptions when parsing dates that should be parseable. I created a unit test that demonstrates the code that is failing on my system: import java.text.DateFormat; import java.text.ParseException; import java.text.SimpleDateFormat; import java.util.Date; import java.util.TimeZone; import junit.framework.TestCase; public class FormatsTest extends TestCase { public void testParse() throws ParseException { DateFormat formatter = new SimpleDateFormat("yyyyMMddHHmmss.SSS Z"); formatter.setTimeZone(TimeZone.getDefault()); formatter.setLenient(false); formatter.parse(formatter.format(new Date())); } } This test throws a ParseException on my system, but runs successfully on other systems. java.text.ParseException: Unparseable date: "20100603100243.118 -0600" at java.text.DateFormat.parse(DateFormat.java:352) at FormatsTest.testParse(FormatsTest.java:16) I have found that I can setLenient(true) and the test will succeed. The setLenient(false) is what is used in the production code that this test mimics, so I don't want to change it.

    Read the article

  • Reformatting a Java String

    - by Travis
    I have a string that looks like this: CALDARI_STARSHIP_ENGINEERING and I need to edit it to look like Caldari Starship Engineering Unfortunately it's three in the morning and I cannot for the life of me figure this out. I've always had trouble with replacing stuff in strings so any help would be awesome and would help me understand how to do this in the future.

    Read the article

  • How do you print a limited number of characters?

    - by Mike Pateras
    Sorry to put a post up about something so simple, but I don't see what I'm doing wrong here. char data[1024]; DWORD numRead; ReadFile(handle, data, 1024, &numRead, NULL); if (numRead > 0) printf(data, "%.5s"); My intention with the above is to read data from a file, and then only print out 5 characters. However, it prints out all 1024 characters, which is contrary to what I'm reading here. The goal, of course, is to do something like: printf(data, "%.*s", numRead); What am I doing wrong here?

    Read the article

  • AudioConverterConvertBuffer problem with insz error

    - by Samuel
    Hi Codegurus, I have a problem with the this function AudioConverterConvertBuffer. Basically I want to convert from this format _ streamFormat.mFormatFlags = kLinearPCMFormatFlagIsSignedInteger | kLinearPCMFormatFlagIsPacked |0 ; _streamFormat.mBitsPerChannel = 16; _streamFormat.mChannelsPerFrame = 2; _streamFormat.mBytesPerPacket = 4; _streamFormat.mBytesPerFrame = 4; _streamFormat.mFramesPerPacket = 1; _streamFormat.mSampleRate = 44100; _streamFormat.mReserved = 0; to this format _streamFormatOutput.mFormatFlags = kLinearPCMFormatFlagIsSignedInteger | kLinearPCMFormatFlagIsPacked|0 ;//| kAudioFormatFlagIsNonInterleaved |0; _streamFormatOutput.mBitsPerChannel = 16; _streamFormatOutput.mChannelsPerFrame = 1; _streamFormatOutput.mBytesPerPacket = 2; _streamFormatOutput.mBytesPerFrame = 2; _streamFormatOutput.mFramesPerPacket = 1; _streamFormatOutput.mSampleRate = 44100; _streamFormatOutput.mReserved = 0; and what i want to do is to extract an audio channel(Left channel or right channel) from an LPCM buffer based on the input format to make it mono in the output format. Some logic code to convert is as follows This is to set the channel map for PCM output file SInt32 channelMap[1] = {0}; status = AudioConverterSetProperty(converter, kAudioConverterChannelMap, sizeof(channelMap), channelMap); and this is to convert the buffer in a while loop AudioBufferList audioBufferList; CMBlockBufferRef blockBuffer; CMSampleBufferGetAudioBufferListWithRetainedBlockBuffer(sampBuffer, NULL, &audioBufferList, sizeof(audioBufferList), NULL, NULL, 0, &blockBuffer); for (int y=0; y<audioBufferList.mNumberBuffers; y++) { AudioBuffer audioBuffer = audioBufferList.mBuffers[y]; //frames = audioBuffer.mData; NSLog(@"the number of channel for buffer number %d is %d",y,audioBuffer.mNumberChannels); NSLog(@"The buffer size is %d",audioBuffer.mDataByteSize); numBytesIO = audioBuffer.mDataByteSize; convertedBuf = malloc(sizeof(char)*numBytesIO); status = AudioConverterConvertBuffer(converter, audioBuffer.mDataByteSize, audioBuffer.mData, &numBytesIO, convertedBuf); char errchar[10]; NSLog(@"status audio converter convert %d",status); if (status != 0) { NSLog(@"Fail conversion"); assert(0); } NSLog(@"Bytes converted %d",numBytesIO); status = AudioFileWriteBytes(mRecordFile, YES, countByteBuf, &numBytesIO, convertedBuf); NSLog(@"status for writebyte %d, bytes written %d",status,numBytesIO); free(convertedBuf); if (numBytesIO != audioBuffer.mDataByteSize) { NSLog(@"Something wrong in writing"); assert(0); } countByteBuf = countByteBuf + numBytesIO; But the insz problem is there... so it cant convert. I would appreciate any input Thanks in advance

    Read the article

  • Replicating Java's DecimalFormat in C#

    - by Frank Krueger
    I am trying to replicate a subset of Java's DecimalFormat class. Below is what I've come up with. Does this look right to everyone? public class DecimalFormat : NumberFormat { int _maximumFractionDigits; int _minimumFractionDigits; string _format; void RebuildFormat () { _format = "{0:0."; _format += new string ('0', _minimumFractionDigits); if (_maximumFractionDigits > _minimumFractionDigits) { _format += new string ('#', _maximumFractionDigits - _minimumFractionDigits); } _format += "}"; } public override string format (object value) { return string.Format (_format, value); } public override void setMaximumFractionDigits (int n) { _maximumFractionDigits = n; RebuildFormat (); } public override void setMinimumFractionDigits (int n) { _minimumFractionDigits = n; RebuildFormat (); } public override void setGroupingUsed (bool g) { } public static NumberFormat getInstance () { return new DecimalFormat (); } }

    Read the article

  • Finding character in String in Vector.

    - by SoulBeaver
    Judging from the title, I kinda did my program in a fairly complicated way. BUT! I might as well ask anyway xD This is a simple program I did in response to question 3-3 of Accelerated C++, which is an awesome book in my opinion. I created a vector: vector<string> countEm; That accepts all valid strings. Therefore, I have a vector that contains elements of strings. Next, I created a function int toLowerWords( vector<string> &vec ) { for( int loop = 0; loop < vec.size(); loop++ ) transform( vec[loop].begin(), vec[loop].end(), vec[loop].begin(), ::tolower ); that splits the input into all lowercase characters for easier counting. So far, so good. I created a third and final function to actually count the words, and that's where I'm stuck. int counter( vector<string> &vec ) { for( int loop = 0; loop < vec.size(); loop++ ) for( int secLoop = 0; secLoop < vec[loop].size(); secLoop++ ) { if( vec[loop][secLoop] == ' ' ) That just looks ridiculous. Using a two-dimensional array to call on the characters of the vector until I find a space. Ridiculous. I don't believe that this is an elegant or even viable solution. If it was a viable solution, I would then backtrack from the space and copy all characters I've found in a separate vector and count those. My question then is. How can I dissect a vector of strings into separate words so that I can actually count them? I thought about using strchr, but it didn't give me any epiphanies.

    Read the article

  • Format date in String Template email

    - by Gearóid
    I'm creating an email using String Template but when I print out a date, it prints out the full date (eg. Wed Apr 28 10:51:37 BST 2010). I'd like to print it out in the format dd/mm/yyyy but don't know how to format this in the .st file. I can't modify the date individually (using java's simpleDateFormatter) because I iterate over a collection of objects with dates. Is there a way to format the date in the .st email template?

    Read the article

  • Why are months off by one with Java SimpleDateFormat ?

    - by Natim
    Hello, I am using SimpleDateFormat to display a Calendar like this : public String getDate() { String DATE_FORMAT = "EEEE, dd/MM/yyyy HH:mm:ss"; SimpleDateFormat sdf = new SimpleDateFormat(DATE_FORMAT); System.err.println(date.getTime().getMonth()); return sdf.format(date.getTime()); } The shell returns 6 and the display : mardi, 06/07/2010 12:44:52 It can't be possible ? Why ? Thanks

    Read the article

  • Python: Convert format string to regular expression

    - by miracle2k
    The users of my app can configure the layout of certain files via a format string. For example, the config value the user specifies might be: layout = '%(group)s/foo-%(locale)s/file.txt' I now need to find all such files that already exist. This seems easy enough using the glob module: glob_pattern = layout % {'group': '*', 'locale': '*'} glob.glob(glob_pattern) However, now comes the hard part: Given the list of glob results, I need to get all those filename-parts that matched a given placeholder, for example all the different "locale" values. I thought I would generate a regular expression for the format string that I could then match against the list of glob results (or then possibly skipping glob and doing all the matching myself). But I can't find a nice way to create the regex with both the proper group captures, and escaping the rest of the input. For example, this might give me a regex that matches the locales: regex = layout % {'group': '.*', 'locale': (.*)} But to be sure the regex is valid, I need to pass it through re.escape(), which then also escapes the regex syntax I have just inserted. Calling re.escape() first ruins the format string. I know there's fnmatch.translate(), which would even give me a regex - but not one that returns the proper groups. Is there a good way to do this, without a hack like replacing the placeholders with a regex-safe unique value etc.? Is there possibly some way (a third party library perhaps?) that allows dissecting a format string in a more flexible way, for example splitting the string at the placeholder locations?

    Read the article

  • Dealing with a badly formatted CSV file

    - by Josh K
    I have an exceptionally bad CSV file. Although I "solved" the problem in the end by manually writing scripts to process and reprocess this specific file I wanted to know if there were any other solutions out there. You have a CSV file that has all the fields terminated by | (pipe) characters. Running a quick check shows you that there are 53 fields in the file. The person who gave you the file claims there there are only 28 fields. Not all of the fields have information in them. For example there are five custom_field_{num} fields which may or may not have data. How would you get this into a database nicely? The ideal solution (and one I searched high and low for) would be to just throw it all into a table with no column names or specifications. Then remove any columns that were completely blank and then give them titles and specifications.

    Read the article

  • Does C++11 offer a better way to concatenate strings on the fly?

    - by Lohoris
    I've seen this answer, and I wonder (I hope) if C++11 has come up with a native better method to concatenate, and possibly format, strings. With "better" I mean actually really one-line, like in pretty much all higher level languages (bonus points if it supports something like python's "formatted string"%(tuple) syntax but I guess that's really hoping for too much). The ideal result should be something like: my_func("bla bla bla" << int(my_int) << "bla bla bla"); The only barely acceptable methods listed in that answer are the fastformat ones, but I wonder if C++11 managed to do better.

    Read the article

  • Java Code Formating

    - by the qwerty
    I'm using FreeMarker to generate java code, but as most of it is dynamically generated it's difficult to control the code formation. I want to get code well formatted. Does anyone knows a lib or something like a pretty printer for java code?

    Read the article

  • XmlSerializer.Deserialize method appends timezone to a time and datetime field

    - by G33kKahuna
    Have a small script in Microsoft.NET 2.0 that deserializes a XML back to a typed object, connects dyanimcally to a web service using ServiceDescription and binds the deserialized typed object to the WebMethod inbound. The XML prior to serialization looks like below <completion_time>12:19:38</completion_time> on the wire when communicating to the web service looks like below <completion_time>12:19:38.0000000-04:00</completion_time> with the timezone appended to the end. This is causing the time to be read differently when communicating to a web service at a different timezone. is there anyway to let XmlSerializer skip the timezone? Or any other known workarounds?

    Read the article

  • Why not put all braces inline in C++/C#/Java/javascript etc.?

    - by DanM
    Of all the conventions out there for positioning braces in C++, C#, Java, etc., I don't think I've ever seen anyone try to propose something like this: public void SomeMethod(int someInput, string someOtherInput) { if (someInput > 5) { var addedNumber = someInput + 5; var subtractedNumber = someInput - 5; } else { var addedNumber = someInput + 10; var subtractedNumber = someInput; } } public void SomeOtherMethod(int someInput, string someOtherInput( { ... } But why not? I'm sure it would take some getting used to, but I personally don't have any difficulty following what's going on here. I believe indentation is the dominant factor in being able to see how code is organized into blocks and sub-blocks. Braces are just visual noise to me. They are these ugly things that take up lines where I don't want them. Maybe I just feel that way because I was weened on basic (and later VB), but I just don't like braces taking up lines. If I want a gap between blocks, I can always add an empty line, but I don't like being forced to have gaps simply because the convention says the closing brace needs to be on its own line. I made this a community wiki because I realize this is not a question with a defined answer. I'm just curious what people think. I know that no one does this currently (at least, not that I've seen), and I know that the auto-formatter in my IDE doesn't support it, but are there are any other solid reasons not to format code this way, assuming you are working with a modern IDE that color codes and auto-indents? Are there scenarios where it will become a readability nightmare? Better yet, are you aware of any research on this?

    Read the article

  • DateTime Format Strings?

    - by Phil
    I have the date format string dd-mm-yy. Please can you tell me how to add hours and minutes to the string (i.e 13-03-2010.21.03) .... DateTime.Today.ToString("dd-mm-yy") ?

    Read the article

< Previous Page | 24 25 26 27 28 29 30 31 32 33 34 35  | Next Page >