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  • How to search for alphanumeric word before or after a keyword in perl?

    - by aliocee
    I have sentences as shown in the below examples: $sen1 = "The quick brown fox jump KEYWORD over123 the3 lazy dog, fox is quick"; $sen2 = "The quick brown fox jump123 KEYWORD over the lazy dog, fox is quick"; i want to use the keyword 'KEYWORD' as my search string to extract the alphanumeric words before and after the search string using Perl regular expression. sample output: over123 jump123 NB: The word 'the3' is left out because i'm only searching for alphanumeric words exactly before or after the 'KEYWORD'. Thanks

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  • Wordpress - related posts by custom taxonomy problem

    - by Nordin
    Hello, I'm trying to display related posts based on a custum taxonomy. I found a query at wordpress.org that kind of works. However the original post gets duplicated in the results multiple times. (words is the name of the custom taxonomy I use) What seems to happen is that the single post gets duplicated according to what amount showpost is set. Any idea's what could cause this? The code: <?php //for in the loop, display all "content", regardless of post_type, //that have the same custom taxonomy (e.g. words) terms as the current post $backup = $post; // backup the current object $found_none = '<h2>No related posts found!</h2>'; $taxonomy = 'words';// e.g. post_tag, category, custom taxonomy $param_type = 'words'; // e.g. tag__in, category__in, but genre__in will NOT work $post_types = get_post_types( array('public' => true), 'names' ); $tax_args=array('orderby' => 'none'); $tags = wp_get_post_terms( $post->ID , $taxonomy, $tax_args); if ($tags) { foreach ($tags as $tag) { $args=array( "$param_type" => $tag->slug, 'post__not_in' => array($post->ID), 'post_type' => $post_types, 'showposts'=>5, 'caller_get_posts'=>1 ); $my_query = null; $my_query = new WP_Query($args); if( $my_query->have_posts() ) { while ($my_query->have_posts()) : $my_query->the_post(); ?> <h3><a href="<?php the_permalink() ?>" rel="bookmark" title="<?php the_title(); ?>"><?php the_title(); ?></a></h3> <?php $found_none = ''; endwhile; } } } if ($found_none) { echo $found_none; } $post = $backup; // copy it back wp_reset_query(); // to use the original query again ?>

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  • Can I write a blog post criticizing Microsoft products ?

    - by madewulf
    My employer is a Microsoft Certified Partner. I am using some technology from Microsoft and as there is not so much feedback about it on the web, I would like to write an overview, with some kind words and a lot of not-so-kind words about it. Does anybody know if this is allowed by the licenses from Microsoft ?

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  • How can I match string order between two documents in PERL?

    - by Randy
    Hi, I've a problem in making a PERL program for matching the words in two documents. Let's say there are documents A and B So I want to delete the words in document A that's not in the document B A: I eat pizza B: She go to the market and eat pizza result: eat pizza I use Perl for the system and the sentences in each document isn't in a big numbers so I think I won't use SQL And the program is a subproram for automatic essay grading for Indonesian Language (Bahasa) Thanx, Sorry if my question is a bit confusing. I'm really new to 'this world' :)

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  • Algorithm for multiple word matching in a text, count the number of every matched word

    - by 66
    I have noticed that it has solutions for matching multiple words in a given text, such as below: http://stackoverflow.com/questions/1099985/algorithm-for-multiple-word-matching-in-text If I want to know exactly the number of appearances of each matched word in the text, my solution is like this: step 1: using ac-algorithm to obtain the maching words; step 2: count the number of each word obtained in step 1 is there a faster way? Thx~

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  • Read next word in java

    - by ArtWorkAD
    Hi, I have a text file that has following content: ac und accipio annehmen ad zu adeo hinzugehen ... I read the text file and iterate through the lines: Scanner sc = new Scanner(new File("translate.txt")); while(sc.hasNext()){ String line = sc.nextLine(); } Each line has two words. Is there any method in java to get the next word or do I have to split the line string to get the words?

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  • Probelm with String.split() in java

    - by Matt
    What I am trying to do is read a .java file, and pick out all of the identifiers and store them in a list. My problem is with the .split() method. If you run this code the way it is, you will get ArrayOutOfBounds, but if you change the delimiter from "." to anything else, the code works. But I need to lines parsed by "." so is there another way I could accomplish this? import java.io.BufferedReader; import java.io.FileNotFoundException; import java.io.FileReader; import java.io.IOException; import java.util.*; public class MyHash { private static String[] reserved = new String[100]; private static List list = new LinkedList(); private static List list2 = new LinkedList(); public static void main (String args[]){ Hashtable hashtable = new Hashtable(997); makeReserved(); readFile(); String line; ListIterator itr = list.listIterator(); int listIndex = 0; while (listIndex < list.size()) { if (itr.hasNext()){ line = itr.next().toString(); //PROBLEM IS HERE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! String[] words = line.split("."); //CHANGE THIS AND IT WILL WORK System.out.println(words[0]); //TESTING TO SEE IF IT WORKED } listIndex++; } } public static void readFile() { String text; String[] words; BufferedReader in = null; try { in = new BufferedReader(new FileReader("MyHash.java")); //NAME OF INPUT FILE } catch (FileNotFoundException ex) { Logger.getLogger(MyHash.class.getName()).log(Level.SEVERE, null, ex); } try { while ((text = in.readLine()) != null){ text = text.trim(); words = text.split("\\s+"); for (int i = 0; i < words.length; i++){ list.add(words[i]); } for (int j = 0; j < reserved.length; j++){ if (list.contains(reserved[j])){ list.remove(reserved[j]); } } } } catch (IOException ex) { Logger.getLogger(MyHash.class.getName()).log(Level.SEVERE, null, ex); } try { in.close(); } catch (IOException ex) { Logger.getLogger(MyHash.class.getName()).log(Level.SEVERE, null, ex); } } public static int keyIt (int x) { int key = x % 997; return key; } public static int horner (String word){ int length = word.length(); char[] letters = new char[length]; for (int i = 0; i < length; i++){ letters[i]=word.charAt(i); } char[] alphabet = new char[26]; String abc = "abcdefghijklmnopqrstuvwxyz"; for (int i = 0; i < 26; i++){ alphabet[i]=abc.charAt(i); } int[] numbers = new int[length]; int place = 0; for (int i = 0; i < length; i++){ for (int j = 0; j < 26; j++){ if (alphabet[j]==letters[i]){ numbers[place]=j+1; place++; } } } int hornered = numbers[0] * 32; for (int i = 1; i < numbers.length; i++){ hornered += numbers[i]; if (i == numbers.length -1){ return hornered; } hornered = hornered % 997; hornered *= 32; } return hornered; } public static String[] makeReserved (){ reserved[0] = "abstract"; reserved[1] = "assert"; reserved[2] = "boolean"; reserved[3] = "break"; reserved[4] = "byte"; reserved[5] = "case"; reserved[6] = "catch"; reserved[7] = "char"; reserved[8] = "class"; reserved[9] = "const"; reserved[10] = "continue"; reserved[11] = "default"; reserved[12] = "do"; reserved[13] = "double"; reserved[14] = "else"; reserved[15] = "enum"; reserved[16] = "extends"; reserved[17] = "false"; reserved[18] = "final"; reserved[19] = "finally"; reserved[20] = "float"; reserved[21] = "for"; reserved[22] = "goto"; reserved[23] = "if"; reserved[24] = "implements"; reserved[25] = "import"; reserved[26] = "instanceof"; reserved[27] = "int"; reserved[28] = "interface"; reserved[29] = "long"; reserved[30] = "native"; reserved[31] = "new"; reserved[32] = "null"; reserved[33] = "package"; reserved[34] = "private"; reserved[35] = "protected"; reserved[36] = "public"; reserved[37] = "return"; reserved[38] = "short"; reserved[39] = "static"; reserved[40] = "strictfp"; reserved[41] = "super"; reserved[42] = "switch"; reserved[43] = "synchronize"; reserved[44] = "this"; reserved[45] = "throw"; reserved[46] = "throws"; reserved[47] = "trasient"; reserved[48] = "true"; reserved[49] = "try"; reserved[50] = "void"; reserved[51] = "volatile"; reserved[52] = "while"; reserved[53] = "="; reserved[54] = "=="; reserved[55] = "!="; reserved[56] = "+"; reserved[57] = "-"; reserved[58] = "*"; reserved[59] = "/"; reserved[60] = "{"; reserved[61] = "}"; return reserved; } }

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  • How to combine array list string in java ?

    - by tiendv
    I have some arraylist string with keyword inside like that ! A windows is arraylist string with keyword is bold Struct of window : 9 words before + keyword + 9 words after You can see some window overlaping How to i combine that arraylist to receive like that : Thanks

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  • Trouble passing a template function as an argument to another function in C++

    - by Darel
    Source of the problem -Accelerated C++, problem 8-5 I've written a small program that examines lines of string input, and tallies the number of times a word appears on a given line. The following code accomplishes this: #include <map> #include <iostream> #include <string> #include <vector> #include <list> #include <cctype> #include <iterator> using std::vector; using std::string; using std::cin; using std::cout; using std::endl; using std::getline; using std::istream; using std::string; using std::list; using std::map; using std::isspace; using std::ostream_iterator; using std::allocator; inline void keep_window_open() { cin.clear(); cout << "Please enter EOF to exit\n"; char ch; cin >> ch; return; } template <class Out> void split(const string& s, Out os) { vector<string> ret; typedef string::size_type string_size; string_size i = 0; // invariant: we have processed characters `['original value of `i', `i)' while (i != s.size()) { // ignore leading blanks // invariant: characters in range `['original `i', current `i)' are all spaces while (i != s.size() && isspace(s[i])) ++i; // find end of next word string_size j = i; // invariant: none of the characters in range `['original `j', current `j)' is a space while (j != s.size() && !isspace(s[j])) ++j; // if we found some nonwhitespace characters if (i != j) { // copy from `s' starting at `i' and taking `j' `\-' `i' chars *os++ = (s.substr(i, j - i)); i = j; } } } // find all the lines that refer to each word in the input map<string, vector<int> > xref(istream& in) // works // now try to pass the template function as an argument to function - what do i put for templated type? //map<string, vector<int> > xref(istream& in, void find_words(vector<string, typedef Out) = split) #LINE 1# { string line; int line_number = 0; map<string, vector<int> > ret; // read the next line while (getline(in, line)) { ++line_number; // break the input line into words vector<string> words; // works // #LINE 2# split(line, back_inserter(words)); // #LINE 3# //find_words(line, back_inserter(words)); // #LINE 4# attempting to use find_words as an argument to function // remember that each word occurs on the current line for (vector<string>::const_iterator it = words.begin(); it != words.end(); ++it) ret[*it].push_back(line_number); } return ret; } int main() { cout << endl << "Enter lines of text, followed by EOF (^Z):" << endl; // call `xref' using `split' by default map<string, vector<int> > ret = xref(cin); // write the results for (map<string, vector<int> >::const_iterator it = ret.begin(); it != ret.end(); ++it) { // write the word cout << it->first << " occurs on line(s): "; // followed by one or more line numbers vector<int>::const_iterator line_it = it->second.begin(); cout << *line_it; // write the first line number ++line_it; // write the rest of the line numbers, if any while (line_it != it->second.end()) { cout << ", " << *line_it; ++line_it; } // write a new line to separate each word from the next cout << endl; } keep_window_open(); return 0; } As you can see, the split function is a template function to handle various types of output iterators as desired. My problem comes when I try to generalize the xref function by passing in the templated split function as an argument. I can't seem to get the type correct. So my question is, can you pass a template function to another function as an argument, and if so, do you have to declare all types before passing it? Or can the compiler infer the types from the way the templated function is used in the body? To demonstrate the errors I get, comment out the existing xref function header, and uncomment the alternate header I'm trying to get working (just below the following commment line.) Also comment the lines tagged LINE 2 and LINE 3 and uncomment LINE 4, which is attempting to use the argument find_words (which defaults to split.) Thanks for any feedback!

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  • about friendfeed search parameter.

    - by user285020
    has anyone find out why FriendFeed advanced search result url doesn't have not search field parameter? some example: contains the words field, when you inputs a text "ok" and push search, then response url is http://friendfeed.com/search?q=ok if you also inputs a text into words in the title field, like texts "I'm", response url is http://friendfeed.com/search?q=ok+intitle%3Ai%27m well, pretty beautiful. not like other site response all field even you don't push a text into. anyone know how to make this effect?

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  • Ignoring a character along with word boundary in regex

    - by DavidP6
    I am using gsub in Ruby to make a word within text bold. I am using a word boundary so as to not make letters within other words bold, but am finding that this ignores words that have a quote after them. For example: text.gsub(/#{word}\b/i, "<b>#{word}</b>") text = "I said, 'look out below'" word = below In this case the word below is not made bold. Is there any way to ignore certain characters along with a word boundary?

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  • Facebook/Youtube Like Multiple Items Select

    - by bradenkeith
    Before we continue: It can't be a predefined list. I need it sort of like this: http://loopj.com/tokeninput/demo.html ... A jQuery plugin that allows the user to type a string of words, press enter, and it makes it a block of text, from there they can press the X to get rid of it, or type more key words into the input area. I've found many things that do this, but all are pulling information from a predefined list of choices.

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  • How can I perform a reverse string search in Excel without using VBA?

    - by e.James
    I have an Excel spreadsheet containing a list of strings. Each string is made up of several words, but the number of words in each string is different. Using built in Excel functions (no VBA), is there a way to isolate the last word in each string? Examples: Are you classified as human? - human? Negative, I am a meat popsicle - popsicle Aziz! Light! - Light!

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  • Question regarding php Regular expression filenames

    - by jason
    I am very bad at regular expressions, but I have a regular expression that is working okay, except for one issue: /\/(.*?).php/ I only need this regular expression to find things like: /this-a-valid-page.php {some words here} /anotherpage.php { some words here} http://www.google.com but do not find URLs the problem i am having is that it find this parts of full URLS i want it to avoid these all together. http://www.google.com/page.php because i have another function that does something different than the filename reg exp.

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  • Android: I uploaded my first app! Keywords?...

    - by Allan
    I've just uploaded my first app on the market. It all went and looks well. I tried a few keywords to search for it, words that I also have in my description AND promo text, but some words don't find my app, some do. How does the keyword strategy work for an app on the market, I couldn't find no documentation on it.

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  • Modify a php limit text function adding some kind of offset to it

    - by webmasters
    Maybe you guys can help: I have a variable called $bio with bio data. $bio = "Hello, I am John, I'm 25, I like fast cars and boats. I work as a blogger and I'm way cooler then the author of the question"; I search the $bio using a set of functions to search for a certain word, lets say "author" which adds a span class around that word, and I get: $bio = "Hello, I am John, I'm 25, I like fast cars and boats. I work as a blogger and I'm way cooler then the <span class=\"highlight\">author</span> of the question"; I use a function to limit the text to 85 chars: $bio = limit_text($bio,85); The problem is when there are more then 80 chars before the word "author" in $bio. When the limit_text() is applied, I won't see the highlighted word author. What I need is for the limit_text() function to work as normal, adding all the words that contain the span class highlight at the end. Something like this: *"This is the limited text to 85 chars, but there are no words with the span class highlight so I am putting to be continued ... **author**, **author2** (and all the other words that have a span class highlight around them separate by comma "* Hope you understood what I mean, if not, please comment and I'll try to explain better. Here is my limit_text() function: function limit_text($text, $length){ // Limit Text if(strlen($text) > $length) { $stringCut = substr($text, 0, $length); $text = substr($stringCut, 0, strrpos($stringCut, ' ')); } return $text; } UPDATE: $xturnons = str_replace(",", ", ", $xturnons); $xbio = str_replace(",", ", ", $xbio); $xbio = customHighlights($xbio,$toHighlight); $xturnons = customHighlights($xturnons,$toHighlight); $xbio = limit_text($xbio,85); $xturnons = limit_text($xturnons,85); The customHighlights function which adds the span class highlighted: function addRegEx($word){ // Highlight Words return "/" . $word . '[^ ,\,,.,?,\.]*/i'; } function highlight($word){ return "<span class='highlighted'>".$word[0]."</span>"; } function customHighlights($searchString,$toHighlight){ $searchFor = array_map('addRegEx',$toHighlight); $result = preg_replace_callback($searchFor,'highlight',$searchString); return $result; }

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  • Creating an accurate php search engine to search database

    - by Adam
    Ok, I attempted at making my own search function which doesnt work very well. It consists of eliminating useless words such as "how" "you" "to" then using a premade Stemmer class that reduces words to their root so "Appointments" searches "appoint" However in the end I'm really only searching keywords and the results are not very accurate. Are there open source search engines that i can implement for free?

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  • Python/YACC Lexer: Token priority?

    - by Rosarch
    I'm trying to use reserved words in my grammar: reserved = { 'if' : 'IF', 'then' : 'THEN', 'else' : 'ELSE', 'while' : 'WHILE', } tokens = [ 'DEPT_CODE', 'COURSE_NUMBER', 'OR_CONJ', 'ID', ] + list(reserved.values()) t_DEPT_CODE = r'[A-Z]{2,}' t_COURSE_NUMBER = r'[0-9]{4}' t_OR_CONJ = r'or' t_ignore = ' \t' def t_ID(t): r'[a-zA-Z_][a-zA-Z_0-9]*' if t.value in reserved.values(): t.type = reserved[t.value] return t return None However, the t_ID rule somehow swallows up DEPT_CODE and OR_CONJ. How can I get around this? I'd like those two to take higher precedence than the reserved words.

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  • can i quickly run entire page's text through a function on page load?

    - by korben
    i have setup a profanity filter with bad words in a XML file and have the following function to run on my page to replace the words: BadWordFilter.Instance.GetCleanString(TextBox1.Text); i'm about to go through my entire site now wrapping that function around every little text variable one by one and it's going to be a huge pain in the butt i'm hoping there's a way that i could just set my masterpage to automatically run all text through this thing on any page_load, so that the effect would be site-wide instantly. is this possible? much appreciated for any help

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  • A more elegant way to parse a string with ruby regular expression using variable grouping?

    - by i0n
    At the moment I have a regular expression that looks like this: ^(cat|dog|bird){1}(cat|dog|bird)?(cat|dog|bird)?$ It matches at least 1, and at most 3 instances of a long list of words and makes the matching words for each group available via the corresponding variable. Is there a way to revise this so that I can return the result for each word in the string without specifying the number of groups beforehand? ^(cat|dog|bird)+$ works but only returns the last match separately , because there is only one group.

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