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  • Inverse relationship of two variables

    - by Jam
    this one is maybe pretty stupid.. Or I am just exhausted or something, but I just cant seem to solve it.. Problem : two variables X and Y, value of Y is dependent on value of X. X can have values ranging from some value to some value (lets say from 0 to 250) and y can have different values (lets say from 0.1 to 1.0 or something..) - but it is inverse relatonship (what I mean is: if value of X is e.g. 250, then value of Y would be 0.1 and when X decreases up to 0, value of Y raises up to 1.0.. So how should I do it? lets say I have function: -- double computeValue (double X) { /computation/ return Y; } Also, is there some easy way to somehow make the scaling of the function not so linear? - For example when X raises, Y decreases slower at first but then more rapidly in the end.. (rly dont know how to say it but I hope you guys got it) Thanks in advance for this stupid question :/

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  • JDO in Google App Engine: order of keys in unowned one-to-many relationship

    - by Kel
    I'm implementing web application with JDO in Google App Engine. According to documentation, in owned one-to-many relationships, order of elements in "owner" object collection is determined either by automatically created index field, or by information given in explicit ordering clause. For example: @PersistenceCapable public class Person { // ... @Order(extensions = @Extension(vendorName="datanucleus", key="list-ordering", value="country asc, city asc")) private List<ContactInfo> contacts = new List<ContactInfo>(); In unowned relationships, "owner" object contains collection of keys of "nested" objects, for example: @PersistenceCapable public class Author { // ... @Persistent private List<Key> books; Is order of keys preserved, if I use List<Key> collection in "owner" object for storing keys of "nested" elements? I could not find answer neither in JDO relationships article, nor in Data Classes article :(

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  • Spring-Hibernate: How to submit a for when the object has one-to-many relations?

    - by Czar
    Hi, I have a form changeed the properties of my object CUSTOMER. Each customer has related ORDERS. The ORDER's table has a column customer_id which is used for the mapping. All works so far, I can read customers without any problem. When I now e.g. change the name of the CUSTOMER in the form (which does NOT show the orders), after saving the name is updated, but all relations in the ORDERS table are set to NULL (the customer_id for the items is set to NULL. How can I keep the relationship working? THX

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  • Getting ORA Oracle error code using PHP function oci_connect?

    - by me_here
    The PHP function oci_connect (which connects to an Oracle database) just returns false if it fails, which at the moment I handle like this: $connection = oci_connect($username, $password, $database); if (!$connection){ return $result = "Trouble connecting to the Oracle Database"; } But really I'd like to have the actual ORA error code, so I can be more informative. Is this possible?

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  • Doctrine2 - relationship

    - by Filip Golonka
    I'm developing an application, which is looking for optimal route and timetable in public transport. I have some experience about Doctrine1, but it's my first time with Doctrine2. There is soem new fields to describe relations (mappedBy and inversedBy) and also some new ways of mapping. I have following code: $query = $this->em->createQuery("SELECT partial cls.{stop}, partial t.{arriveTime, departureTime} FROM \Entities\Timetable t JOIN t.ride r JOIN t.carrierLineStop cls WHERE t.departureTime>=:time AND r.idCarrierLine=:carrierLine AND (cls.idStop=:firstStop OR cls.idStop=:lastStop)"); $query->setParameters(array( 'time' => $time, 'carrierLine' => $path->getLine(), 'firstStop' => $path->getFirstStop(), 'lastStop' => $path->getLastStop() )); When I try to execute that script I've got an error: [Semantical Error] line 0, col 24 near '}, partial t.{arriveTime,': Error: There is no mapped field named 'stop' on class Entities\CarrierLineStop. Mapping files: Entities\CarrierLineStop: type: entity table: carrier_line_stop fields: idCarrierLineStop: id: true type: integer unsigned: false nullable: false column: id_carrier_line_stop generator: strategy: IDENTITY nextStop: type: integer unsigned: false nullable: true column: next_stop manyToOne: idCarrierLine: targetEntity: Entities\CarrierLine cascade: { } mappedBy: null inversedBy: null joinColumns: id_carrier_line: referencedColumnName: id_carrier_line orphanRemoval: false stop: column: id_stop targetEntity: Entities\Stop cascade: { } mappedBy: null inversedBy: carrierLineStop joinColumns: id_stop: referencedColumnName: id_stop orphanRemoval: false lifecycleCallbacks: { } - Entities\Stop: type: entity table: stop fields: idStop: id: true type: integer unsigned: false nullable: false column: id_stop generator: strategy: IDENTITY name: type: string length: 45 fixed: false nullable: true miejscowosc: type: string length: 45 fixed: false nullable: true latitude: type: decimal nullable: true longitude: type: decimal nullable: true oneToMany: carrierLineStop: targetEntity: Entities\CarrierLineStop cascade: { } mappedBy: stop inversedBy: null joinColumns: id_stop: referencedColumnName: id_stop orphanRemoval: false lifecycleCallbacks: { } I have no idea about where the problem is...

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  • Taking a Chomp out of a (Social Network) Product Hype

    - by kellsey.ruppel
    Andrew Kershaw, Senior Director Oracle Social Network Product Development, speaks about Oracle Social Network One of our competitors is being very aggressive with its own developed Social Network add-on, but there should be no doubt in the minds that the Oracle social capabilities available with Fusion CRM stack up well against it. Within the Oracle Cloud, we have announced a product called Oracle Social Network. That technology is pre-integrated into Fusion Applications, enabling your customer to build a collaborative and social enterprise (without all the noise!). Oracle Social Network is designed together with our Fusion Applications. It is very conveniently pre-integrated with CRM, HCM, Financials, Projects, Supply Chain, and the Fusion family. But what's even better is that the individual teams can take a considered approach to what they are trying to achieve within the collaboration process and the outcome they are trying to enable. Then they can utilize the network and collaboration tools to support that result. And there's more! The Fusion teams can design social interactions that bridge across and outside their individual product lines because we have more than just a product line and they know they have the social network to connect them. I know we have a superior product, but it is our ability to understand and execute across the enterprise that will enable us to deliver a much more robust and capable platform in the short term than our competitor can. We have built a product specifically designed for enterprise social collaboration which is not the same for the competition. We have delivered a much more effective solution - one in which individuals can easily collaborate to get results, while being confident that they know who has access to their information. Our platform has been pre-built to cross the company boundaries and enable our customers to collaborate, not just with their customers, but with their partners and suppliers as well. So Fusion addresses the combination of the enterprise application suite with enterprise collaboration and social networking. Oracle Social Network already has a feature function advantage over our competitor's tool providing a real added value to the employees. Plus Oracle has the ability to execute in a broad enterprise and cross-enterprise way that our competitors cannot. We have the power of a tool that provides the core social fabric across all of the applications, as well as supporting enterprise collaboration. That allows us to provide intelligent business insight, connections, and recommendations that our competitor simply can't. From our competitors, customers get integration for Sales; they get integration for Service, but then they have to integrate every other enterprise asset that they have by themselves. With Oracle, we are doing the integration. Fusion Applications will be pre-integrated, and over time, all of the applications in the business suite, including our Applications Unlimited and specialist industry applications, will connect to the Oracle Social Network. I'm confident these capabilities make Oracle Social Network the only collaboration platform on which to deliver the social enterprise.

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  • JPA/Hibernate Parent/Child relationship

    - by NubieJ
    Hi I am quite new to JPA/Hibernate (Java in general) so my question is as follows (note, I have searched far and wide and have not come across an answer to this): I have two entities: Parent and Child (naming changed). Parent contains a list of Children and Children refers back to parent. e.g. @Entity public class Parent { @Id @Basic @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(name = "PARENT_ID", insertable = false, updatable = false) private int id; /* ..... */ @OneToMany(cascade = { CascadeType.ALL }, fetch = FetchType.LAZY) @JoinColumn(name = "PARENT_ID", referencedColumnName = "PARENT_ID", nullable = true) private Set<child> children; /* ..... */ } @Entity public class Child { @Id @Basic @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(name = "CHILD_ID", insertable = false, updatable = false) private int id; /* ..... */ @ManyToOne(cascade = { CascadeType.REFRESH }, fetch = FetchType.EAGER, optional = false) @JoinColumn(name = "PARENT_ID", referencedColumnName = "PARENT_ID") private Parent parent; /* ..... */ } I want to be able to do the following: Retrieve a Parent entity which would contain a list of all its children (List), however, when listing Parent (getting List, it of course should omit the children from the results, therefore setting FetchType.LAZY. Retrieve a Child entity which would contain an instance of the Parent entity. Using the code above (or similar) results in two exceptions: Retrieving Parent: A cycle is detected in the object graph. This will cause infinitely deep XML... Retrieving Child: org.hibernate.LazyInitializationException: failed to lazily initialize a collection of role: xxxxxxxxxxx, no session or session was closed When retrieving the Parent entity, I am using a named query (i.e. calling it specifically) @NamedQuery(name = "Parent.findByParentId", query = "SELECT p FROM Parent AS p LEFT JOIN FETCH p.children where p.id = :id") Code to get Parent (i.e. service layer): public Parent findByParentId(int parentId) { Query query = em.createNamedQuery("Parent.findByParentId"); query.setParameter("id", parentId); return (Parent) query.getSingleResult(); } Why am I getting a LazyInitializationException event though the List property on the Parent entity is set as Lazy (when retrieving the Child entity)?

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  • How can I use "FOR UPDATE" with a JOIN on Oracle?

    - by tangens
    The answer to another SO question was to use this SQL query: SELECT o.Id, o.attrib1, o.attrib2 FROM table1 o JOIN ( SELECT DISTINCT Id FROM table1, table2, table3 WHERE ... ) T1 ON o.id = T1.Id Now I wonder how I can use this statement together with the keyword FOR UPDATE. If I simply append it to the query, Oracle will tell me: ORA-02014: cannot select FOR UPDATE from view Do I have to modify the query or is there a trick to do this with Oracle? With MySql the statement works fine.

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  • django sort by manytomany relationship

    - by Marconi
    I have the following model: class Service(models.Model): ratings = models.ManyToManyField(User) Now if I wanna get all the service with ratings sorted in descending order I did something: services_list = Service.objects.filter(ratings__gt=0).distinct() services_list = list(services_list) services_list.sort(key=lambda service: service.ratings.all().count(), reverse=True) As you can see its a three step process and I don't feel right about this. Anybody who knows a better way to do this?

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  • how to model a many to many relationship

    - by Maulin
    Here is the scenario, Articles have many Comments Users can write many Comments for many Articles The comments table contains both user_id article_id as foreign keys My models are set up like so class User < ActiveRecord::Base has_many :comments has_many :articles, :through => :comments class Article < ActiveRecord::Base has_many :comments has_many :users, :through => :comments class Comment < ActiveRecord::Base belongs_to :users belongs_to :articles My routes.rb has the following code map.resources :articles, :has_many => :comments map.resources :users, :has_many => :comments which produces the following routes new_article_comment edit_article_comment new_user_comment edit_user_comment etc... This is not what I want (atleast not what I think I want), since comments must always be related to users and article, how can I get a route like so new_user_article_comment edit_user_article_comment Then I could just do new_user_article_comment_path([@user, @article]) to create a new comment

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  • Latest Fusion DOO White Paper - Overcoming Order Management Complexity in Global Organizations

    - by Pam Petropoulos
    Check out this latest Fusion Distributed Order Orchestration white paper entitled “Overcoming Order Management Complexity in Global Organizations”.  Discover how Oracle Fusion DOO enables large, complex organizations to streamline their order management processes and take advantage of lower costs, higher margins, and improved customer service. Click here to read the whitepaper.

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  • jpa-Primarykey relationship

    - by megala
    Hi created student entity in gogole app engine datastore using JPA. Student---Coding @Entity @Table(name="StudentPersonalDetails", schema="PUBLIC") public class StudentPersonalDetails { @Id @Column(name = "STUDENTNO") private Long stuno; @Basic @Column(name = "STUDENTNAME") private String stuname; public void setStuname(String stuname) { this.stuname = stuname; } public String getStuname() { return stuname; } public void setStuno(Longstuno) { this.stuno = stuno; } public Long getStuno() { return stuno; } public StudentPersonalDetails(Long stuno,String stuname) { this.stuno = stuno; this.stuname = stuname; } } I stored Property value as follows Stuno Stuname 1 a 2 b If i stored Again Stuno No 1 stuname z means it wont allow to insert the record But. It Overwrite the value Stuno Stuname 1 z 2 b How to solve this?

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  • Model Binding with Parent/Child Relationship

    - by user296297
    I'm sure this has been answered before, but I've spent the last three hours looking for an acceptable solution and have been unable to find anything, so I apologize for what I'm sure is a repeat. I have two domain objects, Player and Position. Player's have a Position. My domain objects are POCOs tied to my database with NHibernate. I have an Add action that takes a Player, so I'm using the built in model binding. On my view I have a drop down list that lets a user select the Position for the Player. The value of the drop down list is the Id of the position. Everything gets populated correctly except that my Position object fails validation (ModelState.IsValid) because at the point of model binding it only has an Id and none of it's other required attributes. What is the preferred solution for solving this with ASP.NET MVC 2? Solutions I've tried... Fetch the Position from the database based on the Id before ModelState.IsValid is called in the Add action of my controller. I can't get the model to run the validation again, so ModelState.IsValid always returns false. Create a custom ModelBinder that inherits from the default binder and fetch the Position from the database after the base binder is called. The ModelBinder seems to be doing the validation so if I use anything from the default binder I'm hosed. Which means I have to completely roll my own binder and grab every value from the form...this seems really wrong and inefficient for such a common use-case. Solutions I think might work, I just can't figure out how to do... Turn off the validation for the Position class when used in Player. Write a custom ModelBinder leverages the default binder for most of the property binding, but lets me get the Position from the database BEFORE the default binder runs validation. So, how do the rest of you solve this? Thanks, Dan P.S. In my opinion having a PositionId on Player just for this case is not a good solution. There has to be solvable in a more elegant fashion.

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  • E-Business Suite 11.5.10 Fenntartó Támogatással és 12.1 Meghosszabbított Támogatással kapcsolatos külön bejelentés

    - by user552636
    Igaz, az idei Oracle Open World (OOW) már régen volt, de akkor ez a blog még nem létezett. Ugyanakkor azóta többektol kaptam kérdést az OOW-n tett E-Business Suite támogatással kapcsolatos bejelentés értelmezésére vonatkozóan. Ezért gondoltam, hasznos lehet a magyar felhasználók számára, ha írok pár sort a bejelentésrol. Az E-Business Suite (EBS) 11.5.10 verzióhoz kapcsolódó bejelentés: Az Oracle Élettartam Támogatási modellje szerint ez a verzió általánosan 2004. novembertol volt elérheto, melyre az Oracle 2010. november 30-ig biztosított Premier Támogatást, 2010. December 1-tol 2013. november végéig pedig Meghosszabbított Támogatást nyújt. Jövo év december 1-tol az EBS 11.5.10 verzió Fenntartó Támogatás szakaszba kerül. Fenntartó Támogatás szakaszban az újonnan felfedezett bug-okat már nem javítja a Fejlesztés. A bejelentés szerint Oracle a 11.5.10 esetében kivételt tesz és a 2013. december 1-tol 2014. november 30-ig terjedo idoszakban az éles üzemet érinto 1-es súlyossági szintu problémák esetében biztosítani fogja új hibák javítását is. Amire ügyelni érdemes, a rendszer a  Doc ID 883202.1 My Oracle Support dokumentumban részletezett minimum patch szinten kell legyen.   Ez a plusz szolgáltatás nem befolyásolja a támogatási díjat. Az E-Business Suite (EBS) 12.1 verzióhoz kapcsolódó bejelentés   Az EBS 12.1 verzió Meghosszabbított támogatásának eredetileg mehírdetett idoszaka 2014. május 1. – 2017. április 30. volt. Oracle ezt az idoszakot 19 hónappal megtoldotta, így ennek a verziónak a Meghosszabbított Támogatása 2018. december 31-ig tart majd. További jó hír e verziót használó Ügyfeleink számára, hogy a Meghosszabbított Támogatás emelt díjától az Oracle eltekint. Standard Oracle árazás szerint a Meghosszabbított Támogatás elso évében a szolgáltatási díj a Premier Támogatás díjának 110%-a, a második, ill. harmadik években a Premier Támogatás díjának 120%-a. Oracle jelen esetben a plusz 10%-tól, ill. a plusz 20 %-tól eltekint. Íly módon a Meghosszabbított Támogatást Oracle a Premier Támogatás díjért biztosítja majd. Amire ügyelni érdemes, a rendszer a  Doc ID 1195034.1 My Oracle Support dokumentumban részletezett minimum patch szinten kell legyen.   Az idoszakok egyszerubb megértése érdekében az alábbi grafikonon ábrázoltam a szóban forgó verziók támogatásának egyes szakaszait.  

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  • M2M Solutions: The Move to Value Creation and the Internet of Things

    - by Javier Puerta
    There's a new Oracle-sponsored report available around big data, specifically machine to machine data (there will probably be more growth in m2m data than human-generated stuff like social media). Forbes published an article, Big Data Set to Explode as 40 Billion New Devices Connect to Internet, which references the report. Login to Download the M2M Solutions Report Good reading!

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  • New Interaction Hub Statement of Direction Published

    - by Matthew Haavisto
    The latest PeopleSoft Interaction Hub Statement of Direction is now available on My Oracle Support.  We think this subject will be particularly interesting to customers given the impending release of the PeopleSoft Fluid User Experience and all that offers.  The Statement of Direction describes how we see the Interaction Hub being used with the new user experience and the Hub's continued place in a PeopleSoft environment.  This paper also discusses subjects like branding, content management, easier design/deployment, and the optional restricted use license.

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  • E-Book on big data (featuring Analysts, Customers and more)

    - by Jean-Pierre Dijcks
    As we are gearing up for Openworld, here is a nice E-book on big data to start paging through. It contains Gartner's take on big data, customer and partner interviews and a lot more good info. Enjoy the read so you come prepared for Openworld!! Read the E-Book here. For those coming to Oracle Openworld (or the Americas Cup races around the same time), you can find big data sessions via this URL. Enjoy!!

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  • Django Aggregation Across Reverse Relationship

    - by Tom
    Given these two models: class Profile(models.Model): user = models.ForeignKey(User, unique=True, verbose_name=_('user')) about = models.TextField(_('about'), blank=True) zip = models.CharField(max_length=10, verbose_name='zip code', blank=True) website = models.URLField(_('website'), blank=True, verify_exists=False) class ProfileView(models.Model): profile = models.ForeignKey(Profile) viewer = models.ForeignKey(User, blank=True, null=True) created = models.DateTimeField(auto_now_add=True) I want to get all profiles sorted by total views. I can get a list of profile ids sorted by total views with: ProfileView.objects.values('profile').annotate(Count('profile')).order_by('-profile__count') But that's just a dictionary of profile ids, which means I then have to loop over it and put together a list of profile objects. Which is a number of additional queries and still doesn't result in a QuerySet. At that point, I might as well drop to raw SQL. Before I do, is there a way to do this from the Profile model? ProfileViews are related via a ForeignKey field, but it's not as though the Profile model knows that, so I'm not sure how to tie the two together. As an aside, I realize I could just store views as a property on the Profile model and that may turn out to be what I do here, but I'm still interested in learning how to better use the Aggregation functions.

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  • [EF + Oracle]Object Context

    - by JTorrecilla
    Prologue After EF episodes I and II, we are going to see the Object Context. What is Object Context? It is a class which manages the DB connection, and the different Entities of our model. When Visual Studio creates the EF model, like I explain previously, also generates a Class that extends ObjectContext. ObjectContext provides: - DB connection - Add, update and delete functions. - Object Sets of Entities. - State of Pending Changes. This class will give a function, for each Entity, like  Esta clase va a contar con una función, para cada entidad, del tipo “AddTo{ENTITY}({Entity_Type } value)”, which are going to add a Entity to the related ObjectSet. In addition, it has a property, for each Entity, like “ObjectSet<TEntity> Entity”, does will keep the related record set. It will be filled with the CreateObjectSet<TEntity> function of Base class (ObjectContext). What is an ObjectSet? It is a class that allows us to manage the Entity Set from a Type. It inherits from: · ObjectQuery<TEntity> · IObjectSet<TEntity> · IQueryAble<TEntity · IEnumerable<TEntity · IQueryAble · IEnumerable An ObjectSet is a class property that allows query, insert, delete and update records from a determinate Entity. In following chapters we will see how to query Entities. LazyLoadingEnabled A very important property of the Context is “LazyLoadingEnabled”. This Boolean property lets indicate if the data loading is lazy, in other words, the Object will not be created and query until not be needed. Finally In this post we have seen what the VS generated context is, some of the characteristics, and where to see Entity data. In next chapters we will see, CRUD operations, and how to query ObjectSets.

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  • JOIN in SQL with one-to-many relationship

    - by Kristopher Ives
    I'm making a tool to track calls to house/senate reps, and I have 2 tables of importance here: reps rep_id rep_name # and more info comments rep_id status # enum about result of contact comment I want to query for all reps joining the most recent associated comments and in some cases joining comments of a specific status, but there might not be any comments associated with that rep yet. THANKS!

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  • Access Relationship Table in Grails

    - by WaZ
    Hi, I have the following domains classes: class Posts{ String Name String Country static hasMany = [tags:Tags] static constraints = { } } class Tags{ String Name static belongsTo = Posts static hasMany = [posts:Posts] static constraints = { } String toString() { "${TypeName}" } } Grails creates an another table in the database i.e. Posts_Tags. My requirement is: E.g. 1 post has 3 tags. So, in the Posts_Tags table there are 3 rows. How can I access the table Posts_Tags directly in my code so that I can manipulate the data or add some more fields to it.

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  • Creating relationship between two model instances

    - by Lowgain
    This is probably pretty simple, but here: Say I've got two models, Thing and Tag class Thing < ActiveRecord::Base has_and_belongs_to_many :tags end class Tag < ActiveRecord::Base has_and_belongs_to_many :things end And I have an instance of each. I want to link them. Can I do something like: @thing = Thing.find(1) @tag = Tag.find(1) @thing.tags.add(@tag) If not, what is the best way to do this? Thanks!

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