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  • using regular expression / Remove special characters with linq to sql

    - by Prasad
    How can i use regular expressions with linq to sql in the asp.net mvc(C#) application? The columns in my MSSQL table (Products) has some special characters like (, - % ',.....). While searching for a product i need to search without that special chareters. For ex.: I have a product say (ABC-Camp's / One), when i search for "abccamp", it should pull the product. I am trying the query like: from p in _context.pu_Products where p.User_Id == userId && p.Is_Deleted == false && p.Product_Name.ToLower().Contains(text.ToLower()) select new Product { ProductId = p.Product_Id, ProductName = p.Product_Name.Replace("’", "").Replace("\"", ""), RetailPrice = p.Retail_Price ?? 0M, LotSize = p.Lot_Size > 0 ? p.Lot_Size ?? 1 : 1, QuantityInHand = p.Quantity_In_Hand ?? 0 } But i need to search without any special characters...

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  • How to write a regular expression for "everything between X and Y" for use with preg_replace

    - by pg
    I want to take a variable called $encoded_str and and remove cd1, CD1 and anything between the first 'l' and the last blank space. So for example "lp6 id4 STRINGcd1" would return "STRING". I'm using PHP 4 for now so I can't use str_ireplace, I have this: $encoded_str=str_replace('CD1','',$encoded_str); $encoded_str=str_replace('cd1','',$encoded_str); $encoded_str=preg_replace('X','',$encoded_str); I've RTFM for preg_replace but am a bit confused. What should I replace the X with and can you suggest a decent introductory primer for writing regular expressions?

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  • Simple Search and Replace use of Regular Expression

    - by nunos
    So, I am adapting some code I found online to suit my needs. However, my set_pixel function has two more parameters. Since there are lots of calls to this function even doing a quick paste over would be very tedious. So, I thought this would be a good time for me to learn some simple regular expressions. So, I have calls of this type: set_pixel(arg1, arg2); which I want to change to something like: set_pixel(arg1, arg2, arg3, arg4); Note: arg1 and and 2 should be preserved, whereas arg3 and arg4 are most of the time the same. How can I achieve this?

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  • regular expression for bit strings with even number of 1s

    - by equilibrium
    Let L= { w in (0+1)* | w has even number of 1s}, i.e. L is the set of all bit strings with even number of 1s. Which one of the regular expressions below represents L? A) (0*10*1)* B) 0*(10*10*)* C) 0*(10*1)* 0* D) 0*1(10*1)* 10* According to me option D is never correct because it does not represent the bit string with zero 1s. But what about the other options? We are concerned about the number of 1s(even or not) not the number of zeros doesn't matter. Then which is the correct option and why?

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  • regular expression

    - by Altariste
    Hi, I need to find all invocations of some logging macros in the code. The macro invocation is of the form: DEBUG[1-5] ( "methodName: the logged message", arguments) But the new versions of the macros are prepending the name of the method automatically, so my task is to write a Python script that will remove the duplicate function names specified already by the programmer. I'm using the sub function from the re module. I plan to substitute the part indicated by || signs below : ||DEBUG[1-5] ("methodName: || the logged message", arguments) with simply DEBUG[1-5](" The problem is following: To find the expressions I want to substitute, I use the following regular expression: ((DEBUG | INFO | all other macros names )[1-5]*)\s*\(\"\w+: But it doesn't match the whole expression ( from DEBUG right to the colon ), but only the macro name, that is for example DEBUG5. Is my expression wrong or there is some quirk in the Python regex processing? ( maybe the fact that I use the DEBUG[1-5] as a subgroup has something to do with this? ) Help from anyone more knowledgable than me appreciated :).

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  • Regular expression to remove one parameter from query string

    - by Kip
    I'm looking for a regular expression to remove a single parameter from a query string, and I want to do it in a single regular expression if possible. Say I want to remove the foo parameter. Right now I use this: /&?foo\=[^&]+/ That works as long as foo is not the first parameter in the query string. If it is, then my new query string starts with an ampersand. (For example, "foo=123&bar=456" gives a result of "&bar=456".) Right now, I'm just checking after the regex if the query string starts with ampersand, and chopping it off if it does. Example edge cases: Input | Output -------------------------+----------------- foo=123 | (empty string) foo=123&bar=456 | bar=456 bar=456&foo=123 | bar=456 abc=789&foo=123&bar=456 | abc=789&bar=456 Edit OK as pointed out in comments there are there are way more edge cases than I originally considered. I got the following regex to work with all of them: /&foo(\=[^&]*)?(?=&|$)|^foo(\=[^&]*)?(&|$)/ This is modified from Mark Byers's answer, which is why I'm accepting that one, but Roger Pate's input helped a lot too. Here is the full suite of test cases I'm using, and a Perl script which tests them. Input | Output -------------------------+------------------- foo | foo&bar=456 | bar=456 bar=456&foo | bar=456 abc=789&foo&bar=456 | abc=789&bar=456 foo= | foo=&bar=456 | bar=456 bar=456&foo= | bar=456 abc=789&foo=&bar=456 | abc=789&bar=456 foo=123 | foo=123&bar=456 | bar=456 bar=456&foo=123 | bar=456 abc=789&foo=123&bar=456 | abc=789&bar=456 xfoo | xfoo xfoo&bar=456 | xfoo&bar=456 bar=456&xfoo | bar=456&xfoo abc=789&xfoo&bar=456 | abc=789&xfoo&bar=456 xfoo= | xfoo= xfoo=&bar=456 | xfoo=&bar=456 bar=456&xfoo= | bar=456&xfoo= abc=789&xfoo=&bar=456 | abc=789&xfoo=&bar=456 xfoo=123 | xfoo=123 xfoo=123&bar=456 | xfoo=123&bar=456 bar=456&xfoo=123 | bar=456&xfoo=123 abc=789&xfoo=123&bar=456 | abc=789&xfoo=123&bar=456 foox | foox foox&bar=456 | foox&bar=456 bar=456&foox | bar=456&foox abc=789&foox&bar=456 | abc=789&foox&bar=456 foox= | foox= foox=&bar=456 | foox=&bar=456 bar=456&foox= | bar=456&foox= abc=789&foox=&bar=456 | abc=789&foox=&bar=456 foox=123 | foox=123 foox=123&bar=456 | foox=123&bar=456 bar=456&foox=123 | bar=456&foox=123 abc=789&foox=123&bar=456 | abc=789&foox=123&bar=456 Test script (Perl) @in = ('foo' , 'foo&bar=456' , 'bar=456&foo' , 'abc=789&foo&bar=456' ,'foo=' , 'foo=&bar=456' , 'bar=456&foo=' , 'abc=789&foo=&bar=456' ,'foo=123' , 'foo=123&bar=456' , 'bar=456&foo=123' , 'abc=789&foo=123&bar=456' ,'xfoo' , 'xfoo&bar=456' , 'bar=456&xfoo' , 'abc=789&xfoo&bar=456' ,'xfoo=' , 'xfoo=&bar=456' , 'bar=456&xfoo=' , 'abc=789&xfoo=&bar=456' ,'xfoo=123', 'xfoo=123&bar=456', 'bar=456&xfoo=123', 'abc=789&xfoo=123&bar=456' ,'foox' , 'foox&bar=456' , 'bar=456&foox' , 'abc=789&foox&bar=456' ,'foox=' , 'foox=&bar=456' , 'bar=456&foox=' , 'abc=789&foox=&bar=456' ,'foox=123', 'foox=123&bar=456', 'bar=456&foox=123', 'abc=789&foox=123&bar=456' ); @exp = ('' , 'bar=456' , 'bar=456' , 'abc=789&bar=456' ,'' , 'bar=456' , 'bar=456' , 'abc=789&bar=456' ,'' , 'bar=456' , 'bar=456' , 'abc=789&bar=456' ,'xfoo' , 'xfoo&bar=456' , 'bar=456&xfoo' , 'abc=789&xfoo&bar=456' ,'xfoo=' , 'xfoo=&bar=456' , 'bar=456&xfoo=' , 'abc=789&xfoo=&bar=456' ,'xfoo=123', 'xfoo=123&bar=456', 'bar=456&xfoo=123', 'abc=789&xfoo=123&bar=456' ,'foox' , 'foox&bar=456' , 'bar=456&foox' , 'abc=789&foox&bar=456' ,'foox=' , 'foox=&bar=456' , 'bar=456&foox=' , 'abc=789&foox=&bar=456' ,'foox=123', 'foox=123&bar=456', 'bar=456&foox=123', 'abc=789&foox=123&bar=456' ); print "Succ | Input | Output | Expected \n"; print "-----+--------------------------+--------------------------+-------------------------\n"; for($i=0; $i <= $#in; $i++) { $out = $in[$i]; $out =~ s/_PUT_REGEX_HERE_//; $succ = ($out eq $exp[$i] ? 'PASS' : 'FAIL'); #if($succ eq 'FAIL') #{ printf("%s | %- 24s | %- 24s | %- 24s\n", $succ, $in[$i], $out, $exp[$i]); #} }

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  • Little Regular Expression (against HTML) help

    - by Marcos Placona
    Hi, I have the following HTML <p>Some text <a title="link" href="http://link.com/" target="_blank">my link</a> more text <a title="link" href="http://link.com/" target="_blank">more link</a>.</p> <p>Another paragraph.</p> <p>[code:cf]</p> <p>&lt;cfset ArrFruits = ["Orange", "Apple", "Peach", "Blueberry", </p> <p>"Blackberry", "Strawberry", "Grape", "Mango", </p> <p>"Clementine", "Cherry", "Plum", "Guava", </p> <p>"Cranberry"]&gt;</p> <p>[/code]</p> <p>Another line</p> <p><img src="http://image.jpg" alt="Array" /> </p> <p>More text</p> <p>[code:cf]</p> <p>&lt;table border="1"&gt;</p> <p> &lt;cfoutput&gt;</p> <p> &lt;cfloop array="#GroupsOf(ArrFruits, 5)#" index="arrFruitsIX"&gt;</p> <p>  &lt;tr&gt;</p> <p> &lt;cfloop array="#arrFruitsIX#" index="arrFruit"&gt;</p> <p>     &lt;td&gt;#arrFruit#&lt;/td&gt;</p> <p> &lt;/cfloop&gt;</p> <p>  &lt;/tr&gt;</p> <p> &lt;/cfloop&gt;</p> <p> &lt;/cfoutput&gt;</p> <p>&lt;/table&gt;</p> <p>[/code]</p> <p>With an output that looks like:</p> <p><img src="another_image.jpg" alt="" width="342" height="85" /></p> What I'm trying to do, is write a regular expression that will remove all the or , and whenever it finds a , it will replace it with a line-break. So far, my pattern looks like this: /\<p\>(.*?)(<\/p>)/g And I'm replacing the matches with: $1\n It all looks good, but it's also replacing the contents inside the [code][/code] tags, which in this case should not replace the tags at all, so as a result, i would lkike to get rid of the tags, when the content isn't inside the [code] tags. I can't ever get negation right, I know it will be something along the lines of \<p\>^\[code*\](.*?)(<\/p>) But obviously this doesn't work :-) Could anyone please lend me a hand with this regex? BTW, I know I shouldn't be using regular expressions to parse HTML at all. I'm fully aware of that, but still, for this specific case, I'd like to use regex. Thanks in advance

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  • How to cut a URL with regular expression

    - by AhmadAssaf
    Hello, i am trying to chop a string that contains several information in java .. the text is something like that : <a href="http://www.hootsuite.com" rel="nofollow">HootSuite</a> i am thinking of using the .split method that need regular expression .. what i want it to split this string into the URL without quotes .. http://...... .com and then the text between the tags .. this case HootSuite .. i will appreciate the help Thank you

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  • Mixing regular expression and other conditional expression in a bash if statement

    - by Tassos
    I can't get around this for quite sometime now. As I read along manuals and tutorials I'm getting more confused. I want an if statement with the following logic: if [ -n $drupal_version ] && [[ "$drupal_version" =~ DRUPAL-[6-9]-[1-9][1-9] ]]; then but I can't get it to work properly. When the script is evaluated using the "bash -x ... " script construct, works ok but when is run as a regular script my expression is not evaluated (eventhough the above condition should be met the else part is run). Could you provide any help?

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  • regular expression to read the string between <title> and </title>

    - by user262325
    Hello every one I hope to read the contents between and in a html string. I think it should be in objective-c @"<title([\\s\\S]*)</title>" below are the codes that rewrited for regular expression //source of NSStringCategory.h #import <Foundation/Foundation.h> #import <regex.h> @interface NSStringCategory:NSObject { regex_t preg; } -(id)initWithPattern:(NSString *)pattern options:(int)options; -(void)dealloc; -(BOOL)matchesString:(NSString *)string; -(NSString *)matchedSubstringOfString:(NSString *)string; -(NSArray *)capturedSubstringsOfString:(NSString *)string; +(NSStringCategory *)regexWithPattern:(NSString *)pattern options:(int)options; +(NSStringCategory *)regexWithPattern:(NSString *)pattern; +(NSString *)null; +(void)initialize; @end @interface NSString (NSStringCategory) -(BOOL)matchedByPattern:(NSString *)pattern options:(int)options; -(BOOL)matchedByPattern:(NSString *)pattern; -(NSString *)substringMatchedByPattern:(NSString *)pattern options:(int)options; -(NSString *)substringMatchedByPattern:(NSString *)pattern; -(NSArray *)substringsCapturedByPattern:(NSString *)pattern options:(int)options; -(NSArray *)substringsCapturedByPattern:(NSString *)pattern; -(NSString *)escapedPattern; @end and .m file #import "NSStringCategory.h" static NSString *nullstring=nil; @implementation NSStringCategory -(id)initWithPattern:(NSString *)pattern options:(int)options { if(self=[super init]) { int err=regcomp(&preg,[pattern UTF8String],options|REG_EXTENDED); if(err) { char errbuf[256]; regerror(err,&preg,errbuf,sizeof(errbuf)); [NSException raise:@"CSRegexException" format:@"Could not compile regex \"%@\": %s",pattern,errbuf]; } } return self; } -(void)dealloc { regfree(&preg); [super dealloc]; } -(BOOL)matchesString:(NSString *)string { if(regexec(&preg,[string UTF8String],0,NULL,0)==0) return YES; return NO; } -(NSString *)matchedSubstringOfString:(NSString *)string { const char *cstr=[string UTF8String]; regmatch_t match; if(regexec(&preg,cstr,1,&match,0)==0) { return [[[NSString alloc] initWithBytes:cstr+match.rm_so length:match.rm_eo-match.rm_so encoding:NSUTF8StringEncoding] autorelease]; } return nil; } -(NSArray *)capturedSubstringsOfString:(NSString *)string { const char *cstr=[string UTF8String]; int num=preg.re_nsub+1; regmatch_t *matches=calloc(sizeof(regmatch_t),num); if(regexec(&preg,cstr,num,matches,0)==0) { NSMutableArray *array=[NSMutableArray arrayWithCapacity:num]; int i; for(i=0;i<num;i++) { NSString *str; if(matches[i].rm_so==-1&&matches[i].rm_eo==-1) str=nullstring; else str=[[[NSString alloc] initWithBytes:cstr+matches[i].rm_so length:matches[i].rm_eo-matches[i].rm_so encoding:NSUTF8StringEncoding] autorelease]; [array addObject:str]; } free(matches); return [NSArray arrayWithArray:array]; } free(matches); return nil; } +(NSStringCategory *)regexWithPattern:(NSString *)pattern options:(int)options { return [[[NSStringCategory alloc] initWithPattern:pattern options:options] autorelease]; } +(NSStringCategory *)regexWithPattern:(NSString *)pattern { return [[[NSStringCategory alloc] initWithPattern:pattern options:0] autorelease]; } +(NSString *)null { return nullstring; } +(void)initialize { if(!nullstring) nullstring=[[NSString alloc] initWithString:@""]; } @end @implementation NSString (NSStringCategory) -(BOOL)matchedByPattern:(NSString *)pattern options:(int)options { NSStringCategory *re=[NSStringCategory regexWithPattern:pattern options:options|REG_NOSUB]; return [re matchesString:self]; } -(BOOL)matchedByPattern:(NSString *)pattern { return [self matchedByPattern:pattern options:0]; } -(NSString *)substringMatchedByPattern:(NSString *)pattern options:(int)options { NSStringCategory *re=[NSStringCategory regexWithPattern:pattern options:options]; return [re matchedSubstringOfString:self]; } -(NSString *)substringMatchedByPattern:(NSString *)pattern { return [self substringMatchedByPattern:pattern options:0]; } -(NSArray *)substringsCapturedByPattern:(NSString *)pattern options:(int)options { NSStringCategory *re=[NSStringCategory regexWithPattern:pattern options:options]; return [re capturedSubstringsOfString:self]; } -(NSArray *)substringsCapturedByPattern:(NSString *)pattern { return [self substringsCapturedByPattern:pattern options:0]; } -(NSString *)escapedPattern { int len=[self length]; NSMutableString *escaped=[NSMutableString stringWithCapacity:len]; for(int i=0;i<len;i++) { unichar c=[self characterAtIndex:i]; if(c=='^'||c=='.'||c=='['||c=='$'||c=='('||c==')' ||c=='|'||c=='*'||c=='+'||c=='?'||c=='{'||c=='\\') [escaped appendFormat:@"\\%C",c]; else [escaped appendFormat:@"%C",c]; } return [NSString stringWithString:escaped]; } @end I use the codes below to get the string between "" and "" NSStringCategory *a=[[NSStringCategory alloc] initWithPattern:@"<title([\s\S]*)</title>" options:0];// Unfortunately [a matchedSubstringOfString:response]] always returns nil I do not if the regular expression is wrong or any other reason. Welcome any comment Thanks interdev

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  • Regular expression replace in PL/pgSQL

    - by dreamlax
    If I have the following input (excluding quotes): "The ancestral territorial imperatives of the trumpeter swan" How can I collapse all multiple spaces to a single space so that the input is transformed to: "The ancestral territorial imperatives of the trumpeter swan" This is going to be used in a trigger function on insert/update (which already trims leading/trailing spaces). Currently, it raises an exception if the input contains multiple adjacent spaces, but I would rather it simply transforms it into something valid before inserting. What is the best approach? I can't seem to find a regular-expression replace function for PL/pgSQL. There is a text_replace function, but this will only collapse at most two spaces down to one (meaning three consecutive spaces will collapse to two). Calling this function over and over is not ideal.

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  • Regular expression in C#

    - by user340015
    i have text something like this. @@MMIVLoader@[email protected]@BCM_7400S_LE@Product@Aug 21 2009@ @@MMIVLib@[email protected]@BCM_7400S_LE@Product@Aug 21 2009@ @@HuaweFGDLDrv@[email protected]@7324@PRODUCT@Aug 20 2009@ @@ProtectVer@[email protected] @BCM_SDE5.03@PRODUCT@Aug 4 2009 06:56:19@ @@KernelSw@[email protected]@BCM-7454@PRODUCT@ Dec 19 2007@ @@ReceiverSw@[email protected]@HWBC01ZS@PRODUCT@May 3 2010@ i want the out put in an array like MMIVLoader 4.1.2 MMIVLib 4.1.2 HuaweFGDLDrv 01.00.09 ProtectVer 127.8.1 KernelSw 0.0.1 ReceiverSw E.5.6.001 Can any one suggest me how to do this in c# using regular expression or is there a any sophisticated way to do this thanks in advance

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  • JavaScript String Replace with a tricky regular expression

    - by Juri
    Hi. I'm trying to work out what regular expression I would need to change this string html = '<img style="width: 311px; height: 376px;" alt="test" src="/img/1268749322.jpg" />'; to this html = '<img width="311" height="376" alt="test" src="/img/1268749322.jpg" />'; with the help of Javascript.replace. This is my start: html = html.replace(/ style="width:\?([0-9])px*"/g, "width=\"$1\""); Can anyone help me? THANKS

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  • Evaluating a regular expression range

    - by Dan Atkinson
    Hi there! Is there a nice way to evaluate a regular expression range, say, for a url such as http://example.com/[a-z]/[0-9].htm This would be converted into: http://example.com/a/0.htm http://example.com/a/1.htm http://example.com/a/2.htm ... http://example.com/a/9.htm ... http://example.com/z/0.htm http://example.com/z/1.htm http://example.com/z/2.htm ... http://example.com/z/9.htm I've been scratching my head about this, and there's no pretty way of doing it without going through the alphabet and looping through numbers. Thanks in advance!

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  • A regular expression that will allow a string with only one Capital Letter

    - by Phoenix
    The string should be 6 - 20 characters in length. And it should contain 1 Capital letter. I can do this in code using C# string st = "SomeString" Regex rg = new Regex("[A-Z]"); MatchCollection mc = rg.Matches(st); Console.WriteLine("Total Capital Letters: " + mc.Count); if (mc.Count > 1) { return false; } But what i really want is a Regular expression that will match my string if it only contains one capital. The string can start with a common letter and should have only letters. Thanks In advance. (I did look at some of the other RegEx questions but they did not help).

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  • Treetop basic parsing and regular expression usage

    - by ucint
    I'm developing a script using the ruby Treetop library and having issues working with its syntax for regex's. First off, many regular expressions that work in other settings dont work the same in treetop. This is my grammar: (myline.treetop) grammar MyLine rule line string whitespace condition end rule string [\S]* end rule whitespace [\s]* end rule condition "new" / "old" / "used" end end This is my usage: (usage.rb) require 'rubygems' require 'treetop' require 'polyglot' require 'myline' parser = MyLineParser.new p parser.parse("randomstring new") This should find the word new for sure and it does! Now I wont to extend it so that it can find new if the input string becomes "randomstring anotherstring new yetanother andanother" and possibly have any number of strings followed by whitespace (tab included) before and after the regex for rule condition. In other words, if I pass it any sentence with the word "new" etc in it, it should be able to match it. So let's say I change my grammar to: rule line string whitespace condition whitespace string end Then, it should be able to find a match for: p parser.parse("randomstring new anotherstring") So, what do I have to do to allow the string whitespace to be repeated before and after condition? If I try to write this: rule line (string whitespace)* condition (whitespace string)* end , it goes in an infinite loop. If i replace the above () with [], it returns nil In general, regex's return a match when i use the above, but treetop regex's dont. Does anyone have any tips/points on how to go about this? Plus, since there isn't much documentation for treetop and the examples are either too trivial or too complex, is there anyone who knows a more thorough documentation/guide for treetop?

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  • Java (Android) regular expression to strip out HTML paragraph

    - by jackbot
    I have an Android application which grabs some data from an external XML source. I've stripped out some HTML from one of the XML elements, but it's in the format: <p class="x">Some text...</p> <p>Some more text</p> <p>Some final text</p> I want to extract the middle paragraph text, how can I do this? Would a regular expression be the best way? I don't really want to start including external HTML parsing libraries.

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  • Usability standards when combining AJAX and regular POST-based form saves

    - by mcrider
    I'm working on a project where on certain pages (e.g. settings pages) we combine AJAX and regular fill-out-the-form-then-submit POST based operations. I'm curious if anyone has advice on improving the usability of such a page. One of my ideas is that when the user enters/modifies a value in a non-ajax part of the page, some sort of div would appear (say in a fashion similar to Growl) indicating that the user needs to save by pressing 'Submit' at the bottom of the page (and possibly putting up a modal dialog if the user navigates away from the page before saving, though that might be a bit too intrusive). I'm sure this type of interaction exists, but I can't find any examples.

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  • Regular expression of unicode characters on string

    - by Marcus King
    I'm working in c# doing some OCR work and have extracted the text I need to work with. Now I need to parse a line using Regular Expressions. string checkNum; string routingNum; string accountNum; Regex regEx = new Regex(@"\u9288\d+\u9288"); Match match = regEx.Match(numbers); if (match.Success) checkNum = match.Value.Remove(0, 1).Remove(match.Value.Length - 1, 1); regEx = new Regex(@"\u9286\d{9}\u9286"); match = regEx.Match(numbers); if(match.Success) routingNum = match.Value.Remove(0, 1).Remove(match.Value.Length - 1, 1); regEx = new Regex(@"\d{10}\u9288"); match = regEx.Match(numbers); if (match.Success) accountNum = match.Value.Remove(match.Value.Length - 1, 1); The problem is that the string contains the necessary unicode characters when I do a .ToCharArray() and inspect the contents of the string, but it never seems to recognize the unicode characters when I parse the string looking for them. I thought strings in C# were unicode by default.

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  • Microsoft Azure compared to "regular" webhosting

    - by Jonas Cannehag
    Hi all, i have an idea of putting my blog on to Azure instead of a regular webhosting company. The only thing i cannot figure out is if that will be cheaper or not. The good part is the getting-knowledge of Azure but on the other hand it is my personal blog and i really don't wanna spend to much money on it. So do you have any idea of how the pricing works? I saw some calculator but didn't manage to understand the numbers. Thanks in advance

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  • codeigniter: how to redirect after login to current controller (php_self in regular php)

    - by krike
    Well it's not really a problem but I check if the user exist and log them in and redirect to site/members_area, but I don't want to send the user to a specific page but i want to reload the current controller. So if I login in index/home I would like to be redirected at index/home, how should I proceed? in regular php I would put in the action to redirect to current page <?php echo $_SERVER['PHP_SELF']; ?> This is the code in the framework function validate_credentials() { $this->load->model('membership_model'); $query = $this->membership_model->validate(); if($query) // if the user's credentials validated... { $data = array( 'username' => $this->input->post('username'), 'is_logged_in' => true ); $this->session->set_userdata($data); redirect('site/members_area'); //<-- this line here should be dynamic } else // incorrect username or password { $this->index(); } }

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  • parsing FireFox bookmarks using regular expression

    - by SIFE
    I tried to parse firefox bookmark(JSON exported version), using this efforts: cat boo.json | grep '\"uri\"\:\"^http\://[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}\"' cat boo.json | grep '"uri"\:"^http\://[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}' cat boo.json | grep '"uri"\:"^http\://[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}"' And few others but all fails, json bookmarked file will look like this: .........."uri":"http://www.google.com/?"......"uri":"http://stackoverflow.com/" So, the output should be like this: "uri":"http://www.google.com/?" "uri":"http://stackoverflow.com/" What is the missing part on my regular expression?

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  • Regular Expression - capturing contents of <select>

    - by joey mueller
    I'm trying to use a regular expression to capture the contents of all option values inside an HTML select element For example, in: <select name="test"> <option value="blah">one</option> <option value="mehh">two</option> <option value="rawr">three</option> </select> I'd like to capture one two and three into an array. My current code is var pages = responseDetails.responseText.match(/<select name="page" .+?>(?:\s*<option .+?>([^<]+)<\/option>)+\s*<\/select>/); for (var c = 0; c<pages.length; c++) { alert(pages[c]); } But it only captures the last value, in this case, "three". How can I modify this to capture all of them? Thanks!

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  • Regular expression to remove all text except...

    - by Barryman9000
    There may be an easier way, and if there is I'm all for it. However - my ASP.NET page has a TON of controls on it, and I've given them all ID's that start with underscore. I copied all the markup into Notepad++ and I'm trying to find a regular expression that will find everything but the controls and replace it with whitespace. that way I'll have a text file that has all my control names which I'll probably throw into Excel and do some string manipulation to add ".Text = " etc. Any suggestions?

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  • Regular expression quantifier questions

    - by Josemalive
    Hello, Im trying to find a regular expression that matches this kind of URL: http://sub.domain.com/selector/F/13/K/100546/sampletext/654654/K/sampletext_sampletext.html and dont match this: http://sub.domain.com/selector/F/13/K/10546/sampletext/5987/K/sample/K/101/sample_text.html only if the number of /K/ is minimum 1 and maximum 2 (something with a quantifier like {1,2}) Until this moment i have the following regexp: http://sub\.domain\.com/selector/F/[0-9]{1,2}/[a-z0-9_-]+/ Now i would need a hand to add any kind of condition like: Match this if in the text appears the /K/ from 1 to 2 times at most. Thanks in advance. Best Regards. Josema

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