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  • Handling data update/freshness issue in web-app in general (or GWT specifically)

    - by edwin.nathaniel
    In general, how do you guys handle user update/data freshness interaction with the user (UI issue) in web-apps? For example: Multi-users web-app (like project management) Login to a "virtual" space People can update project names, etc How to handle a situation such that: user-A and user-B load a project with title "Project StackOverflow" user-B updates the title to "Project StackExchange" user-A updates the title after user-B update operation to "Project Basecamp" The question I'm asking is from the user perspective (UI) and not about transactional operation. What do most people do in this situation? What would you do after user-B updates the title in user-A screen/view? What happened when user-A tries to update the title after user-B finished his/her update operation? do you inform user-A that the title has changed and he/she has to reload the page? do you go ahead and change the title and let user-B has old data? Do you do some sort of application-level "locking" mechanism? (if someone is updating, nobody else can?) Or fix the application workflow? (who has the access to be able to change things, etc). What would be the simplest solution, but at the same time not annoy the user with more dialog/warning messages. I've encountered this particular problem frequently in a GWT app specifically where domain models are being passed around and refreshing the whole app/client-side isn't the optimal solution in my mind (since it means the whole "loading"/initialization phase must be executed again in this specific environment). Maybe the answer is to stay away from GWT? :) Love to hear options, solutions, and advises from you guys. Thanks

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  • Cocoa Services Programming - How to identify whether the selected item is a folder or file wih NSFi

    - by rockybalboa
    Hi , I have some queries regarding Services menu validation . I would like to enable different services provided by my app based on whether a file or folder is selected in the Finder. I have set NSFilenamesPboardType as the send type for the services . I have gone through the - (id)validRequestorForSendType:(NSString *)sendType returnType:(NSString *)returnType method but my issue is that the validation there seems to be done based on the sendType and return type. In my case , the selected file and folder pasteboard type is the same and I cannot determine whether the selected item in the Finder is a file or folder during the validation process ( This is before the actual service gets invoked i.e when the services menu is being shown to the user ) ? So my question is that is there any way I can get some info about the selected item in the Finder and validate the different service menus offered by my application based on some info regarding the item rather than the basic validation of the send and return types ? I am not able to find out any manner to do so but "Folder Actions" service in Snow Leopard gets enabled only for folders so it can be done. I did a /System/Library/CoreServices/pbs -dump_pboard and it is using a NSFilenamePBoardType also yet manages to activate only for folders. Thanks in advace for any help .

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  • Ubuntu - Automatically mount external drives to /media/LABEL on boot without a user logged in?

    - by endolith
    This question is similar, but kind of the opposite of what I want. I want external USB drives to be mounted automatically at boot, without anyone logged in, to locations like /media/<label>. I don't want to have to enter all the data into fstab, partially because it's tedious and annoying, but mostly because I can't predict what I'll be plugging into it or how the partitions will change in the future. I want the drives to be accessible to things like MPD, and available when I log in with SSH. gnome-mount seems to only mount things when you are locally logged into a Gnome graphical session.

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  • "Attach or Add an entity that is not new...loaded from another DataContext. This is not supported."

    - by sah302
    Similar error as other questions, but not quite the same, I am not trying to attach anything. What I am trying to do is insert a new row into a linking table, specifically UserAccomplishment. Relations are set in LINQ to User and Accomplishment Tables. I have a generic insert function: Public Function insertRow(ByVal entity As ImplementationType) As Boolean If entity IsNot Nothing Then Dim lcfdatacontext As New LCFDataContext() Try lcfdatacontext.GetTable(Of ImplementationType)().InsertOnSubmit(entity) lcfdatacontext.SubmitChanges() lcfdatacontext.Dispose() Return True Catch ex As Exception Return False End Try Else Return False End If End Function If you try and give UserAccomplishment the two appropriate objects this will naturally crap out if either the User or Accomplishment already exist. It only works when both user and accomplishment don't exist. I expected this behavior. What does work is simply giving the userAccomplishment object a user.id and accomplishment.id and populating the rest of the fields. This works but is kind of awkward to use in my app, it would be much easier to simply pass in both objects and have it work out what already exists and what doesn't. Okay so I made the following (please ignore the fact that this is horribly inefficient because I know it is): Public Class UserAccomplishmentDao Inherits EntityDao(Of UserAccomplishment) Public Function insertLinkerObjectRow(ByVal userAccomplishment As UserAccomplishment) Dim insertSuccess As Boolean = False If Not userAccomplishment Is Nothing Then Dim userDao As New UserDao() Dim accomplishmentDao As New AccomplishmentDao() Dim user As New User() Dim accomplishment As New Accomplishment() 'see if either object already exists in db' user = userDao.getOneByValueOfProperty("Id", userAccomplishment.User.Id) accomplishment = accomplishmentDao.getOneByValueOfProperty("Id", userAccomplishment.Accomplishment.Id) If user Is Nothing And accomplishment Is Nothing Then 'neither the user or the accomplishment exist, both are new so insert them both, typical insert' insertSuccess = Me.insertRow(userAccomplishment) ElseIf user Is Nothing And Not accomplishment Is Nothing Then 'user is new, accomplishment is not new, so just insert the user, and the relation in userAccomplishment' Dim userWithExistingAccomplishment As New UserAccomplishment(userAccomplishment.User, userAccomplishment.Accomplishment.Id, userAccomplishment.LastUpdatedBy) insertSuccess = Me.insertRow(userWithExistingAccomplishment) ElseIf Not user Is Nothing And accomplishment Is Nothing Then 'user is not new, accomplishment is new, so just insert the accomplishment, and the relation in userAccomplishment' Dim existingUserWithAccomplishment As New UserAccomplishment(userAccomplishment.UserId, userAccomplishment.Accomplishment, userAccomplishment.LastUpdatedBy) insertSuccess = Me.insertRow(existingUserWithAccomplishment) Else 'both are not new, just add the relation' Dim userAccomplishmentBothExist As New UserAccomplishment(userAccomplishment.User.Id, userAccomplishment.Accomplishment.Id, userAccomplishment.LastUpdatedBy) insertSuccess = Me.insertRow(userAccomplishmentBothExist) End If End If Return insertSuccess End Function End Class Alright, here I basically check if the supplied user and accomplishment already exists in the db, and if so call an appropriate constructor that will leave whatever already exists empty, but supply the rest of the information so the insert can succeed. However, upon trying an insert: Dim result As Boolean = Me.userAccomplishmentDao.insertLinkerObjectRow(userAccomplishment) In which the user already exists, but the accomplishment does not (the 99% typical scenario) I get the error: "An attempt has been made to Attach or Add an entity that is not new, perhaps having been loaded from another DataContext. This is not supported." I have debugged this multiple times now and am not sure why this is occuring, if either User or Accomplishment exist, I am not including it in the final object to try to insert. So nothing appears to be attempted to be added. Even in debug, upon insert, the object was set to empty. So the accomplishment is new and the user is empty. 1) Why is it still saying that and how can I fix it ..using my current structure 2) Pre-emptive 'use repository pattern answers' - I know this way kind of sucks in general and I should be using the repository pattern. However, I can't use that in the current project because I don't have time to refactor that due to my non existence knowledge of it and time constraints. The usage of the app is going to so small that the inefficient use of datacontext's and what have you won't matter so much. I can refactor it once it's up and running, but for now I just need to 'push through' with my current structure. Edit: I also just tested this when having both already exists, and only insert each object's IDs into the table, that works. So I guess I could manually insert whichever object doesn't exist as a single insert, then put the ids only into the linking table, but I still don't know why when one object exists, and I make it empty, it doens't work.

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  • What are potential reasons a user could be connected to a home network, but not to the internet?

    - by Matthew
    I have a friend that recently started using Ubuntu, and I've been answering his questions via the internet. However, I'm stuck on this one. He bought Linksys WPC11 wireless card, and says he was able to create a network connection, but was unable to ping or use a browser. I'm not quite sure where to start in figuring this out--what are some common causes of this sort of problem?

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  • Can I stop the page from 'scrolling' back to the top when a user clicks on a tab (with Rails not Jav

    - by Jake
    Ive built a webpage with 'tabs' using rails. When a user clicks a tab, a new page loads. I want to format it so the tabs are always in the same place on the page as a user clicks them. This happens as long as the user has not scrolled down on the page. If a user has scrolled down, clicking on the tab will refresh the page and it is no longer scrolled down - which make clicking the tabs look bad. Is there a way to keep the spot on the page where the user has scrolled down, without using Javascript? If it must be done with Javascript, any suggestions? T

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  • Knowledge and user generated content management system to track files, research, proposals, etc.?

    - by Eshwar
    I'll try keep it short. Here's the scenario: We have employees all over the world performing similar work i.e. research, generating powerpoint slides, word documents, graphics, etc. Many times a lot of this previous work can be reused for another future project. The current arrangement is email and phone calls which as you would agree is quick if you know where to look but otherwise archaic and very very inefficient. So I am looking for software that will allow me to do the following: Tag files e.g. an investor presentation on cellphone usage in kenya would be tagged investor, cellphone, kenya Manage references e.g. if we read something on the internet, should be able to paste that link in some fashion and tag it as above. Preferably cloud based so that it can be accessed by anybody and additionally would be nice (though NOT must) to have access levels (director, manager, everyone) A nice interface that non technically savvy folks can warm up to ;) A desktop app would be handy so that people don't always have to click upload or something A tree based system is inefficient in this case because content is usually linked across branches and also people might not quite agree on one format of a tree. Tagging works around this very nicely. What I have considered so far: Evernote (for its more professional look) Springpad (for its versatility with content) Mendeley (this is a research manager and in some ways ideal, but i fear its limited to PDFs) The goal is that when somebody wants to look for a document, they don't have to ask a colleague, they can just search with keywords and all relevant information shows up. Thanks!

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  • How to rename dir under Mac (10.6.4) via super user?

    - by user56990
    This is my dir list on my NFS: macbook-pro-andrey-k:Download Andrey$ ls 1289816143_PL_t1181913 1289816171_PL_t1183807 1290117075_BFD_DVD02(Drums) I can't delete "1290117075_BFD_DVD02(Drums)" using sudo rm -Rf 1290117075_BFD_DVD02(Drums) because I get error message -bash: syntax error near unexpected token `(' Hlp plz, how can I either rename the dir so that the error message would not show up or delete the dir right away omitting rename procedure? Thank you.

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  • How do I get Google Chrome's root bookmarks folder?

    - by Wayne
    Hi, I'm trying to write a better bookmark manager in chrome extensions. The problem is there are no simple examples (that I can find) about how to actually use the bookmarks api (available here: http://code.google.com/chrome/extensions/bookmarks.html ) I've looked at the example source (when I d/led and installed it on my computer it didn't do anything except provide a search box. Typing/typing and pressing return failed to do anything) and can't find anything useful. My ultimate goal is to make an extension that allows me to save pages to come and read later without having to go sign up for an account on some service somewhere. So I plan to create either one or two bookmark folders in the root folder/other bookmarks - at minimum an "unread pages" folder. In that folder I'll create the unread bookmarks. When the user marks the item as read, it will be removed from that folder. So that's what I'm trying to do... any help will be greatly appreciated, even if it's just pointing me to some good examples. UPDATE: ...<script> function display(tree){ document.getElementById("Output").innerHTML = tree; } function start(){ chrome.bookmarks.getTree(display); } </script> </head> <body> <h4 id="Output"></h4> <script> start(); </script> ... That displays [object Object], that suggests (at least to me with a limited JavaScript experience) that an object exists. But how to access the members of that object? changing tree to tree.id or any other of what look to be parameters displays "undefined".

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  • Is there any user-friendly way to deliver an In-app purchase subscription to multiple devices?

    - by mkvakin
    Hi everybody, Apple requires an in-app purchase subscription purchased on one device to be available on all devices associated with the user: “...subscriptions must be provided on all devices associated with a user. In App Purchase expects subscriptions to be delivered through an external server that you will provide. You must provide infrastructure to deliver subscriptions to multiple devices.” Is there any way to propagate a subscription to another device transparently without user having to create a server side user account and log in each time he needs to enable the subscription on another device? E.g. by reading a username from some kind of API and using it as a key on a server to store information about subscriptions. I tried to find an API for retrieving user account info but couldn't find any.

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  • My datacenter is unable to add PTR/rDNS record, then how can I prevent the mail outgoing from going to spam folder?

    - by gilzero
    I am having problem that mail sent out from my server all goes to recipient's spam folder. I am running Drupal sites on Linux server. CentOS w/ cPanel. Our users cannot receive email as the mail went to the spam folder. (such as registration email, contact form email) I was advised that I need to have PTR/rDNS record added for my host. I then contact my datacenter to add PTR/rDNS thing, unfortunately, the datacenter said they are unable to do it. So what can I do? Any other ways I can fix the problem? Thank you!

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  • Is Family Tree Maker 2011 the right upgrade for a FTM 11 user?

    - by bill weaver
    My father has used Family Tree Maker for years, but hasn't upgraded since version 11. It is difficult to tell from reviews at Amazon and other places whether upgrading to FTM 2011 is a good choice. File incompatibilities and upgrade woes sound like customer service is lacking, and i've read reports of it uploading your data to their database but then trying to sell you a download of data. Looking at the ancestry.com site makes me think it's solely about selling add-ons and upgrades. On the other hand, the feature set seems fairly rich and the software has a pretty strong following. I was able to get Gramps working on my system, but that's not going to work for my dad. Any advice on a good upgrade path?

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  • VSTO - Outlook 2007 How do I show a user property even when it's not present?

    - by Yandros
    I have added user property in a mail folder, let's call it UserProperty01. Some of the folder items have this property, some don't. I need to show in the folder's view if that property is set or not, so I added another property called UserProperty01Present, and I set it to true when I set the original property and false when I deleted it; then I added it to the folder's view. The problem is that the little checkbox appears checked in those mails where the property is set, blank in those where the property was deleted... and nowhere at all in those where the property was never set in the first place. My question is, is there any way to show the blank checkbox when the property is not set? The only alternative I found so far is looking in every mail item and setting it to false when it's not set every time the folder is opened; needless to say, I'm not very happy with this solution. Is there any other way? Thank you for your time.

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  • Windows 7 Create Folder in "Program Files" failing in C# code even thought I have admin rights!

    - by Shiva
    Hi, I am unable to create a file under "program files" folder on my Windows 7 64-bit machine in VS 2008 WPF C# code. The error I get on the following code myFile = File.Create(logFile); is the following. (this is the innerException stack trace). at System.IO.__Error.WinIOError(Int32 errorCode, String maybeFullPath) at System.IO.FileStream.Init(String path, FileMode mode, FileAccess access, Int32 rights, Boolean useRights, FileShare share, Int32 bufferSize, FileOptions options, SECURITY_ATTRIBUTES secAttrs, String msgPath, Boolean bFromProxy) at System.IO.FileStream..ctor(String path, FileMode mode, FileAccess access, FileShare share, Int32 bufferSize, FileOptions options) at System.IO.File.Create(String path) at MyFirm.MyPricingApp.UI.App.InitializeLogging() in C:\Projects\MyPricingApp\App.xaml.cs:line 150 at MyFirm.MyPricingApp.UI.App.Application_Startup(Object sender, StartupEventArgs e) in C:\Projects\MyPricingApp\App.xaml.cs:line 38 at System.Windows.Application.OnStartup(StartupEventArgs e) at System.Windows.Application.<.ctor>b__0(Object unused) at System.Windows.Threading.ExceptionWrapper.InternalRealCall(Delegate callback, Object args, Boolean isSingleParameter) at System.Windows.Threading.ExceptionWrapper.TryCatchWhen(Object source, Delegate callback, Object args, Boolean isSingleParameter, Delegate catchHandler) this seems like it has something to do with UAC in Windows 7, because why else would I get this since my user is already Admin on the machine ?! Also since the WinIOError has SECURITY_ATTRIBUTES, I am thinking this has something to do with a "new way" security is handled in Windows 7. I tried to browse to the "Program Files" folder, under which the log folder and file were to be created. I can create the folder by hand, but when i try to create the file, I get the similar "Access Denied" exception.

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  • mysql subquery strangely slow

    - by aviv
    I have a query to select from another sub-query select. While the two queries look almost the same the second query (in this sample) runs much slower: SELECT user.id ,user.first_name -- user.* FROM user WHERE user.id IN (SELECT ref_id FROM education WHERE ref_type='user' AND education.institute_id='58' AND education.institute_type='1' ); This query takes 1.2s Explain on this query results: id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY user index first_name 152 141192 Using where; Using index 2 DEPENDENT SUBQUERY education index_subquery ref_type,ref_id,institute_id,institute_type,ref_type_2 ref_id 4 func 1 Using where The second query: SELECT -- user.id -- user.first_name user.* FROM user WHERE user.id IN (SELECT ref_id FROM education WHERE ref_type='user' AND education.institute_id='58' AND education.institute_type='1' ); Takes 45sec to run, with explain: id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY user ALL 141192 Using where 2 DEPENDENT SUBQUERY education index_subquery ref_type,ref_id,institute_id,institute_type,ref_type_2 ref_id 4 func 1 Using where Why is it slower if i query only by index fields? Why both queries scans the full length of the user table? Any ideas how to improve? Thanks.

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  • SQLAlchemy & Complex Queries

    - by user356594
    I have to implement ACL for an existing application. So I added the a user, group and groupmembers table to the database. I defined a ManyToMany relationship between user and group via the association table groupmembers. In order to protect some ressources of the app (i..e item) I added a additional association table auth_items which should be used as an association table for the ManyToMany relationship between groups/users and the specific item. item has following columns: user_id -- user table group_id -- group table item_id -- item table at least on of user_id and group_id columns are set. So it's possible to define access for a group or for a user to a specific item. I have used the AssociationProxy to define the relationship between users/groups and items. I now want to display all items which the user has access to and I have a really hard time doing that. Following criteria are used: All items which are owned by the user should be shown (item.owner_id = user.id) All public items should be shown (item.access = public) All items which the user has access to should be shown (auth_item.user_id = user.id) All items which the group of the user has access to should be shown. The first two criteria are quite straightforward, but I have a hard time doing the 3rd one. Here is my approach: clause = and_(item.access == 'public') if user is not None: clause = or_(clause,item.owner == user,item.users.contains(user),item.groups.contains(group for group in user.groups)) The third criteria produces an error. item.groups.contains(group for group in user.groups) I am actually not sure if this is a good approach at all. What is the best approach when filtering manytomany relationships? How I can filter a manytomany relationship based on another list/relationship? Btw I am using the latest sqlalchemy (6.0) and elixir version Thanks for any insights.

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  • How long do uploaded files stay in the tmp folder in Linux Ubuntu?

    - by Jean-Nicolas Boulay Desjardins
    I am building a web application where my users will be able to upload files. After the files are uploaded I need to send the files to two other servers, and after they will be deleted from the server where they were just uploaded to. I am wandering is it a good I idea to keep the uploaded files in the tmp/ folder the time the uploaded files are sent to the other two servers or should I move them to another folder incase they get deleted? I am also wandering because I would like to know if I have to build a cron script to get rid of the files that have been transfered to the other servers so that I get my disk space back.

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  • How to recursively move all files (including hidden) in a subfolder into a parent folder in *nix?

    - by deadprogrammer
    This is a bit of an embarrassing question, but I have to admit that this late in my career I still have questions about the mv command. I frequently have this problem: I need to move all files recursively up one level. Let's say I have folder foo, and a folder bar inside it. Bar has a mess of files and folders, including dot files and folders. How do I move everything in bar to the foo level? If foo is empty, I simply move bar one level above, delete foo and rename bar into foo. Part of the problem is that I can't figure out what mv's wildcard for "everything including dots" is. A part of this question is this - is there an in-depth discussion of the wildcards that cp and mv commands use somewhere (googling this only brings very basic tutorials).

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  • configuration issue with respect to .htaccess file on ubuntu

    - by Registered User
    I am building an application tshirtshop I have following configuration in /etc/apache2/sites-enabled/tshirtshop <VirtualHost *:80> ServerAdmin webmaster@localhost DocumentRoot /var/www/tshirtshop <Directory /var/www/tshirtshop> Options Indexes FollowSymLinks AllowOverride All Order allow,deny allow from all </Directory> ErrorLog ${APACHE_LOG_DIR}/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog ${APACHE_LOG_DIR}/access.log combined </VirtualHost> and following in .htaccess file in location /var/www/tshirtshop/.htaccess <IfModule mod_rewrite.c> # Enable mod_rewrite RewriteEngine On # Specify the folder in which the application resides. # Use / if the application is in the root. RewriteBase /tshirtshop #RewriteBase / # Rewrite to correct domain to avoid canonicalization problems # RewriteCond %{HTTP_HOST} !^www\.example\.com # RewriteRule ^(.*)$ http://www.example.com/$1 [R=301,L] # Rewrite URLs ending in /index.php or /index.html to / RewriteCond %{THE_REQUEST} ^GET\ .*/index\.(php|html?)\ HTTP RewriteRule ^(.*)index\.(php|html?)$ $1 [R=301,L] # Rewrite category pages RewriteRule ^.*-d([0-9]+)/.*-c([0-9]+)/page-([0-9]+)/?$ index.php?DepartmentId=$1&CategoryId=$2&Page=$3 [L] RewriteRule ^.*-d([0-9]+)/.*-c([0-9]+)/?$ index.php?DepartmentId=$1&CategoryId=$2 [L] # Rewrite department pages RewriteRule ^.*-d([0-9]+)/page-([0-9]+)/?$ index.php?DepartmentId=$1&Page=$2 [L] RewriteRule ^.*-d([0-9]+)/?$ index.php?DepartmentId=$1 [L] # Rewrite subpages of the home page RewriteRule ^page-([0-9]+)/?$ index.php?Page=$1 [L] # Rewrite product details pages RewriteRule ^.*-p([0-9]+)/?$ index.php?ProductId=$1 [L] </IfModule> the site is working on localhost and is working as if there is no .htaccess rule specified i.e. if I were to view a page as http://localhost/tshirtshop/nature-d2 then I get a 404 Error but if I view the same page as http://localhost/tshirtshop/index.php?DepartmentId=2 then I can view it. What is the mistake if any one can point out in above configuration, or else I need to check any thing else? sudo apache2ctl -M Loaded Modules: core_module (static) log_config_module (static) logio_module (static) mpm_prefork_module (static) http_module (static) so_module (static) alias_module (shared) auth_basic_module (shared) authn_file_module (shared) authz_default_module (shared) authz_groupfile_module (shared) authz_host_module (shared) authz_user_module (shared) autoindex_module (shared) cgi_module (shared) deflate_module (shared) dir_module (shared) env_module (shared) mime_module (shared) negotiation_module (shared) php5_module (shared) reqtimeout_module (shared) rewrite_module (shared) setenvif_module (shared) status_module (shared) Syntax OK I am using Apache2 on Ubuntu 12.04

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  • What are the risks in putting website files in the "root" folder of a shared web hosting server?

    - by Obay Ouano
    A site I've been asked to manage is hosted (shared) on GoDaddy, with this folder structure: / public_html public_ftp mail stats logs etc... However, the website files are stored in the / folder, and NOT in public_html. I'm not sure if this is how GoDaddy sets up their customers' accounts, or if the old web developer accidentally changed it from public_html to root. But when we call up GoDaddy to tell them to correct this (move files to public_html), they won't change it and insist that there is no security risk unless someone gets a hold of the FTP password. Is this true? (I have always read that website files should be inside public_html.) If not, where could this setting be changed? The .htaccess is empty.

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  • User not in the sudoers file. This incident will be reported

    - by Sergiy Byelozyorov
    I need to install a package. For that I need root access. However the system says that I am not in sudoers file. When trying to edit one, it complains alike! How I am supposed to add myself to the sudoers file if I don't have the right to edit one? I have installed this system and only administrator. What can I do? Edit: I have tried visudo already. It requires me to be in sudoers in the first place. amarzaya@linux-debian-gnu:/$ sudo /usr/sbin/visudo We trust you have received the usual lecture from the local System Administrator. It usually boils down to these three things: #1) Respect the privacy of others. #2) Think before you type. #3) With great power comes great responsibility. [sudo] password for amarzaya: amarzaya is not in the sudoers file. This incident will be reported. amarzaya@linux-debian-gnu:/$

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  • Hibernate - strange order of native SQL parameters

    - by Xorty
    Hello, I am trying to use native MySQL's MD5 crypto func, so I defined custom insert in my mapping file. <hibernate-mapping package="tutorial"> <class name="com.xorty.mailclient.client.domain.User" table="user"> <id name="login" type="string" column="login"></id> <property name="password"> <column name="password" /> </property> <sql-insert>INSERT INTO user (login,password) VALUES ( ?, MD5(?) )</sql-insert> </class> </hibernate-mapping> Then I create User (pretty simple POJO with just 2 Strings - login and password) and try to persist it. session.beginTransaction(); // we have no such user in here yet User junitUser = (User) session.load(User.class, "junit_user"); assert (null == junitUser); // insert new user junitUser = new User(); junitUser.setLogin("junit_user"); junitUser.setPassword("junitpass"); session.save(junitUser); session.getTransaction().commit(); What actually happens? User is created, but with reversed parameters order. He has login "junitpass" and "junit_user" is MD5 encrypted and stored as password. What did I wrong? Thanks EDIT: ADDING POJO class package com.xorty.mailclient.client.domain; import java.io.Serializable; /** * POJO class representing user. * @author MisoV * @version 0.1 */ public class User implements Serializable { /** * Generated UID */ private static final long serialVersionUID = -969127095912324468L; private String login; private String password; /** * @return login */ public String getLogin() { return login; } /** * @return password */ public String getPassword() { return password; } /** * @param login the login to set */ public void setLogin(String login) { this.login = login; } /** * @param password the password to set */ public void setPassword(String password) { this.password = password; } /** * @see java.lang.Object#toString() * @return login */ @Override public String toString() { return login; } /** * Creates new User. * @param login User's login. * @param password User's password. */ public User(String login, String password) { setLogin(login); setPassword(password); } /** * Default constructor */ public User() { } /** * @return hashCode * @see java.lang.Object#hashCode() */ @Override public int hashCode() { final int prime = 31; int result = 1; result = prime * result + ((null == login) ? 0 : login.hashCode()); result = prime * result + ((null == password) ? 0 : password.hashCode()); return result; } /** * @param obj Compared object * @return True, if objects are same. Else false. * @see java.lang.Object#equals(java.lang.Object) */ @Override public boolean equals(Object obj) { if (this == obj) { return true; } if (obj == null) { return false; } if (!(obj instanceof User)) { return false; } User other = (User) obj; if (login == null) { if (other.login != null) { return false; } } else if (!login.equals(other.login)) { return false; } if (password == null) { if (other.password != null) { return false; } } else if (!password.equals(other.password)) { return false; } return true; } }

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