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  • Importing Excel data into SSIS 2008 using Data Conversion Transformation

    Despite its benefits, SQL Server Integration Services Import Export Wizard has a number of limitations, resulting in part from a new set of rules that eliminate implicit data type conversion mechanisms present in Data Transformation Services. This article discusses a method that addresses such limitations, focusing in particular on importing the content of Excel spreadsheets into SQL Server.

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  • adding custom SSIS transformation to visual studio toolbox fails

    - by ryangaraygay
    Just very recently I encountered an issue in deploying a custom SSIS component assembly which turns out to be a relative "no-brainer" error if only the clues were more straightforward. Basically after deploying the assembly I could not find my component listed in the "SSIS Data Flow Items" tab list.It turns out that the assembly containing the component just had missing or referenced the incorrect assemblies.I have outlined the steps I took that guided me on the right direction on this blog post of mine : adding custom SSIS transformation to visual studio toolbox fails 

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  • Enable Seamless Transformation and Effective Adoption of Change with Oracle User Productivity Kit

    Organizations go through continuous transformation and change - whether it is through mergers and acquisitions, standardizations of systems, a rollout of a new application or business process improvements. With Oracle User Productivity Kit, project teams can capture and deploy best practices to streamline efficiency, reduce cost, and ensure successful change adoption. Discover how organizations can leverage the multiple outputs of Oracle UPK for all phases of the project from blueprinting/design/configuration to testing/training/go-live as well as maintenance and support.

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  • Row Number Transformation

    The Row Number Transformation calculates a row number for each row, and adds this as a new output column to the data flow. The column number is a sequential number, based on a seed value. Each row receives the next number in the sequence, based on the defined increment value. Develop seamlessly between Management Studio and Visual StudioSQL Connect is a Visual Studio add-in that makes it easy to keep your database and Visual Studio project in sync.

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  • Row Count Plus Transformation

    As the name suggests we have taken the current Row Count Transform that is provided by Microsoft in the Integration Services toolbox and we have recreated the functionality and extended upon it. There are two things about the current version that we thought could do with cleaning up Lack of a custom UI You have to type the variable name yourself In the Row Count Plus Transformation we solve these issues for you.

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  • How to convert TM-2 degree coordinate to lat lon on Android?

    - by Victor Lin
    I am writing a program that convert TM-2 degree to lat/lon on Android, but I can't find formula for that. I do find some example on internet, but most of them are convert with open source library, that I can't use on Android platform. I also find a java class that do convert from UTM to lat lon, but it seems no suitable for TM 2 degreen coordinate system. So my question is: how do I convert TM 2 degree coordinate to lat/lon? Where can I find formula?

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  • Finding the closest grid coordinate to the mouse position with javascript/jQuery

    - by Acorn
    What I'm trying to do is make a grid of invisible coordinates on the page equally spaced. I then want a <div> to be placed at whatever grid coordinate is closest to the pointer when onclick is triggered. Here's the rough idea: I have the tracking of the mouse coordinates and the placing of the <div> worked out fine. What I'm stuck with is how to approach the problem of the grid of coordinates. First of all, should I have all my coordinates in an array which I then compare my onclick coordinate to? Or seeing as my grid coordinates follow a rule, could I do something like finding out which coordinate that is a multiple of whatever my spacing is is closest to the onclick coordinate? And then, where do I start with working out which grid point coordinate is closest? What's the best way of going about it? Thanks!

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  • Finding the closest grid coordinate to the mouse onclick with javascript/jQuery

    - by Acorn
    What I'm trying to do is make a grid of invisible coordinates on the page equally spaced. I then want a <div> to be placed at whatever grid coordinate is closest to the pointer when onclick is triggered. Here's the rough idea: I have the tracking of the mouse coordinates and the placing of the <div> worked out fine. What I'm stuck with is how to approach the problem of the grid of coordinates. First of all, should I have all my coordinates in an array which I then compare my onclick coordinate to? Or seeing as my grid coordinates follow a rule, could I do something like finding out which coordinate that is a multiple of whatever my spacing is is closest to the onclick coordinate? And then, where do I start with working out which grid point coordinate is closest? What's the best way of going about it? Thanks!

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  • What is the name of this array transformation?

    - by Brandon Tilley
    Start with an array of arrays; in this case, they are different lengths in order to demonstrate the technique, but they do not have to be. [[1,2,3,4], [5,6,7], [8,9,10], [11,12,13,14,15]] At the other end of the transformation, you have an array of arrays where the first array contains the first element from each of the original arrays, the second array contains the second element from each of the original arrays, and so on. [[1,5,8,11], [2,6,9,12], [3,7,10,13], [4,14], [15]] Is there a mathematical or CS term for this operation?

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  • HTML5 canvas screen to isometric coordinate conversion

    - by ovhqe
    I am trying to create an isometric game using HTML5 canvas, but don't know how to convert HTML5 canvas screen coordinates to isometric coordinates. My code now is: var mouseX = 0; var mouseY = 0; function mouseCheck(event) { mouseX = event.pageX; mouseY = event.pageY; } which gives me canvas coordinates. But how do I convert these coordinates to isometric coordinates? I am using 16x16 tiles.

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  • FBX SDK Not Converting Child Node Coordinate Systems

    - by Al Bundy
    I am trying to import a scene into my application from an fbx file. In 3DS Max, the scene and it’s local translations are as follows: Root (0, 0, 0) '-Sphere001 (-15, 30, 0) ' '-Sphere002 (-2, -30, 0) ' '-Sphere003 (-30, -20, 0) '-Cube001 (35, -15, 0) This is the code that I am using to get the translations of each node: FbxDouble3 fbxPosition = pChild->LclTranslation.Get(); FbxDouble3 fbxRotation = pChild->LclRotation.Get(); FbxDouble3 fbxScale = pChild->LclScaling.Get(); When I try to import the scene, the first node from the scene is getting converted to a right handed system, using this conversion: (X, Z, -Y), but none of their child nodes are. after importing the scene, the local translations I get are as follows: Root (0, 0, 0) --Sphere001 (-15, 0, -30) - converted ----Sphere002 (-2, -30, 0) - not converted ------Sphere003 (-30, -20, 0) - not converted --Cube001 (35, 0, 15) - converted Can anybody help me make sense of this? Thanks

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  • Xna Equivalent of Viewport.Unproject in a draw call as a matrix transformation

    - by Nick Crowther
    I am making a 2D sidescroller and I would like to draw my sprite to world space instead of client space so I do not have to lock it to the center of the screen and when the camera stops the sprite will walk off screen instead of being stuck at the center. In order to do this I wanted to make a transformation matrix that goes in my draw call. I have seen something like this: http://stackoverflow.com/questions/3570192/xna-viewport-projection-and-spritebatch I have seen Matrix.CreateOrthographic() used to go from Worldspace to client space but, how would I go about using it to go from clientspace to worldspace? I was going to try putting my returns from the viewport.unproject method I have into a scale matrix such as: blah = Matrix.CreateScale(unproject.X,unproject.Y,0); however, that doesn't seem to work correctly. Here is what I'm calling in my draw method(where X is the coordinate my camera should follow): Vector3 test = screentoworld(X, graphics); var clienttoworld = Matrix.CreateScale(test.X,test.Y, 0); animationPlayer.Draw(theSpriteBatch, new Vector2(X.X,X.Y),false,false,0,Color.White,new Vector2(1,1),clienttoworld); Here is my code in my unproject method: Vector3 screentoworld(Vector2 some, GraphicsDevice graphics): Vector2 Position =(some.X,some.Y); var project = Matrix.CreateOrthographic(5*graphicsdevice.Viewport.Width, graphicsdevice.Viewport.Height, 0, 1); var viewMatrix = Matrix.CreateLookAt( new Vector3(0, 0, -4.3f), new Vector3(X.X,X.Y,0), Vector3.Up); //I have also tried substituting (cam.Position.X,cam.Position.Y,0) in for the (0,0,-4.3f) Vector3 nearSource = new Vector3(Position, 0f); Vector3 nearPoint = graphicsdevice.Viewport.Unproject(nearSource, project, viewMatrix, Matrix.Identity); return nearPoint;

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  • Rotation based on x coordinate and x velocity?

    - by Lewis
    -(void) accelerometer:(UIAccelerometer *)accelerometer didAccelerate:(UIAcceleration *)acceleration { float deceleration = 0.3f, sensitivity = 8.0f, maxVelocity = 150; // adjust velocity based on current accelerometer acceleration playerVelocity.x = playerVelocity.x * deceleration + acceleration.x * sensitivity; // we must limit the maximum velocity of the player sprite, in both directions (positive & negative values) playerVelocity.x = fmaxf(fminf(playerVelocity.x, maxVelocity), -maxVelocity); } Hi, I want to rotate my sprite based on the velocity and accelerometer input. My sprite can move along the X axis like so: <--------- sprite ----------- But it always faces forwards, if it is moving left I want it to point slightly to the left, the degree of how far it is pointing to be judged from the velocity. This should also work for the right. I tried using atan but as the y velocity and position is always the same the function returns 0, which doesn't rotate it at all. Any ideas? Regards, Lewis.

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  • How to transform gameObjects in array?

    - by user1764781
    I have an array of available gameObjects in the scene. An array of GO should be transformed according to received floats through UDP connection. I know it is simple, but can't figure it out how to accomplish the transformation an array of GO according to received unique floats for each GO, any help will be appreciated. Here is a transformation floats, it might be helpful I guess: x =ReadSingleBigEndian(data, signalOffset); signalOffset+=4; y= ReadSingleBigEndian(data, signalOffset); signalOffset+=4; z= ReadSingleBigEndian(data, signalOffset); signalOffset+=4; alpha= ReadSingleBigEndian(data, signalOffset); signalOffset+=4; theta= ReadSingleBigEndian(data,signalOffset); signalOffset+=4; phi= ReadSingleBigEndian(data,signalOffset); signalOffset+=4;

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  • Most efficient way to handle coordinate maps in Java

    - by glowcoder
    I have a rectangular tile-based layout. It's your typical Cartesian system. I would like to have a single class that handles two lookup styles Get me the set of players at position X,Y Get me the position of player with key K My current implementation is this: class CoordinateMap<V> { Map<Long,Set<V>> coords2value; Map<V,Long> value2coords; // convert (int x, int y) to long key - this is tested, works for all values -1bil to +1bil // My map will NOT require more than 1 bil tiles from the origin :) private Long keyFor(int x, int y) { int kx = x + 1000000000; int ky = y + 1000000000; return (long)kx | (long)ky << 32; } // extract the x and y from the keys private int[] coordsFor(long k) { int x = (int)(k & 0xFFFFFFFF) - 1000000000; int y = (int)((k >>> 32) & 0xFFFFFFFF) - 1000000000; return new int[] { x,y }; } } From there, I proceed to have other methods that manipulate or access the two maps accordingly. My question is... is there a better way to do this? Sure, I've tested my class and it works fine. And sure, something inside tells me if I want to reference the data by two different keys, I need two different maps. But I can also bet I'm not the first to run into this scenario. Thanks!

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  • Aberdeen 10/25 Webcast: Service Excellence and the Path to Business Transformation

    - by Charles Knapp
    The uncertain economy has had a sustained impact on service organizations and processes. The impact has contributed to new complexities - new customer engagement channels, enhanced user and customer expectations, rapidly evolving technologies, increased competition, and increased compliance and regulatory mandates. Yet many organizations have embraced these challenges by investing in and transforming customer service to evolve, differentiate, and thrive under current constraints. What is their secret? Transforming Support Centers into Profit Centers According to the recent Aberdeen research report, “Service Excellence and the Path to Business Transformation”, service is now viewed as a strategic profit center at nearly 70% of organizations. As customers demand improved service, in terms of speed, efficiency and reliability, an organization's success has become increasingly dependent on optimizing the customer ownership experience. Those service organizations focused on providing easy, consistent, and relevant interactions across the customer lifecycle, including service and support delivery, are experiencing higher levels of customer acquisition and retention and are achieving better revenue and margin growth rates.  Don't miss this opportunity to learn how to transform to provide the next generation of service offerings. Click here to register now for the webcast and download a complimentary copy of this informative new research paper.

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  • Coordinate and positioning problem on iOS with cocos2d-x

    - by Vexille
    I'm using cocos2d-x alongside with Marmalade and running some tests and tutorials before starting an actual project with them. So far things are working reasonably well on the windows simulator, Android and even on Blackberry's Playbook, but on iOS devices (iPhone and iPad) the positioning seems to be off. To make things clearer, I put together a scene that just draws an image in the middle of the screen. It worked as expected on everything else, but this is the result I got on an iPhone: To get the coordinates for the center of the screen I'm using the VisibleRect class from the TestCpp sample. It just uses sharedOpenGLView to get the visible size and visible origin, and calculate the center from that. CCSprite* test = CCSprite::create("Ball.png", CCRectMake(0, 0, 80, 80) ); test->setPosition( ccp(VisibleRect::center().x, VisibleRect::center().y) ); this->addChild(test); Also I have a noBorder policy set on AppDelegate: CCEGLView::sharedOpenGLView()->setDesignResolutionSize(designSize.width, designSize.height, kResolutionNoBorder); One funny thing is that I tried to deploy the TestCpp sample project to some iOS devices and it worked reasonably well on the iPhone, but on the iPad the application was only being drawn on a small portion of the screen - just like what happened on the iPhone when I tried using the ShowAll policy.

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  • Coordinate spaces and transformation matrices

    - by Belgin
    I'm trying to get an object from object space, into projected space using these intermediate matrices: The first matrix (I) is the one that transforms from object space into inertial space, but since my object is not rotated or translated in any way inside the object space, this matrix is the 4x4 identity matrix. The second matrix (W) is the one that transforms from inertial space into world space, which is just a scale transform matrix of factor a = 14.1 on all coordinates, since the inertial space origin coincides with the world space origin. /a 0 0 0\ W = |0 a 0 0| |0 0 a 0| \0 0 0 1/ The third matrix (C) is the one that transforms from world space, into camera space. This matrix is a translation matrix with a translation of (0, 0, 10), because I want the camera to be located behind the object, so the object must be positioned 10 units into the z axis. /1 0 0 0\ C = |0 1 0 0| |0 0 1 10| \0 0 0 1/ And finally, the fourth matrix is the projection matrix (P). Bearing in mind that the eye is at the origin of the world space and the projection plane is defined by z = 1, the projection matrix is: /1 0 0 0\ P = |0 1 0 0| |0 0 1 0| \0 0 1/d 0/ where d is the distance from the eye to the projection plane, so d = 1. I'm multiplying them like this: (((P x C) x W) x I) x V, where V is the vertex' coordinates in column vector form: /x\ V = |y| |z| \1/ After I get the result, I divide x and y coordinates by w to get the actual screen coordinates. Apparenly, I'm doing something wrong or missing something completely here, because it's not rendering properly. Here's a picture of what is supposed to be the bottom side of the Stanford Dragon: Also, I should add that this is a software renderer so no DirectX or OpenGL stuff here.

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  • Converting Degrees to X and Y Coordinate change

    - by gopgop
    I am using a float positioning system in my game. IE float x,y,z now I want to get the location of the mouse, then to fire an arrow to it. X0 = the players X location X1 = the mouse X location Y0 = the players Y location Y1 = the mouse Y location I want to make a method that the parameters are Degrees and it sets my Yspeed and my Xspeed accordingly to get to the mouse xy starting at player xy How do would I accomplish this?

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  • Zero to Cloud : One stop shop for resources to accelerate your transformation to enterprise private cloud

    - by Anand Akela
    Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} During the Oracle Open World 2012 last week, Oracle introduced "Zero to Cloud" resource center to help you accelerate your transformation journey to enterprise private cloud. To help organizations deploy fully operational, enterprise-grade private cloud environment in as little as half a day, Oracle has brought key content together into this single, user-friendly resource center. Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} The resource center is launched just as the Oracle Cloud Builder Summit series moves into full swing. Designed for executives, cloud architects, and IT operations professionals, the day-long event series will eventually reach nearly 100 cities around the globe. During this event, an interactive "Zero to Cloud" session will showcase the transformational journey of a fictitious enterprise to the private cloud using the latest solutions from Oracle—including, Oracle Database, Oracle Fusion Middleware, Oracle VM and Oracle Enterprise Manager, as well as Oracle’s full range of engineered systems. The online "Zero to Cloud" resource center includes best practices from Oracle experts and early adopter customers as well as interviews with Oracle development executives responsibly for Oracle’s private cloud solutions and roadmap. It also includes a new self-assessment quiz that can help determine readiness for a successful private cloud deployment. Once you've determined organizational readiness, explore early adopter tips, demos, guides, exclusive white papers and more at the "Zero to Cloud" resource center.

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  • Why do we need normalized coordinate system? Options

    - by jcyang
    Hi, I have problem understand following sentences in my textbook Computer Graphics with OpenGL. "To make viewing process independent of the requirements of any output device,graphic system convert object descriptions to normalized coordinates and apply the clipping routines." Why normalized coordinates could make viewing process independent of the requirements of any output devices? Isn't the projection coordinates already independent of output device?We only need to first scale and then translate the projection coordinate then we will get device coordinate. So why do we need first convert the projection coordinate to normalized coordinate first? "Clipping is usually performed in normlized coordinates.This allows us to reduce computations by first concatenating the various transformation matrices" Why clipping is usually performed in normlized coordinates? What kind of transformation concatenated? thanks. jcyang.

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  • Why / how does XNA's right-handed coordinate system effect anything if you can specify near/far Z values?

    - by vargonian
    I am told repeatedly that XNA Game Studio uses a right-handed coordinate system, and I understand the difference between a right-handed and left-handed coordinate system. But given that you can use a method like Matrix.CreateOrthographicOffCenter to create your own custom projection matrix, specifying the left, right, top, bottom, zNear and zFar values, when does XNA's coordinate system come into play? For example, I'm told that in a right-handed coordinate system, increasingly negative Z values go "into" the screen. But I can easily create my projection matrix like this: Matrix.CreateOrthographicOffCenter(left, right, bottom, top, 0.1f, 10000f); I've now specified a lower value for the near Z than the far Z, which, as I understand it, means that positive Z now goes into the screen. I can similarly tweak the values of left/right/top/bottom to achieve similar results. If specifying a lower zNear than zFar value doesn't affect the Z direction of the coordinate system, what does it do? And when is the right-handed coordinate system enforced? The reason I ask is that I'm trying to implement a 2.5D camera that supports zooming and rotation, and I've spent two full days encountering one unexpected result after another.

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