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  • SQL SERVER – Difference between COUNT(DISTINCT) vs COUNT(ALL)

    - by pinaldave
    This blog post is written in response to the T-SQL Tuesday hosted by Jes Schultz Borland. Earlier today, I was presenting a 45-minute session at the Community College about “The Beginning SQL Server Database”. One of the students asked me the following question. What is the difference between COUNT(DISTINCT) vs COUNT(ALL)? I found this question from the student very interesting. He seems to have read the documentation (Book Online) and was then asking me this question. I always carry laptop which has SQL Server installed. I quickly opened it and ran the following script. After looking at the result, I think it was clear to everybody. Here is the script: SELECT COUNT([Title]) Value FROM [AdventureWorks].[Person].[Contact] GO SELECT COUNT(ALL [Title]) ALLValue FROM [AdventureWorks].[Person].[Contact] GO SELECT COUNT(DISTINCT [Title]) DistinctValue FROM [AdventureWorks].[Person].[Contact] GO The above script will give me the following results. You can clearly notice from the result set that COUNT (ALL ColumnName) is the same as COUNT(ColumnName). The reality is that the “ALL” is actually  the default option and it needs not to be specified. The ALL keyword includes all the non-NULL values. I know this is very simple and may be it does not change how we work; however looking at the whole angle, I really enjoyed the question. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, SQLAuthority News, T SQL, Technology

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  • sql-server: how can I list distinct value of table in a single row, separated by comma

    - by RedsDevils
    I have the following Table: CREATE TABLE TEMP (ID INT,SEGMENT CHAR(1),SEGOFF INT,CHECKED SMALLDATETIME) INSERT INTO TEMP VALUES (1,'A',0,'2009-05-01') INSERT INTO TEMP VALUES (2,'B',1,'2009-05-01') INSERT INTO TEMP VALUES (3,'C',0,'2009-05-01') INSERT INTO TEMP VALUES (4,'A',0,'2009-05-02') INSERT INTO TEMP VALUES (5,'B',2,'2009-05-02') INSERT INTO TEMP VALUES (6,'C',1,'2009-05-02') INSERT INTO TEMP VALUES (7,'A',1,'2009-05-03') INSERT INTO TEMP VALUES (8,'B',0,'2009-05-03') INSERT INTO TEMP VALUES (9,'C',2,'2009-05-03') I would like to show Distinct SEGEMENT in Single row separated by comma (e.g: A,B,C) I try as Follow: DECLARE @SEGMENTList varchar(100) SELECT @SEGMENTList = COALESCE(@SEGMENTList + ', ', '') + SEGMENT FROM TEST SELECT @SEGMENTList It shows A, B, C, A, B, C, A, B, C What do I need to change my query? Thanks all!

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  • How to SELECT DISTINCT Info with TOP 1 Info and an Order By FROM the Top 1 Info

    - by Erin Taylor
    I have 2 tables, that look like: CustomerInfo(CustomterID, CustomerName) CustomerReviews(ReviewID, CustomerID, Review, Score) I want to search reviews for a string and return CustomerInfo.CustomerID and CustomerInfo.CustomerName. However, I only want to show distinct CustomerID and CustomerName along with just one of their CustomerReviews.Reviews and CustomerReviews.Score. I also want to order by the CustomerReviews.Score. I can't figure out how to do this, since a customer can leave multiple reviews, but I only want a list of customers with their highest scored review. Any ideas?

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  • Difference between DISTINCT and VALUES in DAX

    - by Marco Russo (SQLBI)
    I recently got a question about differences between DISTINCT and VALUES in DAX and thanks to Jeffrey Wang I created a simple example to describe the difference. Consider the two tables below: Fact and Dim tables, having a single column with the same name of the table. A relationship exists between Fact[Fact] and Dim[Dim]. This relationship generates a referential integrity violations in table Fact for rows containing C, which doesn’t exist in table Dim. In this case, an empty row is virtually inserted...(read more)

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  • Fastest way to check if two square 2D arrays are rotationally and reflectively distinct

    - by kustrle
    The best idea I have so far is to rotate first array by {0, 90, 180, 270} degrees and reflect it horizontally or/and vertically. We basically get 16 variations [1] of first array and compare them with second array. if none of them matches the two arrays are rotationally and reflectively distinct. I am wondering if there is more optimal solution than this brute-force approach? [1] 0deg, no reflection 0deg, reflect over x 0deg, reflect over y 0deg, reflect over x and y 90deg, no reflection ...

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  • Select distinct ... inner join vs. select ... where id in (...)

    - by Tonio
    I'm trying to create a subset of a table (as a materialized view), defined as those records which have a matching record in another materialized view. For example, let's say I have a Users table with user_id and name columns, and a Log table, with entry_id, user_id, activity, and timestamp columns. First I create a materialized view of the Log table, selecting only those rows with timestamp some_date. Now I want a materliazed view of the Users referenced in my snapshot of the Log table. I can either create it as select * from Users where user_id in (select user_id from Log_mview), or I can do select distinct u.* from Users u inner join Log_mview l on u.user_id = l.user_id (need the distinct to avoid multiple hits from users with multiple log entries). The former seems cleaner and more elegant, but takes much longer. Am I missing something? Is there a better way to do this?

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  • How to get distinct results in hibernate with joins and row-based limiting?

    - by Daniel Alexiuc
    I'm trying to implement paging using row-based limiting (for example: setFirstResult(5) and setMaxResults(10)) on a Hibernate Criteria query that has joins to other tables. Understandably, data is getting cut off randomly; and the reason for that is explained here. As a solution, the page suggests using a "second sql select" instead of a join. How can I convert my existing criteria query (which has joins using createAlias()) to use a nested select instead?

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  • How do I Fix SQL Server error: Order by items must appear in the select list if Select distinct is s

    - by Paula DiTallo 2007-2009 All Rights Reserved
    There's more than one reason why you may receive this error, but the most common reason is that your order by statement column list doesn't correlate with the values specified in your column list when you happen to be using DISTINCT. This is usually easy to spot and resolve. A more obscure reason may be that you are using a function around one of the selected columns --but omitting to use the same function around the same selected column name in the order by statement. Here's an example:   select distinct upper(columnA)   from [evaluate].[testTable]    order by columnA  asc   This statement will cause the "Order by items must appear in the select list if SELECT DISTINCT is specified."  error to appear not because distinct was used, but because the order by statement did not utilize the upper() fundtion around colunnA.  To correct this error, do this: select distinct upper(columnA)   from [evaluate].[testTable]    order by upper(columnA) asc

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  • How to get distinct values from the List&lt;T&gt; with LINQ

    - by Vincent Maverick Durano
    Recently I was working with data from a generic List<T> and one of my objectives is to get the distinct values that is found in the List. Consider that we have this simple class that holds the following properties: public class Product { public string Make { get; set; } public string Model { get; set; } }   Now in the page code behind we will create a list of product by doing the following: private List<Product> GetProducts() { List<Product> products = new List<Product>(); Product p = new Product(); p.Make = "Samsung"; p.Model = "Galaxy S 1"; products.Add(p); p = new Product(); p.Make = "Samsung"; p.Model = "Galaxy S 2"; products.Add(p); p = new Product(); p.Make = "Samsung"; p.Model = "Galaxy Note"; products.Add(p); p = new Product(); p.Make = "Apple"; p.Model = "iPhone 4"; products.Add(p); p = new Product(); p.Make = "Apple"; p.Model = "iPhone 4s"; products.Add(p); p = new Product(); p.Make = "HTC"; p.Model = "Sensation"; products.Add(p); p = new Product(); p.Make = "HTC"; p.Model = "Desire"; products.Add(p); p = new Product(); p.Make = "Nokia"; p.Model = "Some Model"; products.Add(p); p = new Product(); p.Make = "Nokia"; p.Model = "Some Model"; products.Add(p); p = new Product(); p.Make = "Sony Ericsson"; p.Model = "800i"; products.Add(p); p = new Product(); p.Make = "Sony Ericsson"; p.Model = "800i"; products.Add(p); return products; }   And then let’s bind the products to the GridView. protected void Page_Load(object sender, EventArgs e) { if (!IsPostBack) { Gridview1.DataSource = GetProducts(); Gridview1.DataBind(); } }   Running the code will display something like this in the page: Now what I want is to get the distinct row values from the list. So what I did is to use the LINQ Distinct operator and unfortunately it doesn't work. In order for it work is you must use the overload method of the Distinct operator for you to get the desired results. So I’ve added this IEqualityComparer<T> class to compare values: class ProductComparer : IEqualityComparer<Product> { public bool Equals(Product x, Product y) { if (Object.ReferenceEquals(x, y)) return true; if (Object.ReferenceEquals(x, null) || Object.ReferenceEquals(y, null)) return false; return x.Make == y.Make && x.Model == y.Model; } public int GetHashCode(Product product) { if (Object.ReferenceEquals(product, null)) return 0; int hashProductName = product.Make == null ? 0 : product.Make.GetHashCode(); int hashProductCode = product.Model.GetHashCode(); return hashProductName ^ hashProductCode; } }   After that you can then bind the GridView like this: protected void Page_Load(object sender, EventArgs e) { if (!IsPostBack) { Gridview1.DataSource = GetProducts().Distinct(new ProductComparer()); Gridview1.DataBind(); } }   Running the page will give you the desired output below: As you notice, it now eliminates the duplicate rows in the GridView. Now what if we only want to get the distinct values for a certain field. For example I want to get the distinct “Make” values such as Samsung, Apple, HTC, Nokia and Sony Ericsson and populate them to a DropDownList control for filtering purposes. I was hoping the the Distinct operator has an overload that can compare values based on the property value like (GetProducts().Distinct(o => o.PropertyToCompare). But unfortunately it doesn’t provide that overload so what I did as a workaround is to use the GroupBy,Select and First LINQ query operators to achieve what I want. Here’s the code to get the distinct values of a certain field. protected void Page_Load(object sender, EventArgs e) { if (!IsPostBack) { DropDownList1.DataSource = GetProducts().GroupBy(o => o.Make).Select(o => o.First()); DropDownList1.DataTextField = "Make"; DropDownList1.DataValueField = "Model"; DropDownList1.DataBind(); } } Running the code will display the following output below:   That’s it! I hope someone find this post useful!

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  • How to create distinct set from other sets?

    - by shyam_baidya
    While solving the problems on Techgig.com, I got struck with one one of the problem. The problem is like this: A company organizes two trips for their employees in a year. They want to know whether all the employees can be sent on the trip or not. The condition is like, no employee can go on both the trips. Also to determine which employee can go together the constraint is that the employees who have worked together in past won't be in the same group. Examples of the problems: Suppose the work history is given as follows: {(1,2),(2,3),(3,4)}; then it is possible to accommodate all the four employees in two trips (one trip consisting of employees 1& 3 and other having employees 2 & 4). Neither of the two employees in the same trip have worked together in past. Suppose the work history is given as {(1,2),(1,3),(2,3)} then there is no way possible to have two trips satisfying the company rule and accommodating all the employees. Can anyone tell me how to proceed on this problem?

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  • WM_CONCAT with DISTINCT Clause - Compiled Package versus Stand-Alone Query Issue

    - by Reimius
    I was writing some program that uses the WM_CONCAT function. When I run this query: SELECT WM_CONCAT(DISTINCT employee_id) FROM employee WHERE ROWNUM < 20; It works fine. When I try to compile the relatively same query in a package function or procedure, it produces this error: PL/SQL: ORA-30482: DISTINCT option not allowed for this function FUNCTION fetch_raw_data_by_range RETURN VARCHAR2 IS v_some_string VARCHAR2(32000); BEGIN SELECT WM_CONCAT(DISTINCT employee_id) INTO v_some_string FROM employee WHERE ROWNUM < 20; RETURN v_some_string; END; I realize WM_CONCAT is not officially supported, but can someone explain why it would work as a stand alone query with DISTINCT, but not compile in a package?

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  • return distinct records using subsonic 3 query and VB

    - by HR
    I have been having issues trying to return distinct records from a subsonic3 query using VB. My base query looks like so: Dim q As New [Select]("Region") q.From("StoreLocation") q.Where("State").IsEqualTo(ddlState.SelectedValue) q.OrderAsc("Region") This returns duplicates. How can I add a distinct clause in this to return distinct records? I have been trying to place around with Contraints, but to no avail. Thanks in advance HR

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  • using distinct in django query

    - by Hulk
    There is a column as designation in the defaults table,How to get the distinct designation values from defaults table In the below the distinct applies on the id field, this need to be on designation field def = defaults.objects.filter(name=sc).distinct() And can some one explain what is flat=true condition Thanks..

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  • postgres - regex_replace in distinct clause?

    - by n00b0101
    Ok... changing the question here... I'm getting an error when I try this: SELECT COUNT ( DISTINCT mid, regexp_replace(na_fname, '\\s*', '', 'g'), regexp_replace(na_lname, '\\s*', '', 'g')) FROM masterfile; Is it possible to use regexp in a distinct clause like this? The error is this: WARNING: nonstandard use of \\ in a string literal LINE 1: ...CT COUNT ( DISTINCT mid, regexp_replace(na_fname, '\\s*', ''...

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  • MySQL: Count occurrences of known (or enumerated) distinct values

    - by Eilidh
    After looking at how to count the occurrences of distinct values in a field, I am wondering how to count the occurrences of each distinct value if the distinct values are known (or enumerated). For example, if I have a simple table - TrafficLight Colour ------------ ------ 1 Red 2 Amber 3 Red 4 Red 5 Green 6 Green where one column (in this case Colour) has known (or enumerated) distinct values, how could I return the count for each colour as a separate value, rather than as an array, as in the linked example. To return an array with a count of each colour (using the same method as in the linked example), the query would be something like SELECT Colour COUNT(*) AS ColourCount FROM TrafficLights GROUP BY Colour, and return an array - Colour ColourCount ------ ----------- Red 3 Amber 1 Green 2 What I would like to do is to return the count for each Colour AS a separate total (e.g. RedCount). How can I do this?

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  • DISTINCT clause in SQLite

    - by Eye of Hell
    Hello. Recently i found that SQLite don't support DISTINCT ON() clause that seems postgresql-specific. For exeample, if i have table t with columns a and b. And i want to select all items with distinct b. Is the following query the only one and correct way to do so in SQLite? select * from t where b in (select distinct b from t)

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  • Why my mysql DISTINCT doesn't work ?

    - by belaz
    Hello, Why the two query below return duplicate member_id and not the third ? i need the second query to work with distinct. Anytime i run a GROUP BY, this query is incredibly slow and the resultset doesn't return the same value as distinct (the value is wrong). SELECT member_id, id FROM ( SELECT * FROM table1 ORDER BY created_at desc ) as u LIMIT 5 +-----------+--------+ | member_id | id | +-----------+--------+ | 11333 | 313095 | | 141831 | 313094 | | 141831 | 313093 | | 12013 | 313092 | | 60821 | 313091 | +-----------+--------+ SELECT distinct member_id, id FROM ( SELECT * FROM table1 ORDER BY created_at desc ) as u LIMIT 5 +-----------+--------+ | member_id | id | +-----------+--------+ | 11333 | 313095 | | 141831 | 313094 | | 141831 | 313093 | | 12013 | 313092 | | 60821 | 313091 | +-----------+--------+ SELECT distinct member_id FROM ( SELECT * FROM table1 ORDER BY created_at desc ) as u LIMIT 5 +-----------+ | member_id | +-----------+ | 11333 | | 141831 | | 12013 | | 60821 | | 64980 | +-----------+ my table sample CREATE TABLE `table1` ( `id` int(11) NOT NULL AUTO_INCREMENT, `member_id` int(11) NOT NULL, `s_type_id` int(11) NOT NULL, `created_at` datetime DEFAULT NULL, PRIMARY KEY (`id`), KEY `s_FI_1` (`member_id`), KEY `s_FI_2` (`s_type_id`) ) ENGINE=InnoDB AUTO_INCREMENT=313096 DEFAULT CHARSET=utf8;

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  • Problems with :uniq => true/Distinct option in a has_many_through association w/ named scope (Rails)

    - by MikeH
    I had to make some tweaks to my app to add new functionality, and my changes seem to have broken the :uniq option that was previously working perfectly. Here's the set up: #User.rb has_many :products, :through = :seasons, :uniq = true has_many :varieties, :through = :seasons, :uniq = true #product.rb has_many :seasons has_many :users, :through = :seasons, :uniq = true has_many :varieties #season.rb belongs_to :product belongs_to :variety belongs_to :user named_scope :by_product_name, :joins = :product, :order = 'products.name' #variety.rb belongs_to :product has_many :seasons has_many :users, :through = :seasons, :uniq = true First I want to show you the previous version of the view that is now breaking, so that we have a baseline to compare. The view below is pulling up products and varieties that belong to the user. In both versions below, I've assigned the same products/varieties to the user so the logs will looking at the exact same use case. #user/show <% @user.products.each do |product| %> <%= link_to product.name, product %> <% @user.varieties.find_all_by_product_id(product.id).each do |variety| %> <%=h variety.name.capitalize %></p> <% end %> <% end %> This works. It displays only one of each product, and then displays each product's varieties. In the log below, product ID 1 has 3 associated varieties. And product ID 43 has none. Here's the log output for the code above: Product Load (11.3ms) SELECT DISTINCT `products`.* FROM `products` INNER JOIN `seasons` ON `products`.id = `seasons`.product_id WHERE ((`seasons`.user_id = 1)) ORDER BY name, products.name Product Columns (1.8ms) SHOW FIELDS FROM `products` Variety Columns (1.9ms) SHOW FIELDS FROM `varieties` Variety Load (0.7ms) SELECT DISTINCT `varieties`.* FROM `varieties` INNER JOIN `seasons` ON `varieties`.id = `seasons`.variety_id WHERE (`varieties`.`product_id` = 1) AND ((`seasons`.user_id = 1)) ORDER BY name Variety Load (0.5ms) SELECT DISTINCT `varieties`.* FROM `varieties` INNER JOIN `seasons` ON `varieties`.id = `seasons`.variety_id WHERE (`varieties`.`product_id` = 43) AND ((`seasons`.user_id = 1)) ORDER BY name Ok, so everything above is the previous version which was working great. In the new version, I added some columns to the join table called seasons, and made a bunch of custom methods that query those columns. As a result, I made the following changes to the view code that you saw above so that I could access those methods on the seasons model: <% @user.seasons.by_product_name.each do |season| %> <%= link_to season.product.name, season.product %> #Note: I couldn't get this loop to work at all, so I settled for the following: #<% @user.varieties.find_all_by_product_id(product.id).each do |variety| %> <%=h season.variety.name.capitalize %> <%end%> <%end%> Here's the log output for that: SQL (0.9ms) SELECT count(DISTINCT "products".id) AS count_products_id FROM "products" INNER JOIN "seasons" ON "products".id = "seasons".product_id WHERE (("seasons".user_id = 1)) Season Load (1.8ms) SELECT "seasons".* FROM "seasons" INNER JOIN "products" ON "products".id = "seasons".product_id WHERE ("seasons".user_id = 1) AND ("seasons".user_id = 1) ORDER BY products.name Product Load (0.7ms) SELECT * FROM "products" WHERE ("products"."id" = 43) ORDER BY products.name CACHE (0.0ms) SELECT "seasons".* FROM "seasons" INNER JOIN "products" ON "products".id = "seasons".product_id WHERE ("seasons".user_id = 1) AND ("seasons".user_id = 1) ORDER BY products.name Product Load (0.4ms) SELECT * FROM "products" WHERE ("products"."id" = 1) ORDER BY products.name Variety Load (0.4ms) SELECT * FROM "varieties" WHERE ("varieties"."id" = 2) ORDER BY name CACHE (0.0ms) SELECT * FROM "products" WHERE ("products"."id" = 1) ORDER BY products.name Variety Load (0.4ms) SELECT * FROM "varieties" WHERE ("varieties"."id" = 8) ORDER BY name CACHE (0.0ms) SELECT * FROM "products" WHERE ("products"."id" = 1) ORDER BY products.name Variety Load (0.4ms) SELECT * FROM "varieties" WHERE ("varieties"."id" = 7) ORDER BY name CACHE (0.0ms) SELECT * FROM "products" WHERE ("products"."id" = 43) ORDER BY products.name CACHE (0.0ms) SELECT count(DISTINCT "products".id) AS count_products_id FROM "products" INNER JOIN "seasons" ON "products".id = "seasons".product_id WHERE (("seasons".user_id = 1)) CACHE (0.0ms) SELECT "seasons".* FROM "seasons" INNER JOIN "products" ON "products".id = "seasons".product_id WHERE ("seasons".user_id = 1) AND ("seasons".user_id = 1) ORDER BY products.name CACHE (0.0ms) SELECT * FROM "products" WHERE ("products"."id" = 1) ORDER BY products.name CACHE (0.0ms) SELECT * FROM "products" WHERE ("products"."id" = 1) ORDER BY products.name CACHE (0.0ms) SELECT * FROM "varieties" WHERE ("varieties"."id" = 8) ORDER BY name I'm having two problems: (1) The :uniq option is not working for products. Three distinct versions of the same product are displaying on the page. (2) The :uniq option is not working for varieties. I don't have validation set up on this yet, and if the user enters the same variety twice, it does appear on the page. In the previous working version, this was not the case. The result I need is that only one product for any given ID displays, and all varieties associated with that ID display along with such unique product. One thing that sticks out to me is the sql call in the most recent log output. It's adding 'count' to the distinct call. I'm not sure why it's doing that or whether it might be an indication of an issue. I found this unresolved lighthouse ticket that seems like it could potentially be related, but I'm not sure if it's the same issue: https://rails.lighthouseapp.com/projects/8994/tickets/2189-count-breaks-sqlite-has_many-through-association-collection-with-named-scope I've tried a million variations on this and can't get it working. Any help is much appreciated!

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  • MySQL - optimising selection across two linked tables

    - by user293594
    I have two MySQL tables, states and trans: states (200,000 entries) looks like: id (INT) - also the primary key energy (DOUBLE) [other stuff] trans (14,000,000 entries) looks like: i (INT) - a foreign key referencing states.id j (INT) - a foreign key referencing states.id A (DOUBLE) I'd like to search for all entries in trans with trans.A 30. (say), and then return the energy entries from the (unique) states referenced by each matching entry. So I do it with two intermediate tables: CREATE TABLE ij SELECT i,j FROM trans WHERE A30.; CREATE TABLE temp SELECT DISTINCT i FROM ij UNION SELECT DISTINCT j FROM ij; SELECT energy from states,temp WHERE id=temp.i; This seems to work, but is there any way to do it without the intermediate tables? When I tried to create the temp table with a single command straight from trans: CREATE TABLE temp SELECT DISTINCT i FROM trans WHERE A30. UNION SELECT DISTINCT j FROM trans WHERE A30.; it took a longer (presumably because it had to search the large trans table twice. I'm new to MySQL and I can't seem to find an equivalent problem and answer out there on the interwebs. Many thanks, Christian

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  • SUBSONIC 3.0.0.3 Subsonic.Query.SqlQuery

    - by dancingn27
    New to subsonic and having issues figuring it out. I am simply just trying to do a distinct search and any documentation I find is telling me to use the class/method SubSonic.SqlQuery Though I am finding out that since I am using the newest version, a lot of the documentation I am finding does not apply. For example, I am getting this query working beautifully using Subsonic.Query.SqlQuery though there is NO distinct method hanging off of it as suggested by what I have seen. Please advice! SubSonic.Query.SqlQuery query = brickDB.SelectColumns(new string[] { "DomainName" }).From<Web.Data.DB.WebLog>() .Where(Web.Data.DB.WebLogTable.DomainNameColumn).IsNotNull(); -> No distinct hanging off of From<>()....

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  • I DISTINCTly hate MySQL (help building a query)

    - by Alex Mcp
    This is staight forward I believe: I have a table with 30,000 rows. When I SELECT DISTINCT 'location' FROM myTable it returns 21,000 rows, about what I'd expect, but it only returns that one column. What I want is to move those to a new table, but the whole row for each match. My best guess is something like SELECT * from (SELECT DISTINCT 'location' FROM myTable) or something like that, but it says I have a vague syntax error. Is there a good way to grab the rest of each DISTINCT row and move it to a new table all in one go?

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