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  • SQL timetable for employee

    - by latinunit-net
    Hi guys, i need to create an employee shift database. so i have 3 tables so far, employee, employee_shift, and shift im suppose to calculate how many shifts an employee has done at the end of the month, my question means, because a month has 30 days some have 28 and 31 days. this means i need to create in the shift table 31 different variations? one for each day of the month? in order to calculate which employee has worked the most? in my business relation it says an employee has either 1 or 2 shifts per day therefore do i have to have 60 different rows of variations? im i right or is there an easy way to work it out

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  • Oracle HRMS API – Update Employee State Tax Rule

    - by PRajkumar
    API --  pay_state_tax_rule_api.update_state_tax_rule Example --   DECLARE      lc_dt_ud_mode                       VARCHAR2(100)   := NULL;      ln_assignment_id                  NUMBER                  := 33561;      ln_object_version_number  NUMBER                  := 1;      ld_effective_start_date          DATE;      ld_effective_end_date            DATE;      lb_correction                            BOOLEAN;      lb_update                                  BOOLEAN;      lb_update_override                BOOLEAN;      lb_update_change_insert    BOOLEAN; BEGIN     -- Find Date Track Mode     -- --------------------------------      dt_api.find_dt_upd_modes      (   p_effective_date                 => TO_DATE('12-JUN-2011'),          p_base_table_name          => 'PER_ALL_ASSIGNMENTS_F',          p_base_key_column         => 'ASSIGNMENT_ID',          p_base_key_value             => ln_assignment_id,          -- Output data elements          -- --------------------------------         p_correction                          => lb_correction,         p_update                                => lb_update,         p_update_override              => lb_update_override,         p_update_change_insert   => lb_update_change_insert     );        IF ( lb_update_override = TRUE OR lb_update_change_insert = TRUE )    THEN       -- UPDATE_OVERRIDE       -- --------------------------------       lc_dt_ud_mode := 'UPDATE_OVERRIDE';    END IF;      IF ( lb_correction = TRUE )    THEN       -- CORRECTION       -- ----------------------      lc_dt_ud_mode := 'CORRECTION';    END IF;      IF ( lb_update = TRUE )    THEN        -- UPDATE        -- --------------        lc_dt_ud_mode := 'UPDATE';    END IF;      -- Update State Tax Rule    -- ---------------------------------     pay_state_tax_rule_api.update_state_tax_rule     (     -- Input data elements           -- ------------------------------           p_effective_date                        => TO_DATE('20-JUN-2011'),           p_datetrack_update_mode   => lc_dt_ud_mode,           p_emp_state_tax_rule_id      => 8455,           p_withholding_allowances  => 100,           p_sit_additional_tax               => 10,           p_sit_exempt                              => 'N',           -- Output data elements           -- --------------------------------           p_object_version_number      => ln_object_version_number,           p_effective_start_date              => ld_effective_start_date,           p_effective_end_date               => ld_effective_end_date      );  COMMIT; EXCEPTION        WHEN OTHERS THEN                        ROLLBACK;                        dbms_output.put_line(SQLERRM); END; / SHOW ERR;  

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  • Be a better programmer or an irreplacable employee?

    - by mahen23
    Before I worked for a web development company, I asked a lot of questions of friends who were working as developers for tips about being good at your job. One answer I got was: "Always make the employers beg for your competencies. Prove to them that you are the best and you cannot be replaced. While keeping the status quo, hold your employers hostage where if one day they remove your from the job or task, no one else will be able to do your job." How true is this statement?

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  • Box2D relations

    - by Valentino Ru
    As far as I know, the unit in Box2D is meters. When I use Box2D in Processing with JBox2D, I set the "world size" as the window size specified in the setup(). Now I'm wondering if there is any function that scales down the world. For example, how can I simulate the throw of tennis ball within a room, without using a window of only 5 x 5 pixels? Additionally, is there any good documentation like the Java API?

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  • Resolving equivalence relations

    - by Luca Cerone
    I am writing a function to label the connected component in an image (I know there are several libraries outside, I just wanted to play with the algorithm). To do this I label the connected regions with different labels and create an equivalence table that contain information on the labels belonging to the same connected component. As an example if my equivalence table (vector of vector) looks something like: 1: 1,3 2: 2,3 3: 1,2,3 4: 4 It means that in the image there are 2 different regions, one made of elements that are labelled 1,2,3 and an other made of elements labelled 4. What is an easy and efficient way to resolve the equivalences and end up with something that looks like: 1: 1,2,3 2: 4 that I can use to "merge" the different connected regions belonging to the same connected component? Thanks a lot for the help!

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  • Copy a Doctrine object with all relations

    - by elManolo
    I want to copy a record with all his relations. I'm trying with: $o = Doctrine::getTable('Table')->Find(x); $copy = $object->copy(); $relations = $o->getRelations(); foreach ($relations as $name => $relation) { $copy->$relation = $object->$relation->copy(); } $copy->save(); This code doesn't works, but I think it's on the way.

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  • How to test if a doctrine records has any relations that are used

    - by murze
    Hi, I'm using a doctrine table that has several optional relations (of types Doctrine_Relation_Association and Doctrine_Relation_ForeignKey) with other tables. How can I test if a record from that table has connections with records from the related table. Here is an example to make my question more clear. Assume that you have a User and a user has a many to many relation with Usergroups and a User can have one Userrole How can I test if a give user is part of any Usergroups or has a role. The solution starts I believe with $relations = Doctrine_Core::getTable('User')->getRelations(); $user = Doctrine_Core::getTable('User')->findOne(1); foreach($relations as $relation) { //here should go a test if the user has a related record for this relation if ($relation instanceof Doctrine_Relation_Association) { //here the related table probably has more then one foreign key (ex. user_id and group_id) } if ($relation instanceof Doctrine_Relation_ForeignKey) { //here the related table probably has the primary key of this table (id) as a foreign key (user_id) } } //true or false echo $result I'm looking for a general solution that will work no matter how many relations there are between user and other tables. Thanks!

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  • Do i need a full time seo employee? [closed]

    - by user481913
    I need seo done for 1 site that's still new. It's a niche listings/ecommerce site. And i need to make a hiring decision for this - whether there's a need for a full time employee dedicated to seo or is part time or a contract sufficient? Here's some info and assumptions : 1)The site's dynamic - so perhaps all ON PAGE SEO - keyword research, page title, meta tags etc. could be built in programatically and is perhaps ONE TIME EFFORT. 2)Most(perhaps not all) ON PAGE SEO is taken care at the start or initially so doesn't need much time devotion later. 3)Most ON PAGE SEO for a DYNAMIC site is a programmer's job(as probably a seo employee doesn't understand programming) with some assistance from a seo employee for KEYWORD RESEARCH etc. So once built into the software, it DOESN'T NEED much effort on part of the seo employee in the later stages. 4)OFF PAGE SEO IS really where the seo employee would really spend most of his/her time - like build some links, write articles/blogs, directory submissions etc. So considering that there's just 1 site and that most effort for the seo employee is concenterated on OFF PAGE SEO, do i really need to hire someone Full Time? You're most welcome to add your own views and perspectives to this. It might help someone else as well in the future in their hiring decision.

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  • Memory error, access violation.

    - by Ordo
    Hello! I'm learning C on my own and as a exercise i have written a program but it does not work. The program is splitted into 3 parts. A header file, a main file for executing the program a file to define the functions. I'm not using all the functions yet but that shouldn't be the problem. Here is my header file, nothing special in it. #ifndef EMPLOYEE_H #define EMPLOYEE_H struct Employee { char first[21]; char last[21]; char title[21]; int salary; }; struct Employee* createEmployee(char*, char*, char*, int); // Creates a struct Employee object on the heap. char* getfirstname (struct Employee*); char* getlastname (struct Employee*); char* gettitle (struct Employee*); int getsalary (struct Employee*); void setfirstname (struct Employee*, char*); void setlastname (struct Employee*, char*); void settitle (struct Employee*, char*); void setsalary (struct Employee*, int); void printEmployee(struct Employee*); #endif In this file i define the functions and how they work: #include "7.1.h" #include <stdio.h> #include <stdlib.h> #include <string.h> struct Employee* createEmployee(char* first, char* last, char* title, int salary) // Creates a struct Employee object on the heap. { struct Employee* p = (struct Employee*) malloc(sizeof(struct Employee)); if (p != NULL) { strcpy(p->first, first); strcpy(p->last, last); strcpy(p->title, title); p->salary, salary; } return p; } char* getfirstname (struct Employee* p) { if (p != NULL) return p ? p->first : ""; } char* getlastname (struct Employee* p) { if (p != NULL) return p ? p->last : ""; } char* gettitle (struct Employee* p) { if (p != NULL) return p ? p->title : ""; } int getsalary (struct Employee* p) { if (p != NULL) return p ? p->salary : 0; } void setfirstname (struct Employee* p, char* first) { if (p != NULL) strcpy(p->first, first); } void setlastname (struct Employee* p, char* last) { if (p != NULL) strcpy(p->last, last); } void settitle (struct Employee* p, char* title) { if (p != NULL) strcpy(p->title, title); } void setsalary (struct Employee* p, char* salary) { if (p != NULL) p->salary, salary; } void printEmployee(struct Employee* p) { if (p != NULL) { printf("%s, %s, %s, %d", p->first, p->last, p->salary, p->salary ); } } And the last file is used to executed the program/functions: #include "7.1.h" #include <stdio.h> #include <stdlib.h> int main () { char decision; struct Employee emp; struct Employee* emps[3]; for ( int i = 0; i < 1; i ++) { printf("Please type in the emplooyes data.\nFirstname:"); scanf("%s", emp.first); printf("Lastname:"); scanf("%s", emp.last); printf("Title:"); scanf("%s", emp.title); printf("Salary:"); scanf("%d", &emp.salary); emps[i] = createEmployee(emp.first, emp.last, emp.title, emp.salary); } printf("Do you want to print out your information? (Y/N):"); scanf("%c", &decision); if (decision == 'y' || decision == 'Y') { printEmployee(emps[1]); } } I don't know what the problem is. I 'm always getting the following error message after typing in first, last, title and salary for the first time. The error is written in german. It means: Unhandled exception at 0x102de42e (msvcr100d.dll) in 7.1.exe: 0xC0000005: Access violation when writing to 0xCCCCCCCC position. I could fix the first problem with the hints given below. Now when i want to print out the employee data using the function:printEmployee(emps[1]);, I get the same kind of error with access violation.

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  • Ruby. Mongoid. Relations

    - by Scepion1d
    I've encountered some problems with MongoID. I have three models: require 'mongoid' class Configuration include Mongoid::Document belongs_to :user field :links, :type => Array field :root, :type => String field :objects, :type => Array field :categories, :type => Array has_many :entries end class TimeDim include Mongoid::Document field :day, :type => Integer field :month, :type => Integer field :year, :type => Integer field :day_of_week, :type => Integer field :minute, :type => Integer field :hour, :type => Integer has_many :entries end class Entry include Mongoid::Document belongs_to :configuration belongs_to :time_dim field :category, :type => String # any other dynamic fields end Creating documents for Configurations and TimeDims is successful. But when i've trying to execute following code: params = Hash.new params[:configuration] = config # an instance of Configuration from DB entry.each do |key, value| params[key.to_sym] = value # String end unless Entry.exists?(conditions: params) params[:time_dim] = self.generate_time_dim # an instance of TimeDim from DB params[:category] = self.detect_category(descr) # String Entry.new(params).save end ... i saw following output: /home/scepion1d/Workspace/RubyMine/dana-x/.bundle/ruby/1.9.1/gems/bson-1.6.1/lib/bson/bson_c.rb:24:in `serialize': Cannot serialize an object of class Configuration into BSON. (BSON::InvalidDocument) from /home/scepion1d/Workspace/RubyMine/dana-x/.bundle/ruby/1.9.1/gems/bson-1.6.1/lib/bson/bson_c.rb:24:in `serialize' from /home/scepion1d/Workspace/RubyMine/dana-x/.bundle/ruby/1.9.1/gems/mongo-1.6.1/lib/mongo/cursor.rb:604:in `construct_query_message' from /home/scepion1d/Workspace/RubyMine/dana-x/.bundle/ruby/1.9.1/gems/mongo-1.6.1/lib/mongo/cursor.rb:465:in `send_initial_query' from /home/scepion1d/Workspace/RubyMine/dana-x/.bundle/ruby/1.9.1/gems/mongo-1.6.1/lib/mongo/cursor.rb:458:in `refresh' from /home/scepion1d/Workspace/RubyMine/dana-x/.bundle/ruby/1.9.1/gems/mongo-1.6.1/lib/mongo/cursor.rb:128:in `next' from /home/scepion1d/Workspace/RubyMine/dana-x/.bundle/ruby/1.9.1/gems/mongo-1.6.1/lib/mongo/db.rb:509:in `command' from /home/scepion1d/Workspace/RubyMine/dana-x/.bundle/ruby/1.9.1/gems/mongo-1.6.1/lib/mongo/cursor.rb:191:in `count' from /home/scepion1d/Workspace/RubyMine/dana-x/.bundle/ruby/1.9.1/gems/mongoid-2.4.6/lib/mongoid/cursor.rb:42:in `block in count' from /home/scepion1d/Workspace/RubyMine/dana-x/.bundle/ruby/1.9.1/gems/mongoid-2.4.6/lib/mongoid/collections/retry.rb:29:in `retry_on_connection_failure' from /home/scepion1d/Workspace/RubyMine/dana-x/.bundle/ruby/1.9.1/gems/mongoid-2.4.6/lib/mongoid/cursor.rb:41:in `count' from /home/scepion1d/Workspace/RubyMine/dana-x/.bundle/ruby/1.9.1/gems/mongoid-2.4.6/lib/mongoid/contexts/mongo.rb:93:in `count' from /home/scepion1d/Workspace/RubyMine/dana-x/.bundle/ruby/1.9.1/gems/mongoid-2.4.6/lib/mongoid/criteria.rb:45:in `count' from /home/scepion1d/Workspace/RubyMine/dana-x/.bundle/ruby/1.9.1/gems/mongoid-2.4.6/lib/mongoid/finders.rb:60:in `exists?' from /home/scepion1d/Workspace/RubyMine/dana-x/crawler/crawler.rb:110:in `block (2 levels) in push_entries_to_db' from /home/scepion1d/Workspace/RubyMine/dana-x/crawler/crawler.rb:103:in `each' from /home/scepion1d/Workspace/RubyMine/dana-x/crawler/crawler.rb:103:in `block in push_entries_to_db' from /home/scepion1d/Workspace/RubyMine/dana-x/crawler/crawler.rb:102:in `each' from /home/scepion1d/Workspace/RubyMine/dana-x/crawler/crawler.rb:102:in `push_entries_to_db' from main_starter.rb:15:in `<main>' Can anyone tell what am I doing wrong?

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  • Employee Monitoring software

    - by nute
    I am looking for an employee monitoring solution, that would allow us to remotely connect to our computers to see what is happening live, and preferably having some recording capabilities such as snapshots, URLs visited, etc ... I've looked around the web and most softwares I found were from unknown companies, had crappy websites, and made me feel like their either wanted me to install a virus on my computer, or to scam me. Most also seemed to have planted "reviews" online most likely written by themselves. Basically, anyone has experience with a trustworthy company to accomplish that? Thanks

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  • Employee Monitoring software

    - by nute
    I am looking for an employee monitoring solution, that would allow us to remotely connect to our computers to see what is happening live, and preferably having some recording capabilities such as snapshots, URLs visited, etc ... I've looked around the web and most softwares I found were from unknown companies, had crappy websites, and made me feel like their either wanted me to install a virus on my computer, or to scam me. Most also seemed to have planted "reviews" online most likely written by themselves. Basically, anyone has experience with a trustworthy company to accomplish that? Thanks

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  • Employee Scheduling

    - by stephane
    Hi, I need a software or simply an excel worksheet to schedule my employees. I have 16 lifeguards and 9 headguards, two of which act as coordinators one day a week. All employees cannot work more than 40 hours a week because of the provincial law. Furthermore, they must staff 6 beaches. Everybeach has different staffing needs. Furthermore, I would like the application to be able to to take into considerations all employees needs such as vacation days and prefered beaches. Finally I would like to create a staff rotation between beaches to encourage employee motivation. Is there an open source application for my needs available out there ?

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  • dataset - set parent child relations

    - by Night Walker
    Hello all I am trying to set the relations of rows in DataSet and then to show that relation in XTraaTreeList as tree with relations. | --| ----| but i get | | | I am doing this code but i get a view without any relations i get them all in one level. Any idea what i am doing wrong ? this.treeList1.BeginUpdate(); this.dataTable1.Clear(); DataRow dr = this.dataTable1.NewRow(); dr[0] = "father"; dr[1] = true; dr[2] = "ddd"; this.dataTable1.Rows.Add(dr); DataRow dr1 = this.dataTable1.NewRow(); dr1[0] = "son"; dr1[1] = true; dr1[2] = "ddd"; dr1.SetParentRow(dr); this.dataTable1.Rows.Add(dr1); DataRow dr2 = this.dataTable1.NewRow(); this.dataTable1.ParentRelations() dr2[0] = "grand son"; dr2[1] = true; dr2[2] = "ddd"; dr2.SetParentRow(dr1); this.dataTable1.Rows.Add(dr2); this.treeList1.EndUpdate();

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  • Oracle Query for getting CURRENT CTC (Salary) of Each Employee

    - by reply2viveksshah
    i want current CTC of each employee following is the design of my table Ecode Implemented Date Salary 7654323 2010-05-20 350000 7654322 2010-05-17 250000 7654321 2003-04-01 350000 7654321 2004-04-01 450000 7654321 2005-04-01 750000 7654321 2007-04-01 650000 i want oracle query for following output Ecode Salary 7654321 650000 7654322 250000 7654323 350000 thanks in advance See also Oracle Query for getting MAximum CTC (Salary) of Each Employee

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  • Little (Employee - Shift) SQL Database help

    - by latinunit-net
    Hi Guys, Im creating a little database that has employee, emp_shift, shift, tables now im suppose to be able to calculate at the end of the month which employee has done the most number of shifts. Ive created the SQL creation, insert statements for the tables, and a little diagram to explain what im trying to acomplish, im a beginner and this is a homework ive been trying to do for the last 4 days. Diagram: http://latinunit.net/emp_shift.jpg SQL: latinunit.net/emp_shift.txt can you please guys check it, deadline is 2 days and this is just a part of the whole database

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  • Symfony: embedRelation() controlling options for nesting multiple levels of relations

    - by wulftone
    Hey all, I'm trying to set some conditional statements for nested embedRelation() instances, and can't find a way to get any kind of option through to the second embedRelation. I've got a "Measure-Page-Question" table relationship, and I'd like to be able to choose whether or not to display the Question table. For example, say I have two "success" pages, page1Success.php and page2Success.php. On page1, I'd like to display "Measure-Page-Question", and on page2, I'd like to display "Measure-Page", but I need a way to pass an "option" to the PageForm.class.php file to make that kind of decision. My actions.class.php file has something like this: // actions.class.php $this-form = new measureForm($measure, array('option'=$option)); to pass an option to the "Page", but passing that option through "Page" into "Question" doesn't work. My measureForm.class.php file has an embedRelation in it that is dependent on the "option": // measureForm.class.php if ($this-getOption('option') == "page_1") { $this-embedRelation('Page'); } and this is what i'd like to do in my pageForm.class.php file: // pageForm.class.php if ($this-getOption('option') == "page_1") { // Or != "page_2", or whatever $this-embedRelation('Question'); } I can't seem to find a way to do this. Any ideas? Is there a preferred Symfony way of doing this type of operation, perhaps without embedRelation? Thanks, -Trevor As requested, here's my schema.yml: # schema.yml Measure: connection: doctrine tableName: measure columns: _kp_mid: type: integer(4) fixed: false unsigned: false primary: true autoincrement: true description: type: string() fixed: false unsigned: false primary: false notnull: false autoincrement: false frequency: type: integer(4) fixed: false unsigned: false primary: false notnull: false autoincrement: false relations: Page: local: _kp_mid foreign: _kf_mid type: many Page: connection: doctrine tableName: page columns: _kp_pid: type: integer(4) fixed: false unsigned: false primary: true autoincrement: true _kf_mid: type: integer(4) fixed: false unsigned: false primary: false notnull: false autoincrement: false next: type: string() fixed: false unsigned: false primary: false notnull: false autoincrement: false number: type: string() fixed: false unsigned: false primary: false notnull: false autoincrement: false previous: type: string() fixed: false unsigned: false primary: false notnull: false autoincrement: false relations: Measure: local: _kf_mid foreign: _kp_mid type: one Question: local: _kp_pid foreign: _kf_pid type: many Question: connection: doctrine tableName: question columns: _kp_qid: type: integer(4) fixed: false unsigned: false primary: true autoincrement: true _kf_pid: type: integer(4) fixed: false unsigned: false primary: false notnull: false autoincrement: false text: type: string() fixed: false unsigned: false primary: false notnull: false autoincrement: false type: type: integer(4) fixed: false unsigned: false primary: false notnull: false autoincrement: false relations: Page: local: _kf_pid foreign: _kp_pid type: one

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  • Finding recurrence relations of an algorithm

    - by Roarke
    I'm reading my algorithms text book, and I'm reading about recurrence relations and finding the algorithms big O complexity. I run across this line "In the case of the merge-sort algorithm, we get the recurrence equation: t(n) = b if n < 2 = 2t(n/2) +bn if n >= 2 for b > 0 my response was "how the heck did we know that?!?!" So i'm wondering if there is a systematic approach, or just a logical way of getting these recurrence relations from the algorithms can some one explain where the b and the two 2's come from?

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  • How to convert an ORM to its subclass using Hibernate ?

    - by Gaaston
    Hi everybody, For example, I have two classes : Person and Employee (Employee is a subclass of Person). Person : has a lastname and a firstname. Employee : has also a salary. On the client-side, I have a single HTML form where i can fill the person informations (like lastname and firstname). I also have a "switch" between "Person" and "Employee", and if the switch is on Employee I can fill the salary field. On the server-side, Servlets receive informations from the client and use the Hibernate framework to create/update data to/from the database. The mapping i'm using is a single table for persons and employee, with a discriminator. I don't know how to convert a Person in an Employee. I firstly tried to : load the Person p from the database create an empty Employee e object copy values from p into e set the salary value save e into the database But i couldn't, as I also copy the ID, and so Hibernate told me they where two instanciated ORM with the same id. And I can't cast a Person into an Employee directly, as Person is Employee's superclass. There seems to be a dirty way : delete the person, and create an employee with the same informations, but I don't really like it.. So I'd appreciate any help on that :) Some precisions : The person class : public class Person { protected int id; protected String firstName; protected String lastName; // usual getters and setters } The employee class : public class Employee extends Person { // string for now protected String salary; // usual getters and setters } And in the servlet : // type is the "switch" if(request.getParameter("type").equals("Employee")) { Employee employee = daoPerson.getEmployee(Integer.valueOf(request.getParameter("ID"))); modifyPerson(employee, request); employee.setSalary(request.getParameter("salary")); daoPerson.save(employee ); } else { Person person = daoPerson.getPerson(Integer.valueOf(request.getParameter("ID"))); modifyPerson(employee, request); daoPerson.save(person); } And finally, the loading (in the dao) : public Contact getPerson(int ID){ Session session = HibernateSessionFactory.getSession(); Person p = (Person) session.load(Person.class, new Integer(ID)); return p; } public Contact getEmployee(int ID){ Session session = HibernateSessionFactory.getSession(); Employee = (Employee) session.load(Employee.class, new Integer(ID)); return p; } With this, i'm getting a ClassCastException when trying to load a Person using getEmployee. XML Hibernate mapping : <class name="domain.Person" table="PERSON" discriminator-value="P"> <id name="id" type="int"> <column name="ID" /> <generator class="native" /> </id> <discriminator column="type" type="character"/> <property name="firstName" type="java.lang.String"> <column name="FIRSTNAME" /> </property> <property name="lastName" type="java.lang.String"> <column name="LASTNAME" /> </property> <subclass name="domain.Employee" discriminator-value="E"> <property name="salary" column="SALARY" type="java.lang.String" /> </subclass> </class> Is it clear enough ? :-/

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  • Drupal: create a node with employee working hours

    - by JMarshall
    I have a bit complicated task. 1. I need to create a node with employee working hours (it's gonna be created for all users with role "employee"), which looks like this: Monday: From __ : __ To __ : __ Tuesday: From __ : __ To __ : __ Wednesday: From __ : __ To __ : __ etc. So, I'll have to create probably 14 CCK fields (monday_from, monday_to, tuesday_from...) or more to store the day of the week and workging hours (hours and minutes). 2. I need to add a view with exposed filters, where visitors can filter employees by day of the week and working hours. What kind of field should I use for working hours? How could views filtering described above be achieved? Any suggestions are greatly appreciated. Thank you!

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  • Almost at our first year anniversary!

    - by Vizioz Limited
    It has been a hectic first year at Vizioz and things are still going from strength to strength. 11 months ago I started Vizioz with zero capital investment in the middle of a recession, which to some may seem a daunting prospect but to others including myself it was the challenge I needed to make me want to get up in the morning :) I wanted to prove that even in the curent financial climate it is still possible to start a new business.We are still experiencing the normal growing pains of a small business but this is something we just need to work our way through, it is amazing how much paperwork and administration there is running a small business, office admin, insurance, vat and for the last few months PAYE.For the last 9 months we have shared an office with another small business called Little Big Ideas. They are a design agency working across a broad spectrum of design from branding, print and digital. Last month we decided to move offices to a larger office and now have room for 8 of us, so now we need a couple more clients to help produce enough work to fill the space and grow to the next level.As well as moving office 2 months ago I blogged about my first employee Colin starting work for me, he has picked up Umbraco very well and has mastered the art of good CSS design, as the majority of our clients are large multi-nationals they still require support for IE6 which as all web developers know is the nightmare of all web browsers.This month has seen the next step in the growth of Vizioz as I have taken on another PhD graduate called Pricilla, welcome to the team!This month we plan to launch our own website to enable us to showcase some of the sites we have built over the past 11 months and to allow potential clients to see what we can offer. We might still be relatively small but we have some great case studies to show and with two PhD graduates on the team we have great talent capable of producing complex and innovative solutions for our clients. As soon as we have launched out new website I will blog again about what the future holds for Vizioz and what we can offer our prospective clients as well as e obvious Umbraco CMS solutions.

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  • I need help on my C++ assignment using MS Visual C++

    - by krayzwytie
    Ok, so I don't want you to do my homework for me, but I'm a little lost with this final assignment and need all the help I can get. Learning about programming is tough enough, but doing it online is next to impossible for me... Now, to get to the program, I am going to paste what I have so far. This includes mostly //comments and what I have written so far. If you can help me figure out where all the errors are and how to complete the assignment, I will really appreciate it. Like I said, I don't want you to do my homework for me (it's my final), but any constructive criticism is welcome. This is my final assignment for this class and it is due tomorrow (Sunday before midnight, Arizona time). This is the assignment: Examine the following situation: o Your company, Datamax, Inc., is in the process of automating its payroll systems. Your manager has asked you to create a program that calculates overtime pay for all employees. Your program must take into account the employee’s salary, total hours worked, and hours worked more than 40 in a week, and then provide an output that is useful and easily understood by company management. • Compile your program utilizing the following background information and the code outline in Appendix D (included in the code section). • Submit your project as an attachment including the code and the output. Company Background: o Three employees: Mark, John, and Mary o The end user needs to be prompted for three specific pieces of input—name, hours worked, and hourly wage. o Calculate overtime if input is greater than 40 hours per week. o Provide six test plans to verify the logic within the program. o Plan 1 must display the proper information for employee #1 with overtime pay. o Plan 2 must display the proper information for employee #1 with no overtime pay. o Plans 3-6 are duplicates of plan 1 and 2 but for the other employees. Program Requirements: o Define a base class to use for the entire program. o The class holds the function calls and the variables related to the overtime pay calculations. o Define one object per employee. Note there will be three employees. o Your program must take the objects created and implement calculations based on total salaries, total hours, and the total number of overtime hours. See the Employee Summary Data section of the sample output. Logic Steps to Complete Your Program: o Define your base class. o Define your objects from your base class. o Prompt for user input, updating your object classes for all three users. o Implement your overtime pay calculations. o Display overtime or regular time pay calculations. See the sample output below. o Implement object calculations by summarizing your employee objects and display the summary information in the example below. And this is the code: // Final_Project.cpp : Defines the entry point for the console application. // #include "stdafx.h" #include <iostream> #include <string> #include <iomanip> using namespace std; // //CLASS DECLARATION SECTION // class CEmployee { public: void ImplementCalculations(string EmployeeName, double hours, double wage); void DisplayEmployInformation(void); void Addsomethingup (CEmployee, CEmployee, CEmployee); string EmployeeName ; int hours ; int overtime_hours ; int iTotal_hours ; int iTotal_OvertimeHours ; float wage ; float basepay ; float overtime_pay ; float overtime_extra ; float iTotal_salaries ; float iIndividualSalary ; }; int main() { system("cls"); cout << "Welcome to the Employee Pay Center"; /* Use this section to define your objects. You will have one object per employee. You have only three employees. The format is your class name and your object name. */ std::cout << "Please enter Employee's Name: "; std::cin >> EmployeeName; std::cout << "Please enter Total Hours for (EmployeeName): "; std::cin >> hours; std::cout << "Please enter Base Pay for(EmployeeName): "; std::cin >> basepay; /* Here you will prompt for the first employee’s information. Prompt the employee name, hours worked, and the hourly wage. For each piece of information, you will update the appropriate class member defined above. Example of Prompts Enter the employee name = Enter the hours worked = Enter his or her hourly wage = */ /* Here you will prompt for the second employee’s information. Prompt the employee name, hours worked, and the hourly wage. For each piece of information, you will update the appropriate class member defined above. Enter the employee name = Enter the hours worked = Enter his or her hourly wage = */ /* Here you will prompt for the third employee’s information. Prompt the employee name, hours worked, and the hourly wage. For each piece of information, you will update the appropriate class member defined above. Enter the employee name = Enter the hours worked = Enter his or her hourly wage = */ /* Here you will implement a function call to implement the employ calcuations for each object defined above. You will do this for each of the three employees or objects. The format for this step is the following: [(object name.function name(objectname.name, objectname.hours, objectname.wage)] ; */ /* This section you will send all three objects to a function that will add up the the following information: - Total Employee Salaries - Total Employee Hours - Total Overtime Hours The format for this function is the following: - Define a new object. - Implement function call [objectname.functionname(object name 1, object name 2, object name 3)] /* } //End of Main Function void CEmployee::ImplementCalculations (string EmployeeName, double hours, double wage){ //Initialize overtime variables overtime_hours=0; overtime_pay=0; overtime_extra=0; if (hours > 40) { /* This section is for the basic calculations for calculating overtime pay. - base pay = 40 hours times the hourly wage - overtime hours = hours worked – 40 - overtime pay = hourly wage * 1.5 - overtime extra pay over 40 = overtime hours * overtime pay - salary = overtime money over 40 hours + your base pay */ /* Implement function call to output the employee information. Function is defined below. */ } // if (hours > 40) else { /* Here you are going to calculate the hours less than 40 hours. - Your base pay is = your hours worked times your wage - Salary = your base pay */ /* Implement function call to output the employee information. Function is defined below. */ } // End of the else } //End of Primary Function void CEmployee::DisplayEmployInformation(); { // This function displays all the employee output information. /* This is your cout statements to display the employee information: Employee Name ............. = Base Pay .................. = Hours in Overtime ......... = Overtime Pay Amount........ = Total Pay ................. = */ } // END OF Display Employee Information void CEmployee::Addsomethingup (CEmployee Employ1, CEmployee Employ2) { // Adds two objects of class Employee passed as // function arguments and saves them as the calling object's data member values. /* Add the total hours for objects 1, 2, and 3. Add the salaries for each object. Add the total overtime hours. */ /* Then display the information below. %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%% EMPLOYEE SUMMARY DATA%%%%%%%%%%%%%%%%%%%%%%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%% Total Employee Salaries ..... = 576.43 %%%% Total Employee Hours ........ = 108 %%%% Total Overtime Hours......... = 5 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% */ } // End of function

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  • Hibernate: order multiple one-to-many relations

    - by Markos Fragkakis
    I have a search screen, using JSF, JBoss Seam and Hibernate underneath. There are columns for A, B and C, where the relations are as follows: A (1< -- ) B (1< -- ) C A has a List< B and B has a List< C (both relations are one-to-many). The UI table supports ordering by any column (ASC or DESC), so I want the results of the query to be ordered. This is the reason I used Lists in the model. However, I got an exception that Hibernate cannot eagerly fetch multiple bags (it considers both lists to be bags). There is an interesting blog post here, and they identify the following solutions: Use @IndexColumn annotation (there is none in my DB, and what's more, I want the position of results to be determined by the ordering, not by an index column) Fetch lazily (for performance reasons, I need eager fetching) Change List to Set So, I changed the List to Set, which by the way is more correct, model-wise. First, if don't use @OrderBy, the PersistentSet returned by Hibernate wraps a HashSet, which has no ordering. Second, If I do use @OrderBy, the PersistentSet wraps a LinkedHashSet, which is what I would like, but the OrderBy property is hardcoded, so all other ordering I perform through the UI comes after it. I tried again with Sets, and used SortedSet (and its implementation, TreeSet), but I have some issues: I want ordering to take place in the DB, and not in-memory, which is what TreeSet does (either through a Comparator, or through the Comparable interface of the elements). Second, I found that there is the Hibernate annotation @Sort, which has a SortOrder.UNSORTED and you can also set a Comparator. I still haven't managed to make it compile, but I am still not convinced it is what I need. Any advice?

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