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  • opath syntax to force dynamic distribution group field as numerical comparison? (Exchange 2010)

    - by Matt
    I'm upgrading a (working) query based group (Exchange 2003) to a new and 'improved' dynamic distribution group (2010). For better or worse, our company decided to store everyone's employee ID in the pager field, so it's easy to manipulate via ADUC. That employee number has significance, as all employees are in a certain range, and all contractors are in a very different range. Basically, the new opath syntax appears to be using string compare on my pager field, even though it's a number. Let's say my employee ID is 3004, well, it's "less than" 4 from a string check POV. Set-DynamicDistributionGroup -Identity "my-funky-new-group" -RecipientFilter "(pager -lt 4) -and (pager -like '*') -and (RecipientType -eq 'UserMailbox')" Shows up in EMC with this: ((((((Pager -lt '4') -and (Pager -ne $null))) -and (RecipientType -eq 'UserMailbox'))) -and (-not(Name -like 'SystemMailbox{*')) -and (-not(Name -like 'CAS_{*')) -and (-not(RecipientTypeDetailsValue -eq 'MailboxPlan')) -and (-not(RecipientTypeDetailsValue -eq 'DiscoveryMailbox')) -and (-not(RecipientTypeDetailsValue -eq 'ArbitrationMailbox'))) This group should have max of 3 members right? Nope - I get a ton because of the string compare. I show up, and I'm in the 3000 range. Question: Anyone know a clever way to force this to be an integer check? The read-only LDAP filter on this group looks good, but of course it can't be edited. The LDAP representation (look ma, no quotes on the 4!) - Also interesting it sort of 'fills the' bed with the (pager=4) thing... (&(pager<=4)(!(pager=4))(pager=*)(objectClass=user)(objectCategory=person)(mailNickname=*)(msExchHomeServerName=*)(!(name=SystemMailbox{*))(!(name=CAS_{*))!(msExchRecipientTypeDetails=16777216))(!(msExchRecipientTypeDetails=536870912))(!(msExchRecipientTypeDetails=8388608))) If there is no solution, I suppose my recourse is either finding an unused field that actually will be treated as an integer, or most likely building this list with powershell every morning with my own automation - lame. I know of a few ways to fix this outside of the opath filter (designate "full-time" in another field, etc.), but would rather exchange do the lifting since this is the environment at the moment. Any insight would be great - thanks! Matt

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  • Open Source but not Free Software (or vice versa)

    - by TRiG
    The definition of "Free Software" from the Free Software Foundation: “Free software” is a matter of liberty, not price. To understand the concept, you should think of “free” as in “free speech,” not as in “free beer.” Free software is a matter of the users' freedom to run, copy, distribute, study, change and improve the software. More precisely, it means that the program's users have the four essential freedoms: The freedom to run the program, for any purpose (freedom 0). The freedom to study how the program works, and change it to make it do what you wish (freedom 1). Access to the source code is a precondition for this. The freedom to redistribute copies so you can help your neighbor (freedom 2). The freedom to distribute copies of your modified versions to others (freedom 3). By doing this you can give the whole community a chance to benefit from your changes. Access to the source code is a precondition for this. A program is free software if users have all of these freedoms. Thus, you should be free to redistribute copies, either with or without modifications, either gratis or charging a fee for distribution, to anyone anywhere. Being free to do these things means (among other things) that you do not have to ask or pay for permission to do so. The definition of "Open Source Software" from the Open Source Initiative: Open source doesn't just mean access to the source code. The distribution terms of open-source software must comply with the following criteria: Free Redistribution The license shall not restrict any party from selling or giving away the software as a component of an aggregate software distribution containing programs from several different sources. The license shall not require a royalty or other fee for such sale. Source Code The program must include source code, and must allow distribution in source code as well as compiled form. Where some form of a product is not distributed with source code, there must be a well-publicized means of obtaining the source code for no more than a reasonable reproduction cost preferably, downloading via the Internet without charge. The source code must be the preferred form in which a programmer would modify the program. Deliberately obfuscated source code is not allowed. Intermediate forms such as the output of a preprocessor or translator are not allowed. Derived Works The license must allow modifications and derived works, and must allow them to be distributed under the same terms as the license of the original software. Integrity of The Author's Source Code The license may restrict source-code from being distributed in modified form only if the license allows the distribution of "patch files" with the source code for the purpose of modifying the program at build time. The license must explicitly permit distribution of software built from modified source code. The license may require derived works to carry a different name or version number from the original software. No Discrimination Against Persons or Groups The license must not discriminate against any person or group of persons. No Discrimination Against Fields of Endeavor The license must not restrict anyone from making use of the program in a specific field of endeavor. For example, it may not restrict the program from being used in a business, or from being used for genetic research. Distribution of License The rights attached to the program must apply to all to whom the program is redistributed without the need for execution of an additional license by those parties. License Must Not Be Specific to a Product The rights attached to the program must not depend on the program's being part of a particular software distribution. If the program is extracted from that distribution and used or distributed within the terms of the program's license, all parties to whom the program is redistributed should have the same rights as those that are granted in conjunction with the original software distribution. License Must Not Restrict Other Software The license must not place restrictions on other software that is distributed along with the licensed software. For example, the license must not insist that all other programs distributed on the same medium must be open-source software. License Must Be Technology-Neutral No provision of the license may be predicated on any individual technology or style of interface. These definitions, although they derive from very different ideologies, are broadly compatible, and most Free Software is also Open Source Software and vice versa. I believe, however, that it is possible for this not to be the case: It is possible for software to be Open Source without being Free, or to be Free without being Open Source. Questions Is my belief correct? Is it possible for software to fall into one camp and not the other? Does any such software actually exist? Please give examples. Clarification I've already accepted an answer now, but I seem to have confused a lot of people, so perhaps a clarification is in order. I was not asking about the difference between copyleft (or "viral", though I don't like that term) and non-copyleft ("permissive") licenses. Nor was I asking about your personal idiosyncratic definitions of "Free" and "Open". I was asking about "Free Software as defined by the FSF" and "Open Source Software as defined by the OSI". Are the two always the same? Is it possible to be one without being the other? And the answer, it seems, is that it's impossible to be Free without being Open, but possible to be Open without being Free. Thank you everyone who actually answered the question.

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  • Remote Development With Solaris Studio

    - by rchrd
    A new technical article has been published on OTN: How to Develop Code from a Remote Desktop with Oracle Solaris Studio by Igor Nikiforov This article describes the remote desktop feature of the Oracle Solaris Studio IDE, and how to use it to compile, run, debug, and profile your code running on remote servers. Published May 2012 Introducing the IDE Desktop Distribution Determining Whether You Need the Desktop Distribution Creating the Desktop Distribution Using the Desktop Distribution See Also About the Author Introducing the IDE Desktop Distribution Sun Studio 12 Update 1 introduced a unique remote development feature that allows you to run just one instance of the IDE while working with multiple servers and platforms. For example, you could run the IDE on an x86-based laptop or desktop running Oracle Linux, and use a SPARC-based server running Oracle Solaris 10 to compile, run, debug, and profile your code. The IDE works seamlessly just as if you had the Oracle Solaris operating system on your laptop or desktop. ....read more

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  • Grails checkbox

    - by Tomáš
    Hi gurus I have trouble with binding Boolean property in association classes. Property is set to true if I check checkbox (good), but is null if checbox is not checked. I know the problem with HTML checkbox. I know why is send "_fieldName" in params, but this "_fieldName" dont set my boolean property to false. class Person{ String title List<Group> groups = new ArrayList() static hasMany = [groups: Groups] } class Group{ String title Boolean isHidden static belongTo = Person } class PersonController{ def form = { def person = new Person() person.groups.add( new Group() ) return ["person": person] } def handleForm = { def person = new Person( params ) println person.groups[0] } } If I check checkbox: [isHidden:on, title:a, _isHidden:] println person.groups[0] //true If I don check checkbox: [title:a, _isHidden:] println person.groups[0] //null Thank a lot for help Tom I am sorry, I searched this web, but did not get actual info for my trouble.

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  • LLBLGen Pro feature highlights: grouping model elements

    - by FransBouma
    (This post is part of a series of posts about features of the LLBLGen Pro system) When working with an entity model which has more than a few entities, it's often convenient to be able to group entities together if they belong to a semantic sub-model. For example, if your entity model has several entities which are about 'security', it would be practical to group them together under the 'security' moniker. This way, you could easily find them back, yet they can be left inside the complete entity model altogether so their relationships with entities outside the group are kept. In other situations your domain consists of semi-separate entity models which all target tables/views which are located in the same database. It then might be convenient to have a single project to manage the complete target database, yet have the entity models separate of each other and have them result in separate code bases. LLBLGen Pro can do both for you. This blog post will illustrate both situations. The feature is called group usage and is controllable through the project settings. This setting is supported on all supported O/R mapper frameworks. Situation one: grouping entities in a single model. This situation is common for entity models which are dense, so many relationships exist between all sub-models: you can't split them up easily into separate models (nor do you likely want to), however it's convenient to have them grouped together into groups inside the entity model at the project level. A typical example for this is the AdventureWorks example database for SQL Server. This database, which is a single catalog, has for each sub-group a schema, however most of these schemas are tightly connected with each other: adding all schemas together will give a model with entities which indirectly are related to all other entities. LLBLGen Pro's default setting for group usage is AsVisualGroupingMechanism which is what this situation is all about: we group the elements for visual purposes, it has no real meaning for the model nor the code generated. Let's reverse engineer AdventureWorks to an entity model. By default, LLBLGen Pro uses the target schema an element is in which is being reverse engineered, as the group it will be in. This is convenient if you already have categorized tables/views in schemas, like which is the case in AdventureWorks. Of course this can be switched off, or corrected on the fly. When reverse engineering, we'll walk through a wizard which will guide us with the selection of the elements which relational model data should be retrieved, which we can later on use to reverse engineer to an entity model. The first step after specifying which database server connect to is to select these elements. below we can see the AdventureWorks catalog as well as the different schemas it contains. We'll include all of them. After the wizard completes, we have all relational model data nicely in our catalog data, with schemas. So let's reverse engineer entities from the tables in these schemas. We select in the catalog explorer the schemas 'HumanResources', 'Person', 'Production', 'Purchasing' and 'Sales', then right-click one of them and from the context menu, we select Reverse engineer Tables to Entity Definitions.... This will bring up the dialog below. We check all checkboxes in one go by checking the checkbox at the top to mark them all to be added to the project. As you can see LLBLGen Pro has already filled in the group name based on the schema name, as this is the default and we didn't change the setting. If you want, you can select multiple rows at once and set the group name to something else using the controls on the dialog. We're fine with the group names chosen so we'll simply click Add to Project. This gives the following result:   (I collapsed the other groups to keep the picture small ;)). As you can see, the entities are now grouped. Just to see how dense this model is, I've expanded the relationships of Employee: As you can see, it has relationships with entities from three other groups than HumanResources. It's not doable to cut up this project into sub-models without duplicating the Employee entity in all those groups, so this model is better suited to be used as a single model resulting in a single code base, however it benefits greatly from having its entities grouped into separate groups at the project level, to make work done on the model easier. Now let's look at another situation, namely where we work with a single database while we want to have multiple models and for each model a separate code base. Situation two: grouping entities in separate models within the same project. To get rid of the entities to see the second situation in action, simply undo the reverse engineering action in the project. We still have the AdventureWorks relational model data in the catalog. To switch LLBLGen Pro to see each group in the project as a separate project, open the Project Settings, navigate to General and set Group usage to AsSeparateProjects. In the catalog explorer, select Person and Production, right-click them and select again Reverse engineer Tables to Entities.... Again check the checkbox at the top to mark all entities to be added and click Add to Project. We get two groups, as expected, however this time the groups are seen as separate projects. This means that the validation logic inside LLBLGen Pro will see it as an error if there's e.g. a relationship or an inheritance edge linking two groups together, as that would lead to a cyclic reference in the code bases. To see this variant of the grouping feature, seeing the groups as separate projects, in action, we'll generate code from the project with the two groups we just created: select from the main menu: Project -> Generate Source-code... (or press F7 ;)). In the dialog popping up, select the target .NET framework you want to use, the template preset, fill in a destination folder and click Start Generator (normal). This will start the code generator process. As expected the code generator has simply generated two code bases, one for Person and one for Production: The group name is used inside the namespace for the different elements. This allows you to add both code bases to a single solution and use them together in a different project without problems. Below is a snippet from the code file of a generated entity class. //... using System.Xml.Serialization; using AdventureWorks.Person; using AdventureWorks.Person.HelperClasses; using AdventureWorks.Person.FactoryClasses; using AdventureWorks.Person.RelationClasses; using SD.LLBLGen.Pro.ORMSupportClasses; namespace AdventureWorks.Person.EntityClasses { //... /// <summary>Entity class which represents the entity 'Address'.<br/><br/></summary> [Serializable] public partial class AddressEntity : CommonEntityBase //... The advantage of this is that you can have two code bases and work with them separately, yet have a single target database and maintain everything in a single location. If you decide to move to a single code base, you can do so with a change of one setting. It's also useful if you want to keep the groups as separate models (and code bases) yet want to add relationships to elements from another group using a copy of the entity: you can simply reverse engineer the target table to a new entity into a different group, effectively making a copy of the entity. As there's a single target database, changes made to that database are reflected in both models which makes maintenance easier than when you'd have a separate project for each group, with its own relational model data. Conclusion LLBLGen Pro offers a flexible way to work with entities in sub-models and control how the sub-models end up in the generated code.

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  • MapReduce in DryadLINQ and PLINQ

    - by JoshReuben
    MapReduce See http://en.wikipedia.org/wiki/Mapreduce The MapReduce pattern aims to handle large-scale computations across a cluster of servers, often involving massive amounts of data. "The computation takes a set of input key/value pairs, and produces a set of output key/value pairs. The developer expresses the computation as two Func delegates: Map and Reduce. Map - takes a single input pair and produces a set of intermediate key/value pairs. The MapReduce function groups results by key and passes them to the Reduce function. Reduce - accepts an intermediate key I and a set of values for that key. It merges together these values to form a possibly smaller set of values. Typically just zero or one output value is produced per Reduce invocation. The intermediate values are supplied to the user's Reduce function via an iterator." the canonical MapReduce example: counting word frequency in a text file.     MapReduce using DryadLINQ see http://research.microsoft.com/en-us/projects/dryadlinq/ and http://connect.microsoft.com/Dryad DryadLINQ provides a simple and straightforward way to implement MapReduce operations. This The implementation has two primary components: A Pair structure, which serves as a data container. A MapReduce method, which counts word frequency and returns the top five words. The Pair Structure - Pair has two properties: Word is a string that holds a word or key. Count is an int that holds the word count. The structure also overrides ToString to simplify printing the results. The following example shows the Pair implementation. public struct Pair { private string word; private int count; public Pair(string w, int c) { word = w; count = c; } public int Count { get { return count; } } public string Word { get { return word; } } public override string ToString() { return word + ":" + count.ToString(); } } The MapReduce function  that gets the results. the input data could be partitioned and distributed across the cluster. 1. Creates a DryadTable<LineRecord> object, inputTable, to represent the lines of input text. For partitioned data, use GetPartitionedTable<T> instead of GetTable<T> and pass the method a metadata file. 2. Applies the SelectMany operator to inputTable to transform the collection of lines into collection of words. The String.Split method converts the line into a collection of words. SelectMany concatenates the collections created by Split into a single IQueryable<string> collection named words, which represents all the words in the file. 3. Performs the Map part of the operation by applying GroupBy to the words object. The GroupBy operation groups elements with the same key, which is defined by the selector delegate. This creates a higher order collection, whose elements are groups. In this case, the delegate is an identity function, so the key is the word itself and the operation creates a groups collection that consists of groups of identical words. 4. Performs the Reduce part of the operation by applying Select to groups. This operation reduces the groups of words from Step 3 to an IQueryable<Pair> collection named counts that represents the unique words in the file and how many instances there are of each word. Each key value in groups represents a unique word, so Select creates one Pair object for each unique word. IGrouping.Count returns the number of items in the group, so each Pair object's Count member is set to the number of instances of the word. 5. Applies OrderByDescending to counts. This operation sorts the input collection in descending order of frequency and creates an ordered collection named ordered. 6. Applies Take to ordered to create an IQueryable<Pair> collection named top, which contains the 100 most common words in the input file, and their frequency. Test then uses the Pair object's ToString implementation to print the top one hundred words, and their frequency.   public static IQueryable<Pair> MapReduce( string directory, string fileName, int k) { DryadDataContext ddc = new DryadDataContext("file://" + directory); DryadTable<LineRecord> inputTable = ddc.GetTable<LineRecord>(fileName); IQueryable<string> words = inputTable.SelectMany(x => x.line.Split(' ')); IQueryable<IGrouping<string, string>> groups = words.GroupBy(x => x); IQueryable<Pair> counts = groups.Select(x => new Pair(x.Key, x.Count())); IQueryable<Pair> ordered = counts.OrderByDescending(x => x.Count); IQueryable<Pair> top = ordered.Take(k);   return top; }   To Test: IQueryable<Pair> results = MapReduce(@"c:\DryadData\input", "TestFile.txt", 100); foreach (Pair words in results) Debug.Print(words.ToString());   Note: DryadLINQ applications can use a more compact way to represent the query: return inputTable         .SelectMany(x => x.line.Split(' '))         .GroupBy(x => x)         .Select(x => new Pair(x.Key, x.Count()))         .OrderByDescending(x => x.Count)         .Take(k);     MapReduce using PLINQ The pattern is relevant even for a single multi-core machine, however. We can write our own PLINQ MapReduce in a few lines. the Map function takes a single input value and returns a set of mapped values àLINQ's SelectMany operator. These are then grouped according to an intermediate key à LINQ GroupBy operator. The Reduce function takes each intermediate key and a set of values for that key, and produces any number of outputs per key à LINQ SelectMany again. We can put all of this together to implement MapReduce in PLINQ that returns a ParallelQuery<T> public static ParallelQuery<TResult> MapReduce<TSource, TMapped, TKey, TResult>( this ParallelQuery<TSource> source, Func<TSource, IEnumerable<TMapped>> map, Func<TMapped, TKey> keySelector, Func<IGrouping<TKey, TMapped>, IEnumerable<TResult>> reduce) { return source .SelectMany(map) .GroupBy(keySelector) .SelectMany(reduce); } the map function takes in an input document and outputs all of the words in that document. The grouping phase groups all of the identical words together, such that the reduce phase can then count the words in each group and output a word/count pair for each grouping: var files = Directory.EnumerateFiles(dirPath, "*.txt").AsParallel(); var counts = files.MapReduce( path => File.ReadLines(path).SelectMany(line => line.Split(delimiters)), word => word, group => new[] { new KeyValuePair<string, int>(group.Key, group.Count()) });

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  • Complete Active Directory redesign and GPO application

    - by Wolfgang Kuehne
    after much testing and hundreds of tries and hours invested I decided to consult you experts here. Overview: I want to apply some GPO to our users which will add some specific site to the Trusted Sites in Internet Explorer settings for all users. However, the more I try the more confusing the results become. The GPO is either applied to one group of users, or to another one. Finally, I came to the conclusion that this weird behavior is cause rather by the poor organization in Users and Groups in Active Directory. As such I want to kick the problem from the root: Redesign the Active Directory Users and Groups. Scenario: There is one Domain Controller, and we use Terminal Services (so there is a Terminal Server as well). Users usually log on to the Terminal Server using Remote Desktop to perform their daily tasks. I would classify the users in the following way: IT: Admins, Software Development Business: Administration, Management The current structure of the Active Directory Users and Groups is a result of the previous IT management. The company has used Small Business Server which has created multiple default user groups and containers. Unfortunately, the guys working before me have do no documentation at all. Now, as I inherit this structure I am in the no mans land. No idea which direction to head first. As you can see, the Active Directory User and Groups have become a bit confusing. There is no SBS anymore, but when migrating from SBS to the current Windows Server 2008 R2 environment the guys before me have simply copied the same structure. The real question: Where should I start cleaning from, ensuring that I won't break totally the current infrastructure? What is a nice organization for the scenario that I have explained above? Possible useful info for the current structure: Computers folder contains Terminal Services Computers user group Members: TerminalServer computer located at Server -> Terminalserver OU Member of: NONE Foreign Security Principals : EMPTY Managed Service Accounts : EMPTY Microsoft Exchange Security Groups : not sure if needed, our emails are administered by external service provider Distribution Groups : not sure if needed Security Groups : there are couple of groups which are needed SBS users : contains all the users Terminalserver : contains only the TerminalServer machine

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  • Efficient representation of Hierarchies in Hibernate.

    - by Alison G
    I'm having some trouble representing an object hierarchy in Hibernate. I've searched around, and haven't managed to find any examples doing this or similar - you have my apologies if this is a common question. I have two types which I'd like to persist using Hibernate: Groups and Items. * Groups are identified uniquely by a combination of their name and their parent. * The groups are arranged in a number of trees, such that every Group has zero or one parent Group. * Each Item can be a member of zero or more Groups. Ideally, I'd like a bi-directional relationship allowing me to get: * all Groups that an Item is a member of * all Items that are a member of a particular Group or its descendants. I also need to be able to traverse the Group tree from the top in order to display it on the UI. The basic object structure would ideally look like this: class Group { ... /** @return all items in this group and its descendants */ Set<Item> getAllItems() { ... } /** @return all direct children of this group */ Set<Group> getChildren() { ... } ... } class Item { ... /** @return all groups that this Item is a direct member of */ Set<Group> getGroups() { ... } ... } Originally, I had just made a simple bi-directional many-to-many relationship between Items and Groups, such that fetching all items in a group hierarchy required recursion down the tree, and fetching groups for an Item was a simple getter, i.e.: class Group { ... private Set<Item> items; private Set<Group> children; ... /** @return all items in this group and its descendants */ Set<Item> getAllItems() { Set<Item> allItems = new HashSet<Item>(); allItems.addAll(this.items); for(Group child : this.getChildren()) { allItems.addAll(child.getAllItems()); } return allItems; } /** @return all direct children of this group */ Set<Group> getChildren() { return this.children; } ... } class Item { ... private Set<Group> groups; /** @return all groups that this Item is a direct member of */ Set<Group> getGroups() { return this.groups; } ... } However, this resulted in multiple database requests to fetch the Items in a Group with many descendants, or for retrieving the entire Group tree to display in the UI. This seems very inefficient, especially with deeper, larger group trees. Is there a better or standard way of representing this relationship in Hibernate? Am I doing anything obviously wrong or stupid? My only other thought so far was this: Replace the group's id, parent and name fields with a unique "path" String which specifies the whole ancestry of a group, e.g.: /rootGroup /rootGroup/aChild /rootGroup/aChild/aGrandChild The join table between Groups and Items would then contain group_path and item_id. This immediately solves the two issues I was suffering previously: 1. The entire group hierarchy can be fetched from the database in a single query and reconstructed in-memory. 2. To retrieve all Items in a group or its descendants, we can select from group_item where group_path='N' or group_path like 'N/%' However, this seems to defeat the point of using Hibernate. All thoughts welcome!

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  • Using SPServices &amp; jQuery to Find My Stuff from Multi-Select Person/Group Field

    - by Mark Rackley
    Okay… quick blog post for all you SPServices fans out there. I needed to quickly write a script that would return all the tasks currently assigned to me.  I also wanted it to return any task that was assigned to a group I belong to. This can actually be done with a CAML query, so no big deal, right?  The rub is that the “assigned to” field is a multi-select person or group field. As far as I know (and I actually know so little) you cannot just write a CAML query to return this information. If you can, please leave a comment below and disregard the rest of this blog post… So… what’s a hacker to do? As always, I break things down to their most simple components (I really love the KISS principle and would get it tattooed on my back if people wouldn’t think it meant “Knights In Satan’s Service”. You really gotta be an old far to get that reference).  Here’s what we’re going to do: Get currently logged in user’s name as it is stored in a person field Find all the SharePoint groups the current user belongs to Retrieve a set of assigned tasks from the task list and then find those that are assigned to current  user or group current user belongs to Nothing too hairy… So let’s get started Some Caveats before I continue There are some obvious performance implications with this solution as I make a total of four SPServices calls and there’s a lot of looping going on. Also, the CAML query in this blog has NOT been optimized. If you move forward with this code, tweak it so that it returns a further subset of data or you will see horrible performance if you have a few hundred entries in your task list. Add a date range to the CAML or something. Find some way to limit the results as much as possible. Lastly, if you DO have a better solution, I would like you to share. Iron sharpens iron and all…   Alright, let’s really get started. Get currently logged in user’s name as it is stored in a person field First thing we need to do is understand how a person group looks when you look at the XML returned from a SharePoint Web Service call. It turns out it’s stored like any other multi select item in SharePoint which is <id>;#<value> and when you assign a person to that field the <value> equals the person’s name “Mark Rackley” in my case. This is for Windows Authentication, I would expect this to be different in FBA, but I’m not using FBA. If you want to know what it looks like with FBA you can use the code in this blog and strategically place an alert to see the value.  Anyway… I need to find the name of the user who is currently logged in as it is stored in the person field. This turns out to be one SPServices call: var userName = $().SPServices.SPGetCurrentUser({                     fieldName: "Title",                     debug: false                     }); As you can see, the “Title” field has the information we need. I suspect (although again, I haven’t tried) that the Title field also contains the user’s name as we need it if I was using FBA. Okay… last thing we need to do is store our users name in an array for processing later: myGroups = new Array(); myGroups.push(userName); Find all the SharePoint groups the current user belongs to Now for the groups. How are groups returned in that XML stream?  Same as the person <ID>;#<Group Name>, and if it’s a mutli select it’s all returned in one big long string “<ID>;#<Group Name>;#<ID>;#<Group Name>;#<ID>;#<Group Name>;#<ID>;#<Group Name>;#<ID>;#<Group Name>”.  So, how do we find all the groups the current user belongs to? This is also a simple SPServices call. Using the “GetGroupCollectionFromUser” operation we can find all the groups a user belongs to. So, let’s execute this method and store all our groups. $().SPServices({       operation: "GetGroupCollectionFromUser",       userLoginName: $().SPServices.SPGetCurrentUser(),       async: false,       completefunc: function(xData, Status) {          $(xData.responseXML).find("[nodeName=Group]").each(function() {                 myGroups.push($(this).attr("Name"));          });         }     }); So, all we did in the above code was execute the “GetGroupCollectionFromUser” operation and look for the each “Group” node (row) and store the name for each group in our array that we put the user’s name in previously (myGroups). Now we have an array that contains the current user’s name as it will appear in the person field XML and  all the groups the current user belongs to. The Rest Now comes the easy part for all of you familiar with SPServices. We are going to retrieve our tasks from the Task list using “GetListItems” and look at each entry to see if it belongs to this person. If it does belong to this person we are going to store it for later processing. That code looks something like this: // get list of assigned tasks that aren't closed... *modify the CAML to perform better!*             $().SPServices({                   operation: "GetListItems",                   async: false,                   listName: "Tasks",                   CAMLViewFields: "<ViewFields>" +                             "<FieldRef Name='AssignedTo' />" +                             "<FieldRef Name='Title' />" +                             "<FieldRef Name='StartDate' />" +                             "<FieldRef Name='EndDate' />" +                             "<FieldRef Name='Status' />" +                             "</ViewFields>",                   CAMLQuery: "<Query><Where><And><IsNotNull><FieldRef Name='AssignedTo'/></IsNotNull><Neq><FieldRef Name='Status'/><Value Type='Text'>Completed</Value></Neq></And></Where></Query>",                     completefunc: function (xData, Status) {                         var aDataSet = new Array();                        //loop through each returned Task                         $(xData.responseXML).find("[nodeName=z:row]").each(function() {                             //store the multi-select string of who task is assigned to                             var assignedToString = $(this).attr("ows_AssignedTo");                             found = false;                            //loop through the persons name and all the groups they belong to                             for(var i=0; i<myGroups.length; i++) {                                 //if the person's name or group exists in the assigned To string                                 //then the task is assigned to them                                 if (assignedToString.indexOf(myGroups[i]) >= 0){                                     found = true;                                     break;                                 }                             }                             //if the Task belongs to this person then store or display it                             //(I'm storing it in an array)                             if (found){                                 var thisName = $(this).attr("ows_Title");                                 var thisStartDate = $(this).attr("ows_StartDate");                                 var thisEndDate = $(this).attr("ows_EndDate");                                 var thisStatus = $(this).attr("ows_Status");                                                                  var aDataRow=new Array(                                     thisName,                                     thisStartDate,                                     thisEndDate,                                     thisStatus);                                 aDataSet.push(aDataRow);                             }                          });                          SomeFunctionToDisplayData(aDataSet);                     }                 }); Some notes on why I did certain things and additional caveats. You will notice in my code that I’m doing an AssignedToString.indexOf(GroupName) to see if the task belongs to the person. This could possibly return bad results if you have SharePoint Group names that are named in such a way that the “IndexOf” returns a false positive.  For example if you have a Group called “My Users” and a group called “My Users – SuperUsers” then if a user belonged to “My Users” it would return a false positive on executing “My Users – SuperUsers”.IndexOf(“My Users”). Make sense? Just be aware of this when naming groups, we don’t have this problem. This is where also some fine-tuning can probably be done by those smarter than me. This is a pretty inefficient method to determine if a task belongs to a user, I mean what if a user belongs to 20 groups? That’s a LOT of looping.  See all the opportunities I give you guys to do something fun?? Also, why am I storing my values in an array instead of just writing them out to a Div? Well.. I want to pass my data to a jQuery library to format it all nice and pretty and an Array is a great way to do that. When all is said and done and we put all the code together it looks like:   $(document).ready(function() {         var userName = $().SPServices.SPGetCurrentUser({                     fieldName: "Title",                     debug: false                     });         myGroups = new Array();     myGroups.push(userName );       $().SPServices({       operation: "GetGroupCollectionFromUser",       userLoginName: $().SPServices.SPGetCurrentUser(),       async: false,       completefunc: function(xData, Status) {          $(xData.responseXML).find("[nodeName=Group]").each(function() {                 myGroups.push($(this).attr("Name"));          });                      // get list of assigned tasks that aren't closed... *modify this CAML to perform better!*             $().SPServices({                   operation: "GetListItems",                   async: false,                   listName: "Tasks",                   CAMLViewFields: "<ViewFields>" +                             "<FieldRef Name='AssignedTo' />" +                             "<FieldRef Name='Title' />" +                             "<FieldRef Name='StartDate' />" +                             "<FieldRef Name='EndDate' />" +                             "<FieldRef Name='Status' />" +                             "</ViewFields>",                   CAMLQuery: "<Query><Where><And><IsNotNull><FieldRef Name='AssignedTo'/></IsNotNull><Neq><FieldRef Name='Status'/><Value Type='Text'>Completed</Value></Neq></And></Where></Query>",                     completefunc: function (xData, Status) {                         var aDataSet = new Array();                         //loop through each returned Task                         $(xData.responseXML).find("[nodeName=z:row]").each(function() {                             //store the multi-select string of who task is assigned to                             var assignedToString = $(this).attr("ows_AssignedTo");                             found = false;                            //loop through the persons name and all the groups they belong to                             for(var i=0; i<myGroups.length; i++) {                                 //if the person's name or group exists in the assigned To string                                 //then the task is assigned to them                                 if (assignedToString.indexOf(myGroups[i]) >= 0){                                     found = true;                                     break;                                 }                             }                            //if the Task belongs to this person then store or display it                             //(I'm storing it in an array)                             if (found){                                 var thisName = $(this).attr("ows_Title");                                 var thisStartDate = $(this).attr("ows_StartDate");                                 var thisEndDate = $(this).attr("ows_EndDate");                                 var thisStatus = $(this).attr("ows_Status");                                                                  var aDataRow=new Array(                                     thisName,                                     thisStartDate,                                     thisEndDate,                                     thisStatus);                                 aDataSet.push(aDataRow);                             }                          });                          SomeFunctionToDisplayData(aDataSet);                     }                 });       }    });  }); Final Thoughts So, there you have it. Take it and run with it. Make it something cool (and tell me how you did it). Another possible way to improve performance in this scenario is to use a DVWP to display the tasks and use jQuery and the “myGroups” array from this blog post to hide all those rows that don’t belong to the current user. I haven’t tried it, but it does move some of the processing off to the server (generating the view) so it may perform better.  As always, thanks for stopping by… hope you have a Merry Christmas…

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  • What is the best Linux distribution as a Xen host?

    - by St3fan
    I ordered a server for the home office and I would like to partition it with Xen. I think this will keep things clean and easier to maintain. I will be running things like MySQL, PostgreSQL, Tomcat and my own code on this machine. My question is: what freely available Linux distribution has the best Xen hosting facilities?

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  • How do I perform 'WHERE' on groups of rows?

    - by Drew
    I have a table, which looks like: +-----------+----------+ + person_id + group_id + +-----------+----------+ + 1 + 10 + + 1 + 20 + + 1 + 30 + + 2 + 10 + + 2 + 20 + + 3 + 10 + +-----------+----------+ I need a query such that only person_ids with groups 10 AND 20 AND 30 are returned (only person_id: 1). I am not sure how to do this, as from what I can see it would require me to group the rows by person_id and then select the rows which contain all group_ids. I'm looking for something which will preserve the use of keys without resorting to string operations on group_concat() or such.

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  • What role does the Apple iTunes server play in Enterprise distribution?

    - by Piepants
    I'm looking into what's involved in distributing an Enterprise App and found this line in Apple's Enterprise App Distribution doc in the section on installing the apps wirelessly: A network configuration that allows the devices to access an iTunes server at Apple What does this mean and why is it necessary? I thought the apps to be installed would be hosted on a company web site, but does this imply otherwise? TIA

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  • Custom rails route problem with 2.3.8 and Mongrel

    - by CHsurfer
    I have a controller called 'exposures' which I created automatically with the script/generate scaffold call. The scaffold pages work fine. I created a custom action called 'test' in the exposures controller. When I try to call the page (http://127.0.0.1:3000/exposures/test/1) I get a blank, white screen with no text at all in the source. I am using Rails 2.3.8 and mongrel in the development environment. There are no entries in development.log and the console that was used to open mongrel has the following error: You might have expected an instance of Array. The error occurred while evaluating nil.split D:/Rails/ruby/lib/ruby/gems/1.8/gems/actionpack-2.3.8/lib/action_controller/cgi_process.rb:52:in dispatch_cgi' D:/Rails/ruby/lib/ruby/gems/1.8/gems/actionpack-2.3.8/lib/action_controller/dispatcher.rb:101:in dispatch_cgi' D:/Rails/ruby/lib/ruby/gems/1.8/gems/actionpack-2.3.8/lib/action_controller/dispatcher.rb:27:in dispatch' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel/rails.rb:76:in process' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel/rails.rb:74:in synchronize' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel/rails.rb:74:in process' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel.rb:159:in process_client' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel.rb:158:in each' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel.rb:158:in process_client' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel.rb:285:in run' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel.rb:285:in initialize' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel.rb:285:in new' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel.rb:285:in run' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel.rb:268:in initialize' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel.rb:268:in new' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel.rb:268:in run' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel/configurator.rb:282:in run' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel/configurator.rb:281:in each' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel/configurator.rb:281:in run' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/mongrel_rails:128:in run' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/../lib/mongrel/command.rb:212:in run' D:/Rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/bin/mongrel_rails:281 D:/Rails/ruby/bin/mongrel_rails:19:in load' D:/Rails/ruby/bin/mongrel_rails:19 Here is the exposures_controller code: class ExposuresController < ApplicationController # GET /exposures # GET /exposures.xml def index @exposures = Exposure.all respond_to do |format| format.html # index.html.erb format.xml { render :xml => @exposures } end end #/exposure/graph/1 def graph @exposure = Exposure.find(params[:id]) project_name = @exposure.tender.project.name group_name = @exposure.tender.user.group.name tender_desc = @exposure.tender.description direction = "Cash Out" direction = "Cash In" if @exposure.supply currency_1_and_2 = "#{@exposure.currency_in} = #{@exposure.currency_out}" title = "#{project_name}:#{group_name}:#{tender_desc}/n" title += "#{direction}:#{currency_1_and_2}" factors = Array.new carrieds = Array.new days = Array.new @exposure.rates.each do |r| factors << r.factor carrieds << r.carried days << r.day.to_s end max = (factors+carrieds).max min = (factors+carrieds).min g = Graph.new g.title(title, '{font-size: 12px;}') g.set_data(factors) g.line_hollow(2, 4, '0x80a033', 'Bounces', 10) g.set_x_labels(days) g.set_x_label_style( 10, '#CC3399', 2 ); g.set_y_min(min*0.9) g.set_y_max(max*1.1) g.set_y_label_steps(5) render :text = g.render end def test render :text = "this works" end # GET /exposures/1 # GET /exposures/1.xml def show @exposure = Exposure.find(params[:id]) @graph = open_flash_chart_object(700,250, "/exposures/graph/#{@exposure.id}") #@graph = "/exposures/graph/#{@exposure.id}" respond_to do |format| format.html # show.html.erb format.xml { render :xml => @exposure } end end # GET /exposures/new # GET /exposures/new.xml def new @exposure = Exposure.new respond_to do |format| format.html # new.html.erb format.xml { render :xml => @exposure } end end # GET /exposures/1/edit def edit @exposure = Exposure.find(params[:id]) end # POST /exposures # POST /exposures.xml def create @exposure = Exposure.new(params[:exposure]) respond_to do |format| if @exposure.save flash[:notice] = 'Exposure was successfully created.' format.html { redirect_to(@exposure) } format.xml { render :xml => @exposure, :status => :created, :location => @exposure } else format.html { render :action => "new" } format.xml { render :xml => @exposure.errors, :status => :unprocessable_entity } end end end # PUT /exposures/1 # PUT /exposures/1.xml def update @exposure = Exposure.find(params[:id]) respond_to do |format| if @exposure.update_attributes(params[:exposure]) flash[:notice] = 'Exposure was successfully updated.' format.html { redirect_to(@exposure) } format.xml { head :ok } else format.html { render :action => "edit" } format.xml { render :xml => @exposure.errors, :status => :unprocessable_entity } end end end # DELETE /exposures/1 # DELETE /exposures/1.xml def destroy @exposure = Exposure.find(params[:id]) @exposure.destroy respond_to do |format| format.html { redirect_to(exposures_url) } format.xml { head :ok } end end end Clever readers will notice the 'graph' action. This is what I really want to work, but if I can't even get the test action working, then I'm sure I have no chance. Any ideas? I have restarted mongrel a few times with no change. Here is the output of Rake routes (but I don't believe this is the problem. The error would be in the form of and HTML error response). D:\Rails\rails_apps\fxrake routes (in D:/Rails/rails_apps/fx) DEPRECATION WARNING: Rake tasks in vendor/plugins/open_flash_chart/tasks are deprecated. Use lib/tasks instead. (called from D:/ by/gems/1.8/gems/rails-2.3.8/lib/tasks/rails.rb:10) rates GET /rates(.:format) {:controller="rates", :action="index"} POST /rates(.:format) {:controller="rates", :action="create"} new_rate GET /rates/new(.:format) {:controller="rates", :action="new"} edit_rate GET /rates/:id/edit(.:format) {:controller="rates", :action="edit"} rate GET /rates/:id(.:format) {:controller="rates", :action="show"} PUT /rates/:id(.:format) {:controller="rates", :action="update"} DELETE /rates/:id(.:format) {:controller="rates", :action="destroy"} tenders GET /tenders(.:format) {:controller="tenders", :action="index"} POST /tenders(.:format) {:controller="tenders", :action="create"} new_tender GET /tenders/new(.:format) {:controller="tenders", :action="new"} edit_tender GET /tenders/:id/edit(.:format) {:controller="tenders", :action="edit"} tender GET /tenders/:id(.:format) {:controller="tenders", :action="show"} PUT /tenders/:id(.:format) {:controller="tenders", :action="update"} DELETE /tenders/:id(.:format) {:controller="tenders", :action="destroy"} exposures GET /exposures(.:format) {:controller="exposures", :action="index"} POST /exposures(.:format) {:controller="exposures", :action="create"} new_exposure GET /exposures/new(.:format) {:controller="exposures", :action="new"} edit_exposure GET /exposures/:id/edit(.:format) {:controller="exposures", :action="edit"} exposure GET /exposures/:id(.:format) {:controller="exposures", :action="show"} PUT /exposures/:id(.:format) {:controller="exposures", :action="update"} DELETE /exposures/:id(.:format) {:controller="exposures", :action="destroy"} currencies GET /currencies(.:format) {:controller="currencies", :action="index"} POST /currencies(.:format) {:controller="currencies", :action="create"} new_currency GET /currencies/new(.:format) {:controller="currencies", :action="new"} edit_currency GET /currencies/:id/edit(.:format) {:controller="currencies", :action="edit"} currency GET /currencies/:id(.:format) {:controller="currencies", :action="show"} PUT /currencies/:id(.:format) {:controller="currencies", :action="update"} DELETE /currencies/:id(.:format) {:controller="currencies", :action="destroy"} projects GET /projects(.:format) {:controller="projects", :action="index"} POST /projects(.:format) {:controller="projects", :action="create"} new_project GET /projects/new(.:format) {:controller="projects", :action="new"} edit_project GET /projects/:id/edit(.:format) {:controller="projects", :action="edit"} project GET /projects/:id(.:format) {:controller="projects", :action="show"} PUT /projects/:id(.:format) {:controller="projects", :action="update"} DELETE /projects/:id(.:format) {:controller="projects", :action="destroy"} groups GET /groups(.:format) {:controller="groups", :action="index"} POST /groups(.:format) {:controller="groups", :action="create"} new_group GET /groups/new(.:format) {:controller="groups", :action="new"} edit_group GET /groups/:id/edit(.:format) {:controller="groups", :action="edit"} group GET /groups/:id(.:format) {:controller="groups", :action="show"} PUT /groups/:id(.:format) {:controller="groups", :action="update"} DELETE /groups/:id(.:format) {:controller="groups", :action="destroy"} users GET /users(.:format) {:controller="users", :action="index"} POST /users(.:format) {:controller="users", :action="create"} new_user GET /users/new(.:format) {:controller="users", :action="new"} edit_user GET /users/:id/edit(.:format) {:controller="users", :action="edit"} user GET /users/:id(.:format) {:controller="users", :action="show"} PUT /users/:id(.:format) {:controller="users", :action="update"} DELETE /users/:id(.:format) {:controller="users", :action="destroy"} /:controller/:action/:id /:controller/:action/:id(.:format) D:\Rails\rails_apps\fxrails -v Rails 2.3.8 Thanks in advance for the help -Jon

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  • Linq-to-SQL: How to perform a count on a sub-select

    - by Peter Bridger
    I'm still trying to get my head round how to use LINQ-to-SQL correctly, rather than just writing my own sprocs. In the code belong a userId is passed into the method, then LINQ uses this to get all rows from the GroupTable tables matching the userId. The primary key of the GroupUser table is GroupUserId, which is a foreign key in the Group table. /// <summary> /// Return summary details about the groups a user belongs to /// </summary> /// <param name="userId"></param> /// <returns></returns> public List<Group> GroupsForUser(int userId) { DataAccess.KINv2DataContext db = new DataAccess.KINv2DataContext(); List<Group> groups = new List<Group>(); groups = (from g in db.Groups join gu in db.GroupUsers on g.GroupId equals gu.GroupId where g.Active == true && gu.UserId == userId select new Group { Name = g.Name, CreatedOn = g.CreatedOn }).ToList<Group>(); return groups; } } This works fine, but I'd also like to return the total number of Users who are in a group and also the total number of Contacts that fall under ownership of the group. Pseudo code ahoy! /// <summary> /// Return summary details about the groups a user belongs to /// </summary> /// <param name="userId"></param> /// <returns></returns> public List<Group> GroupsForUser(int userId) { DataAccess.KINv2DataContext db = new DataAccess.KINv2DataContext(); List<Group> groups = new List<Group>(); groups = (from g in db.Groups join gu in db.GroupUsers on g.GroupId equals gu.GroupId where g.Active == true && gu.UserId == userId select new Group { Name = g.Name, CreatedOn = g.CreatedOn, // ### This is the SQL I would write to get the data I want ### MemberCount = ( SELECT COUNT(*) FROM GroupUser AS GU WHERE GU.GroupId = g.GroupId ), ContactCount = ( SELECT COUNT(*) FROM Contact AS C WHERE C.OwnerGroupId = g.GroupId ) // ### End of extra code ### }).ToList<Group>(); return groups; } }

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  • How to Create a Send/Receive Group for RSS Feeds in Outlook 2013

    - by Lori Kaufman
    If you choose to manually update your RSS feeds on demand, there is a way to do this without having to send and receive your email at the same time. You can create a special Send/Receive Group for your RSS feeds. NOTE: If you choose to not have your RSS feeds updated automatically, creating a separate Send/Receive Group for your RSS feeds is useful so you can update them when you want to. To begin creating a new Send/Receive Group, click the File tab. Click Options in the menu on the left side of the Account Information screen. On the Outlook Options dialog box, click Advanced in the left pane list of menu options. In the right pane, scroll down to the Send and receive section and click the Send/Receive button. On the Send/Receive Groups dialog box, click New next to the list of groups. On the Send/Receive Group Name dialog box, enter a name, such as “RSS Feeds On Demand Only,” in the edit box and click OK. For all the other Accounts, except RSS, in the list on the left, de-select the Include RSS Feeds in this Send/Receive group check box so there is NO check mark in the box. Click RSS under Accounts, and make sure the Include RSS Feeds in this Send/Receive group check box is selected. NOTE: If you want to have a separate Send/Receive group for each RSS Feed or group certain RSS feeds together, you can turn on and off specific feeds in the lower half of the Send/Receive Settings dialog box. If you decide to do this, you might specify a more appropriate name for each Send/Receive group for the RSS feeds. Click OK to accept your changes and close the Send/Receive dialog box. Make sure your new Send/Receive group is selected in the list of groups on the Send/Receive Groups dialog box. De-select all the options under Setting for group section at the bottom of the dialog box and click Close. This prevents this group from being updated when you click the general Send/Receive button to retrieve your email. Click OK on the Outlook Options dialog box. To manually update your RSS feeds, click the Send / Receive tab. Click Send/Receive Groups and select your new group from the drop-down list. You can change, rename, or remove any Send/Receive Groups you create by accessing the Send/Receive Groups dialog box again.     

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  • Ad Hoc Distribution - Does it update an existing previous installed version of an app?

    - by Kriem
    What happens when a user installs an ad hoc distribution of an existing app? And what happens if this app (or a newer one) hits the App Store officially? To sum it up: A user already has a v1.0 and receives a v2.0 ad hoc A user has the ad hoc v2.0 and the official public release of v2.0 hits the store A user has the ad hoc v2.0 and an official public release of v3.0 hits the store In other words, is the ad hoc version a stand-alone build or does it in fact update a previous version as expected from an update? And will it be updated as soon as a newer version hits the store?

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  • Can I make a matrix row group span its child groups in SSRS?

    - by AaronSieb
    I have a matrix, whose rows are grouped into two groups. A class, and a time for that class. The class cell is going to end up being several lines long, and I'd like the rows for each time slot of the class to line up next to the class description, like this: ----------------------------------------- **Class** | 7:00am | [row data] Description of |---------------------- the class, this | 12:00pm | [row data] is several lines |---------------------- long. | 1:00pm | [row data] ----------------------------------------- But what I'm getting is this: ----------------------------------------- **Class** | 7:00am | [row data] Description of | | the class, this | | is several lines | | long. | | ----------------------------------------- | 12:00pm | [row data] | | | | | | | | ----------------------------------------- | 1:00pm | [row data] | | | | | | | | ----------------------------------------- Is there any way to make SSRS collapse the matrix?

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  • Can a repeated piece of regular expression create multiple groups? Such as this example...

    - by Yousui
    Hi guys, I'm using RUBY 's regular expression to deal with text such as ${1:aaa|bbbb} ${233:aaa | bbbb | ccc ccccc } ${34: aaa | bbbb | cccccccc |d} ${343: aaa | bbbb | cccccccc |dddddd ddddddddd} ${3443:a aa|bbbb|cccccccc|d} ${353:aa a| b b b b | c c c c c c c c | dddddd} I want to get the trimed text between each pipe line. For example, for the first line of my upper example, I want to get the result aaa and bbbb, for the second line, I want aaa, bbbb and ccc ccccc. Now I have wrote a piece of regular expression and a piece of ruby code to test it: array = "${33:aaa|bbbb|cccccccc}".scan(/\$\{\s*(\d+)\s*:(\s*[^\|]+\s*)(?:\|(\s*[^\|]+\s*))+\}/) puts array Now my problem is the (?:\|(\s*[^\|]+\s*))+ part can't create multiple groups. I don't know how to solve this problem, because the number of text I need in each line is variable. Anyone can help? Great thanks.

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  • PHP: Is there an elegant way to foreach through multiple items (groups) at a time?

    - by acheong87
    Given an array of N items: $arr = array('a', 'b', 'c', 'd', 'e', 'f'); What's the most elegant way to loop through in groups of M items (assuming N is divisible by M)? I tried foreach (array_chunk($arr, 2) as list($first, $second)) { // do stuff with $first and $second } but this resulted in a syntax error. In other words, I want to emulate what in Tcl would look like this: set arr [a b c d e f] foreach {first second} $arr { // do stuff with $first and $second } For now I've resorted to the obvious measure: foreach (array_chunk($arr, 2) as $group) { $first = $group[0]; $second = $group[1]; // do stuff with $first and $second } But I'm hoping someone has a more elegant method...

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