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  • Apply PHP regex replace on a multi-line repeated pattern

    - by Hussain
    Let's say I have this input: I can haz a listz0rs! # 42 # 126 I can haz another list plox? # Hello, world! # Welcome! I want to split it so that each set of hash-started lines becomes a list: I can haz a listz0rs! <ul> <li>42</li> <li>126</li> </ul> I can haz another list plox? <ul> <li>Hello, world!</li> <li>Welcome!</li> </ul> If I run the input against the regex "/(?:(?:(?<=^# )(.*)$)+)/m", I get the following result: Array ( [0] => Array ( [0] => 42 ) [1] => Array ( [0] => 126 ) [2] => Array ( [0] => Hello, world! ) [3] => Array ( [0] => Welcome! ) ) This is fine and dandy, but it doesn't distinguish between the two different lists. I need a way to either make the quantifier return a concatenated string of all the occurrences, or, ideally, an array of all the occurrences. Ideally, this should be my output: Array ( [0] => Array ( [0] => 42 [1] => 126 ) [1] => Array ( [0] => Hello, world! [1] => Welcome! ) ) Is there any way of achieving this, and if not, is there a close alternative? Thanks in advance!

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  • Editing a remote file on-the-fly with PHP

    - by user275074
    Hi, I have a requirement to edit a remote text file on-the-fly, the content of which currently stands at ~1Mb. I have tried a couple of approaches and both seem to be clunky or hog memory which I can't rely on. Thinking out logically what I'm trying to achieve is: FTP to a remote server. Download a copy of the file for backup purposes and store it somewhere locally. Open the remote file and add the necessary lines required. Remove lines from the remote file as per an array of un-required data generated from the local server. Is this possible? I've managed to code steps 1 and 2 but I'm having difficult with 3 and 4. The way I'm doing it now is to use fgets and return the whole string. Really, I don't want to do this as it involves manipulating and re-generating the whole string (and it's large) and then re-inserting it in between two markers in the remote file. Is there no way of manipulating the lines of text in the file on-the-fly?

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  • php count rss entries since a specific date/time

    - by Steven
    can anyone tell me why this code don't work: $q = $_GET['q']; // Load and parse the XML document $rss = simplexml_load_file("http://search.twitter.com/search.atom?lang=en&q=$q&rpp=100&page=1"); $Count1 = 0; while(strtotime($rss->entry->published)>1270833600){ foreach ($rss->entry as $item) { $Count1++; } } print "Total Record: ".$Count1;

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  • PHP Populating array with $variables

    - by Tom
    Hi, I'm trying to create a basic shopping cart, having an issue with the product page allowing users to add more items to their cart then are in stock (I have code in place to prevent this on the view cart page, just not the view product page) This is what I have so far; for ($i = 0; $i < $numItem; $i++) { extract($cartContent[$i]); $subTotal += $price * $cartQuantity; $cartLimiter[$itemNo => $cartQuantity]; Using an array so the position number becomes the item number and the cart quantity becomes the assigned value, however it doesn't seem to like it and throws out on the bottom line of code: Parse error: syntax error, unexpected T_DOUBLE_ARROW, expecting ']' Thanks

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  • PHP/MYSQL Trouble Selecting by Primary Key

    - by djs22
    Hi all, So I have a primary key column called key. I'm trying to select the row with key = 1 via this code: $query ="SELECT * FROM Bowlers WHERE key = '1'"; $result = mysql_query($query) or die(mysql_error()); For some reason, I'm getting this result: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'key = '1'' at line 1 The mysql statement works for using other keys, ie WHERE name = 'djs22'. Any ideas?

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  • How to get parameter after "/" in URL in PHP

    - by Lucifer
    I need to let my users type anything at the end of my url, like this: http://mysite.com/?somethingorother or http://mysite.com/somethingorother And then I would like to get that last bit that they added to the end of the url like so: $var = $_POST['']; But I'm not sure how to go about this, and I can't find anything, because I'm not quite sure how to search for it. Any help is appreciated, thanks!

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  • php function to make slug (url string)

    - by andufo
    function gen_slug($str){ # special accents $a = array('À','Á','Â','Ã','Ä','Å','Æ','Ç','È','É','Ê','Ë','Ì','Í','Î','Ï','Ð','Ñ','Ò','Ó','Ô','Õ','Ö','Ø','Ù','Ú','Û','Ü','Ý','ß','à','á','â','ã','ä','å','æ','ç','è','é','ê','ë','ì','í','î','ï','ñ','ò','ó','ô','õ','ö','ø','ù','ú','û','ü','ý','ÿ','A','a','A','a','A','a','C','c','C','c','C','c','C','c','D','d','Ð','d','E','e','E','e','E','e','E','e','E','e','G','g','G','g','G','g','G','g','H','h','H','h','I','i','I','i','I','i','I','i','I','i','?','?','J','j','K','k','L','l','L','l','L','l','?','?','L','l','N','n','N','n','N','n','?','O','o','O','o','O','o','Œ','œ','R','r','R','r','R','r','S','s','S','s','S','s','Š','š','T','t','T','t','T','t','U','u','U','u','U','u','U','u','U','u','U','u','W','w','Y','y','Ÿ','Z','z','Z','z','Ž','ž','?','ƒ','O','o','U','u','A','a','I','i','O','o','U','u','U','u','U','u','U','u','U','u','?','?','?','?','?','?'); $b = array('A','A','A','A','A','A','AE','C','E','E','E','E','I','I','I','I','D','N','O','O','O','O','O','O','U','U','U','U','Y','s','a','a','a','a','a','a','ae','c','e','e','e','e','i','i','i','i','n','o','o','o','o','o','o','u','u','u','u','y','y','A','a','A','a','A','a','C','c','C','c','C','c','C','c','D','d','D','d','E','e','E','e','E','e','E','e','E','e','G','g','G','g','G','g','G','g','H','h','H','h','I','i','I','i','I','i','I','i','I','i','IJ','ij','J','j','K','k','L','l','L','l','L','l','L','l','l','l','N','n','N','n','N','n','n','O','o','O','o','O','o','OE','oe','R','r','R','r','R','r','S','s','S','s','S','s','S','s','T','t','T','t','T','t','U','u','U','u','U','u','U','u','U','u','U','u','W','w','Y','y','Y','Z','z','Z','z','Z','z','s','f','O','o','U','u','A','a','I','i','O','o','U','u','U','u','U','u','U','u','U','u','A','a','AE','ae','O','o'); return strtolower(preg_replace(array('/[^a-zA-Z0-9 -]/','/[ -]+/','/^-|-$/'),array('','-',''),str_replace($a,$b,$str))); } Works great, but i've found some cases in which it fails: echo gen_slug('andrés'); returns andras instead of andres why? any ideas on the preg_replace parameters?

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  • Add links to specific words within span tag in PHP

    - by dazhall
    I have a list of words that I'd like to add a link to, I can do this fairly easily using preg_match_all and preg_replace: $str = "<span class=\"cz\">Dám si jedno pivo prosím.</span> = I'll have a beer please."; preg_match_all('/[a-ztúuýžácdéeínórš]+/i',$str,$matches); $matches = array_unique($matches[0]); foreach ($matches as $match) { if(!empty($words[$match])) { $str = preg_replace("/(^|[^\w]){1}(".preg_quote($match,"/").")($|[^\w]){1}/i", '\\1<a href="#">\\2</a>\\3', $str); } } echo $str; What I'd like to do is restrict the linking to only within the span tag. My brain is all regex-ed out, so any help would be appreciated! Thanks! Darren.

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  • PHP echo text if variable is blank

    - by user342391
    I am trying to echo €00.00 if my variable $amount equals zero I have done something wrong can you help?? Code while ($row9 = mysql_fetch_array($result9)) { $amount = $row9['amount']; } //$amount = $amount / 60; //$amount = round($amount, 2); if $amount == 0 echo "<b>Balance: &#8364;00.00</b>"; else echo "<b>Balance: $$amount</b>";

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  • Delete text in text box using PHP

    - by Idealflip
    Hello, is there a way to remove text from a text box using a submit button? I don't want to delete text from all boxes on the form. And I don't want to delete text 'onclick', for the element. I need the code to clear the text box, to initiate from within a block. Thanks for your help!

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  • PHP, MySQL prepared statements - can you use results of execute more than once by calling data_seek(

    - by Carvell Fenton
    Hello, I have a case where I want to use the results of a prepared statement more than once in a nested loop. The outer loop processes the results of another query, and the inner loop is the results of the prepared statement query. So the code would be something like this (just "pseudoish" to demonstrate the concept): // not showing the outer query, it is just a basic SELECT, not prepared statement // we'll call it $outer_query $obj_array = array(); // going to save objects in this $ids = array(18,19,20); // just example id numbers $query = "SELECT field1, field2 FROM table1 WHERE id=?"; $stmt = $db->prepare($query); foreach ($ids as $id) { $stmt->bind_param("i", $id); $stmt->execute(); $stmt->bind_result($var1, $var2); $stmt->store_result(); // I think I need this for data_seek while ($q1 = $outer_query->fetch_object()) { while ($stmt->fetch()) { if ($q1->field1 == $var1) { // looking for a match $obj = new stdClass(); $obj->var1 = $var1; $obj->var2 = $var2; $obj_array[] = $obj; $stmt->data_seek(0); // reset for outer loop break; // found match, so leave inner } } } } The problem I seem to be experiencing is that the values are not getting bound in the variables as I would expect after the first time I use fetch in the inner loop. Specifically, in one example I ran with 3 ids for the foreach, the first id was processed correctly, the second was processed incorrectly (matches were not found in the inner loop even though they existed), and then the third was processed correctly. Is there something wrong with the prepared statment function calls in the sequence I am doing above, or is this an invalid way to use the results of the prepared statement? Thanks.

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  • Validating Login / Changing User settings / Php Mysql

    - by Marcelo
    Hi everyone, my questions are about login, and changing already saved data. (Q1) 'Till now I've only saved input in the tables of the database (registration steps), now I need to check if the input (login steps), are the same of my table in database, in fact I have 3 types of users, then I'll have to check 3 kind of tables. Then if the input data matches with one of those 3 tables I will redirect the user to his specific area. I'm thinking about saved the submitted data $login=$_REQUEST['login']; and $password=$_REQUEST['password']; and compare with the login column in the database. Then if the login matches, I'll compare the password submitted with the one in the row, not in the column. But I don't know how to do this search and comparison,neither what to use. Then if both matches I'll redirect the user. Else I'll send an login error message. (this I know how to do) (Q2) What if need to change an already saved user ? For example to change an email address. My changing user's data web page is exactly the same like the registration user web page. Can I load the already saved options and values of registration (table user for example). Then the user will change whatever he thinks it's necessary, and then when he submits the new information, they would not create a new row in my table, but just be overwritten the old information? How can I do this? Sorry for any mistake in English, and Thanks for the attention.

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  • Exploding a String In PHP

    - by streetparade
    How do i explode this string '||25||34||73||94||116||128' i need to have a array like this array ( 0 => '25', 1 => '34', 2 => '73', 3 => '94', 4 => '116', 5 => '128' ) explode("||", $array); didnt work for me i get this array array ( 0 => '', 1 => '25', 2 => '34', 3 => '73', 4 => '94', 5 => '116', 6 => '128', )

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  • php regex replace slashes and spaces and hyphens

    - by Muhammad Shahzad
    I have fews combinations of strings that I need to bring in to one pattern, that is multiple spaces should be removed, double hyphens should be replaced with single hypen, and single space should be replaced with single hyphen. I have already tried this expression. $output = preg_replace( "/[^[:space:]a-z0-9]/e", "", $output ); $output = trim( $output ); $output = preg_replace( '/\s+/', '-', $output ); But this fails in few combinations. I need help in making all of these combinations to work perfectly: steel-black steel- black steel black I should also remove any of these as well "\r\n\t".

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  • PHP does not store all variables in session

    - by Flurin Juvalta
    Dear all I'm assigning session variables by filling the $_SESSION - Array throughout my script. My problem is, that for some reason not all variables are available in the session. here is a shortened version of my code for explaining this issue: session_start(); print_r($_SESSION); $_SESSION['lang'] = 'de'; $_SESSION['location_id'] = 11; $_SESSION['region_id'] = 1; $_SESSION['userid'] = 'eccbc87e4b5ce2fe28308fd9f2a7baf3'; $_SESSION['hash'] = 'dce57f1e3bc6fba32afab93b0c38b662'; print_r($_SESSION); first call prints something like this: Array ( ) Array ( [lang] => de [location_id] => 11 [region_id] => 1 [userid] => eccbc87e4b5ce2fe28308fd9f2a7baf3 [hash] => dce57f1e3bc6fba32afab93b0c38b662 ) the second call prints: Array ( [lang] => de [location_id] => 11 [region_id] => 1 ) Array ( [lang] => de [location_id] => 11 [region_id] => 1 [userid] => eccbc87e4b5ce2fe28308fd9f2a7baf3 [hash] => dce57f1e3bc6fba32afab93b0c38b662 ) As you can see, the important login information is not stored in the session. Does anybody has an idea what could be wrong with my session? Thanks for your answers!

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  • PHP While Loops from Arrays

    - by Michael
    I have a table that contains members names and a field with multiple ID numbers. I want to create a query that returns results where any values in the ID fields overlap with any values in the array. For example: lastname: Smith firstname: John id: 101, 103 I have Array #1 with the values 101, 102, 103 I want the query to output all members who have the values 101 or 102 or 103 listed in their id field with multiple ids listed. Array ( [0] => 101 [1] => 102 [2] => 103 ) $sql="SELECT firstname, lastname, id FROM members WHERE id LIKE '%".$array_num_1."%'"; $result=mysql_query($sql); while ($rows=mysql_fetch_array($result)) { echo $rows['lastname'].', '.$rows['firstname'].'-'.$rows['id']; }

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  • Create Chart using PHP-MySQL

    - by Ajith
    I have a mysql table - request_events with three fields; request_eventsid,datetime,type.this table will track all the activities of my website day wise and also type wise.thus,type may be 1 or 2.I need to display an open-chart for understanding the progress.So I need to retrieve the ratio of type2/type1 as input day wise.How can I get all these input for last 30 days from this table.Please give me some idea....It already kill my week end.Please help me

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  • Get only new RSS entries with PHP Script ?

    - by ArneRie
    What im trying to do: Fetch X numbers of RSS Feeds from my Blogs and echo only new entries. My Problem is, how to know wich items are already parsed? Solution so far: Fetch the Feed every 5 hours, store all titles inside an Database table or flat file. Next run check if the title is already in database if not print it and save it inside the database. But iam not sure if this is best practise to do this? If someone knows a fast way, it would be great. Sorry for my poor english.

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  • INSERT INTO error MYSQL/PHP

    - by bat
    I get this error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order (total, addy, cc) VALUES ('798' , '123 sadf' , '12124123')' at line 1 $total = addslashes(($_SESSION['total'])); $addy = addslashes(($_POST['addy'])); $cc = addslashes(($_POST['cc'])); echo "$total"; echo "$addy"; echo "$cc"; mysql_query("INSERT INTO order (total, addy, cc) VALUES ('$total' , '$addy' , '$cc')") or die(mysql_error()); help plz =]

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  • PHP search multidimensional array for value, then place that element at start of array

    - by BobFlemming
    I need to search this array: cars - [0] -make : Ford -model: Escort -year: 1991 [1] -make: Honda -model: Civic -year: 1996 [2] -make: Vauxhall -model: Astra -year: 1972 And if (for example) the model is "Civic" , place that 'car' at position 0. So the end array would be like: cars - [0] -make: Honda -model: Civic -year: 1996 [1] -make : Ford -model: Escort -year: 1991 [2] -make: Vauxhall -model: Astra -year: 1972 I've tried some usort variations: function typeSort($a, $b) { if ($a['model'] == 'Civic' ) { return 0; } return ($a['model'] < $b['model']) ? -1 : 1; } but this is just returning 1

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