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  • Display PHP Query Array in the table

    - by Jerry
    Hi all I would like to display my Query from Mysql on the table. However, my data is like this: Array([0]=>data1, [1]=>data2, [2]=>data3,[3]=>data4,[4]=>pic1,[5]=>pic2,[6]=>pic3,[7]=>pic4); I want to display my table as |data1 | data2 |data3 |data4 |pic1 | pic2 |pic3 |pic4 I know how to display the data in the single ling like td or tr but not sure how to do tr and td on the same loop. Any helps? Thanks in advance! while($query=mysql_fetch_array($dataQuery)){ //not sure what to do here. }

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  • Dividing numbers between rows in MySQL + PHP

    - by André Figueira
    Hi I am working on a kind of raffle system which divides 1 million random numbers into an x amount of tickets, e.g. 1 million random numbers to 10,000 tickets. Each ticket is a row in a database, we then have another table ticket numbers in which i need to give 100 numbers to each ticket they are related by the ticket id. So at the moment this is my code: //Amount of the 1 million tickets divided to the tickets $numbersPerTickets = $_POST['numbersPerTicket']; //The total cost of the property $propertyPrice = $_POST['propertyPrice']; //The total amount of tickets $totalTickets = NUMBER_CIELING / $numbersPerTickets; //The ticket price $ticketPrice = $propertyPrice / $totalTickets; //Generate array with random numbers up to 999,999 $randomTicketNumbers = createTicketNumbers(); //Creation loop counter $ticketCreationCount = 1; //Loop and create each ticket while($ticketCreationCount <= $totalTickets) { //Create a padded ticket number $ticketNumber = str_pad($ticketCreationCount, 6, 0, STR_PAD_LEFT); $query = ' INSERT INTO tickets( propertyID, ticketNumber, price ) VALUES( "'.$propertyID.'", "'.$ticketNumber.'", "'.$ticketPrice.'" ) '; $db->query($query); //Get the ID of the inserted ticket to use to insert the ticket numbers $ticketID = $db->insert_id; $loopBreak = $numbersPerTickets; $addedNumberCount = 1; foreach($randomTicketNumbers as $key => $value) { $query = ' INSERT INTO ticketNumbers( ticketID, number ) VALUES( "'.$ticketID.'", "'.$value.'" ) '; $db->query($query); unset($randomTicketNumbers[$key]); if($addedNumberCount == $loopBreak){ break; }else{ $addedNumberCount++; } } $ticketCreationCount++; } But this isn't working it adds the right amount of tickets, which in the case for testing is 10,000 but then adds far too many ticket numbers, it ends up exceeding the million numbers in the random tickets array, The random tickets array is just a simple 1 tier array with 1 million numbers sorted randomly.

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  • PHP explode and set to empty string the missing pieces

    - by Marco Demaio
    What's the best way to accomplish the following. I have strings in this format: $s1 = "name1|type1"; //(pipe is the separator) $s2 = "name2|type2"; $s3 = "name3"; //(in some of them type can be missing) Let's assume namen/typen are strings and they can not contain a pipe. Since I need to exctract the name/type separetly, I do: $temp = explode($s1, '|'); $name = $temp[0]; $type = ( isset($temp[1]) ? $temp[1] : '' ); Is there an easier (smarter whatever faster) way to do this without having to do isset($temp[1]) or count($temp). Thanks!

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  • CSV file read fail (PHP )

    - by user1020069
    I am trying to read a csv file (delimited by commas) but unfortunately, it isn't responding as it ought to. I am not so sure what I am doing wrong here, but I'll paste out the contents of the code and the CSV file both : $row = 0; if($handle = fopen("SampleQuizData.csv","r") !== FALSE) { // WORKS UNTIL HERE, SO FILE IS BEING READ while(!feof(handle)){ $line = fgetcsv($handle, 1024, ",") ; echo $line[2]; // DOES NOT WORK } } And the CSV file is (the emails and names have been changed here to protect the identities of the users) parijat,something,[email protected] matthew,durp, [email protected] steve,vai,[email protected] rajni,kanth,[email protected]

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  • sql select with php variable

    - by user1572526
    I'm trying to print out a html-table from db-table 'dimensions'. I only want dimensions from the selected pipetype which I get from a dropdownbox. For now I just put in "Steel" manually. Steel has pipe_id = 2 in db-table 'pipes'. I've run the first query in my db-tool and it returns 2 so there's nothing wrong there. The second query returns nothing. But when I manually set $wq = 2 (which I comment out below) it prints out the html-table perfectly. What am I doing wrong here? $wq="SELECT pipe_id FROM pipes WHERE title_en = 'Steel'"; //$wq = '2'; $sql="SELECT * FROM dimensions WHERE pipe_id = '".$wq."'";

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  • jquerycropping,codiegniter,php

    - by user345804
    I want to crop the image using jquery,codigniter in jquery i get four coordinate of image x1=249 x2=326 y1=194 y2=271 w=77 h=77 in codiegniter done the query function do_crop() { $x=249; $y=194; $w=77; $h=77; $path= 'system/application/'; $config = array( 'image_library' => 'gd2', 'source_image' => $path.'/jag1/flowers.jpg' , 'new_image' => $path.'/jag2/flowers.jpg', 'maintain_ration' => false, 'width' => $w, 'height' => $h, 'x_axis' => $x, 'y_axis' => $y ); $this->load->library('image_lib'); $this->image_lib->initialize($config); if ( ! $this->image_lib->crop()) { echo $this->image_lib->display_errors(); } $this->image_lib->clear(); } i get cropped image. But problem is don't get exact cropped image x,y coordinate problem

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  • get all fields value from mysql using php

    - by zahir hussain
    hi i want to know how to get all fields value search by array. i have array that s my table is id content 1 zahr 2 hai . . . and so on $a = {2,3,4,5,43,32}; i have to take the contents by this id(from array "a"). i know, i can use "for" loop for getting each element from mysql. but i would like to use any filters or any predefined function thanks and advance

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  • JSON Returning Null in PHP

    - by kira423
    Here is the two scripts I have Script 1: if(sha1($json+$secret) == $_POST['signature']) { $conversion_id = md5(($obj['amount'])); echo "OK"; echo $conversion_id; mysql_query("INSERT INTO completed (`id`,`uid`,`completedid`) VALUES ('','".$obj['uid']."','".$conversion_id."')"); } else { } ?> Script 2: <? $json = $_POST['payload']; $secret = "78f12668216b562a79d46b170dc59f695070e532"; $obj = json_decode($json); if(sha1($json+$secret) == $_POST['signature']) { print "OK"; } else { } ?> The problem here is that it is returning all NULL values. I am not an expert with JSON so I have no idea what is going on here. I really have no way of testing it because the information is coming from an outside website sending information such as this: { payload: { uid: "900af657a65e", amount: 50, adjusted_amount: 25 }, signature: "4dd0f5da77ecaf88628967bbd91d9506" } The site allows me to test the script, but because json_decode is providing NULL values it will not get through the signature block. Is there a way I can test it myself? Or is there a simple error in this script that I may have just looked over?

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  • php | Multidimensional array sorting

    - by user889349
    I have an array and need to be sorted (based on id): Array ( [0] => Array ( [qty] => 1 [id] => 3 [name] => Name1 [sku] => Model 1 [options] => [price] => 100.00 ) [1] => Array ( [qty] => 2 [id] => 1 [name] => Name2 [sku] => Model 1 [options] => Color: <em>Black (+10$)</em>. Memory: <em>32GB (+99$)</em>. [price] => 209.00 ) ) Is it possible to sort my array to get output (id based)? Array ( [0] => Array ( [qty] => 2 [id] => 1 [name] => Name2 [sku] => Model 1 [options] => Color: <em>Black (+10$)</em>. Memory: <em>32GB (+99$)</em>. [price] => 209.00 ) [1] => Array ( [qty] => 1 [id] => 3 [name] => Name1 [sku] => Model 1 [options] => [price] => 100.00 ) ) Thanks!

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  • htaccess in php

    - by Badshah
    I am using htaccess in my projec.there is login section i want to show the my account page as http:///www/domain.com/username . But there is a problem because i have also made a cms which is open as http:///www/domain.com/cms . Although i have validate the user name But there is same page open when i open the cms or user profile page. I have pass the regular expression in htaccess but stil not required result is come

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  • Regex: Match words in sentence PHP

    - by Granit Luzhnica
    Hi, I have an array with words like $arr = arra("go", "walk", ...) I would like to replace these words with links f they are matched in sentences. But it should be only if they match exactly (for example "walk" should match "Walk" or "walk!" but not also "walking") And the replacement should be a simple link like: < a href='#walk' walk< /a Anybody Any idea?

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  • PHP: prepared statement, IF statement help needed

    - by JGreig
    I have the following code: $sql = "SELECT name, address, city FROM tableA, tableB WHERE tableA.id = tableB.id"; if (isset($price) ) { $sql = $sql . ' AND price = :price '; } if (isset($sqft) ) { $sql = $sql . ' AND sqft >= :sqft '; } if (isset($bedrooms) ) { $sql = $sql . ' AND bedrooms >= :bedrooms '; } $stmt = $dbh->prepare($sql); if (isset($price) ) { $stmt->bindParam(':price', $price); } if (isset($sqft) ) { $stmt->bindParam(':price', $price); } if (isset($bedrooms) ) { $stmt->bindParam(':bedrooms', $bedrooms); } $stmt->execute(); $result_set = $stmt->fetchAll(PDO::FETCH_ASSOC); What I notice is the redundant multiple IF statements I have. Question: is there any way to clean up my code so that I don't have these multiple IF statements for prepared statements?

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  • PHP - Get a specific value in an array

    - by Charles Yeung
    Hi Suppose I have the code below: [taxonomy] => Array ( [118] => stdClass Object ( [tid] => 118 [vid] => 4 [name] => A [description] => [weight] => 4 ) [150] => stdClass Object ( [tid] => 150 [vid] => 5 [name] => B [description] => [weight] => 0 ) ) How can I only get the tid number and exclude others, could someone please give me a suggestion? Thanks you

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  • declare or convert a string to array format PHP

    - by Jamex
    How to convert a string format into an array format? I have a string, $string = 'abcde' I want to convert it to a 1 element array $string[0] = 'abcde' Is there a built in function for this task? Or the shortest way is to $string = 'abcde'; $array[0] = $string; $string = $array; TIA

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