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  • Paypal subscription trial extra charge?

    - by DucDigital
    I tried to implement paypal pro for my site. Which will let user enter their info and charge 1$ for the trial, and 10$ for the recursive fee. But when I check my merchant account, it show up 1$ and 10$ in separate order, but within 1 day (it charge 10$ that I don't want) PROFILEID=I%2d0xxxxxx1HCKEF &PROFILESTATUS=PendingProfile &TRANSACTIONID=0NP43842KS810000T &TIMESTAMP=2010%2d05%2d16T18%3a56%3a55Z &CORRELATIONID=89adac79d0d6 &ACK=Success &VERSION=57%2e0 &BUILD=1298200 &METHOD=CreateRecurringPaymentsProfile &VERSION=57.0 &PWD=1274sss7 &USER=sand_12sdsad7629_biz_api1.dital.com &SIGNATURE=IacdATZe5XHmKJs1n2w3uWMRDWyaOGDb &PAYMENTACTION=Sale &AMT=10 &CREDITCARDTYPE=Visa &ACCT=4804270925925835 &EXPDATE=052015 &CVV2=243 &FIRSTNAME= &LASTNAME= &STREET=223232323 &CITY=3232 &STATE=IA &ZIP=5452 &COUNTRYCODE=US &CURRENCYCODE=USD &BILLINGPERIOD=Month &BILLINGFREQUENCY=1 &PROFILESTARTDATE=2010-05-6+02%3A56%3A57 &INITAMT=10 &FAILEDINITAMTACTION=ContinueOnFailure &DESC=Recurring+%2410 &AUTOBILLAMT=AddToNextBilling &PROFILEREFERENCE=Anonymous &TRIALBILLINGPERIOD=Day &TRIALBILLINGFREQUENCY=5 &TRIALAMT=1 &TRIALTOTALBILLINGCYCLES=1 &SALUTE=Mr. &EMAIL=dsads%40dsads.com Was there any problem with this query string?

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  • Querying Two Tables At Once

    - by John
    Hello, I am trying to do what I believe is called a join query. First, in a MySQL table called "login," I want to look up what "loginid" is in the record where "username" equals $profile. (This will be just one record / row in the MySQL table). Then, I want to take that "loginid" and look up all rows / records in a different MySQL table called "submission," and pull data that have that "loginid." This could possibly be more than one record / row. How do I do this? The code below doesn't seem to work. Thanks in advance, John $profile = mysql_real_escape_string($_GET['profile']); $sqlStr = "SELECT l.username, l.loginid, s.loginid, s.submissionid, s.title, s.url, s.datesubmitted, s.displayurl FROM submission AS s, login AS l WHERE l.username = '$profile', s.loginid = l.loginid ORDER BY s.datesubmitted DESC";

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  • How to optimize this user ranking query

    - by James Simpson
    I have 2 databases (users, userRankings) for a system that needs to have rankings updated every 10 minutes. I use the following code to update these rankings which works fairly well, but there is still a full table scan involved which slows things down with a few hundred thousand users. mysql_query("TRUNCATE TABLE userRankings"); mysql_query("INSERT INTO userRankings (userid) SELECT id FROM users ORDER BY score DESC"); mysql_query("UPDATE users a, userRankings b SET a.rank = b.rank WHERE a.id = b.userid"); In the userRankings table, rank is the primary key and userid is an index. Both tables are MyISAM (I've wondered if it might be beneficial to make userRankings InnoDB).

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  • Wordpress: Sort posts by meta value after AFTER querying from database

    - by Joseph Carrington
    Hello, I am pulling posts from my database by using Wordpress' WP_Query object like so: $shows_query = new WP_Query("category_name=shows&meta_key=band&meta_value=$artist_id"); I have another meta value I would like to sort the posts by, however. The meta key is 'date'. The WP_Query object can no work with multiple meta_keys, so this does not work: $shows_query = new WP_Query("category_name=shows&meta_key=band&meta_value=$artist_id&meta_key=date&orderby=meta_value&order=DESC"); So now I have to figure out a way to sort the posts in $shows_query['posts'] by one of their meta_values, which are not even IN their array. Any other, more sensible approach would also be appreciated.

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  • Display field from another table in SQL

    - by Roland Bengtsson
    I'm a newbie with SQL... Now I want to do display some instances of AddrDistances from DevExpress CxGrid with SQL. Select Cast((DistanceAsMeters * 0.001) as Decimal(8,1)) DistanceAsKm, bold_id, created, fromAddress, toAddress From AddrDistance Where DistanceAsMeters = 0 and PseudoDistanceAsCostKm = 0 and not AddrDistance.bold_id in (select bold_id from DistanceQueryTask) Order By Created Desc This SQL is working and the result is: DistanceAsKM Bold_ID Created FromAddress ToAddress 0 134808 16.02.2010 121795 134570 0 121701 10.03.2010 120850 122991 The result I want is this: DistanceAsKM Bold_ID Created FromAddress ToAddress 0 134808 16.02.2010 Kalmar Stockholm 0 121701 10.03.2010 Falkenberg Oslo So the amount of rows is right but I want to replace the numbers in FromAddress and ToAddress with strings from another table. The numbers shows here is just the boldid. Every object in the database have an unique boldid. The addresses above is stored in table Address and it have a City field with the column and a boldid as a key. What should I write in SQL to get this right ? Is there something in the CxGrid that could help here ? Regards

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  • How to add an self defined attribute to ldap user?

    - by Arnab Das
    Hi, I have created an attribute in LDAP using the following code. attrs.put("NUMERICOID", "1.3.6.1.4.1.42.2.27.4.2.3.1.1.9"); attrs.put("NAME", "myattribute"); attrs.put("DESC", "for JNDITutorial example only"); attrs.put("SYNTAX", "1.3.6.1.4.1.1466.115.121.1.15"); DirContext schema = context.getSchema(""); DirContext newAttr = schema.createSubcontext ("AttributeDefinition/myattribute1", attrs); The attribute is created successfully, Now I am trying to add this attribute to a user say "user1"(uid). Attributes attributeslist = context.getAttributes(ld.getUserDN(username)); attributeslist.put("myattribute1", ""); context.modifyAttributes(ld.getUserDN("test5"), DirContext.REPLACE_ATTRIBUTE, attributeslist); But it gives me object class violation error. Can anyone help me to solve this? I need to add an user defined attribut to the user using java code.

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  • MySQL ALTER TABLE on very large table - is it safe to run it?

    - by Timothy Mifsud
    I have a MySQL database with one particular MyISAM table of above 4 million rows. I update this table about once a week with about 2000 new rows. After updating, I then perform the following statement: ALTER TABLE x ORDER BY PK DESC i.e. I order the table in question by the primary key field in descending order. This has not given me any problems on my development machine (Windows with 3GB memory), but, even though 3 times I have tried it successfully on the production Linux server (with 512MB RAM - and achieving the resulted sorted table in about 6 minutes each time), the last time I tried it I had to stop the query after about 30 minutes and rebuild the database from a backup. I have started to wonder whether a 512MB server can cope with that statement (on such a large table) as I have read that a temporary table is created to perform the ALTER TABLE command?! And, if it can be safely run, what should be the expected time for the alteration of the table? Thanks in advance, Tim

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  • MySQL easy question CURDATE()

    - by Tristan
    I want to compare two results one is stored in the first query, and the other is exactly the same as the first, but i want only to recieve data < today "SELECT s.GSP_nom as nom, timestamp, COUNT(s.GSP_nom) as nb_votes, AVG(v.vote+v.prix+v.serviceClient+v.interface+v.interface+v.services)/6 as moy FROM votes_serveur AS v INNER JOIN serveur AS s ON v.idServ = s.idServ WHERE s.valide = 1 AND v.date < CURDATE() ROUP BY s.GSP_nom HAVING nb_votes > 9 ORDER BY moy DESC LIMIT 0,15"; is that correct ? thank you

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  • Losing NSManaged Objects in my Application

    - by Wayfarer
    I've been doing quite a bit of work on a fun little iPhone app. At one point, I get a bunch of player objects from my Persistant store, and then display them on the screen. I also have the options of adding new player objects (their just custom UIButtons) and removing selected players. However, I believe I'm running into some memory management issues, in that somehow the app is not saving which "players" are being displayed. Example: I have 4 players shown, I select them all and then delete them all. They all disappear. But if I exit and then reopen the application, they all are there again. As though they had never left. So somewhere in my code, they are not "really" getting removed. MagicApp201AppDelegate *appDelegate = [[UIApplication sharedApplication] delegate]; context = [appDelegate managedObjectContext]; NSFetchRequest *request = [[NSFetchRequest alloc] init]; NSEntityDescription *desc = [NSEntityDescription entityForName:@"Player" inManagedObjectContext:context]; [request setEntity:desc]; NSError *error; NSMutableArray *objects = [[[context executeFetchRequest:request error:&error] mutableCopy] autorelease]; if (objects == nil) { NSLog(@"Shit man, there was an error taking out the single player object when the view did load. ", error); } int j = 0; while (j < [objects count]) { if ([[[objects objectAtIndex:j] valueForKey:@"currentMultiPlayer"] boolValue] == NO) { [objects removeObjectAtIndex:j]; j--; } else { j++; } } [self setPlayers:objects]; //This is a must, it NEEDS to work Objects are all the players playing So in this snippit (in the viewdidLoad method), I grab the players out of the persistant store, and then remove the objects I don't want (those whose boolValue is NO), and the rest are kept. This works, I'm pretty sure. I think the issue is where I remove the players. Here is that code: NSLog(@"Remove players"); /** For each selected player: Unselect them (remove them from SelectedPlayers) Remove the button from the view Remove the button object from the array Remove the player from Players */ NSLog(@"Debugging Removal: %d", [selectedPlayers count]); for (int i=0; i < [selectedPlayers count]; i++) { NSManagedObject *rPlayer = [selectedPlayers objectAtIndex:i]; [rPlayer setValue:[NSNumber numberWithBool:NO] forKey:@"currentMultiPlayer"]; int index = [players indexOfObjectIdenticalTo:rPlayer]; //this is the index we need for (int j = (index + 1); j < [players count]; j++) { UIButton *tempButton = [playerButtons objectAtIndex:j]; tempButton.tag--; } NSError *error; if ([context hasChanges] && ![context save:&error]) { NSLog(@"Unresolved error %@, %@", error, [error userInfo]); abort(); } UIButton *aButton = [playerButtons objectAtIndex:index]; [players removeObjectAtIndex:index]; [aButton removeFromSuperview]; [playerButtons removeObjectAtIndex:index]; } [selectedPlayers removeAllObjects]; NSError *error; if ([context hasChanges] && ![context save:&error]) { NSLog(@"Unresolved error %@, %@", error, [error userInfo]); abort(); } NSLog(@"About to refresh YES"); [self refreshAllPlayers:YES]; The big part in the second code snippet is I set them to NO for currentMultiPlayer. NO NO NO NO NO, they should NOT come back when the view does load, NEVER ever ever. Not until I say so. No other relevant part of the code sets that to YES. Which makes me think... perhaps they aren't being saved. Perhaps that doesn't save, perhaps those objects aren't being managed anymore, and so they don't get saved in. Is there a lifetime (metaphorically) of NSManaged object? The Players array is the same I set in the "viewDidLoad" method, and SelectedPlayers holds players that are selected, references to NSManagedObjects. Does it have something to do with Removing them from the array? I'm so confused, some insight would be greatly appreciated!!

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  • MySql - Select from - Don't Show Duplicate Words - maybe "on duplicate key"?

    - by ali
    hi, how can I insert "on duplicate key" in this Code to remove duplicate words? or is there a better method that you know? thank you!! this is my code: function sm_list_recent_searches($before = '', $after = '', $count = 20) { // List the most recent successful searches. global $wpdb, $table_prefix; $count = intval($count); $results = $wpdb->get_results( "SELECT `terms`, `datetime` FROM `{$table_prefix}searchmeter_recent` WHERE 3 < `hits` AND CHAR_LENGTH(`terms`) > 4 ORDER BY `datetime` DESC LIMIT $count"); if (count($results)) { foreach ($results as $result) { echo '<a href="'. get_settings('home') . '/search/' . urlencode($result->terms) . '">'. htmlspecialchars($result->terms) .'</a>'.", "; } } }

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  • How do I get hyphens in my attribute names in Flex?

    - by John Leonard
    Flex has an issue with hyphens in xml. I need to generate an xml object with hyphens in the attribute for a Google Checkout implementation. I can get away with: var xml:XML = <item-description/>; and var xml:XML = <item-description the-name="foo"/>; but what I need to do is set the value of an attribute like this: var timestamp:String = methodToGetMyTimestampString(); var xml:XML = <item-desc/>; xml@start-date = timestamp; but I can't do that. Since flex doesn't like the hyphens, I don't know how to get or set attributes with hyphens in the name.

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  • Capistrano 3, Rails 4, database configuration does not specify adapter

    - by Kazmin
    When I start cap production deploy it fails like this: DEBUG [4ee8fa7a] Command: cd /home/deploy/myapp/releases/releases/20131025212110 && (RVM_BIN_PATH=~/.rvm/bin RAILS_ENV= ~/.rvm/bin/myapp_rake assets:precompile ) DEBUG [4ee8fa7a] rake aborted! DEBUG [4ee8fa7a] database configuration does not specify adapter You can see that "RAILS_ENV=" is actually empty and I'm wondering why that might be happening? I assume that this is the reason for the latter error that I don't have a database configuration. The deploy.rb file is below: set :application, 'myapp' set :repo_url, '[email protected]:developer/myapp.git' set :branch, :master set :deploy_to, '/home/deploy/myapp/releases' set :scm, :git set :devpath, "/home/deploy/myapp_development" set :user, "deploy" set :use_sudo, false set :default_env, { rvm_bin_path: '~/.rvm/bin' } set :keep_releases, 5 namespace :deploy do desc 'Restart application' task :restart do on roles(:app), in: :sequence, wait: 5 do # Your restart mechanism here, for example: within release_path do execute " bundle exec thin restart -O -C config/thin/production.yml" end end end after :restart, :clear_cache do on roles(:web), in: :groups, limit: 3, wait: 10 do within release_path do end end end after :finishing, 'deploy:cleanup' end?

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  • Append message to JBoss Console using jboss-log4j.xml

    - by Random Joe
    I'm unable to append messages from my application to the JBoss console. The following are the changes that I made to the jboss-log4j.xml configuration file: <category name="com.tricubes"> <priority value="INFO"/> <appender-ref ref="CONSOLE"/> </category> Here is my code: public class OneToOneValidation2 { private static final Logger logger = Logger.getLogger("com.tricubes"); public boolean validate(byte[] fpImage, byte[] fpTemplate, String desc, String ticket) { ... logger.info("BES INFO: SOCKET MSG SENT " + intToByteArray(x)); ... return b; } } What am I missing? TIA!

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  • function and class to show image not working in php

    - by Gully
    i am trying to get get the following working nothing is happen when i use the function i am trying to get it to display images class ItemRes { //items DB var $img=""; } function ShowItemImage($index,$res_a){ if(sizeof($res_a) > $index){ if($res_a[$index] != NULL) { $cimg = $res_a[$index]->img; return "<img src='$cimg' width='70' height='70' style='cursor:pointer'></img>"; } }else{ return "<center class='whitetxt'><strong>Empty</strong></center>"; } } $res_array = array(); $idx=0; $result21 = mysql_query("SELECT * FROM photos WHERE eid='$eid' ORDER BY id DESC") or die (mysql_error()); while ($row21 = mysql_fetch_array($result21)) { $img_path = $row21['path']; $obj = new ItemRes(); $obj->img = $img_path; $res_array[$idx] = $obj; $idx++; } ShowItemImage(0,$res_array) ShowItemImage(1,$res_array)

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  • How to skip all the column names in MySQL when the table has auto increment primary key?

    - by Jian Lin
    A table is: mysql> desc gifts; +---------------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------------+-------------+------+-----+---------+----------------+ | giftID | int(11) | NO | PRI | NULL | auto_increment | | name | varchar(80) | YES | | NULL | | | filename | varchar(80) | YES | | NULL | | | effectiveTime | datetime | YES | | NULL | | +---------------+-------------+------+-----+---------+----------------+ the following is ok: mysql> insert into gifts -> values (10, "heart", "heart_shape.jpg", now()); Query OK, 1 row affected (0.05 sec) but is there a way to not specify the "10"... and just let each one be 11, 12, 13... ? I can do it using mysql> insert into gifts (name, filename, effectiveTime) -> values ("coffee", "coffee123.jpg", now()); Query OK, 1 row affected (0.00 sec) but the column names need to be all specified. Is there a way that they don't have to be specified and the auto increment of primary key still works? thanks.

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  • Syntax for combining joins in mysql

    - by UltraVi01
    I seem to remember reading somewhere that there is a way to combine LEFT JOIN statements into a more simple query. I have the following query and was hoping someone could kindly take a look at it. SET @userId = 8; SELECT ug.user_id, COUNT(DISTINCT goal_id) as matches FROM user_goal ug, user u, profile p LEFT JOIN user_block ub ON @userId = ub.blocked_id LEFT JOIN user_block ub2 ON @userId = ub2.blocker_id LEFT JOIN user_user uu ON @userId = uu.user_id LEFT JOIN friend_request fr ON @userId = fr.user_id WHERE ug.user_id = u.id AND u.profile_id = p.id AND (ub.blocker_id IS NULL OR ub.blocker_id != ug.user_id) AND (ub2.blocked_id IS NULL OR ub2.blocked_id != ug.user_id) AND (uu.user_friends_id IS NULL OR uu.user_friends_id != ug.user_id) AND (fr.to_user_id IS NULL OR (fr.to_user_id != ug.user_id)) AND ug.user_id!=@userId AND p.suggestible AND goal_id IN (SELECT iug.goal_id FROM user_goal iug WHERE user_id=@userId) GROUP BY user_id ORDER BY matches DESC LIMIT 4

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  • Wordpress Database SQL query help needed

    - by i-CONICA
    Hi, I've written a PHP script to access the latest item from the wordpress database, which it does. But I need to use it twice, once for the latest item from a specific category, and another from a differerent category... But right now I cannot figure out how to put the query together. The post has a post_parent, which in another table, called wp_term_relationships, is referred to as object_id, and has a term_taxonomy_id, which then relates to a different table, called wp_terms where the term_taxonomy_id is now term_id and then you have the category slug name available to select... I really cannot understand how this query would work though. I've made a really crap mock up of it, to try to "visually" explain what i'm trying to do... SELECT * FROM wp_posts WHERE post_status = 'publish' AND (SELECT term_taxonomy_id FROM wp_term_relationships WHERE object_id = post_parent) AND (SELECT slug FROM wp_terms WHERE term_id = term_taxonomy_id) ORDER BY ID DESC LIMIT 1 Really would appreciate some help... Thanks.

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  • facebook messages result set like part 2

    - by David
    Hey guys, I don't think I'm getting it right. Here is my most recent query that I believe is almost working. SELECT max(sender_id) as sender_id, subject, MAX(id) as message_id, MAX(created_at) as updated_at FROM messages where (recipient_id = #{current_user} and recipient_deleted = 'f') or sender_id = #{current_user} GROUP BY subject ORDER BY max(created_at) DESC ; Basically the goal is to fetch all recent messages of a user, group them by subject, and make sure that the photo that is showing up is the other party's photo, never the current user. (also need the most recent message body and message count but that is for another time) Here is what I think is wrong. doing max(sender_id) is wrong, since the current_user id could be higher than the sender's id. I am using the sender_id in the html page to fetch the user's photo.

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  • How do i put this chunk of code into a php variable?

    - by Theron Chong
    if (isset($_SESSION['name'])){ //select BID and duedates which are between the range of 1-3 days // before due date from current date $query = "SELECT DueDate FROM item WHERE DueDate BETWEEN '$warning2' and '$warning' and user='$_SESSION[name]' ORDER BY DueDate DESC"; $find = mysql_query($query); $alert = mysql_num_rows($find); if ($alert>=1){ echo "You have got " .$alert. " item(s) due on: </br >"; while ($item = mysql_fetch_array($find)){ echo $item['DueDate']; echo "<br />"; } } echo "Success!"; } Question: How do i input all this code into a single php variable, say $alert. I am not clear of where to put single quotes or double quotes to make it work. At the end of the day, I will be using the variable for a javascript alert box.

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  • MySQL Rank Not Matching High Score in Table

    - by boddie
    While making a game the MySQL call to get the top 10 is as follows: SELECT username, score FROM userinfo ORDER BY score DESC LIMIT 10 This seems to work decently enough, but when paired with a call to get a individual player's rank the numbers may be different if the player has a tied score with other players. The call to get the players rank is as follows: SELECT (SELECT COUNT(*) FROM userinfo ui WHERE (ui.score, ui.username) >= (uo.score, uo.username)) AS rank FROM userinfo uo WHERE username='boddie'; Example results from first call: +------------+-------+ | username | score | +------------+-------+ | admin | 4878 | | test3 | 3456 | | char | 785 | | test2 | 456 | | test1 | 253 | | test4 | 78 | | test7 | 0 | | boddie | 0 | | Lz | 0 | | char1 | 0 | +------------+-------+ Example results from second call +------+ | rank | +------+ | 10 | +------+ As can be seen, the first call ranks the player at number 8 on the list, but the second call puts him at number 10. What changes or what can I do to make these calls give matching results? Thank you in advance for any help!

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  • Can't use where clause on correlated columns.

    - by Keyo
    I want to add a where clause to make sure video_count is greater than zero. Only categories which are referenced once or more in video_category.video_id should be returned. Because video_count is not a field in any table I cannot do this. Here is the query. SELECT category . * , ( SELECT COUNT( * ) FROM video_category WHERE video_category.category_id = category.category_id ) AS 'video_count' FROM category WHERE category.status = 1 AND video_count > '0' AND publish_date < NOW() ORDER BY updated DESC; Thanks for the help.

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  • Google App Engine update an object from servlet not working ?

    - by Frank
    I use the following code to update an object from servlet in Google App Engine : String Time_Stamp=Get_Date_Format(6),query="select from "+Contact_Info_Entry.class.getName()+" where Contact_Id == '"+Contact_Id+"' order by Contact_Id desc"; PersistenceManager pm=null; try { pm=PMF.get().getPersistenceManager(); // note that this returns a list, there could be multiple, DataStore does not ensure uniqueness for non-primary key fields List<Contact_Info_Entry> results=(List<Contact_Info_Entry>)pm.newQuery(query).execute(); Contact_Info_Entry A_Contact_Entry=results.get(0); A_Contact_Entry.Extra_10=Time_Stamp; pm.makePersistent(A_Contact_Entry); } catch (Exception e) { Send_Email(Email_From,Email_To,"Check_License_Servlet Error [ "+Time_Stamp+" ]",new Text(e.toString()+"\n"+Get_Stack_Trace(e)),null); } finally { pm.close(); } The value "[ 2010-05-13 Thu 15:58:31 ]" was in A_Contact_Entry.Extra_10, but it seems "pm.makePersistent(A_Contact_Entry);" was not executed. The object was not updated and there was no error message, why ? How to fix it ?

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  • How to retrieve the ordered list of best articles having a minimum number of votes by using HSQL ?

    - by fabien7474
    I have a Vote domain class from my grails application containing properties like article_id and note I want to HQL query the Vote domain class in order to retrieve the 5 best rated articles having at least 10 votes. I tried : SELECT v.article_id, avg(v.note), count(*) FROM vote v where count(*) >= 10 group by v.article_id order by avg(v.note) desc limit 5; But unfortunately the insertion of where count(*) >= 10 throws an error. How can I do that in a simple way? Thank you for your help.

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  • Nested mysql select statements

    - by Jimmy Kamau
    I have a query as below: $sult = mysql_query("select * from stories where `categ` = 'businessnews' and `stryid`='".mysql_query("SELECT * FROM comments WHERE `comto`='".mysql_query("select * from stories where `categ` ='businessnews'")." ORDER BY COUNT(comto) DESC")."' LIMIT 3") or die(mysql_error()); while($ow=mysql_fetch_array($sult)){ The code above should return the top 3 'stories' with the most comments {count(comto)}. The comments are stored in a different table from the stories. The code above does not return any values and doesn't show any errors. Could someone please help?

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  • Echoing a pseudo column value after a COUNT

    - by rob - not a robber
    Hi Gang... Please don't beat me if this is elementary. I searched and found disjointed stuff relating to pseudo columns. Nothing spot on about what I need. Anyway... I have a table with some rows. Each record has a unique ID, an ID that relates to another entity and finally a comment that relates to that last entity. So, I want to COUNT these rows to basically find what entity has the most comments. Instead of me explaining the query, I'll print it SELECT entity_id, COUNT(*) AS amount FROM comments GROUP BY entity_id ORDER BY amount DESC The query does just what I want, but I want to echo the values from that pseudo column, 'amount' Can it be done, or should I use another method like mysql_num_rows? Thank you!!!

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