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  • How to query Entities in Entity Framework 4

    - by Picflight
    In VS2008, I think it is EF1.0, this works just fine. string queryString = @"SELECT VALUE USERS FROM ProjectDBEntities.Users AS User INNER JOIN ProjectDBEntities.Favorites AS F ON F.FavUserId = User.UserId WHERE F.UserId = " + 3 + " ORDER BY F.CreateDate DESC "; System.Data.Objects.ObjectQuery<User> usersQuery = new System.Data.Objects.ObjectQuery<User>(queryString, context).Include("Detail"); //int count = usersQuery.Count(); foreach (User result in usersQuery) Console.WriteLine("User Name: {0}", result.UserName); Same code in VS2010 EF4 it crashes on the foreach loop with the following error: The result type of the query is neither an EntityType nor a CollectionType with an entity element type. An Include path can only be specified for a query with one of these result types.

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  • Coldfusion 8: Array of structs to struct of structs

    - by davidosomething
    I've got an array items[] Each item in items[] is a struct. item has keys id, date, value (i.e., item.id, item.date, item.value) I want to use StructSort to sort the item collection by a date Is this the best way to do it in ColdFusion 8: <cfset allStructs = StructNew()> <cfloop array = #items# index = "item"> <cfset allStructs[item.id] = item> <cfset unixtime = DateDiff("s", CreateDate(1970,1,1), item.date)> <cfset allStructs[item.id].unixtime = unixtime> </cfloop> <cfset allStructs = StructSort(allStructs, "numeric", "desc", "unixtime")> It's going to be dreadfully slow

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  • Compare two dates with JPA

    - by Kiva
    Hello everybody, I need to compare two dates in a JPQL query but it doesn't work. Here is my query: Query query = em.createQuery("SELECT h FROM PositionHistoric h, SeoDate d WHERE h.primaryKey.siteDb = :site AND h.primaryKey.engineDb = :engine AND h.primaryKey.keywordDb = :keyword AND h.date = d AND d.date <= :date ORDER BY h.date DESC"); My parameter date is a java.util.Date My query return a objects list but the dates are upper and lower to my parameter. Someone kown how to do this ? Thanks.

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  • How to order by a known id value in mysql

    - by markj
    Hi, is it possible to order a select from mysql by using a known id first. Example: $sql = "SELECT id, name, date FROM TABLE ORDER BY "id(10)", id DESC Not sure if the above makes sense but what I would like to do is first start ordering by the known id which is 10 which I placed in quotes "id(10)". I know that cannot work as is in the query but it's just to point out what I am trying to do. If something similar can work I would appreciate it. Thanks.

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  • sorting and paging with gridview asp.net

    - by dangerisgo
    I'm trying to get a gridview to sort and page manually with no success. The problem is that when a user clicks the column they want to sort, it sorts that page, but doesn't sort the datasource (dataview) behind the gridview. So when they progress to a different page, their sort is lost. Pretty much I'm looking for a sort that will actually sort the datasource behind the gridview. Here is what I have so far: protected void GridView_OnSort(object sender, GridViewSortEventArgs e) { String sortExpression = e.SortExpression; if (GridViewSortDirection == SortDirection.Ascending) { DataView myDataView = new DataView(mybll.GetItemsOrdered()); myDataView.Sort = sortExpression + " DESC"; GridView.DataSource = myDataView; GridView.DataBind(); } else { DataView myDataView = new DataView(mybll.GetItemsOrdered()); myDataView.Sort = sortExpression + " ASC"; GridView.DataSource = myDataView; GridView.DataBind(); } } Any help would be appreciated. Thanks.

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  • will_paginate undefined method error - Ruby on Rails

    - by bgadoci
    I just installed the gem for will_paginate and it says that it was installed successfully. I followed all the instructions listed with the plugin and I am getting an 'undefined method `paginate' for' error. Can't find much in the way of Google search and haven't been able to fix it myself (obviously). Here is the code: PostsController def index @tag_counts = Tag.count(:group => :tag_name, :order => 'updated_at DESC', :limit => 10) @posts = Post.paginate :page => params[:page], :per_page => 50 respond_to do |format| format.html # index.html.erb format.xml { render :xml => @posts } format.json { render :json => @posts } format.atom end end /model/post.rb class Post < ActiveRecord::Base validates_presence_of :body, :title has_many :comments, :dependent => :destroy has_many :tags, :dependent => :destroy cattr_reader :per_page @@per_page = 10 end /posts/views/index.html.erb <%= will_paginate @posts %>

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  • Order by null/not null with ICriteria

    - by Kristoffer
    I'd like to sort my result like this: First I want all rows/objects where a column/property is not null, then all where the colmn/property is null. Then I want to sort by another column/property. How can I do this with ICriteria? Do I have to create my own Order class, or can it be done with existing code? ICriteria criteria = Session.CreateCriteria<MyClass>() .AddOrder(Order.Desc("NullableProperty")) // What do I do here? IProjection? Custom Order class? .AddOrder(Order.Asc("OtherProperty"));

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  • Oracle SELECT TOP 10 records

    - by ArneRie
    Hi, i have an big problem with an SQL Statement in Oracle. I want to select The TOP 10 Records ordered by STORAGE_DB wich arent in a list from an other select statement. This one works fine for all records: SELECT DISTINCT APP_ID, NAME, STORAGE_GB, HISTORY_CREATED, TO_CHAR(HISTORY_DATE, 'DD.MM.YYYY') AS HISTORY_DATE FROM HISTORY WHERE STORAGE_GB IS NOT NULL AND APP_ID NOT IN (SELECT APP_ID FROM HISTORY WHERE TO_CHAR(HISTORY_DATE, 'DD.MM.YYYY') = '06.02.2009') But when i am adding AND ROWNUM <= 10 ORDER BY STORAGE_GB DESC im getting some kind of "random" Records. I think because the limit takes in place before the order. Does someone has an good solution? The other problem: This query is realy slow (10k+ records)

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  • How to optimize this MySQL query

    - by James Simpson
    This query was working fine when the database was small, but now that there are millions of rows in the database, I am realizing I should have looked at optimizing this earlier. It is looking at over 600,000 rows and is Using where; Using temporary; Using filesort (which leads to an execution time of 5-10 seconds). It is using an index on the field 'battle_type.' SELECT username, SUM( outcome ) AS wins, COUNT( * ) - SUM( outcome ) AS losses FROM tblBattleHistory WHERE battle_type = '0' && outcome < '2' GROUP BY username ORDER BY wins DESC , losses ASC , username ASC LIMIT 0 , 50

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  • Yahoo authentication

    - by steve
    Hi - I'm playing around with the new yahoo API. I'd like to scrap some dummy data using the following address http://query.yahooapis.com/v1/public/yql?q=desc%20social.updates.search&format=json&diagnostics=true&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys&callback=cbfunc When I run this I get an authenticaion error (Need to be logged into Yahoo) This is fine obviously for me messing around on the internet. However I'd like to call this from a ruby script. Any ideas how I go about authenticating? I can only seem to find some web enabled version.

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  • Django South Foreign Keys referring to pks with Custom Fields

    - by Rory Hart
    I'm working with a legacy database which uses the MySQL big int so I setup a simple custom model field to handle this: class BigAutoField(models.AutoField): def get_internal_type(self): return "BigAutoField" def db_type(self): return 'bigint AUTO_INCREMENT' # Note this won't work with Oracle. This works fine with django south for the id/pk fields (mysql desc "| id | bigint(20) | NO | PRI | NULL | auto_increment |") but the ForeignKey fields in other models the referring fields are created as int(11) rather than bigint(20). I assume I have to add an introspection rule to the BigAutoField but there doesn't seem to be a mention of this sort of rule in the documentation (http://south.aeracode.org/docs/customfields.html). Update: Currently using Django 1.1.1 and South 0.6.2

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  • A question about the order of pagination

    - by SpawnCxy
    Currently I'm deal with a history message page using Cakephp.And I got a problem about records' order.In the controller,codes about pagination as follows $this->paginate['Msg'] = array('order'=>'Msg.created desc'); $msgs = $this->paginate('Msg'); $this->set('historymsgs',$msgs); Then I got a page of messges like this: tom:I'm eighteen. Jerry:How old are you? tom:Tom. Jerry:what's your name? tom:Hi nice to meet you too! Jerry:Hello,nice to meet you! But what I need is the reversed order of the messages.How can I append a condition of Msg.created asc here? Thanks in advance.

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  • Microsoft T-SQL Counting Consecutive Records

    - by JeffW
    Problem: From the most current day per person, count the number of consecutive days that each person has received 0 points for being good. Sample data to work from : Date Name Points 2010-05-07 Jane 0 2010-05-06 Jane 1 2010-05-07 John 0 2010-05-06 John 0 2010-05-05 John 0 2010-05-04 John 0 2010-05-03 John 1 2010-05-02 John 1 2010-05-01 John 0 Expected answer: Jane was bad on 5/7 but good the day before that. So Jane was only bad 1 day in a row most recently. John was bad on 5/7, again on 5/6, 5/5 and 5/4. He was good on 5/3. So John was bad the last 4 days in a row. Code to create sample data: IF OBJECT_ID('tempdb..#z') IS NOT NULL BEGIN DROP TABLE #z END select getdate() as Date,'John' as Name,0 as Points into #z insert into #z values(getdate()-1,'John',0) insert into #z values(getdate()-2,'John',0) insert into #z values(getdate()-3,'John',0) insert into #z values(getdate()-4,'John',1) insert into #z values(getdate(),'Jane',0) insert into #z values(getdate()-1,'Jane',1) select * from #z order by name,date desc

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  • What is the best database for my needs?

    - by Mr. Flibble
    I am currently using MS SQL Server 2008 but I'm not sure it it is the best system for this particular task. I have a single table like so: PK_ptA PK_ptB DateInserted LookupColA LookupColB ... LookupColF DataCol (ntext) A common query is SELECT TOP(1000000) DataCol FROM table WHERE LookupColA=x AND LookupColD=y AND LookupColE=z ORDER BY DateInserted DESC The table has about a billion rows with 5 million inserted per day. My main problem with SQL Server is that it isn't too easy to shard or spread out the datafiles. Also, exporting seems to max out at 1000rows per second (about 1MB/s) which seems very slow. Another problem I have is, with SQL Server, if I want to add a new LookupCol the log file grows enormously requiring a large amount of rarely used free space on tap. Are there any obvious better solutions for this problem?

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  • Rails - how to use a plugin from github (how to install, utilize, etc)

    - by jyoseph
    I'm trying to install a couple of different plugins for my rails 3 app. I cd to '/vendor/plugins/', then type git clone the_git_src_url. I see the files in the /vendor/plugins/ directory. However when I try to use any of the tags provided by the plugin I get uninitialized constant ContentsController::HTMLToTextileParser PriceTag and html2textile are the two plugins I'm trying to use. This is what triggers the error above: <%= PriceTag.html_to_textile(@content.desc) %> I'm working in development, I've tried to restart the server. Is there something I'm missing?

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  • MYSQL - Group by limit

    - by jono2010
    Hello Is there a simple way to LIMIT the GROUP BY results to the top 2. The following query returns all the results. Using 'LIMIT 2' reduces the overall list to the top 2 entries only. select distinct(rating_name), id_markets, sum(rating_good) 'good', sum(rating_neutral)'neutral', sum(rating_bad) 'bad' from ratings where rating_year=year(curdate()) and rating_week= week(curdate(),1) group by rating_name,id_markets order by rating_name, sum(rating_good) desc Results in the following :- poland 78 48 24 12 <- keep poland 1 15 5 0 <- keep poland 23 12 6 3 poland 2 5 0 0 poland 3 0 5 0 poland 4 0 0 5 ireland 1 9 3 0 <- keep ireland 2 3 0 0 <- keep ireland 3 0 3 0 ireland 4 0 0 3 france 12 24 12 6 <- keep france 1 3 1 0 <- keep france 231 1 0 0 france 2 1 0 0 france 4 0 0 1 france 3 0 1 0 Thanks Jon

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  • complex mysql rank !

    - by silversky
    I have a tb with this col: ein, los, id ... I whant to order the table by this index: win / ( win + los ) * 30 + win / SUM(win) * 70 and then to find the rank for two id's. I'm not very good on mysql, so whath I wrote it's totally wrong: $stmt=$con-prepare("SET @rk := 0"); $stmt=$con-prepare("SELECT rank, id FROM ( SELECT @rk := @rk + 1 AS rank, (win/(win+los)*30+win/SUM(win)*70) AS index, win, los, id FROM tb_name ORDER BY index DESC) as result WHERE id=? AND id=?"); $stmt - bind_param ("ii", $id1, $id2); $stmt - execute(); $stmt - bind_result($rk, $idRk); And also this query it supouse to run maybe every 5-10 sec for every user, so I'm trying to find something very, very fast. if it's necesary I could add, change, delete any column, in order to be as faster as posible.

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  • Gorm findAllBy inside gsp doubt

    - by xain
    Hi, can anybody tell me why this works <g:each var="n" in="${com.pp.News.list()}"> <h2>${n.t}</h2> <p>${n.tx}</p> </g:each> but this doesn't ? <g:set var="news" value="${com.pp.News.findAllByShow(true,[sort:'prio', order:'desc',max:5])}" /> <g:each var="n" in="news"> <h2>${n.t}</h2> <p>${n.tx}</p> </g:each> Part of the exception is Exception Message: No such property: t for class: java.lang.String How can I make it work? Thanks

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  • SQL group and order

    - by John Lambert
    I have multiple users with multiple entries recording times they arrive at destinations Somehow, with my select query I would like to only show the most recent entries for each unique user name. Here is the code that doesn't work: SELECT * FROM $dbTable GROUP BY xNAME ORDER BY xDATETIME DESC This does the name grouping fine, but as far as showing ONLY their most recent entry, is just shows the first entry it sees in the SQL table. I guess my question is, is this possible? Here is my data sample: john 7:00 chris 7:30 greg 8:00 john 8:15 greg 8:30 chris 9:00 and my desired result should only be john 8:15 chris 9:00 greg 8:30

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  • jqgrid ASP.NET MVC -- getting data right for the grid.

    - by SamM09
    Here is my dilemma, I have not been able to manipulate my data to a form fitting to jqgrid standards. This is my first time using the jqgrid and I've spent a lot of time reading up on it. My js code is as follows: jQuery("#list").jqGrid({ url: '/Home/ListContacts/', dataType: "json", contentType: "application/json; charset=utf-8", mtype: 'POST', colNames: ['First Name', 'MI', 'Last Name'], colModel: [ { name: 'First Name', index: 'FName', width: 40, align: 'left' }, { name: 'MI', index: 'MInitial', width: 40, align: 'left' }, { name: 'Last Name', index: 'LName', width: 400, align: 'left'}], pager: jQuery('#pager'), rowNum: 10, rowList: [5, 10, 20, 50], sortname: 'Id', sortorder: "desc", repeatitems: false, viewrecords: true, imgpath: '/scripts/themes/basic/images', caption: 'My first grid' }); }); what im getting from the database: [["4","Jenna","Mccarthy"],["56","wer","weoiru"]] Now correct me if I am wrong, but the index: in my colModel refers to the column names in my database right? Could someone point to a reference that is straight forward or just start me off with this I would be most grateful.

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  • MySQL "OR MATCH" hangs (long pause with no answer) on multiple tables

    - by Kerry
    After learning how to do MySQL Full-Text search, the recommended solution for multiple tables was OR MATCH and then do the other database call. You can see that in my query below. When I do this, it just gets stuck in a "busy" state, and I can't access the MySQL database. SELECT a.`product_id`, a.`name`, a.`slug`, a.`description`, b.`list_price`, b.`price`, c.`image`, c.`swatch`, e.`name` AS industry, MATCH( a.`name`, a.`sku`, a.`description` ) AGAINST ( '%s' IN BOOLEAN MODE ) AS relevance FROM `products` AS a LEFT JOIN `website_products` AS b ON (a.`product_id` = b.`product_id`) LEFT JOIN ( SELECT `product_id`, `image`, `swatch` FROM `product_images` WHERE `sequence` = 0) AS c ON (a.`product_id` = c.`product_id`) LEFT JOIN `brands` AS d ON (a.`brand_id` = d.`brand_id`) INNER JOIN `industries` AS e ON (a.`industry_id` = e.`industry_id`) WHERE b.`website_id` = %d AND b.`status` = %d AND b.`active` = %d AND MATCH( a.`name`, a.`sku`, a.`description` ) AGAINST ( '%s' IN BOOLEAN MODE ) OR MATCH ( d.`name` ) AGAINST ( '%s' IN BOOLEAN MODE ) GROUP BY a.`product_id` ORDER BY relevance DESC LIMIT 0, 9 Any help would be greatly appreciated.

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  • DataMapper is only returning the last part of this query

    - by Josh K
    So I'm using the following: $r = new Record(); $r->select('ip, count(*) as ipcount'); $r->group_by('ip'); $r->order_by('ipcount', 'desc'); $r->limit(5); $r->get(); foreach($r->all as $record) { echo($record->ip." "); echo($record->ipcount." <br />"); } And I only get the last (fifth) record echo'ed out and no ipcount echoed. Is there a different way to go around this? I'm working on learning DataMapper (hence the questions) and need to figure some of this out. I haven't quite wrapped my head around the whole ORM thing.

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  • PHP PDO bindValue() weird problem

    - by TheMagician
    <?php try { $db = new PDO("mysql:host=localhost;dbname=DBNAME", "USER", "PASSWD"); $stmt = $db->prepare("SELECT id, name FROM testdb ORDER BY time DESC LIMIT :index, 10"); $stmt->bindValue(":index", $_GET['index'], PDO::PARAM_INT); $stmt->execute(); while( $r = $stmt->fetch(PDO::FETCH_ASSOC) ) { echo var_dump($r); } } catch( PDOException $e ) { die("Exception"); } The problem is on this line: $stmt-bindValue(":index", $_GET['index'], PDO::PARAM_INT); And the specific parameter is the second one. The code as it is above doesn't work, it doesn't return anything so the while loop isn't executed. If I replace $_GET['index'] with a number, like 10, it works just fine, it returns 10 rows. Echoing $_GET['index'] displays a number, so it should pass a number. I've also tried bindParam, but the result is same. Why isn't this working?

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  • SQL: Gather right hand values from a join

    - by Max Williams
    Let's say a question has many tags, via a join table called taggings. I do a join thus: SELECT DISTINCT `questions`.id FROM `questions` LEFT OUTER JOIN `taggings` ON `taggings`.taggable_id = `questions`.id LEFT OUTER JOIN `tags` ON `tags`.id = `taggings`.tag_id I want to order the results according to a particular tag name, eg 'piano', so that piano is at the top, then by all the other tags in alphabetical order. Currently i'm using this order clause: ORDER BY (tags.name = 'piano') desc, tags.name Which is going completely wrong - the first results i get back aren't even tagged with 'piano' at all. I think my problem is that i need to group the tag names somehow and do my ordering test against that: i think that doing it against the straight tags.name isn't working due to the structure of the resultant join table (it does work if i just do a simple select on the tags table) but i can't get my head around how to fix it. grateful for any advice, max

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