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• Relation/Sort not working in rails controller?

  - by Elliot

  I have the following relation in my rails app: genre - has many - authors authors - belong to genre and has many books books - belongs to authors and belongs to users (users can add books to the db) in my controller I have: @books=current_user.books(:include => [:author => :genre], :order => 'created_at DESC') While I am able to use the @books variable in my views - nothing is done correctly (i.e. its not showing me only books added by that user, and its not descending by created_at)... any ideas? -- Also I'm using clearance for the user auth, so current_user without the @ in the controller seems to work fine Actually, I think the relation is working, only the sort might not be working...

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• Rails - JSON object with an array?

  - by AnApprentice

  Hello, I'm able to create and send a JSON object like so: @mylist << { :id => item.id, :name => name.id } render :json => { :result => 'success', :mylist => @mylist } That works great. Problem I'm having now is that I need to include users with are 1 or more per item. @mylist << { :id => item.id, :name => name.id, :users => item.users } Where item.users contains a list of (user.id, user.name, user.desc). how do I include an array like users inside a json object? How to build in Rails and then how to parse it with jQuery? Thanks

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• How to get count of another table in a left join

  - by Sinan

  I have multiple tables post id Name 1 post-name1 2 post-name2 user id username 1 user1 2 user2 post_user post_id user_id 1 1 2 1 post_comments post_id comment_id 1 1 1 2 1 3 I am using a query like this: SELECT post.id, post.title, user.id AS uid, username FROM `post` LEFT JOIN post_user ON post.id = post_user.post_id LEFT JOIN user ON user.id = post_user.user_id ORDER BY post_date DESC It works as intended. However I would like the get the number of comments for each post too. So how can i modify the this query so I can get the count of comments. Any ideas?

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• Google App Engine PersistenceManager can process multiple objects ?

  - by Frank

  I have some code like this : PersistenceManager pm=PMF.get().getPersistenceManager(); String query="select from "+PayPal_Message.class.getName()+" where processed == false order by time desc"; List<PayPal_Message> messages=(List<PayPal_Message>)pm.newQuery(query).execute(); if (messages.isEmpty()) { } else { for (PayPal_Message g : messages) { Contact_Info_Entry A_Contact_Entry=Process_PayPal_Message_To_Get_A_License(g.getContent().getValue()); pm=PMF.get().getPersistenceManager(); try { pm.makePersistent(A_Contact_Entry); g.setProcessed(true); pm.makePersistent(g); } catch (Exception e) { Send_Email(Email_From,"[email protected]","Servlet Error Message [ "+time+" ]",new Text(e.toString())); } // finally { pm.close(); } } } pm.close(); I wonder if it's ok to use the pm above to process multiple objects before closing it. Or do I have to get and close pm for processing each object ?

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• MySQL date query only returns one year, when multiple exist

  - by Bowman

  I'm a part-time designer/developer with a part-time photography business. I've got a database of photos with various bits of metadata attached. I want to query the database and return a list of the years that photos were taken, and the quantity of photos that were taken in that year. In short, I want a list that looks like this: 2010 (35 photos) 2009 (67 photos) 2008 (48 photos) Here's the query I'm using: SELECT YEAR(date) AS year, COUNT(filename) as quantity FROM photos WHERE visible='1' GROUP BY 'year' ORDER BY 'year' DESC Instead of churning out all the possible years (the database includes photos from 2010-2008), this is the sole result: 2010 (35 photos) I've tried a lot of different syntax but at this point I'm giving in and asking for help!

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• How to retrieve the ordered list of best articles having a minimum number of votes by using HSQL ?

  - by fabien7474

  I have a Vote domain class from my grails application containing properties like article_id and note I want to HQL query the Vote domain class in order to retrieve the 5 best rated articles having at least 10 votes. I tried : SELECT v.article_id, avg(v.note), count(*) FROM vote v where count(*) >= 10 group by v.article_id order by avg(v.note) desc limit 5; But unfortunately the insertion of where count(*) >= 10 throws an error. How can I do that in a simple way? Thank you for your help.

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• Echoing a pseudo column value after a COUNT

  - by rob - not a robber

  Hi Gang... Please don't beat me if this is elementary. I searched and found disjointed stuff relating to pseudo columns. Nothing spot on about what I need. Anyway... I have a table with some rows. Each record has a unique ID, an ID that relates to another entity and finally a comment that relates to that last entity. So, I want to COUNT these rows to basically find what entity has the most comments. Instead of me explaining the query, I'll print it SELECT entity_id, COUNT(*) AS amount FROM comments GROUP BY entity_id ORDER BY amount DESC The query does just what I want, but I want to echo the values from that pseudo column, 'amount' Can it be done, or should I use another method like mysql_num_rows? Thank you!!!

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• Best way to construct this query?

  - by Andrew

  I have two tables set up similar to this (simplified for the quest): actions- id - user_id - action - time users - id - name I want to output the latest action for each user. I have no idea how to go about it. I'm not great with SQL, but from what I've looked up, it should look something like the following. not sure though. SELECT `users`.`name`, * FROM users, actions JOIN < not sure what to put here > ORDER BY `actions`.`time` DESC < only one per user_id > Any help would be appreciated.

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• Mysql query - problem with order by

  - by Sergio

  I'm using two tables for selecting messages between users. Table "messages" for recording the messages and table "members" for checking users data (are they activ or deleted). This query working fine. What I need to do is list the received messsages order by last received. I tried to do with "ORDER BY messages.id DESC" at the end of this query but it didn't work. All messages are listed from first received. This is the mysql join table query that I'm using: sql = "select distinct messages.fromid, messages.readed, messages.fromid, messages.toid, members.id as pid From messages Inner Join members on members.id = messages.fromid Where messages.toid = ".$mid." AND members.status = 7 AND messages.kreaded !='1' AND messages.subject != 'readed' GROUP BY fromid" Is there any way to do this?

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• MySQL: filling empty fields with zeroes when using GROUP BY

  - by SaltLake

  I've got MySQL table CREATE TABLE cms_webstat ( ID int NOT NULL auto_increment PRIMARY KEY, TIMESTAMP_X timestamp DEFAULT CURRENT_TIMESTAMP, # ... some other fields ... ) which contains statistics about site visitors. For getting visits per hour I use SELECT hour(TIMESTAMP_X) as HOUR , count(*) AS HOUR_STAT FROM cms_webstat GROUP BY HOUR ORDER BY HOUR DESC which gives me | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 20 | 3 | | 18 | 2 | | 15 | 1 | | 12 | 3 | | 9 | 1 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | And I'd like to get following: | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 21 | 0 | | 20 | 3 | | 19 | 0 | | 18 | 2 | | 17 | 0 | | 16 | 0 | | 15 | 1 | | 14 | 0 | | 13 | 0 | | 12 | 3 | | 11 | 0 | | 10 | 0 | | 9 | 1 | | 8 | 0 | | 7 | 0 | | 6 | 0 | | 5 | 0 | | 4 | 0 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | How should I modify the query to get such result? Thanks.

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• Hibernate multi column discriminator

  - by shikarishambu

  I have a single lookup table that manages all lookups - legacy and new lookup table structure is context,name, code, value context is either legacy or new name is the name of the lookup - state, status etc...for example code is the code and value is the value associated with the code Is there a way to specify multiple columns as discriminators so that I can get all legacy state code/values or all new status code/values. Is there a different way to do this if discriminators cannot do it? <class name="com.company.domain.Lookup"> <id name="Id" column="id" type="big_integer"> <generator class="org.hibernate.id.TableHiLoGenerator" /> </id> <discriminator column="context" insert="false" /> <property name="code" type="string"/> <property name="value" type="string"/> <property name="desc" type="string"/> <subclass name="com.company.domain.LegacyLookup" discriminator-value="legacy">

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• Grouping by Name but disregarding capitalization...

  - by bgadoci

  I have built a Ruby on Rails app that allows users to track workouts. I also allow them to add groups (like blog tags) to workouts to help keep organized. In most places where I display the tags I do so by grouping by name. @group_counts = current_user.groups.count(:group => :name, :order => 'count_all DESC') Is there a way to disregard capitalization. For instance I have two different records returned for Push press and Push Press.

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• Getting the final value to this MySQL query...

  - by Jack W-H

  I've got my database set up with three tables - code, tags, and code_tags for tagging posts. This will be the SQL query processed when a post is submitted. Each tag is sliced up by PHP and individually inserted using these queries. INSERT IGNORE INTO tags (tag) VALUES ('$tags[1]'); SELECT tags.id FROM tags WHERE tag = '$tags[1]' ORDER BY id DESC LIMIT 1; INSERT INTO code_tags (code_id, tag_id) VALUES ($codeid, WHAT_GOES_HERE?) The WHAT_GOES_HERE? value at the end is what I need to know. It needs to be the ID of the tag that the second query fetched. How can I put that ID into the third query? I hope I explained that correctly. I'll rephrase if necessary.

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• mySQL query : working with INTERVAL and CURDATE

  - by Tristan

  Hello, i'm building a chart and i want to recieve data for each months Here's my first request which is working : SELECT s.GSP_nom AS nom, timestamp, AVG( v.vote + v.prix ) /2 AS avg FROM votes_serveur AS v INNER JOIN serveur AS s ON v.idServ = s.idServ WHERE s.valide =1 AND v.date > CURDATE() -30 GROUP BY s.GSP_nom ORDER BY avg DESC But, in my case i've to write 12 request to recieve datas for the 12 previous months, is there any trick to avoid writing : // example for the previous month AND v.date > CURDATE() -60 AND v.date < CURDATE () -30 I heard about INTERVAL, i went to the mySQL doc but i didn't manage to implement it. Any ideas / example of using INTERVAL please ? Thank you

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• C# String Resource Values as Enum String Part values?

  - by JL

  Using VS2010 and .net V4.0 I would like to achieve the following: I already have 2 resource files in my project for 2 languages - English and Czech. I must say Resource Management in .net is excellent, I am suprised even to get code completion when implementing a String for example: string desc = Strings.ResourceManagerDesc This gets the string associated with the current culture of the thread. Now I am trying to create an Enum that can have the String portion of the Enum interpreted from the Strings resources. In the following way (This code DOES NOT WORK): public enum DownloadStatus { 1 = Strings.DownloadState_Complete, 2 = Strings.DownloadState_Failed, 3 = Strings.DownloadState_InProgress } This is a made up example, but you can see the point here. Since the above code won't work, is there a best practice way to achieve what I want?

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• Find the highest number of occurences in a column in SQL

  - by Ronnie

  Given this table: Order custName description to_char(price) A desa $14 B desb $14 C desc $21 D desd $65 E dese $21 F desf $78 G desg $14 H desh $21 I am trying to display the whole row where prices have the highest occurances, in this case $14 and $21 I believe there needs to be a subquery. So i started out with this: select max(count(price)) from orders group by price which gives me 3. after some time i didn't think that was helpful. i believe i needed the value 14 and 21 rather the the count so i can put that in the where clause. but I'm stuck how to display that. any help?

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• Problem with pattern matching in ocaml

  - by Antony

  I wrote the function used to decompose a Boolean function, the problem is that the compilation I get this : "Warning 5: this function application is partial, maybe some arguments are missing." How can I solve this problem? I've set wrong the patter matching or I can not run this operation with pattern matching The code is the following: let rec decomposition state_init state prec formula = match formula with And form -> (fun () -> let f1 = List.hd form in let f2 = And(List.tl form )in let new_state = Forms (state_init,f1) in decomposition state_init new_state state f1; decomposition state_init new_state state f2; Hashtbl.add graph new_state (("",false,state :: []) , []) ; let x = Hashtbl.find graph state in let succ = state :: snd x in let (desc,last,ptrs) = fst x in Hashtbl.replace graph state ( ("And-node",last,ptrs) , succ))

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• Counting distinct and duplicate attribute values in an array

  - by keruilin

  I have an array of users that's sorted in descending order based on total_points. I need to find the rank of each user in that array. The issue is that more than one user can have the same total points and, thus, the same rank. For example, three users could be in 3rd place with 200 Points. Here's my current code: class Leader < ActiveRecord::Base def self.points_leaders all_leaders = all_points_leaders # returns array of users sorted by total_points in desc order all_leaders_with_rank = [] all_leaders.each do |user| rank = all_leaders.index(user)+1 all_leaders_with_rank << Ldr.new(rank, user) # Ldr is a Struct end return all_leaders_with_rank end end How must I modify the code so that the correct rank is returned, and not just the value of the index position?

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• How to retrieve column total when rows are paginated?

  - by Rick

  Hey guys I have a column "price" in a table and I used a pagination script to generate the data displayed. Now the pagination is working perfectly however I am trying to have a final row in my HTML table to show the total of all the price. So I wrote a script to do just that with a foreach loop and it sort of works where it does give me the total of all the price summed up together however it is the sum of all the rows, even the ones that are on following pages. How can I retrieve just the sum of the rows displayed within the pagination? Thank you! Here is the query.. SELECT purchase_log.id, purchase_log.date_purchased, purchase_log.total_cost, purchase_log.payment_status, cart_contents.product_name, members.first_name, members.last_name, members.email FROM purchase_log LEFT JOIN cart_contents ON purchase_log.id = cart_contents.purchase_id LEFT JOIN members ON purchase_log.member_id = members.id GROUP BY id ORDER BY id DESC LIMIT 0,30";

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• Help with an SQL query on a single (comments) table (screenshot included)

  - by citrus

  Please see screenshot Goal: id like to have comments nested 1 level deep The comments would be arranged so that rating of the parent is in descending order the rating of the children comments is irrelevant The left hand side of the screenshot shows the output that Id like. The RHS shows the table data. All of the comments are held in 1 table. Im a beginner with SQL queries, the best I can do is: SELECT * FROM [Comments] WHERE ([ArticleId] = @ArticleId) ORDER BY [ThreadId] DESC, [DateMade] This somewhat does the job, but it obviously neglects the rating. So the above statement would show output where Bobs Comment and all of the children comments are before Amy's and her childrens comments. How can I run this query correctly?

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• Wordpress database query running slow - one of the columns doesn't exist!

  - by Pavel

  Hi there. I'm having some problems with the query that wordpress runs. That's the one: SELECT DISTINCT ID,post_title,post_date,post_content,MATCH(post_title,post_content) AGAINST ('S') AS score FROM wp_posts WHERE MATCH (post_title,post_content) AGAINST ('S') AND post_date <= 'S' AND post_status = 'S' AND id != N AND post_type = 'S' ORDER BY score DESC When I'm running this query in phpmyadmin it says that N column doesn't exist so clause "AND id != N" si not making any sense. I ran the query again without this clause and db behaved like fully optimized one. Please can someone give me a hint on that? My questions are: What this clause is used for? What wordpress is trying to find by running this and Can I modify core wordpress files to get rid of this clause? Any response or help greatly appreciated!!

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• Optimal Activity Stack Order for a Main Menu button?

  - by kefs

  I'm developing an app that starts with a main menu, and then continues through three different steps (activities) to a final activity where the task is marked complete. On this last activity, i have several additional options (add note, share, etc..) and i also have a return to main menu button. My question is.. how do i stack the activities so that calling finish() on the final activity will return back to the first activity launched? i am currently just starting the new activity via an intent, so pressing back on this screen doesn't return me to home as i would like. Sorry in advance for being so convoluted in my desc

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• Linq query joining with a subquery

  - by Alan Fisher

  I am trying to reproduce a SQL query using a LINQ to Entities query. The following SQL works fine, I just don't see how to do it in LINQ. I have tried for a few hours today but I'm just missing something. SELECT h.ReqID, rs.RoutingSection FROM ReqHeader h JOIN ReqRoutings rr ON rr.ReqRoutingID = (SELECT TOP 1 r1.ReqRoutingID FROM ReqRoutings r1 WHERE r1.ReqID = h.ReqID ORDER BY r1.ReqRoutingID desc) JOIN ReqRoutingSections rs ON rs.RoutingSectionID = rr.RoutingSectionID Edit*** Here is my table scema- Requisitions: ReqID PK string ReqDate datetime etc... ReqRoutings: ID PK int ReqID FK RoutingSection FK int RoutingDate ReqRoutingSections: Id PK int RoutingSection string The idea is that each Requisition can be routed many times, for my query I need the last RoutingSection to be returned along with the Requisition info. Sample data: Requisitions: - 1 record ReqID 123456 ReqDate '12/1/2012' ReqRoutings: -- 3 records id 1 ReqID 123456 RoutingSection 3 RoutingDate '12/2/2012' id 2 ReqID 123456 RoutingSection 2 RoutingDate '12/3/2012' id 3 ReqID 123456 RoutingSection 4 RoutingDate '12/4/2012' ReqRoutingSections: -- 3 records id 2 Supervision id 3 Safety id 4 Qaulity Control The results of the query would be ReqID = '123456' RoutingSection = 'QualityControl' -- Last RoutingSection requisition was routed to

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• NHibernate: how to do lookup a specific date

  - by Daoming Yang

  How I can lookup a specific date in Nhibernate? I'm currently using this to lookup one day's order. ICriteria criteria = SessionManager.CurrentSession.CreateCriteria(typeof(Order)) .Add(Expression.Between("DateCreated", date.Date.AddDays(-1), date.Date.AddDays(1))) .AddOrder(NHibernate.Criterion.Order.Desc("OrderID")); I tried the following code, but they did bring the data for me. Expression.Eq("DateCreated", date) Expression.Like("DateCreated", date) Note: The pass in date value will be like this 2010-04-03 00:00:00, The actual date value in the database will be like this 2010-03-13 11:17:16.000 Can anyone let me know how to do this? Many thanks.

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• How to change the sorting of a view using hook_views_pre_view()?

  - by RD

  I've got the following: function view_sorter_views_pre_view(&$view) { // don't need $items if ($view->name == 'MOST_RECENT') { $insert = array(); $insert[order] = 'DESC'; //SORT ORDER $insert[id] = 'title'; $insert[table] = 'node'; $insert[field] = 'title'; $insert[override] = array(); $insert[override][button] = 'Override'; $insert[relationship] = 'none'; unset ($view->display['default']->display_options['sorts']['title']); $view->display['default']->display_options['sorts']['title'] = $insert; } } Basically, I'm just changing the sort order... but this does not appear on the view when opening it. Any idea why?

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