Search Results

Search found 9031 results on 362 pages for 'permanent position'.

Page 31/362 | < Previous Page | 27 28 29 30 31 32 33 34 35 36 37 38  | Next Page >

  • jQuery - Ajax post result in html displaying in wrong position

    - by Sev
    I have a site with user posted threads that get voted on (up or down), and a vote count is displayed next to each thread. The voting up and down process is being done through jQuery/Ajax, and using something like this: $.ajax({ url: 'vote.php', success: function(data) { $('.result').html(data); } }); the html of the vote count is being updated (.result being the class of the div that holds the vote count number) Also, the threads are being sorted first by vote count descending, and then alphabetically. I'm having a problem with the ajax updating the HTML vote count in real time, i have a hunch that the issue is due to the fact that the order of the threads are changing when the vote count is being updated, but I'm not certain. I know the database is being updated, and when I refresh the page, it's also being updated correctly, but I'm not seeing the real-time behavior that I expect from jQuery/Ajax. What might be the problem?

    Read the article

  • [LaTeX] positions of page numbers, position of chapter headings, chapters AND Table of Contents, Ref

    - by kaikanmonaco
    I am writing my PhD thesis (120+ pages) in latex, the deadline is approaching and I am struggling with layout problems. I am using the documentstyle book. I am posting both problems in this one thread because I am not sure if the solution might be related to both problems or not. Problems are: 1.) The page numbers are mostly located on the top-right of each page (this is correct and where I want them to be). However, only on the first page of chapters and on the first page of what I call "special chapters", the page number is located bottom-centered. With "special chapters" I mean: List of Contents, List of Figures, List of Tables, References, Index. My university will not accept the thesis like this. The page number must ALWAYS be top-right one each page, even if the page is the first page of a chapter or the first page of something like the List of Contents. How can I fix this? 2.) On the first page of chapters and "special chapters" (List of Contents...), the chapter title is located far too low on the page. This is the standard layout of LaTeX with documentstyle book I think. However, the chapter title must start at the very top of the page! I.e. the same height as the normal text on the pages that follow. I mean the chapter title, not the header. I.e., if there is a chapter called "Chapter 1 Dynamics of foobar under mechanical stress" then that text has to start from the top the page, but right now it starts several centimeters below the top. How can I fix this? Have tried all kinds of things to no effect, I'd be very thankful for a solution! Thanks.

    Read the article

  • Java: calculate linenumber from charwise position according to the number of "\n"

    - by HH
    I know charwise positions of matches like 1 3 7 8. I need to know their corresponding line number. Example: file.txt Match: X Mathes: 1 3 7 8. Want: 1 2 4 4 $ cat file.txt X2 X 4 56XX [Added: does not notice many linewise matches, there is probably easier way to do it with stacks] $ java testt 1 2 4 $ cat testt.java import java.io.*; import java.util.*; public class testt { public static String data ="X2\nX\n4\n56XX"; public static String[] ar = data.split("\n"); public static void main(String[] args){ HashSet<Integer> hs = new HashSet<Integer>(); Integer numb = 1; for(String s : ar){ if(s.contains("X")){ hs.add(numb); numb++; }else{ numb++; } } for (Integer i : hs){ System.out.println(i); } } }

    Read the article

  • Flash AS3: position loaded images from loop based on image height

    - by HeroicNate
    I'm trying to dynamically stack images that are being pulled in via an xml file. Below is what I'm doing, and it almost works. The problem is that it only seems to fire off the event complete function on the very last one, instead of going for all of them. Is there a way to make it run the even.complete function for each image? function aboutfileLoaded(event:Event):void { aboutXML = new XML(aboutTextLoader.data); for(var l:int = 0; l < aboutXML.aboutimages.image.length(); l++) { imageLoader = new Loader(); imageSource = aboutXML.aboutimages.image[l]; if (imageSource != "") { this.imageLoader.contentLoaderInfo.addEventListener(Event.COMPLETE, aboutimageLoaded); this.imageLoader.load(new URLRequest(imageSource)); //aboutBox.aboutContent.addChild(imageLoader); //imageLoader.y = imageYpos; //imageYpos = imageYpos + 50; } } } function aboutimageLoaded(event:Event):void { aboutBox.aboutContent.addChild(imageLoader); this.imageLoader.y = imageYpos; imageYpos = imageYpos + this.imageLoader.height; }

    Read the article

  • Visit neighbor of a position in a 2d-array

    - by Martin
    I have the following two dimensional array: static int[,] arr = new int[5, 5] { { 00, 00, 00, 01, 00 }, { 00, 00, 01, 01, 00 }, { 00, 00, 01, 01, 00 }, { 00, 00, 01, 01, 00 }, { 00, 00, 00, 01, 00 }, }; I have to a implement a method called Hit(int x, int y). When we hit a 0 in the array (i.e. Hit(0, 0), Hit(1, 1), but not Hit(3, 0)) I would like all the adjacent zeros to the zero we hit to be incremented by 10. So if I call Hit(1, 1), the array should become the following. static int[,] arr = new int[5, 5] { { 10, 10, 10, 01, 00 }, { 10, 10, 01, 01, 00 }, { 10, 10, 01, 01, 00 }, { 10, 10, 01, 01, 00 }, { 10, 10, 10, 01, 00 }, }; Any idea how I could implement that? It sounds to me like a Depth First Search/Recursive sort-of algorithm should do the job, but I haven't been able to implement it for an 2d array. Thanks for the help!

    Read the article

  • Anchors within the document and their position.

    - by Jose Vega
    On the following website, www.josecvega.com, I have a navigation bar with years that link to sections on that same page. Unfortunately it is not working they way I hoped, when the user selects a year it moves to the section of the page, but puts that section on the top of the page. I have a fixed div on the top of the page that covers the sections and prevents it from properly displaying. What can I do for this to work? It hard to explain my situation, but it can be seen by going to www.josecvega.com and clicking one of the years.

    Read the article

  • How to set the position .

    - by shamim
    http://www.kampyle.com/ in this url when you scroll one picture always moves. i want to know this process name.how can they do it. after click this picture it's vanish and never appear even refresh the page.How they get information i click this picture .it will be helpful for me if some one give me the solution .

    Read the article

  • What are some arguments to support the position that the Dojo JavasScript library is secure, accessi

    - by LES2
    We have developed a small web application for a client. We decided on the Dojo framework to develop the app (requirements included were full i18n and a11y). Originally, the web app we developed was to be a "prototype", but we made the prototype production quality anyway, just in case. It turns out that the app we developed (or a variant of it) is going to production (many months hence), but it's so awesome that the enterprise architecture group is a little afraid. 508c compliant is a concern, as is security for this group. I now need to justify the use of Dojo to this architecture group, explicitly making the case that Dojo does not pose a security risk and that Dojo will not hurt accessibility (and that Dojo is there to help meet core requirements). Note: the web app currently requires JavaScript to be turned on and a stylesheet to work. We use a relatively minor subset of Dojo: of course, dojo core, and dijit.form.Form, ValidationTextBox and a few others. We do use dojox.grid.DataGrid (but no drag N drop or editable cells, which are not fully a11y). I have done some research of my own, of course, but I any information or advice you have would be most helpful. Regards, LES2

    Read the article

  • AWK Shift empty column to left (to start position)

    - by Filip Zembol
    INPUT: fofo jojo tst fojo jofo sts rhr hrhh dodo jojo hoho jojo zozo roro vovo OUTPUT: fofo jojo tst fojo jofo sts rhr hrhh dodo jojo hoho jojo zozo roro popo NOTE: Please help me, I need to shift all rows, which have first column empty. Every fields are tab delimited. In this file some rows start from first column, but some rows start from second or third column. Thank you

    Read the article

  • Scroll to a position in a listView

    - by klaus-vlad
    Hi, I have a long listView that the user scrolls around and then returns to the previous menu . What I want is that when the user opens this list View again the list to be scrolled to where the it was previously left. Any ideas on how this can be achieved ?

    Read the article

  • Good value for declaring "Position reached" in geo coords

    - by poeschlorn
    Hi Guys, I've written a kind of navigation system for pedestrians. The only thing is, that I need a criterion to finish the navigation. My values are gives as lat/long pairs. What would you assume would be a good value to say, both positions are equal/near enough to tell the user that he has reached the goal? Please keep also in mind, that it's idfficult to say "directly equal", because GPS modules may have variances... greetz from europe, poeschlorn

    Read the article

  • How do i get the mouse position?

    - by acidzombie24
    Basically in relation to this question It seems like e.X,y and e.Location.X,Y is relative to mousedown? I seen negative values when i havent moved it left/above the parent picbox. So it seems like the values are relative to my mousedown, but i need values relative to the parent because i update the left/top every event and other datat and relative to mousedown is breaking my code.

    Read the article

  • scroll position for div on timer tick event

    - by MeqDotNet
    I have a chat box that refresh every 7 seconds by a timer the problem is that the div is scrolling top each time the timer I have tried to add the following Page.ClientScript.RegisterClientScriptBlock(this.GetType(), "focus", "document.getElementById('divMessages').scrollTop = document.getElementById('divMessages').style.height;", true); to the timer tick but it doesn't work ticks here is my code <table border="0" cellpadding="0" cellspacing="0"> <tr> <td style="width: 500px;"> <div id="divMessages" style="background-color: White; border-color:Black;border-width:1px;border-style:solid;height:300px;width:592px;overflow-y:scroll; font-size: 11px; padding: 4px 4px 4px 4px;" onload="SetScrollPosition();" onresize="SetScrollPosition()"> <asp:Literal Id="litMessages" runat="server" /> </div> </td> <td>&nbsp;</td> <td> <div id="divUsers" style="background-color: White; border-color:Black;border-width:1px;border-style:solid;height:300px;width:150px;overflow-y:scroll; font-size: 11px; padding: 4px 4px 4px 4px;"> <asp:Literal Id="litUsers" runat="server" /> </div> </td> </tr> <tr> <td colspan="3"> <asp:TextBox Id="txtMessage" onkeyup="ReplaceChars()" onfocus="SetToEnd(this)" runat="server" MaxLength="100" Width="500px" /> <asp:Button Id="btnSend" runat="server" Text="Send" OnClientClick="SetScrollPosition()" OnClick="BtnSend_Click" /> &nbsp; <b>Color:</b> <asp:DropDownList Id="ddlColor" runat="server"> <asp:ListItem Value="Black" Selected="true">Black</asp:ListItem> <asp:ListItem Value="Blue">Blue</asp:ListItem> <asp:ListItem Value="Navy">Navy</asp:ListItem> <asp:ListItem Value="Red">Red</asp:ListItem> <asp:ListItem Value="Orange">Orange</asp:ListItem> <asp:ListItem Value="#666666">Gray</asp:ListItem> <asp:ListItem Value="Green">Green</asp:ListItem> <asp:ListItem Value="#FF00FF">Pink</asp:ListItem> </asp:DropDownList> &nbsp; <asp:Button Id="btnLogOut" Text="Log Out" runat="server" OnClick="BtnLogOut_Click" /> </td> </tr> </table> <script type="text/javascript"> var div = document.getElementById('divMessages'); div.scrollTop = div.style.height; </script> </ContentTemplate> </asp:UpdatePanel>

    Read the article

  • First iPhone App View Position Problem

    - by hytparadisee
    I am closely following the instructions given in the tutorial "Your First iPhone Application" on apple ADC. In the interface builder, I have set up a button positioned on the top according to the Apple Interface Guidelines. It runs without trouble if I simulate the interface in IB. However, if I run the built app, I get what is shown here. If you look at the view clearly, you will see that the entire view has been shifted up. And the magnitude of the shift is exactly the height of the status bar. And that's why the there is blank space at the bottom of the window, which was white instead of red. I have tried turning on the "Simulated Interface Elements", but that doesn't work either. The problem persists on real devices as well. However, using the "Simulate Interface" from IB looks fine. Any help is appreciated. Yun Tao

    Read the article

  • After changing position labels of items are gone

    - by unresolved_external
    I have FrameLayout, which has buttondeclared like this: <Button android:id="@+id/button_face_popup_more" android:layout_alignParentRight="true" android:layout_width="wrap_content" android:layout_height="wrap_content" android:padding="10dp" android:text="@string/more" android:textColor="#1c1c1c" android:textSize="15dp" android:singleLine="true" android:ellipsize="end" /> When I add it to the ViewGroup in the first time, everything is great. But when I need to replace it according to screen size: if ( screenHeight < h + popupRect.top ) { removeView(mPopupView); //((Button) mPopupView.findViewById(R.id.button_face_popup_more)).setText(R.string.more); addView(mPopupView, popupRect.left, screenHeight - h, popupRect.width()); } I got button with no label. What can be the issue? Almost forgot when I check in debug mText filed of that button in both cases, when it is displayeed and when it is not, it equals "".

    Read the article

  • How to change position of inherited items in an Inherited user control

    - by Yalda
    I have used a user control as a base class (let's call it BaseUC) with 3 labels (in 3 lines) on it (they are set as protected). And there is another user control that inherits from it (InheritedUC). I have added two more labels in InheritedUC, which are positioned between the base's labels (so there are 5 lines). Everything is fine is Visiual Studio's design UI view. But when I run the application, labels on BaseUC overlap with the ones in InheritedUC and I can't see the ones on the inherited control. Any ideas to fix this? Thank you very much

    Read the article

  • How to change the pop-up position of the jQuery DatePicker control

    - by gfrizzle
    Any idea how to get the DatePicker to appear at the end of the associated text box instead of directly below it? What tends to happen is that the text box is towards the bottom of the page and the DatePicker shifts up to account for it and totally covers the text box. If the user wants to type the date instead of pick it, they can't. I'd rather have it appear just after the text box so it doesn't matter how it adjusts vertically. Any idea how to control the positioning? I didn't see any settings for the widget, and I haven't had any luck tweaking the CSS settings, but I could easily be missing something.

    Read the article

  • position for texture in opengl

    - by Tyzak
    hello, i have a question concerning how to declare the points for a texture on a cube to be exactly i mean the: glTexCoord2f(x.f, y.f); for the front side, my declaration works: glBegin(GL_POLYGON); //Vorderseite glNormal3f(0.0f, 0.0f, 1.0f);//normale für vorderseite glTexCoord2f(0.0f, -1.f); glVertex3f(-fSeitenL/2.0f,-fSeitenL/2.0f,+fSeitenL/2.0f); glTexCoord2f(1.f, -1.f); glVertex3f(+fSeitenL/2.0f,-fSeitenL/2.0f,+fSeitenL/2.0f); glTexCoord2f(1.f, 0.0f); glVertex3f(+fSeitenL/2.0f,+fSeitenL/2.0f,+fSeitenL/2.0f); glTexCoord2f(0.0f, 0.0f); glVertex3f(-fSeitenL/2.0f,+fSeitenL/2.0f,+fSeitenL/2.0f); glEnd(); but for the right side, it doesn't work, i suggest i need other parameters, for glTexCoord2f, but i don't know witch one. glBegin(GL_POLYGON); //Rechte Seite glNormal3f(1.0f, 0.0f, 0.0f); //normale für rechte seite glTexCoord2f(0.0f, -1.f); glVertex3f(+fSeitenL/2.0f,-fSeitenL/2.0f,+fSeitenL/2.0f); glTexCoord2f(1.0f, -1.f); glVertex3f(+fSeitenL/2.0f,-fSeitenL/2.0f,-fSeitenL/0.0f); glTexCoord2f(1.0f, 0.0f); glVertex3f(+fSeitenL/2.0f,+fSeitenL/2.0f,-fSeitenL/0.0f); glTexCoord2f(0.0f, 0.0f); glVertex3f(+fSeitenL/2.0f,+fSeitenL/2.0f,+fSeitenL/0.0f); glEnd(); after all i close the "texture-declaration with" glDisable(GL_TEXTURE_2D); thanks in advance

    Read the article

  • Fragments keep going back to the default position when MapView is Zoomed In/Out

    - by hectichavana
    I have an activity with 3 fragments displayed, a MapActivity, a ListActivity, and a (normal) DetailsActivity. The ListActivity and DetailsActivity is placed over the MapActivity. There's a function to hide both ListActivity and DetailsActivity with an Animation, and onAnimationEnd() I set a new layout for the hidden Activity. The problem I'm facing is, everytime one of the ListActivity or DetailsActivity hidden (picture State 2), and then I pinch the screen on the MapActivity to zoom the map, it always goes back to the default view (picture State 1). The closed Activities are automatically opened again. Does anybody know how to prevent the hidden fragments from going to the first state again when I pinch the MapActivity? this is an example of the function how I hide the DetailsActivity(): public void hideDetailview() { final Animation close = AnimationUtils.loadAnimation(this, R.anim.close); close.setFillEnabled(true); close.setAnimationListener(closeDetailAnimationListener); fragment_detail.startAnimation(close); Toast.makeText(MainFragmentActivity.this,WWHApplication.getDrawer(), Toast.LENGTH_SHORT).show(); } private AnimationListener closeDetailAnimationListener = new AnimationListener() { @Override public void onAnimationStart(Animation animation) { } @Override public void onAnimationRepeat(Animation animation) { } @Override public void onAnimationEnd(Animation animation) { int newLeft = -330; fragment_detail.layout(newLeft, fragment_detail.getTop(), newLeft + fragment_detail.getMeasuredWidth(), fragment_detail.getTop() + fragment_detail.getMeasuredHeight()); } };

    Read the article

  • VS2010 and CSS: What is the best way to position a single form control

    - by George
    OK, I have a ton of controls on my page that I need to individually place. I need to set a margin here, a padding there, etc. None of these particular styles that I want to apply will be applied to more than control. What is the bets practice for determining at which level the style is placed, etc? OK, my choices are 1) External CSS file 1A) Using ClientIdMode = Auto (the default) I could assign a unique CssClass value to the ASP.NET control and, in the external CSS file, create a class selector that would only be applied to that one control. 1B) User Client ID = Predicatable In the external CSS file, I could determine what the ID will be for the controls of interest and create an ID selector (#ControlID{Style} ). However, I fear maintenance issues due to including/removing parent containers that would cause the ID to change. 1C) User Client ID = Static. I could choose static IDs for the controls such that I minimize the likelihood of a clash with auto generated IDs (perhaps by prefixing the ID with "StaticID_" and use an external stylesheet with ID selectors. 2) I could place the style right on the control. The only disadvantage here, as I see it, is that style info is brought down each time instead of being cached , which is what I'd get using an external CSS. If a style isn't resused, I personally don't see much benefit to placing it in an external file, though please explain why if you disagree. Is there moire of a reason that "It's nice to have all the CSS in one place?"

    Read the article

  • How to convert X/Y position to Canvas Left/Top properties when using ItemsControl

    - by kshahar
    I am trying to use a Canvas to display objects that have "world" location (rather than "screen" location). The canvas is defined like this: <Canvas Background="AliceBlue"> <ItemsControl Name="myItemsControl" ItemsSource="{Binding MyItems}"> <ItemsControl.ItemTemplate> <DataTemplate> <Canvas> <TextBlock Canvas.Left="{Binding WorldX}" Canvas.Top="{Binding WorldY}" Text="{Binding Text}" Width="Auto" Height="Auto" Foreground="Red" /> </Canvas> </DataTemplate> </ItemsControl.ItemTemplate> </ItemsControl> </Canvas> MyItem is defined like this: public class MyItem { public MyItem(double worldX, double worldY, string text) { WorldX = worldX; WorldY = worldY; Text = text; } public double WorldX { get; set; } public double WorldY { get; set; } public string Text { get; set; } } In addition, I have a method to convert between world and screen coordinates: Point worldToScreen(double worldX, double worldY) { // return screen coordinates using the canvas properties and an internal MapData object } With the current implementation, the items are positioned in the wrong location, because their location is not converted to screen coordinates. How can I apply the worldToScreen method on the MyItem objects before they are added to the canvas?

    Read the article

  • Resizing JPanel to prepare for printing without removing it from its original position

    - by Lesman
    In my program I frequently need to print various JComponents (generally JPanels) and I like them to be full-page. The way I do it now is by using the following code: g2d.scale(pf.getImageableWidth()/componentToPrint.getWidth(), pf.getImageableHeight()/componentToPrint.getHeight()); but this often stretches or otherwise deforms whatever I am trying to print, and I would much prefer to do something that re-sized intelligently, perhaps a functional version of: componentToPrint.setSize(pf.ImageableWidth(), pf.ImageableHeight); or say adding the component into a new JFrame and then setting the frame size (problem is components can't exist in two place at once). I wouldn't care if the resizing would make the rest of the GUI look terrible, as long as it is something that can easily be reset. Is there any way to do this?

    Read the article

< Previous Page | 27 28 29 30 31 32 33 34 35 36 37 38  | Next Page >