Java return to position N in call stack.
- by Finbarr
Using the return keyword in Java code will return execution to the last piece of calling code in the call stack. If object foo calls baz.bar(), the return keyword in the bar method will continue code execution in foo.
Let's say I have object foo that calls foofoo that calls foofoofoo in the above scenario, and foofoofoo calls baz.bar(). Is there anyway in Java to use the return keyword, or something else, so that the code in the bar method can return all the way back up to foo?
(WITHOUT THROWING AN EXCEPTION)
